A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
M IHNEA C OL ¸ TOIU
On hulls of meromorphy and a class of Stein manifolds
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 28, n
o3 (1999), p. 405-412
<http://www.numdam.org/item?id=ASNSP_1999_4_28_3_405_0>
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On Hulls of Meromorphy and
aClass of Stein Manifolds
MIHNEA
COLTOIU
(1999),
To the memory of my friend G. Lupacciolu
Abstract. If X is a Stein manifold and K a compact subset one may define the
meromorphy hull of K in two different ways: with respect to principal hypersur-
faces or to arbitrary hypersurfaces. It is shown that the two definitions agree for every compact subset K of X if and only if the following topological condition
on X is satisfied: Hom(H2(X, Z); Z) = 0. It is also shown that this condition is
equivalent to: for every hypersurface h C X and every relatively compact open subset D C C X there exists f E such that h f1 D = {x E = 0} .
Finally, several examples are provided, which show that the topological con-
dition Hom(H2 (X , Z) ; Z) = 0 is sharp.
Mathematics Subject Classification (1991): 32A20, 32E10.
0. - Introduction
Let X be a Stein manifold. Then it is known
(see
e.g.[ 10],
p.181)
that thesecond Cousin
problem
on X can be solved for anarbitrary
divisor if andonly
ifH2(X; Z)
= 0. On the other hand one may consider the strong Poincareproblem
on X:
given
ameromorphic
function on F on X findholomorphic
functionsf, g
on X such that the germs
fZ,
gZ are relativeprime
at anypoint
and F =f /g.
As in the Cousin second
problem,
the strong Poincareproblem
can be solvedfor every
meromorphic
function F on X if andonly
ifH2(X; Z)
= 0(see [13],
p.
250).
Therefore there is a strong connection betweenglobal properties
ofmeromorphic
functions on X and thepurely topological
invariantH2(X; Z).
A weaker condition thanH 2 (X , Z)
= 0 isH 2 (X , Z)
is of torsion. One mayeasily
see
(Proposition 2)
that this isequivalent
to: everyhypersurface
h C X(closed analytic
subset of codimension1)
can be definedglobally by
oneequation
i.e.. there exists
f
EO(X)
such that one hasset-theoretically
h ={ f
=0} .
In this paper we
study
a class of Stein manifolds X whichsatisfy
a weakercondition than
H 2(X, Z)
is oftorsion, namely
we consider thetopological
Pervenuto alla Redazione il 24 giugno 1998 e in forma definitiva il 25 maggio 1999.
406
condition Hom
(H2(X; Z); Z) =
0. This condition is related to thestudy
ofhulls of
meromorphy
of compact subsets K c X.When K c X is a compact subset one may define in a natural way
(see [8], [9])
thefollowing
two hulls:h K
={x
EX ~ I
everyhypersurface passing through x
intersectsK }
H K
={x
EX ~ I
everyprincipal hypersurface passing through x
intersectsK } Obviously h K
CH K
and it is known[8]
thatthey
are compact subsets of X.When X - C" and it ib called the ratiunal iaivcx hull
(see [16]).
We show
(Theorem 1)
that on a Stein manifold X the conditionis
equivalent
to thetopological
conditionIt is also
equivalent
to each of thefollowing
conditions:y)
For everyhypersurface
h c X and everyrelatively
compact open subset D GGX there existsf
EO(D)
such that h n D ={x
ED I f (x )
=0} (in
other words the
hypersurfaces
on X can bedefined, set-theoretically, by
oneequation
on compactsubsets).
3)
Forevery ~
EH2(X; Z)
and everyrelatively
compact open subset D C C X there exists apositive integer
m,depending on ~
andD,
such thatm~ I D=
Z)
is of torsion on compactsubsets).
Finally
wegive examples showing
that the statement of Theorem 1 issharp:
namely,
there exists Stein manifolds Xsatisfying
thetopological
conditionHom
(H2 (X ; Z); Z)
= 0 butH2 (X ; Z)
is not of torsion. Inparticular,
on thesemanifolds there exists
hypersurfaces
which cannot be definedglobally by
oneequation
butthey
can be defined on each compact subset of Xby
oneequation.
AKNOWLEDGEMENT. I wish to thank G.
Lupacciolu
who raised me in autumn1995,
when I wasvisiting
theUniversity
of Rome "LaSapienza",
thequestion
wheather there exist Stein manifolds X and
compact
subsets K c X such that ‘hK
K. This was thestarting point
inwriting
this paper. In want also to thank my friend andcolleague
G. Chiriacescu forhelpful
discussions on thealgebraic
results needed in thegiven examples,
inparticular
for the references[1] ]
and
[12].
1. - Proof of the results
Let X be a Stein manifold of dimension n. A closed
analytic
subset h c Xof pure dimension
(n - 1)
is called ahypersurface.
h is called aprincipal hypersurface
iff there existsf
EO(X)
such that one hasset-theoretically
h ={ f
=01.
For a compact subset K c X we consider the
following
two hulls:{x
EX ~ I
everyhypersurface passing through x
intersectsA"}
H K = {x
EX I
everyprincipal hypersurface passing through x
intersectsK { They
are compact subsets of X[8] (p.
50 and p.52).
Let us recall also the
following
result[5]
LEMMA 1. Let X be a Stein
manifold,
Y C X a closedcomplex submanifold
and denote
by
N =Nylx
the normal bundleof Y
in X.Then there exists an openneighborhood
Uof
the null sectionof
Nbiholomorphic
to an openneighborhood t/i of Y in
Xby
cp :U ~ U1
such that theimage of
the null sectionby
cp is Y .Now we can prove:
PROPOSITION 1. Let X be a Stein
manifold
and assume thathk= Hkfor
every compact subset K C X. Then the Kroneckerproduct H 2 (X ; Z)
xH2 (X ; Z)
--+ Zis the null map.
PROOF. Since X is Stein it follows that
H 1 (X , C~* ) "’ H 2 (X , 7 ) .
On theother hand every line bundle L on X has a section s whose zero set is smooth
(see [9],
p.883)
and this section defines apositive
divisor whichcorresponds
to L. Therefore it is
enough
to show that the Kroneckerproduct c(h),
a > =0,
where h is a smooth and connectedhypersurface, c(h)
EH 2 (X ; Z)
denotesits Chem class and a E
H2 (X ; ~) .
In factc (h ) , a
> is the intersection numberh,
a > of h and a and can be definedchoosing
a smooth2-cycle
a(representing a) intersecting
htransversally (see [7],
p.61).
By
reductio ad absurdum assume that z =h,
a> ~
0. Let N = bethe normal bundle of h in X.
By
Lemma 1 there exists an openneighborhood
Uof the null section of N
biholomorphic
to an openneighborhood Ul
of h inX
by cp : U ~ Ui,
such that theimage
of the null sectionby w
is h. Wechoose a hermitian metric on N such that
{ w
EN 1 {
c U and define V = EN I 1 } ) .
Then V is a closedneighborhood
of h and0
by
Thom’sisomorphism H2 (X , X B V ; ~) "-’
Z. Infact,
ifXo E h
is any
point
andBxo = B (xo, 1)
C V denotes thecorresponding
closed ball with center xo and contained in the fiber thenBxo
can be considered as a0
2-simplex s
of X withboundary
contained inXBV,
so it defines an element0
S E and s is a generator. In what follows we fix some
point
xo E h.408
Consider the exact sequence:
and let us remark that
i (a) ~
0(here i
denotes the naturalhomomorphism
at0
homology
inducedby
the map(X, 0)- (X, X B V )
which is theidentity
onX).
0
Otherwise a = u + v with u =
boundary
inX, v =cycle
inX B V
and it wouldfollow that
z = h , a > = 0
since v does not meet h. Thereforei (a )
= h9with k E
7 B{o}.
We see thatwith al = chain in
X B V
and b=boundary
in X(and
in fact h =z).
Let us define the compact set K = supp
(a 1 )
UBy
ourassumption
hk= H K.
Butxo E h and
h fl K = 0(empty set),
so there exists aprincipal hypersurface H = { f = 0}, f E O(X)
with xo E H and H n K = 0. We have H, a - hs >=H,
a + b > where , > denotes the intersection number.On the other hand H, a >= 0 since H is
principal,
H, b > = 0 since b isa
boundary, H,
ot 1 > = 0 since Hn supp (a 1 )
= 0. ButH, s > ~
0 becauseH n
a Bxo = 0, H (xo) =
0 and onBxo
we have acomplex
structure(see [7]
p.
63, [9]
Lemme5.3).
Weget h
= 0 which is a contradiction. Thereforeh , a
> = 0 and theproof
ofProposition
1 iscomplete.
THEOREM 1. Let X be a Stein
manifold.
Thenthe following
conditions areequivalent:
1 ) ~ K = H K for
every compact subset Kof
X2)
Hom(H2 (X ; Z) ; Z)
= 03)
Forevery ~
EH2(X; Z)
and everyrelatively
compact open subset D C C X there exists apositive integer
m =m (D, ~ )
such thatm~ ~ D =
0.4)
For everyhypersurface
h C X and everyrelatively
compact open subset D CC X there exists aholomorphic function f
E such that one has set-theoretically
h n D =If
=OJ.
PROOF.
1) ~ 2)
It is known
([6],
p.132)
that the naturalmorphism (induced by
the Kro-necker
product) H2 (X ; Z)
-~ Hom(H2(X ; Z); Z)
issurjective.
Therefore everyu E
Hom(H2 (X; Z); Z)
is of the formu (a)
=~,
a > forsome ~
EH2 (X ; Z).
By Proposition
1 it follows that Hom(H2(X ; Z); Z)
= 0.2) 3)
Let ~
EH 2 (X ; ~) , D
C C X arelatively
compact opensubset,
and we have to find apositive integer
m such thatm~ ID=
0. We may assume that theboundary
of D issmooth,
therefore thehomology
groups of D arefinitely generated.
Wedefine 03BE1 = 03BE I D E H 2 (D; Z). By
ourassumption
>= 0 forevery a
EH2(D; Z).
Since thehomology
groups of D arefinitely generated
it follows from
([6],
p.136) that §i
is a torsion element ofH2 (D; Z).
3) 4)
Let h c X be a
hypersurface
and D c c X arelatively
compact open subset. We may assume that D isStein,
thereforeH2 (D; Z) ~ H 1 (D, 0*) .
hdefines a line bundle L E
0*)
which has a canonical section S Erex, L)
with h =is
=0} . Define ~ = c(L)
EH 2 (X ; 7~)
the Chem class of L.By
our
assumption
there exists apositive integer
m withm~
= 0 on D. Thereforeis trivial. Also sm E
r(X, Lm)
andf = sm I D
is aholomorphic
functionon D with h n D =
{ f
=0}.
4) ===} 1)
Let K C X be a compact subset and
xo E X
such that there exists ahypersurface
h c X withXo E h and
h n K =0. We have to find aprincipal hypersurface
H C X withxo E H and
H = 0. Let D C C X be aRunge
domain with K
U {xo }
C D.By
ourassumption
there is aholomorphic
functionHi
EO(D)
with{ Hl
=0}
= h n D(set-theoretically).
Let 80 =
x
E > 0. Since D C X isRunge
we canapproximate
Hl on K U fxol
C Dby Hl
EO(X)
suchthat Hl (x ) - Hl (x ) ~ ~o /4 if X
E Kand IH1(xo)1 ] = IH1(xo) - Eo /4.
DefineH (x )
=Hl(X) -
Then
obviously H (xo)
= 0 andH (x) ~
0 if x E K.Thus our theorem is
completely proved.
COROLLARY 1. Let X be a Stein
manifold
such thatH1(X; Z), H2 (X ; Z)
arefinitely generated (e.g.
X isaffine algebraic).
Then
the following
conditions areequivalent:
1)
every compact subset K C X .2) H2 (X ; Z) is of torsion
3)
For everyhypersurface
h C X there existsf
EO(X)
such that one hasset-theoretically
h =if
=01.
PROOF. Since
Z), H2 (X ; Z)
arefinitely generated
it follows from([6],
p.
136)
that we have a(non-canonical) isomorphism:
where
T1
denotes the torsion part ofHI (X ; Z).
Now the
corollary
followsimmediately
from(*)
and Theorem 1.PROPOSITION 2. Let X be a connected Stein
manifold.
Then thefollowing
twoconditions are
equivalent:
1) H2(X; 7~)
isof torsion
2)
For everyhypersurface
h C X there existsf
EO(X)
such that one hasset-theoretically
h =f f
=OJ.
We first show that
1) ~ 2) .
Let h c X be a
hypersurface
and let L EH 1 (X, 0*)
be thecorresponding
line
bundle,
therefore there is a canonical section s Er(X, L)
with h =ts
=OJ.
Since X is Stein
H2 (X ; Z) ~ H 1 (X, 0*),
hence there is apositive integer
m410
such that Lm is trivial. sm is a section in
rex, Lm)
and if we setf =
smthen
f
is aholomorphic
function on X such that h ={ f
=01.
We prove now that
2) ~ 1 ) .
We recall the
following
result(see [3]):
If L is a line bundle over aconnected Stein manifold X then there is a section s E
r (X, L)
such thatIs
=0}
is irreducible(in
fact the set of sections S Er (X, L )
withis
=0}
irreducible is dense in
r(X,L)).
Let
now ~
EH2(X;Z) 2---- H’(X,0*)
and let L EH1(X,O*)
be thecorresponding
line bundle. We choose s Er(X, L)
such that h =Is
=0}
isirreducible. If we consider
(h)
as a divisor there is apositive integer n
suchthat L =
n (h)
(n is the order of salong h,
which is well defined because h isirreducible).
On the hand there existsf
EO(X)
with h ={/ = 0} (set- theoretically).
If m is the order off along
h thenm (h) -
0. Therefore Lm is the trivial line bundle andconsequently m~ =
0. So we have showed thatH2(X; Z)
is oftorsion,
and theproof
ofProposition
2 iscomplete.
REMARK 1. There is a
surjective homomorphism
group(see [6],
p.132)
from which it follows that:
We shall
give examples
of Stein manifolds X such thatHom(H2 (X; Z); Z) =
0 but
H2 (X ; Z)
contains nontorsion elements. Of course, for such Stein man-ifolds
X, every ~
EH 2 (X ; Z)
is of torsion on compactsubsets,
i.e. for every D CC X there is apositive integer
m =m(D, ~)
withm£ =
0 on D. But itis
possible
that m -~ oo as it will be shownby
our nextexamples.
EXAMPLE 1. In
[ 11 ]
it isgiven
anexample
of a Stein domain X C(~2
withZ) = Q (rational numbers)
andH2 (X ; Z)
= 0.Let us
study H2X ; Z).
There is an exact sequence([4],
p.153):
Therefore we get
H2 (X ; 7~)
=Ext(Q; Z). Clearly Ext(Q; Z)
isa Q
vectorspace, so
every ~
EExt(Q; Z))(0)
is a nontorsion element. We shall prove thatdim Q Ext(Q; Z)
= 00.If p
is aprime
we denoteby
P =the additive group of those rational numbers whose denominators are powers of p and thequotient Z/P.
There is a groupisomorphism (see [12],
p.6): Q/Z ~
Itfollows:
Hom(Q; Q/Z) = Hom(Q; (DHom(Q ;
Now for every
prime
p 0 since we have asurjective
homo-morphism Q -
obtained from thecomposition
of twosurjective
homo-morphisms Q - -pr Z( p°).
If follows thatdim Q Hom(Q; Q/Z)
= 00.From the exact sequence 0 --~
7~ ~ ~ -~ ~/7~ -~
0applying Homz(Q; .)
we get the exact sequence
of Q
vector spaces:Since
Hom(Q; Z) = 0, Hom(Q; Q)
has dimension 1 asa Q
vector space anddim Q Hom(Q; Q/Z)
= oo it follows thatdim Q Ext(Q; Z)
= oo.EXAMPLE 2. For
each integer m a
2 consider the map cp : D -~ is the closed unitdisc,
i.e. D =f z
E1) given by
=(zm , (1 -
where
JR4
is identified withC2
in the usual way. Thenw D
siinjective
andw laD
has
degree
m. _Since a D = if we set
Km
=cp(D),
thenKm
is obtainedfrom S
1by adding
a two cell
by
a map ofdegree
m(see [6],
p.83).
It follows from([6],
p.89)
that
Z) = Z/ m Z
andZ)
= 0.Consider in
JR4
an infinite real lined,
and on d we add the compactsKm
such thatKm
n d = apoint Pm, Km
0 ifm ; n and
islocally
finite.Thus we get a
locally
finite cellularcomplex
M c}R4.
One mayeasily
see thatZ) =
andH2(M; Z)
= 0.From the exact sequence:
we get
H2(M; Z) = Z).
From([1], § 5, Prop.
7, p.89)
TIExt(Gm; 7~)
andby ([4],
p.148) Ext(Z/mZ; Z)
=Z/mZ.
We deduce that
H2(M; Z)
= We take now and openneighborhood
U of M in
R4
such that M is a deformation retract of U.Considering
theinclusion
R4
cC4 given by
Y1 = ... = y4 - 0 where + are thecomplex
coordinates onC4,
there existsby [14]
a Stein domain X CC~4
such that X nR 4
= U and U is a deformation retract ofX. We
haveH 2 (X ; Z)
=and
H2 (X ; Z)
= 0. The element(T, 1, ... 1, ... ) (taking I
on all factors of the infiniteproduct)
is a nontorsion element ofH 2 (X ; Z).
EXAMPLE 3. In
examples 1)
and2)
we haveH2(X; Z) =
0. But it ispossible
to find X withH2(X ; Z) # 0, Hom(H2(X ; Z); Z) =
0 andH2 (X ; Z)
has nontorsion elements. To see this we
replace
inexample 1)
Xby X
1 =X x
{z
EC 1
0H I 1 { .
Thenby
Kiinneth formulaZ) = Q
andH1(X1; Z)
= Z fl9Q.
If follows thatHom (H2 (X 1; Z) ; Z)
= 0 andZ) = Ext(H1 (X1; Z) ; Z)
fl9Q; Z)
=Ext(Q; Z) 1=
0.Similarly
we mayreplace
X inexample 2) by
itsproduct
with{z
EC 1
0N 11.
EXAMPLE 4.
By [15]
it ispossible
to construct, for every countable torsion free abelian groupG,
a compact connected subset K cR 3 (in
fact acurve)
412
such that G and
H2 (II~3 B K ; ~) -
0.Taking
G such thatExt(G; Z)
contains nontorsion elements and X CC3
a Stein open subset such that andJR3BK
is a deformation retract ofX,
one gets as aboveexamples
of Stein manifolds X withHom(H2 (X; Z); Z)
= 0 butH2 (X ; Z)
hasnontorsion elements.
~
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Institute of Mathematics of the Romanian Academy
P.O. Box 1-764 RO-70700 Bucharest, Romania mcoltoiu@stoilow.imar.ro