A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
B ERNHARD R UF
Singularity theory and the geometry of a nonlinear elliptic equation
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 17, n
o1 (1990), p. 1-33
<http://www.numdam.org/item?id=ASNSP_1990_4_17_1_1_0>
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a
Nonlinear Elliptic Equation
BERNHARD RUF
1. - Introduction
In this paper we
apply singularity theory (in
the sense of H.Whitney [11]
and R. Thom
[10])
to obtain acomplete description
of the solution structure of theequation
where A is a
positive constant, S2
c Rn is a bounded smoothdomain,
andh(x)
is agiven
data function.Let 0 =
a A2 a3
... denote theeigenvalues
of theequation
It is easy to see that
( 1.1 )
has aunique
solution infor every
given h
E if A 0. Infact,
in this case the linearization of themapping C = -A -
A +( . )3, namely
is
regular
in everypoint u
EE,
that is C islocally
invertible in anygiven point
u. From this the above statement followseasily,
since Q is proper.Pervenuto alla Redazione il 18 Novembre 1986 e in forma definitiva il 28 Dicembre 1988.
On the other
hand,
if A >a
= 0, then Q hassingular points,
that is thereexist functions u such that the
equation
has a nontrivial solution v.
The aim is to obtain a
complete description
of the solution behaviour ofequation (1.1) through
thestudy
of thesingular
set of 1>.Roughly speaking
we will show
that,
for 0 A12 ,
themapping (D
is aglobal
cusp. Moreprecisely,
we will prove thefollowing
theorem.THEOREM 1.1. For 0 a
A2
there exists in F = aCo-manifold
THEOREM 1.1. For 0 A
12 there exists in F ==
( ) f of
codimension 1 such thatFBG
=F,
UF3
consistsof
two open componentsFl , F3,
with 0 EF3,
and such thatif h
EF3,
thenequation ( 1.1 )
hasexactly
3solutions, if h
EFl ,
thenequation ( 1.1 )
hasexactly
1 solution.We note
that,
forh(x) -
0,equation (1.1)
can be viewed as a bifurcationproblem
in(A, u)
E R xE;
infact,
it follows from the classical results in bifurcationtheory [7,9]
that(Ai,0)
is a bifurcationpoint. Therefore,
for smallA >
a
= 0,equation ( 1.1 ) has,
for h - 0, at least 3solutions, namely
the trivialsolution
(A,0)
and apositive
and anegative
solution. Infact,
for Neumannboundary conditions,
these solutions can be calculatedexplicitely:
let 1 denotethe constant function
(equal 1)
on SZ. Then we have for s ~1,
s ER,
theequation
which has the solutions so =
0,
= ~Ji.
The theorem stated above describes the
global
structure of this bifurcation.If the parameter A crosses the first
eigenvalue À1,
then a setF3(A)
appears in the space F which is covered three timesby
themapping
-0 -À + ( . )3.
Wenote that the
proof given
belowgives
aprecise description
of thegeometric
structure -of the set
F3(a),
which can be visualized as follows.Figure
1As
already mentioned,
theproof
of this theorem relies onsingularity theory
in Banach space.
More
precisely,
one studies the nonlinearmapping
where E and F are as before. For A > 0 this
mapping
hassingular points
u,that is the Frechet derivative in u of
(1.3)
vanishes in some direction v:The aim is to characterize
completely
thesingular
set S(that
is the setof
singular points)
and theimage
of thesingular
set1>(8).
Then one can usethe
following
well-knownproposition
to obtain the desired information about the solution structure ofequation ( 1.1 ).
PROPOSITION 1.2. Let
X,
Y be Banach spaces, and let (D : X --+ Y be aFréchet-differentiable
and propermapping (i.e. for
every K C Y compact, theset
~-1 (K)
c X iscompact). Furthermore,
letThen
N(y)
is constant on the componentsof ( for
aproof,
see e.g.Ambrosetti-Prodi
[1]).
The characterization of the
singular
set involves twosteps. First,
the characterization of the form of thesingular
set, that is thedescription
of thesingular
set S as a subset in thegiven
space.Second,
the classification of thesingular points
on S(according
to the classification ofsingularities
of R.Thom).
We remark that the
singularities
considered here lie in infinite dimensional Banach spaces.However,
underappropriate assumptions
thesesingularities
canbe handled like their finite dimensional
analogues (see
e.g.Berger-Church [2,3], Berger-Church-Timourian [4]).
In
general,
the task ofclassifying
thesingular points
is difficult.However,
in the case of the
mapping (1.3)
this can bedone,
and we will prove in this paper thefollowing
classification result.THEOREM 1.3. Let 0 A
~2.
Then thesingular
set S is a smoothmanifold of
codimension 1 such thatEBS
has two componentsE1
andE3.
Furthermore,
S contains a smoothsubmanifold
Cof
codimension 1(with
respectto
S)
such thatSBC
=81
US2
has two componentsconsisting of fold points
C consists
of
cusppoints (see figure 1).
For the notions of fold
points
and cusppoints
we refer to section 2.We
just
note that folds and cusps are the two mostsimple singularities
in theclassification of R. Thom.
The result in this paper should be
compared
with a result of A. Ambrosetti- G. Prodi.They
showed in[1]
that theequation
with
f
EC2(R), f’(-oo) al f’(+oo) A 2
andf"(t)
> 0, for all t ER,
has the form of aglobal fold,
i.e. thesingular
set of (D = -A -f : Eo - F,
whereEo = JU C
= 0 on9921,
is a smooth manifold ,S of codimension 1consisting
of foldpoints. Furthermore,
M = is a smooth manifold of codimension 1 inF,
andFBM
has twocomponents Mo
andM2
such thatif h E
Mo,
then(1.5)
has nosolutions,
if h E
M2,
then(1.5)
hasexactly
two solutions.In the result of
Ambrosetti-Prodi,
as well as in ourresult,
it is crucial to knowexactly
what kind ofsingularities
occur. Infact,
the limitation AA2
.
y g
.... ’
. 7is used to exclude the existence of
higher singularities
than cuspsingularities.
The existence of such
higher singularities
wouldcorrespond
to the occurrenceof
secondary (and higher) bifurcation,
which wouldcomplicate
the structure ofthe
equation.
We mention that V.
Cafagna-F.
Donati[6]
exhibited a similar structure asthe one described in theorem 1.3 for the
equation
where
a > 0, a2+b2>0
and c0.Finally,
we remark thatby topological
methods one caneasily
establishthe existence of a
region
in F suchthat,
for h in thisregion, equation ( 1.1 )
has at least three solutions.
Thus,
theimportance
of theorem 1.3 lies in the assertion of the exact number of solutions and theprecise description
of theregion
where theequation
has three solutions.We remark that our results could also be useful for numerical
applications.
In
fact,
thesingular
set S is foundconstructively
in ourproof
and is therefore accessible to numerical methods.Furthermore,
theoperator (D
maps S one to one onto1>(8),
and hence also0(6’)
can berepresented numerically.
This thenallows to localize the solutions to a
given
data function h.2. -
Singularity theory
in Banach spaceIn this section we
give
a short account ofsingularity theory
in Banachspace. For more details and the
proofs
we refer to[2,3,4,5,8].
In this section we assume that X and Y are Banach
subspaces
of a Hilbertspace H, and that
is a smooth Fredholm
mapping
of index 0(i.e.
the Frechet derivativeF’(u)
ofF in u E X is a Fredholm
operator
of index0,
thatis,
KerF’(u)
and ImF’(u)
are closed and have closed
complements,
and the index ofF’(u)
is zero, i.e.:= dim Ker
F’(u)-
codim ImF’(u)
= 0. It is easy to see thati(F’(u))
is
independent
of uE X).
DEFINITION 2.1. A
point u
E X is asingular point
ofF,
if theequation
has a nontrivial solution v.
Otherwise, u
is aregular point
of F. We denoteby
S’ the set of
singular points
of F.We now
give
a condition such that the set ofsingular points
of F islocally
nice.PROPOSITION 2.2. Let u E X be a
singular point of
F, and assume that(2.2) (F’(u)v, w)H
=(v, F’(u)w)H, for
every v, w E X.(2.3)
there exists w E X such that(F"(u)(w, e), 0,
where0 =I
e E KerF’(u).
Then there exists a
neighbourhood
Uof
u in X such that S n U is a smoothhypersurface.
In order to
describe
the behaviour of F in aneighbourhood
of asingular point,
we need a classification of thesingular points.
DEFINITION 2.3. Assume that u E X is a
singular point
of Fsatisfying (2.1-3).
We call u afold point,
if thefollowing
condition holdsThe term fold
point
isjustified by
thefollowing
Normal Form theorem.THEOREM 2.4. Let u E X be a
fold point of
F. Then there exists a Banachspace Z such that F is
locally equivalent
at u to the map G : I~ x Z -~ l~ x Zgiven by
-More
precisely,
there existneighbourhoods
Uof
u in X and Vof F(u)
in Y anddiffeomorphisms
a : U - R xZ, {3:
V --+ R x Z such thatIn case that u satisfies
(2.1-3),
but not(2.4),
we say that u is ahigher singularity.
We
give again
first a condition such that the set C ofhigher singularities
islocally
a nice subset of S.PROPOSITION 2.5. Let u E X be a
higher singularity,
and assume thatthere exists a w E X with
where
0 =/
e E KerF’(u)
and z =z(w)
is a solutionof
theequation
Then there exists a
neighbourhood
Uof
u in X such that C n U is a smoothhypersurface
in S, and hence a smoothsubmanifold of
Xof
codimension 2.A
sharpening
of condition(2.5)
leads to thefollowing
definition.DEFINITION 2.6. We call u E X a cusp
point
of F if u is ahigher singular point
of F and if thefollowing
condition holdswhere
0 Q
e E KerF’(u),
andz(e)
isgiven by (2.6).
The term cusp
point
isagain justified by
a Normal Form theorem.THEOREM ° 2.7. Let u E X be a cusp
point of
F. Then there existsa Banach space Z such that F is
locally equivalent
at u to the mapG: R x R x Z --+ R x R x Z given by
For later purposes, we
give
conditions(2.4)
and(2.7)
for themapping F(u) =
-Au - with 0 AA2.
PROPOSITION 2.8. Let
F(~) ==
-Au - Au +u3.
a)
Thefold
condition(2.4)
then isgiven by
where
vl (u)
is the solutionof
b)
The cusp condition(2.7)
isgiven by
PROOF.
a)
Sincewe have
e = v 1 (u),
and hencefrom which
(2.8)
follows.b)
From(2.11 )
we getFurthermore,
from(2.6)
we getSince
(uvf(u),
vl(u))
= 0by assumption,
we can invert theoperator
andget
- I I - 11
From
(2.7)
we now obtain the conditionhence
(2.10);
here( ~ , ~ )
denotes theproduct.
3. - The form of the
singular
setIn this section we describe the form of the
singular
set of themapping
with
The Fréchet-derivative of O is
given by
The
singular
set S of (D is defined asWe denote
by ui(u),
ie N,
the spectrum of(1)’(u)
withcorresponding L2-normalized eigenfunctions
LEMMA 3.l. Let 0 A
A2.
Then thesingular
set Sof (D
isgiven by
Furthermore,
we havePROOF. The statement
(3.2)
follows from(3.3),
since for AA2
we havett2(U)
>0,
for all u E E. Theinequality (3.3)
follows from the variational characterization of theeigenvalues.
Letju2(u) = IL2(U)
+ A- We denoteby
where
(x, y)
EV2
withHere and below
(.,.)
denotes theLI-inner product
and11 - 11
theL2-norm.
Thenwe have
Hence
For the next considerations we
distinguish
between the Sturm-Liouvilleproblem
and theequation
inhigher
dimensions.PROPOSITION 3.2. Let S2 =
(0, 1),
and letDl
denote the unitL2-sphere
inE. Then i 0 a
A2
there exists a radial di
diffe
eomor p hism E.-.,
there exists a radialdiffeomorphism
PROOF. Let u E
Dl
begiven.
We consider the functionThis function is
strictly
monotone in p, sincesince does not
change sign. Furthermore,
we have~i(O) = 2013A
0, sincev 1 (o)
is the constant functionequal
to + 1.From the
following
lemma 3.3 we have thatHence,
if AA 2
there exists on each ray E a4
{P u
P]
q PP( )
such = 0.
The
proposition
now followseasily,
eitherby showing directly
thatp(u)
isdepending smoothly
on u, orby using
theimplicit
function theorem(we
haveshown that u is a transversal vector to S in the
point p(u) - u).
Before
stating
lemma 3.3 we introduce some notation. Let I denote aunion of open and
disjoint
subintervals of(0, 1),
and denote the firsteigenvalue
of theequation
we set
Àl (1) =
+oo, if I =(0, 1).
Note thatFor
this,
one observes thatLEMMA. 3.3. Let SZ =
(0, 1).
ThenPROOF. For u E
D 1,
let E(0,7r)~(a:) ~0}.
We claim thatTo prove
(3.6)
we note first that we have forall This follows from the variational characterization
(we
setagain
We now show that In
fact, (3.7) implies
thatand hence is
relatively compact
inC",
0 a~.
Let be asequence with pn 2013~ +00, and such that We claim that = 0 in
L2(I(u».
If not, we would havecontradicting (3.7).
This
implies
that VI 1 solves theequation (3.4)
with I =I(u),
and hencelim
n-->oo
By Y( ) (3.5)
we have1( ( ))
> -A2 - a
4 and hence the lemma isproved.
p.
For Q eRn, with n > 2, the situation is more
complicated,
since in thiscase there exist rays which do not meet S.
LEMMA 3.4. 2, and assume that A > 0. Then there exist
functions u
EDl
such thatPROOF. Let xo E Q and E > 0 such that
B,(xo)
CSZ,
whereLet Us
E E with supp uE CBe
and=
1. We claimthat,
for c > 0sufficiently small,
the function u has theproperty (3.9).
In
fact,
we note first thatwhere is the first
eigenfunction
of theequation
This follows
by
theanalogue
of(3.7)
inhigher
dimensions(replacing I(u) by
We now estimate +A. Let
Then
where
(here
we assume, without loss ofgenerality,
that xo = 0 c 0 and e > 0 such thatB~(0)
cS2). Then 0,
EHE.
We now estimate~~~~E~~z~~~~E~~2, setting
and
So
sufficiently
small.Finally,
since > d > 0, for 0 e so, we get the estimate and henceWe now set L:=
ju
E81;
lim >0}.
Then we havep+oo
PROPOSITION 3.5. There exists a radial
diffeomorphism
Furthermore, if (un)
C I is a sequenceconverging
to aboundary point of
L,then
p(un)
-> +oofor
n - oo.PROOF. As in
proposition 3.2,
we get thatJ.Ll (pu)
isstrictly
monotoneincreasing
in p.Hence,
if u E L there exists aunique p(u)
such that ti1 ( p(u)u)
= 0.Clearly, p(u)
is smooth in u.Let now
(un )
C I be a sequenceconverging
to theboundary
of E andassume
that,
contrary to ourclaim,
we have E S’ with c, for all n E N . Then we findsubsequences
PnUn --+ pu, = 0 and -~ v 1 and hence we obtain thelimiting equation
But is
strictly increasing
in p, we findthus
contradicting
ourassumption..
We conclude this section with the
following
remark.LEMMA 3.6. The normal vector
n(u)
to S in thepoint
u E S isgiven by n(u)
=PROOF.
By
Lemma 3.1 we have EE; 0}.
HenceDjLl (u)[z]
=6(uvf(u), z),
i.e.n(u)
=6uvf(u)..
4. - The structure of the
singular
setIn this section we
classify
thesingular points
of themapping
1>. Moreprecisely,
we will show that thesingular
set ,S contains a submanifold C of codimension 1(relative
toS)
of cusppoints,
and that,SBC
consists of foldpoints.
First we show
that,
for 0 A7 ’ A2
thesingular
set containsonly
foldpoints
and cusppoints.
PROPOSITION 4.1. Assume that 0 A -
~2.
Then S containsonly fold points
and cusppoints.
7
*
PROOF. Let u E S be a
higher singularity.
VVe claim that thenIn
fact, assuming
to thecontrary
that(4.1)
does nothold,
we obtain the estimateSince, by (3.3), ¡..ti(U)
>~u2(u) > A2 - A,
for every u ES, i
> 2, we obtainOn the other
hand,
we obtain fromby
scalarmultiplication
withand hence
Combining (4.2)
and(4.3),
we getand hence
Therefore,
if A---,
we have a contradiction and hence(4.1)
holds.By proposition (2.10),
it follows that u is a cusppoint..
Next we show that there exist
higher singularities
on S.PROPOSITION 4.2. Let 0 A
A2.
Then S containshigher singularities.
PROOF. Let e = const. and e2 denote the first and second
eigenfunction of - A,
letand let
p(a)
E R + such thatp(a)u(a)
E S. Sinceu(a)
vanishesonly
onsets of measure zero, it follows that
p(a)
+oo, forall
1.Hence, { p(a)u(a); -1 a 1 } is a
continuouspath
with =Noting
that = e 1, we deduce 0 that there existsa a E
(-1,1 )
suchthat f p(a)u(a)v i (u(a))
= 0.COROLLARY 4.3. Assume that 0 a
A2.
Then the sin ular set S COROLLARY 4.3. Assume that 0 A
7
Then thesingular
set Scontains a codimension 1
(relative
toS) manifold
Cconsisting of
cusppoints
and
SBC
consistsof fold points.
PROOF.
By proposition 4.2, C:10 and, by propositions
2.7 and2.4,
C isa codimension 1 submanifold of S.
By proposition 4.1, ,SBC
consists of foldpoints..
5. - The
image
We now come to the characterization of the
image
One way to achieve this would be to prove
that Q|s
is one to one. This wouldimply
that hasexactly
twocomponents. By
theapplication
of thetopological proposition 1.2,
one could then deduce that the number of solutions is constant in each of these components: infact,
3 in one component and 1 in the other.We choose here a more direct and constructive method to prove this
result, namely
theLyapunov-Schmidt
reduction. Thatis,
wedecompose equation (1.1)
into a
pair
ofequations, namely
where
and
Q
= Id - P : F ~{s ’
1; s ER,
1 = constant functionequal
1 onQ}
denote
orthogonal projections (with
respect to theL2-scalar product),
and~ = s ~ 1 + y - Qu + Pu
denotes thedecomposition
of uaccording
to theseprojections (restricted
toE).
One now shows that(5.1 )
has aunique
solutionfor each fixed s E R and
h,
1 EFl,
whichdepends smoothly
onh
1 ands. The
problem
is then reduced tostudy
the functions1’(-, hl) :
R - Rgiven by
PROPOSITION 5.1. Assume that A
A2.
Thenequation (5.1 ) (with
Neumannboundary conditions) has, for
eachfixed
s andgiven
datafunction hl, exactly
one solution which is
smoothly depending
on the arguments s andhl.
PROOF. The existence of a solution follows from the
Leray-Schauder principle (see
e.g.[12,
p.65])
for theequivalent equation
We have to show that there exists a R > 0 such
that,
if(T, y)
E[0, 1]
xEl
solvesthen ||y||E
R. Infact, multiplying
thisequation by
y, we getSince
we conclude that
From this we infer that c, and
then,
forh,
1 E it followsby
standard
regularity
results R.To prove
uniqueness,
assume that there exist solutions yl , y2 EEl
:= PE of(5.1 ),
i.e.Multiplying
thisequation by YI -
y2, we get the estimate:since we
have, setting
iBy assumption
we haveA2
> A and hence yl = Y2-The smooth
dependence of y
on s and~1
iseasily
verified. * We note that forgiven hi
eFl
themappings
s Hu(s,
= s - 1 +y(s, h 1 )
are curves in E which are
disjoint
for We use these curves togive
aninterpretation
of foldpoints
and cusppoints.
PROPOSITION 5.2.
a)
Apoint
+y(s, hi)
E E is afold point if u(s, hl)
is anondegenerate
zeroof
thefuncton
s --~?7(s, hl)
=d r(s, hl),
i.e.and
b)
Apoint u(s, hi)
E E is a cusppoint if u(s, hi)
is anondegenerate
extremumat level zero
of
thefunction 77(s, hl),
i.e.and
PROOF.
a) Taking
the derivative ofequations (5.1)
and(5.3)
withrespect
to s and
writing
ys =d ds y(s, hl),
we obtainHence, I +y,
=: is the firsteigenfunction
to theeigenvalue
if and
only
if = 0, since thenTaking
the derivativeFS d
weget
From
(5.4),
we obtainAdding (5.7)
and(5.8),
we haveMultiplying
thisby
v, = 1 + ys, we obtainby (5.6)
Hence,
ifd
the condition(2.8)
issatisfied,
that isis a fold
point.
b) Taking
the derivative with respect to s of(5.10),
we getSince
d as- n (s, hl ) = 0 by assumption,
weget
from(5.9)
Substituting
this into(5.11),
we see that~I (s ~ hl) ~ 0
iff( 2.10 )
holds. -REMARK 5.3. The reason that the
singular points
can be characterizedby
the solution curves s. 1 is
that,
in asingular point
the
tangent
to the curve has the directionv, (u(so, hi)),
i.e.We now derive a differential
inequality
for the function t7.LEMMA 5.4. For every
h
1 EFl,
thefunction h 1 ) satisfies
theinequality
for
all s E R.PROOF. The
proof
follows the idea ofproposition
4.1.By equation (5.11 )
we
have, setting
u = sl +y(s, hi)
and vl =vl (s)
= 1 +y,(s, hl ),
Let ei, with
9e - an
an aQ = =0,
i E N, denote theL2 -normalized eigenfunctions
of-A. Since
(Yss, el)
= 0, we haveBy (5.9),
we haveand hence
Inserting
this in(5.14),
weget
Hence we can estimate in
(5.13)
We now use that
by (5.4)
and(5.5)
Multiplying
thisequation by vi,
weget
and hence
Using
this in(5.15),
weget (5.12). 0
PROPOSITION 5.5. Let 0 a
A2
Then the set M n S consists o strict PROPOSITION 5.5. Let 0 A7
Then the set M n S consistsof
strictminimum
points for 77(s, hi).
PROOF. For we have
q(s)
= 0 =1/s(8),
and thenby
(5.12) 1/ss(s)
> 0. ·To characterize the
image
ofc1>,
it is crucial to know that isinjective.
For this it is
clearly
sufficient to prove that Q isinjective
onfor every
hi
EFl,
sinceNote that the set
consists of discrete
points,
sinceby proposition
5.5 for apoint 8 E ShJ’
with
1/8(8)
= 0, one has1/88(8)
> 0. Note furthermore that in intervals where=
d
0 the function isstrictly increasing,
whilein intervals where 0 the function r is
strictly decreasing.
To prove
injectivity,
it suffices to consider foursubsequent points
s t 82 t2 in
Sh,
such thatand
(the
cases thatSh,
contains one or twopoints
aretrivial,
while the case thatSh,
contains threepoints
followseasily
from the abovecase).
Since
hi
remains fixed in theargument,
we suppress it in thesequel.
From(5.18)
it follows thatTo obtain
injectivity
it is therefore sufficient to prove thatQualitatively
it is easy to see that this follows frominequality (5.12)
forA 0 with
IÀI I sufficiently
small. Infact,
we have1/(8) ~ -À
for all s cR, since, setting
w= /
1dx,
0
Hence we see that
is
O(A)
for A small. On the otherhand, by (5.12),
r¡ss > d -cq(s) (see below),
S2
and hence it follows that
F(32) - r(tl ) = f n (s)
ds is bounded away from zerotl
for A
tending
to zero, sayr(s2) -
c > 0.Hence,
for Asmall,
we haveIn the
sequel
we estimate the size of A.PROPOSITION 5.6. Let 0 A
~2 . injective.
PROOF. The
proof proceeds
in severalsteps.
1.
Denoting again
w= f
1dx,
we haveQ
2. 0, then vi = 1 + us > 0 in SZ. In
fact,
note that 7y > 0 if andonly
ifthe first
eigenvalue
it, 1 ofis
non-negative (and
1/ > 0 if andonly
if >0). Hence,
if 1/ = 0, then 1 + us is the firsteigenfunction
of(5.22),
and therefore it ispositive.
If 1/ > 0, then> 0, and therefore the
equation
implies by
themaximum-principle
that 1 + ys > 0 in Q.3. We now consider
(5.12) separately, where q
is smaller than6
andwhere it is
larger.
6Here we can estimate
(5.12)
further as follows. In lemma 5.7below,
we showthat,
for ?y;::: 11().)
w with7(A)
> 0.81 for 0 A~2.
Hencewe get, for 0,
_
( )
~( ) _
_12
If 0
q(s) then f vi >
w, since then v, > 0(see above)
and henceHence we
get, by (5.12)
andstep
1above,
where the last estimate is done for
simplification.
Hence we have on the wholeinterval
> ~ ~‘’
~ss -2 - (A2 -
2 7a -6,q).
We solve theequation
The solution is
given by
with
Note that
Let M > 1 be such that
f ( 1 + us)3 Mw,
forq (s)
A(see
lemma 5.7below).
Then we can estimate
5.12 : (A2 -
7A -6M?7(t)).
We solve the
equation A2 -
A
The solution is
given by
c)
We nowjoin
thesolutions ~ and ~
as follows:where a > 0 is such that This
yields
Moreover,
we choose A > 0 such thatz’(t)
is continuous in t = a :~’(a) = £a(a).
Thisyields
cos
Adding
the squares of(5.26)
and(5.27),
andsetting yields
We will use later this relation to estimate B.
4. Next we show that the
solution n(t)
of(5.12)
lies above the functionz(t)
defined in(5.25),
moreprecisely,
ifrespectively,
ifTo see
this,
note thatis the first
eigenfunction (with eigenvalue 01
=1)
of theequation
with
Note
that,
if77(0)
=z(O),
>z(t)
for t near 0, sincer¡’(0)
=z’(0)
= 0 andq"(0)
>z"(0),
andsimilarly,
ifq(c)
=z(c),
then >z(t)
near c. Assume now that?7 (to)
=z(to)
for some to E(0, c). Then q -
z solves-
(q - z)" = 1b(t)(q - z) - g(t),
for some functiong(t) > 0, (Q - z)(0) = (Q - z)(to) = 0, [resp. (Q - z)(to)
=(Q - z)(b)
=0].
Let w 1 denote the
positive
firsteigenfunction
withcorresponding eigenvalue
01(to)
of -v" =v(O) = v(to) =
0[resp. v(to) = v(b) = 0].
Since to E(0, a + b - a),
with a >0,
we have01 (to)
> 1.Multiplying
the aboveequation
with w 1yields
contradicting
5. We have seen in
(5.20)
that forproving injectivity
it suffices to show thatt2
r(t2) - r5i)
> 0. Thisholds,
if81
Since
q(t)
lies above~(t),
we can estimate the left hand side from aboveby Furthermore,
since >z(s),
we know thatThe
integral
on theright
can therefore be estimated from belowby
(it
is seen from the calculations belowthat f ~A
increases for Aincreasing).
Hence
(5.29) holds,
ifWe have
It is shown in lemma 5.7 below
that,
for Withthese values the number
7i
can be estimated:Similarly
we haveIn lemma A 5.7 it will also be shown
that,
for 0p 2013,
12 one hasM
1.54and B
= x2-
> 0.15. With this we estimateHence we find that
II 12
+13..
To
complete
theproof
of theproposition,
it remains to prove thefollowing
lemma.
LEMMA 5.7.
La)
For all s suchthat 1¡(s)
:=~~s> >
0 holdsb)
For one has.PROOF.
l.a) Multiplying (5.16) by vi ,
weget
Using
thatvl(s)
> 0 for > 0, we haveHence we derive from
(5.31)
Since we have furthermore
Using
this in the aboveinequality,
wefind, setting again
This
yields (5.30).
l.b) Setting
B= max q(s),
we obtain(see proof
of prop.5.6,
section3b)
The
equations (5.28)
and(5.33),
considered as asystem,
haveunique
solutionsM > 1 and B > 0. A numerical
calculation yields for p - 12 1
the values inl.b). Finally,
we see that in(5.33),
for B fixed and pdecreasing,
we haveM
decreasing,
while in(5.28),
for M fixed and pdecreasing,
we have Bincreasing.
Thisimplies
that the estimates inI.b)
hold for all p Eo, 12 ’
2.a) Multiplying (5.16) by vi gives
and
hence,
sinceiz(.5) > -A,
for all s E R,Together
with(5.21),
we obtainwhere we have used
(5.32). Setting
we conclude
We use this in
One calculates
that, for - 1 - -
0, the terms on theright
arepositive
and hence
1(1
+ > 0. With this information we canimprove
the estimateby omitting
in(5.34),
on theright
handside,
the term This thenyields, proceeding
asbefore,
instead of(5.35):
and then
This proves
2.a). 2.b)
is asimple
calculation. 0It is now easy to
give
acomplete
characterization of theimage
of 1>. LetI I I
THEOREM 5.8. Let 0 A 12
A2 .
Then the restrictionof cD =
-0 - A +(. )3
to S c E is one to one, and the restrictions
of (D
toC, S,
andS’2
arediffeomorphisms.
Furthermore,
hasexactly
two components, sayFl
andF3,
witho E F3.
The
equation (1.1)
hasfor
h EF3 exactly
3 solutions,and for
h Eexactly
one solution.Finally, for
h Eequation ( 1.1 )
hasexactly
twosolutions.
PROOF.
By proposition
5.6 themapping
is one to one. It then followsby
theorems 2.4 and 2.6that Qlslus2’
arediffeomorphisms.
Note thatthis can also be obtained
directly
from theproof
ofproposition
5.6.Let now
F3 =
E E;0} .
ThenF3
is connected andaF3
=(D(S).
Since is a codimension 1 manifold whichseparates
Flocally
into two
components,
itfollows
that hasexactly
twocomponents,
see[1,
prop.2.7].
LetFl
=FBF3.
We could nowapply proposition
1.2 tocomplete
the
proof
of the theorem.However,
due to theLyapunov-Schmidt reduction,
wecan with little effort
complete
theproof directly.
For
this,
note that the curves s ER,
getmapped by
(Donto the lines
+ hi; t
EIl~ };
infact,
we have- +oo,
s--·too since-c
r(s, ~i)
c, for all s ER,
wouldimply
and
hence s2 + f y2
bounded.If = > 0, then there exists
clearly exactly
onesolution
u(s, hl )
for everygiven
h = tl +hi (note that,
inpoints
with= 0 =
?7.~(s, hi),
we have77,,(s, hi)
> 0by proposition 5.5).
Suppose
now that for agiven h,
1 EFl
there existpoints sl(hl)
the function is monotone
increasing
for s monotonedecreasing
for s 1 s and then
again
monotoneincreasing
for s >Hence,
ift E
(r(t 1, h 1 ), r(s 1, h 1 )),
then there existexactly
3 solutions for tl +h 1,
while if there existsexactly
1solution,
and orthere exist
exactly
2 solutions.Finally,
if there exist two(or more) pairs
s 1 ti 32 t2, with?7(s,
0for sa
s tZ , i =1, 2,
andhi)
> 0 for t 1 s 82, then we seeby
the relation(5.20)
thatr(SI, r(t2,
Hence we findby
the aboveargument
exactly
3 solutions for t E andexactly
1 solution for t t > andexactly
2 solutions for t =r(s; , i = 1, 2, t
=i = 1, 2.
This
completes
theproof.
6. - Remarks and
generalizations
1. Dirichlet
boundary
conditionsAll the
arguments
work with some alterations also for Dirichletboundary
conditions. But there are some
changes
in the results.First,
we remark that for the Sturm-Liouvilleproblem
we now have(as
in the
higher
dimensional case for theNeumann-problem)
rays E which do not meet thesingular
set S.PROPOSMON 6.1. Let Q =
(0, 1)
and considerequation ( 1.1 )
with Dirichletboundary
conditions. Leta
1 aÀ2,
whereÀl, 1B2
denote thefirst
and thesecond
eigenvalue of
-v" =Av, v(O)
=v(l)
= 0. Then there existPROOF. Let u such that supp u C
(0, e).
Thenwhere y+
= Sincesmall.
One has an
analogue
ofproposition
3.5 for this situation.Second,
we note that the condition 0 A~z
becomes morecomplicated
for Dirichlet
boundary
conditions. Theanalogue
of the crucialproposition
4.1is
PROPOSTTION 6.2. Consider
equation (1.1)
with Dirichletboundary
conditions. Let
A2
denote thefirst
and the secondeigenvalue of
and assume that
Then the
singular
set S containsonly fold points
and cusppoints.
PROOF. One