C OMPOSITIO M ATHEMATICA
B OBAN V ELICKOVIC
CCC posets of perfect trees
Compositio Mathematica, tome 79, n
o3 (1991), p. 279-294
<http://www.numdam.org/item?id=CM_1991__79_3_279_0>
© Foundation Compositio Mathematica, 1991, tous droits réservés.
L’accès aux archives de la revue « Compositio Mathematica » (http:
//http://www.compositio.nl/) implique l’accord avec les conditions gé- nérales d’utilisation (http://www.numdam.org/conditions). Toute utilisa- tion commerciale ou impression systématique est constitutive d’une in- fraction pénale. Toute copie ou impression de ce fichier doit conte- nir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
CCC posets of perfect trees
BOBAN VELICKOVIC
© 1991
Department of Mathematics, University of California, Berkeley, CA 94720, U.S.A.
Received 16 March 1989; accepted 15 October 1990
Introduction
For a class -’4’ of
partial
orders and a cardinal x, letFA03BA(K)
be thefollowing
statement.
If 9
is a poset in K and D afamily of
K dense subsetsof 9
then there exists afilter
G in Y such that G n D =1=QS, for
every G E -9.Let
FA(3i)
beFA03BA(K),
for all x2eo.
Thus Martin’s Axiom(MA)
isjust FA(ccc)
while theProper Forcing
Axiom isFAN, (proper) (for
information onPFA see
[Ba]
or[Sh]).
In theproof
of theconsistency
of MA oneperforms
afinite
support
iteration of cccposets
and it is known that such iterations ofarbitrary length
preserve all cardinals.Thus,
one is able to show that MA is consistent with2N0 arbitrary large.
However if one wants to iterate non-cccposets
and preserveN1
countablesupport
iteration is needed and such iterations make CH true at limitstages of cofinality
03C91. Thisputs
severe restrictions on the value of the continuum in such models. Infact,
it is known that some extensions ofMAN1 imply
that2N0 = N2.
The weakest such axiom isFAN,
for the class ofpartial
orders ofsize 2N0
which can be written as acomposition
of a U-closedand a ccc
poset (see [Ve]).
Thus,
theproblem
arises to find a class MT ofposets
richer than the class of allccc
posets
for whichFA(Jf)
is consistent with the continuumbeing large.
Aweaker version of this
question
is that of theconsistency
ofFAN1(K) together
with
2N0
>N2.
This latterproblem
was addressedby
Groszek and Jech([GJ])
who isolated a dass 5i of
posets possessing
a certaintype
of fusionproperty
andproved
theconsistency
ofFAN1(K)
with2N0 > X2.
Theirapproach
was toconsider an iteration
along
asuitably
chosenúJ2-like
directed set instead of theusual linear iterations.
In this paper their result is extended for the case of the
partial
order Y of allperfect
trees([Sa]). Thus, starting
with aregular
cardinal x> N1
such that03BA03BA = K, a ccc
generic
extension of the universe is foundsatisfying
MA +
2N0
= Ktogether
with thefollowing
statementCCC(P).
For
everyfamily -9 of 2N0
dense subsetsof Y
there is a cccperfect subposet Y of
g such that D ~ is dense in
, for
all DE!0.Clearly, CCC(Y)
in the presenceof MAK implies FA03BA(g).
Thisgeneric
extensionis constructed as follows. One
performs
a standard finitesupport
iterationforcing
MA +2N0
= K.Simultaneously,
onegenerates
manypowerfully
cccsuborders of . This is done
following
a construction of Jensen([Jen]),
butinstead
of 0 forcing
is used at eachstage
toadjoin
to each of the currentperfect posets
asufficiently generic
tree. At limitsteps,
one ’seals’ the ccc of all theposets produced
so farby forcing
with the m-power of theirproduct.
Thedelicate
part
of theargument
isshowing
that at a limitstage of cofinality
Wl this’sealing’ poset
is ccc. Theargument
is in fact reminiscent of someapplications
ofQ.
It then remains toverify
that for every!0,
afamily
of2N0
dense subsets ofg,
one of the ccc
posets
constructedcaptures
thedensity
of each DE!0. Infact,
inthe above construction one can
replace
gby
any of the standardposets
foradding
areal,
indeed any of the fusionposets
from[GJ].
One consequence of
CCC()
concerns aquestion
in thetheory
ofdegrees
ofconstructibility.
While it is well-known thatSacks, Laver,
and Silverforcing
notions introduce minimal reals over the
ground
model no suchexample
of a cccposet
is known in ZFC(Jensen ([Jen])
neededQ
for hisconstruction;
Groszek([Gr])
has constructed such anexample
underCH).
Another one involves an oldproblem
of von Neumann(see [Ma, problem 261])
who asked whether there is aweakly-distributive countably generated
ccccomplete
Booleanalgebra
which isnot a measure
algebra. CCC()
resolves both of thesequestions. Namely,
itimplies
that there is aweakly
distributive cccposet
whichadjoins
a real ofminimal
degree
over v Such aposet clearly
cannot add random reals. To obtain it onesimply applies CCC()
to a suitablefamily
of2N0
dense subsets of g to extract a ccc suborder of Yhaving
therequired properties.
It is also shown thatCCC() implies
that i7 preserves allcardinals,
and that in the presence of MA it makes the ideal ofso-sets 2N0-complete.
Finally,
on thenegative side,
PFA is shown toimply
the failure ofCCC(Y).
Asimilar
argument
is used to answer aquestion
of Miller who asked ifMAN1
implies
that the idealof so-sets
is closedunder N1-unions. Namely, starting
witha model of PFA a
generic
extension is constructed which has the same subsets of Wl as theground
model and which contains a dense set D ofperfect
trees suchthat every real
belongs
to the closure of at mostcountably
many members of D.This
easily implies
that the reals can be coveredby N1 so-sets.
Inaddition,
it shows thatMAN,
does notimply FAN1().
The paper is
organized
as follows. Section 1 contains the basicproperties
ofperfect posets
and some technical lemmas. Theconsistency
of MA +2N0 =
x +
CCC(Y)
isproved
in Section 2. The above-mentionedapplications
arededuced in Section 3.
Finally,
Section 4 contains theproof
that PFA refutesCCC()
and theconsistency proof
ofMAN1
+2N0 = N2 + ‹FAN1().
Our
forcing terminology
ismostly
standard and can be found in either[Jec]
or
[Ku].
We denote theground
modelby E
If P is aposet
thenVp
is the Boolean-valued universeusing RO(P).
A subset D of P is calledpredense
iff forevery p e P there
exists q
E D suchthat p and q
arecompatible.
If P and 0 arepartial
orders and P is acomplete
suborder of Q weidentify Vp
with a sub-universe of
Va.
1. Basic
properties
ofperfect posets
In this section we
present
the basic definitions andproperties
ofperfect posets
and prove some lemmas that will be neededsubsequently.
Much of the material is well-known and isreproduced
for the convenience of the reader. For moredetails see
[Ab], [BL],
and[Mi].
Perfect
treesLet 203C9 denote the set of all finite
{0, 1}-sequences
orderedby
extension.T 9 203C9 is called a
perfect
tree if it is an initialsegment
of 203C9 and every element of T has twoincomparable
extensions in T. Let g denote theposet
of allperfect
treespartially
orderedby
inclusion.Thus,
is the well-known Sacksforcing ([Sa]).
For T ~ let[T]
denote the set of all infinite branchesthrough
T.Then
[T]
is aperfect
subset of 203C9. For s E T letT = {t ~
T:s ~ t or t csl.
IfTi
isa
perfect
tree, for i n, we shallidentify ~T0,..., Tn-1~
with theperfect
treeMeet and
join
Given two
perfect
trees T andS,
the meet T ^ S is defined as thelargest perfect
tree contained in both T and
S,
if itexists,
or else0.
Thus[ T
^S]
issimply
theperfect
kernel of[T]
n[S].
Thejoin
T v S issimply
T ~ S. Thefollowing
factsare
easily
verified:Perfect
posetsA collection Y of
perfect
trees is called aperfect
posetprovided:
(a) (2 CO)s
E9,
for all SE 203C9,
(b)
ifT,
S c-,9 then T vS ~ ,
and if inaddition,
TAS =1=QS
then T ^ S E Y.The order on Y is inclusion. Note that
(b) implies
that any two members of f!JJare
compatible
in if andonly
ifthey
arecompatible
in . If is aperfect poset
and T aperfect
tree let9[ T]
be the collection of alljoins
of finite subsetsof ~{Ts: s ~ T}.
Under certain conditionsY[ T]
will be aperfect poset.
If and 9 areperfect posets
let x 9 be the collection ofall T,S~
where T C- 9 and S ~ 2. Then Y x 9 is not aperfect poset
since it is not closed underjoins.
However,
the collection of alljoins
of finite subsets of Y x f2 forms aperfect poset.
The amoeba poset
A()
To each
perfect poset Y
we associate the amoeba posetA(). Elements
ofA(P)
are
pairs (T, n),
where T e éP and n~03C9.Say
that(T, n) K (S, m)
iffT S, n
m, and T n 2m = S n 2m. Note thatA(P)
is ccc iff any finite power of Y is.A(P)-generic
treesSuppose Y
is aperfect poset
and V is a universe of settheory containing
P. If Gan
W(Y)-generic
filter over V letT(G) = ~{T~2n:(T, N)~G}.
Then, by genericity, T(G)
is aperfect
tree and is called theA(P)-generic
treederived from G.
If Pi
is aperfect poset,
for i n, and G isxi generic
onecanonically
defines a sequence~Ti(G):
in)
ofgeneric perfect
trees.Complete
extensionsLet P and 2 be
posets
such that Y is a suborder of2,
and let V be a universe of settheory.
We say that 9 is acomplete
extension of Y over V iff for every n úJ, every D ~ V which ispredense
in Pn is alsopredense
in f2n.A(P)-weakly generic
treesSuppose Y
is aperfect poset
and V a universe of settheory.
We say that aperfect
tree T is
d(f!JJ)-weakly generic
over V if for every D E V which ispredense
in9 n
,for some n, every m co, and 1-1
sequence aE(T n 2m)n
there exists a finite subset X of D such thatT(03C3) vx.
Note that if T is
W(&)-generic
over a universe Vcontaining Y
then it is alsoweakly generic
over E Moreover aperfect
subtree of aweakly generic
tree isitself weakly generic.
This is notnecessarily
true forgeneric
trees and is the mainreason for
introducing
the notion of weakgenericity.
Let P be a
perfect poset, V
a universe of settheory,
and 57 a collection ofperfect posets. Say
that aperfect
tree T isd(f!JJ)-weakly generic
over(V, F)
if forevery
poset 2
which is a finiteproduct
of members ofF,
every D ~ V which ispredense
in Pn x2,
everyS ~ 2, m
03C9, and a 1-1sequence u c- (T n 2m)",
thereexists
R S,
and a finite subset X of D suchthat ~T(03C3), R> X.
One can
generalize
the above definitions forproduct
ofperfect posets. Thus,
suppose
9i
is aperfect poset,
for i n. Asequence ~Ti:
in~
ofperfect
trees iscalled
inA(Pi)-weakly generic
over V if for every~ni:
in)
Econ,
every D E Va
predense
subset ofinPnii,
all m 03C9, and 1-1 sequences03C3i~(Ti~2m)ni,
fori n, there exists a finite subset X of D such
that ~Ti(03C3i):
in~ X. Similarly
one defines what it means that a
sequence ~Ti:
in)
isweakly generic
over(V,F).
We now prove some lemmas that will be useful in the
proof
of the main theorem.They
may appear somewhat technical but the reader should bear in mind that we aretrying
to extendperfect posets
whilepreserving
thepredensity
of certain sets. Instead
of adjoining
ageneric
tree T to aperfect poset
one wantsto
adjoin
aperfect
subtree S of T.Unfortunately,
S need not begeneric
itself.However,
weakgenericity
suffices. An additionalcomplication
is that we in facthave a collection of
perfect posets
which we would like to extend whilepreserving predense
subsets of finiteproducts
of theseposets. Special
care needsto be taken since we are not
extending
all of theseposets
at the same time. This is the reason forintroducing
the notion of weakgenericity
over(V, F).
Note thatLemma 3 below is
analogous
to theproduct
lemma inforcing.
LEMMA 1. Let 9 be a
perfect
poset and V be a universeof set theory containing
P.
Suppose
T isd(9)-weakly generic
over E ThenP[T]
is aperfect
poset.Proof. Clearly, (a)
in the definition ofperfect posets
is satisfied. Toverify (b)
itsuffices to show that for
every R
c- Y there is m E w and A ~ T n 2m such that:R ^ T
equals {Ts:
SEAI.
To that end defineDo
to be the set of all S c- Y suchthat S R,
andD1
to be the set of all S E f!JJ such that S n R is finite.Clearly, Do u Dl
is dense in P.By
the weakgenericity
of Tpick
a finite subset X ofDo u D 1
such thatT X.
LetX
= X nDi,
for i =0, 1.
Find msufficiently large
such that ifSo E Xo
andS1 ~ X1
thenSo
nS1 ~ 2m. Finally,
let A be theset of s ~ T ~ 2n such that
Ts{S:S~X0}
DLEMMA 2.
Suppose 9
is aperfect
poset, F is a collectionof perfect
posetscontaining 9,
and f2 isa finite product of members of 5.
Assume that aperfect
treeT is
W(Y)-weakly generic
over(V,F),
where V is a universeof
settheory.
ThenP[T]
x f2 is acomplete
extensionof 9
x f2 over EProof. Suppose
that D ~ V is apredense
subset of 9n x f2m. Without loss ofgenerality m
= 1. Let~S0,..., Sn-1, Q~
be an element ofP[T]n
x 2. We mayassume that for
some l n
and some p w, there exists a 1-1 sequence03C3 ~ (T ~ 2p)l
such thatSi
=T,(i)
for il,
and thatS ~ P,
for i 1. LetR =
~Sl,..., Sn -1, Q>.
Thenapplying
the weakgenericity
of T to D and R oneobtains an element of D which is
compatible
with~S0,..., Sn-1, Q).
0Suppose Yi
is aperfect poset,
for i n. Let~Ti:
in)
beinA(Pi)-weakly generic
over( V, F),
and let 9 be as in the lemma.Then,
one shows inexactly
thesame way that
( inPi[Ti])
x 9 is acomplete
extension of( inPi)
2 over ELEMMA 3.
Suppose
T isA(P)-weakly generic
over(V, F).
Let W be a universeof
settheory containing
V ~ F~ {T},
and let .2 be anyperfect
poset in F.Assume that S is
A(2)-generic
over W Then~T, S)
isA(P)
xA(2)-weakly generic
over(V,F).
Proof.
Let W be any finiteproduct
ofposets
inF,
let D E Y bepredense
inPn x 9"’ x R.
By
adensity argument, using
the fact that all the relevant information is inW,
it suffices to show that for every(Q, h) ~ A(2)
there exist(Q*, h) ~ A(2),
R*~ R,
and a finite subset X of D such that(Q*, h) (Q, h), R* R,
and for every 1-1 sequences03C4 ~ ( T ~ 2’)" and 03C3~(Q*
n2h)m
~T(03C4), Q*(03C3), R*~ X.
To that end fix an
enumeration ~03C3i:i N>
of 1-1 sequences in(Q
n2h)’tl.
Inductively
build: a sequence~Qi:
iN) of perfect
trees, adecreasing
sequence~Ri:
iN)
of conditionsin R,
and a sequence~Xi:
iN)
of finite subsets of Das follows.
Set
Qo = Q, Ro = R,
andXo = 0. Suppose Qi, Ri, and Xi
have beenconstructed.
Considering ~Qi(03C3i), Ri~
as an element of 9"’ R andusing
theweak
genericity
ofT,
find~Q*i+1, Ri+1~ ~Qi(03C3i), Ri~
andXi+
1 E[D]
03C9 suchthat for every 1-1
sequence 03C4~(T~2h)(n)
Then set
In the end set and .
The
higher
dimensionalanalog
of this lemma isproved
inexactly
the sameway.
Thus, if ~T0,..., Tn-1>
isinA(Pi)-weakly generic
sequence of trees over(V,F)
and if~S0,...,Sm-1>
isjmA(2j)-generic
over W which containsV L) 57
then ~T0,..., Tn-1, S0,..., Sm-1>
isweakly generic
over(V, F).
LEMMA 4. Let V be a universe
of
settheory,
P and 2perfect
posets, and 57 a collectionof perfect
posets such that 2 ~ F.Suppose that ~ T, S)
isA(P)
xA(2)- weakly generic
over(V,F),
and thatSr
does notbelong to V, for
every r E S. Then T isW(Y)-weakly generic
over( V, Fu{2[S]}).
Proof.
Let W be a finiteproduct
ofposets
inF,
and let D E V be apredense
subset of 9" x
2[S]m
xf!Jl,
for some n, m OJ. Since2[S]
n V = A~ V,
it followsthat D is
actually predense
in f!JJn x 2m x W.Suppose ~Q0,...,Qm-1,R~~ 2[S]m
x -4 and 1 03C9 aregiven.
We have to findand finite X ~ D such that for every 1-1 sequence
03C4 ~ (T ~ 21)n
We may assume that for some r m, there is for each i r an si E S such that
Qi = SSi,
and thatQi ~ 2,
for i r. Then findp
1 and a 1-1 sequence(tao , ... , tr-l)
in(S
n2p)r
such that for all i r, si c ti.Using
the factthat ~T, S)
is
weakly generic
and that 9 E IF we findand finite X ~ D such that for all 1-1 sequences
03C4 ~ (T ~ 2p)n
and6 E (S n 2p)r
Set then
Q*i = Sti
for i r. Then~Q*0,...,Q*m-1,R*~
and X are asrequired.
nLike the
previous
two, this lemma can begeneralized
tohigher
dimensions.Thus,
ifYi,
for i n, and2j, for j
m, areperfect posets
and~T0,...,Tn-1,S0,...,Sm-1~
is a sequence of( inA(Pi)) ( mA(2j))- weakly generic
trees over(V,F),
and if(Sj)r ~ V
for everyr~Sj,
then~70,..., Tn-1~
isinA(Pi)-weakly generic
over(V,F ~ {2j[Sj]:j m}).
2.
Consistency
ofCCC(P)
+ MA +2"-
= KIn this section we prove the relative
consistency of CCC()
+ MAtogether
withthe continuum
arbitrary large. Starting
with a cardinal x> N
1 such that03BA03BA = 03BA,
weperform
a standard finitesupport
iteration of cccposets of length K forcing
MA +2N0
= K.Simultaneously,
in order to obtainCCC(),
wegenerate
many cccperfect posets.
LetHK
be the collection of all setshereditarily
of sizeK. For each 03B1 03BA and
f :
a ~HK
which is in theground model,
aperfect poset
f!JJ f
will be defined in the 2a-thstage
of the iteration.Special
care will have to betaken to ensure that all these
posets satisfy
the ccc and that for everyfamily -9
ofx dense open subsets of g in the extension there exists
f
E(HK)V
suchthat Y
captures
thedensity
of all sets in D.THEOREM 1. Assume ZFC. Let K be a cardinal >
N1
such that 03BA03BA = K. Then there exists a cccposet P
such thatvP satisfies CCC(Y)
+ MA +2N0
= 03BA.Proof.
As described in the introduction we shall buildinductively
a finitesupport iteration P03B1; Q03B1:
aK)
of cccposets of size
K. We shall assume thatthe whole iteration is embedded in some reasonable way in
HK,
and for everyf ~(H03BA03BA)V
define aname Pf
for aperfect poset
and a nameTf
for aperfect
tree.If
dom( f )
= a,then f!/J f
will be defined inVP2-
andTf
will be defined inVP2.1
To
begin,
letP >
be the collection ofall joins
of finite subsets of{(203C9)s:s~203C9},
and setQo
=A(P >).
InVP1,
letT
> be thegeneric
treeintroduced
by 00.
For odd ordinals a letQ03B1
be the cccposet generated by
somefixed
bookkeeping
device whichguarantees
that all cccposets
of size 03BA appear at somestage.
This will make sure that MA +2N0
= K holds at the end.Now suppose we are at an even ordinal 03B4 = 2a and
~P03BE; Q03BE: 03BE 03B4~
hasalready
been defined as wellas Pf
andTf,
for allf
E(H03B103BA)V.
CASE 1. a is a successor, say a
= 03B2
+ 1.Suppose f
E(H03B103BA)V. If f(f3)
is a canonicalP203B1-term
for aperfect
subtree ofTf03B2
defineOtherwise let
f!JJ f
=Pf03B2. By
Lemma1, f!JJ f
is aperfect poset.
LetQ2a be
thefinite
support product
of theA(f),
forf ~ (H03B103BA)V.
InVP203B1+1
1 for eachf
letTf
bethe
A(f)-generic
tree introducedby Q2a provided that f!JJ f
=Pf03B2[f(03B2)].
If.
CASE 2. et is a limit ordinal. For each
f
e(H03B103BA)V
letLet
Q0203B1
be the finitesupport product
of cvcopies
ofthe Pf,
and letQ1a
be thefinite
support product
of theA(Pf),
forf ~ (H03B103BA)V. Finally,
letQ203B1 = Q0203B1
xQ1a.
In
VP203B1+1, similarly
to Case1,
forf ~ (H03B103BA)V
defineTf
to be theA(f)-generic
treeintroduced
by Q1203B1,
unless forsome 03BE 03B1 Pf = f03BE.
In that case letTf
beTf Í ç
for such
03BE.
This
completes
the inductive construction. Let the finalposet P
be the direct limitof ~P03B1:03B1 03BA~.
LEMMA 5.
Q03B1 is
ccc inVP03B1, for
all a K.Proof.
For odd ordinals a this ispart
of the definition ofQ03B1.
We proveby
induction the statement for even ordinals 03B1 K. To
simplify
notation letVx
denote the boolean-valued universe
VlP’a.
Notice that if a is a limit ordinal andf ~ (H03B103BA)V,
thenQ203B1
includes as a factor theproduct
of 03C9copies of (!jJ f
and hencef
is a-centered inV203B1+1. Also, if 03B1 = 03B2 +1, f ~ (H03B103BA)V, and f03B2
is a-centered inV203B2+1, then f
is a-centered inV2a. Finally, if (!jJ f
iscr-ccntcred,
then so isA(f).
All of this
implies
that the least ordinal a for which the lemma fails isof cofinality
cvl. Then a =
2a,
andby
a standardargument,
we may assume for somefo,..., h-l E (Hx)V
and n cv, theposet iknfi
is not ccc inV2a.
Fix suchfo,..., h-l and n,
with kbeing
minimal. It follows that if i kthen (!jJ fi
is aproper extension
of f03BE,
forall 03BE
a.Suppose A E Y2a
is an uncountable maximal antichain iniknfi. By
agenericity argument
it follows that if ik,
and
if 03BE
03B1 is asufficiently
closed ordinal of countablecofinality then f03BE
hasa countable dense subset.
Thus, by
a Skolem-closureargument,
we can find a limit ordinal 03B4 et suchthat, setting Aa
= A niknfi03B4,
thefollowing
hold:(i) Aa belongs
to the modelV203B4,
(ii) Aa
is a maximal antichain iniknfl03B4,
(iii) fi03B4
is a proper extension offl03BE, for 03BE
03B4 and i k.We shall show that
Aa
remains a maximal antichain iniknfi. Hence,
A =Aa, contradicting
theassumption
that A is uncountable. To that end we shall provea more
general
fact.LEMMA 6.
Suppose YJ is
suchthat 03B4 ~
et, and letF~ = {:
ik}.
Thenthe following
hold :(a) ik is a complete extension of ik
overV203B4,
(b) ~Tf0~,..., Tfk-1~~ is ikA(fi~)-weakly generic
over(V203B4, F~).
Proof. By
a simultaneous induction on YJ.For ~
=03B4, (a)
isimmediate,
while(b)
follows from
property (iii)
of 03B4above,
since then~Tf003B4,...., Tfk-103B4~
isikA(fid03B4)-generic
overV203B4 and F03B4~ V203B4.
Suppose ~ = 03BE
+ 1 and the lemma is knownfor 03BE.
Let us assume that for some1
k fi(03BE)
is aperfect
subtree ofTfi03BE iff l
i k.Thus Pfi~ = Pfi03BE,
for il,
and
Pfi~
=Pfi03BE[fi(03BE)], for l
ik. So, ~fl(03BE),..., fk-1(03BE)~
islikA(Pfi03BE)-
weakly generic
over(V03B4, F03BE). Then, by
thegeneralization
of Lemma2,
it followsthat
ikPfi~
is acomplete
extension ofikPfi03BE
overV203B4.
To prove(b),
notice that
Tf003BE,....,Tfl-103BE, fl(03BE),..., fk-1(03BE)>
isikA(Pfi03BE)-weakly generic
over(V203B4, F03BE.)
Hence, by
Lemma4, Tfp03BE,..., Tfl-103BE>
isilA(Pfi03BE)-weakly generic
over(V203B4, F03BE ~ {Pfi~: li
ik}). Now,
if i 1 thenTfi~
=Tfi03BE.
On the other handTfi~,..., Tfk-1~>
is thelikA(Pfi~)-generic
sequence of trees overV203B4 adjoined by Q2~. Hence, by
the multidimensional version of Lemma3,
Tf0~,...,Tfk-1~>
isikA(Pfi~)-weakly generic
over(V203B4,F~).
Thiscompletes
theproof
for successor ordinals YJ.Suppose
now ~ is a limit ordinal.Then
for ik, Pfi~
=~03BE~Pfi03BE.
Hence(a)
is immediate. To prove
(b),
let us assume that forsome l k,
for every i k thereis 03BE
YJ such thatPfi~ = Pfi03BE
if andonly
if i 1.Pick 03BE
~sufficiently large
such that if il then Pfi~ = Pfi03BE.
It follows thatif 03BE 03B6 ~
and i 1 thenTfi03B6
=Tfi03BE. Together
with the inductiveassumption
thisimplies
thatTf0~,..., Tfl-1~>
isilA(Pfi~)-weakly generic
over(V203B4,F~). Finally,
Tfl~,..., Tfk-1~>
is thelikA(Pfi~)-generic
sequence of trees introducedby
Q2". Hence, by
thegeneralization
of Lemma 3again, Tf0~,..., Tfk-1~>
isikA(Pfi~)-weakly generic
over(V203B4,F~).
Thiscompletes
theproof
ofLemmas 5 and Lemma 6. 0
LEMMA 7.
Vp satisfies CCC(Y).
Proof.
Forf~(H03BA03BA)V
let us define:Since for each a K,
Pf03B1
is a-centered andcof(03BA) > N1,
it followsthat Pf
is cccin
Vp being
aK-increasing
union of 6-centeredposets. Suppose
thatD03B1: 03B1 03BA>~VP
is a sequence of dense open subsets of g. We shall buildf~(H03BA03BA)V
such thatD03B1 ~ Pf
is dense inPf,
for every 03B1 03BA.Although D03B1: 03B1 K)
is a member ofVp
it isimportant
to arrange that the whole construction off
takesplace entirely
in E Since the whole iteration is embedded inHf
in a reasonable way, every P-term for a real isessentially
a countableobject,
modulo elements of x, and hencebelongs
toHf. Thus,
let us fix someenumeration
03C403B1: 03B1 03BA>
of all P-terms forperfect
trees and an enumeration03C303B1:
ce03BA>
of all P-terms for ordinals K. We buildf recursively
as follows.Suppose f03B4
has been defined for some ordinal 03B4 K. Pick the leastpair
ofordinals
(ce, 03B2>
such that 03C403B1and a pare P203B4-terms,
and03C403B1~Pf03B4
and there is noT ~ D03C303B2 ~ Pf03B4
with T Ta.For
simplicity,
let us assume that every condition in1P2b+ 1 forces
thatTf03B4
03C403B1.Now,
sinceDap
is forced to be a dense open subset ofi7,
thereexists y
> 03B4 and aP203BC-term
r such that03C4~D03C303B2
and03C4 Tf03B4.
Let us extend
f03B4 to 03BC
+ 1by setting f(03BE) equal
to some canonical term for0,
for 5
03BE
,u, andsetting f(J-l)
= r. One can show that thusdefined f
works.This
completes
theproof
of Lemma 7 and Theorem 1. D3.
Applications
The idea of
thinning
out Sacksforcing
to a cccposet
is due to Jensen([Jen]),
who used it to
produce
a non-constructible03C01 2 singleton
of minimaldegree
overL. The
principle CCC(.9)
is anattempt
tocapture
the combinatorial content of Jensen’s constructioncompatible
with MA +‹ CH. We now show that it can beused to extract ccc suborders of Sacks
forcing having
some of theproperties
of.9 itself. Recall that a
poset Y
is calledweakly
distributive if andonly
if any functionf~03C903C9
whichbelongs
toVP
is dominatedby
some g E 03C903C9 from theground
model V. If V is a universe of settheory
and x is a real which does notbelong to V,
x is said to be minimal over Vprovided
for every y EV[x],
eitherYE Y or V[y]
=V[x].
PROPOSITION 1. Assume
CCC(Y).
Then there is aweakly
distributive cccposet Y
which adds a minimal real over theground
model.Proof.
Let si denote the collection of all countable antichains in g. For each sequenceA = An: n 03C9>
of elements of sV letD(A)
denote the set of all T ~ g such that either for every n w there isF ~ [An]03C9
such thatT F
or elsethere exists n such that T ^ R =
0,
forevery R ~ An. By
a fusionargument
one shows thatD(A)
is a dense subset of . Let be a cccperfect poset
such thatD(A)
~ is dense in,
for all A e .s;1’w.CLAIM 1. is
weakly
distributive.Proof
Let r be a -name for an element of 03C903C9. For each n cv, letAn
be a maximal antichain of elements of Ydeciding i(n).
Since Y is ccc eachAn
iscountable. Let A
= An: n 03C9>
and fixR ~ D(A) ~ .
SinceAn
is a maximal antichainin Y,
foreach n,
there existsFn
E[An]
03C9 such thatR V Fn.
Define thefunction g, E cv"
by letting
gR(n)
=sup{m
03C9: for someT~Fn T 03C4(n)
=m}
Then it follows that R r x gR . 0
Let us say that r is a canonical name for a real if it is a countable subset of
203C9
such that: if(S, s), (T,t)~03C4
and s and t areincompatible,
thenS ^ T
= 0;
and if n m then for every(S, s)
e r with s~ 2" there exists(T, t)
e Twith t e 2m such that
T
S and set. For a canonical name r letD(i)
be thecollection of all
perfect
trees T such that: either there existsf
E 203C9 such that if(S, s)
er and S A T ~QS,
then sc f,
or for every n there exists m n and a 1-1 function 9: T n 2" ~ 2m such that if(R, r)~03C4
with r E 2"‘ and R A T ~0,
thenr =
cp(s)
for some s E T n 2n.Again, by
a usual fusionargument,
one shows thatD(i)
is a dense subset of .Suppose
now that 9 is aperfect
cccposet
such thatD(i)
~ is dense inY,
for all canonical names T.CLAIM 2. adds a minimal real over the
ground
model.Proof. Suppose a
is a -term for a new real. For each se 203C9 letAS
be a maximal antichain containedin PT~:
T s cal,
and let T ={(T, s):
T ~As}.
Since a is forced not to
belong
to theground model,
every element ofD(03C4)
satisfies the second clause in the definition of
D(r). Now, given
T ~ G nD(T),
where G is a
generic filter,
one recovers thegeneric
real asU {~-1(t):
t~ a}.
Thus, V[a]
=V[G].
DOur next
application
answers aquestion
ofBaumgartner
who asked if it is consistent with2N0 > N2
that i7 preserves the continuum.PROPOSITION 2. Assume
CCC(Y).
Then Y preserves all cardinals.Proof.
Since i7 has the(2N0)+-cc,
theonly
cardinals it couldcollapse
are2N0. Suppose K 03BB 2N0
are cardinals andf
is an -name for a functionmapping x
onto 2. For each ce03BB,
letD03B1 = {T~:for some 03BE
xT f(03BE)
=03B1}.
Then
Da
is a dense open subset of Y. Nowby applying CCC()
we obtain a cccposet Y
such thatDa
n 9 is dense in,
for all ce 2. Then Ycollapses
2 to x.Contradiction. D
Recall that A s 203C9 is called an
so-set
iff for everyperfect
subset P of 2o thereexists a
perfect Q ~
P such that A nQ
=0. Thus,
A is anso-set
iff the set of allperfect
trees T such that[T]
n A =0
is dense in V. A standard fusionargument
shows that the collection ofso-sets
is a6-complete
ideal. We nowshow that MA +
CCC() implies
that this ideal is2N0-complete.
In the nextsection we shall show that MA does not suffice for this result.
PROPOSITION 3. Assume MA +
CCC(Y).
Then the unionof
less thancontinuum so-sets is an so-set.
Proof.
It suffices to show that for every1,
a collection ofso-sets
of sizex
2N0,
there exists aperfect
set Pdisjoint
fromU
1. For each A ~ X letD(A)
bethe collection of all T~ such that
[T]
n A =0. By CCC()
find a cccperfect poset Y
such thatD(A)
n & is dense inY,
for all A e i. Now consider the amoebaposet A().
It satisfies the ccc and for every A ~X the setE(A)
of all(T, n) ~ A()
such thatT E D(A)
is dense. For each s~203C9 letF,
be the set of all(T, n)
EA()
such thateither s ft
T or there exist distinct t1,t2 ~ T ~
2" such that s ~ t1, t2.Now, applying MA,,
to and the union of{E(A):
A~ X}
and{Fs:
s ~ 203C9},
one obtains aperfect
tree T such that[T]
n A= ~,
for all A ~X.~
4. PFA and the
négation
ofCCC()
In the
previous
sections we have seen thatCCC()
isrelatively
consistent withMA,,,
andconsequently,
so isFA,, (Y). Although FAN1()
follows from PFA weshow that
CCC()
does not. We then show thatMAN,
does notimply FAN1().
This is
accomplished by starting
with a model of PFA andgenerically adjoining
a dense subset D of
,
such that every r~203C9 is a branchthrough
at mostcountably
many members of D. Thisimplies
thatFAN1()
fails. Theforcing
doesnot add new subsets of 03C91 and hence MA +
2N0 = N2
remains to hold in theextension. For this
argument
we needonly
assume afragment
of PFA whoseconsistency
does notrequire
anylarge
cardinalassumptions.
We shall indicatehow this can be established at the end of this section.
Let us first make some definitions which will facilitate the
proofs.
Given afunction
f :
co ~ co such thatf(n)
> n, forall n~03C9,
say that aperfect
tree T isf-
thin
provided
for all n ~ 03C9:card(T f(n)) card(T r n)
+ 1. A sequencef03B1:
a03BA>
of functions in wro is called a weak scaleprovided
it isincreasing
andunbounded in