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(1)

A NNALES DE L ’I. H. P., SECTION B

W ALTER S CHACHERMAYER

The class of Banach spaces, which do not have c0 as a spreading model, is not L2-hereditary

Annales de l’I. H. P., section B, tome 19, n

o

1 (1983), p. 1-8

<http://www.numdam.org/item?id=AIHPB_1983__19_1_1_0>

© Gauthier-Villars, 1983, tous droits réservés.

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The class of Banach spaces,

which do not have c0

as a

spreading model,

is not L2-hereditary

Walter SCHACHERMAYER (LINZ)

Dr. W. Schachermayer, Universitat Linz, Altenberger Str. 69, A-4045 Linz, Autriche

Vol. XIX, l, I983, p. 1-8. Calcul des Probabilités et Statistique.

1. INTRODUCTION

In

[4 ] the problem

was raised wether the

fact,

that a Banach space E does not have co as a

spreading model, implies

that

L2( [0, 1 ] ; E)

has the

same

property.

It was

conjectured

that the answer is no, as the

property

of not

having

co as a

spreading

model is somewhat dual to the Banach- Saks

property (see [2])

and for this latter

property

J.

Bourgain

has cons-

tructed a

counterexample ( [3 ]).

The

present

author has constructed

independently

of J.

Bourgain

another

space E with the Banach-Saks

property

and

L2(E) failing

it

( [6 ])

and it

turns out that the dual E’

gives

a

counterexample

to the

problem

raised

in the title.

2. THE EXAMPLE

Let y == {

n i , n2, ..., an

increasing

finite sequence of natural numbers.

Write ni= vi where this

expression

is

unique,

if we

require

that 2u=.

As in

[d] we

associate to every ni the real number

t(ni)

= E

[0,

1

[

and

call y admissible if

(1)

Annales de l’Institut Henri Poincaré-Section B-Vol. XIX, 0020-2347/1983/1$ 5,00/

1

(3)

2 W. SCHACHERMAYER

(2)

For every 0

__ ~ 2’~~ + 1

there is

only

one f such that

[j~2u1 + ~,

(.l + 1)~2u1 + ~ ~.

_

For an admissible y = ...,

nk)

and the space of finite sequences, we define

For our purposes it will this time be

convenient,

not to use

interpolation

but to follow Baernstein’s

original

definition

([7]):

For x E

(1~~~~

define

where the sup is taken over all

increasing sequences {

of admissible

sets

(i.

e. the last member

of 03B3l

is smaller than the first member of

yr+ 1).

Let

(E, II IIE)

be the

completion

of

~~~>

with

respect

to this norm. In

an

analogous

way as in

[6] ]

we shall show that E has the Banach-Saks

property,

i. e. that it does not have a

spreading

model

isomorphic

to

ll ;

we shall also show that E’ does not have a

spreading

model

isomorphic

to co. In fact we shall prove a much

stronger

result.

PROPOSITION 1. -

a) Every spreading

model based on a normalized

weak null sequence

(x~) ~

1 of E is

isomorphic

to

l2.

b) Every spreading

model based on a normalized weak null sequence

1 of E’ is

isomorphic

to

l2.

Proof 2014 ~)

Let

(x~)~°

1 be a normalized weak null sequence in E. As

(xn)~°

1 converges to zero

coordinatewise,

we may assume

(by

a standard

perturbation argument)

that the

xn’s

are

supported by disjoint blocks,

i. e.

there is an

increasing

sequence 1 of natural

numbers,

such that

with

r(0)

= 0

Then for every sequence ..., ~ of scalars and ~i ... ~, the estimate

. t-

holds

trivially

in view of the definition .

[ (E-

Annales de l’Institut Henri Poincaré-Section B

(4)

For the converse let 1 > G > 0 and choose

inductively

an

increasing

sequence

1 in N

and infinite subsets

Mk

of N: Let

Mo =

N and n1 = 1 and suppose

Mk-

1

and nk

are defined.

Let Pk

be such that

2pk -1 _ r(nk)

2Pk

and consider the

partition

of

[0, 1 [

into the intervals

U/2PB (j+ 1)/~pk [, j

=

0,

...,

2~’~ -1.

For n > nk define

Note

that,

for every n,

in view of the definition of the norm of E and the fact

that ))

= 1.

Find an infinite subset

Mk

of

Mk-1

n

[nk

+

1,

nk +

2,

..., oo

[

such that

for

every j

=

0, ... , 2Pk -

1 the sequence converges, say.

Clearlv

Finally

let

Mk

be the subset of

Mk consisting

of those n for which for

every j

=

0,

..., 2pk - 1

and let nk+ 1 be the first element of

Mk.

This

completes

the induction.

Note that for an admissible y =

(m1,...,mq)

and k ~ N such that

inf (y)

=

m 1 _ r(nk)

and for every choice of scalars 1, ..., l

Indeed,

as

r(nk) 2pk,

we see that y may contain for every

j= o, ... , 2pk-1

at most one index mr

(1

r

q)

with

(j ~- I)/2Fk [;

by

construction the

m/th entry

of each Xnk +

( 1 __ i Q

is bounded in absolut

value + 2-pk .

E/3.

As the are

disjointly supported

we

get

Summing over j

and

recalling

the definition

of )[ .

we

get

the first

inequality

of

(2),

while the second is trivial.

(5)

4 W. SCHACHERMAYER

We now shall pass to the

general

case. Fix a sequence ai, ... , oc~ of scalars. We shall show

which

(in

view of

(1)

and the arbitrarness of e >

0)

will

readily

prove

(a).

So fix an

increasing

sequence y 1 y2 ... of admissible sets. For

brevity

we write

For i =

1, ..., k

let

J(i)

be the set

1,

...,

l ~

such that the last ele- ment of y~ lies in

]r(ni _ 1), r(ni)].

If

J(i)

is not

empty

denote

j(i)

the first ele- ment of

J(i)

and let be the element s

e { 1, ..., k },

such that the first element of lies

]r(ns _ 1, r(ns)].

Note that for

the j E J(i), j

>

j(i)

the

first and the last element of y J lie in

]r(ni _ 1), r(ni) ],

while for

j(i)

in

general only

the last element lies in

]r(ni _ I), r(ni)].

So we may estimate

Annales de l’Institut Henri Poincaré-Section B

(6)

Using (2)

and the fact that

(a i ~ 2

+

b1/2

+

c ~’ 2 )2

Hence we have

proved (3)

and thus

part (a)

of

proposition

1.

Proo, f ’ of (b).

It is

easily

seen

using (a)

that the unit vector basis of E is

shrinking

and

boundedly complete (see [7] ] or [6 ]),

hence the dual unit vectors I form a basis of E’. So let I be a normalized sequence

tending weakly (and

therefore

coordinatewise)

to zero.

Similarly

as in

(a)

we may suppose that there is an

increasing

sequence

(r(n))n

1 such that

Now choose a sequence

{xn~,~ 1

in

E, == ~ 1,

which

clearly implies

that x,~ is of the form

As in the prove of

(a)

find a

subsequence i such

that i spans

a space

6 + E isomorphic

to

l2.

(7)

6 W. SCHACHERMAYER

Now fix a sequence ...,

{3k

of scalars and find a sequence ..., ock

such that

Denote

By (a)

we know that

Hence

On the other hand the reverse

inequality

is

again easily

checked

directly

from the definition

of [[ . lie.

This proves

(b)

and therefore

proposition

1. D

Remark. - Consider the sequence of unit-vectors in E

(resp. (e2n _ 1)~

1 in

E’).

It may be checked that every

spreading

model based on 1

(resp. i )

is isometric to a countable

l2-sum

of 2-dimensional hence in this case the Banach-Mazur distance

equals precisely ./2.

To show that

L 2(E’)

does have co as

spreading

model we need a trivial

probabilistic lemma,

whose

proof

is left to the reader.

LEMMA . Let k ~ N and a >

0;

there is

N(k, 8)

such that for M >

N(k, s)

Annales de l’Institut Henri Poincaré-Section B

(8)

and for

independent

randomvariables

Xi, ... , Xk taking

their values in

{ 1,

...,

M }

in a

uniformly

distributed way, we have

PROPOSITION 2. 2014 co

isometrically

as

spreading

model.

Proof. Similarly

as in

[6] we let { u}~u= 1 be

an

independent

sequence in

L2(E’)

such that

fu

takes the value with

probability

2-u

(for

v =

0, ... , 2~‘ - 1).

This times the are unit-vectors in E’.

Clearly ~ ~ fu

= 1 and for every sequence ul u2 ... and

e. = + 1 _

Hence the

following

claim will prove the

proposition.

CLAIM. - For

every k ~

N

To prove the claim fix k and 8 > 0 and let u be such that 2U > max

(k, N(k, 8)),

where the

N(k, 8)

is defined in the

preceeding

lemma.

Now fix u ui u2 ... and a sequence of

signs

~l, ..., ~k.

To

apply

the above lemma let

X i ,

...,

Xk

be the random variables with values

in { 1, ...,2~ 1 + 1 ~

defined

by

and

It follows form the above lemma and the definition of admissible sets y that there is a subset A ~

[0, 1 [

of measure

greater

than I - ~ such that for 03C9 ~ A the set 03B303C9

= {n1, ..., nk} corresponding

to the indices of the unit

vectors {

.. - , . is admissible. Hence for cc~ E A we have

(9)

8 W. SCHACHERMAYER

Integrating

we obtain

This proves the claim and therefore

proposition

2.

[1] A. BAERNSTEIN, On reflexivity and summability; Studia Math., t. 42, 1972, p. 91-94.

[2] B. BEAUZAMY, Banach Saks properties and spreading models; Math. Scand., t. 44, 1979, p. 357-384.

[3] S. GUERRE, La propriété de Banach-Saks ne passe pas de E à

L2(E) ;

Séminaire sur

la géométrie des espaces de Banach, École Polytechnique.

[4] S. GUERRE, J.-Th. LAPRESTÉ, Quelques propriétés des modèles étalés sur les espaces de Banach, Ann. Inst. H. Poincaré, t. XVI, 4, 1980, p. 339-347

[5] J.-Th. LAPRESTÉ, Sur une propriété des suites asymptotiquement inconditionnelles, Séminaire sur la géométrie des espaces de Banach, École Polytechnique, 1978/

1979, exposé XXX.

[6] W. SCHACHERMAYER, The Banach-Saks property is not

L2-hereditary,

to appear in the Israel Journal.

(Manuscrii le 22 décembre 1981 )

Annales de l’Institut Henri Poincaré-Section B

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