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4 série, t. 36, 2003, p. 463 à 477.

AN ADDITIVE VERSION OF HIGHER CHOW GROUPS

B

Y

S

PENCER

BLOCH

AND

H

ÉLÈNE

ESNAULT

ABSTRACT. – The cosimplicial scheme

= ∆0→→1→→→. . .; ∆n:= Spec

k[t0, . . . , tn] ti−t

was used in (Bloch, S., Algebraic cycles and higherK-theory, Adv. Math. 61 (3) (1986) 267–304) to define higher Chow groups. In this note, we letttend to 0 and replace∆by a degenerate version

Q=Q0→→Q1→→→. . .; Qn:= Spec

k[t0, . . . , tn] ti

to define an additive version of the higher Chow groups. For a fieldk, we show the Chow group of0-cycles onQnin this theory is isomorphic to the group of absolute(n1)-Kähler formsΩnk1.

An analogous degeneration on the level of de Rham cohomology associated to “constant modulus”

degenerations of varieties in various contexts is discussed.

2003 Éditions scientifiques et médicales Elsevier SAS

RÉSUMÉ. – Le schéma cosimplicial

= ∆0→→1→→→. . .; ∆n:= Spec

k[t0, . . . , tn] ti−t

a été utilisé dans (Bloch, S., Algebraic cycles and higherK-theory, Adv. Math. 61 (3) (1986) 267–304) afin de définir des groupes de Chow supérieurs. Dans cette note, nous définissons une version additive des groupes de Chow supérieurs en faisant tendretvers 0 et en remplaçant∆par une version dégénérée

Q=Q0→→Q1→→→. . .; Qn:= Spec

k[t0, . . . , tn] ti

.

Nous montrons que sur un corpsk, le groupe de Chow des 0-cycles dans cette théorie est isomorphe aux formes de Kähler absolues de degré(n1).

Nous discutons une dégénerescence analogue en cohomologie de de Rham apparaissant dans diverses situations pour des familles à module constant.

2003 Éditions scientifiques et médicales Elsevier SAS

1. Introduction

The purpose of this note is to study a common sort of limiting phenomenon which occurs in the study of motives. Here is a simple example. Let kbe a field. LetS=A1t = Spec(k[t])

ANNALES SCIENTIFIQUES DE L’ÉCOLE NORMALE SUPÉRIEURE

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and letT= Spec(k[x, t]/(x(x−t))→A2t,x. OverS[1/t]the Picard schemePic(A2x,t, T)/Sis represented byGm,S[1/t]. On the other hand, whent= 0one getsPic(A1x,{x2= 0})=Ga,k. In some sense,Gmhas “jumped” toGa.

In higher dimension, fort= 0, the homology of the group of algebraic cycles associated to the cosimplicial scheme

= ∆0→→1→→→. . .; ∆n:= Spec

k[t0, . . . , tn] ti−t

(1.1)

is known to give motivic cohomology [9]. What can one say about the algebraic cycle groups (1.3) of the degenerate cosimplicial complex:

Q=Q0→→Q1→→→. . .; Qn:= Spec

k[t0, . . . , tn] ti

? (1.2)

Our main result is a calculation of the Chow groups of0-cycles onQ. LetZn(Qr)be the free abelian group on codimensionnalgebraic cycles on Qrsatisfying a suitable general position condition with respect to the face maps. LetSHn(k, r)be the cohomology groups of the complex

· · · → Zn Qr+1

→ Zn Qr

→ Zn Qr1

→ · · · (1.3)

where the boundary maps are alternating sums of pullbacks along face maps. WriteΩk for the absolute Kähler differentials.

THEOREM 1.1. –

SHn(k, n)= Ωnk1. Note forn= 1, this is the aboveGa.

We explain another example of this limiting phenomenon. We considerPn+1 with homoge- neous coordinatesU0, . . . , Un+1over a fieldk. Let

X: f(U0, . . . , Un+1) = 0 (1.4)

be a hypersurfaceX defined by a homogeneous polynomialf of degreen+ 2(e.g. an elliptic curve inP2).

Writeui=Ui/U0, and define a log(n+ 1)-form onPn+1\X ωf:=du1∧ · · · ∧dun+1

f(1, u1, . . . , un+1). (1.5)

As well known, this form generatesωPn+1(X)=OPn+1.

Let r1, . . . , rn+10 be integers. We consider the action ofGmgiven by the substitutions ui =trivi. Let N be minimal such that tNf(1, tr1u1, . . . , trn+1un+1) is integral in t.

Assumes:=N−

ri>0andsis invertible ink. One checks easily that in the coordinatesvi

one has

ωf=tsνf(t, v1, . . . , vn+1) +sts1dt∧γf(t, v1, . . . , vn+1) (1.6)

with

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νf(t, v1, . . . , vn+1) = dv1∧ · · · ∧dvn+1

tNf(1, tr1v1, . . . , trn+1vn+1), γf(t, v1, . . . , vn+1) =1

s

i

(−1)irivi

dv1∧ · · · ∧dvi∧ · · · ∧dvn+1

tNf(1, tr1v1, . . . , trn+1vn+1).

Thusνf andγfare forms indviof degreesn+ 1andnrespectively which are integral int.

Asωf is an(n+ 1)-form onPn+1in theu-coordinates, it is closed, so sts1dt∧

νf(t, v1, . . . , vn+1)−dγf(t, v1, . . . , vn+1)

+sts1· t

sdνf(t, v1, . . . , vn+1) = 0.

Dividing byts1and restricting tot= 0yields

νf|t=0=f|t=0. (1.7)

In other words, under the action of the 1-parameter subgroup, νf degenerates to the exact formf.

To see the relationship with the0-cycles, take

n+1: f(1, u1, . . . , un+1) =u1u2· · ·un+1(1−u1− · · · −un+1) = 0.

Substitutevi=tui, 1in+ 1. Thens= 1, and a calculation yields

γn+1(:=γf) = n+1

i=1(−1)idlog(v1)∧ · · · ∧dlog(vi)∧ · · · ∧dlog(vn+1) t−v1− · · · −vn+1

, νn+1(:=νf) = dv1∧ · · · ∧dvn+1

v1v2· · ·vn+1(t−v1− · · · −vn+1). (1.8)

Note the limiting configuration ast→0is (compare (1.2)) v1v2· · ·vn+1(v1+· · ·+vn+1) = 0.

For convenience we write

γn:=γn+1|t=0. (1.9)

We viewνn+1|t=1(resp.γn) as a map Z0

An+1k \ (1−u1+· · ·+un+1)u1· · ·un+1= 0

n+1k (resp.

Z0

An+1k \ {v1v2· · ·vn+1(v1+· · ·+vn+1) = 0}

nk).

HereZ0denotes the free abelian group on closed points (0-cycles) and the maps are respectively x→Trk(x)/kν|{x}; x→Trk(x)/kγ|{x}.

(1.10)

In the first case, the Nesterenko–Suslin–Totaro theorem [7,8] identifies the zero cycles modulo relations coming from curves inAn+2with the MilnorK-groupKn+1M (k). The evaluation map

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(1.10) passes to the quotient, and the resulting mapKn+1M (k)n+1k is given on symbols by thedlog-map

{x1, . . . , xn+1} →dlog(x1)∧ · · · ∧dlog(xn+1).

(1.11)

In the second case, factoring out by the relations coming from curves onAn+2as in (1.3) yields the Chow group of0-cyclesSHn+1(k, n+ 1), and our main result is that evaluation onγngives an isomorphism

SHn+1(k, n+ 1)= Ωnk. (1.12)

Sections 2–5 contain the proof of Theorem 1.1. Section 6 contains some brief remarks on specialization of forms as it relates to Aomoto’s theory of configurations, to 0-cycles on hypersurfaces, and to Goncharov’s theory of hyperbolic motives. Finally, Section 7 computes SH1(k, n), responding to a question of S. Lichtenbaum.

2. The additive Chow groups

In this section, we consider a fieldk, and ak-schemeXof finite type.

We will throughout use the following notations.

Notations 2.1. – We setQn= Speck[t0, . . . , tn]/(n

i=0ti), together with the faces

j:Qn1→Qn; j(ti) =



ti i < j, 0 i=j, ti1 i > j.

One also has degeneracies

πj:Qn→Qn1; πj(ti) =



ti i < j, ti+ti+1 i=j, ti+1 i > j.

We denote by{0} ∈Qnthe vertex defined byti= 0. We writeQnX=Qn×Spec(k)X. The above face and degeneracy maps makeQXa cosimplicial scheme.

DEFINITION 2.2. – Let SZq(X, n) be the free abelian group on irreducible, dimension q subvarieties inQnXwith the property:

(i) They don’t meet{0} ×X.

(ii) They meet all the faces properly, that is in dimensionq.

Thus the face maps induce restriction maps

i:SZq(X, n)→ SZq1(X, n1); i= 0, . . . , n; = n i=0

(−1)ii;

yielding complexesSZq−•(X,•):

· · ·→ SZ q+1(X, n+ 1)→ SZ q(X, n)→ SZ q1(X, n1)→ · · · .

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DEFINITION 2.3. – The additive higher Chow groups are given forn1by SHq(X, n) =Hn

SZq−•(X,•)

and (forXequidimensional)

SHp(X, n) =SHdim Xp(X, n).

The groups are not defined forn= 0.

Remarks 2.4. –

(i) The above should be compared with the higher Chow groupsCHp(X, n) defined as above withQreplaced by∆, where∆n:= Spec(k[t0, . . . , tn]/(

ti1)).

(ii) The cosimplicial schemeQadmits an action ofGm,k, which we define by x !(t0, . . . , tn) := (t0/x, . . . , tn/x).

(The reason for the inverse will be clear below.) By functoriality, we obtain ak×-action on theSHp(X, n).

(iii) Letf:X→Xbe a proper map withn= dimX−dimX. Then one has a push-forward map

f:SZp(X,•)→ SZpn(X,•).

On homology this yields SHp(X, n)→SHpn(X, n). We will be particularly in- terested in the case X = Spec(k), X = Spec(k) with [k : k]< . We write trk/k:SHp(k, n)→SHp(k, n) for the resulting map. This trace map is compatible with the action ofk× from (ii) in the sense that forx∈k× anda ∈SHp(k, n) we havex !trk/k(a) = trk/k(x ! a).

LEMMA 2.5. – The!action ofk× onSHn(k, n)extends to an action of the multiplicative monoidkby setting0! x= 0. This action comes from ak-vector space structure onSHn(k, n).

Proof. – We have to show that for a closed pointx= (u0, . . . , un)∈Qn\n

i=0i(Qn1), and a, b∈k, one has(a+b)! x=a ! x+b ! x. For eitheraorb= 0, this is trivial. Thus we assume ab= 0. Letk=k(x). Then the class inSHn(k, n)ofxis the trace fromktokof ak-rational pointx∈SHn(k, n). Using the compatibility of!and trace from Remarks 2.4(iii) above, we reduce to the casex k-rational.

Write(t0−u0, . . . , tn−un)for the ideal ofx. Define$(t) =−uab0t+a+b. Consider the curve W ⊂Qn+1defined parametrically by

W=

t,−t+ u0

$(t), u1

$(t), . . . , un

$(t)

.

To check that this parametrized locus is Zariski-closed, we consider the ideal:

IW =

(t1+t0)$(t0)−u0, t2$(t0)−u1, . . . , tn$(t0)−un

.

Ify= (y0, . . . , yn+1)is a geometric point in the zero locus ofIW, then since theui= 0we see that$(y0)= 0. Substitutingt=y0, we see thatylies on the parametrized locusW.

The equation−t+(t)u0 = 0leads to a quadratic equation intwith solutionst=ua0, t=ub0. Ifa+b= 0we have

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0(W) = u0

a+b, . . . , un

a+b

= (a+b)!(u0, . . . , un),

1(W) = u0

a, . . . ,un

a

+ u0

b , . . . ,un

b

=a !(u0, . . . , un) +b !(u0, . . . , un),

i(W) = 0, i2,

so the lemma follows in this case. Ifa+b= 0, then0W= 0as well, and again the assertion is clear. ✷

3. Additive Chow groups and MilnorK-theory

We consider the map (compatible with faces)ι: ∆→Q+1defined onk-rational points by (u0, . . . , un)(−1, u0, . . . , un). It induces a map of complexesZp(k,•)→ SZp+1(k,+ 1), which in turn induces a map

ι:CHp(k, n)→SHp+1(k, n+ 1).

(3.1)

By [7] and [8], one has an isomorphism

KnM(k)=CHn(k, n) (3.2)

of the higher Chow groups of0-cycles with MilnorK-theory. It is defined by:

(u0, . . . , un)

−u0

un

, . . . ,−un1

un

, (3.3)

{b1, . . . , bn} → b1

c, . . . ,bn

c ,−1 c

; c=−1 + n i=1

bi. (3.4)

Note that ifn

i=1bi= 1, then the symbolβ:={b1, . . . , bn}is trivial in MilnorK-theory, and one mapsβto 0.

In this way, one obtains a map KnM1(k)→SHn(k, n);

{x1, . . . , xn1} →

−1, x1

−1 +n1 i=1 xi

, . . . , xn1

−1 +n1 i=1 xi

, 1

−1 +n1 i=1 xi

. (3.5)

4. Differential forms

In this section we construct a k-linear mapnk1→SHn(k, n). (HereΩik are the absolute Kähler differentiali-forms.)

The following lemma is closely related to calculations in [5].

LEMMA 4.1. – As a k-vector space, the differential formsnk1 are isomorphic to (kZn1k×)/R. The k-structure on k⊗Zn1k× is via multiplication on the first argu- ment. The relationsR, forn2, are thek-subspace spanned by

a⊗(a∧b1∧ · · · ∧bn2) + (1−a)⊗

(1−a)∧b1∧ · · · ∧bn2

,

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forbi∈k×,a∈k. The map(kZn1k×)/R →Ωnk1is then defined by (a, b1, . . . , bn1)→adlogb1∧ · · · ∧dlogbn1.

Proof. – Write:= (kZk×)/R. This is a quotient of the gradedk-algebrak⊗Zk× by the graded idealRand hence has a gradedk-algebra structure, generated in degree1. There is an evident surjection of graded algebras, so, by the universal mapping property of the exterior algebraΩ, it suffices to check1= Ω1.

Define D:k→(kZk×)/Rby D(a) =a⊗afora∈k×, elseD(0) = 0. To define the required inverse, it suffices to show that D is a derivation. Clearly,D(ab) =aD(b) +bD(a).

Also1⊗ −1is trivial ink⊗k×, soD(−a) =−D(a). Givena, b∈k×, writeb=−ac. We have D(a+b) =D(a−ac) =aD(1−c) + (1−c)D(a)

=−aD(c) +D(a)−cD(a) =D(a) +D(−ac) =D(a) +D(b).

(4.1)

HenceDis a derivation so the inverse mapΩ11is defined. ✷ Remark 4.2. – We will frequently use the relations in the equivalent form

a⊗a∧(· · ·)(1 +a)⊗(1 +a)∧(· · ·)0.

PROPOSITION 4.3. – One has a well-definedk-linear map φ: Ωnk1→SHn(k, n), α:=adlogb1∧ · · · ∧dlogbn1→a !

−1,b1

γ, . . . ,bn1

γ ,−1 γ

, whereγ=1 +n1

i=1 bi. (Defineα= 0whenγ= 0.) The diagram KnM1(k) dlog

(3.5) ι

nk1

φ

SHn(k, n) SHn(k, n) is commutative.

Proof. – We writec=1 +a+n1

i=2 bi. By Lemma 4.1, we have to show 0 =ρ:=a !

1,a

c, . . . ,bn1

c ,−1 c

(a+ 1)!

1,a+ 1

c+ 1, . . . ,bn1

c+ 1,− 1 c+ 1

. Ifa= 0, then one has

ρ=

−1,1

c, . . . ,bn1

c ,−1 c

=−ι{1, b2, . . . , bn1}= 0.

Similarly,ρ= 0ifa=1. Assume nowa= 0,1. Setb=−a∈k\ {0,1}. One defines, for n3and(u1, . . . , un1)(∆n2\n1

i=1n3)(k), the parametrized curve Γ(b, u) :=

−1

b +t, 1

b−1,−t, −u1

b(b−1), . . . , −un1

b(b−1)

⊂Qn+1

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and forn= 2

Γ(b) :=

1

b +t, 1

b−1,−t, 1 b(b−1)

⊂Q3. (4.2)

(See [8] for the origin of this definition.) This curve is indeed in good position, so it lies in SZn(Qn+1). One computes

∂Γ(b, u) = (1−b)!

−1,11 b,u1

b , . . . ,un1

b

+b !

−1, b

b−1, −u1

b−1, . . . ,−un1

b−1

. (4.3)

(Resp. in the casen= 2

∂Γ(b) = (1−b)!

−1,11 b,1

b

+b !

−1, b b−1, −1

b−1

.) Now one has

−1,11 b,u1

b , . . . ,un1

b

=ι 1−b

un1

,− u1

un1

, . . . ,−un2

un1

=ι

1−b,− u1

un1

, . . . ,−un2

un1

un1, u1, . . . , un2

,

as the rest of the multilinear expansion contains only symbols of the shape {. . . , un1, . . . ,

−un1, . . .}. On the other hand, since n1

i=1 ui = 1, one has {un1, u1, . . . , un2} = 0.

Similarly, one has

−1, b

b−1, −u1

b−1, . . . ,−un1

b−1

=ι b

un1

,− u1

un1

, . . . ,−un2

un1

. The same argument yields that this is

ι

b,− u1

un1

, . . . ,−un2

un1

.

It follows now from (4.3) that forn3we have the relation inSHn(k, n) (1−b)! ι

1−b,− u1

un1

, . . . ,−un2

un1

+b ! ι

b,− u1

un1

, . . . ,−un2

un1

= 0.

(4.4)

(The analogous relation forn= 2is similar.) ✷ PROPOSITION 4.4. – With notation as above, the map

φ: Ωnk1→SHn(k, n)

is surjective. In particular,SHn(k, n)is generated by the classes ofk-rational points inQn.

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Proof. – It is easy to check that the image of φcoincides with the subgroup of SHn(k, n) generated byk-points. Clearly,SHn(k, n)is generated by closed points, and any closed point is the trace of a k-rational point for some finite extensionk/k. We first reduce to the case k/k separable. Ifx∈Qnk is a closed point in good position (i.e. not lying on any face) such thatk(x)/k is not separable, then a simple Bertini argument shows there exists a curveC in good position onQn+1such that∂C=x+ywhereyis a zero cycle supported on points with separable residue field extensions overk. Indeed, letW⊂Qn+1be the union of the faces. View x∈W. Since xis in good position, it is a smooth point of W. Bertini will say that a non- empty open set in the parameter space ofn-fold intersections of hypersurfaces of large degree containingxwill meetW inxplus a smooth residual scheme. Sincekis necessarily infinite, there will be such ann-fold intersection defined overk. Since the residual scheme is smooth, it cannot contain inseparable points. Thenx≡ −ywhich is supported on separable points.

We assume now k/k finite separable, and we must show that the trace of a k-point is equivalent to a zero cycle supported onk-points. Since the image ofφis precisely the subgroup generated byk-rational points, it suffices to check that the diagram

nk1

φ

Trk/k

SHn(k, n)

Trk/k

nk1 φ SHn(k, n) (4.5)

commutes. Because k/k is separable, one has Ωnk1nk1, and Ωnk1=k·nk1. One reduces to showing, forα= (−1, α1, . . . , αn)∈Qn(k)andt∈k, thatTr(t ! α) = (Tr(t))! α inSHn(k, n).

Let P(V) =VN +aN1VN1+· · ·+a1V +a0∈k[V] be the minimal polynomial of

1t. We set bN = α1

n, bi = αai

n, i=N 1, . . . ,2 and bi =ai, i = 1,0. We define the polynomialQ(V, u) =bNVN1u+· · ·+b2V u+b1V+b0∈k[V, u], which by definition fulfills Q(V,−αnV) =P(V). We define the ideal

I=

Q(V0, u), V1+α1V0, . . . , Vn1+αn1V0

⊂k[V0, . . . , Vn1, u].

It defines a curve W An+1. We think of An+1 as being Qn+1 with the faces V0 = 0, . . . , Vn1= 0, u= 0, u+n1

i=0 Vi = 0. Then this curve is in general position and defines a cycle inSZ1(k, n+ 1).

Sinceb0= 0, andαi= 0, one has

iW= 0, i= 0,1, . . . , n1.

(4.6) One has

uW defined by(a1V0+a0, V1+α1V0, . . . , Vn1+αn1V0).

To compute the last face, we observe that the ideal

u+

n1

i=0

Vi, V1+α1V0, . . . , Vn1+αn1V0

,

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containsu+αnV0. Consequentlyu+n−1

i=0ViW is defined by

Q(V0,−αnV0), V1+α1V0, . . . , Vn1+αn1V0

,

withQ(V0,−αnV0) =P(V0). Thus one obtains 0(−1)n∂W=a1

a0

!(−1, α)−t !(−1, α).

SinceP is the minimal polynomial of1t,aa1

0 is the trace oft.5. The main theorem

Recall (1.8) we have a logarithmic(n−1)-formγn1onQn= Spec(k[v0, . . . , vn]/(n i=0vi)) γn1= 1

v0

n 1

(−1)idlog(v1)∧ · · · ∧dlog(vi)∧ · · · ∧dlog(vn), n1=νn=dv1∧ · · · ∧dvn

v0v1· · ·vn

. (5.1)

Writingvi=Vi/Vn+1, we can viewγn1as a meromorphic form on Pn= Proj

k[V0, . . . , Vn+1] n

0

Vi

.

Let A: V0· · ·Vn = 0; ∞: Vn+1 = 0. The fact that n1 has log poles on the divisors Vi= 0, 0inimplies that

γn1Γ

Pn,nPn1

log(A+∞) (−∞)

. (5.2)

In particular, γn1 has log poles, so we can take the residue along components ofA. (The configurationAdoes not have normal crossings. The sheafΩnPn1(log(A+∞))is defined to be the subsheaf ofjnPn−A−∞1 , wherej:Pn\(A ∪ ∞)Pn is the open embedding, generated by forms without poles and the evident log forms with residue 1 along one hyperplane and (−1)along another one. According to [1], the global sections of this naturally defined log sheaf compute de Rham cohomology.)

In the following, we adopt the sign conventionRest=0dt

t ∧ω=ω. This yields Rest=0d

dt t ∧ω

=−d

Rest=0

dt t ∧ω

. LEMMA 5.1. – We have the following residue formulae

Resvi=0γn= (−1)iγn1; 0in+ 1.

Proof. – One can either compute directly or argue indirectly as follows:

−dResvi=0γn= R esvi=0n= R esvi=0νn+1

= (−1)i+1νn=−d

(−1)iγn1

= 0.

(5.3)

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To conclude now, it suffices to show that the space of global sections (5.2) has dimension1. To verify the dimension1property, letA⊂ Abe defined byV1· · ·Vn= 0. ThenA+consists ofn+ 1hyperplanes in general position inPn, so

nPn1

log(A+∞)

=n11Pn

log(A+∞)∼=OPnn.

One looks at the evident residue ΩnPn1

log(A+∞)

(−∞)nPn−12

log(A+∞) (−∞) alongV0= 0. ✷

Remark 5.2. – The computation of the lemma shows that γn1 is the unique (n1)- differential form in Γ(Pn,nPn1(log(A+∞))(−∞)) withn1=νn. The configurationA being given, fixingfixesγn1.

THEOREM 5.3. – The assignmentx→Trk(x)/k(γ(x))gives an isomorphism forn1 SHn(k, n)= Ωnk1.

Proof. – LetX⊂Qn+1k be a curve in good position. For a zero-cyclecin good position onQn we writeTrγn1(c)nk1(absolute differentials) for the evident linear combination of traces from residue fields of closed points. We must showTrγn1(∂X) = 0. LetXdenote the closure ofXinPn. We considerγn1|XΓ(X,nX/1

Z(∗D)), whereDis the pole set ofγn1|X. The formγn1 dies when restricted to. ThusD=n

j=0Dj⊂X, withDj:=j(Qn)∩X. We define the residue alongDjas follows. One has an exact sequence

0nk⊗ OXnX(logD)→nk1⊗ωX(logD)→0.

(5.4)

The residue map followed by the trace

ωX(logD)Tr

ResDj

−−−−−−−→k (5.5)

yields, by the reciprocity formula, a vanishing residue map on globaln-forms H0

X,nX/Z(logD)

nk1

k

H0

X, ωX(logD) 0

nk1. (5.6)

On the other hand, the residue decomposes as

H0

X,nX/Z(logD)

jResDj

−−−−−−→

n j=0

nDj1

jTr

−−−−→nk1. (5.7)

By Lemma 5.1,γn1(Dj) = (R esvj=0γn)(Dj). The desired vanishing follows.

We now have

nk1φ SHn(k, n)γ−→n−1nk1.

It suffices to check the composition is multiplication by(−1)n+1. Givenb1, . . . , bn1∈kwith c:=

bi1= 0, the composition is computed to be (use (5.1) and Proposition 4.3)

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a·dlog(b1)∧ · · · ∧dlog(bn1)

−a

(1)idlog b1

ac

∧ · · · ∧ dlog

bi

ac

∧ · · · ∧dlog 1

ac

. Expanding the term on the right yields

−a

(−1)idlog b1

c

∧ · · · ∧ dlog

bi

c

∧ · · · ∧dlog −1

c

−a·dlog(a)(. . .),

and it is easy to check that the terms involvingdlog(a)cancel. In this way, one reduces to the casea= 1. Here

(−1)idlog b1

c

∧ · · · ∧ dlog

bi

c

∧ · · · ∧dlog −1

c

= (−1)n+1db1

b1

∧ · · · ∧dbn1

bn1

+dc

c (. . .).

(5.8)

Again the terms involvingdlog(c)cancel formally, completing the proof. ✷

Challenge 5.4. – Finally, as a challenge we remark that the Kähler differentials have operations (exterior derivative, wedge product, . . . ) which are not evident on the cycles SZ. For example, one can show that the map

∇(x0, . . . , xn) =

x0,− x1x0

1−x0

, . . . ,− xnx0

1−x0

,− x0

1−x0

(5.9)

satisfies

γn

(x)

= (1)nn1(x) (5.10)

and hence induces the exterior derivative on the 0-cycles. The map is not uniquely determined by this property, and this particular map does not preserve good position for cycles of dimension

>0. Can one find a geometric correspondence on the complexSZ which inducesdon the 0-cycles? What about the pairings(a, b)→a∧bor(a, b)→a∧db?

6. Specialization of forms

In this section we consider again the specialization of differential forms as in Section 1. Recall f(U0, . . . , Un+1)is homogeneous of degreen+ 2,ui=Ui/U0, andvi=triui.N is minimal such thattNf(1, tr1v1, . . . , trn+1vn+1)is integral int, and we assumes=N−

ri>0. We have forms

ωf:=d(tr1v1)∧ · · · ∧d(trn+1vn+1)

f(1, tr1v1, . . . , trn+1vn+1) =tsνf+sts1dt∧γf

(6.1)

andνf|t=0=f|t=0.

We have already mentioned the case f= ∆n+1=

t1v1

· · · t1vn+1

1−t1v1− · · · −t1vn+1

.

The forms νn+1 and γn+1 are given in (1.8). As before, we write νn+1 :=νn+1|t=0; γn:=γn+1|t=0. The differential formνn+1plays an interesting rôle in the computation of de

(13)

Rham cohomology of the complement of hyperplane configurations. LetAtbe the configuration in Pn of (n + 1) hyperplanes in general position with affine equation u0u1· · ·un= 0, u0+u1+· · ·+un=t= 0. ThenHn(Pn\ At) =H0(Pn,nPn(logAt))is a pure Tate structure generated by ν∆n+1. Now make t tend to 0 and consider the degenerate configurationA0

with affine equationu0u1· · ·un= 0,u0+u1+· · ·+un= 0. Exactness ofνn+1=n in the case (1.7) follows from Aomoto’s theory [1,4]. Due to the special shape of the configurations At considered, however, more is true. We have fixed , and the differential formγn lies in H0(Pn+1,n(log(A0+∞))(−∞)). That is, it has log poles along all components ofA0, and it vanishes as a differential form at(see Lemma 5.1). Thisk-vector space of differential forms is1-dimensional. In other words, the differential formγn is uniquely defined by the vanishing condition at and the secondary data n =νn+1 (see Remark 5.2). Do such primitives for more general degenerating configurations admit an interpretation identifying0-cycles with spaces of differential forms?

Here is another example of specialization and0-cycles. Define f(1, u1, u2) =u21−u32−au2−b;

v1=t3u1, v2=t2u2. (6.2)

One computes

ν= dv1∧dv2

v21−v32−at4v2−bt6; γ= 2v2dv13v1dv2

v12−v23−at4v2−bt6. (6.3)

One checks thatRes(γ|t=0) =v2/v1and

d(v2/v1) =−dv2/2 =dRes(ν|t=0) onv21−v23= 0.

(6.4)

The assignmentx→Trk(x)/k(v2/v1)(x)identifies the jacobian of the special fibrev12−v23= 0 withGa(k) =k.

A final example of specialization, which we understand less well, though it was an inspiration for this article, concerns the hyperbolic motives of Goncharov [6]. The matrix coefficients of his theory (in the sense of [2]) are the objectsH2n1(P2n1\Q, M\Q∩M). HereQ⊂P2n1 is a smooth quadric and M is a simplex (union of2n hyperplanes in general position). The subschemesQandM are taken in general position with respect to each other. The notation is intended to suggest a sort of abstract relative cohomology group. In de Rham cohomology, the non-trivial class inHDR2n1(P2n1\Q)is represented by

ω= du1∧ · · · ∧du2n1

(u21+· · ·+u22n11)n. (6.5)

Substitutingui=vit, we get

ω=t2n1dv1∧ · · · ∧dv2n1+t2n2dt∧

(−1)ividv1∧ · · ·dvi· · · ∧dv2n1

(t2(v12+· · ·+v2n2 1)1)n . (6.6)

We get

ν|t=0=±dv1∧ · · · ∧dv2n1

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