R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
H ERMANN H EINEKEN
Nilpotent groups of class two that can appear as central quotient groups
Rendiconti del Seminario Matematico della Università di Padova, tome 84 (1990), p. 241-248
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Nilpotent Groups
that Can Appear
asCentral Quotient Groups.
HERMANN
HEINEKEN (*)
In this note we will be concerned with the
following question:
Suppose Z(G).
What can be said aboutGIZ(G)
if G isisomorphic
to some centralquotient
groupH/Z(g)
of a group H?The answer to the
corresponding question
forIG’I
= p is wellknown for along time;
it isIG/Z(G)I
=p2 (see
for instanceBeyl
andTappe
[1; p. 233]).
The
proof
of the answer(Proposition 3)
makes use of our knowl-edge
about vector spaces with twoalternating
bilinear forms. The bounds obtained are strict for oddprimes
p ; this is shown in the second section. In the third section wegive
anexample
of agroup G
such that
and G is a central
quotient.
This shows at leastquadratic growth
for the upper bound of the rank of
G/Z(G)
withgrowing
rank of G’.1. The bounds for
In what follows we will have to deal with vector spaces V with two
alternating
bilinear formsfi, 12
which are of acomparatively transparent
structure: There are two linear combinations(*) Indirizzo dell’A.: Universität
Wurzburg,
FederalRepublic
ofGermany.
242
and a basis xl, ... , Xm of V such that
For
brevity
we will call such a vector space astring
withrespect
to g1 and g2 . If dim Y is
odd,
V is also astring
withrespect
to any two different linear combinations off l, f 2;
on the other hand if dim V is even, g1 is fixed and g, can bechanged
to any other linear combina- tion different from g1. The reference to therespective
bilinear forms willmostly
be unnecessary and is then omitted.A direct sum is called an
orthogonal
sum, if in addition the sum- mands areorthogonal
to each other withrespect
to all bilinear forms considered.PROPOSITION 1. If two
alternating
formsf 1, f 2
are defined on afinite dimensional vector
space V,
then V is theorthogonal
sumwhere every linear combination 0 is
nondegenerate
on 1~and ... ,
Xt
arestrings. Any
two suchdecompositions
of Tr areof the same form.
PROOF.
Following
Scharlau[2],
we can compare the finite dimen- sional vectorspace V possessing
twoalternating
forms with a Kro- necker moduleconsisting
of two spaces and twoendomorphisms mapping
the first space into the second: for the first space take asubspace
which is maximal withrespect
to both formsreducing
tothe zero form on
it,
for the second take the dual of therespective quotient
space. Scharlau proves[2; 3.e,
Theorem p.14]
that the de-composition
of such a vector space into an unrefineableorthogonal
sum is
unique
up toisomorphism.
For .R we take the sum of suchsummands with all linear combinations
rfi + r f 2 non-degenerate;
theremaining
summandscorrespond
to Kronecker modulesLn, L§J
as described in
[2; p. 16],
and these arestrings
in our sense.PROPOSITION 2. Denote
by V’
a finite-dimensional vector space with twoalternating
formsfi
and12
such that every lineare combina- tion-f- r/2
isnon-degenerate
on V. Then(i)
dim V is even, and at least 4.(ii)
If W is asubspace
of Y~ of codimension1,
then W =T ~ ~S,
where every linear combination
r f 1-f--
isnon-degenerate
on T while~S is a
string
of odd dimension.PROOF. Since
f 1
isnondegenerate
onV,
dim Tr is even, for dim Y’ = 2f 1
andf 2
arelinearly dependent.
On the otherhand,
dim yY = dim Tr - 1 is
odd,
and every linear combinationrfi +
isdegenerate
onyY,
so W is anorthogonal
sum with at least onestring,
and onestring
of odd dimension. Since every linear combina- tionsl2
isnondegenerate
onV, W )
= 0 has as space of solution asubspace
of dimension dim V - dim W = 1 at most. This shows that there is at most onestring,
it contains all the solutions mentioned.In the
sequel
we make use of thefollowing
well known fact: If G is a p-group ofnilpotency
class 2 and G- x~b~
with pP = bp =1,
then the
mapping
induces two
alternating
bilinear forms on This allows us to argue from vector spaces to groups and back. Thisargument
can be foundoperating
in Vishnevetskii[3],
for instance.PROPOSITION 3. If G is a finite group such that
and there is a group .g such that G =
H/Z(H),
thenPROOF. The first
part
of theinequality p2 GIZ(G)
is obvious.For the other we
begin
with somepreliminary
statements. We assumethat G is
isomorphic
to somequotient H/Z(H)
and deduce restrictionson G.
244
If,
on thecontrary,
G = UTr with[ U, V] = 1
and and G =.H/Z(H),
we choose a basis u1, ... , 9 VI ... , vs of G such that theelements ui belong
to U and the to V. Since U n V cZ(G)
we have ..., =
UZ(G)
andv1, ... ,
=VZ(G).
The
pre-image
of the element x of G withrespect
to themapping
of H onto G = shall be denoted
by
~.Now
The same holds if the roles of U and TT are
interchanged.
TakeThen c i Z(H)
and[c, vk]
=[c,
= 1 for allk,
a contradiction. So(a)
is true.By (a)
we haveU’ m V’= 1,
and thehypothesis yields U’o 10 V’.
So both commutator
subgroups U’,
V’ haveorder p
andUZ(G)/Z(G)
and
YZ(G)/Z(G)
areelementary
abelian of even rank.Using (a) again
we see that both these
quotient
groups must be of orderp2
and(b)
follows.
From now on we consider
G/Z(G)
as aFp-vector
space V with twoalternating forms,
as outlinedjust
before thisProposition. By
(b )
we have(c)
Ifdim V > 4,
there is no properdecomposition
of V’ into anorthogonal
sum .We assume dim Tr = m > 5. If there is a linear combination
((r, s) # (0, 0))
which isdegenerate on V,
then V is astring
withrespect
to and one of11, 12,
sayf.
So there are gener- atorsx~Z(G), ... , xmZ(G)
ofGIZ(G)
and a, b of G’ suchUsing pre-images
as before we haveand, using
the sameargument,
and neither £ nor
6
are outsideZ(H),
a contradiction. This shows(d)
If V is astring, dim Y c 5 .
Assume now that V is not a
string
but all bilinear forms are non-degenerate
on Tr and Consider asubspace
yY of codimen- sion 1 ofY; by Proposition
2 we know that W is theorthogonal
sumof a
completely nondegenerate part
and astring.
Ifdim V > 8
either theorthogonal
sum is nontrivial andii, b
commute with all elementsof the
prc-image
ofW,
or yY is astring
of dimension 7 atleast,
withthe same consequence. Since this holds for all
W,
this also holds forV,
a contradiction. We have found(e ) dim V> 7 .
If dim Y =
6,
each ZY must be astring by Proposition
2(i).
Wechoose a basis ... ,
X6Z(G)
ofG/Z(G)
and determine the maxi- malsubgroups
of G such that[ tli, xi]
=b~.
We have
corresponding subspaces Wi
of codimension 1 of V. Thesesubspaces
arestrings
and allow a basis as astring
such that xi appearsas the first basis element yi . Now
246
and
d, b
commute with every of theXi’
the final contradiction(f) dimV6,
and this proves the
Proposition.
2. Construction of some groups H.
To show that
Proposition
3 is in a sensebestpossible
we constructgroups l~ for the case
This
excludes p
=2,
where more scrutinous observations are neces-sary. In each case a basis of
g3
nZ(H)
will begiven
such that the order of this characteristicsubgroup
is maximal. It is not too dif- ficult to determine all T cH3
nZ(H)
such that is stillisomorphic
toG;
forbrevity
we do not concern ourselves with this.task.
Case A:
IGjG’1
=p3.
Here we have
In the notation as before we find
Case B:
IGIGI =p4,
thestring
case.Then
and
Case 0:
IGIGI
=p4
and G is a directproduct x1, X2) X X4).
Then
Case D: =
p 4, completely nondegenerate
case.Here G can be described as a group with the
galois
field of orderp2
as
operator domain,
and.g3
r1Z(H) p4.
The actual
description
woulddepend
on theprime
p.Case E:
G/G’ = p5.
Here
and
(In particular H
does not exist ifx2 = [x,, x4].)
REMARKS.
(1)
Thequotient
groupsH2
nZ(H)jHa
nZ(H)
haveorders bounded
by
p in CaseA, p4
in CasesB, C, D
andp8
in Case E.(2)
If G =HjZ(H)
and G is a p-group, if furtherIx>1
= p, then also is a centralquotient:
Choose a maximalsubgroup
M of G and an
element y
such that G= M, y>,
and form the exten-sion .g of
x, z) by H
such that zP = 1 =[x, z], [x, y]
= z,[x, 11
_=
[z, 1]
= 1 forall 1
in thepre-image k
of ll~ in ~. Now.KiZ(g)
is
isomorphic
to G Xx~.
This shows that
groups H
do exist as constructed in this sectionas
long
as Gp =1,
even ifG’ ~ Z(G).
248
3. An
example
forhigher
rank.Consider
This group is
isomorphic
to a centralquotient HjZ(H)
whereThis follows from the fact that the vector space
corresponding
tothe
subgroup ti,
si,sjtj, Z(G)~
is astring.
REFERENCES
[1] F. R. BEYL - J. TAPPE, Extensions,
representations,
and the Schur multi-plicator,
Lecture Notes in Mathematics,958,
Berlin,Heidelberg,
New York,1989.
[2] R. SCHARLAU, Paare alternierender Formen, Math. Z., 147 (1976), pp. 13-19.
[3] A. L. WISHNEVETSKII,
Groups of
class 2 and exponent p with commutatorsubgroups of
orderp2, Doklady
Akad. Nauk Ukrain. S.S.R. Ser. A, 103,9 (1980), pp. 9-11
(Russian).
Manoscritto