C OMPOSITIO M ATHEMATICA
V. A VERBUCH
Remark on the definition of an automorphic form
Compositio Mathematica, tome 59, n
o1 (1986), p. 3-13
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3
REMARK ON THE DEFINITION OF AN AUTOMORPHIC FORM
V. Averbuch
@ Martinus Nijhoff Publishers, Dordrecht - Printed in the Netherlands
Introduction
Let k be a
global field,
G a reductivealgebraic
group over k. Let be amaximal
compact subgroup
ofGA,
and letKf
be it’s finitecomponent.
In 111,
anautmorphic
form a G is defined as a smooth C-valued function onGA,
which satisfied thefollowing
conditions.(1) f
isKf-finite
and Hecke-finite.(2) f
is a function onGk B GA
(3) f
transformsaccording
to a character under the action of the centre.(4) f
satisfies a moderategrowth
condition in theSiegel
domain.(Precise
definition isgiven
in thebeginning
of Part 1 forGLn
overQ
and in thebeginning
of Part 2 for thegeneral case).
These conditions are not
independent.
If char k >0,
then(4)
can bededuced from
(1)-(3).
If char k =0,
then Hecke-finiteness at finiteplaces
follows from other conditions and Hecke-finiteness at Archemedian
places.
Here we prove thefollowing
theorem:THEOREM:
If
char k =0,
then(4)
can bededuced from (2), (3), K t-finite-
ness and
Hecke finiteness at
somebig finite place - p,
s. t.f
is invariant underKp.
Big finite place
is anyplace
p at whichNp
=#Op/mp
C where Cdepends
on G nd on k.1 want to thank Prof.
Ilya Piatetski-Shapiro.
Hesuggested
thisprob-
lem to me and gave me many advices
during
the work.Part 1. Case of G =
GL",
k =Q
,We prove the main theorem first in this case because of two reasons.
First,
theproof
in thegeneral
case isessentially
the same, but includessome technical details.
Second,
the intermediate results of this case areneeded in the
general
case.NOTATION: B is the standard Borel
subgroup,
al’...’ an-l isimple
roots, Xl’.." X n -1 the fundamental
weights.
For each X,, there is acharacter 03BCi:
GA ~ R*,
trivial onGk,
s. t.|~l03BCi| is
trivial on the centre.Let K be the standard maximal
compact subgroup.
We have the Iwasawadecomposition GA = BA · KA.
If X
is analgebraic
characteron B,
we canconsider |~| 1
as a functionon
GA, using
the Iwasawdécomposition, ! 1 X (bk) 1 = 1 X (b) 1.
Recall our definition of the Hecke
ring H( Gp ).
It consists of allcompactly supported
smooth functions onGp. Multiplication
isgiven by
convolution. If K’ is an open
compact subgroup
ofGp,
we can defineHK’(Gp)
as thesubring consisting
of all two-sided K’-invariant functions.If g
E Gp,
we can define an elementf 9 e HK’(Gp), by
Here p
is the standard Haar measure.(The
measure of maximalcompact subgroup
is1).
We have a
decomposition
K’gK’ = U gl K’ (disjoint union)
Since K’ is
compact
and open, the union is finite. Iff
is any smoothK’-invariant function on
G,
orGA,
the action off g
onf
isgiven by
We recall some facts about fundamental domains. For c >
0,
setThese sets are called
Siegel
domains.THEOREM 1: There is
co > 0,
s. t.GA=GQ.a(co)K. Any a (c)
whichsatisfies
this condition is called afundamental
domain. Wefix
co to be s. t.Q ( co )
is afundamental
domain.For each C >
0,
letBQ
acts onMc from
theleft,
and thequotient
iscompact,
modulo thecentre.
Now we can state the main theorem.
MAIN THEOREM : Let
f
be afunction
onGQ B GA s. t.
(1) f
is smooth andKp-invariant,
andtransforms by
a character under actionof
the centre.(2) f is
Heckefinite
atplace
p.Let
L ( c )
=maxg - Mc 1 f (g) 1
-Iflp à C,
where C is some constant, whichdepends only
onG,
thenL ( c)
has a moderate
growth
as c - oc, t. i. there are constantsAl, A2, A3,
s. t.L(c) A1 · cA2 for c > A3.
We need one
simple property of
thedecomposition GA
=GQ - a (co) -
K.LEMMA 1: Let
b, b’ E BA, b’ = q. b. k,
whereq E GQ,
k OE K. Let X be adominant
weight. Then,
Here W is the
Weyl
groupPROOF : We shall first prove the case
of X
= X n -1· since dent b’|= |1 det b 1
,it is sufficient to
show,
that|b’n| min |bl|,
wherebl, bl
are thediagonal
entries
of b,
b’. Letb1, ..., bn
be the row vectors of b. It is easy to see, thatLet j
beminimal,
s.t.qnj ~
0. Since b is uppertriangular,
So
So,
the case of x = ~n-1 isproved.
Now,
let us use therepresentation
g ~n-1g.
Sincethe case x = Xl, be follows from the
previous
case. Let now X be any dominantweight.
Consider therepresentation V(~)
withhighest weight
X.
Using
thisrepresentation
we see, thatwhere ~1
is someweight
in therepresentiation V(~).
It can beeasily
seen, that there exists w E
W,
s.t.We need some
properties
of Heckeoperators.
THEOREM 2:
(1)
Let a, =diag(p-1, ..., p-1, 1,...,1) (i
timesp-1).
LetKaiK=
U
bjK
be adisjoint
uniton withbj
EBp.
Then eachbj
has ieigenvalues
withabsolute value p and n - i
eigenvalues
with absolute value 1.Among them,
there is
only
one whosefirst
ieigenvalues
have absolute value p. This element lies in aK.(2) If
g,g’EGp,
then g EKg’K ~ for
allj,
the maximal absolute valueof j . j
minorsof
g isequal
to thatof g’.
This theorem is well-known and we shall not prove it. We use this theorem in the
following formulation.
Let us denoteby A +
the setof
alldiagonal matrixes,
absolute valuesof
whoseeigenvalues
are notincreasing.
THEOREM 3:
Let
a E A +,
letKaK = aK ~ (~bjK)
be adisjoint decomposition
withbj ~B.
(1)
Let X be any dominantweight,
and w EW any
elementof
theWeyl
group.
Then,
(2) Suppose
thatB:I,
s. t.1 03B1l(a)| > 1,
we havey,/X,
t is a dominantweight. Then,
PROOF 1:
(1)
We canwrite X
as aproduct
of fundamentalweights,
andsince both sides of the
inequality
armultiplicative
in X, we can assumethat X = X 1 for some i.
Then |~(a)|
is the maximal absolute value of ai X i minor of a,
and ! |w~(bj)|
is the absolute value of some i X i minor ofb.. Since bj
EKaK, (1)
now follows from Theorem2, (2).
(2)
We can write a as aproduct
of a0 · c -03A0anii,
where a o EK n A,
c lies in thecentre, a
1 are as in Theorem 2and nl
0. For a = a o - c the theorem is trivial because KaK = aK.So,
suppose thata = a’ · ai, a’ ~ A+
and the
theorey
is true fora’,
and let us prove the theorem for a. LetSince KaK c Ka’K.
Ka, K,
Since
bl ~ aK, b,
lies in one of the classesb’jalK
ora’b§k
orb;bJK.
It iseasy ’to see, that if
bl ~ b · K,
then|~(bl)|=|~(b)|.
.Since |~| 1
ismultiplicative
onB,
it isenough
to prove, that(i) |~(a’)|>|~(b’i)|
(2) |~(ai)|>|~(bij)|.
since X and a
satisfy
second condition of thetheorem,
X and a’ alsosatisfy
this condition.So, (1)
is checked.Also,
from second condition wehave: X = Xi -
X’,
whereX’ is
a dominantweight.
Frompart (1)
of thetheorem, |~’(ai)| |~(bij)|.
Frompart (1)
of theorem 2 we have thatNow,
we can prove the main theorem.We
assumed,
thatf
is Hecke-finite at p. Letf, = f,..., fN
be thebasis of the finite-dimensional space that
f
spans under the action of the Heckering HKp (Gp ). They
all areKp-invariant
from theright.
Recall our sets
M’,
which were defined atbeginning
of thepart.
Letus define
L’( c) exists,
sinceBq BMC
iscompact,
modulo the centre. We shallshow,
that there are constants cl, c2, C3 s.t. for c c3.,L’(c) max(c1L’(c/c2), L’(c/2)).
Here cl, C2depend
on p, and this will prove the theorem.Furthermore,
we can take C2= p/A’,
where A’ isa constant. Let us estimate
L’(c),
with c » 1.Let us take
g E Mc, g ~ Mc/2,
g = b. k.Since Ji
areKp invariant,
wecan assume
k p
= 1.Since
03A0 1 Xi (b) |>>1,
there is somesimple
root ai s.t.|03B1l(b)| »
1.We use the Hecke
operator T
=Kal K.
IfKalK = ai KU (~blK),
wehave
so
In order to prove our
estimate,
it is sufficient tocheck,
that everyargument
in theright
side can be written as q ·g’ with q E GQ
andg’ ~ MCIC2:
It is easy to see, that
ga-1l ~ MC/p.
Let us write
ga l lbl
= q ·g’, g’ E 03C3(c0) ·
K.From Lemma
1, 1 XK(g’) max 1 (WXK )(ga; lb/) 1. (although g’, gai ’b,
do not lie in
B,
wealready defined ! 1 X |
on the groupG).
LEMMA 2: A doesn’t
depend
on p.PROOF:
(i)
Sincegp E B,
We can write
Case 1: nl > 0. In this case,
is
bounded,
so the assertion isproved.
and |03B1K(g)|
are bounded frombelow,
sinceg ~ 03C3(c0) · K,
this expres- sion is bounded from above.Since ,
By
Theorem3,
(ii) Again,
we writeWe have two cases:
Case 1: n
>
0.Then,
as we sawbefore,
Case 2 : n = 0. Then wX = ~l.
So,
we needonly
to check thatThis is
proved
in Theorem3, (2)
Hence,
we can takePart 2. Notation and basic facts
If k is a number
field,
wealways
normalise it’s absolute valuesby
thecondition,
that theproduct
formula should besatisfied,
and at any non-archimedianplace
the value group must begeneratd by
the numberof elements in the residue field.
Recall the
following
facts( 12
Let S be a maximal
split
torus.Let ~
be the rootsystem (possibly non-reduced)
relative toS,
and ai, ... , ai a base. We shall call ai thesimple
roots. Let B be the minimalparabolic subgroup
relative to thebase
(03B81,..., a,).
Let Z be the centralizer of ,S inG,
and let K be amaximal
compact subgroup.
We have the Iwasawadecomposition GA
=BAKA.
Let
k
be a finite extension ofk,
in which G issplit,
and letSI
be amaximal torus of
G()
which containsS().
If a is a root of
G()
relative toSI,
then the restriction of a to S is a character from S to k. There is a base1,..., êK
inG ( k )
relative toSI,
s.t. restriction of each
i
to S is either apositive
root or 1.Let h
be the Borelsubgroup
ofG()
relative to the baseal’’’’ aK.
Let
be a maximalcompact subgroup
ofG()
which contains K. Wehave G (A=A·A.
For each
simple
rootâi,
there is a copy ofSL2()
imbeded inG(),
whose standard
unipotent subgroup
coincides with the root space, corre-sponding
toi.
LetHl c G()
be the standard maximalcompact
sub- group of this copy.We can find a finite set 1 of
places
p, s.t.|Hl|p ~ K.
forp OE
2.Let 2 be the set of restrictions
ouf 2
to k.We defineSiegel
domainswhere
Zo
is acompact
subset inZA
s.t.ZA
=ZQ · Z0 · SA,
and U is theunipotent
radical of B.THEOREM 1 * : There is a constant co >
0,
s. t.for
0 c co. For theproof,
see,[3].
Any
suchQ(c)
will becalled
thefundamental
domain. LetU
be the Liealgebra of U,
andY
cU
be thesubspace generated by
root spaces withrespect
toS,
whose roots are ai, and let Xi denote the determinantof
theadjoint
actionof
B inVi.
If
X is anyalgebraic
characterof B,
itgives
a characterof B,
and afunction 1 X 1
asG()A.
Restrictionof
thisfunction
toGA satisfies
Finally, if
p is non-archimedianplace of k,
we denoteby 1 p 1
thenumber
of
elements in the residuefield of
p.We now state the main theorem.
Again,
we introduce the setsSk - Uk
acts on Mcfrom
theleft,
and thequotient
iscompact,
modulo thecentre.
MAIN THEOREM
(FOR
GENERALCASE) :
Let
f
be afunction
onGk B GA
s. t.(1) f is
a smoothfunction
onGA
andKp-invariant for
someplace
p.(2) f transforms by
a character under the actionof
the centre.(3) f
isHecke-finite
at p.If 1 p Cl,
whereCl depends only
on G andk,
thenOf
course,max g E MC |f(g) 1 exists,
since,SkUk BMc
is compact modulo thecentre.
We shall now
generalize
theproof of
caseGLn(Q).
First we prove the
generalizations
of Lemma 1 and Theorem 3.LEMMA 1*:
If b,
b’ EBA,
b’ = q - b.k,
q EGk,
k EKA,
X is a dominantweight
overk,
W theWeyl
group overk,
thenHere b’, b
are considered as elementsof G(), an 1 xl, w~1
aredefined
on
G ( k )
as wasexplained before.
PROOF: In
fact,
the assertion is aboutG(),
so we can assume, that G issplit
and k =k.
LetV(~)
be the irreduciblerepresentation
withhighest weight
X. If g EG,
we shall denoteby g
itsimage
inGL(V(~)). Also,
foreach
weight
X 1 ofrepresentation V(~),
there is defined the standardweight ~1
ofGL(V(~))
Let
KI
be a maximalcompact subgroup
inGZ(V(~))A
which con-tains the
image
of K. LetKo
cGL(V(~))A
be a standard maximalcompact subgroup
relative to a basis in which S actsdiagonality.
LetBo
be the standard Borel
subgroup containing
B.Let g = q · b.
Then,
there is k’ EKo,
s.t.gk’
EBo. Also, gk E Bo.
Weknow from Lemma
1,
thatwhere M is the set of all
weights
ofV(~).
It is easy to see, thatQ.E.D.
THEOREM 3*:
Let p ~ E.
Let
w
bean element of the Weyl
group overk,
and X a dominantweight
over
k.
(1) |~(s)| IwX(bi)l.
(2)
Let now, X o bethe
determinantof
the actionof
B on the spanof
those root spaces
Va
orwhich 1 a(s) >
1.Suppose
thatX/Xo
is adominant
weight.
ThenPROOF:
Again,
the theorem is aboutG(),
so we can assume that G issplit.
(1)
Use therepresentation
withhighest weight
X.(2)
We need a lemma.LEMMA: Let b E
B,
and supposethat |03B1i(b)|
1.Then,
there is b’ E KbK ~ B s. t.PROOF: We shall find such b’ in
HibHl
~ B. First we seek for b’ which satisfies(1).
Then thisproblem
reduces to the case G =SL2,
an this iseasy.
Now, Hi
is contained in theparabolic subgroup
on whichXj
is defined as acharacter, if j #
i.Since |~j|Hl=1 (since Hi
iscompact)
Now, take bi
and supposethat ! ~(bi) || 1 X(s) 1. Using
theLemma,
weget
asequence bl
=bi, b2,...,
which canstop
at some bn if|03B1j(bn)| 1~j.
Since one of the characters
|~j| always
growsat 1 pl
from bn tobn+1,
and on the otherside |~j(bk)| | ~j(s)| by part
1 of thetheorem,
this sequence must
stop. So,
there is some bns.t. | 03B1j(bn)| 1B:1 j.
If
|~(bi)|~(s)| then part 1. If |03B1;(s)|>1, then |~/~j 1 is dominant, by assumption that |~/~0|
is dominant. Sine|~j(bn)||~j(s)| for all j, |~j(bn)|=|~j(s)| if |03B1j(s)|>1. Weight
~2j/03B1j
isalways
dominant or 1.So,
Let
x’
be a dominantweight
s.t. everysimple
root entersx’
withpositive
coefficients. Sincewe have
We use now any faithful
representation
of G in someGLN
anTheorem 3 to show that bn E Ks.
Suppose that b¡ =1=
b’. Then we used somesimple
rootaj
s.t.|03B1j(bn-1)|
1 and the lemma toget
bn. There are twopossibilities.
1) 1 aj(s) =
1.Then, by
the firstpart
of thelemma,
1 03B1j(bn)|
> 1_1 03B1j(bn)| > |03B1j(s) 1
contradiction.2) |03B1j(s)| >
1.Then,
again
contradiction.Q.E.D.
Now,
we can prove the main theorem. The results which we used incase of
GLn(Q),
that is Lemma 1 and Theorem 3 werealready
gener- alized.We assume
that p OE E,
and we choose a basisf, = f, f2,...,fn
of thespace which
f
spans under the action of the Heckering.
We estimateWe prove that
L(c) max(CL(c/c2), L(c/2)),
where c2 can be chosengreater
than 1f or p
» 1.References
[1] A. BOREL and H. JACQUET: Automorphic forms and automorphic representations. Proc.
of Symp. in Pure Math. 33 (1979) 189-202.
[2] A. BOREL: Linear algebraic groups. Proc. of Symp. in Pure Math. 9 (1966) 3-19.
[3] A. BOREL: Reduction theory for arithmetic groups. Proc. of Symp. in Pure Math. 9 (1966), 20-25.
(Oblatum 4-11-1983 & 6-11-1985) Department of Mathematics Tel Aviv University
Ramat-Aviv Israel