C OMPOSITIO M ATHEMATICA
W. L. B YNUM
A class of spaces lacking normal structure
Compositio Mathematica, tome 25, n
o3 (1972), p. 233-236
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233
A CLASS OF SPACES LACKING NORMAL STRUCTURE by
W. L.
Bynum 1
Wolters-Noordhoff Publishing Printed in the Netherlands
In
[5,
Lemma5],
Goebel showed that if B is a Banach space with coefficient ofconvexity
less than1,
then B has normal structure. This papergives
anexample (Theorem 1 )
of a class of spaces which lack normal structure and have coefficient ofconvexity
1.Thus,
Goebel’s result is the best resultpossible.
In Theorem 2 of this paper, it is shown that the duals of this class of spaces have normal structure and that their coefficients ofconvexity
are between 1 and2,
so that normal structure is not self-dual.We shall use the
following
definitions and notation. Let B be a Banach space withnorm ~~
and let K denote the unitsphere
of B. The modulusof convexity
of B is the function ô defined for t in[0, 2]
as follows :(see [4]).
A space B isuniformly
convexprovided
that its modulus ofconvexity
ispositive
on(0, 2] ([3], [4]).
Thecoefficient of convexity
ofB,03B50
=03B50(B),
is sup{t
e[0, 2] : 03B4(t)
=0} ([5]).
Let C be a bounded subset of B. The diameter
of C,
diamC,
issup {~x-y~ : x, y ~ C}.
A member x of C is a non-diametralpoint provided
that diam C >sup {~x-u~
: u EC}
and a diametralpoint of
Cis a
point x
for which theprevious inequality
isreplaced by equality.
For y
inB,
thedistance from y to C, d(y, C),
isA space B has normal structure if each bounded convex subset of B with
positive
diameter has a non-diametralpoint ([2]).
The convex hullof a subset A of B will be denoted
by
co A.A
space B
isuniformly
non-square if there is an r > 0 such that for xand y
inX having
norm1, ~x+y~ + ~x-y~ ~
4-r([7]).
The examples
in this paper are based on thelp
spaces. For 1 p 00and x in
lp,
define sequencesx+
and x- as follows:1 Research supported by a Faculty Research Grant of the College of William and
Mary.
234
For x in
l p , x +
and x - are inlp
and x =x+ - x-.
Denote thelp
normby ~ Il.
For 1~ q
oo, letlp, q
denote the set of elements oflp
withthe norm:
Let
lp,~
denote the set of elements of1 p
with the norm:It is easy to show that for 1
~ q ~
oo, thefunction || is
indeed a normfor
lp
which isequivalent
to theil
norm. We shall show in Theorem 1 thatfor 1 p oo,
lp, 00
lacks normal structure and03B50(lp,~) = 1
and inTheorem 2 that
lp,1
has normal structure and21/p ~ Bo(lp, 1)
2.Using
anargument
which isconsiderably
morecomplicated
than theproof
ofTheorem
2,
one can show that03B50(lp,1)
isactually equal
to21/p.
If 1 p oo and 1
~ q ~
ooand p*
andq *
are theconjugate
indicesof p
and q, then astraightforward argument
shows that(lp,q)*
is isomet-rically isomorphic
tolp*,
q*.Thus, by combining
Theorems 1 and2,
we obtain a class of reflexive spaces such that each space lacks(has)
normalstructure while its dual has
(lacks)
normal structure, so that normal structure is not self-dual.A lack of connection between normal structure and
reflexivity
hasbeen shown
previously.
In[1,
p.439] Belluce,
Kirk and Steiner gave anexample
of a reflexive spacelacking
normal structure(the
coefficient ofconvexity
of thisexample
is2); consequently, reflexivity
does notimply
normal structure. On the other
hand,
Zizler has shown[8, proposition 2] ]
that eachseparable
Banach space B has anequivalent
norm withrespect
to which B has normal structure;thus,
normal structure does notimply reflexivity.
Using
the methods of this paper, one can show that for 1 p, q oo,lp, q
isuniformly
convex and therefore has normal structure. We shall notanalyze
these spaces here.Incidentally,
it is not difhcult to prove that in anarbitrary
Banach space B with modulus ofconvexity ô,
the limit from the left of ô at2, 03B4(2-),
is
equal
to 1-(eo/2).
In[5],
Goebel has noted that B isuniformly
convexif and
only
if eo = 0.Consequently,
we have that B isuniformly
convexif and
only if 03B4(2-)
= 1. It isinteresting
to compare this with Goebel’s observation that B isstrictly
convex if andonly if 03B4(2)
= 1.THEOREM
(1).
For 1 p oo ,lp,~
lacks normal structure and itscoef- ficient of convexity
is 1.PROOF. The
following
theorem of Brodskii and Mil’man[2]
is used toshow that B =
lp,~
lacks normal structure:A space X does not have normal structure if and
only
if there is a bounded sequence{xn}
of elements of X such that the distance from xn+1to co
{x1,···, xn}
tends to the diameter of the set of all xi as n - oo(such
a sequence is called a diametralsequence).
We shall show that the sequence,
{en},
of unit vectors of B(i.e.,
en is that member of B whose n-th coordinate is 1 with all other coordinates0)
is a diametral sequence. If m is apositive integer
and oc, + ··· + oc. = 1and 0 ~ 03B1i ~
1 for 1~ i ~ m,
thenThus,
the distance from em+1 to co{e1,···, em}
is 1. The aboveequation
also shows that the diameter of the sequence
{en}
is1,
so B lacks normal structure.By
Goebel’s lemma 5 and theprevious paragraph, 03B50(B) ~
1. We shallshow that
03B50 ~
1.Suppose that 03B4(t)
= 0 for some t in[0, 2]. Then,
thereare sequences
{xn} and {yn}
inK,
the unitsphere of B,
such that for eachn,
|xn-yn| ~
t and|xn+yn| ~
2 as n ~ 00. For eachu in B, (-u)+ =
u-and
(- u)- = u+,
so we may assume that foreach n, |xn+yn| = ~(xn +Yn)+1B | and |xn - yn| = ~(xn-yn)+~. But, 2 ~ I I xn +y+n~~ ~xn+yn~-.2;
consequently,
the uniformconvexity
oflp implies that ~xn+-yn+~ ~
o.Therefore,
Thus, eo = 1,
and theproof is complete.
THEOREM
(2).
For 1 p 00,l p,1
has normal structure and21/p ~ 03B50(lp, 1)
2.PROOF.
First,
we establish theinequality
for 80. Let x = eland y
=- e2 .
Then Ix+yl (
= 2and |x-y|
=21/p,
so that03B50 ~ 21/p.
In[5],
Goebel notes that a
space B
isuniformly
non-square if andonly
if80(B)
2. It is easy to see that if B is
uniformly
non-square then B* is also.By
Theorem1, 03B50(lp*,~)
=1,
andthus, 03B50(lp,1)
2.To show that
lp,1
has normal structure, we shall use thefollowing
theorem of Gossez and Lami Dozo
[6]:
Let B be a Banach space with Schauder basis
{en}.
For eachpositive integer k
and each x inB,
letUk(x) = 03A3k1xnen
and letVk(x)
= x -Uk(x).
Suppose
that{kn}
is astrictly increasing
sequence ofpositive integers
with the
following property:
If c >
0,
there is an r > 0 with theproperty
that if x is in B and n is aninteger such that IIUkn(x)11 =
1and ~Vkn(x)~ ~
c, then~x~ ~
1 + r.Then,
each convexweakly relatively compact
subset of B of at leasttwo
points
has a non-diametralpoint.
236
The sequence
{en}
of unit coordinate vectors is a Schauder basis for1 "Il.
It follows from the Minkowskiinequality
that for eachpositive integer k
and each x in1,, 1,
Therefore,
the above theorem isapplicable.
Since this space isreflexive,
each bounded convex subset is
weakly relatively compact. Thus, lp,1
hasnormal structure. 1 want to thank the referee for
calling
my attention tothe paper of Gossez and Lami Dozo.
REFERENCES
L. P. BELLUCE, W. A. KIRK AND E. F. STEINER
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M. S. BRODSKII AND D. P. MIL’MAN
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J. A. CLARKSON
[3] Uniformly convex spaces, Trans. Amer. Math. Soc. 40 (1936), 396-414.
M. M. DAY
[4] Uniform convexity in factor and conjugate spaces, Annals of Math. 45 (1944), 375-385.
K. GOEBEL
[5] Convexity of balls and fixed point theorems for mappings with nonexpansive
square, Compositio Math. 22 (1970), 269-274.
J. P. GOSSEZ AND E. LAMI DOZO
[6] Structure normale et base de Schauder, Bull. de l’Acad. Royale de Belgique (5e Ser.) 55 (1969), 673-681.
R. C. JAMES
[7] Uniformly non-square Banach spaces, Annals of Math. 80 (1964), 542-550.
V. ZIZLER
[8] Some notes on various rotundity and smoothness properties of separable Banach
spaces, Comment. Math. Univ. Carolinae 10 (1969), 195-206.
(Oblatum 30-VIII-1971 & 24-IV-1972) Department of Mathematics College of William and Mary Williamsburg, Virginia 23185