C OMPOSITIO M ATHEMATICA
J AMES A RTHUR
A trace formula for reductive groups. II : applications of a truncation operator
Compositio Mathematica, tome 40, n
o1 (1980), p. 87-121
<http://www.numdam.org/item?id=CM_1980__40_1_87_0>
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87
A TRACE FORMULA FOR REDUCTIVE GROUPS II:
APPLICATIONS OF A TRUNCATION OPERATOR
James Arthur*
@ 1980 Sijthoff & Noordhoff International Publishers - Alphen aan den Rijn Printed in the Netherlands
1. A truncation operator
... ’ 892. Integrability of k X (x, f )
... 983. The operator M J;( 1T)
... 1074.
Evaluation in a special case ...
1135. Conclusion ... 120
Introduction
This paper, as
promised
in the introduction to[1(c)],
contains anidentity
which is valid for any reductive group G over Q, and whichgeneralizes
theSelberg
trace formula foranisotropic
G. We havealready
shown that a certain sum of distributions onO(A)I,
indexedby équivalence
classes inG(Q), equals
theintégral
of the functionThe main task of this paper is to show that the
integral
may be takeninside the sum over x. There does not seem to be any easy way to do this. We are forced to
proceed indirectly by
firstdefining
andstudying
a truncation
operator AT
on functions onG(G)BG(A)’.
Recall that
k x T(X@ f)
was obtainedby modifying
the functionKx(x, x).
We shallapply
the results of § 1 to the function*Partially supported by NSF Grant MCS77-0918.
OOl0-437X/80/01/0087-36 $00.20/0
obtained from
Kx(x, y) by truncating
in each variableseparately,
andsetting x
= y. It will turn out that the functionis
integrable.
Then in§2,
our mainchapter,
we shall show that for Tsufficiently regular,
converges
absolutely.
We shall also show that for each X, theintegral
over
G(Q)BG(A)’ equals
0. If we setJ;(f) equal
tothe
identity
associated to G is thenWe should note that the distributions
J’
andIr
are not ingeneral
invariant. Moreover,
they depend
on a choice of maximal compactsubgroup
and minimalparabolic subgroup.
However, it should bepossible
tomodify
each of the distributions so thatthey
are invariantand
independent
of thesechoices,
and so that theidentity
still holds.We
hope
to do this in a future paper.Both formulas for
J X ( f )
arelikely
to be useful. Theintegral
on theright
isparticularly
suited toevaluating Ir
on the function obtainedby subtracting f
from aconjugate
of itselfby
agiven
element inO(A)I.
It can also be used to showthat Ir (f)
is apolynomial
functionin T. We shall not discuss these
questions
here. On the otherhand,
theintégral
on the left can be calculatedexplicitly
if theclass X
isunramified. We do this in §4. The result follows from a
formula,
announcedby Langlands
in[4(a)],
for the innerproduct
of twotruncated Eisenstein series. It was
by examining Langlands’
methodfor
truncating
Eisenstein series that 1 was led to the definition of the operatorA T.
1. A truncation
operator
Let G be a reductive
algebraic
group defined over 0. Weadopt
thedefinitions and notation of
[I(c)].
Inparticular,
K is a maximal compactsubgroup
ofG(A)
andPo
is a fixed minimalparabolic subgroup
of G defined over 0.Again
we shall use the term’parabolic subgroup’
for aparabolic subgroup
P ofG,
defined over Q, which contains Po. We would like to prove that the terms on theright
handside of the
identity given
inProposition
5.3 of[1(c)]
areintegrable
functions of x. To this
end,
we shall introduce a truncation operator for functions onG(Q)BG(A)’.
Recall that T is a
fixed, suitably regular point
ina 0 ’. If 0
is acontinuous function on
0(0)B0(#B)1,
define(A Tf»(X)
to be the func-tion
(the
sum over P is of course over allparabolic subgroups.)
Note thesimilarity
with our definitions of the functions kr (x, f )
andk; (x, f)
in[1(c)]. If 0
is a cuspform, A Tc/J = c/J.
It is a consequence of[1(c), Corollary 5.2]
that if0(x)
isslowly increasing,
in the sense thatfor some C and N, then so is LEMMA 1.1: Fix PI. Then
for
unless
PROOF: For any
P,
letn(4o; P)
be the set of sEn such thats-la >0
for each aEi!Õ. Applying
the Bruhatdecomposition
toP(Q)BG(Q),
we find thatfNt(Q)BNt(A) A Tq,(nlx) dnl equals
the sum overP and s E
f2(ao; P)
of theintegral
over n inN(Q)BN(A)
of theproduct
of(-l)dim(Alz)
withSince
N,(G)BN,(A)
=No(Q)BNÕ(Q)NI(A),
this lastexpression equals
Decompose
This induces a
decomposition
of the measuredn
1 asdn* dn*.
Thenwrite
and
finally,
combine theintegral
overfi *
with theintegral
over n inN(Q)BN( 11B).
Because s lies in!J(40; P), No
flwsNlws n
M is theunipotent
radical of a standardparabolic subgroup
of M. It followsthat
is the
unipotent
radical of auniquely
determinedparabolic subgroup P,
ofG,
which is contained in P. We have shown thatf N I(O)BN I(A) ( (n lx)
dn 1equals
We shall
change
the order ofsummation,
and consider the set of P whichgive
rise to a fixedP,.
Fix s E f2. DefineSI (resp. Sl)
to be theset of a
eào
such thats-Ia
is apositive
root which isorthogonal (resp.
notorthogonal)
to a i. IfP,
is one of the groups that appear in the aboveformula, à 0 -’
will be a subset ofSI.
Those P whichgive
riseto a fixed
P,
areexactly
the groups for which4 ô
is the union of2lg
and a subset S ofSi. Thus,
for fixed s withàj
CS’,
we will obtain analternating
sum overSCSI
of thecorresponding
functionsTp.
Weapply Proposition
1.1 of[ 1(c)]. Let XS
be the characteristic function of the set ofH E 40
such that fora OEào -,à-’ 0 U Si, w«(H)
>0,
whilew,,,, (H) --5
0 for a inSi.
Here 1170 is the element injo corresponding
toa. Then
fN1(Q)BN1(A) ((nix)
dn1 is
sum over s E f2 and over all subsets4 ô
of
S’,
of theintegral
over n* inW;I No(A)ws nN((Q)Ni(A)) NA(O)NI(A)
and n inNs(Q)BNs(A)
of theproduct
ofwith -1 raised to a power
equal
to the number of roots inào - SI
USi.
Suppose
that for some s,Xs(Ho( wsn * v) - T)
does not vanish. Then ifta is
positive
for a inao - dô
USI,
and is notpositive
for a ESi.
If10’ E j¡,
where s-’a
isorthogonal
toa’
if a ES’.
This last number isclearly
less than or
equal
to 0. Nowfor some element v
OENo(A).
Ifw EEjo,
it is well known that111
(s-’Ho(wsvws’)
isnonnegative
and w(T - s-’ T)
isstrictly positive.
Therefore 111 (Ho(x) - T )
isnegative
for any w EÂi.
0From the definition of
A T
we obtainLEMMA 1.3:
Suppose
that(i
andcf>2
are continuousfunctions
on0(0)B0(1B)1.
Assume that(i
1 isslowly increasing,
and thatcf>2
israpidly decreasing,
in the sense thatfor
anyN,
thefunction
IlxilN . )(2(x))
is bounded on anySiegel
set. ThenPROOF: The inner
product (A TCPI, cp2)
is definedby
anabsolutely
convergentintegral.
Itequals
This last
expression
reduces toREMARK: It can be shown that
A T
extends to anorthogonal projection
onL2(G(Q)BG(A)I).
We would like to show that under suitable
conditions, A Tep (x)
israpidly decreasing
atinfinity.
The argumentbegins
the same way as theproofs
of Theorems 7.1 and 8.1 of[1(c)]. Suppose 0
is a con-tinuous function on
G(Q)BG(#B)I. Apply
Lemma 6.4 as in thebegin- ning
of theproof
of Theorem 7.1 of[1(c)].
We find thatA To (x)
is thesum over
{PI,
P2:Po
CPI
CP21
and 5 EPI(Q)BG(Q),
ofwhere
For the moment, fix 8 and x. We
regard
8 as an element in0(0)
which we are f ree to left
multiply by
an element inPl(O).
We cantherefore assume, as in
[1(c), §7]
thatwhere
k E K, n*,
n *, and mbelong
to fixedcompact
subsets ofN2(A), N2(A)
andMI(A)L respectively,
and a is an élément inAI(R)D
with
o-’(HO(a) - T) 0
0. Thereforewhere c
belongs
to a fixed compact subset ofG(A)’
whichdepends only
on G.The function
cPPloP2
resembles the function estimated in the corol-lary
of[3,
Lemma10].
We want aslightly
different statement of theestimate, however,
so we had best re-examine theproof.
If aE LiT,
letp«, Pi
C p« CP2,
be theparabolic subgroup
such thatA’î = à g
is thecomplement
of a inLlT.
For each a,let (Y«,i, ..., Ya,na}
be a basis ofnâ(Q),
the Liealgebra
ofN 2(a).
We shall assume that the basis iscompatible
with the action ofA i,
so that eachY«,;
is a root vectorcorresponding
to the root/3a,i
of(M2 n Pl, AI).
We shall also assumethat if i
j,
theheight
of/3a,i
is not less than theheight
offl«,j.
Define na,j,0 j n«
to be the direct sum of{Ya,h..., Y,,,jl
with the Liealgebra
ofN2,
and letNa,j
= exp na,j. ThenN«,;
is a normalsubgroup
of
Ni
which is defined over 0. If V is anysubgroup
ofNI,
definedover
Q,
letir(V)
be the operator whichsends 0
toThen
Op,,p2
is the transformof 0 by
theproduct
over aE L1 Î
1 of the operatorsIf Ko is an open compact
subgroup
ofG(Aj), G(Q)BG(A)IIKo
isdiff erentiable manifold. We assume from now on
that 0
is a functionon this space which is differentiable of
sufficiently high
order.Sup-
pose that 1 is a collection of indices
Then
and
are normal
subgroups
of Ni. Letn’
be the span of{Ya,ia}
and letn’(Q)’
be the set of elementsThen if n is any
positive integer,
is a nonzero real number.
By
the Fourier inversion formula for the groupA/a, cf>Pl.Pl(Y)
is the sum over all I ofHere e
and Vi
are as in[1(c), §7] and ( ,)
is the innerproduct
definedby
our basis onnj.
If n is apositive integer,
can be
regarded
as an element inOU(g(R)1 @ C).
Thent!>Pt,P2(Y) equals
the sum over I and
over e
En,(G)’
ofNow,
we setas above.
Since uy(Ho(a) - T) #= 0,
abelongs
to a fixedSiegel
set inM2(/A).
It follows that theintegrand
in(1.1),
as a function ofX,
is invariantby
an opencompact subgroup
ofn/(/A,)
which is in-dependent
of a and c.Consequently, (1.1)
vanishesunless e belongs
to a fixed
lattice, LI (Ko),
innI (R).
But for nsufficiently large
is finite for all I. Let
cn(Ko)
be the supremum over all I of these numbers. Thenlq,pt>piac)1
is boundedby
Let
/31
= E«/3a,ia.
Then/31
is apositive
sum of rootsin a i.
For any n,We can choose a finite set of elements
{Xi}
inIM(g(R)’(& C), depend- ing only
on n andKo,
such that for anyPi, P2, I
and c,is a linear combination of
fxij.
Since c lies in acompact
set, we mayassume that each of the coefficients has absolute value less than 1.
We have thus far shown that
lA TcP(x)1
is boundedby
the sum over allPi, P2
and 8 EPI(O)BG(O)
of theproduct
ofwith
LEMMA 1.4: Let 6 be a
Siegel
set inG(A)I.
For anypair of positive integers
N’ andN,
and any open compactsubgroup Ko of G(At),
wecan choose a
finite
subset(X;) of OU(g(R)’(D C)
and apositive integer
r which
satisfy
thefollowing
property:Suppose
that(S, do)
is ameasure space and that
r#(a, x)
is a measurablefunction from
S tocr(G(O)BG(A)l/Ko).
Thenfor
any x E6,
is bounded
by
PROOF: Substitute
cf>(u) for 0
in(1.2)
andintegrate
over a. Theresult is
If Sx = ac, with a and c as
above,
We are
assuming
thatuT(Ho(a) - T) 0
0.Since 131
is apositive
sum ofroots
inài
we conclude from[1(c), Corollary 6.2]
thatIlall
is boundedby
a fixed power ofIt f ollows that for any
positive integers
N andNi
we may choose nso that
(1.3)
is boundedby
a constantmultiple
ofIt is well known
(see [2])
that there is a constant ci such that for anyy E
G(Q)
and xE 6,
The
only thing
left to estimate isThe summand is the characteristic
function,
evaluated at8x,
of a certain subset ofThe sum is bounded
by
It f ollows from
[1(c),
Lemma5.1]
that we can find constantsC2
andN2
such that for allPi
this lastexpression
is boundedby C211x1lN2.
SetNi
= N’ +N2. Ni
dictates our choice of n, from which we obtain the differential operatorslxil.
The theorem follows with any r greater than all thedegrees
of the operatorsXi.
0In the next section we will need to have
analogues
of the operatorsA T
for differentparabolic subgroups
of G. IfPI
is aparabolic subgroup, and 0
is a continuous function onPI(O)BG(A)’,
defineLEMMA 1.5 :
Suppose
that P is aparabolic subgroup and 0
is acontinuous
function
onP(Q)BG(A)I.
Thenequals
PROOF: We need to prove that
(1.4)
is the sum over and 8 ER(O)BP(G)
of theproduct
ofwith
Consider Lemma 6.3 of
[ 1 (c)],
with A apoint in -(at)+.
The sumgiven
in that lemma then reduces to(1.5).
It follows from[l(c), Prop.
1.1]
that(1.5)
vanishes if R # P andequals
1 if R = P. This establishesLemma 1.5. D
2.
Integrability
ofk f (x, f)
We take r to be a
sufficiently large integer,
and continue to let T bea
suitably regular point
inat.
In[1(c)]
we associated to everylE Cr c(G(A)’)
afunction, kf(x,f),
onG(Q)BG(A)’.
THEOREM 2.1: For
sufficiently regular T,
is
finite.
We will not prove the theorem
directly. Rather,
we shall relatek;(x, f)
to the truncation operators whoseasymptotic properties
wehave
just
studied. We shall operate onKp.x(x, y),
which of course is a function of two variables. If Pi CP2,
we shall writeT’PI (resp. A 2’Pl)
forthe operator A
T,PI, acting
on the first(resp. second)
variable.PROOF: The
given expression
is the sum over all chainsPl
C P CP2
CP3
and over 5 EPI(G)BG(G),
ofAs we have done many
times,
weappeal
to[l(c), Prop. 1.1].
We see that the sum overP2 equals
0 unless P =P3.
Therefore thegiven
expression equals
Apply
Lemma 1.5 to the sum overPi.
We obtainSince
this last
expression equals kI(x, f),
asrequired.
0Fix Pl C P2. Motivated
by
the lastlemma,
we shall examine theexpression
It
equals
Let
F(Pl, P2)
be the set of elements inPl(o)BP2(0)
which do notbelong
toPi(0)BP(Q)
for anyP,
withPl
C PCP2. By [I(c), Prop. 1.1]
the above
expression equals
In this last formula we have affected the cancellation
implicit
in thealternating
sum over P. In order toexploit
theequation
we havejust derived,
weinterrupt
with a lemma.LEMMA 2.3:
Suppose
thatfor
eachi,
1 sis n, we aregiven
aparabolic subgroup Qi D Pl, points
xi, Yi EG(A)
and a number ci such thatvanishes
for
all m EMI(Q)BM,(A)’.
Then for any X E#,
also vanishes
for
all m EMI(G)BM,(A)’.
PROOF:
Suppose
that for agiven X’ E #,
there is a group R inPx’
which is contained in
Pl.
We would like to prove that for any function4>x’
EL2(MR(Q)BMR(IA.)I)x"
theintegral
vanishes for
X# X’. Suppose
thatX# X’,
andthat 0
EYeQ(ir),
forsome
Q
cQi,
and some 7T EII(MQ).
The construction of Eisenstein series is such that if the functionis substituted for
hx
in(2.1),
the result is 0. It follows from the estimates of[1(c), §4]
that(2.1)
itself is 0. The same estimatesyield
constants c and N such that
By assumption, 1,, hx(m) equals
0.Consequently (2.1)
is zero evenwhen X = X’.
Thefunction hx
is continuous. Because(2.1)
vanishes for all0,,,, h,,
satisfies thehypotheses
of[4(b),
Lemma3.7]. hx
istherefore zero. D
To return to the
proof
of thetheorem,
we look for conditionsimposed
on x, y and yby
thenonvanishing
ofSet
There is a
compact
subset ofG(A)’, depending only
on thesupport
off,
which contains somepoint
whenever
(2.2)
does not vanish. Fix w eâ
1 and let A be a rationalrepresentation
of G withhighest weight dw,
d > 0. Choose aheight
function )) [[
as in[I(c), §1].
If v is ahighest weight
vector, we can choose a constant ci such thatwhenever
x-tynrmYl
lies in thegiven
compact subset ofG(/A)I.
Thelef t side of this
inequality equals
which is no less than a constant
multiple
ofIn other
words, 0153(Ho(yx)-Ho(Y»
is no less than a fixed constant. Itfollows from this observation that we may choose a
point To E
ao,depending only
on the support off,
such thatwhenever
(2.2)
does not vanishidentically
in m. We conclude from Lemma 2.3 that if(2.3)
fails to hold for agiven
x, y and y, thenvanishes for
all x
and m.Combining [l(c),
Lemma5.1]
with what we havejust shown,
we conclude that for fixed x and y,vanishes unless y
belongs
to a finite subset ofF(Pi, P2), independent
of X. Theref ore the sums in
are finite. Since the
expression
vanishes for all m inMI(Q)BM,(A)’,
we can
apply
Lemma 2.3. We obtain anequality
of functions of y foreach X.
We arecertainly
atliberty
toapply
our truncation operator to those functions. It follows that forany X E ae,
equals
We have thus far shown that
is bounded
by
the sum overLet 6 be a fixed
Siegel
set inMI(A)’
withMI(Q)6
=M1(A)I,
and let rbe a compact subset of
Ni(A)
withNI(Q)r
=N1(A).
Then the lastintegral
is boundedby
theintegral
over n EF,
m E 6 rlPo(A), a
EA1(R)0
rlG(A)I,
and kE K,
ofSuppose
that f or n, m, a and k asabove,
and f or somey E
F(PI, P2)
and X Ef,
Write l’ = VWs1T, for
v G NÉ(Q), TT E Po(Q)
ands E nM2,
theWeyl
group of
(M2, Ao).
It follows from Lemma 2.3 that there is a fixedcompact
subset of0(1B)1
which containsfor
points
ni ENo(A)
and pi EMI(/A)INI(/A).
Fix w EA,
and let ll andv be as above.
A(ws)v
is aweight
vector, withweight
sw. The vectorcan be written as a sum of
weight
vectors, withweights higher
thanS’m.
By
the construction of ourheight function,
It f ollows that there are constants c’ and c,
depending only
on the support off,
such thatSince s fixes d2
pointwise,
theinequality
holds for the
projection
of 1IJ ontoai.
In otherwords,
we may take to be an element inâ i.
For each such w, m - s w is anonnegative integral
sum of roots inL1i.
We claim that the coefficient of the element a inà’,
suchthat w =
is not zero. Otherwise we would have(w -
s w)(w ’)
=0,
orequivalently,
S1I7 = w . This would f orce s tobelong
to12",-
for someparabolic subgroup P,
Pl C PGP2.
Thiscontradicts the
assumption
that y = VWs1Tbelongs
toF(PI, P2),
so the coefficient of a is indeedpositive.
We can assume that a has the additional property thatIt follows from
Corollary
6.2 of[1(c)]
that for any Euclidean norm1111
on ao there is a constant c such thatWe have shown that if a E
AI(R),
nG(A)l
is such that for some X, y,n,m,mandk,
does not
vanish,
then theinequality (2.5)
holds.Suppose
thatf
isright
invariant under an open compactsubgroup
Ko
ofG(Af).
Then ifIpl( TT, f)o 0
0 for some TTand 0
E9ÃPl( 1T)x,
thefunction
E(y, 0)
isright Ko-invariant
in y. Theref ore for any x, y and X,Kplox( ;’x, y)
isright Ko-invariant
in y. It follows that(2.6)
isright
invariant in m under the open compact
subgroup
of
M1CA.f)l.
Weapply
Lemma 1.4 with the group Greplaced by MI.
For any
positive integers Nl
andNI
we can choose a finite set{A,}
ofelements
in OU(ml(R)’(& C),
the universalenveloping algebra
of thecomplexification
of the Liealgebra
ofMl(R)l,
such that for all n Er,
is bounded
by
We can choose éléments
{Yj}
inôh(g(R)’(D C)
such thatwhere
Cij(k)
are continuous functions on K. Recall thatKp,,"(x, y)
isultimately
defined in terms off.
The functionR,(Yj)Kpl’X(X, y)
isdefined the same way, but with
f replaced by f * f 4’.
The support off * F*
is contained in the support off,
so we can assume that(2.3)
isvalid whenever
R,( Yi)Kpl’X( l’X, y)
does not vanish.By Corollary
4.6 of[l(c)],
is bounded
by
a constantmultiple
of a power ofllxll - M.
It followsfrom
Corollary
5.2 of[l(c)]
that theexpression
is also bounded
by
a constantmultiple
of a power ofllxll - Ilyll. By taking Ni
to belarge enough
we obtain constantsCz
andN2
such(2.8),
and therefore(2.7),
is boundedby
Set m = m in
(2.7). Integrate
theresulting expression
over n Er,
m E 6 fl
Po(A),
k E K and a in the subset of elements inAI(R)o
nG(A)’
whichsatisfy (2.5).
There are constantsC3
and N3 such that the result is boundedby
If we set
Ni
=N3,
this is finite. Theproof
of Theorem 2.1 iscomplete.
Il LEMMA 2.4: For T
sufficiently regular,
and rsufficiently large,
for
allf
ECr(G(A)’)
and X E X.PROOF: It follows from the
proof
of Theorem 2.1 that theintegral
of
k x ’(x, f)
is the sum over allPl C P2
of theproduct
of(-1)dim(A2/Z)
with
As a double
integral
over x and y this convergesabsolutely.
IfPt
=P2 gé G,
theintegrand
is zero. IfPt
=P2
=G,
the result is theintegral
ofAIKx(x, x).
We haveonly
to show that ifPI CP2,
theresult is zero. Let
n(PI, P2)
be the set of elements s infl’°2
such thatsa and
s -’a
arepositive
roots for each aeà 0 and
such that s does notbelong
to any!JM,
withPICP CP2.
Then the aboveintegral equals
the sum over all s E!1(Pt, P2)
ofSince
for any y E
PI(O),
thisequals
If s E
Q(Pi, P2), W;lpows
nMI
is the standard minimalparabolic subgroup
ofMI,
sinces-la
> 0 for ae A 1.
Theref oreMi
nW;lplws equals mi
nPs,
for aunique parabolic subgroup Ps
ofG,
withPo
CPs C Pl.
Write theintegral
in(2.9)
as a doubleintegral
overMs(Q)Ns(/A)BG(/A)1 x (pi(o)
nw;IPt(Q)ws)BMs(Q)Ns(/A).
PI nws’Plws
is the semi-direct
product
ofmi
nW;IpIWs
and Ni nws’P1 ws, and MI n W;lplws decomposes
further as the semidirectproduct
of
Ms(G)
andNS(Q). Therefore, (2.9) equals
theintegral
over x inMs(O)Ns(A)BG(A)’
of theproduct
ofU1(Ho(x) - T)
andThis last
expression equals
We
apply
Lemma 1.1 to theparabolic subgroup mi
nP,
ofMI.
Then thisexpression
vanishes unless w(Ho(x) - T)
isnegative
for eachw Ej’.
On the otherhand,
we can assume that(2.3) holds,
with y, x,and y
replaced by
ws, nix, and nxrespectively.
In otherwords,
for
each 117 E j 1.
But it is well known thatso there is a constant
C, depending only
on thesupport
off,
such thatfor every w in
’&1.
These two conditions onHo(x),
werepeat,
are based on theassumption
that(2.10)
does not vanish. We obtain a thirdcondition
by demanding
thatUT(Ho(x) - T)
not vanish. We shall show that these three conditions areincompatible
if T issufficiently regular.
We write the
projection
ofHo(x) -
T ona i
asThe first and third conditions on
Hc(x)
translate to thepositivity
of eachca and c,. Now the Levi component of P,
equals Ml f1 ws’M, ws.
Therefore S4ô is
orthogonal
to a i. Then forwo E j 1,
equals
Now 111 v - S1I1 v is a
nonnegative
sum of co-roots, so the sum over w isnonnegative.
Moreover we canreplace
each a in the sumover d by
the
corresponding
root inAo’BAs.
Since s maps the roots in this latter set topositive
roots, the sum over a is alsononnegative. Finally,
forany wo,
1I10(T - sT)
can be madearbitrarily large
for Tsufficiently regular.
We thus contradict the second condition onHo(x).
Therefore(2.10)
isalways
zero so theintegral
ofk[(x,f) equals
that ofll
2 TK,(x, x).
DFor any x E
ài,
setIn this section we shall
give
anotherformula,
which reveals adifférent set of
properties
of thedistributions j x T.
We shall build onLemma
2.4,
which is apartial
step in this direction.Fix
P,
1T’ Ell(M) and X
E X.Suppose
that A is a linear operator onWp(w)
under which one of the spacesXp(ir),, YP(Ir),,K,,
orgep(ir),K,,w
is invariant. HereKo
is an open compactsubgroup
ofG(Af)
and W is anequivalence
class of irreduciblerepresentations
of KR. We shall writeAX, AX,KO
orAx,Ko,w
for the restriction of A to thesubspace
inquestion.
Suppose
that 6 is aSiegel
set inG(IA.)I.
It is a consequence of Lemma 1.4 and[1(c), (3.1)]
thatgiven
anyinteger
N’ and a vectorcp
EYo p (ir),,
we can choose alocally
bounded functionc(C)
on the setof C
Ea*,c
at whichE(x, cp,)
isregular,
such thatfor all x e 6. It follows that for
0, 41
EYe’p(ir),,
theintegrals
and
converge
absolutely,
and definemeromorphic
functions in(£, Ti)
which are
regular
whenever theintegrands
are.By Corollary
1.2 andLemma 1.3 these
meromorphic
functions areequal.
Thus we obtain alinear operator
M 5(w)
onX’(ir) by defining
for every
pair 4>1
and4>2
inW$(w). M 5(w) dépends only
on the orbitof 1T in
nG(M).
It is clear thatMp(1T)x
isself-adjoint
andpositive
definite. Notice also that
for all k E K. It f ollows that for any Ko and
W, Mp(7T)x
leave s the finite dimensional spaceXP(Ir),,K,,,W
invariant.Recall that in the
proof
of Lemma 4.1 of[1(c)],
we fixed anelliptic
element à in’*(g(R)’(D C)KR.
For anyKo
andW, Yep(ir),K,,w
is aninvariant
subspace
for the operatorIp(7T, à ).
Choose à so that for anyX, ir, W
andKo,
such thatXp(ir),Ko,w 0 JOI, Ip(ir,,à),K,,,w
is theproduct
of theidentity
operator with a real number which islarger
than 1. For
example,
we could take à toequal
1+ A *,à 1, where A 1 is
a suitable linear combination of the Casimir elements forG(R)’
and KR.If A is any operator on a Hilbert space,
IIAlh
denotes the trace classnorm of A.
THEOREM 3.1: There is a
positive integer
n such thatfor
any open compactsubgroup
Koof G(Af),
is
finite.
Assume the
proof
of the theorem for the moment andtake ri
=deg a". Suppose
thatf
is a function inC§i(G(A)),
which is bi- invariant under Ko. ThenFor any 7T the norm of the operator
Ip(7T,i1n * f )
is boundedby
Thus,
Theorem 3.1implies
that for everyis
finite,
and in fact defines a continuous seminorm onC§i(G(A)).
Inparticular,
the operatorM5(w) . Ip( 7T, f)x
is of trace class for almost aIl 7T.THEOREM 3.2: There is an r a ri such that
f or
an y X and an yWe shall prove the two theorems
together,
Let N and ro be thepositive integers
of Lemma 4.4 in[1(c)].
Choose an opencompact subgroup, Ko,
ofG(Af)
and aSiegel
set d inG(/A)I. According
toLemma 1.4 and the lemma
just quoted
from[1(c)],
we may choose afinite set
1 Yil
of elements inOU(g(R)1 Q9 C)
such that for x EG(A)I,
and
f
a K-finite function inis bounded
by
When we set x = y and
integrate
the aboveexpression
overGG)BG(A)’,
the result is boundedby
Suppose w = ( W,, W2)
is apair
ofequivalence
classes of irreduciblerepresentations
ofKR.
We defined the functionin §4 of
[ 1(c)].
We also defined thepositive integer eo.
LetAs we saw in §4 of
[1(c)],
is a continuous seminorm on
C2(G(A)’).
We have shown thatis bounded
by IIfIJ"2’
for everyf
EC?(G(A)’).
Let r
by
anyinteger larger
than r2 f or which Lemma 2.4 is valid.Then if
f
EC§(G(A)), and X
isfixed,
by
Tonelli’s theorem. The operatorAT
is defined in terms of sumsand
integrals
over compact sets. If we combine Tonelli’s theorem with the estimates of[1(c), §41
we find that we can takeAT
outside the sums over0,
P and W, and theintegral
over ir. The result iswhich
by
Lemma 2.4equals J;(f).
Theproof
of Theorem 3.2 will nowf ollow from Theorem 3.1 if we take r to be
larger
than ri.The
only remaining thing
to prove is Theorem 3.1. We shall useLemma 4.1 of
[ 1(c)].
We canchoose n,
and functionsg’
eC?(G(A)’)
and
gR
EC§f(G(A )l’
such that J n *gR
+gR
is the Dirac distribution at 1 inG(R)I.
If 1 =1, 2,
setwhere
chKo
is the characteristic function ofKo.
ThenSuppose
that W is an irreducibleKR-type
and that w =( W, W).
Then the trace of the restriction ofM’(ir), - Ip(ir,,à")-l
toJ(ep(ir),K,,,w
isSince the
eigenvalues
ofIp(ir,,à’)
are alllarger
than1,
this lastexpression
is boundedby
Now the trace class norm of the operator
is the sum of the traces of its restriction to each of the
subspaces 7lep( TT)x,Ko,W.
Thereforeis bounded
by
the sum over i =1, 2
ofThis in turn is bounded
by
which is
just (3.2)
withf replaced by
gi. Theorem3.1,
as well asTheorem
3.2,
is nowproved.
04. Evaluation in a
spécial
caseIn this section we shall
give
anexplicit
formula forJ;(f)
for aparticular
kind ofclass X
E ae. Thesespecial X
we will callunramified;
they
areanalogues
of the unramified classes o e 0 for which we wereable to calculate
J’(f)
in[1(c), §81.
The formula forJ;(f)
is aconsequence of an inner
product
formula ofLanglands
which wasannounced in
[4(a), §9].
Most of this section will be taken up with theproof, essentially
that ofLanglands,
for the formula.First, however,
we must demonstrate a connection between the truncation operator
A T
and the modified Eisenstein series definedby Langlands
in[4(a)].
Fix a
parabolic subgroup
Pi and arepresentation
TT EII(Mi).
Ifcf> E Xop,(lr) and C
E ate,
writeIf s E
f2(al, a2),
defineM(s,
11’,C)
=M(s, C) by
M(s, C)
mapsYp,(ir)
toW’p,(sir). Suppose that XE ae
is such that Pi EP,,.
Then forall X
EG(A)’,
is a cusp form in m. If
P2
is a second group in9Jx’
we have thefollowing
basic formula from thetheory
of Eisenstein series:A formula like this exists if
P2
isreplaced by
anarbitrary (standard) parabolic subgroup,
P. Recall that12(al; P)
is defined to be the unionover all a2 of those elements s E
f2(al, a2)
such that s a i = a2 contains a, ands-la
ispositive
for each aE 42 .
Then we haveThe verification of this formula is a
simple
exercise which we canleave to the reader. It can be
proved directly
from the series definitionof
E(x, cf>, £). Alternatively,
one can prove itby
induction on dimA, applying [4(b),
Lemma3.7]
to the group MLEMMA 4.1:
Suppose
thatPi E P/Jx
asabove, that cf>
E>%$(w)
andthat C is a point in a te
whose realpart CR
lies inpi + (aÎ)+.
ThenA
TE(x, cf>, £) equals
with the sum over 8
converging absolutely. (The functions
E2 and1>2
are as
[I(c), §8].)
PROOF:
Suppose
thatP2
and s ESlÎ(a i, a2)
aregiven.
In the processof
verifying
theequality
of(8.5)
and(8.6)
in[1(c)],
we ended upproving
that for all H E ao,was
equal
toApply
this to(4.2).
Thendecompose
the sum overP2(O)BG(O)
into asum over
P2(0)BP(G)
andP(Q)BG(O).
The sum overP(Q))G(Q)
willbe finite
by [l(c),
Lemma5. 1].
If aEEàp, s-’a’
is anonnegative
sumof éléments of the form
8’, for,6 E dl.
It follows thatis
positive.
Therefore the sumis
absolutely
convergent, and in factequal
toEp(8x, M(s, C)O, sC).
Inparticular,
theoriginal
sum over 5 in(4.2)
isabsolutely
convergent.We find that
(4.2) equals
If the left hand side of
(4.1)
is substituted into thebrackets,
the resultis ll
TE(x, 0, l).
DTo
simplify
thenotation,
we shall assume thatTT(a)
is theidentity
operator for all a EAI(R)I.
This entails no loss ofgenerality,
sinceany 1T1 E
II(Ml) equals
TTl1’ for some such ir and some q Eia*.
GivenP2,
defineIf define
for x E
G(A)’.
This function is not hard to compute. We haveonly
toevaluate
Since
a ---> H2(ax)
is a measurepreserving diffeomorphism
fromA2(R)°
nG(A)’
ontoaG@
this lastexpression equals
Make a further
change
of variablesOf course, we will have to
multiply by
the Jacobian of thischange
ofmeasure. It is the volume of