Probabilit´ es: exercice de base 3
Sources S ´ esamath
Seconde
SourcesS´esamathSeconde Probabilit´es: exercice de base 3
´ enonc´ e
On consid` ere deux ´ ev´ enements A et B tels que:
p(A) = 0, 7 p(B) = 0, 5 p(A ∪ B) = 0, 9 Calculer p(A ∩ B)
SourcesS´esamathSeconde Probabilit´es: exercice de base 3
correction
On sait que P (A ∪ B) = p(A) + p(B) − p(A ∩ B)
SourcesS´esamathSeconde Probabilit´es: exercice de base 3
correction
On sait que P (A ∪ B) = p(A) + p(B) − p(A ∩ B) donc P (A ∩ B ) = p(A) + p(B) − p(A ∪ B )
SourcesS´esamathSeconde Probabilit´es: exercice de base 3
correction
On sait que P (A ∪ B) = p(A) + p(B) − p(A ∩ B) donc P (A ∩ B ) = p(A) + p(B) − p(A ∪ B ) P (A ∩ B) = 0, 7 + 0, 5 − 0, 9
SourcesS´esamathSeconde Probabilit´es: exercice de base 3
correction
On sait que P (A ∪ B) = p(A) + p(B) − p(A ∩ B) donc P (A ∩ B ) = p(A) + p(B) − p(A ∪ B ) P (A ∩ B) = 0, 7 + 0, 5 − 0, 9
p(A ∪ B) = 0, 3
SourcesS´esamathSeconde Probabilit´es: exercice de base 3