C OMPOSITIO M ATHEMATICA
J. B. M ILLER
Normed spaces of generalized functions
Compositio Mathematica, tome 15 (1962-1964), p. 127-146
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by J. B. Miller
1. Introduction
We describe here some
pairs
of dual spaces determined frominitially prescribed
normed linear spacesby
means of boundedlinear
operators.
If theprescribed
spaces are function spaces, the dualpair frequently play
the roles of a space ofgeneralized
func-tions and its space of test
functions,
and the construction serves as a method ofembedding
agiven
function space in an extension space ofgeneralized
functions which can be described asstrong
limits. The construction of a
pair
of dual spaces isstraightforward.
Let X
and ?)
be Banach spaces, and A a suitableoperator
on 3iinto
ID.
We can define a new norm on 3iby writing
and if 3i so normed is
incomplete,
embed 3i in itscompletion,
which we write as
3E+ and
call aninflation
of Xby
A. At the sametime,
the range of Ain ?)
can be normedby
we call this a
deflation
ofID,
and denote itby IDÃ-l.
The spaces(where
* dénotes theadjointing operation)
constitute the dualpair
determinedby 3E, V
and A.Consider two
examples.
1°.
Take 3C = ?)
=L2(0, oo)
and define Aby
It turns out that
3EA+
is an extension ofL2{0, oo )
whose elements have some of theproperties usually
associated withgeneralized
functions. The space contains a delta
function,
and up to kderivatives can be defined
locally
for itsmembers, though
notvery
conveniently.
The dual space(X*)-i
determinedby
theadjoint operator
is made up of L 2 functions x for which
t""0153(k)(t)
e L2 andX =
A*[uk0153(k)(u)J.
Elements of this space possess atleast k deriv-atives,
with certainLipschitz properties.
These spaces are discussedin detail in
[5], [6]
and[7].
Some other extensions ofL2(0, oo)
are described in
[8].
2°. Take x =
Ll (0, oo),
let F be acompact
subset of thepositive
reals with
non-empty interior,
and consider theLaplace
transfor-mation
as a
mapping
ofLl(0, oo)
into thespace ?)
=C(F)
of continuous functions on F with theuniform
norm. Thenand
by completion
under this norm LIyields
a space in which every element has a well-definedstrong
left derivative. We return to thisexample later,
and obtain ageneralization
of itin §
7.Other
examples
of thetypes
of structurescontemplated
in thispaper will be found in
[2], [8]
and[4].
A. P. Guinand in[2]
describes some deflations of
L2(0, oo),
and also usesdeflationary
processes to obtain a
pair
of subclasses ofL2(0, 2n)
and 12 with aFourier-series
reciprocity property.
R. R.Goldberg
in[3] general-
izes some deflations described
by
Guinand and the author.CONTENTS.
In §
2 wespecify
a class ofoperators
whichgive
riseto inflations and
deflations,
and in§
3 we examine further theduality
between the two spaces;§
4 is devoted toexamples. §
5discusses the
partial ordering
of inflationsby inclusion. §
6describes inflation of
algebras.
We use
Example
2° as amotivating
and illustrativeexample
inthe course of the
discussion,
andin §
7 obtain a naturalgeneraliza-
tion
by using
the Gelfandrepresentation
of a commutative Banachalgebra.
2.
Inflating
operators in Banach spacesStarting
withspaces 3E
andID,
we first consider the conditions which A shouldsatisfy
in order thatXÀ
be a workable extension ofX. For
simplicity
we suppose Alinear;
andalthough
the norm of 3iand its
completeness
are not necessary for the definition of theinflation,
none the less we suppose both 3Eand ?)
to be Banachspaces. We can
regard ae+
as usual as the set ofequivalence
classesof sequences of elements of 3i which are
Cauchy
withrespect
tothe
A-norm II-liA,
and write(X,,)IAX,
X.-->AX,ae = limAaen
if the sequence
(x.),
x. e ae(n
->oo)
determines x in3E+.
Welay
down the
following requirements.
(a) 1 IXI JA
be defined for allx e 3E;
i.e.D(A)
= X.(b)
The norm of ae bestronger than ".11 A,
so that thelimiting
process in l£ be
preserved
inae+A;
i.e.For this it is necessary and sufficient that A be bounded.
(c)
The normtopology
of3E+
indu ce a Hausdorfftopology
onae; Ï.e.
which is the case if Ax = 0, x e ae
imply x
= 0. This condition alsoensures
that l’. liA
has theproperties
of a norm.(d)
A ae be dense inID.. (If
the closure A ae were a propersubspace
of
ID,
we could restate thetheory using
thissubspace
inplace
ofD.) (e) ae+A
be a proper extension ofae;
i.e. there exist at least onesequence
(sn)’ Sn
eae,
which isCauchy
inae+A
but not in ae.These
suggest
DEFINITION 1. The linear
operator
Afrom ae into D
is called a"proper inflator" (proper inflating operator) il
DÀ(I)
A isbounded,
with domainae;
(2)
Ax = 0, x e aeimply x
= 0;(3 )
the range01
A isdense,
butproperly contained, in 9).
Il
instead Asatis f ies (1), (2)
and(3)’
the range01
A isID,
.it is called an
"improper inflator".
we denote the set of
inflating operators by (ae, D),
of proper inflatorsby Ùp .
A proper inflator satisfies(a)
to(e).
If A is animproper inflator,
thenae+A
= ae: for A -1 existsby (2),
and is bound-ed, by
a well-known theorem ofBanach; 1 )
hence every A -Cauchy
sequence isCauchy
in ae.As consequences of
Q(l )-(3)
we notethat
A isclosed,
and its1) See [1 ], Theorem 2.12.1. Other theorems in Chapters 1 and 2 of [1] are used
below.
range is of the first
category in ID (by
the closedgraph theorem);
A-1 is defined and closed but
unbounded;
A*(the adjoint
ofA)
exists as a bounded linear
operator mapping ID*
into 3i*(the conjugate
Banachspaces), IIA*11
=IIAII,
and(A* )-1
=(A-’)*,
the
operators being
unbounded. We summarize the construction ofYÀ
inTHEOREM 1.
If
A is a properinflator
inU(ae, D),
thenae+A
is aBanach space
isometrically isomorphic
toID,
and ae is a dense sub-space in
ae1.
Theoperator
A can be extended to anoperator mapping XÀ
ontoID,
with aunique
inverse which is the extensionof
the A-’determined
by QA(2).
We shall not as a rule
distinguish A,
A* or A-1 from their extensionsexplicitly.
Thefollowing
result is useful.LEMMA 1.
Il
a subset lIof 1
is dense inae,
then it is dense inae+A;
thatis,
A U is dense inD.
The
proof
isstraightforward.
A consequence of the lemma is that
U(ae, D)
is asemigroup
under
operator multiplication;
for ifA, B, e Ù,
then A Bclearly
satisfies
S2AB (1)
and(2),
and(3)
follows from the lemma.3p
islikewise a
semi-group,
and we havefor if
A B,
forexample,
isimproper, (A B -1
isbounded,
and so thenis A -1 = B (A B)-’, implying A e We note that I c- %’ e 0 e
THEOREM 2.
Il
A is animproper inflator,
then so is A*.I f
A
ej)(ae, ID)
and 3E isreflexive,
then A * e3E*).
PROOF. If A
e(ae, ID),
thenQA-(l)
and(2)
hold. If A is im- proper then(A*)-’
=(A-’)*
has domainae*,
and so A * is animproper
inflator.Suppose
A proper; we prove.QA(3).
NowA * ID*
isproperly
contained inae*,
for if not then A -1 is bounded and A isimproper.
AlsoA*?)*
is dense in ae* if X is reflexive.For then the closure
A * fi* equals [N (A ) ]0,
the annihilator of the null space of A :here 91(A)
is{0},
and hence[N(A )]°
= 3E*. ThusQA*(3) holds. 2 )
The condition that 3i be reflexive cannot be omitted. A counter-
example
will be found in[12],
Ex.(II2, 11,2)’
THEOREM 3. When A e
8(X, ?)),
thede f lation IDA -1
is a Banachspace.
PROOF. The deflation space is
clearly linear ;
theproof
of its2 ) We have used [1], Theorem 2.11.15 and [14], p. 286, Theorem 2.
completeness
followsdirectly
from its définition and the assump- tion that 3E iscomplete.
If A * is an
inflator,
the setA *ID*
can in the sameway be
madeinto a Banach space
(ae*>:*-l,
a déflation ofX*,
with the normWe note that if A e
U(ae, ID), (ae*)Ã.-l
is a Banach space even whenA * j iJ(ID*, ae*),
i.e. whenQA*(8)
does not hold.Let
[., .]..4
be thecomplex-valued
bilinear function on(3i* )x*-i X ££ defined by
With this
form,
the deflation and inflation become apair
of dualspaces in the sense of Rickart
[10],
p.62,3)
in fact normeddual,
since
We shall denote this
pair
of spacesbriefly by 3i*-, X+, omitting
the "A" when there is no
ambiguity.
3.
Conjugacy
and A-weak convergenceWe now look for conditions under which the
duality
betweenthe spaces ae*- and X+ becomes one of
conjugacy,
and to this endprove Theorem 5 below. We also consider a form of weak conver-
gence in 3i+ under which ae+ may be
complete.
The two resultssliow the way in which ae*- may
play
the role of a space of test functions for a space ae+ ofgeneralized
functions. We assume in this section that Ae(ae, D),
but make nostipulation
about A*.DEFINITION 2. The sequence
(xn),
aen e3E,
is calledA-weakly Cauchy il [X*, X.-X,,,]A ->
0 as min(n, m)
-> oo,f or
every X* e(x* )A *-1.
THEOREM 4. Let A
c- jà(3E, ?»
and letfi
bere f lexive.
Then theA-weak
completion of ae
isae1,
andae+
isA-weakly complete.
PROOF. If
x E ,
then(2.1)
shows thatdefines a bounded linear
functional ~
in(X*")*, thé conjugate
8) Cf. Lemma 2, below.
space of
(ae*)Ã*-l.
If(aen)
isA -weakly Cauchy,
it then follows from the theorem of uniform boundedness thatalso defines an element of
(ae*-)*.
Therefore every x* eae*-,
abounded linear functional in
ae*,
can be extended to a boundedlinear functional in ae+*
by defining x*(x)
when x e ae+ to belimnooae*(aen),
where(aen) "-’Aae:
the limit exists since any A -Cauchy
séquence isA -weakly Cauchy,
and it isindependent
of thesequence chosen for x. Moreover
and IIXIIA
is the norm of this functional in 3i+*.Inequality (3.2 )
is valid for all x e
3i+,
x* E3E*-,
and the definition of anA -weakly Cauchy
sequence can be extended to include sequences with elements from 3E+. We call the collection of A-weak limits of(equivalent) A -weakly Cauchy
sequences from 3i the A -weakcompletion
of X.Clearly 11
is contained in the A -weakcompletion
of X. Conver-sely,
suppose that(xn ), xn
eX,
isA-weakly Cauchy.
Thenfor all x* =
A* y*
eae*-,
i.e. the sequence(Axn,)
isweakly Cauchy
in
ID,
andsince ?)
is reflexive4)
convergesweakly
to some elementy e
ID. By
Theorem1, y
= Ax for some x eae+;
sincex*(x)
=y*(Ax),
we have
showing
that(aen)
convergesA-weakly
to an element of ae+.The same
argument
shows that ae+ isA-weakly complete.
LEMMA 2. Let A
e %’S(ae, ID)
andae e ae.
Thenil
andonly il
x = o.PROOF. If x e
X,
the result is trivial. Thesufficiency
of x = 0is also obvious.
Suppose (xn ), xn
eX,
is a sequence for x e ae+ and that(3.3) holds,
i.e.lim_z*(z)
= 0, all x* EA*ID*.
Writeae. =
A* y*;
it follows that(Axn)
isweakly Cauchy
inID.
It isalso
strongly Cauchy by definition;
since thestrong
and weaklimits
coincide,
wehave IIA0153nll
-> 0, thatis, x
= 0.C) [14] p. 156, Theorem 2.
THEOREM 5.
1 f
A e(ae, ID) and ?)
isreflexive,
thenae
and((3i* )x*-i]*
areisometrically isomorphic.
PROOF. Let
xeae;
we sawthat ~
in(3.1)
is then an element in(3i*-)*. Conversely,
any element in(3i*-)*
can be sowritten;
let ~
be anarbitrary
bounded linearfunctional
on3E*-,
so thatIcI>(x*) 1 Χ" IIX*IIA--l’
, i.e.Then
cp(A *.)
defines a bounded linéar functionaly**
on?)*,
andsince ID is reflexive,
an elementy e ID
such thatcp(4 * y*)
=y**(y* )
=y*(y),
ally* e ?)*. Since y
= Ax for some x eae+,
§(A*y* )
=y*(4x) = (A*y*)(x); thus cp
has the form(3.1)
forsome x e ae+. Moreover
The
mapping x --> cp
of X+ onto(X*")*
determinedby (3.1)
iseasily
seen to be ahomomorphism,
in fact anisomorphism by
Lemma 2, and it has been shown to be an
isometry.
This proves the theorem.When A is
improper,
so isA*,
and the theorem takes the form3i çr
X**. Thus it may bethought
of asproviding
ageneralization
of
reflexivity.
If?)’,is
notreflexive,
we can still conclude that3e+ c (I*-)*.
COROLLARY.
If A e 9(X, and X
isreflexive,
then(ID*).
and(eAzi)*
areisometrically isomorphic.
The
proof
comesby applying
the theorem to A* ei1(ID*, ae*).
4.
Examples
1°
(continued).
It can be verified that theoperators
A and A*of § 1, 1 °
areinflators,
in the sense of Definition 1. Theorems 4 and 5apply.
2°
(continued).
Let usverify
that A eÙ(Ll(o, oo), C(F)}
forthe
operator
in(1.3). Clearly Q(l)
holds.Moreever,
if x eLl(0, oo ),
its
Laplace
transform x 1(z)
is aholomorphic
function inR(z)
>O;b)
therefore if
xv(z)
vanishes onF,
it vahishes for all9t (z)
> 0, and so x = 0; thus12(2)
holds. To proveS2(3) we
use the Stone-5) [13], p. 57.
Weierstrass Theorem. Let a
product
inLl(0, co)
be definedby
the
products
inducedby regarding Ll(0, oo )
as the closedsubalgebra {x: x(u)
= 0 if u0}
of the groupalgebra Ll(-oo, co)
withconvolution
product,
and consider theimages
ofLl(0, oo )
under A.Since
x v (z)y v (z) = (x y)V(z),
these form analgebra.
Thealgebra separates points;
for ifx v (.1) = . v (z.)
for allx e L’,
thene-Z1U-e-Sau as an element of L°° defines a zero functional in
(L’)*,
and so zl = x2. It follows from the
complex
case of the above- mentioned theorem that ALl is dense inC(F); 8)
since it is certain-ly
not all ofC(F), Q(3 )
is true.Clearly 3iQ
is analgebra
with iden-tity.
The
adjoint
deflation in this case is the space of all measurable functionsf
on(0, oo)
of the formwhere /À
is aregular countably-additive
set function on the Borelsets of
F, and IlfIL.*-l
=JFld,u(s)l.
3°. Take 3i =
LI( - 00, oo ), and ?)
=Co(2013oo, oo ),
the space of continuous functions on the real line which vanish at :f: 00, with uniform norm, and take for A the Fourier transformationQ(l)
and(2) hold,
and(3) also,
for it isknown 7)
that the Fourier transforms of functions ofLI( -
oo,oo)
are dense and of the firstcategory
inCo( - oo, oo ).
Thus A determines a proper inflation of Ll. If Ll is made into a commutativealgebra by
means of theconvolution
product,
so thatA (x . y)
=AxAy,
thenT+
is alsoan
algebra;
but it does not contain anidentity (delta function),
nor is it
possible
to define derivativesconveniently
init,
even ofall L’
functions;
thus it lacks the more usefulproperties
of theusual
generalized-function
spaces.4°. Consider the A of 3° instead as a
mapping into
=C(F).
In this case
D(I)
and(3) hold,
but not(2).
Let1) [10], (3.2.13). ALI is self-adjoint on F since F is contained in the positive real
axis.
7) See Segal, [11].
IF is a closed ideal in Ll.
Let À
be theoperator
inducedby
A which maps
LIlI F
intoC(F),
i.e.Then À
is a proper inflator on 3C =LI/IF"
and thealgebra Il
is well defined. It has an
identity,
theelement â
for whichô A (t)
= 1.(t
eF).
Let Th be the translationoperator
so that
zh is constant on cosets
of IF,
and soTh( = (Th) -)
isdefined,
map-ping X
intoI;
andsince ))ïj
=IlilIÃ, TA is extendible to Il.
Consider the
operator
on L1given by (1.h
=h-l(Th_l),
forwhich, (exAae)"(t) = h-l(e-iht-l)ae"(t).
Now ifItl C
and h is smalland so
by appropriate
choice of C we findthat,
for x eLI,
It follows that
(ae(t+h)-ae(t»)/h
as h -> 0 isCauchy
in A-norm.In
fact,
it is easy to see that(0153hx)
isCauchy
inÂ-norm
for any x eae,
and hence that derivatives are definableby strong
limits inX*t,
for all elements of the space.A similar
argument (without
recourse to a factoralgebra) justifies
the assertion at the endof §
1, 2°.To
identify
theadjoint deflation,
notice that 3E*(LIlI F)*
can be identified with those elements of
(Ll)*
which are constanton
Ip,
with the same norms, while(C(F))*
is the spacerca(F)
ofall
regular countably-additive
set functions on the Borel sets of F. It can then be shown thatJ*
maps y erca(F)
intof(t)
=!Feit’dfl(s); thus (ae*).-l consists of such/, with 1I/IIA*-l
=J pld,u(s)l.
5. Partial
ordering
of inflationsWe examine conditions for different
inflating operators
todetermine the same inflation or same
déflation,
and moregeneral-
ly,
for inflations and deflations to be orderedby
inclusion. In- clusion andequality
for two deflations of the same space mayobviously
be taken to mean set inclusion andequality;
and thenwe have
THEOREM 6.
I f
A e3(X, ))
and B e9(S8, ?)),
a necessary andsufficient
conditionfor IDÃ-l ID:B-l is
that B-1 A have domain ae. In this case B-1 A is bounded.The
proof
isstraightforward.
B-1 A is a closedoperator,
andtherefore bounded when its domain is ae.
In
defining
inclusion for two inflations of the same spaceX,
we wish to preserve the
individuality
of the elements of the included space, and this is achieved if weregard
an inflationof X as a set of
equivalence
classes of sequences fromX,
and so as asubclass of the class
@(ï)
of all sets of sequences fromX,
andunderstand inclusion and
equality
to mean set inclusion andequality
in 6.Accordingly
we makeDEFINITION 3.
Il A e (ae, ID)
and Be (ae, g) then I ae
shall mean that
(a)
everyA-Cauchy
sequencefrom ae is
alsoB-Cauchy, (b)
any twoA -Cauchy
sequences which areB-equivalent
are alsoA -equivalent.
We note that
(a ) implies
that two sequences which areCauchy
and
equivalent
in A-norm are so in B-normalso,
and that a se-quence which converges to 0153 e ae in A-norm does so in B-norm also. Thus
(a )
ensures that anequivalence
class inae
ispreserved
intact in
ae; (b)
ensures thatIl.IIB imposes
a Hausdorfftopology
on
ae1 ,
asrequired.
It is clearthat C partially
orders the deflations and inflations of agiven
space.A necessary and sufficient condition for
(a)
to hold is that BA -1 be bounded inID.
For BA -1 maps Aae ontoBX;
if it is bound-ed, then ) )BA-ly)[ cllYl1
for ally e AI,
andso IIB0153ll cllA0153l1
for all x e
X,
and(a)
follows.Suppose conversely
that(a) holds,
and let yn -+ y for Yn’ y e Aae.
Writing Yn
=Axn , y
=Ax,
wehave 0153n -+ .A0153, and therefore 0153n -+B 0153;
i.e., BA -IYn -+ BA -ly.
Thus BA -1 is continuous on its
demain,
and so bounded. In thiscase the least bounded closure BA -1 exists.
THEOREM 7.
Il
Ae(ae, ID)
and Be (ae, ,8), a
necessary andsu f f icient
conditionf or XCX
is thatBA-l e ae(ID, ,8).
Forae1 . ae, it is
necessary andsulficient
that BA -1 beimproper, i.e.,
that BA -1 and A B-1 are bou’l1.d,ed.PROOF.
Suppose
that C = BA-1 is aninflator ; then C is bound-
ed,
and(a )
holds. To prove(b ),
let(x’), (xi )
be twoA -Cauchy
sequences from 3i which are
B-equivalent,
and write xnXl _X2
yn =
Aaen.
ThenBx.,,
0; also yn --> y for some y eID,
and soCy,, -> Cy. Since IICYnl1 = IIBaenl1
-- 0, we haveBA -1 y = Cy
= 0, and therefore y = 0by !Jc(2).
ThusAx,.
0, and(xl), (xi)
are
A -equivalent.
Hence(b ) holds,
andX CX.
To prove
necessity,
suppose(a)
and(b)
hold.By (a),
BA-1 isbounded with
domain ?),
andQc(l)
is satisfied.Clearly Qc(3)
or(3 )’ holds,
and it remains to proveQc(2). Let y e ?)
be such thatBA -1 y
= 0,y ~
0.By S2A (3 )
we can find a sequence of elements yn =A xn ,
xn eae,
suchthat yn
-- y ; the(aen)
so determined is thenan
A -Cauchy
sequencedefining
someae e ae,
and ae =F 0 sincey e
0. On the otherhand,
that
is, IIBxnll
- 0, so that(xn )
and(0)
areA -Cauchy
sequences which areB-equivalent
but notA -equivalent,
which contradicts(b).
The firstpart
of the theorem isproved.
The second follows withoutdifficulty.
COROLLARY 1.
Il
A and Bbelong to (x, ID)
and ae isreflexive, ae ae implies (x* >:;*-1 (X*)j-i.
PROOF. The first inclusion
implies
that BA-le (ID, ID),
andhence that A *-1 B* =
(BA -1)*
=(BA -1)*
hasdomain ID*;
theresult follows from Theorems 2 and 6.
COROLLARY 2.
Il A
and Bbelong to (x, I), then ae aeB’
. with
equality i f
andonly il
A isimproper.
PROOF. We know that A B e
8(X, X).
Since A = AB . B-1 is aninflator, x C ££ .
If the spaces areequal,
A-l =B(AB)-1
isbounded and A is
improper; conversely
if A isimproper, B (A B )-1
and AB . B-1 are both bounded and so
X
=.X1B.
COROLLARY 3.
Unless j)(x, ae)
isempty, ae
has nogreatest inflation.
PROOF. If A e
Ù(3i, ae), Âri
Caeft+l
for n = 1, 2, ....The next result concerns
repeated
inflation.THEOREM 8.
I f A
and Bbelong to Ù(£, £ )
and3i£ C £x ,
then Bhas a
closure 11 in (ae1, ae),
andPROOF.
Since Bx = IIABA-l. Axll, B
exists if andonly
ifA BA-1 is
bounded;
but this is a consequence of BA -1 e(ae, ae).
Now suppose C is a bounded linear
operator mapping ae
intoitself;
it is easy toverify
that C e(ae, ae)
if andonly
ifACA-1 e
9(X, I).
Forexample, Qc(2; X)
takes the formwhich
by
the substitutionxn
=A x.
becomesand this is
equivalent
to: x EX,
A CA w x = 0imply i
= 0. Thusit follows from
ABA-l=ABA-l=A.BA-le(ae,ae)
thatB e Ù(3i£ , ae).
And3E’
=(ae).
For the elements of these spacesare the classes of
.B-equivalent
sequences of elements from3i, 3i£ respectively,
and any class of(3E+)-t
canby
thediagonal
process be seen to contain a sequence from X. But two such se-
quences determine the same or distinct elements in
(3i£))
accord-ing
asthey
determine the same or distinct elements in3E+
Thus the spaces are
isomorphic,
and since one contains theother, they
areequal.
The theorem and
corollary point
the distinction betweenXA+2 and (1+)+ = 3e+
A A A ..If the
operator
of(1.1)
is denotedby Ak ,
it can be verifiedby using
Mellin transformtheory
thatin the sense of Definition 3.
Consider the
dependence
inExample
2° ofX+
upon the set F:write AF for the
operator
in(1.3),
and letF,
G be twocompact
sets of the
type
describedin §
1,2°,
with F C G.Clearly IlxllÂI’
1 Ixl ÂG
for x e3i ;
but this is not sufficient toimply
that3E’, C 3e+
In
fact, AFAG’
satisfiesQ(l)
and(3)’,
but not(2).
The setis a closed ideal in
£+
and(On
the otherhand,
theadjoint
deflation for F is contained in that forG).
At the same time there exist sequences which areCauchy
in A F-norm but not inAG-norm. Shrinking
the set Fhas the effect of
making
the inflation lessdiscriminating.
6. Inflation of Banach
algebras
We suppose now that 3E
and ?)
are both commutative Banachalgebras
over thecomplex field,
and that A is also anisomorphism
of 3E onto a dense subset in
ID,
i.e. that it satisfiesS2A(1)
to(3)
as a
mapping
of linear spaces, andalso
Then the
norms 11 - 1 J.A and 11 - 1 IA -1
arealgebra
norms, andX+A IDÃ-l
are likewise Banach
algebras.
Let
0(3E), 0(?»
denote the carrierspaces 8)
ofae, ID,.i.e.
thesubsets of
ae*, ?)* respectively
whose elements are the homo-morphisms
from the spaces onto. thecomplex-number field;
for cp
e4>(ae)
and x e X letx(cP)
denote theimage
of x underc/J.
The
isomorphism
A induces amapping Â
of0(?»
intoO(Y), by
the relation
Â
is a continuousmapping
under the X- and?)-topologies (the
weakest
topologies
onP(X)
and0(?»
for which the functionsx, y
arecontinuous).
Because ofQA(3), Â
maps the zero homo-morphism
onto the zerohomomorphism,
and is one-to-one:for if
Âcp
=Ây for §, y
eO(D),
thenby (6.1), y(cp)
=y(tp)
forall y
in a dense set of
3),
in fact all ye ID since
is a continuous function of y;hence cp
= tp. It is clear thatif cp
e(X) corresponds
toE* e X* under the
embedding (P X*,
thenx( cp) = E* (ae)
for allx e
ae; (6.1)
shows that theadjoint operator
A* coincideswith Â
as a
mapping
on0(?».
THEOREM
9. The carrier spaceof ae
isA (P(ID),
and consistaol those cp in 0 (3E) for
which(and
sof or
ail x eae).
Similarly Â(P(IDÃ-l) = (p(ae),
and(P(î})
consistsof
thosey in (P(IDÃ-l) for
whichPROOF.
If cp
=A1p
eA{/)(ID)
then(6.2) certainly holds,
forOn the other
hand,
if(6.2)
holds thenclearly §
has a well-defined 8) (/j(ae) is0£,
in the notation of [10], Chapter 3.extension to
3i£ ,
and(A-I .)"(cI»
determines ahomomorphism
onjJ
onto thecomplex numbers,
say.Then Ây c- ÂO(?».
The
proof
of the secondpart
is similar.Example
2°(continued).
Let us determine the carrier spaces for X =Ll(o, oo)
and itsinflation, bearing
in mind that 3e is not the usual groupalgebra
for the group ofpositive reals,
but isto be
regarded
as a closedsubalgebra
ofLl(-oo, oo),
with theform of
product (4.1).9)
The
homomorphisms ci>
ofP(X)
are in one-to-onecorrespondence
with the maximal modular ideals of ae. Let ffi and R stand for the
algebras
obtained fromLl ( -
oo,oo )
andLI(0, oo) by adjunction
ofthe
(common) identity. Every
maximal idealm( =1= Ll(0, oo))
in 91intersects R in a maximal ideal of
R ;
moreover,if Ml
is a maximalideal in R contained in some maximal ideal
91
in91,
thenMl
=
9Ri
n R. On the otherhand,
the maximal modular ideals inLl(0, oo)
areprecisely
the intersections withLl(0, oo)
of the maxi-mal ideals in R other than
Ll (0, oo )
itself. Thus to every 9X will corre-spond
a maximal modular ideal inLl(0, oo ), namely
m nL’ (0, oo).
But the 9X are in one-to-one
correspondence
with the elements x of the character group of( - oo, oo ),
and from this it can be deduced that the maximal modular ideals M induced inLl(0, oo )
as a
subalgebra
ofLl ( -
oo,oo )
are thosegiven by
relations of the formHere
ix,
Mand Z
arecorresponding elements, and X
ranges over( - 0, oo ).
The
epiX
so determined do not exhaust(ae).
We can obtain thewhole space as follows.
Every cp
in the space,being
a boundedlinear functional on
L1 (0, oo ),
determinesby
an
essentially
bounded measurable function go = g.Then,
forany x, y in
L1 (0, oo),
9 ) For the following remarks cf. [9], § 7,2, VI, and § 31, 1.
while
These
imply
and this
identity,
with themeasurability
of g,implies
thatlo)
for some
complex
number z =co-f-ix depending
uponcp,
withco > 0. We have
x(c/>.)
=aeV (z)
in the notation of(1.3),
and theelements of
0(£)
can be identified with thepoints
of the half-plane 9î(z)>
0, theregion
of convergence of theLaplace
trans-form.
If
ae1
is the inflationof Ll(0, oo) by
A =Ap,
of(1.3),
Theorem9 shows that
0(3E+)
can be identified with thecompact
set F.0 (C (F»
is also F.7. Inflations
using C(F)
We end with a discussion of the
case ID
=C(F),
and obtain ageneralization suggested by Example
2°. We consider thefollowing
situation.
Let I stand for any one of the real number sets
Il
=(0, oo), Il
=( - oo, 0 ),
orIz
=( - oo, oo).
Let 21 =2«1)
be acomplex
commutative Banach
algebra
withoutidentity,
whose elements arefunctions on I to some
général
linear space9,
so thatx(t)
e Qwhenever
ae(.)
e2[, t
e I.Let Il.11
be the norm of9Î,
and supposethat
the linearoperations
of addition and scalarmultiplication
in21 are those induced from 9.
Let 0 =
O(W)
be the carrier space of 21. We know that x -> x is ahomomorphic mapping
of 21 intoCo(OE),
the space of all continuous functions on thelocally compact space 0
which vanish at oo, with the uniform norm.Let F be a
compact
subsetof 0,
which does not contain the zerohomomorphism.
Let A p be the inducedmapping
x -> i of S?.C intoC(F),
the space of all continuous functions onF,
and writeIn what circumstances does AF e
S(9t, C (F)) ?
Sincel0153lF 1 lx 11, .Q(l) certainly
holds.Q(2),
will not hold ingeneral;
it is valid in1°) [1], Corollary to Theorem 4.1?’.3.
the case of
Example 2°,
but not forExample
4°. Conditions forQ(3)
aregiven by
the Stone-Weierstrass theorem: Ap9certainly separates
thepoints
ofF,
and does sostrongly
since F does notcontain the zero
homomorphism;
if alsoAp9
isself-adjoint
onF, (contains
thecomplex conjugate t(e)
whenever it contains/(e), for 0
eF)
it follows thatAp 91
is dense inC(F).
Assume thatS2(2)
does hold: if dF is such that= 1 for cp
e F thenx - dp = x for all x
e W, contradicting
theassumption
that 3thas no
identity;
thereforeAp2{
is a proper subset ofC ( F ).
ThusS2(2)
andself-adjointness together imply S2(3). Q(4) obviously
holds.
To
reproduce
the characteristics ofExample
2° we need someassumptions concerning
the translationoperation
We shall assume:
(i)
that W is closed under translations rh for every h eJ, J being
one of the setsIl, lI,
orI Z ,
notnecessarily
distinct from I.(ii)
that -rhis astrongly
continuousoperator
function of h at 0, in the senseand
(iii)
that theproduct
in 91 is so defined thatNotice
that,
if 9 is analgebra, (iii)
holdsonly
if theproduct
in 21is not that induced from 9
(except
in the trivial case when allelements of 2( are constant on
I);
thegiven property
is characteris- tic ofconvolution-type products.
(Example
2° can be considered as a case where 7 =Il, J
=Il.
We have to remember in
defining
e thatx(t)
= 0 for t0).
We now prove
THEOREM 10. Let
9t(/),j
and F bedefined
asabove,
and suppose thatA.F
issell-adjoint
on F and that.QAp(2)
is valid.Then A F e
(9t, C ( F ) ),
andSt
containsf or
each01
its elements xa derivative
PROOF. The
assumptions
make A p a proper inflator. Now if~
e0(21),
and x, y e9t,
It follows that
where
f
is some numerical functiondepending
upon~.
Fromzk+k = dik and the definition of z-° we deduce
Also,
if h eJ,
foreach e
e F we can find an x such thatx( c/J) =1=
0,and then
by assumption (i);
hencet(h)
is continuous on both sides at every k eJ.
It is therefore a measurablefunction,
and we conclude asbefore that
for some
complex
number s which will ingeneral dépend
uponcp.
Let S be the
image
of F under themapping - s(cp)
= s.It is clear that the
mapping
iscontinuous,
for since A F21 is densein
C(F)
an x can be found for whichx(~) =F
0for cp
e F. S istherefore a
compact
set in thecomplex plane.
Theproof proceeds
now as
in §
4, 4°. For he J, Ihl ho,
we haveso that zh is extendible to a bounded linear
operator mapping
91A+p
into itself. It should beemphasized
that ourassumptions -
do not make the elements of the inflation functions on I to
9,
so that for x e
91A+,,, x(-
+h )
must be taken to be defined asTx
rather than the converse.
Writing 0153h
=h-l(Th_l),
weget
valid for every x e
91A+p;
and allCauchy subsequences
of«(1.h0153),
h -> 0, define the derivative xd as an element of
%A+p.
This concludes the
proof.
We note that if x has a derivative
already
defined as astrong
limit inW,
then this coincides with xd. Theoperation d
islinear,
andhas the
product
lawClearly (0153d)" (cf» = x( cf» . s( cf».
We notice also that
21,+,
is analgebra
withidentity, ô
= dvsay, whose
defining property
isà(§)
= 1. Now 21 is withoutidentity;
let91,
be thealgebra
obtainedby adjoining
anidentity, e
say. Since ô and e have the same
algebraic properties,
we mayembed
Ni
in9Ï by making x+Âe correspond
toae+Âd
for everyx c- 91 and scalar Â. Then 3t C
91,
ClllQ .
The norm of&1’ given by llx+Âôll
=Ilaell+IAI,
dominates1-1p.
Since s as a function
of ~ belongs
toC(F),
there is some elementin
2I1.F
to which itcorresponds:
it isô,,
for(dd)"(cf> ) = à(§)s(§) = s( cf».
We see that differentiation can be written asmultiplication by
8a: xd =(x. ô)"
= x. ô,.Integration
inS?.iÂF
can be defined as follows.Suppose
F sochosen that
s(~))
does not vanish in F: then[s(~)]-1 belongs
toC(F)
and so determines anelement, q
say. We defineintegration
to be the
operation
ofmultiplying by
q, and write x’ = q x. Thenq may be identified with
(dd)-I.
These formal calculationssuggest
that a Mikusinski-like calculus exists in
AF;
but the space mustalways
possess divisors of zero, and thegeneralized
functionsenvisaged
here areessentially
different from Mikusinski’s.The
adjoint operator A*
maps the spacerca (F)
into91*,
and thus the
adjoint
deflation 21*- consists of those bounded linear functionals x* on 3t which can be written in the formfor some p,
e rca(F).
HereA t p
=x*,
andlIae*IIÂj;l
=Jpldfl(CP)I.
The A F-weak
completion
of 3t consists of the limits of séquences(xn),
aen e9t,
for whichfp(xn(cp)-xm(cp»)dp,(cp)-+O,
forall p e