C OMPOSITIO M ATHEMATICA
R. A. R ANKIN
The zeros of certain Poincaré series
Compositio Mathematica, tome 46, n
o3 (1982), p. 255-272
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255
THE ZEROS OF CERTAIN
POINCARÉ
SERIESR.A. Rankin
© 1982 Martinus Nijhoff Publishers - The Hague Printed in the Netherlands
1. Introduction
K. Wohlfahrt
[6]
showed in 1964 that theonly
zeros of the Eisen- stein seriesEk
for the modular group lie on transforms of the unit circle when 4 ~ k ~26,
andconjectured
that this holds for all k & 4.The range of k was extended to k 5 34 and k = 38 in
[4],
but in[2]
F.K.C. Rankin and H.P.F.
Swinnerton-Dyer proved
Wohlfahrt’s con-jecture
for all kby
asimple argument.
The purpose of thepresent
paper is to show that similar
properties
hold for a wide class ofmeromorphic
modular formsbelonging
to the modular group. Inparticular,
it is shownthat,
ifGk(z, m)(m
EZ)
is the mth Poincaré series ofweight k,
then for m :5 1 all its finite zeros in the standard fundamentalregion
lie on the lower arcA,
while for m > 1 at mostm - 1 of these zeros do not lie on
A;
for m = 0 thisreproduces
theresult of
[2].
Throughout
the paper 1 shall be concerned withmeromorphic
modular forms of even
positive weight k 2:
4 on the upperhalf-plane
H =
f z:
Im z >01
for the modular groupThe vector space of all such forms is denoted
by Mk. Thus,
iff
EMk, f
has a Fourier seriesexpansion
of the formwhich is
convergent
when Im z issufhciently large.
Thesubspace
of0010-437X/82060255-18$00.2010
Mk consisting
offorms f
EMk
that areholomorphic
on H is denotedby Hk ;
for such forms the series(1.1)
converges for all zEH. Thesubspace
ofHk consisting
of cuspforms,
for which we can takeN = -
1,
is denotedby Ck.
If f
EMk, then f
has at most a finite number ofpoles
in anyfundamental
region.
From the work of Petersson[1]
it follows thatf (z)
can berepresented
as the sum of Poincaré seriesHere
where
and the summation is over all
pairs
ofcoprime integers
c,d ;
for eachsuch
pair
we choose asingle
T Er(i)
with[c, d]
as bottom row. HereR(t)
is asuitably
chosen rational function of t. The series is ab-solutely
anduniformly convergent
on everycompact
subset of H free ofpoles
off.
To illustrate this result we take two
special
cases. In the firstplace,
take
and
put
in this case. For
m > 0, Gk(z, m) ~ Ck
andCk
isspanned by
thoseGk (z, m )
for whichsee
[5],
Theorem 6.2.1. For m =0, Gk(z, 0)
is an Eisensteinseries,
being usually
denotedby Ek(z).
For m0, Gk(z, rn) E Hk
and has apole
of order m at 00.As a second
example
takewhere
Then
Gk(z ; R)
haspoles
of order n at thosepoints
of Hcongruent
tow modulo
1"(I).
By taking
R to be anappropriate
linear combination of the rational functions described in theprevious
twoparagraphs
we see that any functionf
EMk
can beexpressed
in the form(1.2).
If f
EMk,
thenfK
EMk,
wheresee
§8.6
of[5]. Moreover, fK = f
if andonly
iff
has real Fouriercoefficients. Such a form we call a real modular
form
and denoteby Mt
the subset ofMk consisting
of suchforms; similarly
forHt
andCt.
These areclearly
vector spaces over the real field R. Notethat,
iff
EMk,
then bothare in
Mt,
so that thereis,
in a sense, no loss ofgenerality
inconfining
attention to real modular forms.If
f
EMt
and iff
has a zero orpole
at apoint
zE H,
then it has another of the same order at - z.Further,
if the rational function R has realcoefficients,
thenclearly Gk(z; R)
EMt ;
we call such a func-tion R a real rational
function.
Whenrepresenting
real modular formsas Poincaré series
Gk(z; R)
we shall restrict our attention to real rational functions R. Such a function has theproperty
thatfor all tEC.
An
arbitrary
modular form may have a zero at anypoint
of H.However,
we shall show that there is a wide class of real forms that have all their zeros on transforms of the arcThis is
already
known to be true for the Eisenstein seriesEk ;
see[2].
2. General results
We denote
by F
the standard fundamentalregion
for0393(1).
This isthe subset of C
consisting
of allpoints
z e H for which eitheror
and we
regard 00
asbelonging
to F. F is bounded on its lower sideby
the arc
S,
butonly
half this arc,namely
is contained in F.
If f
EMk
and has N zeros and Ppoles
inF,
counted withappropriate multiplicities,
thensee
[5],
Theorem 4.1.4. Here zeros orpoles
at i are counted withweight 1 2,
while those at p =e"’ 13
are counted withweight 3.
Let
and
so that
Li,
A andLp
form theboundary
in H of theright-hand
half ofF.
For k 2: 4 we express k in the form
where
and
If
f
isholomorphic
at i and p,then,
sincewe see that we must have
in the six cases,
respectively. Accordingly
the totalweighted
order ofthe zeros of
f
at i and p is at leasts/12
in each case.Let
Gk(z ; R)
be defined as in(1.2)
and suppose that this function isholomorphic
on the arc A. We wish to count the number of its zeros on A. For this purpose it is convenient to considerpoints
on thelarger
arc S andput
where 0 E
[(Tr/3), (27T/3)] = I,
say. If wepair
the terms of the Poincaré seriescorresponding
to c, d andd,
c, and use(1.5),
we see thatFk(8, R)
is real for 0 E I.Further,
where
and
Ft(8; R)
consists of those terms of the seriesdefining Fk
for whichc2 + d2 2.
Note thatgk(03B8; R) arises
from the terms withc,d = ±1,0 and 0, ±1.
As 0
increases
fromn-/3
to27r/3
thepoint
describes in a clockwise direction a curve y
beginning
atwhich encircles the
origin, passing through
thepoint
and
returning
to - ro. The curve y ispear-shaped
andsymmetric
aboutthe real axis. It has a cusp at - ro, the two
tangents
theremaking angles
of± 03C0/3
with thepositive
real axis. The curve y and its interiorD03B3
areentirely
contained in the unit discMoreover there is a one-to-one
correspondence
betweenpoints
t =e21riz
inD03B3
andpoints
z of F forwhich Izi
> 1.We now assume that R has na zero or
pole
on y and that it hasNy
zeros and
Py poles
inD03B3,
counted with theappropriate multiplicities.
Then the variation in the
argument
ofeik03B8/2R(t)
as t describesS,
i.e. as03B8 goes from
03C0/3
to21r/3
isclearly
by
theArgument Principle.
Because of the
symmetry
of y about the realaxis,
the variation irr theargument
ofeik8/2R(t)
as t describesA,
i.e. as _0 goes fromu13
to7r/2, is
half this amount,namely
Now
and
Thus we may take
where no and ni are
integers
andNow suppose that
Gk(z; R)
hasNR zeros
and,PR poles in
F, counted withappropriate multiplicities and weights.
ThenWe are now
ready
to prove our main theorems. Theseapply
torational functions R with certain
properties’
Weshall
saythai R:
hasproperty Pk
if(i)
R is a real rationalfunction, (ii)
aH thepoles
of R liein
D03B3,
R has no zeros on y,(iii)
1 2:N03B3 - Py,
and(iv)
for 03B8 ~ I0 = [03C0/3, 1T12].
Note that(2.14) ensures
thatGk(z; R) does not
vanishidentically.
THEOREM 1:
Suppose
that Rî hasproperty Pk. Then. the Poincaé
series
Gk,(z; R) has
at leastNR - N’Y
zeros atpoints of
A.PROOF: Note that
Ny
is aninteger,
butNR
need not be.Further,-, by
our.
assumptions, PR
=Py.
It can,be checked in each 01 the
six cases° that
theintqsvài [pro+ k/6,
Mi +k/4] contains exacHy
integers N. Note that
n, - n0 + 1qby (2.12)
andcondition (iii).
At the corresponding points
N 03C0, gk(03B8; R) takes aiternately thevalues ± |gk(03B8; it follows by continuity from (2.10 14) that
Fk(03B8; R) vanishes at least once in each of the n1 - n0 + l’subintervals
between these points. Hence Gk(z; R) has
at least-zéros at
interior points
of A andtherefore by (2.13), at least
zeros on A.
As an immediate
corollary
we haveTHEOREM 2.
Suppose
that R hasproperty Pk
and that it does not vanish inD03B3.
Then all the zerosof Gk(z ; R) in F
lie on A.They
are allsimple
zerosexcept that,
when k ~ 2(mod 6),
there areof necessity
double zeros at p= e03C0i/3.
PROOF: For
Ny
= 0 and we see that in(2.8), 2 3
occursonly
for k = 2(mod 6).
THEOREM 3:
Suppose
that R hasproperty Pk
and that it hasexactly
one zero in
D’Y’
which is at theorigin
and issimple. Suppose
also thatR is bounded on
D -D’Y.
ThenGk(z; R)
has asimple
zero at 00. Allits other zeros in F lie on A and are
simple except that,
when k ~ 2(mod 6),
there are double zeros at p.For it is easy to see that
Gk(z; R)
has a zero at 00 wheneverR(O)
= 0.3.
Applications
Before the theorems of the
previous
section can beapplied,
it isnecessary to
put
condition(2.14)
ofproperty Pk
into a more usable form. For ourpresent
purposesfairly
crude estimatessufhce,
al-though
we shallrequire
more refinedapproximations
in§4.
For
c2 + d2 ~ 2
andz = ei8 E A,
say. Now it is
easily checked, since |cd| ~ 1,
thatand hence
Accordingly,
Define
Note that M is finite
by
condition(ii)
ofPk since,
at anypole
t ofR, |t| r0.
Accordingly
we havewhere,
in the summation we takeNow
has,
for 0 EIo, a
maximum value when 0 =ir/3
ofand
accordingly
subject
to the same conditions(3.5).
The series on theright is, apart
from the omission of the terms withc2+ d2
=1,
a well-knownEpstein
zeta-function and we therefore have
where
Here e
is the Riemann zeta-functionand,
fors > 1, Z3(s)
is the Dirichlet L-seriesak is a
decreasing
function of k. We havewhile
and for
large
kAccordingly,
condition(2.14)
will be satisfied ifWe
now make a number ofapplications
of thèse results.CASE
1:Talee
so that
MR = e03C0m3,
whileSQ that
(3.9) is satisfied because 03B1k
1.Since P03B3 = m and N03B3 = 0 it is elcar
that-property Pk
holds. We deduce that- the Poincaréméfies Gk(z, m)
haW all- its zeros in F on Aand that thdy
-arc aitsimple except- as specified
inTheorem
2. Thisincludes the case
m = 0considered in [2].
where fm and gn
are realpolynomials
withleading coefficients
1 andof
degrees m
and n,respectively,
where m 2: n.They
thereforepossess a total of m + n
non-leading
coefficients all of which are real.We assume that the zeros of
f m
and gn lie inD03B3. Property Pk
then holds.We deduce from Theorem 1
that, provided
thatthe Poincaré series
Gk(z; R)
has at leastNR - N’Y
zeros on A. Now(3.10)
is satisfied whenfm(t)
=tm, gn(t)
= t"by
Case 1. Because ofcontinuity
and thecompactness
of the setsinvolved,
there exists aneighbourhood
U of theorigin
inRm+n
suchthat,
if thenon-leading
coefficients of
f m
and gn lie inU,
thenGk(z; R)
has at leastNR - Ny
zeros on A.
In
particular,
if n =1, gn(t)
= t and m ~1,
it follows from Theorem 3that,
on someneighbourhood
V of theorigin
in Rmcontaining
thenon-leading
coefficients offm, Gk(z; R)
has theproperties
stated inthat
theorem, provided
thatfn(0) ~
0.CASE 3: We examine in
greater
detail thespecial
case whenwhere m EE N
and q
~ R ~Dr Accordingiy
Note that
Then, for t ~ 03B3,
where
Also,
forAccordingly (3.10)
is satisfied wheneverand we have
Condition
(3.11)
iseasily
seen to beequivalent
toThus,
when q lies in thisinterval,
all the zeros ofGk(z ; R)
lie onA,
for all k 2: 4.
4.
Application
to cusp forms In what follows we takeso that, by (1.3),
We assume that
For
Gk(z, rn)
vanishesidentically
for k =4, 6, 8, 10, 14, while,
fork =
12, 16, 18, 20, 22, 26,
the location of its zeros isknown,
sincewhere
Ek-12
is an Eisenstein series(Eo
=1)
andBk,m
is a constant. It isknown that the functions
Gk(z, m) (0 m ~ l)
spanCk
and thereforedo not vanish
identically.
It is necessary to assume in what follows that
By (2.12)
and(4.2),
so that the interval
[no
+k/6,
ni +k/41
contains 1 - m + 1 * 2integers
and condition
(iii)
ofproperty Pk
holds.To obtain the results we wish to prove we must examine the function
F*k(03B8; R)
ingreater
detail thanpreviously.
We consider first the terms withThese
give
contributionsWrite
and
put
for
03C0/3 ~
03B8 ~03C0/2.
ThenThe
expression
in square brackets decreases as 0 increasestaking
itsmaximum value of
((2wm - k3)
at 6 =1 303C0.
This value isnegative,
sothat
G’(03B8) ~ 0
and thereforeAlso
which is
positive
since k 2: 12m. HenceWe have
c2 + d2 ?
5 for theremaining
values of c, d summed overin
Fk(03B8; R),
and03C8T(03B8) ~ 0;
see(3.1). Hence,
as in§ 3,
an upper bound for theremaining
terms isgiven by
We have
and, by using
theapproximations
we find that
The
only
condition ofproperty Pk
that remains to be checked is(2.14),
which now takes the formFor this to hold we
require
thatwhich, by (4.6),
since12(m + 1) ~ k,
reduces toFor k 2: 24 the left-hand side is less than 0.00849 so that condition
(2.11)
is satisfied.THEOREM 4:
Suppose
that 1 = dimCk
~ 1 and that 0 m ~ 1. ThenGk(z, m)
has at leastf2k -
m zeros on A and at least one at 00. Inparticular,
all the zerosof Gk(l, m)
in F aresimple, except for
adouble zero at p =
e03C0i/3,
when k= 2(mod 6).
Oneof
thesesimple
zerosis at 00 and the others lie on A.
In view of the
preceding analysis
we needonly
remark that the theorem is trivial when m = 1 since in that case there are at leasts/12
zeros at i and p.
5.
Cusp
forms ofweight
24Theorem 4
gives
an exact estimate of the number of zeros ofGk(z, m)
on Aonly
when m = 1. For m > 1only
a lower bound isgiven.
It would be of interest to have more
precise
information about the location of zeros when m > 1. In this section we examine the first such case, which arises whenThe space
C24
has a basisconsisting
of the newformswhere the coefficients
03BBj(n)
are theeigenvalues corresponding
toHecke’s
operator Tn.
We have(see [3], (9.7))
where
and
It follows from
(5.1, 2)
thatso that
For later purposes we also
require
the valuesand
In all these and later estimates the last
digit
may be in doubt.Write
Then
where
Tm
is Hecke’soperator;
see[3].
If we writethen
We are
particularly
interested in the location of the zeros of g2, and thereforerequire
to evaluateel
and03BE2.
From
[3] (p. 205)
we know thatel
ande2
arepositive
and that(see [3], equation (7.4),
with q =20,
r =4, k
=24)
Here
and an is the coefficient of
e203C0iz
in the Fourierexpansion
ofEn(z),
andnot the
quantity
defined in(3.8).
AlsoFinally
where the
product
is carried out over allprime
numbers p.By using
the values ofÀj(2)
andÀj(3)
andDeligne’s
boundsfor p > 3 we find that
which leads to the values
and
From
(5.3, 5)
we see that g2 has asimple
zero at 00. We now showthat it does not vanish on
A,
but that itsremaining
zero in F lies onLp,
theright-hand boundary
of F, and issimple.
For this purpose weput
where
hn
EH12
andThen
h2
hasexactly
one zero, which issimple,
in F. Sinceh2
EH 2
thiszero lies either on A or on
Li
or onLpo
To check this werequire
thevalues of
E12
and à at thepoints
i and p. We haveso that
See
(6.1.14-16)
of[5];in (6.1.16)
the denominator should be 762048. It follows thatfor
384q
1723008.Since
h2
is real onLp
andh2(-) = elXI
+03BE203BB2
>0, by (5.5),
it followsthat
h2
has asimple
zero at apoint
ofLp.
It can be shown in a similar way that the same is true forh4.
On the otherhand, h3
has asimple
zero on
Li.
Observe thatLp
formspart
of the set of transforms of the unit circle underr(1),
whereasLi
does not.Finally, by using
the fact thatf
1 andf2
areorthogonal
and theasymptotic
formula for03A3n~x03BB2i(n)
we can show that for every N E N there exists an n 2: N such that gn does not vanish on A. A similar result holds with Areplaced by Li
andLpo
REFERENCES
[1] H. PETERSSON: Theorie der automorphen Formen beliebiger reeller Dimension und ihre Darstellung durch eine neue Art Poincaréscher Reihen. Math. Ann. 103 (1930) 369-436.
[2] F.K.C. RANKIN and H.P.F. SWINNERTON-DYER: On the zeros of Eisenstein series.
Bull. London Math. Soc. 2 (1970) 169-170.
[3] R.A. RANKIN: The scalar product of modular forms. Proc. London Math. Soc. (3)
2 (1952) 198-217.
[4] R.A. RANKIN: The zeros of Eisenstein series. Publications Ramanujan Inst. 1 (1969) 137-144.
[5] R.A. RANKIN: Modular forms and functions. Cambridge Univ. Press, 1977.
[6] K. WOHLFAHRT: Uber die Nullstellen einiger Eisensteinreihen, Math. Nachr. 26 (1964) 381-383.
(Oblatum 29-III-1981) University of Glasgow Glasgow G12 8QW
Scotland