C OMPOSITIO M ATHEMATICA
A RJEH M. C OHEN
G ABRIELE N EBE
W ILHELM P LESKEN Cayley orders
Compositio Mathematica, tome 103, n
o1 (1996), p. 63-74
<http://www.numdam.org/item?id=CM_1996__103_1_63_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
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Cayley orders
ARJEH M.
COHEN1,
GABRIELE NEBE and WILHELMPLESKEN2
lFac. Wisk. en Inf, TU Eindhoven, Postbox 513, 5600 MB Eindhoven, The Netherlands
2RWTH,
Lehrstuhl B für Mathematik, Templergraben 64, 52062 Aachen, GermanyReceived 3 May 1994; accepted in final form 7 May 1995
© 1996 Kluwer Academic Publishers. Printed in the Netherlands.
1. Introduction
Let G be a finite
subgroup
of a realsimple
Lie group A.Then, viewing
A as thereal
points
of asimple algebraic
group defined over R andusing
a result of Weil(cf. [Wei 64], [Slo 93], [CoW 94]),
we can find a number field K and a K-formAh
of A so that G isconjugate
in A to asubgroup
of the groupAK(K)
of theI( -rational
points
ofAK -
If A is
compact
oftype G2,
then A is known to be theautomorphism
groupAut( C )
of the realCayley
divisionring
C. In line with the aboveresult,
onemight expect,
for a finitesubgroup
G ofA,
a K-formCK
of C into whoseautomorphism
group G embeds. Such a form
Cx
will be called a K-G-form(see
below for aprecise definition). Pushing
it evenfurther,
one may ask for an RG-invariant order inCK,
where R is thering of integers
in 1(.In
[CoW 83],
the finitesubgroups
ofG2(C),
resp.Aut(C),
are described. The maximal finite ones that are not contained in a proper closed Liesubgroup (of nonze-
ro
dimension)
areisomorphic
to23 GL(3, 2), G2(2), PSL(2, 8),
orPSL(2, 13) (one
conjugacy
class for eachisomorphism type,
see[Gri 94]).
Viewed assubgroups
ofGL(C , they
haveunique
minimalsplitting
fieldsIl, namely Q, Q, Q(cos(27r/9»,
Q(B/13)
in therespective
cases. It tums out that there is aunique K -form CK
withG Aut(CK).
Passing
to the arithmetic of thesituation,
call a full Z-lattice L inCK
aCayley
order for
G,
if(i)
L ismultiplicatively closed;
(ii)
L isG-invariant;
(iii)
L is maximal with(i)
and(ii).
GENERAL LEMMA. Let L be a
Cayley
order inCh for
G. Then L is anR-lattice containing
the unit element eo = 1of CK.
Proof.
Consider the full Z-latticegenerated by
RL andReo.
It is aCayley
orderfor G
again
and containsL,
so must coincide with L. 0Remark. Let
cg
be the usualCayley
divisionalgebra over Q (see
section 2below).
ACayley
order incg
for the trivial group is a set ofintegral
elements in the sense of[Dic 23],
pp.141-142;
see alsoproperties (i)-(iv)
listed in[Cox 46].
In
[Cox 46],
Coxeterpointed
out aCayley
order for the trivial group with Iî =Q,
which also is aCayley
order forG2(2).
In[vdBS 59],
it is shown that thisCayley
order isunique
up toisomorphism
for the trivial group incg. This
Cayley
order is known to have 240 invertible elements. Its numbertheory
has beeninvestigated
in[Reh 94].
The main result of this paper, which uses
computer
calculations as described in Section 4.2.2 of[HoP 89],
contends that for all four maximal finite closedsubgroups
there are
unique Cayley
orders. But theCayley
orders for the threegroups G2(2)
are less
interesting
in the sense that nosurprising
invertible elements arefound to
occur
except
for some well-known ones for23 - GL(3, 2).
For instance theCayley
order for the latter group is
spanned by
the usual monomial basis eo,..., e7(see below)
and2 1 (eo
+ ... +e7) ;
its invertible elements are::l:ei
for i =0,...,
7.THEOREM. Let G be a
subgroup of Aut(C) isomorphic
to oneof 23 - GL(3, 2), G2 (2), PSL(2, 8),
andPSL(2, 13),
and let K =Q, Q, Q(2cos(21r 19)), Q( VU)
in the
respective
cases. Then there is aunique K-G-form CK of C
on which G acts.Moreover,
insideCK
there is aunique Cayley order for
G. In the latter two cases,all
of
their invertible elements are contained in the unitsof R,
thering of integers of K (via
theidentification of R -
eo withR,
where eo is theidentity
elementof C).
2. Preliminaries
We first recall an
explicit
construction of the realCayley
divisionring
C. As avector space, C is 8-dimensional over R with basis
(ei 1 i
=0, ... , 7) (the
nonzeroindices will be taken mod 7 with values in
1, ... , 7).
Withrespect
to this basis themultiplication
isgiven by
We dénote
by cg
theQ-subalgebraofC
withQ-basis
eo,..., e7.By (’,’)
we denotethe standard inner
product
withrespect
to this basis. A characteristicproperty
of C is that thecorresponding quadratic
form N withN(x) :_ (x, x) is multiplicative, i.e., N(xy)
=N(x)N(y)
for all x, y E C. Moreover this innerproduct
definesan involution - : C -
C, X 2(x, eo)eo -
x. Then(x, y)eo
=!(xy + yx) ==
(xy, eo)eo
for all x, y e C.Let r : C --> C be the
orthogonal projection
ontoReo
=FixC(-)
and 1r’ :=id - 7r. Then
1r(x)
=!(x
+x) _ (x, eo)eo
and7r’(x)
=2(x - x)
for all x e C.Note C =
Reo ?
V with V =(ei,..., e7)g = 7r’(C),
theorthogonal complement of Reo
in C.Let G be a finite
subgroup
ofAut(C).
Calla Ii(-subspace CK
of C a K-G-formof C, if
(i) Ch
has a K-basis which is an R-basis ofC;
(ii) Ck
is aK-subalgebra
ofC;
(iii)
G acts onCK by K-algebra automorphisms.
Denote the
orthogonal complement (with respect
toN)
ofKeo
inCK by VK.
Thus,
forexample, cg
is a K-1-form of C andVQ = (el,..., e7 )Q.
For the
proof
of the next lemma one needs thefollowing
MULTIPLICATION FORMULA.
rl(x 1r’(x . y» (x, y)x - (z , z )y for all
x, y E V.
Proof.
Let x, yE V.
Thenusing
the fact that1r’ (z)
== z -(z, eo)ep
for all z EC,
onegets 1r’( x .1r’( x.y)) == x (x y) - (x y, eo) x - (x (x y), eo) eo + (x y, eo)(x, eo)eo (*).
Since x, y E V one has
(y, eo) = (x, eo)
= 0 andx(xy)
=x2y
=-N(x)y
E V.Moreover
(xy, eo) == (x, y) == -(x, y). Using (*),
we find1r’(x . 1r’(x . y»
-N(x)y + (x, y)x.
DUNIQUE
K-G-FORM LEMMA. Let K be asubfield of R
such thatG Aut(C)
is
conjugate
underGL(C)
to asubgroup of GL8 (K).
Assume that the characterof
G on C is 1
+ x with x absolutely
irreducible.(a)
There exists at most oneK-G-form CK of C.
(b) If X satisfies (x2-, X)
= 1(where x2-
denotes the characterof
G on theskewsymmetric
partA 2
Vof V 0 V),
then there exists aK-G-form CK of C.
Proof.
(a)
LetCK, CK
be I( -G-forms of C.Clearly CK
=Keo OE) VK,
withVK
asimple
KG-submodule of V
(the orthogonal complement
ofReo
inC). Similarly
Ch - Keo ED Vh-. By
absoluteirreducibility
there exists a À E R withVk == À V K,
because aKG-isomorphism
fromVK
toVx-
extendsuniquely
to an
RG-isomorphismofV.
Choose vl, V2 EVK
with vlvz = aeo + w and0 fl w
EVK.
ThenAvl AV2
=À2aeo
+À(Àw).
Since Àw EAVK
=VK
andA2w
eVK
one concludes that À e 1(.(b)
Themorphism /B2 V -+
V determinedby x A
y -1r’(xy)
isG-equivariant.
But, by
the charactercondition,
any suchmorphism
is a scalarmultiple
of anonzero
generator
of the1-space
ofG-equivariant morphisms /B2 V -+
V.This
generator
is defined overVK,
and so there is A ER, A 0 0,
such that1r’( xy)
EÀ VK
for all x, y EVK. Replacing VK by A - 1 VK,
we find thatBut then the
multiplication
formula shows thatN(x) E I(
and(x, y)
e Il forall x, y e
VK.
Inparticular,
xy =1r’(xy)
+1r(xy) == 1r’(xy)
+(xy, eo) eo
EIi7eo
+VK.
We conclude thatIÇ’eo
+Vh
is a K-G-form. DNow,
let G be one of the four maximal finitesubgroups
mentioned above and let K be the minimalsplitting
field of therepresentation
of G onC,
resp. V. Then G satisfies the character conditions of theunique
K-G-formlemma,
hence there is aunique
K-G-form in each case. Ourcomputations
show thatCh
=OQ.
The latter follows
immediately
in the first 3 cases ofG,
but after some calculation in the last case(cf. below).
It can also be concluded from[Spr 63],
pg. 14. This establishes the first statement of the theorem in Section 1.Coming
to the arithmetic let L be aCayley
order for G inCK. Then,
as a I( G-module,
KL isisomorphic
toIleo e VK
whereVK = (el,..., e7)K
is asimple
K G-module of dimension 7. Set
L1
:= L nVK
andL’ r’(L).
ThenLI and L’
are RG-lattices in
VK by
the General Lemma.NORM LEMMA.
For any x
EL we have N(x)
E R and x =2(x, eo)eo - x
e L.Proof.
For x E L consider leftmultiplication
with x. Its characteristicpolyno-
mial lies in
R[t],
since xL C L. On the other hand x is a root of thequadratic
polynomial t2 - 2(eo, x)t
+N(x)
which must therefore divide the characteris- ticpolynomial
and hence lies inR[t].
The firstpart
follows from a look at the constant term. The linear termgives 2(x, eo)
eR,
so,by
the GeneralLemma,
2(x, eo)eo
EL,
whence x e L. 0COROLLARY. Either L =
Reo e LI
orReo e L1
c L c§Reo e L’
withL’IL1 1RIR and 2(L,,L’) C
R.Proof.
Since R D2(eo, L)
=2(eo, 7r(L»
one hasx (L) ç ! R.
Since 2R is amaximal ideal of
R,
there areonly
twopossibilities: 7r(L)
= R orx (L) 1 R.
Moreover 2(L1, Li)
=2(L1, L) C
R. 1:1For all four groups G it tums out that the second
possibility
occurs,i.e.,
L is asubdirect
product
of!Reo
andL’ amalgamated
over the common factor module!RIR c--- L’I IL, c---- F2n
with n =[I( : Q]
on which G actstrivially.
For theprime ideals p
of R notcontaining
2 the abovecorollary
has animportant
consequence.ODD PRIME LEMMA.
Let p
be aprime
idealof R
notdividing
2. Then theP-adic completion Lp of
L isgiven by Rpeo EB (LI)p
where(LI),
is theunique RpG-
sublattice X
of K
0KVK
with X =X#:= {x
EI(p 0K VK (X, x) C Rpl.
Proof.
From thedecomposition numbers,
cf.[JLPW 94],
oneimmediately
seesthat
XI pX
is asimple R/G-module
in all four cases. Therefore the set ofRtG-
lattices in
A"p
0KVK
forms a chain of the kind ... Dp-lx D
X 2Px :) - - ..
Our later constructions show that there is an RG-lattice Y in
Vh
such that Y . Y CReo EB Y and [y# : Y] is a 2-power, where y# :== {x
EVK 1 (Y, x)
CR}.
(For
instance2L,
satisfies theserequirements.)
Hence there isexactly
oneR,G-
lattice X in
Kt, (DK YK satisfying
X =X#.
Moreover X - XC Rpeo e
X. 0This lemma leaves
only
theprime
2 to beinvestigated.
There the lattice of RG-lattices in
Yh
is morecomplicated.
It can however becomputed by
the methoddescribed in
[HoP 89]
pg.105,
which runsroughly
as follows: Let M be any full RG-lattice inYh
and M’ be a maximal RG-sublattice of M. ThenM/M’
is asimple (R/pR)G-module
for someprime p
inR,
hence M’ is the kemel of anepimorphism
M - S for somesimple (R/pR)G-module
S.The remainder of this paper is devoted to this
investigation
and hence a caseby
case
proof
of the secondpart
of the theorem in Section 1.The final
point
of this section concems the notation for matrices:they
act fromthe
right; diag(A 1, ... , An)
denotes the blockdiagonal
matrix withA 1, ... , An
onthe
(block-)diagonal;
for apermutation
in thesymmetric
groupSn usually given
in
disjoint cycle notation, Pn( 7r)
denotes the n xn-permutation
matrix whôse(i, j)-entry
is 1 if ix= j
and 0 otherwise.3. The case G =
23 . GL(3, 2)
Here
K = Q
and R = Z. Withrespect
to the basis( e 1, ... , e7)
ofVK,
the group Gis
generated by
thefollowing
two matrices:diag( 1, 1, 1, - 1, - 1, 1, 1) . P7 ( ( 1 , 2) ( 3, 6) ) ,
and
P7((I,2,3,4,5,6,7)) (cf. [Cox 46]).
Thus we can take
VK
=EDL,Qei. Up
toisomorphism (i.e.,
up tomultiplication
with elements
ofQ*)
there are five ZG-latticesMi,..., M5
inVK. Representatives
can be chosen as follows
!MIIM2, M2/M4,
andM4/Mi
arenonisomorphic simple 1F2G-modules
ofdimensions
1, 3, 3, respectively.
One hasMI - Mi
=Zeo CD Ml,
but(Ml, 11 (eo
+... +
e7))
is stillmultiplicatively closed,
whereasM4 - M4 = !Zeo JS! Ml
is thesubdirect
product of 1 MI and !Zeo amalgamated
over the common factor moduleS -
!MIIM2 iZeo/Zeo
andM5 - M5
=!Z
®M2.
Since themultiplicative
closures of the lattices
M4
andM5
are nolonger lattices,
one hasthat,
as aZ-lattice,
the
unique Cayley
order for G isgenerated by
eo,..., e7and 1(eo
+ ... +e7).
4. The case G =
G2 (2)
Again K = Q
and R = Z. Withrespect
to the basis( e 1, ... , e7)
ofYx,
the group G isgenerated by
the two matricesThus we can take
VK
=EBI=1 Qei. Up
toisomorphism (i.e.,
up tomultiplication
with elements
ofQ*)
there are two ZG-latticesMi
andM2
inVK. Representatives canbechosenasfollows:Mi
=(el ,
e2, e3,e6, !(el+e2+es+e6), !(e2+e3+
e6 +
e7), !(el
+ e2 + e3 +e4))Z, M2
=(2Mi,
e3 + e4 +e6).
BothMi/M2
andM2/2Mi
aresimple IF2G-modules
of dimensions 6 and1, respectively.
One hasM2.M2
=;leoEBM2,andMI.MI
=(eo,
en e2, e3,!(eo+e3+e4+e6), !(el +
e2 + es + e6), § (e2 + e3 + e6 + e7 ) , § (e l + e2 + e3 + e4 ))Z ÉÉ !ÍZeo AS !M2 is the
subdirect
product of ! ÍZeo and ! M2 amalgamated
over the common factor moduleS ÉÉ §M2 /Mi ÉÉ §Zeo/Zeo.
SinceMl . Mi
ismultiplicatively closed,
it is theunique Cayley
order for G.5.
The case G = PSL(2, 8)
Now R =
ÍZ[w],
wherew3 -
3w + 1 =0,
is thering
of allintegers
in li =Q( w) == Q(cos(27r/9)).
Withrespect
to the basis(el, ... , e7)
ofVK,
the group Gis
generated by
thefollowing
three matricesdiag(
Here a := 3 - w -
w2,
b := -2+ w2
and c := 20131 2013 w.Again
we can takeVK
=q)7lKei.
The 2 x 2-matrices added indicate acorrespondence
with theusual
presentation of PSL(2, 8)
overIF2 [w].
Notethat (el,..., e7)R
is not an RG-lattice in
V K .
Up
toisomorphism (i.e.,
up tomultiplication
with elements ofK*)
there arefour RG-lattices
Ml , ... , M4
inVK. Representatives
can be chosen as followsMi /M2, Mi /M3,
andM4 /2Mi represent nonisomorphic simple IFg
G-modulesof dimensions
1, 4, 2, respectively.
One has
Mi . Mi = (Reo Q9 Ml , M2 . M2
=4 Reo e 1 M3,
where S ’=Reo/ 1 Reo § M3 / § M4 , M3 . M3 = 1 Reo ED lM4 and M4 - M4 !Reo ;SM3,
where S c-
!Reo/Reo c-’- M3/M4.
It follows that L =M4 - M4
is theunique Cayley
order forPSL(2, 8).
Invertible elements of L have invertible norms
lying
in R.Being
interestedin which invertible values from R the
Cayley
normtakes,
wecompute
modulo squares, asthey
are the norms of elements from R themselves. Modulo squares we haveR*I(R* ) 2 c-- (Z/2Z)3.
So there are 8 invertible values modulo squares of R*.They correspond
to the 8 differentsign patterns
for the 3 realembeddings.
But thenorm values must be
positive
in eachembedding,
and soonly
the class of 1 e R*occurs as a norm value. The elements of L of norm 1 are
precisely feo.
6. The case G =
PSL(2,13)
We recall from
[CoW 83]
thefollowing
three elements ofAut(C) generating
asubgroup
Gisomorphic
toPSL(2, 13).
The action is written withrespect
to the basis el, ... , e7 of V. The 2 x 2 matrices added indicate acorrespondence
with theusual
presentation of PSL(2, 13).
where Cj =
cos( jx / 1 3)
and sj =sin(j7r/13),
where
Note that in
[CoW 83]
there are somemisprints: 13 2013 B/13
should be 3 --%/1-3
andcos(a)
should be 2cos(a)
in c,d,
and e.Now R =
ÍZ[¥] is the ring of all integers
in K= Q( 03).
The first(and
main) problem
is to find a K-formCh
of C. The above data can beinterpreted
as anF-G-form CF of C (isomorphic to FCO as F-algebra), where F : - (Q «52+ (21 ) =
Q(sin(21r/I3))
with(52
=exp(27ri/52).
The Galois descent fromCF
toCK
canbe
performed roughly
as follows. Let(VF)K
be the I(G-module obtained from the FG-moduleVF (of
dimension 7 overF) by restricting
scalars toK,
so inpanicular diMK (VF) K
= 7 - 6 and E :=EndKG «VF) K) -- K6 x 6.
From the way(VF)h
isgiven,
one obtains F as a maximal subfield of E and can thereforeeasily
construct E as a crossed
product algebra
of F withGal(FIK) C--- C6.
As a resultof
this,
aparametrization
of allsimple
I( G -submodules W of(VF)K
ensues. Onereadily
finds a W with W - W CKeo (D W,
which thereforeyields
theunique
K-G-form
Cx
=Ileo e
W. To beexplicit,
W =VK
can be chosen asÀel
KGwith À = 13s -
64s3 + 83s5 - 4587
+IIs9 - sll,
where s =sin(27r/13) (in
particular A2 = 34-13).
To proveCK
K@Q cg
it suffices to check that thenorm forms are
equivalent by [vdBS 59]
pg. 410.Again by
the result of[vdBS 59]
on
composition algebras
overcomplete
discrete valuationrings
and thelocal-global principle
forquadratic
forms over numberfields,
cf.[Sch 85]
Cor.6.6,
it suffices to check that the norm form ofCK
istotally positive definite,
cf. also[Spr 63].
Up
toisomorphism,
there are two RG-latticesMi
andM2
inV K.
Thequotients MIl M2
andM2/2M1 represent nonisomorphic IF4G-modules
of dimension 1 and6, respectively. Mi
is as RG-latticegenerated by !Ael,
where À is as above.M2
is as RG-lattice
generated by l3(À2e2
+À3e3
+À5e5), À2 = 65s2 - 169s4
+130s6 - 39sg
+4s’o, A3
= 13 -117s2
+143s4 - 65s6
+13s8 - s10, Às = 52 - 286s2 + 364s4 - 182s6
+39s8 - 3s1°,
where s =sin(21r 113)
is as above(Â2Â3À5
=-169À2).
One
computes Ml Mi = 1/4 Reo E8 1 M2
and M:= M2 . M2 = 1/2 Reo ÀSMI,
with
S EÉ RG (! R) 1 R RG Mi /M2.
Observe that M ismultiplicatively closed,
whereas the
multiplicative
closure of thesuperlattice Mi
ofM2
is nolonger
alattice in
CK.
As in the case G =PSL(2, 8)
one obtains that M = L is theunique Cayley
order forPSL( 2,13 )
and the invertible elements in L are theéléments in R*eo.
Though everything
in the abovedescription
ofYk
isexplicit,
it is often moreconvenient to describe
Yk
withrespect
to a basis moreadjusted
to G. The matricesof G are monomial with
respect
to theQ-basis (VI, V14)
ofV K where vi
=r7 =1
aijej andHere
À, À2, À3 ,
andA5
are asabove,
andand
where s =
sin(27r/13)
is as above.With
respect
to theQ-basis (v 1, ... , v14)
ofVh
one hasand
The element in the
commuting algebra
of Gcorresponding
to,fl--3
is(aij )I,}=l’
where
otherwise
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