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Characterizations of function spaces by the discrete Radon transform

A. Abouelaz a & T. Kawazoe b

a Department of Mathematics, Faculty of Sciences and

Informatics , University Hassan II , B.P. 5366, Maarif , Casablanca , Morocco

b Department of Mathematics , Keio University at Fujisawa , Endo, Fujisawa , Kanagawa , 252-8520 , Japan

Published online: 26 Sep 2011.

To cite this article: A. Abouelaz & T. Kawazoe (2012) Characterizations of function spaces by the discrete Radon transform, Integral Transforms and Special Functions, 23:9, 627-637, DOI:

10.1080/10652469.2011.618928

To link to this article: http://dx.doi.org/10.1080/10652469.2011.618928

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Integral Transforms and Special Functions Vol. 23, No. 9, September 2012, 627–637

Characterizations of function spaces by the discrete Radon transform

A. Abouelaza* and T. Kawazoeb

aDepartment of Mathematics, Faculty of Sciences and Informatics, University Hassan II, B.P. 5366 Maarif, Casablanca, Morocco;bDepartment of Mathematics, Keio University at Fujisawa, Endo,

Fujisawa, Kanagawa 252-8520, Japan (Received 22 May 2011; final version received 27 August 2011)

LetZnbe the lattice inRnandGthe set of all discrete hyperplanes inZn. Similarly, as in the Euclidean case, for a functionfonZn, the discrete Radon transformRfis defined by the integral off over discrete hyperplanes, andRmaps functions onZnto functions onG. In this paper, we determine the Radon transform images of the Schwartz spaceS(Zn), the space of compactly supported functions onZn, and a discrete Hardy spaceH1(Zn).

Keywords: linear diophantine equations; discrete Radon transform; discrete Fourier transform; charac- terization of the discrete Radon transform images

2000 Mathematics Subject Classification: Primary: 44A12; 44A53; Secondary: 05C25; 05C65; 08H10

1. Introduction

The Radon transform is a fundamental topic in the integral geometry, which plays a preponderant role in various fields of mathematics, physics, medicine, and so on. We briefly recall the classical Radon transformRon the Euclidean spaceRn, which is defined by integrating functionsf onRn over hyperplanesξ inRn

Rf (ξ )=

ξ

f (x)dξ(x),

where dξ(x) is then−1-dimensional Lebesgue measure on the hyperplaneξ. The fundamental problems of the integral geometry is to recoverf(x) fromRf (ξ )and to characterize the Radon transform images of some function spaces onRn. We refer to Helgason [4–6] to the ranges of the Radon transform. The goal of this paper is to obtain analogous results for the discrete Radon transformRonZn.

LetZnbe the lattice inRn. Fora =(a1, a2, . . . , an)∈Zn\{0}andk∈Z, the linear diophantine equationa·x=khas an infinity of solutions inZnif and only ifkis an integral multiple of the

*Corresponding author. Email: [email protected]

ISSN 1065-2469 print/ISSN 1476-8291 online

© 2012 Taylor & Francis

http://dx.doi.org/10.1080/10652469.2011.618928 http://www.tandfonline.com

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greatest common divisor d(a) ofa1,a2,. . .,an. Therefore, foraP = {z∈Zn\{0} |d(z)=1}, the set of solutionsH (a, k)= {x∈Zn|a·x=k}forms a discrete hyperplane inZn. LetGbe the set of all discrete hyperplanes inZn, which can be parametrized asP×Z/{±1}[1, §2]. As an analogue of the Euclidean case, the discrete Radon transformR, which maps functions onZn to functions onG, is given by

Rf (H (a, k))=

mH (a,k)

f (m)

for a suitable functionf onZn. In their previous paper, Abouelaz and Ihsane [1] investigated the basic properties ofR. Especially, the Strichartz-type inversion formula and the support theorem forRwere obtained. Moreover, they showed that the discrete Radon transformRis a continuous linear mapping ofS(Zn)intoS(G)(see Section 2 for the definitions of the Schwartz spaces on ZnandG). Our natural question is whether this mapR:S(Zn)S(G)is bijective or not. Let us suppose thatf belongs toS(Zn). LetFf (t )=

m∈Znf (m)eim·t,t∈Tn, denote the Fourier (inverse) transform off. Then, it follows from [1, Corollary 3.10] that forθ∈T

F1Rf (H (a,·))(θ )=Ff (θ a),

whereF1 is the Fourier (inverse) transforms onZ. We note thatFf is aC function onTn. Therefore, in order to show the surjectivity of the above mapping, we have to construct aC function onTnfrom (θ,a) variables inP. However, it is impossible, becauseθavaries in a dense subset ofTn(see Remark 9). Hence, the mapRfromS(Zn)intoS(G)is not bijective, and to characterize the Radon transform image ofS(Zn), a condition corresponding to the above relation inS(G)is required.

This paper is organized as follows. In Section 3, a characterization of the local Schwartz space S(Zna)is given. Here, we use a terminology ‘local’, when we fix anaP and we restrict our attention to a local areaZnainZnandGa = {H (a, k)|k∈Z}inG. A Paley–Wiener-type theorem is obtained in Section 4 (see Theorem 4). We determine the Radon transform image of the global Schwartz spaceS(Zn)in Section 5 (see Corollary 7). We introduce discrete Hardy spaces onZn andG, locally and globally, in Section 6 and we characterize their Radon transform images (see Theorem 13).

2. Notations

LetZn be a lattice inRn of alla=(a1, a2, . . . , an), ai ∈Z, equipped with the norm a2= a12+a22+ · · · +an2 and the inner producta·b=a1b1+a2b2+ · · · +anbn. For 1≤p <∞, let lp(Zn)denote the space of all complex-valued functionsf onZnwith finite norm:

fp=

m∈Zn

|f (m)|p 1/p

<.

We introduce a spaceGof hyperplanes inZn. Fora =(a1, a2, . . . , an)∈Zn\{0}, let d(a) denote the greatest common divisor ofa1,a2,. . .,an and putP = {a∈Zn\{0} |d(a)=1}. For each (a, k)P×Z, we define a discrete hyperplaneH(a,k) inZnby

H (a, k)= {m∈Zn|am=k}.

We denote by G the set of all discrete hyperplanes H(a,k) with (a, k)P×Z, which is parametrized asP×Z/{±1}. For 1≤p <∞, letlp(G)denote the space of all complex-valued

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Integral Transforms and Special Functions 629

functionsFonGwith finite norm:

Fa,p=

k∈Z

|F (H (a, k))|p 1/p

<

for allaP. We introduce the Schwartz spaces onZnandGas follows. LetS(Zn)denote the space of all complex-valued functionsf onZnsuch that for allN ∈N,

pN(f )= sup

m∈Zn(1+ m2)N|f (m)|<

andS(G)the space of all complex-valued functionsFonGsuch that for allN ∈N,

qN(f )= sup

a∈P,k∈Z

1+k2 1+ a2

N

|F (H (a, k))|<.

Forfl1(Zn), the discrete Radon transformRf onGis given by Rf (H (a, k))=

am=k

f (m). (1)

Then,Ris a continuous linear mapping ofl1(Zn)intol1(G)[1, Remark 3.8] and the Strichartz-type inversion formula is given as follows:

f (m)= lim

j→∞Rf (H (aj, aj ·m)),

whereaj=(1,j,j2,. . .,jn−1) [1, Theorem 4.1]. Moreover,Ris a continuous linear mapping of S(Zn)intoS(G)[1, Theorem 3.7]. ForfS(Zn)and a moderate growth functionφonZ

k∈Z

Rf (H (a, k))φ (k)=

m∈Zn

f (m)φ (a·m)

for all aP [1, Proposition 3.9]. In particular, by takingφ(k)=eikθ, it follows that for all (a, θ )P×T,

F1Rf (H (a,·))(θ )=Ff (θ a), (2) whereFandF1are Fourier (inverse) transforms onTnandT, respectively. Similarly, by taking φ(k)=k, it follows that for allp=0, 1, 2,. . .

k∈Z

Rf (H (a, k))kp=

m∈Zn

f (m)(a·m)p. (3)

In particular, as a function ofaP,

k∈Z

Rf (H (a, k))kpis a homogeneous polynomial inaof degreep. (4)

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3. Radon transform of local Schwartz spaces

As in the classical case (cf. [3, Theorem 2.4]), we shall consider local Schwartz spaces onZnand G, respectively. In what follows, we fix anaP. For each hyperplaneH(a,k), letpa,k∈Znbe the point inH(a,k) that is nearest from the origin. We set

Zna = {pa,k|k∈Z}. We define a local Schwartz spaceS(Zna)onZnby

S(Zna)= {fS(Zn)|supp(f )⊂Zna}. We denote byGathe set of all hyperplanes with directiona, that is,

Ga = {H (a, k)|k∈Z}.

SinceH (a, k)H (a, k)= ∅ifk=k and∪k∈ZH (a, k)=Zn, it is clear thatGa∩Ga = ∅if a=a and∪a∈PGa =G(see [1, §2] for more details). We define a local Schwartz spaceS(Ga) onGby

S(Ga)= {FS(G)|supp(F )⊂Ga}.

For a functionFonG, we denote byPGa(F )the function onGsuch thatPGa(F )(H )=F (H )if H ∈Gaand 0 otherwise.

Theorem1 For allaP,

PGaR(S(Zna))=S(Ga).

Proof The argument used in the proof that R(S(Zn))S(G) [1, Theorem 3.7] yields that PGaR(S(Zna))⊂S(Ga). We shall prove the converse inclusion. ForFS(Ga), we put

f (m)=

k∈Z

F (H (a, k))χpa,k(m),

whereχzdenotes the characteristic function of the pointz∈Zn. Then,f is supported onZnaand it follows Proposition 3.4 in [1] that

Rf (H )=

k∈Z

F (H (a, k))χpG

a,k(H ),

whereχzGis the characteristic function of the set of all hyperplanes containingz, that is,χzG= R(χz). IfH=H (a, k)∈Ga, thenRf(H(a,k))=F(H(a,k)) andRf(H)=0 otherwise. Therefore, PGaR(f )=F. Hence, to complete the proof of the surjectivity, it is enough to prove that fS(Zna). Sincef is supported onZnaandpa,k ≤ |k|, it follows that for allm=pa,k,

(1+ m2)N|f (m)| =(1+ pa,k2)N|f (pa,k)|

(1+k2)N|F (H (a, k))|.

SinceFS(G), it follows thatpN(f ) <∞.

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Integral Transforms and Special Functions 631

4. A Paley–Wiener-type theorem

We shall consider a discrete Paley–Wiener theorem relative to the discrete Radon transform, which characterizes the Radon transform image of functions on Zn with finite support. Let K= {x1,x2,. . .,xl}be a finite set inZn. We denote byDK(Zn)the subspace ofS(Zn)consisting of all complex-valued functions onZnsuch that suppf ⊂K. LetGK = {H∈G|HK= ∅}. We denote byDK(G)the subspace ofS(G)consisting of all complex-valued functions onGsuch that suppF ⊂GK. Then, each functionfDK(Zn)is of the form

f =

zK

f (z)χz.

As shown in the support theorem [1, Theorem 5.3],Rf is of the form

Rf =

zK

f (z)χzG (5)

and suppRf ⊂GK. Hence,Rfbelongs toDK(G). In what follows, we shall characterize functions of the form (5). We define a subspace ofDK(G)as

D,K(G)={FDK(G)|F satisfies the moment condition (4) and for eachm∈Zn, there existsjm∈Nfor which

F (H (aj, aj ·m))=F (H (ajm, ajm·m))for alljjm, (6) whereaj =(1, j, j2, . . . , jn1)}.

Lemma2 LetFDK(G)andaP. Assume that

k∈Z

F (H (a, k))kp =0 for allp=0,1,2, . . . .

Then, F(H(a, k))=0 for allk∈Z.

Proof We note that for a fixedaP,F(H(a,k))=0 except finitekand

p=0

k∈Z

F (H (a, k))(iθ k)p

p! =

k∈Z

F (H (a, k))eiθ k=0

for all θ∈T. Therefore,F1F (H (a,·))(θ )=0 and thus F(H(a,k))=0 for all k∈Z. Hence,

F=0.

Lemma3 Letm∈Zn.

(i) The case of mK: Letjm,K=

zKzm2. If jjm,K, then H (aj, aj ·m)K= ∅. (ii) The case of mK: LetjK =

zKz2. If j>2jK, then H (aj, aj ·m)K= {m}.

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Proof (i) LetmK andjjm,K. We assume thatH (aj, aj ·m)K = ∅andzH (aj, aj · m)K. This implies that

(z1m1)+(z2m2)j+ · · · +(znmn)jn−1=0.

Hence,j|(z1m1), and thus, there existsα∈Zsuch thatz1m1=αj. Then, it follows that (αj )2=(z1m1)2zm2jm,K.

Therefore,αmust be 0 andz1=m1. We repeat the same argument forz2m2and so on. Then, z=m. This contradictsmKandzK. Hence,H (aj, aj ·m)K= ∅for alljjm,K.

(ii) Let mK and j>2jK. We assume that zH (aj, aj·m)K. Similarly, as above, z1m1=αj. Then, it follows that

jKz2z21=m21+(αj )2+2αj m1

(αj )2−2|α|jjK = |α|j (|α|j−2jK).

Therefore,α=0 andz1=m1. We repeat the same argument forz2−m2and so on. Then,z=m.

Theorem4 R is a linear bijection ofDK(Zn)ontoD,K(G).

Proof LetfDK(Zn). As mentioned in the beginning of this section,RfDK(G), and it satisfies (4), becauseDK(Zn)S(Zn). Moreover, it follows from the proof of Theorem 4.1 in [1] that Rf satisfies (6). Therefore,Rf belongs toD,K(G). Since the inversion formula of R exists, it remains to prove the surjectivity ofR. LetFD,K(G). We define a functiongonZnby g(m)=limj→∞F (H (aj, aj ·m)). Then,gDK(Zn)by Lemma 3. SinceFsatisfies (6) andK is finite, there existsJK∈Nsuch thatg(m)=F(H(aj,aj·m)) for allmKandjJK. Therefore, it follows from (3) and Lemma 3 that for allj > j0 =max{2jK, JK}andp=0, 1, 2,. . .,

k∈Z

Rg(H (aj, k))kp =

m∈Zn

g(m)(aj ·m)p

=

mK

F (H (aj, aj ·m))(aj ·m)p

=

k∈Z

mH (aj,k)K

F (H (aj, k))

kp

=

k∈Z

F (H (aj, k))kp.

Hence,

k∈Z(RgF )(H (aj, k))kp=0 for allj>j0. SinceRf andFsatisfies (4),

k∈Z(RgF )(H (a, k))kpis a homogeneous polynomial inaof degreep, which is equal to 0 ata=ajfor allj>j0. Therefore,

k∈Z(RgF )(H (a, k))kp=0 for allaP. Then, by Lemma 2, we see

thatF=Rg. This completes the proof of the theorem.

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Integral Transforms and Special Functions 633

We rewrite Theorem 4 in terms of trigonometric polynomials. LetPK(Tn)=F(DK(Zn)), that is, the set of trigonometric polynomials onTnof the form

p(x)=

mK

cmeim·x.

LetP,K(P×T)denote the set of all functionsp(a,θ) onP×Twhose Fourier series p(a, θ )=

k∈Z

ca,keikθ satisfies

(1) ca,k=0 ifk=a·m,mK, (2)

k∈Zca,kkp is a homogeneous polynomial inaof degreep,

(3) for eachm∈Zn, there existsjm∈Nsuch that for alljjm,caj,aj·m=cajm,ajm·m. Then, it follow from Theorem 4 and (2) that

Corollary5 F1RF−1is a linear bijection ofPK(Tn)ontoP,K(P×T). In particular, P,K(P×T)= {p(θ a)|p(x)PK(Tn)}.

5. Characterization of global spaces

We shall obtain a global characterization of the Radon transform images of subspaces ofl1(Zn) in terms of the Fourier series. For a function G(t )L1(Tn), let

m∈ZnG(m)eˆ im·t denote the Fourier series ofG. For a subspaceXofL1(Tn), letXˆ denote the space onZnconsisting of all Fourier coefficients ofGX, that is,

Xˆ = {f :Zn→C| there existsGXsuch thatf (m)= ˆG(m)}. LetXGdenote a subspace ofl1(G)defined as

XG = {Fl1(G)| there exists aGXfor whichF1F (H (a,·))(θ )

=G(θ a)for all(a, θ )P×T}. (7)

Theorem6 Suppose thatXˆ ⊂l1(Zn). Then, R is a bijection ofXˆ ontoXG.

Proof SinceXˆ ⊂l1(Zn)andR(l1(Zn))l1(G),Ris defined onXˆ and eachRf,f ∈ ˆX, belongs tol1(G). Moreover, it satisfies (7) withG=FfX(see (2)). Hence,R(X)ˆ ⊂XG. Since the inversion formula ofRexists, it remains to prove the surjectivity ofR. LetFXGand suppose thatF1F (H (a,·))(θ )=G(θ a)forGX. SinceXˆ ⊂l1(Zn), it follows that

G(θ a)=

m∈Zn

G(m)eˆ −im·θ a=

m∈Zn

G(m)eˆ −iθ m·a

=

k∈Z

mH (a,k)

G(m)ˆ

⎠eiθ k.

Hence,F (H (a, k))=

mH (a,k)G(m). Therefore, if we define a functionˆ gonZnbyg(m)= G(m),ˆ m∈Zn, then F=Rg. Clearly, GX implies g∈ ˆX. This completes the proof of the

theorem.

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LetX=C(Tn). Then,Xˆ =S(Zn)andXGequals to

S(G)= {FS(G)| there exists aGC(Tn)for which (7) holds.} Corollary7 R is a bijection ofS(Zn)ontoS(G).

Let X=A1(Tn) be the subspace of L1(Tn) consisting of all GL1(Tn) such that

m∈Zn| ˆG(m)|<∞. Then,Xˆ =l1(Zn)andXGequals to

l1(G)= {Fl1(G)| there exists aGA1(Tn)for which (7) holds.} Corollary8 R is a bijection ofl1(Zn)ontol1(G).

Remark 9 (i) In Corollaries 7 and 8,Ris continuous; however, the continuity ofR1is an open problem. (ii) The left-hand side of (7) is a function ofθwith 0≤θ≤2πandGin the right-hand side is a function onTn. Therefore, for a fixedaP,θin the right-hand side varies in the set of 0≤θLa/a, whereLais the length of the line segment with directionabetween the origin and the boundary ofTn. Hence, if we rewrite (7) as

F1F (H (a,·)) θ

a

=G|

θ a a

, 0≤θLa, (8)

thena/a,aP, moves all rational points inSn−1∩Tn. Therefore, condition (8) implies that the left-hand side defined on

{|ωSn−1∩Tnand rational, 0≤rLω} can be extended to a functionGonTn.

6. Discrete Hardy spaces

The latticeZnis a space of homogeneous type, becauseZnis equipped with a Euclidean distance and a counting measure. Hence, we can introduce real Hardy spaces onZnaccording to the process in [2]. We shall prove that the Radon transformRlocally mapsH1(Zn)toH1(Z)and globally maps to an atomic Hardy space onG.

We briefly overview the definition ofH1(Zn)and its atomic decomposition. ForφS(Rn), we define a discrete dilationφt,t ∈N, ofφby

φt(x)=tn

m∈Zn

φ (t1m)χm(x), x∈Zn.

In the Euclidean case,φtis an approximate identity ast→0. Hence, to keep this property, we put φ0(x)=φ (0)χ0(x).

In what follows, we suppose that

Rnφ (x)dx =0. For anyfS(Zn), we define a radial maximal functionMφf onZnby

Mφf (x)= sup

t=0,1,2,...|fφt(x)|, x∈Zn,

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Integral Transforms and Special Functions 635

where * is the discrete convolution onZn. Then, the discrete Hardy spaceH1(Zn)is defined as H1(Zn)= {fS(Zn)| MφfL1(Zn)}.

We putfH1= Mφf1. Since|f(x)| ≤cMφf(x), it follows thatH1(Zn)l1(Zn). According to the process in [2, Chapter 3], we can obtain an atomic decomposition ofH1(Zn): we say that a functionbonZnis a(1,,0)-atom onZnif it satisfies

(i) suppbB(m0, r), (ii) brn, (iii)

m∈Znb(m)=0,

whereB(m0,r) is a closed ball centred atm0∈Znand radiusr∈N, which depends onb. Then, fH1(Zn)if and only if there exist a collection{bi}of(1,,0)-atom onZnand a sequence {λi}of complex numbers with

i|λi|<∞so that

f =

i

λibi,

and moreover,fH1 ∼inf

i|λi|, where the infimum is taken over all atomic decomposition off. Similarly, we can defineH1(Z)onZ. Forl∈N, we define a subspaceHl(Z)ofH (Z)as

Hl(Z)= {fH (Z)| f has an atomic decomposition with(1,,0)-atoms onZsupported on intervals with length 2rl,r∈N}.

Now, we shall characterize the image RbonGof a (1,,0)-atomb onZn. As pointed in Section 3, Rb=

zB(m0,r)b(z)χzG. Therefore, for each fixedaP, as a function ofk∈Z, Rb(H(a,k)) is supported on{a·z|zB(m0,r)}. We denote byk0=a·m0the middle point of this support. Then, we can easily deduce that

suppRb(H (a,·))⊂ [k0ar, k0+ ar],

because ifk=a·zis in the support ofRb(H(a,·)),|k−k0| = |a·(z−m0)| ≤ ar. We note that

|Rb(H (a, k))| ≤

mH (a,k)

|b(m)|

rn|H (a, k)B(m0, r)|

rncrn1

a =c(ar)−1 (9)

and

k∈Z

Rb(H (a, k))=

m∈Zn

b(m)=0. (10)

These properties imply thatc−1Rb(H(a,k) is a(1,,0)-atom onZwith radiusar. Therefore, if we defineRaby

Raf (k)=Rf (H (a, k)), we can obtain the following.

Proposition10 For eachaP,Racontinuously mapsH1(Zn)intoH1a(Z).

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For the surjectivity, we shall prove the following lemmas.

Lemma11 LetaPand Q be a cube inRnsuch that it is centred at the origin, each side length is2ar withr∈Nand a face parallels to H(a,0). Then, for each integer l∈[− ar,ar],

|QH (a, l)|contains at least(2r)n−1elements.

Proof Since Q is cubic, we may suppose l=0. When n=2, the assertion is clear.

Let a=(a1,a2,. . .,an), n≥3, and bi=(0,. . ., 0,ai,ai+1, 0, . . ., 0) for 1≤in−1. Then, it follows from the case of n=2 that there exist at least 2r elements ni,j= (0,. . ., 0,mi,j,mi+1,j, 0,. . ., 0)∈Qfor whicha·nij=bi·nij=mi,jai+mi+1,jai+1=0, 1≤j≤2r.

Hence, eachni,jbelongs toQH (a,0). Sinceni,j, 1≤in−1, are linearly independent, the

desired result follows.

Lemma12 LetaP. For each(1,,0)-atom B onZwith radiusar, r∈N,there exist a (1,,0)-atom b onZnand a constant C for which B=CRab, where C depends only on n and a.

Proof We may suppose thatBis supported on [− ar,ar]. LetQbe a cube inRnsuch thatQis centred at the origin, each side length is 2arand a face parallelsH(a, 0). By Lemma 11, for each integerl∈[− ar,ar],QH (a, l)contains (2r)n1integral points, say{mql}, 1≤q≤(2r)n1. We define a functionbonZnas

b(mql)=(2r)(n−1)B(l)

for− ar≤l≤ ar, 1≤q≤(2r)n−1and 0 otherwise. Thenbis supported onQB(0, ([√ n] + 1)ar), where [x] is the greatest integer not exceedingx. We note that

m∈Zn

b(m)=

l,q

b(mql)=

l

B(l)=0

by the moment condition ofB. Moreover, it follows that

|b(mql)| ≤(2r)(n1)|B(l)| ≤2a1(2r)n. Therefore, it is easy to see that 2n1([√

n] +1)nan+1bis a(1,,0)-atom onZn. Last we note that

Rab(l)=

mH (a,l)

b(m)=

q

b(mql)=B(l).

Hence,B=Rab=Cn,aRa(Cn,a−1b), whereCn,a =2n+1([√

n] +1)nan−1. Let FH1a(Z) and F =

iλiBi an atomic decomposition of F, where each atom Bi

is supported on an interval with length 2ar. Then, it follows from Lemma 12 that there exists a(1,,0)-atombi onZn so that Bi=Cn,aRabi. Therefore,F =Ra(

iλiCn,abi)and

i|λi|Cn,aCn,aFH1. Hence,

iλiCn,abiH1(Zn)andFRa(H1(Zn)).

Theorem13 For eachaP,Racontinuously mapsH1(Zn)ontoH1a(Z).

Now, we shall introduce an atomic Hardy space onG. LetB(m, r)⊂Znbe a closed ball centred atm∈Znwith radiusr∈N. We use the notation in Section 3 and we recall Theorem 4 and (9).

Downloaded by [Moskow State Univ Bibliote] at 19:47 11 November 2013

(13)

Integral Transforms and Special Functions 637

We say that a functionBonGis a(1,,0)-atom onGif it satisfies (i) BD,B(m,r)(G),

(ii) |B(H (a, k))| ≤ |H (a, k)B(m, r)|rn for allH (a, k)∈G, (11) (iii)

k∈Z

B(H (a, k))=0 for allaP,

whereB(m,r) depends onB. Clearly, if b is a(1,,0)-atom on Zn, thenRb is a(1,,0)- atom onG(see Theorem 4, (9), (10)). LetB be a(1,,0)-atom onG. Then, by Theorem 4 and its proof, R−1B is supported on B(m,r), and if xB(m,r), then for a sufficiently large j, H (aj, aj ·x)B(m, r)= {x} (see Lemma 3). Hence, it follows from (11) that

|R−1B(x)| = |B(H(aj,aj·x))| ≤rn, and thus,R−1Brn. Moreover,

m∈Zn

R−1B(m)=

k∈Z

mH (a,k)

R−1B(m)

=

k∈Z

B(H (a, k))=0.

Therefore, it is easy to see thatR1Bis a(1,,0)-atom onZn.

Finally, we define the atomic Hardy spaceH1,0(G)onGasFH1,0(G)if and only if there exist a collection{Bi}of (1,,0)-atoms onGand a sequence{λi}of complex numbers with

i|λi|<∞so thatF =

iλiBi. We putFH∞,01 =inf

i|λi|, where the infimum is taken over all atomic decomposition ofF. Then, the previous argument yields the following.

Theorem14 R is an isomorphism ofH1(Zn)ontoH1,0(G).

References

[1] A. Abouelaz and A. Ihsane,Diophantine integral geometry, Mediterr. J. Math. 5 (2008), pp. 77–99.

[2] G.B. Folland and E.M. Stein,Hardy Spaces on Homogeneous Groups, Mathematical Notes, Vol. 28, Princeton University Press, Princeton, NJ, 1982.

[3] S. Helgason,The Radon Transform, Progress in Mathematics, Vol. 5, Birkhäuser, Boston, MA, 1980.

[4] S. Helgason,Ranges of the Radon transforms,Computed tomography (Cincinnati, OH, 1982), Proceedings of Symposia in Applied Mathematics, Vol. 27, American Mathematical Society, Providence, RI, 1982, pp. 63–70.

[5] A. Hertle,On the range of the Radon transform and its dual, Math. Ann. 267 (1984), pp. 91–99.

[6] P.D. Lax and R.S. Phillips,The Paley–Wiener theorem for the Radon transform, Comm. Pure Appl. Math. 23 (1970), pp. 409–424.

Downloaded by [Moskow State Univ Bibliote] at 19:47 11 November 2013

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