R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
B. G OLDSMITH
Essentially indecomposable modules over a complete discrete valuation ring
Rendiconti del Seminario Matematico della Università di Padova, tome 70 (1983), p. 21-29
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Essentially Indecomposable
a
Complete Discrete Valuation Ring.
B.
GOLDSMITH (*)
1. Introduction.
Torsion-free modules over a
complete
discrete valuationring
Rare
markedly
different from abelian groups or modules over an in-complete
discrete valuationring
in that theonly indecomposable
modules which exist have rank 1 and so areisomorphic
to R itselfor the
field, Q,
of fractions of 1~([7],
p.45).
In this paper we inves-tigate
how close a reduced torsion-free R-module of infinite rank can come tobeing indecomposable.
Inparticular
we establishin §
4 theexistence of
essentially indecomposable
modules with basic submodules of countable rank. The results here bear astrong
resemblance to results on p-groups([2], [5], [9]
and[10]).
Notation follows the stand- ard works of Fuchs[3], [4]
while set-theoreticconcepts,
y which arekept
to aminimum,
may be found in Jech[6].
2. Maximal pure submodules.
Let .R denote a
complete
discrete valuationring
ofcardinality v
with
unique prime
p. For an infinite cardinal ~ we let S;.(or just S
if no
ambiguity
ispossible)
denote a free .R-module of rank A. Cle-arly
SA is notcomplete
in thep-adic topology
and we denote itscompletion by 8a (or just ~) .
(*) Indirizzo dell’A.: Dublin Institute of
Technology,
Dublin 8, Irelandand Dublin Institute for Advanced Studies, Dublin 4, Ireland.
22
DEFINITION. A R-module X is said to be a maximal pure sub- module of the
complete
R-module~§
if X is a pure submodule of~S containing S
and the field of fractions of I~. We remark that if X is a maximal pure submoduleof S
then for any x e8%X,
we have
~S’
==X, .x~* .
LEMMA 2.1. If G and X are pure submodules of
S containing
then if and
only
if there is anautomorphism
6 ofS
with GO = K.PROOF. The
sufficiency
isclear,
we establishnecessity . Let q
bean
isomorphism
from G onto K.Then o
extendsuniquely
to an endo-morphism §3
of~S. Similarly if y
is the inverse of q, it extends to anendomorphism y
of8.
However since G and IT are dense subsets of the Hausdorffspace S,
it followseasily
that§3§J
and§J§3
act as theidentity
on8.
Thus 0= ~
is therequired automorphism.
Before
examining
theendomorphism rings
of maximal pure sub- modulesof Ag,
we introduce theconcept
of an inessentialendomorphism
(cf. [5]).
Let X be a pure submodule ofS containing S, then,
as wenoted in the
proof
of Lemma2.1,
anyendomorphism 99
of X has aunique extension ~
to anendomorphism
of/§.
We define an endo-morphism
of X to be inessential if itsunique
extension to~S’
maps ~S into X. It iseasily
seen that the difference of two inessential endo-morphisms
is inessential while thecomposition
of tw oendomorphisms
is inessential when either factor is inessential. Thus the inessential
endomorphisms
of X form a two-sided ideal in theendomorphism ring E(X)
of X.THEOREM 2.2. For any infinite
cardinal A,
there exists an R-moduleG,
with basic submodule ofrank h,
such thatE(G)
is thering split
extension of R
by I(G),
PROOF. Let S be a free R-module of rank A and let G be any maximal pure submodule of
S. Clearly S
is basic in G. We mayidentify E(G)
as asubring
ofE(8) by identifying
eachendomorphism P
in
E(G)
with itsunique extension P
inE(S).
With this identificationI(G)
is a left ideal of.E(~).
Pick x E Then for
arbitrary T
inE(G)
we must haveq(x’) -
- tx
+
g, someq, t
ER, g
E G. Since every element of .R is aproduct
of a power of p and a
unit,
there is no loss ingenerality
insupposing
q =
pr, t
= ps. We consider two cases:In this case
pr(z§3 -
= g. Thepurity
of Gin 9 implies
thatps-r1 ) belongs
to G. Since G is invariantps-rl
andG, x~* _ 8,
it is clear that -p s-r 1 )
is contained in G. ThusI(G)
and soE( G) _ .R + I(G).
We show that this case cannot arise. As before we can show that
E G and deduce that
pr-S§3
-1 EI (G) . Suppose pr-S§3 -
-1 =
0,
where 0 EI(G).
Since r > s,belongs
to the Jacobson radical of(see [8])
and this forces 0 to be a unit inE(8).
How-ever since G is
certainly
not ahomomorphic image
of9, I(G)
is aproper left ideal of which contains a unit-contradiction. So
case
(ii)
does not arise.Since G is pure
in 8,
R nI (G)
= 0 andqua’ modules, .E(G) _ .R ~+
However this is
clearly
aring split
extension also and we have established the result.3.
Essentially-rigid systems
of R-modules.As we noted in the introduction
indecomposable
.R-modules have rank 1 whereasindecomposable
abelian groups ofarbitrary large
rankexist
[11].
One useful tool in theinvestigation
ofindecomposable
abelian groups was the
concept
of arigid system
of groups(see [4],
§ 88).
In this section we define andexplore
ananalagous concept
for R-modules.We extend the
concept
of inessential tohomomorphisms
betweendifferent reduced torsion-free R-modules
by defining
===
where P
denotes theunique
extensionof 99
to a0l;.
DEFINITION. A
family (j
EJ)
of reduced torsion-free R-modules is said to beessentially rigid
iffor all
i, j
E J.24
Suppose throughout
this section that 1~ is acomplete
discretevaluation
ring
ofcardinality v
and h is an infinite cardinalsatisfying
p = ~,~° = 21 and For an infinite cardinal (1, let (1+ denote the
successor of or. We can now state the main result of this section.
THEOREM 3.1. If 2 is an infinite cardinal with the
property
thatp =
Amo = 21
and R is acomplete
discrete valuationring
ofcardinality
then there exists an
essentially-rigid family
of R-moduleshaving p+
members.REMARK.
(i) By assuming
G.C.H. we may, of coursereplace ft+
by
2 ~.(ii)
Cardinals of the form 2 do exist for values of 2 other than A -~o
e.g.assuming G.C.H.,
any cardinal ofcofinality
~o will do.
LEMMA 3.2. Let V be a vector space of dimension a, an infinite
cardinal,
over a field. Letfwil (i ~)
be afamily
ofsubspaces
of Vindexed
by
thecardinal B a,
such that dimWi
= a for all ifl.
Then there exist a+
subspaces {U}
of V such that eachsubspace
Uis of codimension 1 in V and no
subspace
is contained in anysubspacc
U.PROOF.
By
a result of Beaumont and Pierce(Ll]),
Lemma5.2)
there exists at least one such
subspace, Uo
say.Suppose
that thesubspaces {Ui} (i Z)
have been constructed Then the set ofsubspaces consisting
of thegiven Wi together
with the con-structed
subspaces Ui
constitutes afamily
of at most asubspaces
each of dimension a.
Applying
Beaumont and Pierce’s result to thisfamily yields
anothersubspace
of codimension 1. Call thissubspace
U~ .
The result followseasily by
transfinite induction.LEMMA 3.3. If S is free of rank h then there exist
p+
maximalpure submodules of
~S
with theproperty
that none of them contains a submoduleisomorphic
to8.
PROOF. Since is free of - max But v p
implies
that So9/S
is aQ-vector
spaceof
dimension n = lN0.
Now let(k
EiT)
be the collection of sub- modulesof 9
which areisomorphic
to~S’.
Each of these submodules is determinedby
anendomorphism
of~S.
However eachendomorphism
of
l#
iscompletely
determinedby
its action on S which hasrank A,
so _
11/’
-(21)1
= 2A = it. Hence(k
EK)
is afamily
ofat
most It
submodules of8.
_
Let
Wk = 8)*18.
Then(k
is afamily
of atmost u
subspaces
of theQ-vector
space which has dimension It.Since it folloTv-s that each has di -
mension ,u.
By
Lemma 3.2 we canfind p+ subspaces
U such thatno
Wk
is contained in any Uand,
moreover, each U has codimen- sion 1 in818.
If G is a submodule of8
withGI8
=U,
then G is amaximal pure submodule of
/S
andclearly
noWk
is contained in any G.Thus w e have constructed the
required family
ofu+
maximal puresubmodules.
Let 9), denote the collection of all maximal pure submodules of
8¡.
which do not contain an
isomorphic
copy of9,z.
LEMMA 3.4. If
(a ~)
is a subset of ga andIfll
then thereexist
fl+
submodules G in such that HomG)
= for allaB.
PROOF. The
proof
is similar to that of Lemma 3.3.Suppose {Wai}
denotes the set of
endomorphic images
ofGa
which haverank p.
Thenfor each a, the set is of
cardinality
at most p. Since the union of all such collections is a set of atmost p
submodules of/?.
Call this set ‘LU. Now let ‘l~ denote the set of
endomorphic images
of
Aq
which areisomorphic
to~S.
Then i0 U ‘l~ is a collection of at most p submodules say U u 9Y -(Xz) (i _ ,u) .
Note that eachXi
has rank p. SetXi = ~Xi -+-
then(i _,u)
is a collection
of p subspaces
of theQ-vector
space818
and eachX
has dimen--sion p. By
Lemma 3.2 thereexist u+
maximalsubspaces
U such thatno
Xi
is contained in a U. Choose a maximal pure submodule G such that U.Clearly
Now consider Hom
(Ga, G)
for any el. If cp: Ga -~- G is not ines- sential thenKer ~
is contained in Ga which forcesKer ~
to have rankless than p. But then Im
G«/Ker
99 is anendomorphic image
ofGa of rank p and is contained in G-contradiction. So we conclude that Hom
(Ga, G) =
for each «.LEMMA 3.5. Given any maximal pure submodule G of there
are at
most p
maximal pure submodulesG
of8;.
for which HomG) =F 1i(G).
26
PROOF.
Suppose
there exists afamily (Gz) (i
EJ)
of morethan p
submodules. For each
pick
ahomomorphism
Thenis a
family
of more than pendomorphisms
ofga.
SinceIE(SJ.)
_ ,u, we must forsome i -=F- j
E J. But thenThus Ti is inessential-contradiction. This establishes the lemma.
PROOF OF THEOREM 3.1. Choose
Go
to be any member of 9A.Sup-
pose the
essentially-rigid family (a ~8)
has been constructedfor fl /-l+. By
Lemma 3.4 there existIt+
maximal pure submodules G such that Hom(Ga, G) = Ia(G).
However for each there are,by
Lemma3.5,
at most p of these submodules G for which Horn(G, G«) # I(Ga).
Thendeleting
all such submodules G deletes at most /-l submodules from theoriginal
collection So there exists G e tlli with Hom(G, Ga)
= and Hom(Ga, G)
=Ia(G)
for all «fl.
Set
G~ =
G. Then thefamily
isessentially-rigid.
Theproof
iscompleted by
transfinite induction.4.
Essentially-indecomposable
modules.In this section we show that a
slightly stronger
result than The-orem 3.1 can be deduced and
apply
this new result to the construc-tion of
essentially indecomposable
modules.We shall use the term basic rank of a
homomorphism
to denotethe rank of a basic submodule of the
image
of thehomomorphism.
DEFINITION. If S is a free .R-module of infinite rank A and X is a pure submodule of
~S containing S,
then we defineand ~
has basic rankA)
Clearly la(X)
is an ideal inE(X).
THEOREM 4.1. If R is a
complete
discrete valuationring
of car-dinality v
and A is an infinite cardinal suchthat p
= ÂNo = 2l andthen there exists a
family
ofy+
R-modules suchthat
(i)
foreach j E J, E(Gj)
=RQ 1;.(Gj);
(ii)
fordistinct j, k
EJ,
everyhomomorphism Gi
~Gk
is ines-sential and has basic rank less than A
PROOF. This
stronge
result comesby observing
in theproof
ofTheorem 3.1 that all of the modules constructed
actually belong
to,
. Since theimage
of an inessentialhomomorphism
iscomplete,
itmust be the
completion
of a free module of rank less than A. Thisgives
the desired result.Recall that
Eo(G)
denotes the ideal ofE(G) consisting
of all endo-morphisms
of finite rank.COROLLARY 4.2
(G.C.H.).
If R is acomplete
discrete valuationring
ofcardinality 2No,
then there exists afamily
of22No
1-~ modules( j
EJ)
each with basic submodules of rankNo
such that(i)
forE(Gj) = RQ+ E,,(Gj);
(ii)
fordistinct j, k
EJ,
everyhomomorphism G~
-G,
has finiterank.
PROOF. Since
2No,
we see that 2 - No sat- isfies thecardinality requirements
of Theorem 4.1. However if ahomomorphism
fromGi
has finite basic rank then itclearly
also hasfinite rank. The result now follows from Theorem 4.1 and G.C.H.
DEFINITION. If 2 is an infinite cardinal we say that a reduced torsion-free R-module G is
h-essentially indecomposable
if in anydecomposition
G = one ofA, B
is thecompletion
of a freemodule of rank less then }~.
In the case A _ No we are
requiring
that in any directdecomposi-
tion one of the summands is
complete
of finite rank. A module with thisproperty
is said to beessentially indecomposable (cf. essentially indecomposable
p-groups,[9], § 15).
The existence of
h-essentially indecomposable
modules follows rath-er
easily
from Theorem 4.1 in the case ~,~° = 2A. For if G is one of the modules constructed in Theorem 4.1 and we have adecomposition
G = B with associated
projections
11:l and ~z2, then one of 11:1’ ~c2belongs
to since thequotient
is a domain. If n1 EE then
clearly
A is thecompletion
of a free R-module of rank less then A. Inparticular
if ~, _No
we have established the existence of °essentially indecomposable
R-modules for anycomplete
dis-crete valuation
ring
.R ofcardinality
2m-.28
We conclude this section
by constructing
anessentially
indecom-posable
module which is not a maximal pure submodule of acomplete
module.
PROPOSITION 4.3. If 1~ is a
complete
discrete valuationring
ofcardinality
2m- and S is a free R-Inodule ofcountably
infiniterank,
then there exists a pure submodule H of
~S containing S
with~Q@Q
and such thatE(H) _
.R (DEo(H).
PROOF. Choose distinct maximal pure submodules G and
Gl belong- ing
to thefamily
constructed inCorollary
4.2. SetClearly
and both inclusions are pure. AlsoLet
~S
=H,
x,~~*
where G =H, x~*
andG1= H, y~* .
Let 99 be anyendomorphism
of H. Then as in theproof
of Theorem 2.2 ivemay write
where q,
a,B, Y, d
E R andh,,,
H.Now 1 and so maps G into
G,.
From theproperties
of G andG1
we conclude that a1 is an inessentialendomorphism.
It follows as in theproof
of Theorem2.2,
thatØIG belongs
to Hence w e can writeq = r + 0
where0 E
l(G,).
But then 0 EE(H)
r1I(G1) = E(H)
nEo(H).
SoT E
.R Q+ Eo(H)
andE(H) ~ 1~ Q+ Eo(H).
The reverseinequality
isclearly
true so
E(H)
= R 0E(H).
Acknowledgment.
This paper is based on work in the author’s D. Phil. thesis written under thesupervision
of Dr. A. L. S.Corner;
I would like to express my
appreciation
of hisencouragement
andhelp.
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