The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
The H-principle for Isometric Embeddings
Vincent Borrelli
Université Lyon 1
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Isometric Maps
Definition.– A map f : (M n , g) −→ C
1E q is an isometry if f ∗ h., .i = g.
The length of curves is preserved by an isometric map.
In a local coordinate system x = (x 1 , ..., x n ) : 1 ≤ i ≤ j ≤ n, h ∂f
∂x i (x ), ∂f
∂x j (x )i = g ij (x ) The Janet dimension :
s n = n(n + 1)
2 .
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Isometric Maps
Definition.– A map f : (M n , g) −→ C
1E q is an isometry if f ∗ h., .i = g.
The length of curves is preserved by an isometric map.
In a local coordinate system x = (x 1 , ..., x n ) : 1 ≤ i ≤ j ≤ n, h ∂f
∂x i (x ), ∂f
∂x j (x )i = g ij (x )
The Janet dimension :
s n = n(n + 1)
2 .
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Isometric Maps
Definition.– A map f : (M n , g) −→ C
1E q is an isometry if f ∗ h., .i = g.
The length of curves is preserved by an isometric map.
In a local coordinate system x = (x 1 , ..., x n ) : 1 ≤ i ≤ j ≤ n, h ∂f
∂x i (x ), ∂f
∂x j (x )i = g ij (x ) The Janet dimension :
s n = n(n + 1)
2 .
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Nash-Kuiper Theorem
Definition.– A map f : (M n , g) −→ C
1E q is called strictly short if f ∗ h., .i < g.
John Forbes Nash Nicolaas Kuiper
Theorem (1954-55-86).– Let M n be a compact Riemannian manifold and f 0 : (M n , g) C
1
−→ E q be a strictly short
embedding. Then, for every > 0, there exists a C 1
isometric embedding f : (M n , g) −→ E q such that
kf − f 0 k C
0≤ .
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Nash-Kuiper Theorem
Definition.– A map f : (M n , g) −→ C
1E q is called strictly short if f ∗ h., .i < g.
John Forbes Nash Nicolaas Kuiper
Theorem (1954-55-86).– Let M n be a compact Riemannian manifold and f 0 : (M n , g) −→ C
1E q be a strictly short
embedding. Then, for every > 0, there exists a C 1
isometric embedding f : (M n , g) −→ E q such that
kf − f 0 k C
0≤ .
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Nash-Kuiper Spheres
?
Nash-Kuiper Spheres.– Let 0 < r < 1. There exists a
C 1 -isometric embedding of the unit sphere of E 3 in a ball of
radius r .
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Sphere Eversion
Sphere Eversion.– The sphere S 2 ⊂ E 3 can be turned
inside out by a regular homotopy of isometric C 1
immersions.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Flat Tori
Definition.– Any quotient E 2 /Λ of the Euclidean 2-space by a lattice Λ ⊂ E 2 is called a flat torus
Flat Tori.– Any flat torus E 2 /Λ admits a C 1 isometric
embedding in E 3 .
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Flat Tori
Definition.– Any quotient E 2 /Λ of the Euclidean 2-space by a lattice Λ ⊂ E 2 is called a flat torus
Flat Tori.– Any flat torus E 2 /Λ admits a C 1 isometric
embedding in E 3 .
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Our Goal
Goal of this talk.– To recover the Nash-Kuiper result on C 1 isometric embeddings from the machinery of the Gromov Integration Theory.
Our main ingredient.– The Gromov Theorem : Let R ⊂ J 1 (M, N) be an open and ample differential relation. Then R satisfies the parametric h-principle i. e.
J : Sol(R) −→ Γ(R) is a weak homotopy equivalence.
Our main obstacles.–
• The isometric relation is not ample
• The isometric relation is closed
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Decomposition
• For simplicity M n = [0, 1] n .
• The image of the metric distorsion
∆ := g − f 0 ∗ h., .i E
qlies inside the positive cone M of inner products of E n .
• There exist S ≥ n(n+1) 2 linear forms ` 1 , . . . ` S of E n such that
g − f 0 ∗ h., .i E
q=
S
X
j=1
ρ j ` j ⊗ ` j
where ρ j > 0.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Adapting the Gromov machinery
The strategy is to do the successive convex integrations along the S directions corresponding to the S linear forms
` 1 , ..., ` S .
rather than
along the n directions of the coordinates in [0, 1] n .
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Adapting the Gromov machinery
• This will produce S intermediary maps f 1 , ..., f S such that
g − f 1 ∗ h., .i E
q≈ρ 2 ` 2 2 +ρ 3 ` 2 3 +...+ρ S ` 2 S g − f 2 ∗ h., .i E
q≈ ρ 3 ` 2 3 +...+ρ S ` 2 S
.. . .. .
g − f S−1 ∗ h., .i E
q≈ ρ S ` 2 S g − f S ∗ h., .i E
q≈ 0.
• The map f := f S is then a solution of R e = Op(R).
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Adapting the Gromov machinery
We have
f j ∗ h., .i E
q− f j−1 ∗ h., .i E
q=(g − f j−1 ∗ h., .i E
q) − (g − f j ∗ h., .i E
q)
≈ ρ j ` j ⊗ ` j .
Hence, the fundamental problem is the following : Fundamental Problem.– Given a positive function ρ, a linear form ` 6= 0 and an embedding f 0 how to build an other embedding f such that
f ∗ h., .i E
q≈ µ
where µ := f 0 ∗ h., .i E
q+ ρ ` ⊗ ` ?
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
The one dimensional case
One dimensional fundamental problem.– Let
f 0 : [0, 1] −→ E q be an embedding, ρ a positive function,
` 6= 0 a linear form on R , how to build an other embedding f : [0, 1] −→ E q such that
∀u ∈ [0, 1], kf 0 (u)k 2 ≈ kf 0 0 (u)k 2 + ρ(u)` 2 (∂ u ) ?
• For short, we set r (u) :=
q
kf 0 0 (u)k 2 + ρ(u)` 2 (∂ u ).
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Choosing the Loops
with
∀s ∈ R / Z , h u (s) := r (u)e iα(u) cos(2πs)
and α(u) > 0 is such that Z 1
0
r (u)e iα(u) cos(2πs) ds = f 0 0 (u).
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Choosing the Loops
with
∀s ∈ R / Z , h u (s) := r (u)e iα(u) cos(2πs) and α(u) > 0 is such that
Z 1 0
r (u)e iα(u) cos(2πs) ds = f 0 0 (u).
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Our Convex Integration Process
• The convex integration formula : f (t) := f 0 (0) +
Z t
0
r (u)e iα(u) cos 2π N u du.
where e iθ := cos θ t + sin θ n with t := f
0 0
kf
00k and n is a unit normal to the curve f 0 .
Lemma.– The map f solves the one dimensional
fundamental problem. Its speed kf 0 k is equal to the given function r = (kf 0 0 k 2 + ρ` 2 (∂ c ))
12. Moreover
kf − f 0 k C
0= O 1
N
and if N is large enough f is an embedding.
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Our Convex Integration Process
• The convex integration formula : f (t) := f 0 (0) +
Z t
0
r (u)e iα(u) cos 2π N u du.
where e iθ := cos θ t + sin θ n with t := f
0 0
kf
00k and n is a unit normal to the curve f 0 .
Lemma.– The map f solves the one dimensional
fundamental problem. Its speed kf 0 k is equal to the given function r = (kf 0 0 k 2 + ρ` 2 (∂ c ))
12. Moreover
kf − f 0 k C
0= O 1
N
and if N is large enough f is an embedding.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Our Convex Integration Process
A short curve f
0(black) and the curve f obtained with the one
dimensional convex integration formula (grey, N = 9 and N = 20).
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• We assume for simplicity that ker ` = Span(e 2 , ..., e n ) and
`(e 1 ) = 1.
• Let s ∈ [0, 1] and c = (c 2 , ..., c n ) ∈ [0, 1] n−1 , we set f (s, c) := f 0 (0, c) +
Z s
0
r (u, c)e iα(u,c) cos 2πNu du
with r = p
µ(e 1 , e 1 ) = p
kdf 0 (e 1 )k 2 + ρ.
• The map f is not a solution of our Fundamental Problem. We do not have
kf ∗ h., .i E
q− µk C
0= O 1
N
with µ := f 0 ∗ h., .i E
q+ ρ ` ⊗ `.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• We assume for simplicity that ker ` = Span(e 2 , ..., e n ) and
`(e 1 ) = 1.
• Let s ∈ [0, 1] and c = (c 2 , ..., c n ) ∈ [0, 1] n−1 , we set f (s, c) := f 0 (0, c) +
Z s
0
r (u, c)e iα(u,c) cos 2πNu du
with r = p
µ(e 1 , e 1 ) = p
kdf 0 (e 1 )k 2 + ρ.
• The map f is not a solution of our Fundamental Problem.
We do not have
kf ∗ h., .i E
q− µk C
0= O 1
N
with µ := f 0 ∗ h., .i E
q+ ρ ` ⊗ `.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• By C 1, ˆ 1 -density we have
df (e j ) = df 0 (e j ) + O( 1 N )
• Thus, for all 1 < i , 1 < j, we have
(f ∗ h., .i E
q)(e i , e j ) = hdf (e i ), df (e j )i E
q= hdf 0 (e i ), df 0 (e j )i E
q+ O 1
N
= µ(e i , e j ) + O 1
N
• Therefore
k(f ∗ h., .i E
q− µ)(e i , e j )k C
0= O 1
N
for all 1 < i, 1 < j.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• By C 1, ˆ 1 -density we have
df (e j ) = df 0 (e j ) + O( 1 N )
• Thus, for all 1 < i, 1 < j , we have
(f ∗ h., .i E
q)(e i , e j ) = hdf (e i ), df (e j )i E
q= hdf 0 (e i ), df 0 (e j )i E
q+ O 1
N
= µ(e i , e j ) + O 1
N
• Therefore
k(f ∗ h., .i E
q− µ)(e i , e j )k C
0= O 1
N
for all 1 < i, 1 < j.
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• By C 1, ˆ 1 -density we have
df (e j ) = df 0 (e j ) + O( 1 N )
• Thus, for all 1 < i, 1 < j , we have
(f ∗ h., .i E
q)(e i , e j ) = hdf (e i ), df (e j )i E
q= hdf 0 (e i ), df 0 (e j )i E
q+ O 1
N
= µ(e i , e j ) + O 1
N
• Therefore
k(f ∗ h., .i E
q− µ)(e i , e j )k C
0= O 1
N
for all 1 < i , 1 < j.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• By definition of f we have
df (s,c) (e 1 ) = r (s, c)e iα(s,c) cos 2πNs .
• Thus
(f ∗ h., .i E
q)(e 1 , e 1 ) = hdf (e 1 ), df (e 1 )i E
q= r 2 (s, c)
= µ(e 1 , e 1 )
• Therefore
k(f ∗ h., .i E
q− µ)(e 1 , e 1 )k C
0= 0.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• By definition of f we have
df (s,c) (e 1 ) = r (s, c)e iα(s,c) cos 2πNs .
• Thus
(f ∗ h., .i E
q)(e 1 , e 1 ) = hdf (e 1 ), df (e 1 )i E
q= r 2 (s, c)
= µ(e 1 , e 1 )
• Therefore
k(f ∗ h., .i E
q− µ)(e 1 , e 1 )k C
0= 0.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• By definition of f we have
df (s,c) (e 1 ) = r (s, c)e iα(s,c) cos 2πNs .
• Thus
(f ∗ h., .i E
q)(e 1 , e 1 ) = hdf (e 1 ), df (e 1 )i E
q= r 2 (s, c)
= µ(e 1 , e 1 )
• Therefore
k(f ∗ h., .i E
q− µ)(e 1 , e 1 )k C
0= 0.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• The problem arises with the mixted term hdf (e 1 ), df (e j )i E
q, j > 1.
• Indeed, in the one hand
(f ∗ h., .i E
q)(e 1 , e j ) = hdf (e 1 ), df (e j )i E
q= hdf (e 1 ), df 0 (e j )i E
q+ O 1
N
= hr e iF , df 0 (e j )i E
q+ O 1
N
= hr cos( F )t, df 0 (e j )i E
q+hr sin( F )n, df 0 (e j )i E
q+ O
1 N
= r cos( F )
kdf 0 (e 1 )k hdf 0 (e 1 ), df 0 (e j )i E
q+O
1 N
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• The problem arises with the mixted term hdf (e 1 ), df (e j )i E
q, j > 1.
• Indeed, in the one hand
(f ∗ h., .i E
q)(e 1 , e j ) = hdf (e 1 ), df (e j )i E
q= hdf (e 1 ), df 0 (e j )i E
q+ O 1
N
= hr e iF , df 0 (e j )i E
q+ O 1
N
= hr cos( F )t, df 0 (e j )i E
q+hr sin( F )n, df 0 (e j )i E
q+ O
1 N
= r cos( F )
kdf 0 (e 1 )k hdf 0 (e 1 ), df 0 (e j )i E
q+O
1 N
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• In the other hand, since `(e j ) = 0, we have µ(e 1 , e j ) = hdf 0 (e 1 ), df 0 (e j )i E
q.
• Therefore
k(f ∗ h., .i E
q− µ)(e 1 , e j )k C
06= O 1
N
unless hdf 0 (e i ), df 0 (e j )i E
q≡ 0.
Claim.– This difficulty vanishes if the convex integration is done along the integral lines of a vector field W such that
∀j ∈ {2, ..., m}, µ(W , e j ) = 0
i. e. W is µ-orthogonal to ker `.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• In the other hand, since `(e j ) = 0, we have µ(e 1 , e j ) = hdf 0 (e 1 ), df 0 (e j )i E
q.
• Therefore
k(f ∗ h., .i E
q− µ)(e 1 , e j )k C
06= O 1
N
unless hdf 0 (e i ), df 0 (e j )i E
q≡ 0.
Claim.– This difficulty vanishes if the convex integration is done along the integral lines of a vector field W such that
∀j ∈ {2, ..., m}, µ(W , e j ) = 0
i. e. W is µ-orthogonal to ker `.
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
A technical difficulty
• In the other hand, since `(e j ) = 0, we have µ(e 1 , e j ) = hdf 0 (e 1 ), df 0 (e j )i E
q.
• Therefore
k(f ∗ h., .i E
q− µ)(e 1 , e j )k C
06= O 1
N
unless hdf 0 (e i ), df 0 (e j )i E
q≡ 0.
Claim.– This difficulty vanishes if the convex integration is done along the integral lines of a vector field W such that
∀j ∈ {2, ..., m}, µ(W , e j ) = 0
i. e. W is µ-orthogonal to ker `.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Adjusting the convex integration formula
Proposition.– The resulting map f solves the fundamental problem. Precisely
kf ∗ h., .i E
q− µk = O 1
N
where µ = f 0 ∗ h., .i E
q+ ρ ` ⊗ `. Moreover 1) kf − f 0 k C
0= O N 1
, 2) kdf − df 0 k C
0≤ Cte N + √
7ρ
12|`(W )|,
and if N is large enough, f is an embedding.
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Thickening the Differential
Relation
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Thickening the Differential
Relation
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Thickening the Differential
Relation
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Thickening the Differential Relation
Question.– Is the limit
−→0 lim f an isometric map (if it exists) ?
Answer.– No !
−→0 lim f = f 0 .
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Thickening the Differential Relation
Question.– Is the limit
−→0 lim f an isometric map (if it exists) ? Answer.– No !
−→0 lim f = f 0 .
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Approximating the Differential
Relation
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Approximating the Differential
Relation
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Iterated Convex Integrations
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Iterated Convex Integrations
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Iterated Convex Integrations
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Thickening the Differential Relation
Question.– Is the limit
k−→+∞ lim f k an isometric map (if it exists) ?
Answer.– Yes ! Let us see why
i) it is C 0 converging, ii) it is C 1 converging. Consequently
f ∞ := lim
k−→+∞ f k is a C 1 isometric map.
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
Thickening the Differential Relation
Question.– Is the limit
k−→+∞ lim f k an isometric map (if it exists) ? Answer.– Yes !
Let us see why
i) it is C 0 converging, ii) it is C 1 converging.
Consequently
f ∞ := lim
k−→+∞ f k is a C 1 isometric map.
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
C 0 Convergence
It is enough to control the difference kf k − f k−1 k C
0.
We set
f ∞ = lim
k→+∞ f k .
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
C 1 convergence
It is enough to control the difference kdf k − df k−1 k C
0.
kdf k − df k−1 k C
0≤ C te q
dist ( R e k −1 , R e k )
H-principle for Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?
C 1 convergence
It is enough to control the difference kdf k − df k−1 k C
0.
kdf k − df k−1 k C
0≤ C te q
dist ( R e k−1 , R e k )
The H-principle for
Isometric Embeddings
V.Borrelli
Isometric Maps How to deal with the non- ampleness ? The one dimensional case How to deal with a closed relation ?