• Aucun résultat trouvé

NON-LERFNESS OF ARITHMETIC HYPERBOLIC MANIFOLD GROUPS AND MIXED 3-MANIFOLD GROUPS

N/A
N/A
Protected

Academic year: 2022

Partager "NON-LERFNESS OF ARITHMETIC HYPERBOLIC MANIFOLD GROUPS AND MIXED 3-MANIFOLD GROUPS"

Copied!
42
0
0

Texte intégral

(1)

MANIFOLD GROUPS AND MIXED 3-MANIFOLD GROUPS

HONGBIN SUN

Abstract

We will show that for any noncompact arithmetic hyperbolicm-manifold withm > 3, and any compact arithmetic hyperbolic m-manifold with m > 4 that is not a 7- dimensional one defined by octonions, its fundamental group is not locally extended residually finite (LERF). The main ingredient in the proof is a study on abelian amal- gamations of hyperbolic3-manifold groups. We will also show that a compact ori- entable irreducible 3-manifold with empty or tori boundary supports a geometric structure if and only if its fundamental group is LERF.

1. Introduction

For a groupGand a subgroupH < G, we say thatH isseparableinGif for any g2GnH there exists a finite-index subgroupG0< Gsuch thatH < G0andg…G0. Here,Gis calledLERF(locally extended residually finite) orsubgroup separableif all finitely generated subgroups ofGare separable.

The LERFness of a group is a property closely related with low-dimensional topology, especially the virtual Haken conjecture (settled in [3]). In this paper, we are mostly interested in fundamental groups of some nice manifolds and graphs of groups constructed from these groups.

Among fundamental groups of low-dimensional manifolds, the following groups are known to be LERF: free groups (see [19]), surface groups (see [36]), Seifert man- ifold groups (see [36]), and hyperbolic3-manifolds groups (see [3] and [43]); while the following groups are known to be non-LERF: groups of nontrivial graph mani- folds (see [30]), and groups of fibered3-manifolds whose monodromy is reducible and satisfies some further condition (see [24]).

In this paper, we give more examples of non-LERF groups arising from topol- ogy. These results imply that 3-manifolds with LERF fundamental groups support

DUKE MATHEMATICAL JOURNAL

Advance publication—final volume, issue, and page numbers to be assigned.

© 2019 DOI10.1215/00127094-2018-0048

Received 2 March 2018. Revision received 27 August 2018.

2010Mathematics Subject Classification. Primary 57M05; Secondary 57M05, 20E26, 22E40.

1

(2)

geometric structures, and it seems that hyperbolic manifolds with LERF fundamental groups have dimension at most3.

One main result of this paper is about high-dimensional arithmetic hyperbolic manifolds (with dimension at least4). Comparing to 3-dimensional case, there are much fewer examples of hyperbolic manifolds with dimension at least4. Many exam- ples of high-dimensional hyperbolic manifolds are constructed by arithmetic methods, and some other examples are constructed by doing cut-and-paste surgery on these arithmetic examples. So the following results suggest that having a non-LERF funda- mental group is a general phenomenon in a high-dimensional hyperbolic world.

THEOREM1.1

LetMmbe an arithmetic hyperbolic manifold withm5which is not a7-dimensional arithmetic hyperbolic manifold defined by octonions. Then its fundamental group is not LERF.

Moreover, ifM is closed, then there exists a nonseparable subgroup isomorphic to a free product of surface groups and free groups. IfM is not closed, there exists a nonseparable subgroup that is isomorphic to either a free subgroup, or a free product of surface groups and free groups.

Comparing with Theorem1.1, it is shown in [6] that all geometrically finite sub- groups of standard arithmetic hyperbolic manifold groups are separable. It will be easy to see that nonseparable subgroups constructed in the proof of Theorem1.1are not geometrically finite (see Remark5.1).

Theorem1.1does not cover the case of arithmetic hyperbolic 4-manifolds. By using a slightly different method in Theorem1.2, we show that noncompact arithmetic hyperbolic manifolds with dimension at least4have non-LERF fundamental groups.

Of course, the only case in Theorem1.2that is not covered by Theorem 1.1is the 4-dimensional case.

Note that in the more recent work [38], it is proved that all closed arithmetic hyperbolic4-manifolds also have non-LERF fundamental groups. So, with possible exceptions in7-dimensional arithmetic hyperbolic manifolds defined by octonions, all arithmetic hyperbolic manifolds with dimension at least4have non-LERF funda- mental groups.

THEOREM1.2

LetMmbe a noncompact arithmetic hyperbolicm-manifold withm4. Then1.M / is not LERF.

Moreover, there exist a nonseparable subgroup isomorphic to a free group and another nonseparable subgroup isomorphic to a surface group.

(3)

Some examples of high-dimensional nonarithmetic hyperbolic manifolds are con- structed in [2], [18], and [5]. These examples are constructed by cutting arithmetic hyperbolic manifolds along codimension-1totally geodesic submanifolds and then pasting along isometric boundary components. Since all these nonarithmetic hyper- bolic manifolds contain codimension-1 arithmetic hyperbolic submanifolds, Theo- rem1.1implies Theorem5.2, which claims that all nonarithmetic examples in [18]

and [5] (only4-dimensional examples are constructed in [2]) with dimension at least 6have non-LERF fundamental groups.

In Theorem5.3, we also show that compact reflection hyperbolic manifolds with dimension5and noncompact reflection hyperbolic manifolds with dimension4 have non-LERF fundamental groups.

Another main result in this paper concerns compact orientable irreducible 3- manifolds with empty or tori boundary. Thurston’s geometrization conjecture (con- firmed by Perelman) implies that any compact orientable irreducible3-manifoldM with empty or tori boundary has a minimal collection of incompressible tori, such that each component of its complement supports one of Thurston’s eight geometries.

If this set of incompressible tori is empty, then we say that M is a geometric 3- manifold.

The following theorem implies that a compact orientable irreducible3-manifolds with empty or tori boundary is geometric if and only if its fundamental group is LERF.

The author thinks that this result is very interesting, since it gives a surprising relation between geometric structures on3-manifolds and LERFness of 3-manifold groups, and these two topics in3-manifold topology have been very popular in the last two decades. This result also confirms Conjecture 1.5 in [24].

THEOREM1.3

For a compact orientable irreducible3-manifoldM with empty or tori boundary,M supports one of Thurston’s eight geometries if and only if1.M /is LERF.

When1.M /is not LERF, there exists a nonseparable subgroup isomorphic to a free group. IfM is a closed mixed3-manifold, then there also exists a nonseparable subgroup isomorphic to a surface group.

The proof of Theorem1.3is enlightened by the construction in Section 8 of [24].

To prove this theorem, the main case we need to deal with is thatM is a union of two geometric3-manifolds along one torus, with one of them being hyperbolic.

From a group theory point of view, the above group is aZ2-amalgamation of two LERF groups. An even simpler case is a Z-amalgamation of two hyperbolic 3-manifold groups, that is, the fundamental group of a union of two hyperbolic3- manifolds along one essential circle.

(4)

There have been a lot of works that study LERFness ofZ-amalgamated groups AZB, with bothAandBbeing LERF. For instance, the first such non-LERF exam- ple ofAZBwas constructed in [34]. It has been shown that if bothAandBare free groups (see [8]), or ifAis free,Bis LERF, andZ< Ais a maximal cyclic subgroup (see [17]), or if bothAandBare surface groups (see [27]), thenAZBis LERF.

Here, we give a family of non-LERFZ-amalgamations of3-manifold groups.

THEOREM1.4

Let M1, M2 be two finite-volume hyperbolic 3-manifolds, and let ikWS1!Mk, kD1; 2be two1-injective embedded circles. Then the fundamental group of

XDM1[S1M2

is not LERF.

Moreover, if bothM1 andM2have cusps, then there exists a nonseparable sub- group isomorphic to a free group. If at least one ofMk is closed, then there exists a nonseparable subgroup isomorphic to a free product of surface groups and free groups.

Theorem1.4is the main ingredient to prove Theorem1.1. We will use the fact that arithmetic hyperbolic manifolds have a lot of totally geodesic submanifolds of smaller dimension. If an arithmetic hyperbolic manifold has dimension at least5, then there are two totally geodesic3-dimensional submanifolds intersecting along a closed geodesic, which gives a picture addressed in Theorem1.4.

In dimension4, such a picture does not show up by dimension reason, so The- orem1.4does not help here. However, Theorem1.3implies that the double of any cusped hyperbolic3-manifold has non-LERF fundamental group, and groups of all noncompact arithmetic hyperbolic manifolds with dimension at least4contain such doubled 3-manifold groups (see [25]). So Theorem 1.2is a consequence of Theo- rem1.3.

The organization of this paper is as follows. In Section2, we review some back- ground on group theory,3-manifold topology, and arithmetic hyperbolic manifolds.

In Section3, we prove Theorem1.3, which is enlightened by the construction in [24].

In Section4, we prove Theorem1.4, whose proof is similar to the proof of Theo- rem1.3, with some modifications. In Section 5, we deduce Theorems 1.1 and 1.2 from Theorems1.4and1.3, respectively. In Section6, we ask some questions related to the results in this paper.

2. Preliminaries

In this section, we review some basic concepts in group theory,3-manifold topology, and arithmetic hyperbolic manifolds.

(5)

2.1. Locally extended residually finite

In this subsection, we review basic concepts and properties on LERF groups.

Definition 2.1

LetGbe a group, and letH < Gbe a subgroup. We say thatH isseparableinGif, for anyg2GnH, there exists a finite-index subgroupG0< Gsuch thatH < G0and g…G0.

An equivalent formulation is thatH is separable inGif and only ifH is a closed subset under the profinite topology ofG.

Definition 2.2

A groupG isLERForsubgroup separableif all finitely generated subgroups ofG are separable inG.

A basic property on LERFness is that any subgroup of a LERF group is still LERF. This property is basic and well known, while the proof is very simple. How- ever, since this property is crucial for us, we give a proof here.

LEMMA2.3

LetGbe a group, and let < Gbe a subgroup. For a further subgroupH < , ifH is separable inG, thenHis separable in.

In particular, ifis not LERF, thenGis not LERF.

Proof

If we take an arbitrary element2nH, then2GnHholds. SinceHis separable inG, there exists a finite-index subgroupG0< Gsuch thatH < G0and…G0. Then 0DG0\is a finite-index subgroup of, withH < G0\D0and…G0\D 0. SoH is also separable in.

Ifis not LERF, then it contains a finitely generated subgroupH which is not separable in. Then the previous paragraph implies thatH is not separable inG. So Gis not LERF.

In this paper, the main method to prove that a groupG is not LERF is to find a descending tower of subgroups of G until we get a subgroup which has a nice structure such that a topological argument can be applied to prove its non-LERFness.

(6)

2.2. Geometric decomposition of irreducible3-manifolds

In this paper, we assume that all manifolds are connected and oriented and that all3- manifolds are compact and have empty or tori boundary. For any noncompact finite- volume hyperbolic manifoldM, we always truncateM by deleting a horocusp for each cusp end ofM. Then we can consider M as a compact3-manifold with tori boundary, and the boundary has an induced Euclidean structure.

LetM be an irreducible3-manifold with empty or tori boundary. By the geome- trization of3-manifolds, which is achieved by Perelman and Thurston, exactly one of the following hold:

M is geometric; that is,M supports one of the following eight geometries:

E3,S3,S2E1,H2E1, Nil, Sol,PSL2.R/, andH3.

There is a nonempty minimal unionTM M of disjoint essential tori and Klein bottles, unique up to isotopy, such that each component ofM nTM is either Seifert-fibered or atoroidal. In the Seifert-fibered case, the interior sup- ports both theH2E1-geometry and thePSL2.R/-geometry; in the atoroidal case, the interior supports theH3-geometry.

If M has nontrivial geometric decomposition (as in the second case), we say thatM is anongeometric3-manifoldand call components ofM nTM Seifert pieces orhyperbolic pieces, according to their geometry. If all components ofM nTM are Seifert pieces, thenM is called agraph manifold. Otherwise,M contains a hyperbolic piece, and it is called amixed manifold. Since we only consider virtual properties of 3-manifolds in this paper, we can pass to a double cover of the3-manifold and assume that all components ofTM are tori.

The geometric decomposition is very closely related to, but slightly different from, the more traditional Jaco–Shalen–Johannson (JSJ) decomposition. Since these two decompositions agree with each other ifM has no decomposing Klein bottle (which can be achieved by a double cover), and we are studying virtual properties, we will not make much of a difference between them.

2.3. Fibered structures of3-manifolds

In the construction of nonseparable subgroups in Theorem1.3and Theorem1.4, all subgroups have a graph of group structures, and the vertex groups are fibered surface subgroups in geometric pieces. We will briefly review the theory of the Thurston norm and its relation with fibered structures on3-manifolds.

If a3-manifold M has a surface bundle over circle structure withb1.M / > 1, thenM has infinitely many different such structures (which works for all dimensions).

These fibered structures of the3-manifoldM are organized by the Thurston norm on H2.M; @MIR/(ŠH1.MIR/by duality) defined in [39].

For any˛2H2.M; @MIZ/, its Thurston norm is defined by:

(7)

k˛k Dinf®ˇˇ.T0/ˇˇˇˇ.T; @T /.M; @M /represents˛¯

;

where T0 T excludes S2 and D2 components of T. In [39], it is shown that this norm can be extended toH2.M; @MIR/homogeneously and continuously, and the Thurston norm unit ball is a polyhedron whose faces are dual with elements in H1.MIZ/=T or. For a general3-manifold, the Thurston norm is only a seminorm, while it is a genuine norm for finite-volume hyperbolic3-manifolds.

For a top-dimensional open faceF of the Thurston norm unit ball, letC be the open cone overF. In [39], Thurston showed that an integer point˛2H2.M; @MIR/ corresponds to a surface bundle structure ofM if and only if˛is contained in an open coneC as above, and all integer points inC correspond to surface bundle structures ofM. In this case,C is called afibered cone, and the corresponding faceF is called afibered face. Any point (which may not be an integer point) in a fibered cone we call afibered class.

Thurston’s theorem implies that the set of fibered classes ofM is an open subset ofH2.M; @MIR/. In particular, for any fibered class ˛2H2.M; @MIR/and any ˇ2H2.M; @MIR/, there exists > 0, such that˛Ccˇ2H2.M; @MIR/is a fibered class for anyc2.; /.

2.4. Virtual retractions of hyperbolic3-manifold groups

In the proof of Theorem1.3and1.4, we need to perturb a fibered class ˛2H2.M;

@MIR/ to get a new fibered class with some desired property. To make sure the desired perturbation exists, we need the virtual retract property of geometrically finite subgroups of hyperbolic3-manifold groups.

Definition 2.4

For a groupGand a subgroupH < G, we say thatH is avirtual retractionofGif there exists a finite-index subgroupG0< Gand a homomorphismWG0!H, such thatH < G0andjH DidH.

For a finite-volume hyperbolic 3-manifold M, the following dichotomy for a finitely generated infinite-index subgroupH < 1.M /holds:

(1) H is a geometrically finite subgroup of1.M /from the Kleinian group point of view. Equivalently,His (relatively) quasiconvex in the (relative) hyperbolic group1.M /from the geometric group theory point of view.

(2) H is a geometrically infinite subgroup of1.M /. In this case,H is a virtual fibered surface subgroup ofM.

Here, we do not give the definition of geometrically finite and geometrically infinite subgroups. Readers only need to know that ifH is not a virtual fibered surface sub- group, then it is a geometrically finite subgroup. An introduction of geometrically

(8)

finite subgroups can be found in [7] and [26, Chapter VI]. The proof of the above dichotomy relies on the covering theorem (see [10], [41]) and the Tameness theorem (see [1], [9]) on open hyperbolic3-manifolds.

In [11], it is shown that (relatively) quasiconvex subgroups of virtually compact special (relative) hyperbolic groups are virtual retractions. The celebrated virtual com- pact special theorem of Wise (see [43] for cusped case) and Agol (see [3] for closed case) implies that groups of finite-volume hyperbolic3-manifolds are virtually com- pact special. These two results together give us the following theorem.

THEOREM2.5

LetM be a finite-volume hyperbolic3-manifold, and letH < 1.M /be a geometri- cally finite subgroup (i.e.,H is not a virtual fibered surface subgroup). ThenH is a virtual retraction of1.M /.

2.5. Arithmetic hyperbolic manifolds

In this subsection, we briefly review the definition of (standard) arithmetic hyperbolic manifolds. Most material can be found in [42, Chapter 6].

Recall that the hyperboloid model ofHnis defined as the following. EquipRnC1 with a bilinear formBWRnC1RnC1!Rwith

B

.x1; : : : ; xn; xnC1/; .y1; : : : ; yn; ynC1/

Dx1y1C CxnynxnC1ynC1:

Then the hyperbolic spaceHnis identified with In

E

xD.x1; : : : ; xn; xnC1/ˇˇB.x;E x/E D 1; xnC1> 0¯ :

The hyperbolic metric is given by the restriction ofB.;/on the tangent space ofIn. The isometry group of Hn consists of all linear transformations of RnC1 that preserveB.;/and fixIn. LetJDdiag.1; : : : ; 1;1/be the.nC1/.nC1/matrix defining the bilinear formB.;/. Then the isometry group ofHnis given by

Isom.Hn/ŠPO.n; 1IR/D®

X2GL.nC1;R/ˇ

ˇXtJ XDJ¯

=.X X /:

The orientation-preserving isometry group ofHnis given by IsomC.Hn/ŠSO0.n; 1IR/;

which is the component of SO.n; 1IR/D®

X2SL.nC1;R/ˇˇXtJ XDJ¯ that contains the identity matrix.

(9)

Now we give the definition ofstandard arithmetic hyperbolic manifolds; they are also calledarithmetic hyperbolic manifolds of simplest type.

LetKRbe a totally real number field, and let1Did; 2; : : : ; kbe all embed- dings ofKintoR. Let

f .x/D

nC1X

i;jD1

aijxixj; aij Daj i2K

be a nondegenerate symmetric quadratic form defined overK with negative inertia index 1(as a quadratic form over R). We further suppose that, for any l > 1, the quadratic form

fl.x/D

nC1X

i;jD1

l.aij/xixj

is positive definite. Then the information ofK andf can be used to define an arith- metic hyperbolic group.

LetOKbe the ring of algebraic integers inK, and letAbe the.nC1/.nC1/

matrix definingf. Since the negative inertia index ofAis1, thespecial orthogonal group off,

SO.fIR/D®

X2SL.nC1;R/ˇˇXtAXDA¯

;

is conjugate to SO.n; 1IR/by a matrixP (satisfyingPtAPDJ). Moreover, SO.fI R/has two components, and we let SO0.fIR/be the component that contains the identity matrix.

Then we form the set of algebraic integer points SO.fIOK/D®

X2SL.nC1;OK/ˇˇXtAXDA¯ in SO.fIR/. The theory of arithmetic groups implies that

SO0.fIOK/DSO.fIOK/\SO0.fIR/

is conjugate to a lattice of IsomC.Hn/(by the matrixP); that is, it has finite covol- ume. For simplicity, we abuse notation and still use SO0.fIOK/to denote its P- conjugation in SO0.n; 1IR/ŠIsomC.Hn/.

Here, SO0.fIOK/IsomC.Hn/is calledthe arithmetic groupand is defined by number fieldKand quadratic formf, andHn=SO0.fIOK/is a finite-volume hyper- bolic arithmetic orbifold. A hyperbolicn-manifold (orbifold)M is called astandard arithmetic hyperbolic manifold (orbifold)ifM is commensurable withHn=SO0.fI OK/for someKandf.

(10)

The arithmetic orbifoldHn=SO0.fIOK/is noncompact if and only iff .Ex/D0 has a nontrivial solution in2KnC1, which happens only if KDQ(i.e.,OKDZ).

Whenn4,Hn=SO0.fIOK/is noncompact if and only ifKDQ.

For this paper, the most important property of standard arithmetic hyperbolic manifolds is that they contain a lot of finite-volume hyperbolic3-manifolds as totally geodesic submanifolds. This can be done by diagonalizing the matrixA(overK) and taking an indefinite44submatrix.

The above recipe using quadratic forms over number fields gives all even- dimensional arithmetic hyperbolic manifolds (orbifolds). In any odd dimension, there is another family of arithmetic hyperbolic manifolds (orbifolds) which are defined by (skew-Hermitian) quadratic forms over quaternion algebras. We do not give the definition of this family here; readers can find a detailed definition in [23].

This family of arithmetic hyperbolic manifolds defined over quaternions also has many finite-volume hyperbolic 3-manifolds that are totally geodesic submanifolds.

This can be done by diagonalizing the quadratic form over quaternions and taking a 22submatrix. Note that this fact is also used in [22].

In dimension7, there is a third way to construct arithmetic hyperbolic manifolds by using octonions. Only sporadic examples exist, and the author does not know whether these manifolds have totally geodesic (or1-injective) 3-dimensional sub- manifolds. All examples in this family are compact manifolds.

3. Non-LERFness of nongeometric3-manifold groups

In this section, we prove that groups of nongeometric3-manifolds are not LERF. The construction of nonseparable (surface) subgroups is enlightened by the construction in [24] (and also in [35]). The proof of nonseparability is essentially a computation of the spirality character defined in [24]. Here, we modify the construction in [24]

and give an elementary proof of nonseparability without using the spirality character explicitly.

3.1. Finite semicovers of nongeometric3-manifolds

We first review the notion of finite semicovers of nongeometric3-manifolds, which was introduced in [32].

Definition 3.1

LetM be a nongeometric3-manifold with tori or empty boundary. Afinite semicover ofM is a compact3-manifoldN and a local embeddingf WN!M, such that its restriction on each boundary component of N is a finite cover to a decomposition torus or a boundary component ofM.

(11)

For a finite semicoverf WN !M, ifM has no decomposing Klein bottle, the decomposition tori ofN is exactlyf1.TM/n@N, and the restriction off on each geometric piece ofN is a finite cover of the corresponding geometric piece ofM.

One important property of finite semicovers is given by the following lemma in [24].

LEMMA3.2 ([24, Lemma 6.2])

IfN is a connected finite semicover of a nongeometric3-manifoldM with empty or tori boundary, thenN has an embedded lifting in a finite cover ofM. In fact, the semicovering mapN!M is1-injective, and1.N /is separable in1.M /.

Remark 3.3

In [24], this lemma is only stated in the case thatM is a closed orientable irreducible nongeometric 3-manifold, but it also clearly holds for irreducible nongeometric3- manifolds with nonempty boundary. This is because we can first take the double D.M /ofM, apply the closed manifold version of Lemma3.2toN !D.M /, and apply Lemma2.3to get separability of1.N /in1.M /.

3.2. Reduction to nongeometric3-manifolds with very simple dual graph

To prove Theorem1.3, we will reduce it to the case that the dual graph ofM consists of two vertices and two edges (a bigon), andM has at least one hyperbolic piece.

LetM be an orientable irreducible nongeometric3-manifold with tori or empty boundary. It is known that all graph manifolds have non-LERF fundamental groups (see [30]), so we can assume thatM has at least one hyperbolic piece; that is,M is a mixed3-manifold.

The dual graph ofM is a graph with vertices corresponding to geometric pieces ofM and edges corresponding to decomposition tori. The following lemma is the first step of our reduction of3-manifolds, which reduces the non-LERFness of mixed 3-manifold groups to a very simple case: the dual graph ofM has only two vertices and one edge.

LEMMA3.4

LetM be a mixed3-manifold. Then there exists a3-manifoldN DN1[T N2 such that the following hold:

(1) N1is a cusped hyperbolic3-manifold, andN2is a geometric3-manifold.

(2) N1\N2DT is a single torus, andNDN1[T N2is a fibered3-manifold.

(3) N is a finite semicover ofM, so1.N /is a subgroup of1.M /.

(12)

Proof

By [31], we take a finite cover of M such that it is a fibered 3-manifold; we still denote it byM.

We first suppose thatM has at least two geometric pieces. Take any hyperbolic pieceN1, and take another (distinct) geometric pieceN2adjacent toN1. It is possible thatN1\N2 consists of more than one tori, and letT be one of them. We cutM along all decomposition tori inTM exceptT; then the component containingN1and N2is the desiredN, which is clearly a finite semicover ofM.

The fibered structure onM induces a fibered structure onN, since fibered struc- tures of3-manifolds are compatible with geometric decomposition. It is easy to see that all other desired conditions hold forN.

It remains to consider the case thatM has only one geometric piece, and we denote it byN1. Since the geometric decomposition ofM is nontrivial, there is a decomposition torusT of M that is adjacent toN1 on both sides. Then we take a double cover ofM dual toT and reduce it to the previous case.

By Lemma2.3, to prove non-LERFness of mixed3-manifold groups, we only need to consider the case M DM1[T M2 as in Lemma3.4 (we use M and Mi

instead ofNandNisince we will do further constructions). The dual graph ofM has two vertices and one edge, which is not our desired model for constructing nonsep- arable subgroups. Actually, we need a cycle in the dual graph of the3-manifold. So we use the following lemma to pass it to a further finite semicover, such that its dual graph consists of two vertices and two edges (a bigon).

LEMMA3.5

LetM DM1[T M2 be a3-manifold satisfying the conclusion of Lemma3.4. Then there exists a3-manifoldNDN1[T[T0N2 with nonempty boundary such that the following hold:

(1) N1is a cusped hyperbolic3-manifold, andN2is a geometric3-manifold.

(2) N1\N2DT[T0is a union of two tori, andNDN1[T[T0N2is a fibered 3-manifold.

(3) The homomorphism H1.T [T0IZ/!H1.N1IZ/ induced by inclusion is injective.

(4) N is a finite semicover ofM, so1.N /is a subgroup of1.M /.

(5) There exists a fibered surfaceS of N, which is a union of two subsurfaces SDS1[c[c0S2, such thatSiDS\Ni,cDS\T, andc0DS\T0. Here, bothS andS0are connected, while bothcandc0are one single circle.

(13)

Proof

Claim. There exists a3-manifoldNDN1[T[T0N2satisfying conditions (1)–(4).

We first prove this claim.

We take a basepoint ofM1onT. ForZ2Š1.T / < 1.M1/ <IsomC.H3/, we take any hyperbolic elementg21.M1/which maps the fixed point of1.T /onS12 to a different point. By the Klein combination theorem (see [26, Section VII, Theo- rem A.13]), for large-enough positive integerk, the subgroup of1.M1/generated by 1.T /and gk1.T /gk is isomorphic to the free product of these two groups, that is, isomorphic toZ2Z2, and we denote it byH.

SinceH < 1.M1/is not a surface subgroup, it is geometrically finite. By Theo- rem2.5, there exists a finite coverN1ofM1, such thatH < 1.N1/, and there exists a retraction homomorphism1.N1/!H. Since hyperbolic3-manifolds have LERF fundamental groups (see [3], [43]), by passing to a further finite cover (still denoted by N1), we can assume thatgk1.N1/and thatN1 has at least three boundary components.

Sincegk1.N1/, any (embedded) arc inN1 (starting from the lifted base- point) corresponding togk21.M /connects two different boundary components of N1, and we denote them byT1andT10. Note that the restriction of covering mapN1! M1maps bothT1andT10 toT by homeomorphisms. ThenH < 1.N1/corresponds to the fundamental group of the union ofT1,T10, and. SinceH D1.T1[T10[ / is a retraction of1.N1/,H1.T1[T10[IZ/ŠH1.T1[T10IZ/is a retraction of H1.N1IZ/. So condition (3) holds forN1.

IfM2is a cusped hyperbolic3-manifold, by doing the same construction asM1, we get a finite coverN2!M2 such that two boundary componentsT2 and T20 of N2are mapped toT by homeomorphisms. By identifyingT1andT10withT2andT20, respectively, we get a semifinite coverNDN1[T[T0N2ofM satisfying conditions (1)–(4). Here, we useT to denote the image ofT1 andT2, and we useT0 to denote the image ofT10andT20.

IfM2is a Seifert-fibered space, then we first do the following preparation before doing the above construction for M1. Since M is a fibered 3-manifold, we have M DS I =, whereWS !S is a reducible homeomorphism on a surfaceS. By taking some finite cyclic coverM0ofM alongS, we can assume thatM0has two adjacent geometric pieces, such that one of them is a cusped hyperbolic3-manifold, and another one is homeomorphic to†S1with.†/ < 0.

We take the union of these two adjacent pieces along a common torus and get our newM DM1[TM2withM2D†S1. Then we do the same construction for M1as above to get a finite coverN1. ForM2, letcbe the boundary component of† corresponding to the boundary componentT @M2. Since.†/ < 0, there exists a

(14)

double cover†0!†such that there are two boundary componentsc2; c20 @†0that are mapped tocby homeomorphisms.

Then N2D†0 S1 is a finite cover of M2. Let T2 and T20 be the boundary components ofN2 corresponding to c2S1 and c20 S1, respectively; then they are both mapped toT by homeomorphisms. We pasteN1 andN2together to get the desired finite semicoverNDN1[T[T0N2.

This finishes the proof of the claim.

Now N DN1[T[T0 N2 satisfies conditions (1)–(4), so we need to work on condition (5).

SinceM is a fibered3-manifold, the semicoverN has an induced fibered struc- ture. The corresponding fibered surfaceS might be more complicated than what we want in condition (5), sinceS\Ni,S\T, andS\T0may not be connected.

We write N as N DS I =. Since N has nontrivial torus decomposition, WS!S is a reducible self-homeomorphism ofS. Let C be the set of reduction circles such that j WS nC !S nC is either pseudo-Anosov or periodic on each -component (by [40]).

We first suppose that there are two components S1 and S2 ofS nC such that SiNi, and such thatS1\S2contains two circlescandc0withcT andc0T0. Take a positive integer k, such that k preserves each component of both S nC andC. In this case, N0D..S1[c[c0S2/I /=k is a finite semicover ofN. Let NNiDSiI =k, and letTN andTN0be the components of@NN1(also@NN2) containing c andc0, respectively. Then it is easy to check thatNN D NN1[TN[ NT0NN2 satisfies all desired conditions.

If there are not two components ofSnCsatisfying the above condition, we need to modify the fibered surfaceS. The new fibered surface is the Haken sum ofSand a multiple ofT1, and the detail is as follows.

We take a tubular neighborhoodN.T1/ofT1inN1 and give it a coordinate by N.T1/DT1I D.S1I /S1such that

S\N.T1/D

¹a1; a2; : : : ; akº I S1;

with a1; : : : ; ak following a cyclic order on S1. The fibered structure on N.T1/ is given by a fibered structure of S1I and then crossed with S1. For any integer j, we modify the fibered structure onN.T1/by modifying the fibered structure on S1I. For each fixed integer j, a new fibered structure onS1I is given by a union of disjoint embedded arcsIiS1I, such thatIiconnects.ai; 0/to.aiCj; 1/

(modulok), whereiD1; 2; : : : ; k. This fibered structure onN.T1/can be pasted with the original fibered structure ofNnN.T1/to get a new fibered structure ofN.

If we start from one componentS1S\N1, then take any componentS2S\ N2such thatS1\S2\T0¤ ;. ThenS1\T1andS2\T2are two families of parallel

(15)

circles onT, but it is possible any two circles in these two families are not identified with each other. Then we apply the above modification of the fibered structure for a proper chosenj, such that the new fibered surface satisfies the assumption of the previous case.

Actually, condition (5) is not really necessary in the proof of Theorem1.3, but it will make the immersed1-injective surface constructed in Proposition3.6a simple shape.

3.3. Construction of nonseparable surface subgroups

In this subsection, we construct a1-injective properly immersed subsurface in the 3-manifold N DN1[T[T0N2 constructed in Lemma3.5 and then prove that this surface subgroup is not separable in1.N /.

The following proposition constructs a1-injective properly immersed subsur- face inN, which is our candidate of nonseparable surface subgroup. Readers may want to compare this construction with the construction in Section 8 of [24].

PROPOSITION3.6

For the3-manifoldNDN1[T[T0N2and fibered subsurfaceSDS1[c[c0S2con- structed in Lemma3.5, there exists a connected1-injective properly immersed sur- faceiW†N such that the following hold:

(1) †is a union of connected subsurfaces as†D.†1;1[†1;2/[.S2n

kD12;k/, withi.†1;j/N1andi.†2;k/N2.

(2) The restrictions ofion1;j and2;kare embeddings, and their images are fibered surfaces inN1andN2, respectively.

(3) Each2;kis a parallel copy ofS2inN2, so2;kintersects with bothT and T0along exactly one circle.

(4) †1;1\†2;1consists of two circlessands0, withi.s/T andi.s0/T0. (5) †1;1\T consists of A parallel copies of c, and †1;1\T0 consists of B

parallel copies ofc0, withA¤B.

Proof

When we cutN alongT[T0and cutSalongc[c0, we useTi andTi0to denote the copies ofT andT0inNi, respectively, and useciandci0to denote the copies ofcand c0inSi, respectively.

Let˛2H1.NIZ/be the fibered class dual toS, and let˛1D˛jN1. Then˛1jT1

is dual toc1T1, and˛1jT0

1is dual toc10 T10.

SinceH1.T1[T10IZ/!H1.N1IZ/is injective, there exists a direct summand A < H1.N1IZ/such that AŠZ4 andH1.T1[T10IZ/ < A. SinceZ4 ŠH1.T1[

(16)

T10IZ/ < AŠZ4is a finite-index subgroup, there exists a homomorphism WA!Z such that jH1.T1IZ/is equal tol˛1jT1for somel2ZC, and jH1.T0

1IZ/D0.

LetWH1.N1IZ/!Abe a retraction given by the direct sum structure. Then we get a cohomology classˇ2H1.N1IZ/defined by ıWH1.N1IZ/!Z. By the construction of ,ˇjT1D ıjT1D jT1Dl˛1jT1for somel2ZCandˇjT0

1D0.

Since˛1is a fibered class onN1, for large-enoughn2ZC1;1Dn˛1Cˇand

˛1;2Dn˛1ˇare both fibered classes inH1.N1IZ/. Here, we can also assume that n > land gcd.n; l/D1.

Since˛1;1jT1is dual tonClcopies ofc11;1jT0

1is dual toncopies ofc10, and gcd.n; l/D1,˛1;12H1.N1IZ/is a primitive class. Similarly,˛1;22H1.N1IZ/is also primitive.

Let†1;1N1 be the connected fibered surface dual to˛1;12H1.N1IZ/, and let†1;2N1be the connected fibered surface dual to˛1;2. Then†1;1\T1consists ofADnClcopies ofc1(as oriented curves),†1;1\T10consists ofBDncopies of c10,†1;2\T1consists ofnlcopies ofc1, and†1;2\T10consists ofncopies ofc10. So.†1;1[†1;2/\T1 and.†1;1[†1;2/\T10consist of2n(oriented) copies ofc1

andc10, respectively.

Note that bothS2\T2 andS2\T20 are exactly one (oriented) copy ofc2 and c20, respectively. We take 2n copies of S2 in N2, and denote them by †2;k, with k D1; 2; : : : ; 2n. Then we identify parallel circles in .†1;1 [†1;2/\T1 with .S2n

kD12;k/\T2onT DT1DT2and identify parallel circles in.†1;1[†1;2/\T10 with.S2n

kD12;k/\T20onT0DT10DT20 to get an immersed surface†. In the iden- tification process, we first identify one circle in†1;1\T1with the circle in†2;1\T2

and identify one circle in†1;1\T10 with the circle in†2;1\T20. Then we identify the remaining circles arbitrarily. There are actually many ways to do the identification in the second step, since we can isotopy any†2;k0such that its intersection withT2 slides over the other circles†2;k\T2, while the other surfaces in¹†2;kºare fixed.

It is easy to see thatiW†N is a properly immersed surface, and it satisfies conditions (1)–(5) in the proposition by the construction.

Moreover, by conditions (3) and (5), there exists some †2;k0 such that both

1;1\†2;k0 and †1;2\†2;k0 are not empty. So †1;1 and †1;2 lie in the same connected component of†. Then†must be connected, since each†2;k intersects with at least one of†1;1and†1;2.

Now we show thatiis1-injective by using classical3-manifold topology. Sup- pose there is a mapj WS1!†which is not null-homotopic in†, butiıjWS1!N is null-homotopic inN.

We can assume thatiıj is transverse with the decomposition toriT[T0, and j minimizes the number of points in.iıj /1.T[T0/S1 in the homotopy class

(17)

ofj. This number is not zero; otherwise it contradicts the1-injectivity of fibered surfaces.

Sinceiıj is null-homotopic, it can be extended to a mapkWD2!N such that kjS1Diıj. We can homotopykrelative toS1such that it is transverse withT[T0, andk1.T [T0/consists of disjoint simple arcs inD2.

Then there exists a subarc˛S1and an arc componentˇink1.T[T0/D2, such that ˛and ˇ share endpoints and there are no other components ofk1.T [ T0/lying in the subdiskBD2 bounded by˛[ˇ. Without loss of generality, we suppose thatj.˛/lies in†1;1N1,k.ˇ/T, andk.B/N1. Then it is easy to see that thek-images of two endpoints of˛lie in the same component of†1;1\T by considering the algebraic intersection number between†1;1and˛[ˇ. Moreover, kjˇWˇ!T is homotopic to a map into†1;1\T, relative to the boundary ofˇ.

Then it is routine to check thatjj˛W˛!†1;1is homotopy to a map with image ini1.T /, relative to the boundary of˛. After a further homotopy ofj supporting on a neighborhood of˛, we get anotherj0WS1!†which is homotopy toj and has a fewer number of points in.iıj0/1.T[T0/S1.

So we get a contradiction with the minimality ofj, andiW†Nis1-injective.

The following proposition proves the nonseparability of i.1.†// < 1.N / constructed in Proposition3.6. Essentially, the proof checks that the spirality char- acter of†!N is nontrivial (defined in [24]), but we do not use the terminology of the spirality character here, since the picture is relatively simple and we can give a direct proof.

PROPOSITION3.7

For the properly immersed subsurface i W†N constructed in Proposition 3.6, i.1.†// < 1.N /is a nonseparable subgroup.

Proof

Suppose thati.1.†// < 1.N /is separable; we will get a contradiction.

LetNQ be the covering space ofN corresponding toi.1.†//. Since each com- ponent of†\i1.Nk/is a fibered surface inNkforkD1; 2, it is easy to see thatNQ is homeomorphic to†R. SoiW†N lifts to an embedding† ,! QN.

Sincei.1.†// < 1.N /is separable, by [36] there exists an intermediate finite coverNO !N ofNQ !N such thatiW†N lifts to an embeddingOiW† ,! ON.

SinceiW†N is a proper immersion,iOW† ,! ON is also a proper embedding.

So†defines a nontrivial cohomology class2H1.NOIZ/.

(18)

For each decomposition torusTOs ON, suppose†\ OTs consists ofks parallel circles. LetK be the least common multiple of allks. By taking theK-sheet cyclic cover ofNO along†(corresponding to the kernel ofH1.NOIZ/! Z!ZK), we get a further finite cover NN !N. Then†embeds into NN, and it intersects with each decomposition torus ofNN exactly once.

LetNN1 andNN2be the geometric pieces ofNN containing†1;1and†2;1, respec- tively. Since†1;1\†2;1Ds[s0, letTN andTN0be the decomposition tori inNN1\ NN2

containingsands0, respectively. Then the finite coverNN !N induces finite covers:

NN1!N1; NN2!N2; TN!T; TN0!T0:

Since bothTN !T andTN0!T0are induced byNN1!N1andNN2!N2, we will get two relations between deg.TN !T /and deg.TN0!T0/and then get a contradic- tion.

Since †1;1 is an embedded fibered surface in both NN1 and N1,NN1 is a finite cyclic cover ofN1along†1;1. Similarly,NN2is a finite cyclic cover ofN2along†2;1. Since†1;1\T consists ofAparallel circles and†1;1\T0consists ofBparallel circles, while†1;1\ NT and†1;1\ NT0are both only one circle,NN1!N1is a cyclic cover whose degree is a multiple of lcm.A; B/, and

Adeg.TN !T /Ddeg.NN1!N1/DBdeg.TN0!T0/: (1) We also have that†2;1is an embedded fibered surface in bothNN2andN2. Since

2;1\T,†2;1\T0,†2;1\ NT, and†2;1\ NT0are all just one circle, andNN2!N2 is a finite cyclic cover, we have

deg.TN !T /Ddeg.NN2!N2/Ddeg.TN !T0/: (2) Equations (1) and (2) imply thatADB, which contradicts with condition (5) in Proposition3.6. Soi.1.†//must be a nonseparable subgroup of1.N /.

Remark 3.8

From the proof of Proposition3.7, readers can see that the main ingredient for prov- ing the nonseparability of 1.†/ is the subsurface†1;1[s[s02;1. However, the author cannot prove that1.†1;1[s[s02;1/is nonseparable in1.N /yet, although it seems quite plausible.

In the proof of Proposition3.7, we do need the properness of the immersed sub- surfaceiW†N so that we can take the finite cyclic cover ofNO along†to getNN and then get the contradiction. Actually, most of the proof can be translated to purely group theoretical language, except that the author does not know how to interpret

“properly immersed subsurface” algebraically.

(19)

3.4. Proof of Theorem1.3

Now we are ready to prove Theorem1.3.

Proof

Suppose thatM supports one of Thurston’s eight geometries. Since the fundamen- tal group is finite or virtually abelian, ifM supports theS3- orS2E1-geometry, then LERFness trivially holds. IfM supports theE3-, Nil-,H2E1-, orPSL2.R/- geometry, thenM is a Seifert manifold and LERFness is proved in [36]. IfM sup- ports the Sol-geometry, thenM is virtually a torus bundle over circle, and a proof of LERFness can be found in [30]. IfM is a hyperbolic3-manifold, then LERFness is shown by the celebrated works of Wise (see [43] for the cusped case) and Agol (see [3] for the closed case).

Now we need to show that nongeometric3-manifolds have non-LERF fundamen- tal groups. We first suppose thatM is a mixed3-manifold; that is,M has a hyperbolic piece.

IfM is not a closed manifold, then Lemmas3.4and3.5imply thatM has a finite semicoverNDN1[T[T0N2satisfying the conditions in Lemma3.5. In particular, 1.N /is a subgroup of1.M /. Then Proposition3.6constructs a nonclosed surface subgroup (free subgroup)1.†/ < 1.N /, and Proposition3.7shows that1.†/is not separable in1.N /. Finally, Lemma2.3implies that1.†/is not separable in 1.M /, and thus1.M /is not LERF.

IfM is a closed mixed3-manifold, then the above proof also shows the existence of a nonseparable free subgroup in1.M /. We need also to construct a nonseparable closed surface subgroup.

LetN !M be the finite semicover constructed in Lemma3.5(with@N ¤ ;), and let†N be the1-injective properly immersed surface constructed in Propo- sition3.6. To make the geometric picture simpler, we apply Lemma3.2to construct a finite coverM0ofM such thatN lifts to an embedded submanifold ofM0.

In this case, the induced map†M0is an immersion but is not a proper immer- sion. So we cannot use the proof of Proposition3.7for this†. Now we extend†to a closed surface†0, with an immersionjW†0M0. Then we can apply the argument in the proof of Proposition3.7to prove the nonseparability of1.†0/ < 1.M0/.

The construction ofj W†0M0is actually done in Section 8 of [24], so we only give a sketch here.

Let the boundary components of†bes1; : : : ; sm, with eachsi lying on a decom- position torusTiM0. By Theorem 4.11 of [13], there exists an essentially immersed subsurfaceRiM0, such that@Ri consists of two componentsbi andbNi, whilebi

andbNiare mapped to a positive and a negative multiple ofsiTi, respectively, with

(20)

the same covering degree. Moreover, a neighborhood of@Ri inRi is mapped to the side ofTithat is notN, andRi intersects withTM0 minimally.

Then we take some finite cover of†O !†such that each boundary component of†O that is mapped to si has covering degree deg.bi !si/, and we take another copy of †O with opposite orientation. Together with a proper number of copies of Ri,iD1; : : : ; m, they can be pasted together to get a1-injective immersed closed subsurface †0 M0. A similar argument as in Proposition 3.7 can be applied to

†O †0 to show that1.†0/is not separable in1.M0/, and so it is not separable in 1.M /.

IfM is a graph manifold, it was already shown in [30] that1.M /is not LERF.

So we only sketch the construction of nonseparable surface subgroups.

The first step is to show thatM has a finite semicoverN DSI =, whereSD S1[c[c0S2andis a composition of Dehn twists alongcandc0. Then we perturb the fibered structures on bothN1 andN2 (since Seifert-fibered spaces have less flexible fibered structures) to get a1-injective properly immersed subsurface similar to what we get in Proposition3.6. Then a similar argument as in Proposition3.7shows that this surface subgroup is not separable. Here, we do need to use the fact that two adjacent Seifert pieces in a graph manifold have incompatible regular fibers on their intersection torus.

However, in general, it does not seem easy to construct a nonseparable closed surface subgroup in a closed graph manifold.

Remark 3.9

In [35], the authors constructed a1-injective properly immersed subsurface † M for some graph manifold M. Then [29] proved that 1.†/ is not contained in any finite-index subgroup of 1.M / (not engulfed). In the proof of [29], only the infinite plane property of the surfaces constructed in [35] is used. Since the surfaces we constructed in the proof of Theorem 1.3 also have the infinite plane property, for any mixed3-manifoldM, we can find a finite coverM0!M and a1-injective properly immersed subsurface†M0such that1.†/is not contained in any finite- index subgroup of1.M0/.

In [30], it is shown that all graph manifold groups contain LD hx; y; r; sjrxr1Dx; ryr1Dy; sxs1Dxi

as a subgroup. Then the non-LERFness ofLimplies the non-LERFness of all graph manifold groups. It is easy to see that some mixed manifolds (e.g., the double of any cusped hyperbolic3-manifold) do not containLas a subgroup in their fundamental groups. SoLis not the source of the non-LERFness of these groups.

(21)

Since any free product of LERF groups is still LERF, we have the following direct corollary of Theorem1.3.

COROLLARY3.10

LetM be a compact orientable3-manifold with empty or tori boundary. Then1.M / is LERF if and only if all prime factors ofM support one of Thurston’s eight geome- tries.

Knot complements inS3also form a classical family of interesting3-manifolds, and each knot is a torus knot, a hyperbolic knot, or a satellite knot. We have the following corollary for knot complements.

COROLLARY3.11

LetM be the complement of a knotKS3. Then1.M /is LERF if and only ifK is either a torus knot or a hyperbolic knot.

4. Union of two hyperbolic3-manifolds along a circle

In this section, we will give the proof of Theorem1.4. The proof is very similar to the proof of Theorem1.3. For some lemmas and propositions in this section, we will only give a sketch of the proof; we point out necessary modifications of the corresponding proofs in Section3.

In the proof of the non-LERFness of 1.M1[S1M2/, we actually only use machinery on hyperbolic 3-manifolds for M1 (the crucial ingredient is the virtual retract property of its geometrically finite subgroups), and do not have much require- ment forM2. So we will have some more general results on the non-LERFness of Z-amalgamated groups in Section4.2.

4.1. Non-LERFness of1.M1[S1M2/for hyperbolic3-manifoldsM1andM2

Suppose thatM1andM2are two finite volume hyperbolic3-manifolds (possibly with cusps), and letikWS1!Mk,kD1; 2be two essential circles. Here, we can assume that bothikare embeddings into int.Mk/, and we denote the image ofikbyk. It is possible that the element in1.Mk/corresponding tokis a parabolic element or a nonprimitive element. For simplicity, the readers can think ofkas a simple closed geodesic inMkmost of the time.

LetXDM1[M2be the space obtained by identifying1and2by a home- omorphism; then we need to show that1.X /is not LERF. For a standard graph of space, the edge space should beS1I. Here, we directly pasteM1andM2together along the circles, which makes the picture simpler. We also give orientations on1

and2such that the pasting preserves orientations on these two circles.

(22)

For any point inX, either it has a neighborhood homeomorphic toB3(the open unit ball inR3) orBC3 (the points in B3 with nonnegativez-coordinate), or it has a neighborhood homeomorphic to a union of twoB3’s alongIzDB3\.z-axis/; that is,B3[IzB3.

We first give a name for the spaces that locally look likeB3,BC3, orB3[IB3. Definition 4.1

A compact Hausdorff spaceXis called asingular3-manifoldif, for any pointx2X, either it has a neighborhood homeomorphic toB3 orBC3, or it has a neighborhood homeomorphic toB3[Iz B3 withx 2Iz. We call points in the first classregular points, and we call points in the second classsingular points.

We can think of a singular3-manifoldXas a union of finitely many3-manifolds along disjoint simple closed curves, and we call each of these3-manifolds a3-manifold piece ofX.

In the proof of Theorem1.3, the concept of a finite semicover played an important role, so we need to define a corresponding concept for singular3-manifolds. Here, the set of singular points in singular3-manifolds corresponds to the set of decomposition tori in3-manifolds.

Definition 4.2

LetY,Z be two singular3-manifolds. A mapiWY !Zis called asingular finite semicoverif, for any pointy2Y, one of the following holds:

(1) imaps a neighborhood ofyto a neighborhood ofi.y/by homeomorphism.

(2) yis a regular point andi.y/is a singular point, such thatimaps aB3neigh- borhood of y to one of theB3’s in aB3[Iz B3 neighborhood of i.y/ by homeomorphism.

Under a singular finite semicover, all singular points are mapped to singular points, and all regular points not lying in a finite union of simple closed curves in Y are mapped to regular points. It maps each3-manifold piece ofY to a3-manifold piece ofZby a finite cover.

It is easy to see that a singular finite semicoveriWY !Z induces an injective homomorphism on fundamental groups. The author also believes that a singular finite semicover gives a separable subgroup1.Y / < 1.Z/, but we do not need this result here.

The following lemma corresponds to Lemma3.4.

Références

Documents relatifs

It is known (see [CCJ + 01], Corollary 7.4.2) that, if G belongs to the class PW, then G has the Haagerup property (or is a-T-menable), i.e. Up to now, the problem of stability of

(iii)⇒(iv) follows from Proposition 5.5 and the fact that any hyperbolic locally compact group admits a continuous, proper cocompact action by isometries on a proper hyperbolic

Complex reflection groups as Weyl groups.. Michel

It is known (see [CCJ + 01], Corollary 7.4.2) that, if G belongs to the class PW, then G has the Haagerup property (or is a-T-menable), i.e.. Up to now, the problem of stability of

On the other hand, the tameness theorem [Ago1, CG] asserts that, when K is a finitely generated torsion free Kleinian group, H 3 /K is homeomorphic to the interior of a

Alternatively, in the torsion-free case, if one could show that (hyperbolic) 3-dimensional Poincare duality groups are 3-manifold groups, then Thurston's Haken uniformization

Proof. — Use induction from, say, abelian subgroups. For the latter, since the exponent is either 4 or 6, the numbers of irreducible real and rational representations coincide. But

is finitely generated, abelian-by-finite and centralized by a finite index subgroup of Out (Γ). The case of a general polycyclic-by-finite group. — In this subsection, we ex- plain