A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
V ILMOS K OMORNIK
A new method of exact controllability in short time and applications
Annales de la faculté des sciences de Toulouse 5
esérie, tome 10, n
o3 (1989), p. 415-464
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- 415 -
A
newmethod of
exactcontrollability in short time
and applications
VILMOS
KOMORNIK(*)(1)
Annales Faculté des Sciences de Toulouse Vol. X, n°3, 1989
RÉSUMÉ. 2014 On introduit une methode nouvelle, generale et constructive pour obtenir des estimations optimales ou presque optimales du temps de controlabilite exacte des systemes d’evolution linéaires. La methode est basee
sur la methode d’unicité hilbertienne (HUM) introduite par J.-L. Lions et
sur une methode d’estimation due a A. Haraux. On applique cette methode
pour plusieurs problemes concrets concernant 1’equation des ondes et de
diverses modeles de plaques.
ABSTRACT. - We introduce a new general and constructive method which allows us to obtain the best or almost the best estimates of the time of exact controllability of linear evolution systems. The method is based
on the Hilbert Uniqueness Method of J.-L. Lions and on an estimation method introduced by A. Haraux. Our method is applied for several concrete
problems related to the wave equation and to various plate models.
0. Introduction
In order to motivate the
investigations
of thepresent
paper, consider thefollowing typical problem :
let 03A9 be aregular,
bounded domain in>
1 )
withboundary 1,,
let T be apositive
number and consider thesystem
~*~ The results of this paper were obtained while the author was visiting the Universite de Savoie (Chambery) and the Universite de Bordeaux I
~l Eotvos Lorand University, Department of Analysis, H-1088 Budapest, Muzeum krt.
6-8, Hungary
We recall the
following
exactcontrollability
result due to L.F. Ho[1]
and J.-L. Lions
[2] :
there exists apositive
numberTo
such that if T >To,
then for every initial data E
L2(S2)
xI~-1(S2)
there exists a controlv E
L2 (0, T; F) driving
the system(o.l)
to rest at time T i. e. such that the solution of(0.1)
satisfiesy(T )
=y’(T )
= 0.According
to the HilbertUniqueness
Method introduced in J.-L. Lions[1],
this result was a consequence of thefollowing
apriori
estimates concer-ning
thehomogeneous system
there exists a
positive
numberTo
such that if T >To,
then for every initial data(ZO,
E nHo (SZ))
xHo (SZ)
the solution of(0.2)
satisfies theinequalities
where
8yz
denotes the normal derivative of z and where c and C arepositive constants, independent
of the choice of(ZO,
The estimates
(0.3)
were provenby
amultiplier
method. Thisprovided
an
explicit
value forTo.
This value was not the best one ; several methodswere
developed
toimprove
the value ofTo
in this and similarproblems.
Themain purpose of this paper is to introduce a new
general
and constructive method which allows one to obtain the best or almost the best value ofTo
. in most exact
controllability problems.
Let us
explain briefly
the main ideas of this method. The first observation is that(0.3)
holds under a weakerassumption
on T if the initial databelong
to a suitable
subspace
of finite codimension of nHo (SZ))
xHo (SZ).
To make this more
precise,
let us denoteby
1]1 1]2 ... theeigenvalues
of -A in
H2(S~)
n letZ2, ...
be thecorresponding eigenspaces
and let w1, w2, ... be a sequence of the numbers
~(r~l )1/2 ~ ~(~2)1/2 ~ .. "
It iswell-known that every solution of
(0.2)
may be written in the formwith suitable vector coeflzcients z~.
Furthermore, introducing
inH2(S2)
f1Ho ( S2 )
t he normf~
and the semi norm
(0.3)
may be written in the formNow the
multiplier
methode allows us to prove thefollowing
result : thereexists a
positive
numberT¿( To)
such that for every T >To
there is apositive integer k
and there arepositive
constants c and C such that(0.5)
holds for all solutions
z(t)
of(0.2) satisfying
=0, Vj
> k.The second observation is that
(0.5)
then extendsautomatically
for allsolutions of
(0.2),
without theassumption zj = 0, V;
k(with possibly
different constants c and
C). Indeed, imagine
for the moment that thecoefficients zj
in(0.4)
are not vectors scalars. Then(0.5)
means that thesystem of
exponential
functions t is a Riesz basis(in
its closed linearhull)
on the interval(0, T).
It is well-known from thetheory
of nonharmonic Fourier series that if we have a Riesz basis ofexponential
functions on aninterval
(0, T)
and if weenlarge
it with a finite number of newexponential functions,
then theresulting system
will be a Riesz basis on every interval withlength greater
thanT ;
cf. e. g. R. M.Young [1]. Recently,
in order toprove some interior
controllability theorems,
anelementary proof
wasgiven
for this result
by
A. Haraux[1] and, fortunately,
thisproof
mayeasily
beadapted
to the moregeneral
case with vector coefficients. This proves(0.3)
for all T >
T~.
The
plan
of this paper is thefollowing :
In section 1 we prove the basic abstract results of the new method.
In section 2 we introduce our method
by improving
two results of J.-L. Lions
[2] concerning
the waveequation.
First we show that lower- order terms of the evolutionequation
do not affect ingeneral
the time ofexact
controllability. Secondly
wegive
anapplication
to aproblem
witha
"strenghtened norm"
; this is atypical
situation forexample
in exactcontrollability problems
with Neumann action.Let us mention that the results of this section may also be obtained
(at
least if theboundary
of the domain and thepotential
function is verysmooth) by
apowerful
method of C.Bardos,
G. Lebeau and J. Rauch[1]
(based
on microlocalanalysis) developed
forhyperbolic systems.
Sections 3 and 4 are devoted to two
problems
raised in J.Lagnese
andJ.-L. Lions
[1].
Section 3 is devoted to the exactcontrollability
of Kirchoffplates.
We prove the convergenceof
theoptimal
exact controlfunctions
when the uniform thickness of the
plate
tends to zero. In Section 4 we prove theuniform
exactcontrollability
of Mindlin-Timoshenkoplates
withrespect
to the shear modulus.
Other
applications
aregiven
in V. Komornik[5], [6] .
The author is
grateful
to A.Haraux,
J.-L. Lions and E. Zuazua for fruitful discussions.1. Norm estimates
L1. - Formulat ion of the results
Let H and V be two real or
complex,
infinite-dimensional Hilbert spaces with a dense and continuousimbedding
V C H.Identifying H
with its(anti)dual
H’ we obtain V C H c V’.Let
a(u, v)
becontinuous; symmetric (rep. hermitian)
bilinearform
on V.Then there exists a
unique
bounded linearoperator
A’ : V -~ Y’ such thata(u, v)
=A’u,
v > , ,Vu,
v E V. Let us introduce in H theoperator
Agiven by D(A)
:={v
E EH~,
Av := A’v for all v ED(A).
Assume that there exist two
positive
constants ao and ai such thatand let s be an
arbitrary nonnegative
real number. Let us introduce forbrevity
the notationThen it is well-known
(cf.
J.-L. Lions and E.Magenes [1])
that for everyinitial data
(uo,
E LVs theCauchy problem
has a
unique
solution u =u(t)
inC(R; D((A
+ nC1(R; D((A
+a1 I ) s )) (The equation
in( 1.2)
is understood in thefollowing
sense :Furthermore,
we have the conservation of energy :Let p be a semi norm on WS. For every
compact
interval I C R we may define a new semi norm on W~by
the formulaThe purpose of this section is to find conditions
ensuring
that this seminorm is
equivalent
to(or stronger than)
the norminduced
by
V x H on W ~ .Let us assume that the
imbedding
V C H iscompact.
Then theeigenvalue problem
has an infinite sequence of
eigenvalues
and a
corresponding
sequenceZl, Z2, ...
ofpairwise orthogonal (in H),
finite-dimensional
eigenspaces
whoseorthogonal
direct sum isequal
to H.For every
positive integer k,
let us denoteby W:
thesubspace
of Wsconsisting
of those elements(u, v),
for which both u and v areorthogonal
inH to the
subspaces Z;
forall j
k.(If k
=1,
thenW~
=Ws.)
It is clearthat if
(UO, u1 )
EWk then
the solution of(1.2)
satisfies(u(t), u’(t))
EWk
for all t E R.
We shall prove the
following
result.TIIEOREM A. Let be a
positive integer.
Assume thatfor
everyinteger
k >ko
there is acompact
intervalI~,
C R and there arepositive
constants ck and
Ck
such thatAssume also that
for
everypositive integer
kko
there is acompact interval Ik
C R and there arepositive
constants ck andCk
such thatLet us denote
by I
thelengh of Ik
and setThen
for
everycompact
interval I C Rof length> To,
there are twopositive
constants c and C such thatMoreover, if
we denoteby
k the leastpositive integer
k >ko
such that(
then the constants c and C may be chosen to be continuousfunctions of
the numbers c~,Cj,
r~~ andof
theend-points of
the intervalsh for j
=1, ... ,1~.
0Remark 1.1. It is clear if condition
(1.8)
is satisfied for somepositive integer k,
then it is satisfiedautomatically
for everygreater
value of k withthe same interval and the same constant. In the
applications, however,
weshall
usually
obtain asequence I
ofdecreasing length : [ > ~ i
>... 0
Remark 1.2. Let us
emphasize
thatTo
does notdepend
onIk
fork
ko.
Infact,
as we shall see later(cf. Proposition C),
if(1.9)
is satisfied forsome compact interval
Ik ,
then it is satisfied for everycompact
subinterval of R(with
different constants c,(in general).
DRemark 1.3. 2014 Theorem A
implies
inparticular
that for > To the seminorm
(1.4)
is in fact a norm. As a consequence, we obtain thefollowing
uniqueness
theorem : ifu(t)
is a solution of thesystem (1.2)
such thatp(u(t), u’(t))
vanishes in some interval oflenght
>To,
thenu(t)
vanishesidentically
on R. 0Remark 1.4. The last assertion of the theorem will follow from the constructive character of the
proof ;
hence we shall obtainexplicit
constantsc and C. This will be
important
whendealing
withsystems depending
ona
parameter,
cf Section 3 below.Remark 1.5. - If k is a
positive integer
such that thecorresponding eigenvalue ~k
ispositive,
then the natural norm of V x H isequivalent
to the square root of the energy
(1.3)
on thesubspace W: (and
thereforealso on its
subspace Zk
xZk ) .
In this case we may(and
weshall) replace
+
by u1)
in(1.8)
and(1.9).
0We shall encounter several
problems
where theright
side estimate of condition(1.8)
of Theorem A will not be satisfied.(This
will occur forexample
when we"strenghten"
the semi normp.)
Then we shallapply
thefollowing
result.THEOREM B. - Let k be a
positive integer.
Assume thatfor
everyinteger
1~ >
ko
there is acompact
intervalIk
C R and apositive
constant ck suchthat the solution
of (1.2~ satisfies
Assume also that
for
everypositive integer
kko
there is acompact
intervalI~;
C R such thatThen
for
everycompact
interval I C Rof length > To,
there is apositive
constant c such that
Remark 1.6. Remark that
To
does notdepend on |Ik|
for kk0
.Indeed,
as we shall see inProposition
Cbelow,
if(1.12)
is satisfied for somecompact
intervalIk,
then it is satisfied for everycompact
subinterval of R. 0Remark 1.7. We have the same
uniqueness
theorem as in Remark1.3. 0
Remark 1.8. We remark that the
proof
of TheoremB, given below,
isnot constructive. As a consequence, we do not obtain
explicitly
a constantc
satisfying (1.13).
DRemark 1.9. If > 0 for some
J~,
then we may(and
weshall) replace
+
by E( uO,
in thecorresponding
condition(1.11).
aLet us note that the real case of both theorems follows
easily
fromthe
complex
oneby
a standardcomplexification argument. Indeed,
let usintroduce the
complexification H, V, Ws, Wj, , a(., . ) by
the usual way(cf.
P. R. Halmos
[1]),
and define on WS a semi normp by
the formulaIt is easy to
verify
that if thehypotheses
of Theorem A or Theorem Bare satisfied in the real case, then the
corresponding
conditions are satisfied in thecomplexified
case, too.Applying
thecorresponding
theorem in thecomplex
case, our conclusion contains the desired real estimate(1.10)
or(1.13)
as aspecial
case.In view of this remark we shall restric ourselves in the
sequel
to thecomplex
case.Finally
we shall prove thefollowing
result whichpermits
toreplace
condi-tion
(1.9)
of Theorem A or condition(1.12)
of Theorem Bby
astationary
condition. Here we denote
by p the complexification
of p.(Naturally, p = p
in the
complex case.)
PROPOSITION C. - Let k be a
positive integer. If
there is acompact
interval I C R such thatwhere =
(r~,~)1~2 if
r~k > 0 and w =2(-~k)1~2 if
~k 0.Conversely, if
this lastproperty
issatisfied,
thenfor
every compact interval I c R there exist twopositive
constants c and Csatisfying
In subsection 1.2 we prove Theorem A in the
special
case where allthe
eigenvalues
arepositive.
This is sufficient for manyapplications
ofthe present paper. Our
proof
isessentially
a vector extension of a method introduced in A. Haraux[1].
Theproof
of Theorem A in thegeneral
case isgiven
in Subsection 1.3. Subsection 1.4 is devoted to theproof
of TheoremB,
andProposition
C isproved
in Subsection 1.5.1.2. Proof of theorem A when all the
eigenvalues
arepositive
First of
all,
in this case we may(and
weshall)
take a1 = 0 in(1.1).
In order to
simplify
the calculations we setThen for every E W’ the solution u =
u ( t )
of(1.2)
isrepresented by
aunique convergent (in C(R; D(A’+1/2))
nC1(R; D(A’)))
seriesConversely,
every such function is a solution of(1.2)
for some initial data E W s.In the
sequel by
solution we shall mean anarbitrary
function u EC(R; D(As+1~2))
nC1(1.~; D(A9))
of the form(1.14).
We shall use for
brevity
the notationIt is easy to
verify
that the norm + isequivalent
toWe may
(and
weshall)
thereforereplace ~u°~2v + ~u1~2H by (1.8) - (1.10).
We have the
following
lemma.LEMMA 1.10. 2014 Assume that
for
someinteger k
> 2 andfor
somepositive
numbers T and
d1
we havefor
all solutionsu(t)
such that u1 = u2 = ... = uk_1 = 0.Then
for
every ~ > 0 there is apositive
constantd2
such thatfor
all solutionsu(t)
with u1 = u2 = ... = uk-2 = o.The constant
d2 depends only
ond1,
~ and on min :j
>k}.
Proof.
- Letu(t)
be anarbitrary
solutionsatisfying
u1 = u2 = ... =uk-2 = 0. Let us
introduce, following
A. Haraux[I],
theauxiliary
functionAn easy calculation shows that
so that we may
apply
the estimate(1.16)
forv(t).
Sincethere existes a
positive
constantd3, independent
of the choice ofu(t~,
suchthat
On the other
hand,
from the definition ofv(t)
we deduce the estimatesCombining
with(1.19),
the lemma followsby taking d2
=dl d3 /4
ClNext we prove the
following simple
lemma.LEMMA 1.11.2014 Let k be a
positive integer.
a)
Assume thatfor
somecompact
interval I c R andfor
somepositive
constant c we have
Then the same
inequality
holdsfor
everycompact
interval I c R with asuitable
positive
constant cdepending
on~I~.
b)
Assume thatfor
some compact interval I C R andfor
somepositive
constant c we have
Then the same
inequality
holdsfor
everycompact
interval I C Rhaving
atleast the same
length
as the above one, with the same constant c.Proof.
- It is sufficient to prove the lemma for the translates of the intervalI;
thegeneral
case ofa)
hence followsby
thetriangle inequality,
while the
general
case ofb)
is then obvious.If for
example
theinequality
ina)
is satisfied for some interval I =[a, b],
,then for every s E R on the interval I’ =
[a
+ s, b +s]
we haveApplying
ourhypothesis
we obtainSince [
=1,
thiseyields
the desiredinequality
for I’ with the sameconstant c.
The
proof
of the caseb)
isanalogous.
DNow it is easy to establish the
following proposition.
LEMMA 1.12.- Assume that
for
someinteger
m > 2 andfor
somepositive
numbersT, d1
andd4
we havefor
all solutionsu(t)
such that ul - ... = u,.,z._1 =0,
andfor
all solutionsu(t)
such that u j = 0for
allj ~
m - 1.’
Then for
every ~ > 0 there exist twopositive
constantsd5
andd6
suchthat
for
all solutionsu(t)
such that u1 = ... = u,.,.t_2 = 0Furthermore, d5
andd6 depend only
onT,
~,d1, d4
and on03C9m-1| : j ~ m}.
Proo f
. Given a solution u =u(t)
with u l = ... = u,.,.t _2 =0,
let usput
for
brevity
Using
thetriangle inequality, (1.20)
andapplying
Lemma 1.10 we obtainthat
i. e. the left side
inequality
of(1.21)
is satisfied withThe
right
sideinequality
of(1.21)
followseasily from (1.20),
firstapplying
the
triangle inequality
for the seminorm ~ ~ ~~
and thenusing
Lemma 1.11.We may take for
example
Finally
we need thefollowing
variant of Lemma 1.11 :LEMMA 1.13. -. Let k be a
positive integer.
Assume that there exists acompact interval I c R and
positive
constantsd7, d8
such thatfor
all solutionsu(t)
with uj = 0for
allj ~
k. Then the sameinequality
holds
for
every compact interval I’ C R insteadof I,
with suitablepositive
constants
d?
andd8.
.Proof.-Since
w; ER, ~j ~ 1,
the functionp(u(t),u’(t))
is in factindependant
of t :Hence,
if I’ C R is anarbitrary
compactinterval,
then the desiredinequality
holds
with dh
=(II’IIIII )d7
andd8
= pNow we turn to the
proof
of the theorem.Let n > ko
be the leastinteger
satisfying |In|
. It follows from(1.8)
and from Lemma 1.11 that forevery compact interval J c R of
length J ~
there exist twopositive
constants c and C such that
for all solutions
u(t) satisfying
u1 = ... = u2n-2 = 0. If n =1,
then Theorem A followsby taking
J = I.If n > 1,
then weapply
Lemma 1.12 with m = 2n -1 and with T >arbitrary.
Condition(1.20) is
satisfiedby (1.23), (1.8), (1.9)
and Lemma 1.13(we
use( 1.8)
if and(1.9)
if m -1ko ) . Applying
Lemma 1.13and then
using
Lemma 1.11 we find that for everycompact
interval J c R oflength IJI >
the estimates( 1.23)
hold for all solutionsu(t) satisfying
u1 = ... = 2L2n-3 = 0
(the
constants c, C are notnecessarily
the same asbefore).
Repeating
thisargument
2n - 3 times we obtain that for every compact interval J C R oflength J~
> the estimates(1.23)
hold for all solutions.Putting
J = I hence the estimates(1.10)
of Theorem A followThe last assertion of Theorem A follows from the
analysis
of theexplicit
constants obtained
during
theproof
DL3. Proof of theorem A in the
general
caseWe shall use the
following
notations : if = 0 for somej’,
then setIf
all
theeigenvalues
are different from zero, then letj’
be the first index’such
that > 0 and setUsing
thisnotation,
there is a one-to-onecorrespondance
between the elements( u ° , u 1 )
of W ~ and theconvergent
series of the formin
C(R; D((A
+a1I)s+1/2))
nC~ (R; D((A
+a1I )s )),
the latterbeing
thesolution of
(1.2).
In thesequel by
solution we shall mean anarbitrary
function u E
C(R; D((A
+aII)s+1~2))
nC1 (1.~; D((A
+ of the form(1.25). Introducing
in V the norm =(a(v, v)
+(cf. (1.15)),
we have
again
theequivalence
ofThe
proof
of Theorem A in thegeneral
case follows the same line as in thespecial
case considered before :Lemma 1.10 remains valid with the
only
modification thatd2 depends
now also on S
(cf. (1.24)).
There are two smallchanges
in theproof :
- Since the numbers are not
necessarily real, (1.18)
is not obvious.However,
thanks to(1.24),
it is satisfied if we choose c > 0sufficiently
small.
- In the last estimates of the
proof
we obtain the factor 2 + instead of4;
hence(1.17)
follows withd2
= +Lemma 1.11 remains
valid,
too, with theonly change
that the constantsc now
depend
on I. In casea)
we obtain theinequality
while in case
b)
we haveTherefore it is sufficient to find two
positive
constants c’ and c" such thatThis is satisfied for
example
if we take(to
obtain c’ we maydistinguish
the cases >21s I
and~~ul~~ _ 2ISI (
Lemma 1.12 and its
proof
remain validexcept
that we have to write u2t instead ofeverywhere. Again,
since weapply
Lemma1.10,
theconstants
d5, d6
will nowdepend
also on S.Finally,
Lemma 1.13 remainsvalid,
too, but theproof
isslightly
differentif wk is
imaginary.
If k~ 2,
then we have the formulawhence the desired
inequality
followseasily
withThe case k = 2 is more technical.
Clearly
it is sufficient to find twopositive,
continuous real functions defined in
{~a, b)
ER2
: ab}
such thatThe
right
side of(1.26)
follows at once from thetriangle inequality
andfrom the
Cauchy-Schwary inequality.
We havewhence the
right
sideinequality
of( 1.26)
is satisfied withTo prove the reverse
inequality
first we write theinequality
this may be obtained
again by applying
thetriangle inequality
and theCauchy-schwarz inequality. Choosing s = (b - a)/2
andintegrating by t
from a to a -~- s we find
Next we write the
inequality
Integrating by t
from a to b and thenusing (1.27)
we obtainThe left side
inequality
of(1.26)
now follows from(1.27)
and(1.28) by taking
1.4. Proof of theorem B
We use the same notations as in the
preceeding
subsection. First wenote that condition
(1.12) implies
in fact condition( 1.9)
becauseZk
xZk
iffinite-dimensional.
Using
thisremark,
we mayrepeat
theproof
of TheoremA, replacing
Lemma 1.12by
thefollowing
one : :LEMMA 1.14. Assume that
for
someinteger
m > 2 andfor
somepositive
numbers T anddl
we havefor
all solutionsu(t)
such that u1 = ... = ur,.t_1 =0,
andfor
all solutionsu(t)
such that u j = 0for
allj ~
m - 1.Then
for
every ~ > 0 there exists apositive
constantds
such thatfor
all solutionsu(t)
such that ul = ... = = 0.Proof
. Let us denoteby
Y(resp. by
the vector space of all solutionssatisfying
u 1 = ... = = 0( resp.
u 1 = ... = u,.,.,, _ 1 =0)
and letya be finite-dimensional vector space of all solutions
satisfying
u j = 0 forall j =I
m - 1. Then Y is the direct sum of Y°‘ andYb.
Given u E Yarbitrarily,
we introduce the same notationsua, ub,
as in theproof
Lemma 1.12.(If
nz =3,
thenaccording
to thepreceeding
subsectionwe set
ua(t)
= u2 t instead of Then we have thedecomposition
,
Let us observe that the semi is in fact a norm on Y.
Indeed,
if u E Y and =
0,
thenapplying
Lemma 1.10 to(1.29)
we obtainwhence
ub =
0 and u = ua.Now
applying (1.29)
for u = ua we find = = 0 i. e. u = 0.We shall prove the lemma
by
contradiction.Assuming
that(1.30)
doesnot
hold,
in view of Lemma 1.10 there exists a sequence C y suchthat, using
thedecompositions
un =un
+un, un
EYa, ubn
EYb,
we haveBeing
Yafinite-dimensional,
we may also assume(taking
asubsequence
if
needed)
that converges :Since
( ~ ( ~
is also a norm on the finite-dimensional spaceYa, ( 1.34) implies
that
From
(1.32)
and(1.35)
we conclude thatbelongs
to the closure ofYb
with
respect
to thenorm ~ ~ (~
in Y. Ourhypothesis (1.29) implies
thatThis
inequality
extendsby continuity
for all u E Y in the closure ofYb
withrespect to ~ ~ ~ ~ .
Inparticular
we haveUsing (1.32), (1.33), (1.35)
andletting n
--~, we obtain that~~ *
= 1.On the other
hand,
it follows at once from(1.31)
and(1.34)
that= 1. This contradiction proves the lemma. D 1.5. 2014 Proof of
proposition
CApplying
the samecomplexification argument
as for Theorems A andB,
it is sufhcient to consider the
complex
case.The first
part
of theproposition
is immediate. Assume that there is acompact
interval I C R such thatand let
0 ~ v
EZ;
begiven arbitrarily. Applying (1.36)
withu(t)
=and
using
the obviousidentity
we obtain
Conversely, assuming
that(1.37)
holds for all0 ~ v
eZk,
it is sufficient to prove that(u°, u1 )
6Zk x Zk
and = 0imply u° = ul -
0.Indeed, being Zk
xZk finite-dimensional,
then there exist twopositive
constants c and C such that
Consider first the case
r~~; ~
0. Thenu(t)
has the formand from the
hypothesis p(u(t),
= 0 we deduce thatUsing
thehomogenity
of p andapplying
thetriangle inequality
hence weobtain
for all
t, s
E I.Choosing t, s
such that0, using
thehomogenity of p
andfinally applying ( 1.37)
we obtain v = 0. We may proveby
the sameway that w = 0. Hence
u(t)
= 0 and u° =ul
= 0.Consider now the case qk = 0. Then
u(t)
has the formRepeating
the aboveargument
now we obtainChoosing t 7~
s,using
thehomogenity of p
andapplying (1.37)
we obtainv = 0.
Substituting
this result into(1.38)
we obtainp(w, 0) =
0whence, using (1.37) again,
w = 0. Henceu(t)
= 0 and u° =u1
= 0. 02.
Applications
to the exactcontrollability
of the waveequation
The main purpose of this section is to introduce the new estimation method. We shall
improve
some results obtained in J. -L. Lions[2], [3].
In the first subsection pure Dirichlet action is considered. We show that Theorem A allows us to treat
equations containing
apotential
termby
constructive way. The same method may be
applied
in other situations aswell,
to prove that the lower-order terms in the evolutionequation
do notchange
the minimal time of exactcontrollability,
cf. V. Komornik[5], [6].
In the second subsection pure Neumann action is considered. In this case
the "natural" semi norm p is not a norm; this motivates the introduction of
strenghtened
norms. This is atypical
situation for theapplication
ofTheorem B.
2.1. A
problem
with a lower order termLet 03A9 be a
non-empty, bounded,
connected open set inRN (N
=1, 2, ... ) having
aboundary
r of classC2,
and denoteby v(x)
=(vl (x),
..., vN(x))
the unit normal vector to
r,
directed towards the exterior of n. Fix apoint
x ° E
RN arbitrarily
and setwhere
RN,
and . denotes the scalarproduct
inRN.
Let q : ~ -->
R’
be a functionsatisfying
Then, applying
the Sobolevimbedding
theorem and theinterpolational inequality,
there arepositive
constants ao, ai such thatConsider the
following system :
(As usual,
we writeu’,
u" for It is well-known that for every initial date E nH® (SZ))
xHo (SZ), (2.3)
has aunique
solution
u E
C(R;
nHo (S~))
nC1(R~ Ho (~))~
The purpose of this subsection is to prove the
following
estimate :THEOREM 2.1.-- Assume
(,~.1~, (2.2)
and let I C R be acompact
interval
of length (.I)
>2Ro.
. Then there exist twopositive
constants c and Csuch that
for
every E nHo (~))
xHo (SZ),
solutionof (,~. ~3~
satisfies
thefollowing inequalities :
:(In (2.4) ayu
denotes the normal derivativeof u.~
Remark 2.2. - In the
special
case q = 0 these estimates were obtainedby
L. F. Ho[1]
under astronger hypothesis
on and thenby
J. -L.Lions
[2]
under the abovehypothesis ~I~
>2Ro, using
a non-constructivecompactness-uniqueness argument.
Later a constructiveproof
wasgiven
inV. Komornik
[1], [2] (cf.
also J.-L. Lions[3]).
The caseq >
0 of Theorem2.1 was
proved
earlier in V. Komornik and E. Zuazua[2], using
an indirectargument. Applying
the samemethod,
E. Zuazua[3] proved
also a variantof Theorem
2.1,
under theassumption
q E xI).
0Remark 2.3.
Applying
HUM as in J.-L. Lions~2J, ~3~,
Theorem 2.1implies
the exactcontrollability
of thesystem
in the
following
sense : if T >2Ro,
then for every initial data(yO, y1 )
EL2(n)
xH ~ 1 ( SZ )
we can find acorresponding
control v E x(0,T)) driving
the system(2.5)
to rest in timeT,
i. e. such thatyeT)
=y’(T)
= 0.For the
presentation
of the HUM method(Hilbert Uniqueness Method)
werefer to J.-L. Lions
[1], [2], [3].
DProof of
Theorem ,~.1. We aregoing
toapply
Theorem A with V =Ho (SZ), H = L2(S2), a(u, v)
=the
integer ko
will be chosen later. Then we introduce theeigenvalues
r~~,the
eigenspaces Zk,
the spaces and the energy Eaccording
tothe
general
scheme described in Subsection 1.1. We have inparticular
It follows from
(2.1)
and(2.2)
that the bilinear forma(u, v)
is continuouson V and satisfies the condition
(1.1).
To prove the
properties (1.8)
and(1.9)
weadapt
the method in J.-L.Lions
[2], ~3~ ,
with an extraargument
if we cannot choose ai = 0 in(2.2).
First we choose an
arbitrary
function h E such that h = v on P.Multiplying
theequation (2.3) by h ~
Vu andintegrating by parts
onr x J where J c R is an
arbitrary compact interval,
we obtaineasily
theestimates ,
with a constant C’
depending
on J. Inparticular,
theright
sideinequalities
in
(1.8)
and(1.9)
are satisfied for everycompact
intervalI~.
To prove the reverse
inequality
wereplace
themultiplier h
. Vuby
2m . +
(N - 1)u.
We obtain for every T > 0 theidentity
Let k be a
positive integer
and assume that(u°, u1 )
EW~ ~2.
In thefollowing
estimates0(1)
and0(1)
will denote diverse constantsdepending only
on k(i.
e.independent
of t E R and of the choice of(UO, u1 )
EW~~2)
and
being
bounded resp.converting
to zero as k - oo.Furthermore,
in orderto