M ARK D WYER
F RED R. M C M ORRIS
R OBERT C. P OWERS
Removal independence and multi-consensus functions
Mathématiques et sciences humaines, tome 148 (1999), p. 31-40
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REMOVAL INDEPENDENCE AND MULTI-CONSENSUS FUNCTIONS Mark
DWYER1,
Fred R.MCMORRIS2,3,
Robert C.POWERS1
RÉSUMÉ -
Indépendance
parsuppression
et multi-fonctions de consensus.Vincke et
Bouyssou
ont montré que, si uneprocédure d’agrégation
depréordres
totaux peut retournerplusieurs solutions,
alors elle peutsatisfaire
tous les axiomes du théorème d’Arrow sans être pour autant dictatoriale. Nous étendons cetteapproche
aux hiérarchies utilisées enclassification.
Dans ce contexte, on obtient des résultats qui peuventdifférer
de ceux de Vincke et de
Bouyssou.
MOTS-CLÉS - Théorie de la
décision,
consensus,multi-fonctions
de consensus, hiérar-chies,
théorème d’ArrowABSTRACT - Work
of
Vincke andBouyssou
showed thatif aggregation procedures
on weak orders are allowed to return more than one
result,
then itmight
bepossible for
aprocedure
tosatisfy
all the axiomsof
Arrow’s Theorem yet not be dictatorial. Thisapproach
is extended
from
ordered sets to n-trees, which are set-systems used inclassifications theory.
Results in this context can
differ from
thoseof
Vincke andBouyssou.
KEYWORDS - Decision
theory,
consensus, multi-consensusfunction, hierarchies,
Ar-row’s Theorem
1. INTRODUCTION
Vincke
(1982)
andBouyssou (1992)
havegiven thought provoking interpretations
of the classical
impossibility
result of Arrow(1963).
A centralpoint
of these paperswas that if
aggregation procedures
on weak orders are allowed to return more thanone result and Arrow’s axioms are extended to this
situation,
then"possibility"
rather than
"impossibility"
may occur.1 University
of Louisville, Louisville, KY 40292, U.S.A.2Illinois Institute of Technology, Chicago, IL 60616-3793, U.S.A.
3email: mcmorrislâiit.edu
In the
present
paper we consider a class of hierarchies(called n-trees)
ratherthan the classical weak
orders,
anddevelop
a program similar to that of Vincke andBouyssou.
Ann-tree,
viewed as a hierarchicalclassification, might
resultafter the
application
of aclustering algorithm
toappropriate
data. If several ofthe many available
algorithms
are used on the samedata,
theproblem
ofproducing
an overall summary
(consensus)
n-tree isclearly
one of decisionanalysis.
Since theearly
1970’s(as
asample,
see Adams1972, Barthélemy
et al.1986, Lapointe
andCucumel 1997,
Leclerc andCucumel 1987)
thisapproach
has been used in an areaof
biology
called NumericalTaxonomy,
forexample.
Because of theimpact
andbeauty
of Arrow’s Theorem in the socialsciences,
this is often atarget
theoremin more
general
contexts such asn-trees,
but for n-trees a richvariety
of resultscan occur.
Indeed, Barthélemy
et al.(1995)
have shown that there are at least 9 distinct versions of theindependence
of irrelevant alternatives axiom of Arrow. Asour
starting point,
we will use theanalog
of Arrow’s Theorem for n-treesproved by Barthélemy
et al.(1991) using
thekey
axiom of "removalindependence".
2.
DEFINITIONS,
TERMINOLOGY AND TECHNICAL BACKGROUND Let S be a finite set with n elements. An n-tree on S is a set T of subsets of Ssatisfying: S e T; 0 e T; ~x~
e T for all x eS;
and X n Y E{0, X, Y}
for allX, Y
E T. If X E T with 1~X~
n then X is called a nontrivial cluster of T.T0
will denote the n-tree with no nontrivial clusters. For X any subset ofS, Tlx
denotes the n-tree on S whose nontrivial clusters are thenonempty
distinct elements of{~4 D
X : A is a nontrivial cluster ofT}.
Another very useful wayto realize an n-tree T is
by
its associatedternary
relation(Colonius
and Schulze1981)
wherexylrz
if andonly
if there is an A E T such that x, y EA,
andz e
A.Elements in this
ternary relation
are called triads. The set of all n-trees on S will be denotedby Tn.
We letP(X)
denote the set of all subsets of a setX,
and~m(X)
denote the set of all subsets of X with no more than m elements.A consensus
function
onTn
is a function F:7~ 2013~ Tn,
where k is apositive
integer
and7,-,’
is the k-fold cartesianproduct.
Elements of7-nk
are calledprofiles
and are denoted
by
P =(tel, ... , Tk),
P’ _(Tl, ... , Tk)
and so on. For X EP(S)
and
profile
P =(Tl, ... , Tk),
we letPlx - (Ti ( x, ... , Tklx).
In the classicaltheory
of Social Choice initiated in Arrow(1963), 7~
isreplaced by
the set ofall weak orders on
S,
and consensus functions are called socialwelfare functions.
As mentioned in the
Introduction,
there has been agood
deal of workstudying
various forms of consensus functions for tree structures. A nice summary of this
work, including
more than 90references,
can be found in Leclerc(1998).
Most of the axioms for social welfare functions have
analogs.
Forexample,
a consensus function F satisfies the Pareto condition
if,
for anyprofile
P =(Tl, ... , T~); A
ETi
for allz, implies
that A EF(P),
i.e.n Ti C F(P).
F issaid to be
independent, (o f
irrelevantalternat2ves) if,
for any twoprofiles P, P’;
Plx - P’Bx implies
thatF(P)lx == F(P’)Bx.
The immediateanalog
of Arrow’sImpossibility
Theorem would read: If a consensus function satisfies the Paretocondition and is
independent,
then it is adictatorship,
where F is a dictator con-sensus function if there exists
a j
such that for allprofiles P;
A ETj implies
A e
F(P).
InBarthélemy
et al.(1991)
anexample
wasgiven showing
that thisstraightforward
translation of Arrow’s theorem is not true and that theindepen-
dence axiom needs to be modified.
Indeed,
inBarthélemy
et al.(1995),
severalversions of
independence
that can be defined for7-,
were studied. For a non-trivial subset X C S and T e
Tn,
letTjx -
X denote the n-treeTlx
withoutthe cluster X. As
expected,
for aprofile
P we writeP~X - X
for theprofile
F satisfies removal
independence
when forevery X
C Sand
profiles P, P’; Plx -
X =pllx -
Ximplies
thatF(P) lx -
X =F(PI)/X -
X.The main result in
Barthélemy
et al.(1991)
states that if F is a consensus func- tion onTn
that satisfies the Pareto and RemovalIndependence conditions,
thenit is a dictator consensus function. It is this result that we will
place
in the con-text
developed
in Vincke(1982)
andBouyssou (1992)
where a consensus functionis allowed to be set-valued.
Specifically,
a function F :T ~ -~ ~ (Tn ) - ~ ~ ~
is amulti-consensus
function
onTn.
A multi-consensus function F is an m-consensusfunction
if it maps F :7~ 2013~ 7~~ (7~) 2013 {0}.
Thus a 1-consensus function isjust
an
ordinary
consensus function.We now
give straightforward generalizations
of the axioms of Pareto and Re- movalIndependence
to the multi-consensus caselabeling
them(P)
and(RI).
Let F be a multi-consensus function on
Tn.
Then F satisfies the Pareto condi- tion(P) if,
for everyprofile
P =(Tl, ... , T~); A
Elll
for every iimplies
that A E Tfor every T E
F (P).
F satisfies rerrzovalindependence (RI) if,
forevery X
E S’ andprofiles
P andP’; Plx -
X =P’Ix -
Ximplies that,
for each T eF(P),
thereexists T’ e
F(P’)
such thatAs first observed
by
Vincke(1982)
in the context of consensus functions onweak
orders,
the dictator axiom has two very natural extensions to multi-consensus functions.Obviously
this is the case here also. F is a(strong)dictator (D)
multi-consensus function if there exists
a j
such that for everyprofile
P =(Tl, ... , T~),
there exists a T e
F(P)
withT~ C
T. F is a weak dictator(WD)
multi-consensus function if there existsa j
such that for everyprofile
P =(Tl, ... , Tk), ll§ C
UTEF(P)
T.Clearly
condition(D) implies
condition(WD)
and that for 1-consensus functionsthey
both areequivalent
to the standard definition of a dictator consensusfunction.
3. EXAMPLES
In this section we first
present
anexample showing
that it ispossible
to have amulti-consensus function that satisfies
(P)
and(RI)
but not(WD) [and
hence alsonot
(D)].
This contrasts with the situation in Vincke(1982)
for weakorders,
whereit is shown that every multi-consensus function on weak orders
satisfying
Paretoand
Independence
mustsatisfy (WD).
EXAMPLE 1. For an
exarrzple
we let 5 =={X1,X2,X3,X4,XS}, Sl
=txl ~ X21 X3, X4 1,
and
S2
=fX2,
X3, X4, SetM(Si)
to be the setof
all 5-trees T on S where= T and T has
exactly
one clusterof
size 2 and 3. Notethat ]
=12. Let
M(Sl) = IT1,
...,T12}
and~I (S2) _ IT13,
...,T241-
Consider theprofile
Now
for 25
i 48 setDefine
.by
Clearly
F satisfies(P).
To see that F does notsatisfy (WD)
we needonly
look atthe
profile P.
Forevery j
E{1,.... 12}
and T EF(P),
we haveTj B T,
while forevery j
Ef 131
...,241
and T EF(P)
we havefX2,
X3, X4,X51
ETjBT-
To check that F satisfies
(RI) requires
a tedious butstraightforward
caseby
caseanalysis.
Example
1 usedprofiles
oflength
24 for the domain. It would beinteresting
to find the smallest k for which there exists a multi-consensus function F :
T~ 2013~
{0} satisfying (P)
and(RI)
but not(WD).
In the next section we show that it is
impossible
to construct a function as inExample
1 if we restrict ourselves to 2-consensus functions. This then raises thequestion
as to whether there is a 2-consensus functionsatisfying (P)
and(RI)
butnot
(D).
Our nextexample
shows that this is indeed the case, andparallels
thework
by Bouyssou (1992)
for weak orders.. EXAMPLE 2 . Let S =
{~l~2~3~4~5,~6}
the 6-trees on Sdefined as follows (only listing
the nontrivialclusters):
Set P = (T1,T2).Define by
1
Clearly
F satisfies(P).
To see that F does notsatisfy (D)
we needonly
look atthe
profile
P and observe that neitherT1
norT2’
is a subset ofT3
orT4.
An eveneasier case
argument
shows that F satisfies(RI).
4. A DICTATORSHIP RESULT
The
goal
of this section is to statecarefully
and prove our main result which was mentioned in the context of Section 2.THEOREM 3 . Let
181
= n > 4 and let k > 3.If
and
(RI),
then Fsatisfies (WD).
satisfies (P)
What now follows is a series of technical
results, eventually leading
to theproof
of Theorem
3, although
we feel that several of these results areinteresting
in theirown
right.
Let F :
7-k T~(T~) 2013{0}
be a multi-consensus function that satisfies(RI)
and(P).
Since the consensusoutput F(P)
is a set of n-trees we will write AEV F(P)
ifA E T for some T E
F(P). Moreover,
we will write AEÂ F(P)
if A e T for everyT E
F(P).
This notation will be extended to triads. Soablc cv F(P)
means thatablTe
for some T EF(P)
andabjc EÂ F(P)
means thatab/Te
for every T EF(P).
If
Pl f a,b,cl - f a, b, cl
=la, b, cl, then,
since F is removalindependent, EV F(P) implies cv F(P’).
Since this situation occursfrequently
wewill
only
write the conclusion:able cv F(P) implies able EV F(~).
The readershould understand that we are
applying
the axiom of removalindependence
andthat the
hypothesis,
= holds true.Finally,
let
(T0,
...,T0)
andPA
=(TA,
...,TA)
be notation for constantprofiles
whereWe will assume
throughout
this section that F :7~ 2013~
satisfies(P)
and(RI).
The firstlemma, however,
is true even if wereplace P2(T n) by P(T n) - {0}.
LEMMA 4 .
If abjc cv F(P0) for
some a,b,
c ES,
thenxylz EV F(P0) for
allx, y, z E S.
Proof.
We aregiven
thatab 1 c EV F(P0)
for some a,b,
c E S. Let zb, c}.
Then
ab 1 c EV F(P0) implies ab 1 c EV
Sincef c, z 1 EÂ
it followsthat
C’
Nowablz EV implies ablz cv F(P0).
Soablz cv F(P0)
Let E
~B fa, b, cl.
Thenablc cv F(P0) implies ablc ev
Sinceta, xl CA
it follows thatxblc Eiv
Nowcv implies xblc cv F(P0).
Soxblc EV F(P0)
for all x ES B (b, cl.
It now follows that
ev F(P0)
for all x, y, z E S. 0PROPOSITION 5 .
F(P0) == {T0}.
Proof.
AssumeF(P0) i- ~T~~.
Then thereexists a, b,
c E S such thatab 1 c EV F(P0).
By
Lemma4, ev F(PO)
for all e S. Inparticular,
there exist threepairwise incompatible
triads in at most two n-trees which is a contradiction. DThe next lemma is a "Co-Pareto condition" on triads.
LEMMA 6 . Let P =
(Tl, ..., T~)
ET~. EV F(P) for
somea, b, c
E5,
thenb|c E T1 U T2 U ....U
Proof.
Assumeab Ji
LetThen
EV F(P) implies ab)c cv F(P). Since Ti
E for i =1, ...,1~,
it follows thatwhere E
S B ta, b, cl.
Sinceablx e’ F(P0)
it follows thatablx ev F(P).
Notethat
ablc EV F(P)
andablx e vF (P) imply F(P).
LetNote that
Ti
E for i =1,...,
k. NowE’ F(P) implies ax 1 c C’ F(P).
So
axlb cv F(P)
orbxlc cv F(P). If ax|b EV F(P),
thenaxlb EV F(P0)’
Ifbxlc cv F(P),
thenbxlc EV F(Pm).
In either case we contradictF(P0) ==
Let K denote the set
{l, ...,
For any D C K and x, y ES,
letwhere
Ti
= for i E D andTi = T0
for i EK ~
D.LEMMA 7.
Proof.
This result followsimmediately
from Lemma 6. DLet D=
{D Ç K : EV F(Plx,yl;D)
for some x, ye SI.
Since F satisfies(P)
it follows that K E D.LEMMA 8 .
If M
is a minimal setbelonging
toD,
then = 1.Proof.
Assume there exists a minimal set Mbelonging
to D suchthat IMI
> 2.Since there exist a, b E S such that
ta, b~ ev
Let c ES B ta, bl and j
e M. Define P =(Tl,
...,Tk)
as follows:Ti
=Tta,bl; Ti
= forLet
dES B cl
and set P’ =(~,..., T~) - {a, b,
Note thatTf
= for i E M andT’
=T0
for i EK 1
M.So
f a, bl Ev F(P’).
Nowab 1 d c’ F(P’) implies
thatab d Ev F(P).
Sinceax 1 d e
Tl
U .... UTk
for all x ES B {a, b,
c,d}
it follows from Lemma 6 thataxld ftv F(P)
Thus
ta, bl Ev F(P)
or(a, b, cl EV F(P).
If
{a, bl Ev F(P),
thenab)c ev F(P).
NowEv F(P) implies
thatcv
since =
ta, b, c~.
It follows from theprevious
lemmathat
fa, bl ev
So{ j ~
E Dcontrary
to theminimality
of M.If
ta, b, cl Eiv F(P),
thenEV F(P).
NowE" F(P) implies
thatE"
since
tb,
c,dl.
It follows from theprevious
lemma that
~b, cl C’
SoM B
E D. Thisagain
contradicts theminimality
of M andcompletes
theproof. D
Since D is
nonempty
it contains at least one minimal set. For convenience wewill assume
that {1}
e D. So~a, b~ EV
for some a, b e S.LEMMA 9. For any 1
Proof.
Let y ES B la, bl
and set P = ...,i Ttb,yl) -
If z ES B ta, b, y 1,
then
EÂ F(P).
NowEV implies
thatC’ F(P). Putting together c" F ( P)
andEV F(P)
weget cv F(P).
The latterimplies
that
ev F(Pfa,yl;fll)-
So~a, y~ EV F(Pta,yl;fll)
for any yla, bl.
If wefix y,
then, by symmetry, lx, YI ev
for any x E S. The result nowfollows. D
LEMMA 10 . For any x, y E S and D
C
K with 1 ED, lx, yl ev
Proof.
Let x, y e S and DC K
with 1 E D. Define P =(Tl,
...,Tk)
as follows:Tl
=Tfxlyl; Ti
=Tfxly,zl
for i ETi
=T0
for i EK ~ D.
ThenEiv F(P)
since = Since
ywlz e
for all w eS ~
it follows from Lemma 6 that
ywlz ev F(P)
for all w ES B lx,
y, So?/} C-’
F(P).
Inparticular, xy 1 w EV F(P)
where w ES B t x,
y,z 1.
Nowxy 1 w E" F(P) implies
thatev By
Lemma7, lx, yl ev F(Pf.,YI;D).
DIt follows from the last lemma that for any D
C K,
with 1 ED,
D E D.LEMMA Il . Let
ablc cv F(P).
If
ETi
andbcla tt
thenProof.
NowTl 1 t,,,b,,l - ta, b, cl
= and -la, b, cl
ETf a,,,l 1
for i =
2,..., k.
Let P =cl
and setP
=la, b, dl.
Notethat
P
= with 1 E D.By
theprevious lemma, la, bl cv F(P).
Soev F(P).
NowEV F(P) implies_that EV F(P).
Sincebcld e
it follows from Lemma 6 that
bcld ev F(P).
Soab c Eiv F(P).
NowEiv F(P) implies
thatev F(P) . D
By symmetry
we couldreplace bcia
in theprevious
lemmaby ac b.
LEMMA 12 . Let
If ablc
ETl,
thenablc e’ F(P).
Proof.
Let~a, b, c}
and set P’ _(T’~,...,~)
whereT{
= andTl
={a, b, c}
for 2 =2,...,
k. If{a,
c,d} =
p" _(Tl’, ..., ~),
then
adle
ETi’
andBy
theprevious lemma, ad~c e~ F(P").
Thelater
implies
thatadle EV F(P’).
Sinceadlb rt.
it follows from Lemma 6 thatadBb tf-v F(P’).
Nowad~c EV F(P’)
andF(P’) imply
thatF(P’).
Finally, able EV F(P’) implies
thatable EV F(P). D
LEMMA 13 . The set D conta2ns at most two minimal sets.
Proof. By
Lemma8,
a minimal set from D is asingleton
set. We know that{1}
e D. Assume that D contains at least two other minimal setsbesides ~ 1 } .
For convenience we will assume that
{2}, {3}
E D. It follows from theprevious
lemma that
EV F (P)
where P = Since2 we obtain a contradiction. n
We know
that {1}
e D.By
theprevious lemma,
D contains at most one othersingleton
set. This means that there are at least k - 2singleton
subsets of K that do notbelong
to D. For convenience we may assume thatf Z« 1 e
D for i =3,..., k.
Thus
{2}
may or may not be an element of D.The next lemma is an
improvement
of Lemma 6.LEMMA 14. Let
If ablc C’ F(P),
thenablc
ETl
UT2.
Proof.
Nowab 1 c E‘’ F(P) implies
thatab 1 c E’ F (P 1 f a, b,,l - 1 a, b, c}).
It follows from Lemma 6 thatabld C’ ta, b, cl) {a, b, c~.
Nowabld EV
la, b, cl) implies
thatabld C’
where(a, b, d) .
It follows from Lemma 7 that{a, b} EV
80D E D. It follows from the
previous
lemma that either 1 e D or 2 E D. Thusn
LEMMA 15. Let
If ablc
ETl
f1T2,
thenablc EÂ F(P).
Proof.
Define P’ _(TI,
...,T~)
as follows:Tl
=T2
= andT’
= Utia, b, cll
for i =3,..., k.
So~a, b, CI
=c~.
Note thatabld E T’
for i =1,
..., k. It follows thatab | â E/B F (P’ ) .
SinceTl
UT2
itfollows from the
previous
lemma thatev F(P’).
Soablc E/B F(P’).
The laterimplies
thatabjc E/B F(P). D
For the next lemma we will use the
following
notation. For any T E7-k
andnonempty
subset A of S we letLEMMA 16 . Let P =
T~.
Let A be a maxirrzal cluster inTl
whichis not
properly
contained in a nontrivial cluster inT2.
Then AC’ F(P).
Proof.
Let7~ F(P).
If A ET,
then we’re done. IfA tt T,
thenAT D
A. We nowassert that AT = S.
Assume AT C S. Let x e
AT ~ A
and z Then e T forall y
e A.By
Lemma14,
eTl
UT2
for all y E A. Since A is maximal inTl, xy 1 z Tl
for
all y
E A. So ET2
for all y E A. This means thatT2
has a cluster thatproperly
contains Acontrary
to thehypothesis.
So AT - S.Let M =
{X
E XC A
and X ismaximal }.
Thatis,
M contains themaximal clusters in which are subsets of A. Since AT = S’ it follows that
IMI
> 2.Let
X,
X’ E M. For any x EX, y
e X’ and z ES B A, xylz e
T.(Otherwise,
there exists Y E T such that x, y e Y
and z e
Y. Then A n Ye Tj A
intersects two maximal clusters inT 1 A.)
So E T’ where T’ EF (P) B {T}.
For any x, x’ e Xand z E E T’ since
xy 1 z
andx’y 1 z belong
to T’ where y E X’. It followsSoAET’.
Hence A E’ F(P). r-1
LEMMA 17 . Let Let A be a maxzmal cluster in
Tl
whichis
properly
contained in a nontrivial cluster B inT2.
Then A C’F (P) .
Proof.
Take B to be the smallest cluster inT2
thatproperly
contains A and letP’ = B =
(Tl,
...,Tk) -
Then A ETl
is maximal and it is notproperly
contained in a cluster from
T2. By
theprevious lemma,
Aev F(P’).
So AC’
for some X Eiv
F(P).
If there exists x eXBA,
thenx e B. Thenx,yeXandz eX. Soxy|zev F(P).
By
Lemma14,
ETl
UT2.
Ifxy 1 z
ETl,
then there exists Z ETl
such thatx, y E Z and and A
contrary
to themaximality
of A.So
xylz e Ti .
IfT2,
then there exists Z ET2
suchthat x,
y e Zand z e
Z.Note that B n
Z 7~ 0
andZ g
B.Also, B g
Zsince z e
Z. So B and Z can notbelong
to the same n-tree. In sum, there does not exist x EX B
A. So XÇ
A.But A = X n B
implies
that AC
X. So A = X. Hence AEV F(P).
0It follows from the
previous
two lemmasthat,
for any P =(T1, ..., T~),
i AE‘’
F(P)
whenever A is a maximal cluster inTl.
We can nowcomplete
theproof
ofTheorem 3.
LEMNIA 18. Let then A
EV F(P).
Proof.
Let A eTl .
If A is a maximalcluster, then,
aswe j ust observed, A EV F ( P) .
So we may assume that A is not maximal. Then there exists a chain
of j
> 2(nontrivial)
clustersA2 D
... DAj
inTl
such thatA1
ismaximal, Ai+1
is aproper subset of
Ai
for i =1, ..., j -1, and Aj
= A.Further,
we want this chainto be maximal in the sense that there does not exist a chain
with j + 1
clusterssatisfying
theprevious properties.
From Lemmas 16 and17, Ai cv F(P) ,
so ournext
goal
is to show thatF(P).
Let P’ =
PIAI - (Tl,
...,T~).
Note thatA2
ETl
is maximal and soF(P’)
ThusA2 ev Al.
SoA2 =
X for some XC’ F(P).
IfA1
and X are contained in the same n-tree in theoutput F(P),
then X =A2
andwe’re done. So we may assume that
A,
e T and X E T’ whereF(P) = IT, Tl.
We may assume that there exists x
e X B A2.
Now for any y EA2
andz E
A, B A2, F(P) B Tl.
So ET2
for all y EA2
and z EA, B A2.
Itfollows that
T2
contains a cluster Z such thatA2
C Z and Z n(~4i B A2) = 0.
Notethat e
Tl n T2
for all a, b EA2
and c CAI B A2. By
Lemma15, able EÂ F(P)
for all
a, b
eA2
and c EA2.
Inparticular, abjc
E T for alla, b
eA2
andc E
A2.
SinceA1
E T it follows that e T for all a, b eA2
and c ES’ ~ A1.
In sum,
able
E T for all a, b eA2
and ce S B A2.
ThusA2 cv F(P).
This
argument
can berepeated
to establish thatAi EV F(P)
for i =2, ..., j.
Inparticular, A = Aj ev
ACKNOWLEDGEMENTS - This research was
supported
in partby
ONR grants N00014- 95-1-0109 andN00014-94-1-0955(AASERT)
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