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Estimating temperature gradients and dew point temperatures for

building envelopes

Scheuneman, E. C.

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ESTIMATING TFNPEBATURE

GRADIENTS

AND

DEW

POINT

TEMPERATURES

FOR BUILDING M E L O P E S

Division

of Building

Research, National

R ~ S ~ T C ~

Council of

Canada

(3)

ESTIMATING TEMPERATURE GMDIEMTS AND DEW PQINT TEMPERATURES FOB

BUILDING

ENVELOPES

E.C. Scheuneman

It is useful and often essantfal t o h o w the temperature a d moisture conditions that exist throughout buildlng assemblies and

components. Such temperature and mofsture information may be utilized when d e s i g d u g a

.new

building, investigating problems

in

an existing

building, and planning t o retrofit a building. The temperature gradient and smkr/winter temperature extremes are of

ten

useful data to

d e t e d n e the materials t o be used in a building envelope (exterior

s h e l l ) . A knawledge of air-mo$~ture/temperature conditions and

relationships I s essential in locating the vapour barrier d t h respect

to other components in the building assembly.

The following sections give simplified versions of temperature and dew point calmlations that are generally useful for a variety of

purposes. Results

from

these calculations p l i l l be on the conservative s i d e , that is, they may indicate a problem whereas a more accurate analysis would show no problem. For such borderline cases or for c o q l i c a t e d and c r i t i c a l problem, it m y be necessary t o do a more precise analysia or consult a specialist in thermal analysis.

TEMPERATURE Gl?ADmm

During c o l d weather the temperature at the interior surface of the building envelope, except for w i n d m s , will be close to t h e room

temperature. Moving outward through t h wall

or

ceiling the temperature

becomes increasingly colder u n t i l 1 t reaches the outdoor tersgerature j u s t beyond the exterior fFnish. It: is poesXble to calculate and chart these tenperature changes through the various building caponents; this is

known

as the temperature profile or gradient. During warm or hot

weather the outdoor temperature may be greater than the indoor temperature, h t the same general rules and procedures apply.

( 5 ) Temperature Change for Components

Before performing such calculations,

we

need t o examine b r i e f l y

t h e basic relationshfp between thermal resistance of the building components and temperature drop {change) through each component.

The information in t h i s Note is based on reports given by DBR personnel

(4)

If we assttme that heat flows through each component under steady-

s t a t e parallel heat f l o w conditions,

then

the follawing f o r m l a can be uaed t o calculate the temperature change across each component.

where

AT =

temperature change across a component R = thereal resistance o f the caqonent

%

= total thermal resistance of a l l cornpadents

ATT = total temperature change from interior to exterior

This assumption of steady-state condition means that the calculation w f l f be subject to errors, especially for rapidly changing outside a i r

temperatures. Nonetheless, i t provides useful information.

The forms, Ffgures 1

and

2, have been designed to a s s i s t with t h e

calculation

and

visualization of the temperature p r o f i l e through the building assembly. Figure 1 is for vertfeal assemblies (such as walls); Figure 2 is for horizontal assemblies (such

as

ceilings or roofs),

(These £ o m may be reproduced t o carry out your awn s t u d i e s , ) The general procedure

i a

t o list the b u i l d i n g components in the table (left side) and draw lines representing their thickness on the graph (right slde) after choosing

a

s u i t a b l e scale. The t h e m 1 resistance values

(Bus) are found from Appendix A and used with the known interior and exterior teqexatures t o calculate the values (R, R/%, AT,T) t o

complete the cable. The temperatures are then plotted an the graph to give a p i c t o r i p l repreeedtation of the calculations. Note that. the Winter AT and T columns

are

uaed when the Exterior T is less than the

Interior T; the S m r

AT

and T columne are used when t h e Exterior

T

is greater than the Interior

T.

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(6)

TEM P E R A T U

RE

G

R A

I)

I

E N T

T A B L E

COMPONENT

G R A P H NAME

DATE

ADDRESS

ASSEMBLY

FIGURE 2

H O R I Z O N T A L A S S E M B L Y

TEMPERATURE,

OC

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We w i l l now use the simple e q l e shown in Figure 3 to follow thtough the step-by-step procedure, The results are

shown

In F i g u r e 4.

Determine the temperature gradient for the i l l u s t r a t e d wall assembly

(Fig. 3) with an interior temperature of 2 0 . 0 ° ~ and an exterior temperature of -15.U°C.

13 mrn G Y P S mrn M E T A L S I D I N G mm P L Y W O O D

Figure 3,

A

W a l l Assembly

Stew 1

List the components in appropriate sequence in t h e table (Figure 4).

Step 2

Using a ruler or other straight-edge, draw the assembly on the

graph a f t e r choosing a s u i t a b l e scale. Designate the coupanents by

number. Step 3

Using t h e appropriate data from Appendix A, f i l l in the lt column in the t-kble.

(8)

S t e p 4

Add up a l l the R's t o give

%

( 2 . 5 5 ) and enter in the TOTAL r o w at

bottom of t h e R column. Step 5

Calculate t h e ratio K/RT for each component. Total up the ratios

in this column and enter them in the TOTAL row at bottom of the R/% column. Note that t h i s total should always be very c l o s e or equal to

1.00; if not, recheck your c a l c u l a t i o n s for t h i s column.

S t e p 6

Write the i n t e r i o r ( 2 0 , 0 ° ~ ) and exterior ( - 1 5 . 0 " ~ ) temperatures in she appropriate p l a c e s under the Winter

T

column (or under the Summer T column if appropriate).

S t e p 7

Calculate

ATT

by subtracting the Exterior T from the Interior T.

Enter t h i s figure 135.0) in the TOTAL row at bottom of he AT column. (If the Exterior T is greater than the Interior T, subtract the Interior

T from t h e Exterior T . ) Step 8

Calculate AT for each component by m u l t i p l y i n g each R / K ~ times

ATT

(equation 1) and enter the figures. Note that the total of these A T ' S

should equal, or be very close ta, ATT. Lf not, recheck the calculations.

S t e p 9

F i l l in the Winter T column by adding the first component No. 1,

AT (0.4) to t h e T in the row above (Exterior T of -15.0) and p l a c i n g t h i s new T ( - 1 4 . 6 ) i n t h e row below component No. 1. Continue t h i s sequence of adding each AT to t h e T above and entering the new T i n t h e r w below. (When Exterior T is greater than Interior

T,

each AT is subtracted from the T in the row above.)

As

a check, the f i n a l

coqonent A T added to the preceding T (1.8

+

18.4 = 20.2) s h o u l d yield the Interior T (20.0) or be very close.

By glancing down t h e T column in the completed table, one sees the

temperatures on each s i d e (interface) of each component.

On the graph, mark the temperatures ( T ' s ) at each coqonenr edge

( i n t e r f a c e ) , and then draw s t r a i g h t lf nes joining e a c h p o i n t to t h e next. This completes both the arithmetic and graphic representations of t h e temperature or thermal gradient.

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(10)

( i f ) Temperature at a S p e c i f i c P o i n t and Location of a Certain Temperature

We

may want t o know

the

temperature at a specific point in the assembly (besides the fnterfaces), or where in the assembly a certain

temperature w i l l occur. Et is possible t o deternine these temperatures or points

by

using either the table or graph.

Suppose we wish to know

(1)

the temperature in the fibreglass batt 35 m from its cold s i d e and (2) where in the assembly the temperature w i l l be 5*.

(a) Graphical Method

'Phis is the easiest and quickest method. Use a straight-dge

r u n d a g vertically t o l i n e up with 35 mm from the cold side of the batt (73 mm from interior) and note the point of interaeckion with the

teqerature gradient line. This gives a value of about -lo. See vertical dashed line on Figure 4.

Use a straight-edge ruaaing horfzwtally t o line up with 5' and note the point of intersection with the temperature gradient l i n e . This gives a value of about 41 nua into the batr

from

the warm s i d e ( 5 4 ram from interior). (See dashed horizontal l i n e on F i g u r e

4.)

(b) Arithmetic Method

This method may be preferred by many as it gives more exact values

than the graphical me tho& h e f ollawf ng

f

0-1 a y i e l d s the temperature at

a

s p e c i f i c point:

where

T

= temperature at the specific po%nt

Tw

= teqerature at w a r m interface of conpoaent conLaining the specffic point

L

= distance of specific p o l n t f ram warm side of component L

T

= total thickness of component

A = temperature change across component

(11)

The following f o r m l a w i l l yield the location of a certain

temperature:

where

L

= location of certain temperature from warm side of component Ifw = temperature at: warm interface of eomp~aent containing the

specific temperature

T

= temperature at the specific point

AT

= temperature change across component

$

= total thickness of coqonent

For this e-ple dealfng with component No.

4,

we have

which yields

The above two results are t h e same as those obtafned graphically (Figure 4 ) .

Note: The temperature gradient calculations for the Table qnd the

k i t h t i c Method are s h m w i t h a precis1 on of 1 or 2 decimal places; thig is done to maintain the relatfonship between the

d i f f e r e n t Rts, R / R ~ ~ s , AT'S and T's, It is m a t h a t i c a l l y convenient with electrouic calculators t o use t h i s degree of precision. The final results of calculaeions are rounded to the nearest whole unft of degrees C e l s i u s (OC) or m f l l t ~ t r e s (mm).

As previously mentioned, the temperature gradient

calculations assume steady-state conditioa~ which means that the rasulte are usually leas accurate than the nearest whole u n i t . However, the calculated values are generally close enough to be

useful, e s p e c i a l l y when looking at extreme or worst-case

situations.

Further explanation and examples can be found

in

references 1, 2a, and 3.

(iii) Extreme Temperatures at Outer Surfaces

Qulte often the temperature of the outer surface of a b u t l d i n g assembly can be significantly higher or lower than the outside air

(12)

temp eratare. Higher temperatures result from absorption of solar (short-wave) radiation by the surface. Lower temperatures result from the surface g i v i n g o f f infrared (long-wave) radiation t o a clear n i g h t

sky or to o t h e r b o d i e s .

The following formulae have been developed to account for these

two effects on roof assemblies ( 4 , 5 ) . The references use degrees Fahrenheit (OF); this paper uses the formulae in degrees Celsius

(*C)-

They may also be used for walls that are exposed to the sky. Shaded walls would use the outdoor temperature as the e x t e r i o r surface

terrrperature.

(a) High Heat Capacity Substrate

(such as concrete under the surface material)

HIGH DAY-TIME TEMPERATURE

TS =

TA

+

42a (sunny conditions)

TS = TA

+

55a (sunny conditions p l u s reflected sunshine

from other surf aces) LOW NIGHT-TIME TEMPEUTURE

TS =

TA

- 5 (clear night sky) (b) Low Heat Capacity Substrate

(such as insulation under the surf ace mater-lal)

HIGH DAY-TIME TEMPEMTURE

TS =

TA

+

55a (sunny conditions)

TS = TA

+

72a (sunny c o n d i t i o n s p l u s reflected sunshine

from other s u r f a c e s )

LOW MZGHT-TIME TFXPERATURE

(clear night sky)

The deftnitions far the symbols are as follows: TS= temperature of surface ( O C )

TA = temperature of air (OC)

a = solar absorption coefficient (no units)

Appendix B gives a t a b l e of solar absorption coefficients for d i f f e r e n t

materzals. The value can be hfghly variable if the s u r f a c e

deteriorates, accumulates d i r t , or i s covered with water.

These extreme temperatures and temperature g r a d i e n t s s h o u l d b e u t i l i z e d when choosing materials requfred to withstand extreme

(13)
(14)

Example 2

A f l a t roof assembly built of a 100 m concrete deck (high density) with 25 mm extruded polystyrene on t o p covered w i t h built-up raaflng covered with grey gravel. Determine the extreme temperature gradients for this roof that receives no reflected sunshine for a summer high air temperature of 35% and a d n t e r low air temperature of -30°C. The following temperatures are u t i l i z e d :

-

interior T = 20°C

-

winter minimum TA = -30°C

Reace, mintmum surface temperature T = TA

-

10 giving

TS = -30°

-

lo0

= -40°C

Hence, maximum surface temperature

TS

= T A + 55a

where a = 0.75 {from Appendix

B)

giving

Since the max5mm and mfnimum temperatures occur on the surface material rather than i n the

air,

the external air f i l m is omitted from the

R,

R/RT and

AT

calculations. A t a b l e is completed and the graph is drawn

according

to the procedure described previously. The results are shown in Figure 5.

(15)

For comparison, the procedure has been carried out in Figure 6 with no surface temperature effects ( s o l i d line)

and

the graphical results f r o m

Figure 5 added (dashed lines). There is

a much

larger difference between the t w o maximum temperature gradients than between the two

m i n i m temperature gradients. This illustrates that the heating effect

of solar radiation is nuch larger than the cooling efEecr produced by long-wave radiation, as shorn also by the temperature equations. For

further explanation

and

exaqles see ref erencea 1, 2a, 3, 4 , and 5.

8 . DEW POINT TEIfFEBATURES

Relative humidity Ls the percentage ratio of the actual mount of water vapour h e l d in the air compared t o the maxtmrm I t could hold a t a given temperature. Far example, a relative humidity

CR.H.)

of 50% means

that the air is carrying o n e h a l f the total amount of water vapmr it is capable of holding at that temperature. Air with 100% R.H. has reached i t s saturation point; the water vapour I t holds will begin t o condense if the temperature drops or moxe moisture is added. The water vapour

wfll

condense as l i q u i d if T is greater than O°C or as ice crystals if

T

is

lese than O°C. The temperature a t which condensation takes p l a c e is called the "dew point" temperature.

Understanding the dew p o i n t and the moiature capacity of air is c r u c i a l to understanding condensation/moie ture problem f n bu i l d i n g a . When the temperature af air decreases, the m a d m u m amount of water vapour that the a i r can carry is reduced. For example, if air at 2 1 * C and 50% R.H. is cooled t o 1l0C, the RtR, w i l l reach 100% (the dew p o i n t ) . If the tenperature is lowered further, water w i l l condense out

of the a i r to maintan the R.H, at 100%. hferences 2b, 6 and 7 give further explanation and d e t a i l .

(16)
(17)

A

psychrometric chart (Figure 7) shaws the relationship between the relative humidity (R,E.) and temperature of air.

me

curved

lines

beginning on the r i g h t v e r t i c a l scsle i n d i c a t e the, variation o f the r e l a t i v e humidity ( X ) . The straight l i n e s running vertically

fram

the bottom borlzoatal

scale

to the saturation curve give the air temperature ( "C)

(f) Finding the Dew Point Temperature

Par a Laom value of air temperature and relative humidity (R.H.]

one can use the psychromtric chart to f i n d the dew p o i n t temperature. The procedure is as folluws:

Step 1

Determine the air temperature inside the house by using a

thermonreter (or an assumed value),

Step 2

D e t e d n e the relative humtdfty i n s i d e the house using a sling psychrometer or a hygrometer (ar an assumed value). The R.R. values

recorded by hygrometers may be in error by as rsuch as

20%

so a c a l l b r a t e d instmnment should be used.

S t e p 3

On

the psychrometric chart, locate the interior air temperature of the house an the horizontal (bottom) scale and mark the p o i n t where the vertical projection from t h i s temperature intersects the curve which represents the B.H. of the house air.

Starting at the intersection p o i n t , run a straight-edge parallel to the bottom OC scale and left to cross the curved lOOX R.H. line. The crossing point gives the dew point temperature.

(18)
(19)

Example 3

Three examples are s h m in Fl.gure 8:

3(a) The house interror a i r temperature is 2S°C and the R.B. is

60%. The dew point teqerature at: which water v a p w r w i l l

condense as l i q u i d for this situation is 16.5OC.

Water vapour w i l l condense out as l i q u i d at 10.5V

3(c) T = 17%

R.H. = 25%

Water vapour will condense o u t as ice a t the dew point

temperature of -3*C.

Cii) Finding the New B.H. After a Temperature Change

As previously noted, the capacity of a i r t o hold water vapour 3 s

different fur different temperatures. The hfgher the

air

temperature, the greater the amount of water vapour that can be held.

The procedure to f i n d the new R.H. after a temperature change is

as follows:

S t e p 1

Locate the point on the psychrametric chart that corresponds to the o r i g i n a l teuperature and relative humidity.

Step 2

U s i n g a straight-edge, p r o j e c t a horfeontal l i n e to the new

temperature. The point of intersection with the curved

R,H.

line gives Lhe new relative humidity.

(20)
(21)

Example 4

Three examples are shown in Figure 9 :

4(a)

?he household

a i r

is at; 20°C and 40%

R.H.

What is the new

R.E1. when the a i r Is cooled to 10°C? (R.H. becomes 75%,) 4(b)

T

= 2 S 0 C

R.H. = 80%

What is the R.B. when t h i s

warm,

humid air cools t o 20'C? (R.H. becomes 100% and same water condenses to maintain the R.H. at 100%-)

4(e)

T

= -15'C R.H. = 95%:

What is the R.H. when t h h c o a l outside air is brought into

the house and warmed to 20"C? {R.B* becomes 8X which is very d q .

1

LOCATION OF DEW

POINT

TEMPERATURES FOR BUILDING ASSEMBLIES Three examples are g l m n t o i l l u s e r a c e the combined use of temperature gradients with the psycbrome.tric chart to locate the dew

(22)
(23)

A double-glazed window has temperature gradients as shown in

F i g u r e 10. When t h e house T = 22°C and

R.H.

= 5 0 X , will water vapour condense on the inside glass when the outside T a -22"C?

Ue calculate the values to complete the t a b l e and draw the

temperature profile. Referring to the psgchroretric chart ( F i g . 7 ) , we

f i n d that air at 22%

and

50X R.H. has its dew point at l l . S ° C . Either rhe t a b l e or gradient shows that the inside glass tenperature is 6.6"C.

As the glass l a colder than the dew point, water vapour will condense as

l i q u i d on the wf n d w .

Since the i n s i d e glass of a window is usually the coldest surface in a room, it determines the m a d u u m R.H. that can be maintained without condensation. U s i n g t r i p l e glazing raises the inside glass temperature and, thus, the maintained R,H.

(24)

T E M P E R A T U R E G R A D I E N T

T A B L E

d

NAME

DATE

ADDRESS

ASSEMBLY

GRAPH

FIGURE 10.

E X A M P L E 5

(25)

Example 6

We have a partly-insulated wall as s h m fn Figure: 11. Where

will

water vapour condense in the wall assembly if there is no vapour

barrier? The conditions are as follows: Interior T = 18OC

Exterior T = -35OC inside R.H. = 30%

The table and profile are calculated and drawn, The psychrometric

thart reveals that the dew point temperature is 0°C- (1) Graphical Method

We can see at a glance that: O°C lies within the rack wool insulation. By drawing a horizontal line from the O 0 point on the teqerature scale, we find that 0' occure at about 22

mm

from the

Interior s i d e of t h e batt (35 mm f r o m interior surface), Arithmetic Hethcd

using $pu.ation (33,

Results from both ti) and (ii) agree.

Note: This discussion applies when the temperature og the

-

iasulation has reached

or is

colder than the dew point temperature.

Uuder steady-stalte conditions the water vapour would

continue to d i f f u s e through those tnsulatLons that have little resistance t o moisture flow; the water vapour would condense on the next colder interface such as the exterior sheathing which has a

much

larger resistance. However, the water vapour can condense i n the i n ~ u l a t i o n under norrsteady-state conditions which u s u a l l y occur more than 80X ~f each day. When the

insulation or other materiah in the assembly have a high resistance to moisture flow Cdlffusion), a vapour pressure

gradient s h w l d be drawn (see R e f erenee 71.

When

water

vapour is transported into a building assembly by

warm a i r f l o w rather than vapour diffusion, condensatton can occur within the insulation unless the velocity of the aZr flow ia high enough t o warm up the insulation and carry the vapaur

(26)

T E M P E R A T U R E G R A D

1

E N T

T A B L E

I

COMPONENT

I

I

I

SUMMER

I

WINTER

I

G R A P H

NAME

DATE

ADDRESS

ASSEMBLY

(27)

A c e i l h g is going to be reinsulated with

new

152 mm f r i c t i o n fft

f i k r g l a s s batts over the origxual

63

mm rock wool batts. Can

we

place a 0.15

mm

poLyethyleue vapvur barrier over the original insulation

before adding the new i~aulation?

Lf

the dew point temperature w i l l occur on the colder s i d e of the vapour barrier, then we may use the polyethylene.

The c o d i tioas are as follaws: inside T = 20%

attic

T

= -30aC

inside

R.H.

= 30X

The table and temperature profile are completed as in Pigtrre 12.

Using the psychrometric chart w e find that condensation should occur at about 2°C. h o k i n g at the table and p r o f i l e we see that the vapour barrier temperature is 4°C. Since this 2s alightly higher than the dew p o i n t temperature, no condensation should occur under these condirions as the vapwr barrier w i l l prevent water vapour from reaching the dew p o i n t temperature which is located within the new insulation.

It should be noted that changing conditions can alter the s i t u a t i o n .

(i) If the R.H. of the house rises t o 3 5 % , the dew poFnt teuperature rises to 4OC. Water vapour can condense at the vapoux barrier (if vapour can pass through the c e i l i n g ) and then d r t p or d i f f u s e back d w n to the ceiling.

Iii) If the a t t i c temperature drops to -35°C instead of -30°C, then the vapour barrier temperature becomes 2.4' which is close to t h e dew point temperature,

When the vapour barrier temperature fs below the dew polnt temperature as a result of very cold weather a x high indoor R.H., there may nat be a condensation problem if t h i s situation occurs for only a few days each heating season s i n c e the building assembly can hold

certain

quantities of

moisture with no

resultant

problem- This analysis assumes that the vapour barrier is camplete and that there are no air leakage paths through the polyethylene vapatr barrier.

(28)

T E M P E R A T U R E

G R A D I E N T

T A B L E

COMPONENT SUMMER

WINTER

R R/RT *

A T I

T

A T I

r

NAME

DATE

ADDRESS

ASSEMBLY

G R A P H

T E M P E R A T U R E ,

OC

FIGURE

1 2 ,

E X A M P L E

7

(29)

The following references . e v e more detailed and technical

explanat I o n of the concepts discussed in this paper,

( 1 ) LatEa, J.K. and Garden, G.K., Temperature Gradients Through

Building Envelapea, Matima1 Research Council of Canada, D i v i s i o n of Build- Research, CXD 36, 1962 (corrected 1968).

(2) Latta, J8K-b Walls, Windows and Roofs for the Canadfan Climate,

National Research Council of Canada, Divlsion of Building Research, Special Technical Publication No. 1, 1973.

NRCC 13487.

(3) Baker, M.C., Roofs: Design, Application a d Maintenance,

National Research Council of Canada, (Multiscience Publications Limited,

Montreal),

1980,

Chapter 5 .

( 4 ) Stephenson, D.G., Extreme Temperaturea at the Outer Surfaces of Buildings, Nat ianal Research Council of Canada, M v i s i o n o f Building Research, CBD

47,

1963.

(5) Garden,

G.K.,

Thermal Considerations in Rsnf Design, National Research Council of Canada, Divfsion of Building Research, CBD 70, 1965.

( 6 ) Hutcheon, N.B., Humidity id Canadian Buildings, National

Research Council of Canada, Divf sion of Buildt ng Research,

CBD

1 ,

1960 (corrected 2968).

(7) Lettta, J.K. and Beach, R.K., Vapour Diffusion and Condensation,

N a t i o n a l Research Council of Canada, Division of Building

(30)

THERMAL

RESISTANCE

OF SQPEE COMMON BUILDING MATERIALS* Thermal Resistance B u i l d i n g Material or Component S o l .

-

a/-

For Imperial W i n . Fo r Thickness Thickness L i s t e d L i s t e d Insulation Fibreglass Batt Eeockwool Batt Fibreglass Loose F i l l ( B l m - I n ) Fibreglass Loose Fill (Poured)

Rockwool Loose Fill (Blown-In)

Rodcwol Loose F i l l (Poured) Cellulose Pibre (Blown) Cellulose Fibre (Poured)

Expanded Mica

(Vermiculite, Zonollte, etc.)

Polystyrene Loose Pill

Expanded PoIystyrene { U g t d ) Extruded Polystyrene (figid] Polyurethane (Rigid)

Polyurethane ( F o a i ~ d i n Place)

Fibreglass Sheathing

Urea Formaldehyde (Foamed in Place, After Curiug)

Wood Fibre

Wood Shavings Cork

Glass F i b r e Roof Hoard

Mineral Aggregate Board Coupressed Straw Board Fibrebaard

Structural Haterials

Saf m o d Lumber (except Cedar) Cedar Logs and Lumber

Concrete 2400 kg/m3 (150 l b / f t 3 ) Concrete 176U k g l m 3 (1 10 l b / f t3)

Concrete 480 kg/m3 (30 l b / f t 3 1

* H E E n Scheuneman, S .

Moff a t t and M. Adelaat, Canadian General Standards Board. CGSB 51-GP-42MP, Ottawa, July 1980.

(31)

THERMAL RESISTANCE OF SOME COMMON BUILDING MATERIALS (Cont'd) Thermal Res 1 stance

Building Material or Component S.I. R/mm For I m p e r i a l Rlin. Po r Thickness Listed Thickness L i s t e d Structural Materials ( C o n t ' d )

Concrete Block (3 Oval Core) Sand and Gravel Aggregate

100 mm (4") 200 mm ( 8 " ) 300 mm (12") Cinder Aggregate

loo

mm ( 4 " ) 200 m (8") 300 mm (12") Lightweight Aggregate 100 mm ( 4 " ) 200 TJIIO ( 8 " ) 300 mm ( 1 2 " )

Conrmon Brick, Clay, 100 nrm ( 4 " )

Common Brick, Concrete, 100 mm ( 4 " )

Stone ( L i m e or Sand)

S t e e l

Aluminum

Glass (No Air F i l n r s ) 3

-

6 mm

(1/8"

-

1 / 4 " )

Air

-

Enclosed Air Space (Non-Reflective) Heat F l o w Up, 25

-

100 mm

(1'. - 4 " ) ---

Heat Flow Down, 25

-

100 mm

(1"

-

4 " )

--

Heat Flow Horizontal,

25 - 100 mm (1" - 4 " )

--

6.17

---

Air Surface F i l m s

Outside Air Film (Pioving A i r ) -- 0.03

---

I n s i d e M r Film (Still Air)

Horizontal, Heat F l o w Up

-

0.11

--

S l o p i n g 4 5 " , Heat Flow Up

-

0.11

-

Vertical, Heat Flow Horizontal --- 0.12

--

Horizontal, Hear Plow Down --- 0.16

-

(32)

THERMAL

RESISTANCE OH -SOME COMMUN

BUILDING

MATERIALS (Cont'd) Thermal Resistance Building Material or Component: Roofing S . I .

-

Imperial

B/mm For

in.

For

Thickness Thickness

Listed L i s t e d

Asphalt Roll Roofing

--

0 -03

Asphalt Shingles -.- 0 -08

Wood Shingles (Cedar Shakes)

--

0 -17 Built-up Membrane (Hot Mopped)

--

0.06

Crushed Stone ( N o t Dried) 0.00055

--

Sheathing Materials

Saftwoad Plywood

Mat-Formed Particle Board

Insulating Fibreboard Sheathing Gypsum Sheathing

Sheathing Paper

Asphalt-Coated W a f t Paper

Polyethylene Vapour

Barrier

Cladding Haterials 0,0087

-

0.0087

--

0.017

---

O.UO62

---

0.00040

--

Negli ,

-

N e g l i .

--

Ffbreboard Sfding Medium I k n s i t y

Hardboard,

11 mm (7116")

High Density Hardboard,

11 mm (7116")

Softwood Siding (Lapped)

Drop, 18 x 184 m (3/4" x 7

t " )

--

B e v e l , 12 x 184 aan ( * * I x 7 )")

-

Bevel, 18 x 235 nm (3/4" x

9

f " )

--

Plywood, 9 tam (3/8")

--

Woad Shingles

_-

Brick (Clay or Shale) 100

mm

(4")

-

Brick (Concrete, Sand-Lime)

loo

mm

(4")

---

Stucco, 25 mm (1") 0.0014 1.25 1-25 2.45 0.89 0.06 N e g l i

.

N e g l i *

(33)

THERMAL RBSISTANCE OF SOW

COMMON

BUfLDING HATEgIALS.(Cont'd) Thermal Resistance

Building Material

or Component

S.I. I m p e r i a l

R/w For

in.

Fox

Thf ckness Thicknes s

Listed L f s t e d

Cladding MaterLals (Conr'dj Hecal Siding

Horizontal Clapboard Profile

Horizontal Clapboard w i t h

Backing

Vertical V-Groove Profile

Vertical Board and Batten Profile

Interior Finishes

Gypsum Boaxd, Gypsum Lath,

Drywall, 13 mm

(4")

0.0062 0.08 0 . 8 9 Gypsum P l a s t e r Sand Aggregate, 13 mm

( 3 " )

0.014 0.02 0.20 Lightweight Aggregate, 13 (+") 0.0044 0.06 0.63 Plywood, 7.5

nrm

(5116") 0.0093 0.07 1.34 Hardboard, (Standard), hm

0")

0.0053 0.03 0.76 Insulating Fibreboard, 25 mm (1") 0.017 0.42 2 . 4 5 Flooring

Maple or Oak (hardwood), 19 mm ( 3 1 4 " )

Pine or Fir ( s o f t w o o d ) ,

19 mm ( 3 1 4 " )

Plywood, 16 nrm (518") Mat-formed Particle Board,

16 mm (5/8")

Wood F i b r e Tiles, 13 ma

Linoleum, Tile ( r e s i l i e n t ) ,

3 mm ( 1 1 8 " )

Terrazzo, 25 rmrt (I")

Carpet, Typical Thickness

with F i b r o u s Underlay

(34)

T H E W

RESISTANCE

UP SOME COMMON BUILDING MATERIALS (Cont'd) Thermal Resistance BuTldirtg Material or Component

S.I.

Imperial R / m For R/f

n.

For Thickness Thickness Llsced L i s t e d Windows

(including i n s i d e and outside

air

f i l m ) Single Glass

Insulated Glass (.Double Pane)

5 mm (3116") Air Space 6 mm

E*")

Air Space 13 mm (*") Air Space 19 m ( 3 1 4 " ) Air Space Insulated Glass {Triple Pane)

6 mm

(i")

Alr Space

13 mm

{i")

Air S p a c e

19

aun

( 3 1 4 " ) Air Space

S t o m Wtndows

Single Pane

+

25

-

100 mm

(1"

-

4 " ) Air Space 19 mm ( 3 1 4 " ) S e a l e d U n i t

+

(35)

T a b l e B-1. Roofing Materials

Copper

-

new, p o l i s h e d (brown)

-

tarnished (brown)

-

weathered patina (green) Aluminum

-

weathered

Galvamized Iron

-

new

- weathered S t e e l

-

white

enameled

-

green enameled

-

dark red enameled

-

blue enameled

Lead Sheeting

-

weathered

~ s b e s t o s / ~ e w n t :

-

new white

-

weathered

Table B-2. Masonry Bricks

-

glazed white

-

glazed ivory Lo cream

-

common light red

-

coramun red Limestone - l i g h t

-

dark

Sandstune

-

light

fawn

-

light grey

-

red 0.79 Marble

-

white

-

dark

0 -42

0.8U Granite

-

reddish Smooth Surf ace Asphalt

-

weathered 0.93

Grey Gravel - weathered 0.75 White Gravel

-

weathered

Table B-3. Faints

(can vary for different shades)

-

black

-

white

-

green

-

yellow - orange

-

dark brmn

-

dark blue

*

Computed by averaging values given by a range

of

different references.

(36)

References for Appendix 3

Baker, M.C., Roofs: Design, Application and Maintenance, Multiscience

Publications Limited, Montreal, 1980, page 134.

M f i e , J.A., and W.A. B e c h n , Solar Energy Thermal Process, Wiley- Interscfence, John Wiley & Sons, Toronto, 1974, page 97.

Garden, G.K., Therraal Considerations in Roof Design, Canadian Building Digest 70, National Research Council, O t t a w a , October 1965,

page 70-3.

Kreider, 3 . F . , and F. Kreith, Solar Heating and Cooling: Engineering,

Practical

Revised First Edition, Hemisphere

Pub1,isMng Corporation, McGraw-Hill, Toronto, 1977, page 247.

S t r o c k , C., and R.L. Koral, Handbook of A i r Conditioning Heating and Ventilating, Second Edition, Industrial P r e s s , New York, 1965, p. 1

-

61.

Figure

Figure  3,  A  W a l l   Assembly
Table B-2.  Masonry  Bricks  -  glazed  white

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