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www.elsevier.com/locate/anihpc

Some new results in competing systems with many species

Kelei Wang, Zhitao Zhang

,1

Academy of Mathematics and Systems Science, Chinese Academy of Sciences, Beijing 100190, China Received 3 August 2009; received in revised form 1 November 2009; accepted 1 November 2009

Available online 10 November 2009

Abstract

In this paper, we prove some uniqueness and convergence results for a competing system and its singular limit, and an interior measure estimate of the free boundary for the singular limit.

©2009 Elsevier Masson SAS. All rights reserved.

MSC:35B40; 35R35; 92D25; 35K57; 58E20

Keywords:Competing species; Free boundary problem; Harmonic map into singular space

1. Introduction

The Lotka–Volterra model of competing species describes the competition of a number of species in a fixed domain.

Its general form is as following:

⎧⎪

⎪⎩

∂ui

∂tui=fi(ui)ui

j=i

bijuj, inΩ×(0,+∞), ui=φi, onΩ× {0},

wherebij0 are constants and 1i, jM, andMis the number of the species andΩ is a bounded domain inRn (n1) with smooth boundary. Usually we consider homogeneous Dirichlet or Neumann boundary condition. We only study nonnegative solutions, that is,ui0 for alli.

The study of this reaction–diffusion systems has a long history and there exist a great amount of works. However, most of these works are concerned with the case of two species. As far as we know, the study in case of many competing species is not so much, in 1990s Dancer and Du studied three species competition systems and got very interesting existence results. In fact, it’s believed that generally this system has complicated dynamics (see [8,9]), even in the ordinary differential equation cases (see [15]).

In recent years, people show a lot of interests in strongly competing systems with many species, that is, the system (or its elliptic case)

* Corresponding author.

E-mail addresses:wangkelei05@mails.gucas.ac.cn (K. Wang), zzt@math.ac.cn (Z.T. Zhang).

1 Supported by National Natural Science Foundation of China (10671195, 10831005, 10971046).

0294-1449/$ – see front matter ©2009 Elsevier Masson SAS. All rights reserved.

doi:10.1016/j.anihpc.2009.11.004

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∂ui

∂tui= −κui

j=i

bijuj,

whereκ is sufficiently large (or its limit at κ= +∞). Conti, Terracini and Verzini [5,6], Caffarelli, Karakhanyan and Lin [1,2], etc., established the regularity of the singular limit (and the partial regularity of its free boundary) as κ→ +∞and the uniform regularity for allκ >0. Conti, Terracini and Verzini find that in the singular limit species are spatially segregated and they satisfy a remarkable system of differential inequalities, and these two conditions are also satisfied by the solution of a variational problem. Although it’s not fully established, it’s very possible that this singular limit has a variational structure. That is, the solution of corresponding elliptic problem is the harmonic map from the domainΩ into a metric spaceΣ with nonpositive curvature, which has been studied by many authors since the work of [11]. Here the metric spaceΣis defined as follows:

Σ:=

(u1, u2, . . . , uM)∈RM: ui0, uiuj=0 fori=j .

Under the intrinsic metric structure, it is a metric space of nonpositive curvature (for the definition, please see [11]).

The harmonic map is the critical point (in weak sense) of the following functional

i Ω

|∇ui|2,

defined in the class of functions u =(u1, u2, . . . , uM)(H1(Ω))M satisfying ui 0 and uiuj =0, a.e., see [5].

In this paper, we present some results concerning this problem. First we prove the uniqueness result of the following Dirichlet boundary value problem of elliptic systems in a smooth domainΩ inRnfor∀n1:

⎧⎨

ui=κui

j=i

bijuj, inΩ,

ui=ϕi, on∂Ω.

(1.1) Herebij>0 are constants and satisfybij =bj i,ϕi are given Lipschitz continuous functions on∂Ω, which satisfy ϕi0. In the paper we will simply takebij=1, without loss of generality.

In the paper [6], they prove the existence of the positive solution of (1.1), using Leray–Schauder degree theory.

However, the uniqueness of the solution was not known. Here, we will use the sub- and sup-solution method to show that the uniqueness is indeed right. That is

Theorem 1.1.κ0, there exists a unique positive solution(u1, . . . , uM)of (1.1).

The application of the sub- and sup-solution method in nonlinear elliptic systems was known for a long time, see for example [13]. Our main contribution here is a simple observation which leads to the uniqueness in our current situation.

This method can also be applied to the parabolic case. We consider the parabolic analogue of Eq. (1.1), that is, the following initial–boundary value problem:

⎧⎪

⎪⎪

⎪⎪

⎪⎩

∂ui

∂tui= −κui

j=i

bijuj, inΩ×(0,+∞),

ui=ϕi, on∂Ω×(0,+∞),

ui=φi, onΩ× {0}.

(1.2)

Hereϕiare given Lipschitz continuous functions on∂Ω, which satisfyϕi0; andφi are given Lipschitz continuous functions onΩ, which satisfyφi0 andφi=ϕi on∂Ω. We have the following theorem:

Theorem 1.2.κ0, the solution(u1(x, t ), . . . , uM(x, t ))of (1.2)exists globally, and it converges to the(unique) solution of the stationary equation(1.1)ast→ +∞(inC(Ω)).

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Then we give a uniform Lipschitz estimate, using Kato inequality (this inequality was also used in [10]) and our observation from the symmetric assumptionbij=bj i:

Theorem 1.3.There exists a constantCindependent ofκ, such that for any solutionui,κ of(1.2)we have sup

Ω×[0,+∞)

Lip(ui,κ)C.

The elliptic case can be treated similarly.

Theorem 1.4.There exists a constantCindependent ofκ, such that for solutionui,κ of(1.1)we have sup

Ω

|∇ui,κ|C.

Next we consider the uniqueness of the singular limit of (1.1) asκ→ +∞. We know that, asκ→ +∞, solutions of (1.1) converge to some(u1, . . . , uM)which satisfy the following conditions (see [6]):

⎧⎪

⎪⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

⎪⎪

ui0, inΩ,

ui

j=i

uj

0, inΩ,

ui=ϕi, on∂Ω,

uiuj=0, inΩ.

(1.3)

First we establish some results concerning the estimate of the (n−1)-dimensional Hausdorff measure of the free boundary. From the regularity theory in [1], we know that{ui >0}and{vi>0}are smooth hypersurface except a closed set of dimensionn−2. What we show is that they have finiten−1 dimension Hausdorff measure in the interior ofΩ.

Theorem 1.5.For any compact setΩΩ, we have Hn1

Ω{ui>0}

<+∞.

This result is valid for locally energy minimizing maps too, because it also satisfy the same conditions such as monotonicity of the frequency function (see [3]). We also establish a uniform interior estimate of the level sur- face.

Then we consider the uniqueness problem of (1.3). In the paper [7], the authors prove the uniqueness and least energy property of(u1, . . . , uM)which satisfies (1.3) in the case ofM=3 and in dimension 2. Here we will generalize their result to arbitrary dimension and arbitrary number of species.

Theorem 1.6.Given a solution(u1, . . . , uM)of (1.3), it must be the harmonic map into the spaceΣ.

By definition the harmonic map is the critical point of the energy functional

Ω

i|∇ui|2dx (under the same boundary condition, see [11] or [3]). Because this functional is convex with respect to the geodesic homotopy, then it must be the (unique) energy minimizing map. The uniqueness of energy minimizer has been proved by M. Conti, S. Terracini and G. Verzini in [5], see their Theorem 4.2. We also use the construction of the test functions in their proof in our Section 6.

Our method is to compute the derivative of the energy functional with respect to the geodesic homotopy betweenu and a comparison (an energy minimizing map v with same boundary values). This involves some procedures of integration by parts. In order to make this procedure rigorous, we first calculate in an approximate setting where we can avoid the free boundary which may contain singularity, at this stage we can also cancel (or place a good control on) the terms which involve the integration on the free boundary ofv. This control is necessary, even with our knowledge on the interior measure estimate of the free boundary ofv, because we do not have the corresponding estimate near

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the boundary (this may be true, if we can choose the boundary value good enough). At last, for those integration on the free boundary ofu, we can control them well enough and after take the limit, they all cancel.

At last, we consider the uniqueness of the initial–boundary value problems and the asymptotic of following singular limit of (1.2):

⎧⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎩

∂ui

∂tui0, inΩ×(0,+∞),

∂t

ui

j=i

uj

0, inΩ×(0,+∞),

uiuj=0, inΩ×(0,+∞),

ui=ϕi, on∂Ω×(0,+∞),

ui=φi, onΩ× {0}.

(1.4)

Various regularity results concerning this system are proved in [1]. We give a simple proof of the following result:

Theorem 1.7.There exists a unique solution of (1.4), and it converges to the unique solution of(1.3)ast→ +∞.

There is another simple result which we would like to mention. A simple blow up argument shows that ∂u∂ti,κ are uniformly bounded asκ→ +∞, so for solutionuof (1.4), ∂u∂ti are bounded. Although we don’t need this result in our paper, we hope it will be useful in other settings.

At last, we would like to add a remark on the symmetric assumptions onbij in the above equation. This assumption is essential for our proof. This can also be seen from the regularity results in [1], which, according to [6], may be wrong ifbij is not symmetric.

The organization of this paper is as follows. In Section 2, we prove Theorem 1.1. In Section 3, we prove Theo- rem 1.2. In Section 3, we prove Theorem 1.3 and Theorem 1.4. The methods in these three sections are very easy. In Section 5, we prove Theorem 1.5. In Section 6, we prove Theorem 1.6. These two sections are the main part of this paper. In Section 7, we prove Theorem 1.7. This again, is a simple treatment.

2. Uniqueness in the elliptic case

We use the following iteration scheme to prove the uniqueness of solutions for (1.1). First, we know the following harmonic extension is possible:

ui,0=0, inΩ,

ui,0=ϕi, on∂Ω, (2.1)

that is, this equation has a unique positive solutionui,0. Then the iteration can be defined as:

⎧⎨

ui,m+1=κui,m+1

j=i

uj,m, inΩ, ui,m+1=ϕi, on∂Ω,

(2.2) this is a linear equation, and it satisfies the Maximum Principle, so the existence and uniqueness of the solution is clear.

Now concerning theseui,mwe have the following result:

Proposition 2.1.InΩ

ui,0(x) > ui,2(x) >· · ·> ui,2m(x) >· · ·> ui,2m+1(x) >· · ·> ui,3(x) > ui,1(x).

Proof. We divide the proof into several claims.

Claim 1.i, m,ui,m>0inΩ.

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Because

j=iuj,0>0 inΩ, Eq. (2.2) satisfies the maximum principle. From the boundary conditionϕi0, then we haveui,1>0 inΩ. By induction, we see the claim is right for allui,m.

Claim 2.ui,1< ui,0inΩ.

From the equation, now we have ui,10, inΩ,

ui,1=ui,0, on∂Ω, (2.3)

so we haveui,1< ui,0from the comparison principle.

In the following we assume the conclusion of the proposition is valid until 2m+1, that is inΩ ui,0>· · ·> ui,2m> ui,2m+1> ui,2m1>· · ·> ui,1.

Then we have:

Claim 3.ui,2m+1ui,2m+2. By (2.2) we have

ui,2m+2κui,2m+2

j=i

uj,2m, (2.4)

ui,2m+1=κui,2m+1

j=i

uj,2m. (2.5)

Becauseui,2m+1andui,2m+2have the same boundary value, comparing (2.4) and (2.5), by the comparison principle again we obtain thatui,2m+1ui,2m+2.

Claim 4.ui,2m+2ui,2m.

This can be seen by comparing the equations they satisfy:

⎧⎪

⎪⎪

⎪⎪

⎪⎩

ui,2m+2=κui,2m+2

j=i

uj,2m+1, ui,2m=κui,2m

j=i

uj,2m1.

(2.6)

By assumption we haveuj,2m+1uj,2m1, so the claim follows from the comparison principle again.

Claim 5.ui,2m+3ui,2m+1.

This can be seen by comparing the equations they satisfy:

ui,2m+3=κui,2m+2

j=iuj,2m+2, ui,2m+1=κui,2m+1

j=iuj,2m. (2.7)

By Claim 4 we haveuj,2muj,2m+2, so the claim follows from the comparison principle again. 2

Now we know that there exist two family of functions ui and vi, such that limm→∞uj,2m(x)=uj(x) and limm→∞uj,2m+1(x)=vj(x),xΩ. Moreover, from the elliptic estimate, we know this convergence is smooth inΩand uniformly onΩ. So by taking the limit in (2.2) we obtain the following equations:

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⎧⎪

⎪⎪

⎪⎪

⎪⎩

ui=κui

j=i

vj, vi=κvi

j=i

uj.

(2.8)

Becauseui,2m+1uj,2m, by taking limit we also have

viui. (2.9)

Now summing (2.8) we have

⎧⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

i

ui

=κ

i

ui

j=i

vj

,

i

vi

=κ

i

vi

j=i

uj

.

(2.10)

It is easily seen that

i

ui

j=i

vj

=

i

vi j=i

uj

, so we must have

iui

ivi because they have the same boundary value. This means, by (2.9), uivi. In particular, they satisfy Eq. (1.1).

Proposition 2.2.If there exists another positive solutionwi of(1.1), we must haveuiwi.

Proof. We will proveui,2mwiuj,2m+1,m, then the proposition follows immediately. We divide the proof into several claims.

Claim 1.wiui,0. This is because

wi0, inΩ,

wi=ui,0, on∂Ω. (2.11)

Claim 2.wiui,1. This is because

⎧⎪

⎪⎪

⎪⎪

⎪⎩

wi=κwi

j=i

wj, ui,1=κui,1

j=i

uj,0.

(2.12)

Noting that we havewj< uj,0, so the comparison principle applies.

In the following we assume that our claim is valid until 2m+1, that is ui,2mwiui,2m+1.

Then we have

Claim 3.ui,2m+2wi.

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This can be seen by comparing the equations they satisfy:

⎧⎪

⎪⎪

⎪⎪

⎪⎩

wi=κwi

j=i

wj, ui,2m+2=κui,2m+3

j=i

uj,2m+1.

(2.13)

By assumption we haveuj,2m+1wj, so the claim follows from the comparison principle again.

Claim 4.ui,2m+3wi.

This can be seen by comparing the equations they satisfy:

⎧⎪

⎪⎪

⎪⎪

⎪⎩

wi=κwi

j=i

wj, ui,2m+3=κui,2m+3

j=i

uj,2m+2.

(2.14)

By Claim 3 we haveuj,2m+2wj, so the claim follows from the comparison principle again. 2

Remark 2.3.From our proof, we know that the uniqueness result still holds for equations of more general form:

⎧⎨

ui=ui

j=i

bij(x)uj, inΩ,

ui=ϕi, on∂Ω,

(2.15)

wherebij(x)are positive (and smooth enough) functions defined inΩ, which satisfybijbj i. 3. Asymptotics in the parabolic case

In this section we prove Theorem 1.2. We can use the method of Section 2 to prove there exists a globally unique solutionui(x, t ). Moreover we can get a result about the asymptotic behavior of this solution from this method.

Proof. Let’s consider the iteration scheme analogous to (2.2). First we consider

⎧⎪

⎪⎨

⎪⎪

∂ui,0

∂tui,0=0, inΩ×(0,+∞), ui,0=ϕi, on∂Ω×(0,+∞), ui,0=φi, onΩ× {0}.

(3.1)

We know this equation has a unique positive solutionui,0(x, t ). We also have

t→+∞lim ui,0(x, t )=ui,0(x), (3.2)

where the convergence is (for example), in the space ofC0(Ω)andui,0(x)is the solution of (2.1). In fact, we can prove that

Ω

∂ui,0

∂t

2dxC1eC2t (3.3)

for some positive constantsC1andC2.

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Now the iteration can be defined as:

⎧⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

∂ui,m+1

∂tui,m+1= −κui,m+1

j=i

uj,m, inΩ×(0,+∞),

ui,m+1=ϕi, on∂Ω×(0,+∞),

ui,m+1=φi, onΩ× {0}.

(3.4)

This is just a linear parabolic equation, and there exists a unique global solutionui,m+1(x, t ). Differentiating (3.4) in timetwe get

∂t

∂ui,m+1

∂t∂ui,m+1

∂t = −κ∂ui,m+1

∂t

j=i

uj,m,κui,m+1

j=i

∂uj,m

∂t . (3.5)

By the induction assumption and maximum principle we know fort >1 we have for some constantCm

j=i

uj,m+1Cm , (3.6)

and

Ω

∂ui,m

∂t

2dxCm,1eCm,2t (3.7)

for some positive constantsCm,1andCm,2.

Multiplying (3.5) by ∂ui,m∂t+1, with the help of (3.6), we get (note that we have the boundary condition ∂ui,m∂t+1 =0 on∂Ω)

d dt

Ω

1 2

∂ui,m+1

∂t 2+

Ω

∂ui,m+1

∂t

2κCm

Ω

j=i

∂uj,m

∂t

∂ui,m+1

∂t

. (3.8)

Using Cauchy inequality, we get d

dt

Ω

1 2

∂ui,m+1

∂t 2+

Ω

∂ui,m+1

∂t 2 κCm

Ω

j=i

∂uj,m

∂t 21

2

Ω

∂ui,m+1

∂t 21

2

. (3.9)

From (3.7) and Poincaré inequality, we get

Ω

∂ui,m+1

∂t

2dxCm+1,1eCm+1,2t, (3.10)

for some positive constantsCm+1,1andCm+1,2. By standard parabolic estimate this also implies

sup

Ω

∂ui,m+1

∂t

Cm+1eCm+1t, (3.11)

for another two constantsCm+1andCm+1. At last we get

t→+∞lim ui,m+1(x, t )=ui,m+1(x). (3.12)

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Furthermore, the convergence can be taken (for example), in the space ofC0(Ω)andui,m+1(x)is the solution of (2.2).

The same method of Section 6.1 gives, inΩ×(0,+∞)

ui,0>· · ·> ui,2m> ui,2m+2>· · ·> ui>· · ·> ui,2m+1> ui,2m1>· · ·> ui,1. Now our Theorem 1.2 can be easily seen. In fact,∀ >0, there exists anm, such that

max

Ω

ui,2m(x)ui(x)<

and max

Ω

ui,2m+1(x)ui(x)< .

We also have that there exists aT >0, depending onmonly, such that,∀t > T, max

Ω

ui,2m(x, t )ui,2m(x)< , and

max

Ω

ui,2m+1(x, t )ui,2m+1(x)< . Combing these together, we get∀t > T,

max

Ω

ui(x, t )ui(x)<4 . (3.13)

This implies,ui(x, t )converges to the solutionui(x)of (1.1) ast→ +∞, uniformly onΩ. (If the boundary values are sufficiently smooth, we know that in fact the convergence in Theorem 1.2 is smooth enough.) 2

4. A uniform Lipschitz estimate

Here we use the Kato inequality to establish the uniform Lipschitz bound of solutions for (1.1) and (1.2). We will only treat the parabolic case, the elliptic case is similar.

First differentiating Eq. (1.2) in a space directionewe obtain an equation forDeu:=e· ∇u:

∂t

Deui,κ= −κDeui,κ

j=i

uj,κκui,κ

j=i

Deuj,κ. (4.1)

Now using the Kato inequality we have

∂t

|Deui,κ|−κ|Deui,κ|

j=i

uj,κ+κui,κ

j=i

|Deuj,κ|. (4.2)

Sum these iniwe get

∂t

i

|Deui,κ|0. (4.3)

On the other hand, forΦi to be the solution of

⎧⎪

⎪⎨

⎪⎪

∂Φi

∂tΦi=0, inΩ×(0,+∞), Φi=ϕi, on∂Ω×(0,+∞), Φi=φi, onΩ× {0},

(4.4)

we have (see [6] for the elliptic case)

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⎧⎨

Φiui,κ, Φi

j=i

Φjui,κ

j=i

uj,κ. (4.5)

This implies sup

∂Ω×(0,+∞)

∂ui,κ

∂ν C,

for alli, where ν is the outward unit normal vector andC is independent ofκ. With the assumption of Lipschitz continuity of the initial–boundary values, we in fact have

sup

∂Ω×(0,+∞)

|∇ui,κ|C,

with a constantCindependent ofκagain. Next we also have att=0,ui,κ=φi, so sup

Ω×{0}|∇ui,κ| =sup

Ω |∇φi|.

Now Maximum Principle implies a global uniform bound:

sup

Ω×[0,+∞)

|∇ui,κ|C.

Then standard method means we also have a uniform Lipschitz bound with respect to the parabolic distance.

Remark 4.1.Without the boundary regularity, we can still get an interior uniform bound. Multiplying the equation by ui,κand integrating by parts, we can get anL2bound for anyT >0

i T+1

T Ω

|∇ui,κ|2C, (4.6)

withCindependent ofκ. Then we can use the mean value property for sub-caloric (or subharmonic function) to give a uniform upper bound for|∇ui,κ|.

Remark 4.2.If we consider the original Lotka–Volterra system

∂ui

∂tui=aiuiu2iκui

j=i

uj, (4.7)

with homogeneous Dirichlet boundary condition, the above results still hold. In fact, we only need to prove a boundary gradient estimate, which can be guaranteed by the following argument: if we definevi to be the solution of

∂vi

∂tvi=aivivi2, (4.8)

with the same initial value, then by maximum principle we have for eachκ ui,κvi,

which, together with the boundary condition, implies ∂ui,κ

∂ν

∂vi

∂ν ,

whereνis the unit outward normal vector to∂Ω; using the boundary condition once again we get on the boundary

|∇ui,κ||∇vi|,

where the right-hand side is independent ofκ.

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5. Interior measure estimate

In this section we prove Theorem 1.5.

In order to prove this theorem, we need some lemmas (following the same ideas in Section 5.2 of [12]). The first is a compactness result, so given anN1, let’s define

H1N:=

u: B1(0)Σ, satisfies (1.3) except the boundary condition,

B1(0)

i|∇u2i|

∂B1(0)

iu2i N,

∂B1

2

(0)

i

u2i =1

.

Then we have

Lemma 5.1.H1Nis compact inL2(B1(0)).

Proof. First from the monotonicity of the frequency we have a well-known doubling property, which implies

∂B1(0)

i

u2i C(N ), (5.1)

whereC(N )depends only on N. By the definition and Poincaré inequality (noting here we have a boundary con- straint), we have

B1(0)

i

u2i+

i

u2i C(N ), (5.2)

for another constant C(N ). So for any sequenceumH1N, there exists a subsequence converging to u, weakly in H1(B1)and strongly inL2(B1).

We claim that the limitumust be inH1N, too. First, we know those properties in (1.3) are preserved under weak convergence inH1(B1)and strong convergence inL2(B1). Next, we claim for anyr <1,umconverges toustrongly inH1(Br). This is because, if we take a smooth cut-off functionζ, from the continuity ofumand the fact thatui,m

is a Radon measure supported on{um>0}, we have 0= ui,m·ui,mζ2

= − |∇ui,m|2ζ2+2ζ ui,mui,mζ.

So from the weak convergence ofui,minH1(B1)and the fact thatui,mconverges toui uniformly, we get

m→+∞lim |∇ui,m|2ζ2= |∇ui|2ζ2. From Trace Theorem, we also have

∂B1 2

(0)

i

u2i = lim

m→+∞

∂B1 2

(0)

i

u2i,m=1.

Thus for anyr <1

Br(0)

i|∇u2i|

∂Br(0)

iu2i = lim

m→+∞

Br(0)

i|∇u2i,m|

∂Br(0)

iu2i,m N.

By the monotonicity and continuity of the frequency this implies

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B1(0)

i|∇u2i|

∂B1(0)

iu2i N. 2

The next step is to divide the free boundary into two parts: the good parts are those which are uniformly smooth (the gradient has a uniform lower bound there), while for the bad parts we have a control on its size. In the following we shall denote the free boundary ofuasF(u).

Lemma 5.2.For anyuH1N, there exist finite ballsBrk(xk)withrk12such that

xB1

2,

i

u2iγ (N )

F(u)

k

Brk(xk), (5.3)

and

k

rkn11

2, (5.4)

whereγ (N )is a constant depending only on the dimensionnandN.

Proof. For anyu0H1N, the singular set of the free boundarysing(F(u0))has vanishing (n−1)-dimensional Haus- dorff measure:

Hn1 sing

F(u0)

=0.

So there exist finite ballsBrk(xk)withrk12such that sing

F(u0)

k

Brk

2(xk), (5.5)

and

k

rkn1 1

2n. (5.6)

Of course, there exists a constantγ (u0) >0, such that, on the setB1

2F(u0)\(

kBrk 2(xk)),

i

|∇ui,0|23γ (u0). (5.7)

Now we claim there exists an (u0) >0 such that for anyuH1N withuu0L2(B1) (u0), onB1

2F(u)\ (

kBrk(xk)),

i

|∇ui|2γ (u0).

With the compactness ofH1NinL2(B1), our conclusion is easily seen.

Assume this claim is not true, then there exists a sequence of umH1N withumu0L2(B1)m1, but∃xmB1

2F(um)\(

kBrk(xk)),

i

|∇ui,m|2(xm)γ (u0). (5.8)

Then from the uniform Lipschitz estimate, we have um converge tou uniformly on any compact subset ofB1(0).

This implies for any δ >0, for m large enough depending only on δ,F(um)is in the δ neighborhood of F(u).

However, nearB1

2F(u0)\(

kBrk(xk)), locally, there exist exact two components ofu0which are non-vanishing here, without loss of generality, assuming to beu1,0andu2,0, which satisfies

(u1,0u2,0)=0.

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Using the same method of the Clean Up Lemma in [1], we can show that locally, formlarge, we also have, onlyu1,m andu2,mare non-vanishing. (This can also be proven by the upper semicontinuity of the frequency function under the convergence ofumuandxmx.) Then we also have locally

(u1,mu2,m)=0.

In view of their convergence inL2loc, we have here locally u1,mu2,mu1,0u2,0 smoothly.

Now coming back to (5.8), without loss of generality, assumingxmx0, which lies inB1

2F(u0)\(

kBrk(xk)), we can take the limit in (5.8) to get

i

|∇ui,0|2(x0)γ (u0), (5.9)

which contradicts (5.7). 2

First we need to control the measure of the good part. This needs a comparison with some standard models, for example, in [12], they use the comparison with harmonic functions. But here we have no such smooth model to compare, instead, we will compare it with the homogeneous elements inH1N, which has the property

u(rx)=rdu(x), for somed >0.

It can be represented byu(rθ )=rdϕ(θ ), forϕdefined onSn1, satisfying

⎧⎪

⎪⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

⎪⎪

(θ+λ)ϕi0, (θ+λ)

ϕi

j=i

ϕj

0,

ϕi0, ϕiϕj=0,

(5.10)

whereλsatisfiesd(d+n−2)=λandλN, andθ is the Laplacian onSn1. By induction on the dimension, we can assume

Hn2

F(ϕ)∩Sn1

C(N, n). (5.11)

Note here in dimensionn=2, eachϕcan be computed explicitly.

Lemma 5.3.With the assumptions of the preceding lemma, if moreover

B1(0)

i|∇u2i|

∂B1(0)

iu2iN (u,0)σ, (5.12)

whereσ is a constant depending only on the dimensionnandN, and N (u,0)=lim

r0

r

Br(0)

i|∇u2i|

∂Br(0)

iu2i . (5.13)

Then Hn1

F(u)B1 2 \

k

Brk(xk)

C(N ),

whereC(N )is a constant depending only on the dimensionnandN.

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Proof. Take aδ >0 small enough. If we chooseσsmall enough too, then by compactness there exists a homogeneous wH1N such that

uwL2(B1)δ,

andF(u)is in theδneighborhood ofF(w). Define S1:=

xB1

2,

i

u2iγ (N )

F(u),

S2:=

xB1

2,

i

wi2γ (N )

F(w).

Ifσ is small,S1is in theδneighborhood ofS2, too. Take anεδ, and take a maximalεseparated sets{yk}ofS2. Then we havedist(yk, yl)ε2 andS2

kBε(yk).

In eachBε(yk),w has exactly two components which are non-vanishing. Moreover, the free boundaryF(w)Bε(yk)can be represented by the graph of aC1function defined on the tangent plane toF(w)atyk. Now ifδis small enough, this property is also valid foru. The same method of Lemma 5.25 in [12] gives our conclusion. 2

Now the proof of Theorem 1.5 can be easily done by an iteration procedure exactly as in [12]. Here, we just need to note that in Lemma 5.2, those radiusri can be chosen arbitrarily small so that the assumptions in Lemma 5.3 are satisfied.

At last, we give a theorem on the uniform estimate of the measure of the level surface{ui=δ}. Theorem 5.4.ForuHN1,δ >0and1iM, we have

Hn1 B1

2 ∩ {ui=δ}

C(N ).

This is also valid if we consider the local energy minimizing map.

Proof. First, because eachui is subharmonic, from theL2(B1)bound we have sup

B1 2

uiC(N ). (5.14)

We claim that,∀δ >0,∃C(δ, N ), such that,t > δ Hn1

B1

2 ∩ {ui=t}

C(δ, N ). (5.15)

If this is not true, then∃tkδandukHN1 such that Hn1

B1

2 ∩ {ui,k=tk}

k. (5.16)

By (5.14), we can assumetktδ. By the compactness ofHN1, we can assumeukuinL2(B1). By the uniform Hölder continuity [1], we can also assumeui,kui inC(B2

3).

Ifui≡0, then forklarge sup

B2

3

ui,k< t 2.

This is impossible, soui is not 0. In fact,{ui=t} ∩B1

2 = ∅. Because in{ui>0},ui is harmonic, we have Hn1

B1

2 ∩ {ui=t}

<+∞. (5.17)

We also have forklarge,B1

2 ∩ {ui,k=tk}lies in a small neighborhood ofB1

2 ∩ {ui=t}. In this neighborhood,ui,k converge touismoothly, so forklarge,∃C >0 such that

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