C OMPOSITIO M ATHEMATICA
I RENE L LERENA
Wedge cancellation of certain mapping cones
Compositio Mathematica, tome 81, n
o1 (1992), p. 1-17
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Wedge cancellation of certain mapping
conesIRENE LLERENA (Ç)
Universitat de Barcelona, Fac. de Matematiques, Gran Via 585, 08007 Barcelona, Spain Received 24 September 1990; accepted 25 February 1991
0. Introduction
In his thesis 1. Bokor
proved
thefollowing.
THEOREM.
Suppose given
ai,03B2i
E03C04n-1(S2n),
1i H,
1j H,
andassume that
they
are elementsof infinite
orderfor
im,j m’,
and elementsof finite order for
i >m, j
> m’. Denoteby Cal, Cpj
thecorresponding mapping
cones.Then
f
andonly if
In this paper we want to
study
the case of spaces with one cell in dimensions 0 and 4n and a finite number of cells in dimension 2n. That is to say, we aregoing
to consider
mapping
cones of mapss4n -
-V k s’2n.
It turns outthat, for k 2,
theprevious
theoremfails;
see section 4 for anexample. Nevertheless,
the resultis true if we consider
p-local mapping
cones. Recall that thep-localization
of amapping
coneCa
ishomotopy equivalent
to themapping
cone of the p- localization 03B1(p) of the map a:Ca(P). M oreover,
each mapSn(p) ~ V k Sr(p)
is the p-localization of a
map S’° - v k S",
andA basic reference for
p-localization
of groups and spaces is[4].
We shall prove the
following.
THEOREM 1. Let p be a
fixed prime integer.
Givenf ,
gj:S4n-1(p) ~ v k s2n
1 i
H,
1j M,
assume thatthey
represent elements in1C4n -1 (V k S2n)(p) of
infinite
orderif
im,j m’,
and elementsof finite
orderif
i >m, j
> m’. Thenif
andonly if
In some
special
cases,however,
awedge
cancellationproperty
similar to theone in Theorem 1 holds for non-local
mapping
cones. In Section 4 westudy
twosuch cases and we obtain the Bokor theorem as a
Corollary.
1. The tools
We summarize in this section some facts that we shall use to prove our results.
Suppose
is a
homotopy
commutativediagram
suchthat ~, 03B4
arehomotopy equivalences
and A is a Moore space
K’(G, n). If n
2 and Y is2-connected,
then there is ahomotopy equivalence gi:
A - Bcompleting
thediagram;
see[3].
In thispaper f and g
willalways
be elements in[ v S4n+1,
vS2n]
or in[ v S4n-1(p),
vS2n(p)].
In thesecond case, for
instance,
eachhomotopy equivalence
Arises from a
homotopy
commutativediagram
where 9
and 03C8
arehomotopy equivalences.
Observe that[vkS2n(p), Vk 2ni
isisomorphic
to thering
of k x k matrices overZ(p),
thep-localization
of thering Z,
and the
homotopy
class of ç is determinedby
a matrix(~ij)
with entrieswhere
inj
and qi are the obvious inclusion andprojection.
We shall denote this matrixby
9.Actually,
wesystematically employ
this abuse ofterminology
anddenote
by
the samesymbol
a map and its matrix. It is clear that 9 is ahomotopy equivalence
if andonly
if det ç is a unit inZ(p), Analogously, 03C8
is determined upto
homotopy by
a H x H matrix with determinant a unit inZ(p).
The non-local case can be treated in a similar way. In
particular,
thehomotopy equivalences correspond
to unimodularinteger
matrices.The
machinery
that follows is due to I. Bokor. Its interest lies in the fact that it reduces thehomotopy commutativity
of the abovediagram
to some "matricial"formulas.
We
know, by
the Hilton-MilnorTheorem,
thatthe direct summands
1C4n - 1 (s4n - 1)
are embedded in03C04n-1(vkS2n) by
com-position
of certain Whiteheadproducts: [ii, lj].
The direct summands03C04n-1(S2n)
are embedded
by
the inclusions. Recall thatwhere Z is
generated by [i;, li], if n ~ 1, 2, 4,
andby
theHopf map
~i,if n
=1, 2,
4.
Hence,
any03B1 ~ 03C04n-1(vkS2n), n ~ 1, 2, 4,
can be written in the formwhere
03B1i ~
T and aii,aij ~
Z. For n =1, 2, 4,
weget
a similarexpression replacing [li’ ïj by
theHopf
map ili. Observe that theHopf
invariant of the mapS4n-1 ~ VkS2n ~ S2n is
We define
H(a)
as the k x ksymmetric
matrix with entries aij,1 ~ j,
off thediagonal
and theHopf
invariantsH(qi - a)
on thediagonal.
Now,
thesuspension homomorphism
induces a
monomorphism
on~k
T. Thus(03B11,..., ak)
E~k T
is determinedby
itsimage (03A303B11,..., Eak).
Thisimage
coincides with Eawhen n ~ 1, 2, 4.
We shallagain
abuse theterminology
and denoteby
Ea the matrixfor all n.
Clearly H(a)
and 03A303B1 characterise thehomotopy
class a.Given maps
03C8:S4n-1 ~ S4n-1 and
~:vkS2n ~ vk S2n
I. Bokorproved
thatHere
qJt
denotes thetranspose
of the matrix ~,and 03C8
is thedegree
of the map03C8:S4n-1 ~ S4n-1.
We shall also deal with maps
Then we define
H(a)
as the K x HK matrix obtainedby j uxtaposing
the matricesH(,Yi)
Similarly
Given maps and we obtain
Here
(03C8ij) = 03C8, I,
is the K x Kidentity
matrix andAssume
finally
that we have maps oci,03B2j:S4n-1 ~ vk S2n, 1 i H,
1
j
H. Take a = a 1 v ...v 03B1H and 03B2 = 03B21
v ... v03B2H,
so thatC03B1 ~ V H Cai
and
C03B2 ~ vH C03B2j.
It is easy to see thatand
similarly
forH(03B2)
and03A303B2.
Consider now adiagram
Suppose 1/1
=(t/J ij)
with03C8ij ~ Z,
andwhere
~ij
is the k x k matrixcorresponding
to the obvious mapVk S2n inj VH(vk S2n)~ vH(vkS2n) ~ vk S2n. From (1.1) we easily get that
the
diagram (1.2)
ishomotopy
commutative if andonly
if thefollowing
conditions hold.
Analogous
conditions can be obtained for thep-localization
at anyprime
p.2. The
proof
of Theorem 1~. It is obvious.
=>.
(i)
H = M is clear(by comparing
the 4n-dimensionalhomology).
Consider now
f = vHi’ï,
g =vH gj.
We haveCf ~ Cg.
Thishomotopy equivalence
arises from ahomotopy
commutativediagram
where gl
and ç arehomotopy equivalences
and the conditions(I)
and(II)
inSection 1 hold.
When f
is of finite orderH(fi)
= 0. So it follows from(I)
in Section 1 thatBut
det 03C8 ~
0.Thus m
m’.By
thesymmetry
we alsohave m’
m, so thatm = m’.
(ii)
Write thematrices 03C8
and ç in the formwhere ’Y, is
a m x m matrixand 03A61 is
a mk x mk matrix. LetIn
particular,
we haveApplying
Lemma 6.4 in[1]
it follows that there are matrices C and A such thatare units in the
corresponding rings
of matrices overZ(p).
Consider the
diagrams
We are
going
to prove that each ishomotopy commutative, checking
theconditions
(I)
and(II)
in each case. The conditions(I)
on the seconddiagram
areobvious since
H(fi)
= 0 =H(gj)
ifi, j
> m. To check(II)
let us write03A64
=03A64
+A03A62
in the formThen
since
~li03A3fi
=03C8li03A3gl
andt/!li
= 0 for1 K m,
i > m. So the seconddiagram
ishomotopy
commutativeand,
since’II 4
andffi4
arehomotopy equivalences,
itinduces
In order to prove the
homotopy commutativity
of the firstdiagram,
let uswrite
03A61
=03A61
+CB203A63 in
the formNow
Observe that
B103A62
+B203A64
= 0.Hence,
if1 x m,
i > m,Thus
Since
t/J ri
= 0 if i m, r > m.But
r, i >ml
are the entries of the unit matrix’II 4. So,
for 1 m,Hence,
from(2.3)
and(2.4)
we obtainand the first
diagram
in(2.2)
ishomotopy
commutative. Since03A81
and03A61
arehomotopy equivalences,
weget
(iii)
Without lossof generality
we may now assume that all theelements fi
andgj are of infinite order. We argue
by
induction on thehighest rank,
say r, of the matricesH(fi)
andH(gi).
Assume that rank
H(gj)
= r if andonly
if 1j
t. Sincedet 03C8
~0;
it followsthat,
foreach j t,
there is aninteger a(j)
suchthat 03C8j03C3(j)
~ 0.Thus, by (1),
Moreover,
ifs ~ j
Now,
sinceH(gs) ~
0.if s ~ j. In
otherwords,
all the elements in the(J(j)
column of thematrix
are 0except 03C8j03C3(j). Since t/J
is a unit in thering
of matrices overZ(p),
it follows thatt/J ja(j)
is a unit inZ(p)
and that the mapis 1-1. In
particular,
the number t’ ofelements fi
such thatrank H(fi)
= r isgreater
than orequal
to the number t ofgj’s
with rankH(g)
= r.By symmetry
we
get t’
= t. We shall suppose that rankH(fi)
= r if andonly
if 1 i t.Let
where the
Cij
are k x k matrices with entries inZ(p).
Thus
and,
from Lemma 6.4 in[1],
it follows that there is amatrix Bi
such thatis a unit in the
ring
of k x k matrices overZ(p). Now, by (1),
since
and
03C8s03C3(j)
= 0 for s ~j.
In additionHence,
thediagram
is
homotopy
commutative and inducesFinally,
writewhere 03A61
is a tk x tk matrix.Again by
Lemma 6.4 in[1]
there is a matrix D suchthat
is a unit. That is to say, there are matrices
Du
suchthat,
if03A64
=(~ij),
Let W
denote the minorof 1/1
formedby
the columns i > t and therows j
> t.IF
isclearly
a unit.Now, using (I)
and(II)
andarguing
asbefore,
it can beeasily
checked that the
diagram
is
homotopy
commutative.Therefore,
it induces ahomotopy equivalence
By
induction we obtain(iii).
This ends theproof
of Theorem 1.n
3. Two Corollaries
COROLLARY 1. Given maps ai,
03B2j: S4n-1 ~ vk s2n,
1 iH,
1j M,
such that ai and03B2j
represent elementsof infinite
order in1C4n-1( Vk S2n) if and only if i m and i m’, then
are in the same genus.
If and
only
ifRecall that two finite
C W complexes
X and Y are in the same genus if andonly
if theirp-localizations
at eachprime
p arehomotopy equivalent X(p) ~ Y(p).
Observe that the spaces
Cal’ Cat,
i =1, ... ,
m, inCorollary
1 needn’t be in thesame genus, since the
permutation
in Theorem 1(iii) depends
on theprime
p.Take,
forinstance,
ai,03B2i :S4n-1
-S2v
VS2n,
i =l, 2,
such thatEai
= 0 =03A303B2i,
i =
1,
2 andwhere p ~ q
areprime integers.
Then,
for anyprime r ~
p,and
but
so that
Cal
is not in the genus ofCPI’
i =1,
2.COROLLARY 2. Let
f : S4n-1(p) ~ v
kiS2n(p), 1 i H,
andgj: S4n-1(p) ~
v kj
S2n(p),
1j M,
and supposethatfi
and g J represent elementsof infinite
orderin the
corresponding homotopy
groupsif
1 i m, 1j
m’. Then~
(i) N = M, m = m’.
(ii) vHm+1 Cfi
v T ~vHm+1 CgJ
vT’, for
somewedges of p-localized
2n-spheres
T and T’.(iii) C gj
vTj ~ Cf03C3(j)
vTi, for
somewedges of p-localized 2n-spheres 1)
andTi,
j
=1,...,
m,and for
somepermutation
(Jof {1, 2,..., m}.
Proof. Comparing
thehomology
of the twogiven wedges,
weeasily get
H = M and 03A3ki = 03A3hj. Now, take k = max{ki, hj;
11 H,
1j H}
andconsider
Clearly Hence,
since
03A3i(k - ki)
=03A3i(k - kj),
and we canapply
Theorem 1. D4. Some results in the non-local case
The
following example
shows that Theorem 1 fails fornon-p-local
spaces.Consider maps 03B1i,
03B2jS4n-1 ~ S2"
vS2n i, j = 1, 2,
such thatwhere y
and zgenerate
twocyclic subgroups
of order 8 in03C04n(S2n+1)
whichintersection is the unit element. It is easy to see that the
diagram
where
is
homotopy
commutativeby checking
the conditions(I)
and(II)
in Section 1.Hence,
Obviously C03B11 ~ C03B21,
since a ~fli. However,
for anyhomotopy
commutativediagram
we have
det -
~ + 3 module 8.Therefore
ip
is not aunit,
andC(l2 *- C0 2
Some
special
resultshold, however,
in the non-local case.THEOREM 2.
Suppose
that 03B1i,03B2j: S4n-1 ~ V k s2n,
1i H,
1j M,
aregiven
andrank
H(ai)
= k = rankH(03B2j) if
andonly if
im,j
m’.Then
if
andonly if
for
somepermutation
6of Proof.
G is obvious. We prove ~.Clearly H
= M. Consider thehomotopy
commufativediagram
where 03C8
and ç arehomotopy equivalences
which induce thegiven homotopy equivalence C03B1 ~ C03B2.
Since gl
isunimodular,
foreach j m’
there is aninteger a(j)
such that03C8j03C3(j)
~ 0. But detH(03B2j) ~
0 and from(1)
and(II)
in Section 1 it follows thatdet
H(03B103C3(j)) ~
0 and det~j03C3(j) ~
0.Thus
03C3(j)
m and~s03C3(j)
= 0 if s ~j. Arguing
now as in theproof
of Theorem 1we
get m
= m’ and03C8s03C3(j)
= 0if s :0 j.
So 03C3 must be 1-1and 03C8
and (p are of thefollowing
formwith
03A81, 03A84, 03A61, 03A64
unimodular matrices. Now it can beeasily
checked that thediagrams
are
homotopy
commutative and inducehomotopy equivalences
between thecorresponding mapping
conesThe Factorisation Theorem in
[2]
is the case k = 1 of Theorem 1.THEOREM 3.
Suppose
that 03B1i,03B2j: S4n-1 ~ s2n
Vs2n,
1 iH,
1j M,
represent elementsof infinite
order inn4n- @(S2n
Vs2n).
Thenif
andonly if
H = M andfor
somepermutation
6of
Proof By
Theorem 2 themapping
conescorresponding
to maps03B1i, 03B2j
withrank
H(ai)
= 2 = rankH(03B2j)
arehomotopy equivalent
and can be cancelled.Hence,
we may assume that rankH((XJ
= 1 = rankH(fij)
for all i andj.
Each of the matrices
H(al) (and H(03B2i))
is asymmetric
matrix of rank1;
that isHence
and
Cù rr C03B1i. Therefore,
we may assume thatNow the
homotopy equivalence vHC03B11 ~ vHC03B2J
arises from ahomotopy
commutative
diagram
where
and ç arehomotopy equivalences. Write 03C8 = (03C8ij) and 9
=(4)i)
with~ij
2 x 2integer
matrices. Foreach j
there is aninteger a(j)
such that03C803C3(j)j ~
0then,
from(I)
in Section1,
it followsIn
particular,
r = :t:’ 1 and03C803C3(j)j
= ±1, since 03C8
and (p are unimodular.On the other
hand,
ifZaj . xj yj),
from(II)
in Section 2 it follows thatThus u’ ~
0,
v’ ~ 0module |yj|.
That is to say the matrices~sj,
s ~03C3(j),
are 0module 1 yjl and, hence,
det ~ ~ det~03C3(j)j
= rvmodulo |yj|.
Thus v ~ + 1modulo 1 yj since
9 is unimodular and r = + 1. Now it is easy to see that thediagram
is
homotopy
commutative and induces ahomotopy equivalence C03B1j ~ C03B203C3(j).
D
Acknowledgement
The author wishes to thank P.
Hilton,
W. Dicks and P. Menal forhelpful
conversations
concerning
this paper.References
1. H. Bass: K-Theory and stable Algebra, Publ. Math. I.H.E.S., 22, Paris (1964).
2. I. Bokor: On Genus and Cancellation in Homotopy, Isr. Journal M. (to appear).
3. P. Hilton: Homotopy theory and duality, Gordon and Breach, New York (1965).
4. P. Hilton, G. Mislin and J. Roitberg: Localization of Nilpotent Groups and Spaces, Math. Studies, 15, North-Holland, Amsterdam (1975).