R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
G IULIA S ARGENTI
Continuity results for solutions of certain degenerate parabolic equations
Rendiconti del Seminario Matematico della Università di Padova, tome 99 (1998), p. 105-131
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of Certain Degenerate Parabolic Equations.
GIULIA
SARGENTI(*)
ABSTRACT - In this paper we prove the local
continuity
foressentially
boundedlocal weak solutions of a
large
class ofdegenerate parabolic
equations, withprincipal
part characterizedby
non standardgrowth
conditions.1. - Introduction.
The
present
section is devoted to introduce a class ofquasilinear
de-generate parabolic equations
of thetype
where = S~ x
( o, T),
,~ is a bounded domain inR N
and 0 T 00, 6D’ is the space of distributions on and Du denotes thegradient
re-spect only
to the space variable. Here we assume:(1.2)
F: Rx
(n, z) - F(n, z)
is continuous in n,
uniformly
continuous In z .There exists two functions
C1, C2,
such that forall 17 E=- R,
(*) Indirizzo dell’A.:
Dipartimento
di Matematica, Universita di Roma «LaSapienza»,
Piazzale Aldo Moro 2, 00185 Roma,Italy.
E-mail:
[email protected]
for a.e.
(x, t)
EQ T. Here p
>q ~ 0, (s), s
>0,
is a nonincreasing
and
positive function,
whiles H C2 ( s ),
s > 0 is a nondecreasing
func-tion. For
0~1,
we shall assume that isuniformly
continuous and
bounded,
say forexample
there exists some constants 0 1 s 2 such thatA measurable function u is a local distributional solution
(supersolu- tion, subsolution)
of(1.1)
in if it satisfies thefollowing
condi-tions :
and for every
compact
subset % of S~ and every subinterval of(o, T]
for every non
negative
localtesting
functions =- ~ cp
E~( S2 T ):
cp withsupport
in x x[ tl ,
We can also assume that
for some
positive
and finite constant M. Moreover(1.8)
The maximum
principle
holds forboundary
valueproblems
~~°~~
(associated
toequation (1.1) .
Lastly,
we assume that a solution of(1.1)
can be constructed as the weak limit in the norm(1.5)
of local smooth solutions ofregularized problems
where F satisfies thefollowing monotonicity
condition:for all zi , Z2 e
R, where {’, ’)
denotes the scalarproduct
inRN.
We
always
refer to((C1 (M), C2 (M), M, N,
p,q)
as the data and wesay C =
C(data)
if C is a constant which we can determinate apriori
interms of the
previous quantities.
The aim of this paper is to
get
aregularity
result for a solution of( 1.1 ).
Moreprecisely
we want to state thefollowing
theorem:MAIN THEOREM. Under the
assumptions (1.2)-(1.9),
every essen-tially
bounded distributional solutionof (1.1) is locally
continuous inQT . Moreover,
there exists anondecreasing,
nonnegative function
such that
for
all(Xi, ti )
E K x( E, T),
K acompact
subsetof Q,
i =1, 2 .
The idea of theproof
may beeuristically
discussed as follows: for everyQ T,
there is a sequence ofshrinking cylinders
around(xo , to )
such that the essential oscillation of u in these sets decreases to zero asthey
tend to zero. The crucialstep
is to obtain from(1.1)
some basicinequalities.
This kind ofequations
can describe the evolution of nonlinear elasticphenomena.
Thestationary
case has beenwidely
stud-ied
(see
for istance the contributions due to Marcellini[9, 10, 11]
for awide literature on this
subject).
Here ourapproach
iscompletely
differ-ent : we will
apply
the newtechniques mainly developped by
DiBenedetto and
usually applied
for some nonlinearparabolic prob- lems-(see [4, 5, 6,14,16])-even
in this case, where the maindifficulty
is
given by
the non standard structure condition(1.3).
The way weovercome this obstacle is
fully explained
in the next section. Section 3 is devoted to other basicinequalities
necessary toprove-in
the last sec-tion-the main theorem.
REMARK 1.1. For the
proof
of the main theorem it isonly
necess-ary to assume instead of
(1.7).
We can also assumeREMARK 1.2. Main teorem is still valid for the
operator
which satisfies
(1.2)-(1.8)
and it is also continuous in t.2. - Notation and local
integral inequalities.
Let 1 be fixed. In what
follows,
wealways
assumethat 0
and Q
are numbers such that:where
Q(g,
is thecylinder
centered in theorigin,
withheight
cross section
Ke ,
For k we define the truncations
We will choose levels k
satisfying
where 3 is a
positive
number to fix later. Since F satisfies(1.9),
for allk E R the functions
(u - k) +
are subsolutions of(1.1)
in the sense of(1.6) (see [5, chapter II,
section1]).
LetHk
be defined as in(2.1).
We intro- duce thelogarithmic
functionwhich we
briefly
denoteby Vf(u)
and apiecewise
smooth cutoff function~,
defined in thecylinder [(xo , to )
+Q(Q, B~o p + 2 )]
and such thatWe also define the sets
Now we can state the fundamental
inequalities
necessary to prove the main theorem. First we need thefollowing
lemma:-
LEMMA 2.1. Let
(1.2)-(1.4)
and(1.7)
hold. There exists constantsCi
=Ci (Ci (M)),
i =1, 2
such thatfor
all L >1, for
all y >0,
thereexists 3 E
(0, 1/2 ),
which can be determinated apriori in
termsof
the data and
~3
E[ q, p]
snch thatfor all
zoI
E[1, L ], for
allr¡o E R,
where
PROOF. If
(1.4) holds, (2.4)
followswith B
= 0. If(1.3) holds,
weget
for a.e.
(X, t)
EBy (1.2), (1.3)
and(1.7),
weget
the existence of anumber
f3
E[q, p]
and of a constant C E[ C1 (M),
such thatwhere
I
isarbitrarily
fixed in[ 1, L ] [ y, M],
y > 0. Since(1.2) holds,
for all E > 0 thereexists dE > 0
such thatVz,
We fix - =
C1 (M)/2. Collecting
theprevious inequalities
we obtainfor all
(n, z)
E1,5 (no,
We choose 6 =d(C, (M))
E(o, 1/2).
SinceLemma will follow
choosing
PROPOSITION 2.1. Let
(1.1)-(1.9)
hold. There exists a constant C =C(data)
such thatfor
everycylinder [(xo , to )
+Q(ag,
cwhere a E
( 0, 1 ),
andfor
every levelPROOF. It would be
technically
convenient to have a formulationequivalent
to(1.6)
that involves ut. Fix t E( o, T)
and let h be so small that 0 t t + h T. In(1.6)
we taket1
=t, t2
= t + h and a functioncp =
cp(x). Dividing by h,
weget
where Uh
is the Steklov average of u,Now we fix a subinterval
[t1, t2] ç (0,
+ h 5 T and we inte-grate
theprevious integral equality
over with atesting
function
where u’
is the average of Uk in the xvariables,
with w E C °°
(R N ), w
= 0 for1, f w(y) dy
= 1. Such a choiceIYI -1 1
of q is admissable since supp cp =
Q, Q
= x’ x[tl , t2 ],
with x’ c %,at cp
EL 2 ( Q ), D n cp
EC( ~ ),
for any order n .Up
to a translation we mayassume
(xo , to )
=(0, 0)
and we maychoose g sufficiently
small in orderto have
(see [7, chapter II]
for more details).
We will state(2.5) only
when thestructure conditions
(1.2), (1.3), (1.5)-(1.9)
hold since in the case(1.4)
we havenothing
to prove.By
Lemma2.1,
for all(x, t)
EQ(Q, Bop + 2 ),
forall u
satisfying (1.7),
whatever is the value which thegradient
of u as-sumes, there exists an interval of the
type 15-whom
thegradient
be-longs
to-such that(2.4)
holds.Moreover,
forall j ~ 1,
we can define thefollowing
sets:Aj = t)
EQ(Q, + 2 ):
there exists/3~
E[q, p]
such thatwhere
Co , C2
are fixed constants for every intervalObviously
moreover,
V(.r, t )
e9o p + 2 )
there exists anumber j = j,
such that(x, t) EAJ,
so weget
For
semplicity
we setfor t E
( - B~O p + 2 , 0).
Weintegrate by parts
overQt
and estimate the termsseparately. By
theregularity
ofuh
and its convergence to uh inthe norm
L 2 (Q), letting e
- 0 weget
and
then, by
the convergence of ~h to u inL 2 (Q),
for h - 0 weget
By (1.5)
theregularity of Duh and Uk
and the use of the local smoothapproximations
andicated in theintroduction,
weget
where C doesn’t
depend
on E, we canapply Lebesgue
theorem: sinceDu’
and to asubsequence-converges
toDUh and
a. e. inQ,
for E ~ 0 we obtain
(see
also[7, chapter II]
for the convergencearguments ). Combining (2.7)
with(2.8),
we obtainBy
means of(2.6),
we can writewhere
From the definition of
Aj, using
Holder’sinequality
withexponents
+
2 )/(~i~
+1)
and(3j, choosing
a= (3j
+2,
weget
Inserting (2.10)
in(2.9)
andusing (2.11),
we obtainWe fix the value
By (2.13), (2.12)
becomesIn order to estimate the second term of the
right
hand side of(2.14)
we observe that since
where is the characteristic function on the set A.
Applying
Hold-er’s
inequality
weget
We
apply (1.3)
on the third term of the left hand side of(2.14)
in which also we insert(2.15).
Thisyealds
thefollowing
estimate:(2.5)
follows from(2.16), using
the fact that t wasarbitrary
in the in-terval
( - oep + 2 , 0)..
PROPOSITION 2.2. Let
(1.1)-(1.6)
hold. There exists a constant C ==
C(data)
such thatfor
every level ksatisfying (2.1)
and 1/2PROOF. We may assume
(xo , to )
=(0, 0)
and we work with the setsA~
and thecylinders
t andQt
introduced earlier. We take the cutofffunctions ~
defined in(2.3) indipendent
of0)
andwe select the
testing
functionswhere we use the
symbol ’ -
a u andwhere uEh
is defined as in theproof
of
Proposition
2.1.By
direct calculationwhich
implies
that T is an admissable function in(1.6).
We follow the scheme used in theprevious proof:
weintegrate by parts
overQ, t and
consider
separately
the terms. For E - 0 weget
then for h - 0
In the same way, for E ~ 0
For
h -~ 0,
theprevious inequality implies
Collecting (2.18)
with(2.19),
we obtainWe
repeat
the method used inProposition (2.1).
DefineBy
Lemma2.1, using
Holder’sinequality
withexponents
+2)/
+
1) and f3j
+2, choosing
a =~i~
+2,
weget
By
virtue of(2.2)
and(2.1)
Therefore, inserting (2.22)
in(2.21),
weget
Inserting (2.23)
in(2.20), using (1.3) together
with(1.7)
and(2.4),
weobtain
We f°1x e as in
(2.13)
and we omit the third term on the left handside;
then
(2.24)
becomesArguing
as in the conclusion of theProposition
2.1Combining (2.26)
with(2.25), (2.17)
follows.3. - Basic results.
Let introduce the
following
subsets ofand
The
previous
definitionsimply
where M is the constant introduced in
(1.7).
In whatfollows,
wealways
consider the values E R of the
type
where ) *
E(0, 1/2 )
and when we want topoint
out thedependence
of kto ~ ± ,
we shall writeA~ ± , e
instead of For sake ofsemplicity,
wealso introduce the
following
notation:let m, p > 1 and consider the Banach spaces
both
equipped
with the normWhen m = p we set
(Q T)
= Vp( S~ T ).
Without loss ofgenerality,
we may assume
We
apply
theinequalities
stated in section 2 toget
an estimate of!~B.!.
..PROPOSITION 3.1. There exists a number v + = v + E
( 0, 1 ),
v + == v +
( cv , ~ + , 0, data),
such thatif
then
There exists a number v + E
( 0, 1 ),
v + =C( data)/B
such thatif (3.3)
and alsohold,
thenAnalogous
resultfor
the setA~ _ , ~ ~ .
.PROOF. We can assume
(xo , to )
=(0, 0).
We will work within thecylinders
where
In Qn
we define a sequence of cutofffunctions iz
suchthat iz
= 1over
Qn , ç n
= 0 on theparabolic boundary
of2 nje,
0 ~~
at ~ n ~
Then we chooseFirst we observe that
so that
(3.1)
and(1.10) imply
We can
apply (2.5): using
the fact that(u - kn )2 , (u - ~n )q + 2
and(u_~)p+2B(u_~)q+2~
weget
Let
(x)
be a nonnegative piecewise
smooth cutoff function defined inK, ,
whichequals
one onKen +
1 and which satisfiesthen ( Since
we can rewrite
(3.7)
in a more concise way:By
means ofCorollary
3.1 inchapter
Iof [5],
Holder’sinequality
andthe fact that
(u - kn)+ Çn
E(0, 1],
weget
By
means of(3.8), (3.9)
becomesNext we observe that
indeed,
ifnot,
we wouldimmediately get (3.4)
and thecontinuity
theo-rem will
easily
follows. ThusThe left hand side of
(3.10)
is estimated belowby
C ombining (3.10)
with(3.11),
we obtainWe divide
(3.12) by 1
and introduce thequantities Yn
==
I
so that(3.12)
becameswhere
By [5,
Lemma4.1, chapt. I], (3.4)
follows if(3.3)
holds with(3.6)
follows in a similar waychoosing
in(2.5)
a sequence oftesting
functionsdepending only
on x andworking
within thecylinders
The main difference is that in this case
PROPOSITION 3.2. E
(0, 1/2)
be afixed
number such thatthen for
every v + E( 0, 1 ),
there exists a E( 0, ~ o /4 ),
where~+ = ~+ (~6, (J, data),
such thatAnalogous
resultfor
the setI A-, Q (t)|.
-PROOF. We may assume
(xo , to)
=(0, 0)
and choose in(2.2)
the valueswhere 0
~ + ~/4
will be chosen later. In this way(u - 1~)+ ~
~ ~o cv ~
1/2 so that(2.1)
is satisfied with 3 K 1/2. We canapply proposi-
tion 2.2: we choose a
testing function ~
such thatUsing (3.13), (3.15)
and the fact that 0~ 1,
weget
that theright
hand side of
(2.17)
ismajorised by
We minorise the left hand side of
(2.17) by
(3.17) together
with(3.16) gives
To prove
(3.14),
wechoose C+
from the relation4. - Proof of the
continuity
theorem.In this
section,
we prove the main theoremfollowing
the methodused in
[6,
Sections5-29]
and[14,
Section4]. Up
to a translation we can assume(xo , to )
_(0, 0)
and choose theparameter
0equal
to 1.The
first
alternative.If
(3.3) hold,
thanks to(3.4),
we canapply proposition
3.2.(3.14)
im-plies again (3.3)
from which(3.4)
follows in thecylinder Q(e/4, (e/4)P + 2 ). This joined
with theanalogous
result forplies
’
where t7 = q(m)
E(0, 1). Thus, going
down fromQ(e, ~Op + 2 )
too p + 2 ~8 ),
the oscillation of u decreasesby
a factor t7.The second alternative: the case N = q + 2.
Assume that both
(3.3)
and theanalogous
forA~ - , e ~ I
are violated.Arguing
as in[6,
sections5-9],
weget
the existence of a constant C =C(data)
such that:where D = E
(6e, e)
x(-~~~~, 0))
and 3 e(0, 1)
is anincreasing
function of w,
5(~)2013~0
for ~2013~0[6, Propositions 8.1].
We write
(4.2)
for thefamily
ofcylinders
Adding over j
and then over n =0, 1,
..., no -1,
we arrive at thefollowing
estimate:Thanks to
(2.5),
we canmajorize
theright
hand side of theprevious
inequality by C(02QN .
ForN = q + 2 we get:
We choose a number no such that the reverse
inequality
holds. Thecontradiction
implies (3.3)
must hold and thecontinuity
theorem fol- lowsarguing
as in the first alternative.The case
N > q + 2.
In order to state the main theorem in dimension
greater
than q +2,
we
substantially
follow[6,
Sections22-29]:
first we make apartition
ofin the
following
way:We fix one of these box and translate its vertex into the
origin. By
few
changes
ofPropositions
22.1 and 23.1 of[6],
we obtain thefollowing
result:
PROPOSITION 4.1. There exists
positive integers
m and 6 E( o, 1),
which can be determined a
priori
in termsof only data,
co, such thatfor
each box
[(0, ti )
+Q(Q, o ~ + 2 )],
there exists asubcylinder [(xl , th)
++
Q( 2d o o, 2(d o o)p + 2 )], for
which eitherwhere
Now assume that one of the
previous conditions,
say forexample (4.4),
holds in thecylinder
TE[-~(4~o)~-~~(l-~)(4~o)~L
r E con-tained in the lower half of
Q(Q, being
fixed. From such a boxwe can construct the
long cylinder
’
Thus
(4.4) implies
The last information is the
analogous
of(3.13); using Proposition 3.1,
we
get
thefollowing
result:PROPOSITION 4.2. Under the
previous assumptions,
there exists anumber ~
E( o, 1/18),
that can be determined apriori
in termsof data,
to, such that
PROOF. See
[6, Proposition 24.1]
for more details.If xl
=0,
we couldprocede
as in the first alternative. Since in gener- al is not so, we have to prove that an estimate similar to(4.6) actually
holds in a
cylinder
with vertex at theorigin.
We will determine the number 0 as theproduct
of a finiteincreasing
sequence ofpositive
inte-gers i.e.
We assume that ...,
kj
have been found anddetermine kj + 1.
We take
contiguous
stacks of boxes of thetype (4.3),
eachcontaining Ft 1 ki
of suchcylinders,
i.e.In turn we form
larger
stacksby taking kj+1 contiguous
stacks of the formS~,
i. e.Each
stn + 1
is the union1 pairwise disjoint
stacksS~, By
a lem-ma of
sequential
selection[6,
Lemma29.1],
we find ...,such that among the stacks there exists one where
(4.4)
holds for the same abscissa xl , for at least one cube of thetype (4.3),
within each of the smaller stacksSi (see
also[6,
section26]).
Now we rewrite(4.4):
within
Q(Q, 9~0 ~ + 2 ),
for some 1 E( - 0, 0),
there is acylinder
such that
0,
we can consider it as the centre of a ball con-tained in and
including K2e .
Now we make achange
of vari-ables :
Since
0g,
we have the transformationWe introduce the new function
(4.8)-(4.10)
enable us to formulate thefollowing parabolic prob-
lem :
Here we assume:
is continuous in w,
uniformly
continuous inDw ,
is monotone for all z
There exists two functions
Ci , i
=1,
2 defined as in(1.3),
such thatPROPOSITION 4.3. Consider the
parabolic problem
Under
assumptions (4.1l)-(4.13) problem (4.14)-(4.15)
has aunique
continuous radial solution
Moreover,
there exists a number ao and a time level k which can be determine apriori
in termsof
thedata,
suchthat, for
every yI d ~,
there is a time t E( 0, k)
such thatPROOF. With few
modifications,
we can make use of the energy es- timates contained in sections2,
3 and the first and the second alterna- tive of thepresent
section in order to prove thecontinuity
of v. In par-ticular, using
the scheme of sections 20 and 21of [6],
weget (4.17),
while(4.16)
is a consequence ofassumption (1.7) (see
also[6, Propositions 13.1-13.3]
for moredetails).
We will use v as a
comparison
function for the solution of(4.12).
In- deedby (4.17),
we can state the existence of apositive
number ao ; such that’
where t E
( o, k~ + 1 ).
We fix apoint
for which(4.18)
holds: sincev( ~, t)
iscontinuous in {!~2d}~ uniformly in t,
there exists a ballBýÑdj(Y)
such thatSince
v(., t)
isradial,
theprevious
lower bound still holds at thatpoint
of the annulus{1 ~x~ 2d}
which coincides with theorigin
ofthe
original
coordinates.By (1.8)
weget
i.e., using (4.10), coming
back to theoriginal variables,
there exists atime level
to ,
and a
number 6
such thatBy
thisprocedure
we candetermine kj+1
from ... , Analo-gously
if we have started from(4.5).
Now the main theorem follows asin
[6, Propositions 24.2,
24.3 and section25].
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Manoscritto pervenuto in redazione il 19
aprile
1996e, in forma revisionata, il 27