R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
V. V. B ELYAEV M. K UZUCUO ˘ GLU E. S EÇKIN
Totally inert groups
Rendiconti del Seminario Matematico della Università di Padova, tome 102 (1999), p. 151-156
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V. V.
BELYAEV (*) -
M.KUZUCUO011FLU(**) -
E.SEÇKIN(***)
Let G be any group and H be a
subgroup
of G. Then H is called aninert
subgroup
of G if H n1
00 forall g
e G.Every
finitesubgroup,
every normalsubgroup
and the group itselfare the trivial
examples
of inertsubgroups
in a group. Moreover if G ==
GL(n, Q),
thenSL(n, Z)
is inert in G see[7,
page55].
In abarely
transi-tive group G the stabilizer H of a
point
and any groupcontaining
H areinert
subgroups
of G see[5].
A group G is called
totality
inert group(TIN-group)
if every sub- group of G is inert.Clearly
everyFC-group
is aTIN-group.
But there existtotaly
inertnon-FC- groups. The groups constructed
by
Olsanskff are theexamples
of non-FC
TIN-groups.
Thefollowing
is an easierexample
of anon-FC, TIN-group.
Let A be an infinite abelian
2’-group.
Let t be aninvolutory
automor-phism
of A such thata
t =a -1
for all a eA. Then G = is not anFC-group
but it is aTIN-group.
Because forany H
G thegroup H
n Ais a normal
subgroup
of G.Clearly
theproperty
ofbeing
aTIN-group
is a naturalgeneralization
ofbeing
anFC-group.
The aboveexample
shows that the class of TIN- groups islarger
than the class ofFC-groups.
One may think that every FC
by
finite group isTIN-group.
But thefollowing example
shows that this is not true.(*) Indirizzo dell’A.:
Krasnoyarsk
StateAcademy
of Architechture and Ci- vilEngineering. Svobodny
av., 82,Krasnoyarsk,
660041, Russia.E-mail:
[email protected]
(**)
Department
of Mathematics, Middle East TechnicalUniversity,
06531 Ankara,Turkey.
E-mail[email protected]
(***)
Department
of Mathematics, Middle East TechnicalUniversity,
06531 Ankara,Turkey.
E-mail[email protected]
152
Let G =
(t)
where and the or-der of t is 2. Then for the
subgroups
and Iwe have C n
C~
= 1. This group G is an FCby
finite group but it is not aTIN-group.
It is clear that any
subgroup
of aTIN-group
is aTIN-group
and anyhomomorphic image
of aTIN-group
is aTIN-group.
But thefollowing example
shows that directproduct
of twoTIN-groups
is notnecessarily
a
TIN-group.
Let A be an infinite abelian
2’-group
and t be aninvolutory
automor-phism
of A such thata t = a -1
for all a E A. Let G = A x(A >Q ~t))
andLet
( 1, t )
be an element of G. ThenThen
implies
thatHence
a 2 = 1,
but thisimplies
a = 1 as A is anabelian
2’-group.
Hence x = 1 and H is not an inertsubgroup
of G.What are the structures of
locally
finiteTIN-groups?
The groups constructed
by
Olsanskii[6]
areexamples
ofsimple
TIN-groups. But of course
they
are notlocally
finite. Does there exist an infi- nitelocally
finitesimple TIN-group?
In this article we answer this ques- tionnegatively.
THEOREM 1. There exists no
infinite simple locally finite
TIN-group.
Basic
Properties
of InertSubgroups.
LEMMA 1.
(i) If H
is aninfinite simple
inertsubgroup of
a groupG,
then(ii)
Let G be asimple
group and H be a proper inertsubgroup of
G. Then H is
residually finite.
(iii) Homomorphic image of
aTIN-group
is aTIN-group.
(iv) If H is
an irtertsubgroup of
G and N aG,
then HN is irtert in G.PROOF.
(i)
Trivial.(ii) n
H9 G. Since G is asimple
group we have = 1.geG
Hence the result follows.
(iii)
and(iv)
are trivial.LEMMA 2. Let P be a
locally
andresidually finite
p-groupfor
someprime
p.If
P/P’ isfinite,
then P is afinite
group.PROOF. Since P/P’ is
finite,
there exists a finite subset KcG such that(K, P’ )
= P. Assume ifpossible
that(K) ~
P.Let 9
e P -(K).
Then(K, g)
is finite and there exists a normalsubgroup
such thatand
N n (K, g) = 1.
LetP = P/N, K = KN/N.
Since(K, P’ )
= P weget (K, P’)
=P,
but for a finite p-group the commutatorsubgroup
lies inside the Frattinisubgroup
therefore it is a non genera- tor. Hence(K)
=P.
Butg
So weget
P =(K).
It follows that P is a finite group.DEFINITION 1. Let X and Y be two
subgroups of
a group G. We say that X and Y arecommensurable
X nY[ I
oo andY:
Y nX I
oo.LEMMA 3.
If X
is an inertsubgroup of a
group G and X is commen-surable with the
subgroup
Yof G,
then Y is an inertsubgroup of
G.PROOF. Let
g E G. By assumption
andand Then It follows that
Since the group X is inert we have , Hence
and This
gives
Then Then we
get
and
Then
LEMMA 4
[1, Corollary 2.6].
Let G be asimple TIN-group
and 1 ~~ K a H be
subgroups of
G. Then H/K is anFC-group.
LEMMA 5. Let G be a
simple TIN-group.
Then(i) for
all nonidentity
elements x and y inG,
the groupsCG(x)
and
CG(y)
are commensurable.(ii) if
isinfinite for
a nonidentity
torsion element x inG,
then G is
locally finite.
(iii) if
G islocally finite,
HG,
then either H is anFC-group
orF(H)
= 1 whereF(H)
is the Hirsh-Plotkin radicalof
H.154
PROOF.
(i).
Let be an element of G. Thenis a normal
subgroup
of G. It is clearthat
product
of two elements are in N. So we show thenormality
of N.Let
y E N and
t e G. Then It follows thatThen
Since
CG (x)
is an inertsubgroup
of G we haveHence
...
1
oo. But G issimple
and x E Nimplies
that N = G. Hence forall x
and y
in G the groupsCG(x)
andCG(y)
are commensurable.It follows that for any x e G the group
CG ( x )
is anFC-group.
(ii)
Let 1 ~ x be a fixed element of G such thatCG (x)
is infinite.Let
T(G) = {g
e G : orderof g
isfinite}
be the set of torsion elements of G. ThenT(G)
is a normalsubgroup
of G. Indeed if K is a finite subset ofT( G ),
thenby (i)
HenceCG (K)
is an infi-nite group. Let
aeCG(K).
ThenK;CG(a)
andCG(a)
is anFC-group.
Then
by
Dietzmann Lemma(K) ~
is finite. Hence(K)
is a finitesubgroup.
HenceT(G)
= G and G islocally
finite.(iii)
Let x and y benonidentity
elements of H. ThenKl
=(XH )
andK2
=(yH)
are commensurable.Indeed,
forany i
=1,
2by
Lemma 4H/K2
areFC-groups. Let y
== yKl e H/Kl.
Then(yll)
=K2/(Kl n
which is finite. Simi-larly KI /(Kl
nK2 )
is finite.Let
F(H)
be the Hirsh-Plotkin radical. Assume ifpossible
that H is notan
FC-group.
Thenby [2,
Theorem 1.4] F(H)
is a p-group andby [2, Corollary
2.2 and Theorem4.5] FC(F(H) )
= 1. Since there exists no FC- element everyconjugacy
class is infinite. Let and(XF(H»
= L. Since the group L is an infiniteresidually
finite p-group weget L
> L’. Lety e L’ .
Then(y F(H»
aL’ andby
Lemma 21 L: (y F(H) ) I
is infinite. But any two normal
subgroups
ofF(H)
are commensurableby
the above
paragraph.
Hence we obtain a contradiction.LEMMA 6. Let G be a
locally finite
group. Let A be a normalinfi-
nite
Elementary
abelianp-subgroup of
G. Assume that everysubgroup of A
is inert in G. Thenfor
any x eG,
there exists asubgroup
Bof finite
index in A such
that, for
allbeB,
bX e(b).
PROOF. Assume on the
contrary that,
there exists 1 ~ x e G such that ifA :
B then there existsal e B
such that Thenax1> n a1> = 1.
Let Then
Al
is finite andBl
is(x)-invariant
and has finite index in A.By
a similarargument
there exists such that(at)
fl(a2 )
= 1.Let
A2
=(at)
x(ct2)
andBl
xA’
The group
B2
has finite index inB1
andB2
is(x)-invariant.
There exists such thatLet
Continuing
like this we obtain an infinite sub- group of Anamely,
Let Then C" n C = 1. Hence C is not inert in G which is a contradiction.
LEMMA 7. Let G be a
locally finite
group and A be a normalinfi-
nite
elerrzentary
abelianp-subgroup of
G.If
everysubgroup of A
is inertin
G,
thenfor
all x EG’, [A , x ] I
00. I. e G ’ acts asfinitary
lineargroup on A.
PROOF. Let x E G ’ . Then x = Xl X2 ... Xn where xi =
[ yi , zi I
for somei =1, 2 , ... n. Clearly
Henceit is
enough
to prove that[A , xi ]
is finite for all i =1, 2,
... n.By
Lemma6, for y2 and zi ,
there existBi
andBi
such thatBi I
oo and
A : oo and for all b E Bi,
E ~ b ~.
ThenA : B I
oo and for allb E B ,
andThis
implies
b Yi = b ni and b zi = b’ni for some ni and mi in Z. Since theautomorphism
group of acyclic
group is abelian weget
= b forall b E B. So
A : I
00 since Hence[A ,
00.PROOF OF THE THEOREM 1. Asume that G is a
simple locally
finiteTIN-group. By [4]
Theorem 4.4 everylocally
finitesimple
group has a lo-cal
system consisting
ofcountably
infinitelocally
finitesimple
sub-groups. But
by
Lemma 1 in asimple locally
finiteTIN-group,
an infinitesimple subgroup
is a normalsubgroup,
so we may assume that G itself is countable.156
By [3,
Theorem BPage 190]
a countablenon-finitary locally
finitesimple
group has maximalsubgroups.
Let M be a maximalsubgroup
ofG. Then for
1M: M n Mg I
00 andI
oo. It fol-lows from
[1]
Lemma 5 that~M ,
M n M gI
00. As M is a maxi-mal
subgroup
of G weget
M = M forall g
e G. Hence M is a normal sub- group of G. But G issimple,
hence we may assume that G is acountable, finitary locally
finitesimple
group.By [3,
page 216 Theorem8],
thereexists a
prime p
such that if H is any proper inertsubgroup
ofG,
thenHIOp(H)
islocally
normal.Consequently
ifF(H)
=1,
then H islocally
normal. If
F(H) ~ 1,
thenby
Lemma 5(iii)
H islocally
normal.By [3,
page 216 Theorem
6]
G isisomorphic
to analternating
group offinitary permutations
on some set SZ. But a stabilizerGa
of a e Q is an infiniteproper
simple subgroup
ofG,
and this isimpossible by
Lemma 1(i).
REFERENCES
[1] V. V. BELYAEV,
Locally finite
groups with010Cernikov Sylow p-subgroups,
Al-gebra
iLogika,
20 (1981), pp. 605-619. TranslationAlgebra
andLogic,
20 (1981), pp. 393-402.[2] V. V BELYAEV, Inert
subgroups
ininfinite simple
groups, Sibirskii Mathe- maticheskii Zhurnal, 34 (1993), pp. 17-23.English
Translation Siberian, Math.J., 34 (1993), pp. 218-232.
[3] B. HARTLEY et al, Finite and
Locally finite Groups,
NATO ASI series C, 471, Kluwer Academic Publishers (1995).[4] O. H. KEGEL - B. A. F. WEHRFRITZ,
Locally finite Groups,
North Holland, Amsterdam (1973).[5] M. KUZUCUO011FLU,
Barely
Transitivepermutation
groups, Arch. Math., 55 (1990), pp. 521-532.[6] A. Ju. OL’SANSKII, An
infinite
group withsubgroups of prime
orders, Izv.Akad. Nauk. USSR. Ser. Mat., 44, 2 (1980), pp. 309-321.
[7] G.
SHIMURA,
Introduction to the ArithmeticTheory of Automorphic
Func- tions, IwanamiShoten,
PrincetonUniversity.
Manoscritto pervenuto in redazione l’l dicembre 1997.