Season 1 • Episode AP06 • Using Geogebra to solve a problem
0Using Geogebra to solve a problem
Season 1
Episode AP06 Time frame 1 period
Prerequisites :
None.Objectives :
•
Usinggeogebra toonjueture and solvea problem.Materials :
•
Computer room.•
Exerise sheets.1 – Part A 20 mins
Using geogebra and working by pairs, Students have to draw a gure and to onjeture
the maximalvalue of anarea.
2 – Part B 20 mins
Studentshavetondout the funtioninvolved inthe problemandthentodrawit(using
geogebra) in order tond the maximal value of the area.
3 – Part C 20 mins
In this part, Students have to onrm their previous answers, this time using omputa-
tions.
Using Geogebra to solve a problem Episode AP06
Document ICT
In the gure below,
ABC
is a right-angled isoseles triangleinA
suh thatBC = 8
m.M N P Q
is a retangle insribed in△ ABC
. The lengthBM
is variable, we denote itx
,in m.
The aim of this session isto nd the position of the point
M
that maximizesthe area ofthe retangle
M N P Q
.B N
A
P
C
M Q
x
Part A – Using Geogebra
1. Use Geogebra to draw the gure. Don't forget to display the area of the retangle
on the gure.
2. Movethepoint
M
onthesegmentBC
andonjeturethemaximalvalueoftheareaof
M N P Q
.Part B – Using the graph of a function
1. What is the minimal value for
x
? Explain quikly your answer.2. What is the maximal value for
x
?3. What are the measures of the angles of
△ ABC
? of△ BM N
? Dedue the natureof the triangle
BM N
then the length ofM N
as afuntion ofx
.Season 1 • Episode AP06 • Using Geogebra to solve a problem
24. Let
f
bethe funtion thatmaps any adequatevalueofx
tothe orrespondingarea ofM N P Q
. Prove thatf (x) = 8x − 2x 2
5. UseGeogebratodrawthe graphof
f
andgivethemaximalvalue off
andthevalueof
x
for whih it isreahed.6. Dedue the maximalarea of
M N P Q
and thepositionof thepointM
forwhihit'sreahed.
Part C – Using computation
In this part, let's admit that the area of
M N P Q
is given by the expression8x − 2x 2
,where
x
represents the lengthBM
.1. What is the sign ofthe expression
− 2(x − 2) 2
?2. Expand the expression
−2( x − 2) 2
.3. Usingthetwopreviousquestions,dedue themaximalvalue ofthe areaof
M N P Q
.In the gure below,
ABC
is a right-angled isoseles triangleinA
suh thatBC = 8
m.M N P Q
is a retangle insribed in△ ABC
. The lengthBM
is variable, we denote itx
,in m.
The aim of this session isto nd the position of the point
M
that maximizesthe area ofthe retangle
M N P Q
.B N
A
P
C
M Q
x
Part A – Using Geogebra
1. Use Geogebra to draw the gure. Don't forget to display the area of the retangle
on the gure.
2. Movethepoint
M
onthesegmentBC
andonjeturethemaximalvalueoftheareaof
M N P Q
.The maximum area for
M N P Q
seems tobe8
m2
.Part B – Using the graph of a function
1. What is the minimal value for
x
? Explain quikly your answer.The minimalvalue for
x
is0
beausex
represents adistane.2. What is the maximal value for
x
?The maximal value for
x
is4
beauseM
an't be on the other side of themidpoints.
3. What are the measures of the angles of
△ ABC
? of△ BM N
? Dedue the natureof the triangle
BM N
then the length ofM N
as afuntion ofx
.△ ABC
isaright-angledisoselestriangleinA
so∠BAC = 90 o
and∠ABC =
∠BCA = 45 o
.In
△ BM N
,∠BM N = 90 o
beauseM N P Q
is a retangle and∠M BN =
∠CBA = 45 o
. So△ BM N
is aright-angledisoseles triangleinB
.We dedue that
M N = BC = x
.Season 1 • Episode AP06 • Using Geogebra to solve a problem
44. Let
f
bethe funtion thatmaps any adequatevalueofx
tothe orrespondingarea ofM N P Q
. Prove thatf (x) = 8x − 2x 2 f ( x ) = M N × M Q = x × (8 − 2 x ) = 8 x − 2 x 2
.5. UseGeogebratodrawthe graphof
f
andgivethemaximalvalue off
andthevalueof
x
for whih it isreahed.Aording to the graph, the maximal value of
f
seems to be8
reahed forx = 2
.6. Dedue the maximalarea of
M N P Q
and thepositionof thepointM
forwhihit'sreahed.
Thefuntion represents thearea sothe maximalvalue ofthe area seemstobe
8
m2
reahed forBM = 2
m.Part C – Using computation
In this part, let's admit that the area of
M N P Q
is given by the expression8x − 2x 2
,where
x
represents the lengthBM
.1. What is the sign ofthe expression
−2( x − 2) 2
?( x − 2) 2
is asquaredthus positive.As wemultiplyitby−2
whihis negative,we dedue that
− 2(x − 2) 2
is negative.2. Expand the expression
− 2(x − 2) 2
.− 2(x − 2) 2 = − 2(x 2 − 4x + 4) = − 2x 2 + 8x − 8
.3. Usingthetwopreviousquestions,dedue themaximalvalue ofthe areaof
M N P Q
.Aording tothe rst question
− 2(x − 2) 2
is negativeso− 2(x − 2) 2 6 0
.Aordingtotheseondquestion,weget
− 2x 2 +8x − 8 6 0
thus− 2x 2 +8x 6 8
.The lastinequationmeans that
f ( x )
an't be greater than8
.In the gure below,
ABC
is a right-angled isoseles triangleinA
suh thatBC = 8
m.M N P Q
is a retangle insribed in△ ABC
. The lengthBM
is variable, we denote itx
,in m.
The aim of this session isto nd the position of the point
M
that maximizesthe area ofthe retangle
M N P Q
.B N
A
P
C
M Q
x
Part A – Using Geogebra
1. Use Geogebra to draw the gure. Don't forget to display the area of the retangle
on the gure.
2. Movethepoint
M
onthesegmentBC
andonjeturethemaximalvalueoftheareaof
M N P Q
.Part B – Using the graph of a function
1. What is the minimal value for
x
? Explain quikly your answer.2. What is the maximal value for
x
?3. What are the measures of the angles of
△ ABC
? of△ BM N
? Dedue the natureof the triangle
BM N
then the length ofM N
as afuntion ofx
.4. Let
f
bethe funtion thatmaps any adequatevalueofx
tothe orrespondingarea ofM N P Q
. Prove thatf ( x ) = 8 x − 2 x 2
5. UseGeogebratodrawthe graphof
f
andgivethemaximalvalue off
andthevalueof
x
for whih it isreahed.6. Dedue the maximalarea of
M N P Q
and thepositionof thepointM
forwhihit'sreahed.
Part C – Using computation
In this part, let's admit that the area of
M N P Q
is given by the expression8 x − 2 x 2
,where
x
represents the lengthBM
.1. What is the sign ofthe expression
− 2(x − 2) 2
?2. Expand the expression
−2( x − 2) 2
.3. Usingthe twopreviousquestions, dedue the maximalvalue of the area of
M N P Q
and the position ofthe point