A NNALES DE L ’I. H. P., SECTION B
W ALTER S CHACHERMAYER
The class of Banach spaces, which do not have c0 as a spreading model, is not L2-hereditary
Annales de l’I. H. P., section B, tome 19, n
o1 (1983), p. 1-8
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The class of Banach spaces,
which do not have c0
as aspreading model,
is not L2-hereditary
Walter SCHACHERMAYER (LINZ)
Dr. W. Schachermayer, Universitat Linz, Altenberger Str. 69, A-4045 Linz, Autriche
Vol. XIX, n° l, I983, p. 1-8. Calcul des Probabilités et Statistique.
1. INTRODUCTION
In
[4 ] the problem
was raised wether thefact,
that a Banach space E does not have co as aspreading model, implies
thatL2( [0, 1 ] ; E)
has thesame
property.
It wasconjectured
that the answer is no, as theproperty
of nothaving
co as aspreading
model is somewhat dual to the Banach- Saksproperty (see [2])
and for this latterproperty
J.Bourgain
has cons-tructed a
counterexample ( [3 ]).
The
present
author has constructedindependently
of J.Bourgain
anotherspace E with the Banach-Saks
property
andL2(E) failing
it( [6 ])
and itturns out that the dual E’
gives
acounterexample
to theproblem
raisedin the title.
2. THE EXAMPLE
Let y == {
n i , n2, ..., anincreasing
finite sequence of natural numbers.Write ni= vi where this
expression
isunique,
if werequire
that 2u=.As in
[d] we
associate to every ni the real numbert(ni)
= E[0,
1[
andcall y admissible if
(1)
Annales de l’Institut Henri Poincaré-Section B-Vol. XIX, 0020-2347/1983/1$ 5,00/
1
2 W. SCHACHERMAYER
(2)
For every 0__ ~ 2’~~ + 1
there isonly
one f such that[j~2u1 + ~,
(.l + 1)~2u1 + ~ ~.
_For an admissible y = ...,
nk)
and the space of finite sequences, we defineFor our purposes it will this time be
convenient,
not to useinterpolation
but to follow Baernstein’s
original
definition([7]):
For x E(1~~~~
definewhere the sup is taken over all
increasing sequences {
of admissiblesets
(i.
e. the last memberof 03B3l
is smaller than the first member ofyr+ 1).
Let
(E, II IIE)
be thecompletion
of~~~>
withrespect
to this norm. Inan
analogous
way as in[6] ]
we shall show that E has the Banach-Saksproperty,
i. e. that it does not have aspreading
modelisomorphic
toll ;
we shall also show that E’ does not have a
spreading
modelisomorphic
to co. In fact we shall prove a much
stronger
result.PROPOSITION 1. -
a) Every spreading
model based on a normalizedweak null sequence
(x~) ~
1 of E isisomorphic
tol2.
b) Every spreading
model based on a normalized weak null sequence1 of E’ is
isomorphic
tol2.
Proof 2014 ~)
Let(x~)~°
1 be a normalized weak null sequence in E. As(xn)~°
1 converges to zerocoordinatewise,
we may assume(by
a standardperturbation argument)
that thexn’s
aresupported by disjoint blocks,
i. e.there is an
increasing
sequence 1 of naturalnumbers,
such thatwith
r(0)
= 0Then for every sequence ..., ~ of scalars and ~i ... ~, the estimate
. t-
holds
trivially
in view of the definition .[ (E-
Annales de l’Institut Henri Poincaré-Section B
For the converse let 1 > G > 0 and choose
inductively
anincreasing
sequence
1 in N
and infinite subsetsMk
of N: LetMo =
N and n1 = 1 and supposeMk-
1and nk
are defined.Let Pk
be such that2pk -1 _ r(nk)
2Pkand consider the
partition
of[0, 1 [
into the intervalsU/2PB (j+ 1)/~pk [, j
=0,
...,2~’~ -1.
For n > nk defineNote
that,
for every n,in view of the definition of the norm of E and the fact
that ))
= 1.Find an infinite subset
Mk
ofMk-1
n[nk
+1,
nk +2,
..., oo[
such thatfor
every j
=0, ... , 2Pk -
1 the sequence converges, say.Clearlv
Finally
letMk
be the subset ofMk consisting
of those n for which forevery j
=0,
..., 2pk - 1and let nk+ 1 be the first element of
Mk.
Thiscompletes
the induction.Note that for an admissible y =
(m1,...,mq)
and k ~ N such thatinf (y)
=m 1 _ r(nk)
and for every choice of scalars 1, ..., lIndeed,
asr(nk) 2pk,
we see that y may contain for everyj= o, ... , 2pk-1
at most one index mr(1
rq)
with(j ~- I)/2Fk [;
by
construction them/th entry
of each Xnk +( 1 __ i Q
is bounded in absolutvalue + 2-pk .
E/3.
As the aredisjointly supported
weget
Summing over j
andrecalling
the definitionof )[ .
weget
the firstinequality
of(2),
while the second is trivial.4 W. SCHACHERMAYER
We now shall pass to the
general
case. Fix a sequence ai, ... , oc~ of scalars. We shall showwhich
(in
view of(1)
and the arbitrarness of e >0)
willreadily
prove(a).
So fix an
increasing
sequence y 1 y2 ... of admissible sets. Forbrevity
we writeFor i =
1, ..., k
letJ(i)
be the set1,
...,l ~
such that the last ele- ment of y~ lies in]r(ni _ 1), r(ni)].
IfJ(i)
is notempty
denotej(i)
the first ele- ment ofJ(i)
and let be the element se { 1, ..., k },
such that the first element of lies]r(ns _ 1, r(ns)].
Note that forthe j E J(i), j
>j(i)
thefirst and the last element of y J lie in
]r(ni _ 1), r(ni) ],
while forj(i)
ingeneral only
the last element lies in]r(ni _ I), r(ni)].
So we may estimateAnnales de l’Institut Henri Poincaré-Section B
Using (2)
and the fact that(a i ~ 2
+b1/2
+c ~’ 2 )2
Hence we have
proved (3)
and thuspart (a)
ofproposition
1.Proo, f ’ of (b).
It iseasily
seenusing (a)
that the unit vector basis of E isshrinking
andboundedly complete (see [7] ] or [6 ]),
hence the dual unit vectors I form a basis of E’. So let I be a normalized sequencetending weakly (and
thereforecoordinatewise)
to zero.Similarly
as in(a)
we may suppose that there is an
increasing
sequence(r(n))n
1 such thatNow choose a sequence
{xn~,~ 1
inE, == ~ 1,
whichclearly implies
that x,~ is of the formAs in the prove of
(a)
find asubsequence i such
that i spansa space
6 + E isomorphic
tol2.
6 W. SCHACHERMAYER
Now fix a sequence ...,
{3k
of scalars and find a sequence ..., ock’
such that
Denote
By (a)
we know thatHence
On the other hand the reverse
inequality
is
again easily
checkeddirectly
from the definitionof [[ . lie.
This proves(b)
and therefore
proposition
1. DRemark. - Consider the sequence of unit-vectors in E
(resp. (e2n _ 1)~
1 inE’).
It may be checked that every
spreading
model based on 1(resp. i )
is isometric to a countablel2-sum
of 2-dimensional hence in this case the Banach-Mazur distanceequals precisely ./2.
To show that
L 2(E’)
does have co asspreading
model we need a trivialprobabilistic lemma,
whoseproof
is left to the reader.LEMMA . Let k ~ N and a >
0;
there isN(k, 8)
such that for M >N(k, s)
Annales de l’Institut Henri Poincaré-Section B
and for
independent
randomvariablesXi, ... , Xk taking
their values in{ 1,
...,M }
in auniformly
distributed way, we havePROPOSITION 2. 2014 co
isometrically
asspreading
model.Proof. Similarly
as in[6] we let { u}~u= 1 be
anindependent
sequence inL2(E’)
such thatfu
takes the value withprobability
2-u(for
v =
0, ... , 2~‘ - 1).
This times the are unit-vectors in E’.Clearly ~ ~ fu
= 1 and for every sequence ul u2 ... ande. = + 1 _
Hence the
following
claim will prove theproposition.
CLAIM. - For
every k ~
NTo prove the claim fix k and 8 > 0 and let u be such that 2U > max
(k, N(k, 8)),
where theN(k, 8)
is defined in thepreceeding
lemma.Now fix u ui u2 ... and a sequence of
signs
~l, ..., ~k.To
apply
the above lemma letX i ,
...,Xk
be the random variables with valuesin { 1, ...,2~ 1 + 1 ~
definedby
and
It follows form the above lemma and the definition of admissible sets y that there is a subset A ~
[0, 1 [
of measuregreater
than I - ~ such that for 03C9 ~ A the set 03B303C9= {n1, ..., nk} corresponding
to the indices of the unitvectors {
.. - , . is admissible. Hence for cc~ E A we have8 W. SCHACHERMAYER
Integrating
we obtainThis proves the claim and therefore
proposition
2.[1] A. BAERNSTEIN, On reflexivity and summability; Studia Math., t. 42, 1972, p. 91-94.
[2] B. BEAUZAMY, Banach Saks properties and spreading models; Math. Scand., t. 44, 1979, p. 357-384.
[3] S. GUERRE, La propriété de Banach-Saks ne passe pas de E à
L2(E) ;
Séminaire surla géométrie des espaces de Banach, École Polytechnique.
[4] S. GUERRE, J.-Th. LAPRESTÉ, Quelques propriétés des modèles étalés sur les espaces de Banach, Ann. Inst. H. Poincaré, t. XVI, n° 4, 1980, p. 339-347
[5] J.-Th. LAPRESTÉ, Sur une propriété des suites asymptotiquement inconditionnelles, Séminaire sur la géométrie des espaces de Banach, École Polytechnique, 1978/
1979, exposé XXX.
[6] W. SCHACHERMAYER, The Banach-Saks property is not
L2-hereditary,
to appear in the Israel Journal.(Manuscrii le 22 décembre 1981 )
Annales de l’Institut Henri Poincaré-Section B
REFERENCES