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6.12 1) ~a + ~b − ~c = (2 ~e1

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6.12 1) ~a+~b~c= (2e~1e~2 + 5e~3) + (e~1e~3)−(e~1+e~2−3e~3)

= 2e~1e~2+ 5e~3+e~1e~3e~1e~2+ 3e~3

= 2e~1−2e~2+ 7e~3

2) 3~a+ 3~b= 3 (2e~1e~2 + 5e~3) + 3 (e~1e~3)

= 6e~1−3e~2+ 15e~3+ 3e~1−3e~3

= 9e~1−3e~2+ 12e~3

3) ~a~b~c= (2e~1e~2+ 5e~3)−(e~1e~3)−(e~1+e~2−3e~3)

= 2e~1e~2+ 5e~3e~1+e~3e~1e~2+ 3e~3

=−2e~2+ 9e~3

4) 3~a+ 2~c= 3 (2e~1e~2 + 5e~3) + 2 (e~1+e~2−3e~3)

= 6e~1−3e~2+ 15e~3+ 2e~1+ 2e~2−6e~3

= 8e~1e~2+ 9e~3

Géométrie : vecteurs Corrigé 6.12

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