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Ann. I. H. Poincaré – AN 31 (2014) 1–22

www.elsevier.com/locate/anihpc

Existence and qualitative properties of solutions to a quasilinear elliptic equation involving the Hardy–Leray potential

Susana Merchán

a

, Luigi Montoro

b

, Ireneo Peral

a,

, Berardino Sciunzi

b

aDepartamento de Matemáticas, Universidad Autónoma de Madrid, 28049 Madrid, Spain bDipartimento di Matematica, UNICAL, Ponte Pietro Bucci 31 B, 87036 Arcavacata di Rende, Cosenza, Italy

Received 10 September 2012; accepted 18 January 2013 Available online 1 February 2013

Abstract

In this work we deal with the existence and qualitative properties of the solutions to a supercritical problem involving the

p(·)operator and the Hardy–Leray potential. Assuming 0∈Ω, we study the regularizing effect due to the addition of a first order nonlinear term, which provides the existence of solutions with a breaking of resonance. Once we have proved the existence of a solution, we study the qualitative properties of the solutions such as regularity, monotonicity and symmetry.

©2013 Elsevier Masson SAS. All rights reserved.

MSC:35J20; 35J25; 35J62; 35J70; 35J92; 46E30; 46E35

Keywords:Quasilinear elliptic equations; Hardy potential; Supercritical problems; Existence and nonexistence; Regularity; Symmetry of solutions

1. Introduction

In this paper we shall study the existence and qualitative properties of weak positive solutions to the supercritical problem

pu+ |∇u|p=ϑ uq

|x|p +f inΩ, u0 inΩ, u=0 on∂Ω,

(P)

whereΩis a bounded domain inRNsuch that 0∈Ω,ϑ >0,p−1< q < p,f 0,fL1(Ω)and 1< p < N. The existence in the semilinear casep=2 has been investigated in the recent work[15]. We start giving the following definition.

S.M., L.M. and I.P. have been partially supported by project MTM2010-18128 of MICINN Spain. L.M and B.S. are partially supported by PRIN-2009-grant:Metodi Variazionali e Topologici nello Studio di Fenomeni non Lineari. B.S. is also supported by ERC-2011-grant:Elliptic PDE’s and symmetry of interfaces and layers for odd nonlinearities.

* Corresponding author.

E-mail addresses:susana.merchan@uam.es(S. Merchán),montoro@mat.unical.it(L. Montoro),ireneo.peral@uam.es(I. Peral), sciunzi@mat.unical.it(B. Sciunzi).

0294-1449/$ – see front matter ©2013 Elsevier Masson SAS. All rights reserved.

http://dx.doi.org/10.1016/j.anihpc.2013.01.003

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Definition 1.We say thatuis a weak solution to

pu+ |∇u|p=ϑ uq

|x|p +f inΩ, ifuW01,p(Ω)and

Ω

|∇u|p2(u,φ)+

Ω

|∇u|pφ=ϑ

Ω

uq

|x|pφ+

Ω

f φφW01,p(Ω)L(Ω).

The behavior of the supercritical problem with 0∈∂Ωis quite different. See details in[10]and[15]forp=2 and [16]for thep-Laplacian case 1< p < N.

In this work we consider 0∈Ω and, because of the regularizing effect due to the presence of the gradient term

|∇u|pon the left-hand side of problem (P), we are able to prove the existence of a weak solutionu(see Definition1) to problem (P), remarkably for anyϑ >0 and for eachfL1(Ω), f 0. As nowadays well understood, the solution obtained is calledsolutions obtained as limits of approximations, or simply SOLA, see[5]. By using the results in[6]

in this case SOLA is equivalent toentropy solution, see[1], orrenormalized solution.

We have the following result:

Theorem 1.Consider problem(P)with1< p < N,p−1< q < pand assume thatfL1(Ω)is a positive function.

Then for allϑ >0there exists a weak solutionuW01,p(Ω)to(P).

This result emphasizes the fact that the term |∇u|p on the left-hand side of (P) is enough to get a resonance breaking result. The scheme of the proof is the following:

(i) We prove the existence of a solution to the truncated problem

puk+ |∇uk|p=ϑ Tk uqk

|x|p

+Tk(f ) inΩ, ukW01,p(Ω).

whereTk(s)=max{min{k, s},k},k >0. This is done by solving the regularized problem (3) below and passing to the limit inW01,p(Ω).

(ii) We show that the sequence of solutions to the truncated problem converges weakly inW01,p(Ω)and then we deduce the a.e. convergence of the gradients. Finally we exploit it to deduce strong convergence inW01,p(Ω).

(iii) We pass to the limit in the truncated problem and we obtain the existence of a solution to (P).

Let us remark that, because of the presence of the gradient term (which causes the existence of solutions), to pass to the limit in the truncated problem it is necessary to deduce the convergence ofuk(solutions of the truncated problem) inW01,p(Ω). A convergence inW01,q(Ω)withq < p, in the spirit of[3], would not be sufficient to pass to the limit and get a weak formulation of the problem.

In the second part of this paper we deal with the study of the qualitative properties of weak solutions to (P). First we point out some regularity properties of the solutions and then we prove the following result:

Theorem 2.LetuC1\{0})be a weak solution to(P). Consider the domainΩstrictly convex w.r.t. theν-direction SN1)and symmetric w.r.t.T0ν, where

T0ν=

x∈RN: x·ν=0 .

Moreover, assumefC1\ {0})to be non-decreasing w.r.t. theν-direction in the set Ω0ν= {xΩ: x·ν <0}

and even w.r.t.T0ν. Thenuis symmetric w.r.t.T0νand non-decreasing w.r.t. theν-direction inΩ0ν. Moreover, ifΩ is a ball, thenuis radially symmetric with ∂u∂r(r) <0forr=0.

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Remark 1.Notice that the extra regularity hypothesis onf is sufficient to have the corresponding regularity of a solution. See[20]for details on regularity.

We point out that Theorem2will be a consequence of a more general result, see Proposition3below, which states a monotonicity property of the solutions in general domains near strictly convex parts of the boundary. This can be useful for example in blow-up analysis.

Also, it will be clear from the proof, that the same technique could be applied to study the case of more general nonlinearities. In particular, we note that the nonlinearity in problem (P) is in general locally Lipschitz continuous only in(0,).

The main ingredient in the proof of the symmetry result is the well knownMoving Plane Method[21], that was used in a clever way in the celebrated paper[12]for the semilinear nondegenerate case. Actually our proof is more similar to the one of[2]and is based on the weak comparison principle in small domains. TheMoving Plane Method was extended to the case ofp-Laplace equations firstly in[7]for the case 1< p <2 and later in[9]for the casep2.

In the casep2 it is required the nonlinearity to be positive and as can be seen in some examples, this assumption is in general necessary.

The first crucial step is the proof of a weak comparison principle in small domains that we carry out in Proposition2.

This is based on some regularity results in the spirit of[9]. These results hold only away from the origin due to the presence of the Hardy potential in our problem. This will require more attention in the application of the moving plane procedure. Moreover, the presence of the gradient term|∇u|p, leads to a proof of the weak comparison principle in small domains which makes use of the right choice of test functions.

Notation.Generic fixed numerical constants will be denoted byC(with subscript in some case) and will be allowed to vary within a single line or formula. Moreoverf+andfwill stand for the positive and negative part of a function, i.e.f+=max{f,0}andf=min{f,0}.We also denote|A|the Lebesgue measure of the setA.

2. Existence of an energy solution to the problem (P)

It will be useful to refer to the following result.

Lemma 1(Hardy–Sobolev inequality). Suppose1< p < N anduW1,p(RN). Then we have

RN

|u|p

|x|p CN,p

RN

|∇u|p,

withCN,p=(Npp)poptimal and not achieved constant.

2.1. Existence of a solution to the truncated problem

First, we are going to study the existence of a solution to the truncated problem

puk+ |∇uk|p=ϑ Tk uqk

|x|p

+Tk(f ) inΩ, ukW01,p(Ω), (1) whereTk(s)=max{min{k, s},k},k >0.

Theorem 3.There exists a positive solution to problem(1).

Notice thatφ≡0 is a subsolution to problem (1). Considerψthe solution to −pψ=ϑ·k+Tk(f ) inΩ,

ψ=0 on∂Ω. (2)

In factψturns to be a supersolution to (1).

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To prove Theorem3we will consider a sequence of approximated problems that we solve by iteration and by using some convenient comparison argument. We take as starting pointw0=0 and consider iteratively the problem,

⎧⎨

⎩−pwn+ |∇wn|p

1+1n|∇wn|p =ϑ Tk wnq1

|x|p

+Tk(f ) inΩ,

wn=0 on∂Ω.

(3) Notice that the subsolution φ≡0 and the supersolutionψ to problem (1) are subsolution and supersolution to the problem (3).

Next proposition follows using a comparison argument from[4].

Proposition 1.There existswnW01,p(Ω)L(Ω)solution to(3).

Moreover,0wnψn∈N.

Proof of Theorem3. We proceed in two steps.

Step 1: Weak convergence ofwninW01,p(Ω).By simplicity let us set Hn(wn)= |∇wn|p

1+1n|∇wn|p. (4)

Takingwnas a test function in the approximated problems (3), we obtain

Ω

|∇wn|pdx+

Ω

Hn(wn)wndx=ϑ

Ω

Tk wqn1

|x|p

wndx+

Ω

Tk(f )wndx

ϑ

Ω

kwndx+

Ω

f wndx.

SincewnW01,p(Ω)L(Ω)andfL1(Ω), there exists a positive constantC(k, f, ψ, ϑ, Ω)such that

Ω

|∇wn|pdx+

Ω

Hn(wn)wndxC(k, f, ψ, ϑ, Ω).

Moreover, since

ΩHn(wn)wndx0, we have

Ω

|∇wn|pdxC(k, f, ψ, ϑ, Ω). (5)

Therefore, up to a subsequence,wn uk weakly inW01,p(Ω)andwn uk weakly-* inL(Ω), giving ukW01,p(Ω)L(Ω).

Step 2: Strong convergence ofwninW01,p(Ω)and passing to the limit in (1).To get the strong convergence in W01,p(Ω)first of all we notice that

wnukW1,p

0 (Ω)(wnuk)+

W01,p(Ω)+(wnuk)

W01,p(Ω). (6)

Thus, we proceed estimating each term on the right-hand side of (6).

Asymptotic behaviour of(wnuk)+W1,p

0 (Ω).Choosing(wnuk)+as a test function in (3) we obtain

Ω

|∇wn|p2

wn,(wnuk)+ dx+

Ω

Hn(wn)(wnuk)+dx

=ϑ

Ω

Tk wqn1

|x|p

(wnuk)+dx+

Ω

Tk(f )(wnuk)+dx. (7)

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Since wn uk in W01,p(Ω), one has wnuk a.e. in Ω and thus (wnuk)+ →0 a.e. in Ω together with (wnuk)+ 0 inW01,p(Ω)as well. Therefore, the right-hand side of (7) goes to zero whenngoes to infinity.

Then, since

ΩHn(wn)(wnuk)+dx0, (7) becomes

Ω

|∇wn|p2

wn,(wnuk)+

dx=o(1) asn→ +∞. (8)

Since

Ω

|∇uk|p2

uk,(wnuk)+

=o(1) asn→ +∞, it follows

Ω

|∇wn|p2wn− |∇uk|p2uk,(wnuk)+

dx=o(1). (9)

Then, from (9) we have o(1)=

C1(p) |∇(wnuk)+|2

(|∇wn|+|∇uk|)2p if 1< p <2,

C1(p)|∇(wnuk)+|p ifp2, (10)

withC1(p)a positive constant depending onp. In any case, since for 1< p <2 using Hölder’s inequality one has

Ω

(wnuk)+p

Ω

|∇(wnuk)+|2 (|∇wn| + |∇uk|)(2p)

p

2

Ω

|∇wn| + |∇uk|p2p

2

, (11)

we obtain

(wnuk)+

W01,p(Ω)→0 asn→ +∞. (12)

Asymptotic behaviour of(wnuk)W1,p

0 (Ω).Let us considerewn[(wnuk)]as a test function in (3),

Ω

ewn|∇wn|p2

wn,(wnuk) dx+

Ω

ewn

|∇wn|p

1+1n|∇wn|p − |∇wn|p

(wnuk)dx

=ϑ

Ω

ewnTk wqn1

|x|p

(wnuk)dx+

Ω

ewnTk(f )(wnuk)dx. (13) We point out that using this test function it follows

Ω

ewn

|∇wn|p

1+1n|∇wn|p − |∇wn|p

(wnuk)0. (14)

As above, since(wnuk)→0 a.e. inΩ, the right-hand side of (13) tends to zero as n goes to infinity. Being wnψ(see Proposition1), one hasewnγ >0 uniformly onn. Then Eq. (13) states as

γ

Ω

|∇wn|p2

wn,(wnuk)

dx=o(1). (15)

Arguing in the same way as we have done from Eq. (8) to (12), we obtain (wnuk)

W01,p(Ω)→0 asn→ +∞. (16)

From Eq. (6), by using (12) and (16) we get (wnuk)

W01,p(Ω)→0 asn→ +∞

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and consequently∇wn→ ∇uka.e. inΩ. Then, by (4) followsHn(wn)→ |∇uk|pa.e. inΩand by Vitali’s Lemma, Hn(wn)→ |∇uk|p inL1(Ω).

Hence,ukW01,p(Ω)L(Ω)satisfies the problem in the following sense

Ω

|∇uk|p2(uk,φ)+

Ω

|∇uk|pφ=ϑ

Ω

Tk upk

|x|p

φ+

Ω

Tk(f )φφW01,p(Ω)L(Ω), (17) concluding the proof. 2

2.2. Passing to the limit and convergence to a solutionuof(P)

We want to show thatukustrongly inW01,p(Ω)in order to prove the existence of a solutionuto problem (P).

Proof of Theorem1. We perform the proof in different steps.

Step 1: Weak convergence ofukinW01,p(Ω).We start takingTn(uk)as a test function in the truncated problem (1), obtaining

Ω

Tn(uk)pdx+

Ω

|∇uk|pTn(uk) dx=ϑ

Ω

Tk uqk

|x|p

Tn(uk) dx+

Ω

Tk(f )Tn(uk) dx.

Notice that, defining Ψn(s)=

s 0

Tn(t)1pdt, (18)

one has

Ω

Tn(uk)pdx+

Ω

Ψn(uk)pdx=ϑ

Ω

Tk uqk

|x|p

Tn(uk) dx+

Ω

Tk(f )Tn(uk) dx

ϑ

Ω

uqk

|x|pTn(uk)+nfL1(Ω). (19) By a straightforward calculation it is easy to check that for fixedq∈ [p−1, p),∀ε >0 and∀n >0,there exists Cεsuch that

sqTn(s)εΨnp(s)+Cε s0. (20)

Thanks to Lemma1and (20), Eq. (19) states as

Ω

Tn(uk)pdx+

Ω

Ψn(uk)pdxε ϑ CN,p

Ω

Ψn(uk)p+ϑ Cε

Ω

1

|x|p +nfL1(Ω). Then choosingε >0 such that 0< εCϑ

N,p <1, for some positiveCwe get

Ω

Tn(uk)pdx+C

Ω

Ψn(uk)pdxϑ Cε

Ω

1

|x|p +nfL1(Ω)C(ϑ, ε, f, p, n, Ω). (21) Fixedl1, by definition (18) ofΨland Eq. (21), one has

Ω

|∇uk|pdx

Ω

Tl(uk)pdx+

Ω∩{ukl}

|∇uk|pdx

Ω

Tl(uk)p+1 l

Ω

Ψl(uk)pC, (22) uniformly onk. Therefore, up to a subsequence it followsuk uweakly inW01,p(Ω)and a.e. inΩ.

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Step 2: Strong convergence inL1(Ω)of the singular term.By Hölder inequality we have

Ω

Tk uqk

|x|p

Ω

uqk

|x|p

Ω

upk

|x|pdx q

p

Ω

1

|x|pdx p−q

p C

Ω

|∇uk|p q

pC, (23)

withC a positive constant that does not depend onk. It follows thatTk(u

q

|xk|p)is bounded inL1(Ω)and converges almost everywhere to |ux|qp. In particular Fatou’s Lemma implies|uxq|pL1(Ω). Moreover, letEΩbe a measurable set, by Fatou’s Lemma we have

E

Tk

uqk

|x|p

E

uqk

|x|p lim

n→+∞

E

wnq

|x|p

E

ψq

|x|p δ

|E| ,

uniformly in kwhere lims0δ(s)=0, wn is as in the proof of Theorem3andψ as in Proposition1. Thus, from Vitali’s Theorem it follows

Tk uqk

|x|p

uq

|x|p inL1(Ω). (24)

Step 3: Strong convergence of|∇uk|p→ |∇u|p inL1(Ω).To show the strong convergence of the gradients we need some preliminary results. We have the following

Lemma 2.Letukbe defined by(1). Then

nlim→∞

{ukn}

|∇uk|p=0 (25)

uniformly ink.

Proof. Let us consider the functions

Gn(s)=sTn(s), and ψn1(s)=T1

Gn1(s) .

Notice that,ψn1(uk)|∇uk|p|∇uk|pχ{ukn}. Usingψn1(uk)as a test function in (1) we get

{ukn}

|∇uk|p

Ω

ψn1(uk)p+

Ω

|∇uk|pψn1(uk)

=

Ω

ϑ Tk uqk

|x|p

ψn1(uk)+

Ω

Tk(f )ψn1(uk). (26)

Since {uk}is uniformly bounded in W01,p(Ω), then up to a subsequence, {uk} strongly converges in Lp(Ω) for 1p < p=NNpp and a.e. inΩ. Thus we obtain that

x∈Ω: n−1< uk(x) < n→0 ifn→ ∞, xΩ: uk(x) > n→0 ifn→ ∞,

uniformly onk. Then, from (24) and (26) we have uniformly ink

nlim→∞

{ukn}

|∇uk|p=0. 2 (27)

Next lemma shows the strong convergence of the truncated terms.

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Lemma 3.Consideruk uas above. Then one has uniformly inm, Tm(uk)Tm(u) inW01,p(Ω)fork→ +∞.

Proof. Notice that Tm(uk)Tm(u)

W01,p(Ω)Tm(uk)Tm(u)+

W01,p(Ω)+Tm(uk)Tm(u)

W01,p(Ω). (28) We are going to estimate each term on the right-hand side of (28).

Asymptotic behaviour of (Tm(uk)Tm(u))+W1,p

0 (Ω). We take (Tm(uk)Tm(u))+ as a test function in (1), obtaining

Ω

|∇uk|p2uk,

Tm(uk)Tm(u)+ dx+

Ω

|∇uk|p

Tm(uk)Tm(u)+ dx

=

Ω

ϑ Tk

uqk

|x|p

+Tk(f )

Tm(uk)Tm(u)+

dx. (29)

SinceTm(uk) Tm(u)andTm(uk)Tm(u)a.e. inΩ, we have(Tm(uk)Tm(u))+ 0 inW01,p(Ω)and(Tm(uk)Tm(u))+→0 a.e. inΩ. Thus, the right-hand side of (29), by dominated convergence, tends to zero ask goes to infinity. From (29) we have

Ω

|∇uk|p2uk,

Tm(uk)Tm(u)+

dx=o(1). (30)

We estimate the left-hand side of (30) as

Ω

|∇uk|p2uk,

Tm(uk)Tm(u)+ dx

=

Ω∩{|uk|m}

Tm(uk)p2Tm(uk)−∇Tm(u)p2Tm(u),

Tm(uk)Tm(u)+ dx

+

Ω∩{|uk|m}

Tm(u)p2Tm(u),

Tm(uk)Tm(u)+ dx

+

Ω∩{|uk|>m}

|∇uk|p2uk,

Tm(uk)Tm(u)+

dx. (31)

Since(Tm(uk)Tm(u))+ 0 weakly inW01,p(Ω), denotingχmthe characteristic function of the set{xΩ: |uk|>

m}, the second term on the right-hand side of (31) becomes

Ω∩{|uk|m}

Tm(u)p2Tm(u),

Tm(uk)Tm(u)+ dx

Ω

Tm(u)p2Tm(u),

Tm(uk)Tm(u)+ dx

+

Ω∩{|uk|>m}

Tm(u)p2Tm(u),

Tm(uk)Tm(u)+ dx

o(1)+Cup1

W01,p(Ω)χmTm(u)

Lp(Ω)→0 ask→ +∞,

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since, by dominate convergence again,χmTm(u)→0 strongly in(Lp(Ω))N. As above, the last term in (31) can be estimated as

Ω

|∇uk|p2uk, χmTm(u) dx

Cukp1

W01,p(Ω)χmTm(u)

Lp(Ω)→0, (32)

ask→ +∞.

Considering that, by the dominated convergence theorem, we have

Ω∩{|uk|>m}

Tm(uk)p2Tm(uk)−∇Tm(u)p2Tm(u),

Tm(uk)Tm(u)+ dx

Ω

χmTm(u)p→0 ask→ +∞, Eq. (30) becomes

Ω

|∇uk|p2uk,

Tm(uk)Tm(u)+ dx

=

Ω

Tm(uk)p2Tm(uk)−∇Tm(u)p2Tm(u),

Tm(uk)Tm(u)+

dx+o(1).

Finally we obtain

Ω

|∇uk|p2uk,

Tm(uk)Tm(u)+ dx

C1(p) |∇(Tm(uk)Tm(u))+|2

(|∇Tm(uk)|+|∇Tm(u)|)2p+o(1) if 1< p <2, C1(p)|∇(Tm(uk)Tm(u))+|p+o(1) ifp2,

(33) withC1(p)a positive constant depending onp, which implies (together with (11))

Tm(uk)Tm(u)+

W01,p(Ω)→0 ask→ +∞. (34)

Asymptotic behaviour of(Tm(uk)−Tm(u))W1,p

0 (Ω).We useeTm(uk)(Tm(uk)Tm(u))as a test function in (1) (see Section2.1) obtaining

Ω

eTm(uk)

|∇uk|p2uk,

Tm(uk)Tm(u) dx

Ω

eTm(uk)

Tm(uk)Tm(u)

|∇uk|p2uk,Tm(uk) dx

+

Ω

|∇uk|peTm(uk)

Tm(uk)Tm(u) dx

=

Ω

ϑ Tk

uqk

|x|p

+Tk(f )

eTm(uk)

Tm(uk)Tm(u)

dx. (35)

In this case as well, since(Tm(uk)Tm(u)) 0 weakly inW01,p(Ω)and(Tm(uk)Tm(u))→0 a.e. inΩ, the right-hand side of (35) tends to zero askgoes to infinity.

The first term on the left-hand side of (35), being(Tm(uk))χm=0, states as

(10)

Ω

eTm(uk)

|∇uk|p2uk,

Tm(uk)Tm(u) dx

+

Ω∩{|uk|>m}

|∇uk|peTm(uk)

Tm(uk)Tm(u)

dx=o(1). (36)

We point out that

Tm(uk)Tm(u) χm=0, hence (36) becomes

Ω

|∇uk|p2uk,

Tm(uk)Tm(u)

=Cmo(1) ask→ +∞, (37)

withCma positive constant depending onm.

The choice and use ofeTm(uk)(Tm(uk)Tm(u))as a test function allows to simplify conveniently Eq. (35) in order to obtain the desired result. In fact, we proceed writing the left-hand side of (37) as

Ω

|∇uk|p2uk,

Tm(uk)Tm(u) dx

=

Ω∩{|uk|m}

Tm(uk)p2Tm(uk)−∇Tm(u)p2Tm(u),

Tm(uk)Tm(u) dx

+

Ω∩{|uk|m}

Tm(u)p2

Tm(u),

Tm(uk)Tm(u) dx

+

Ω∩{|uk|>m}

|∇uk|p2uk,

Tm(uk)Tm(u)

dx. (38)

The second term on the right-hand side of (38) can be estimated as follows

Ω∩{|uk|m}

Tm(u)p2

Tm(u),

Tm(uk)Tm(u) dx

=

Ω

Tm(u)p2

Tm(u),

Tm(uk)Tm(u) dx

Ω∩{|uk|>m}

Tm(u)p2

Tm(u),

Tm(uk)Tm(u) o(1)+Cup1

W01,p(Ω)χmTm(u)

Lp(Ω)→0 ask→ +∞, (39)

since by weak convergence the first term on the right-hand side of (39) goes to zero, while the second one goes to zero using (22) and the fact that, for dominated convergence,χmTm(u)→0 strongly inLp(Ω). Moreover, we observe that the last term in (38) is zero since(Tm(uk)Tm(u))χm=0. Finally as above, Eq. (38) becomes

o(1)=

Ω

|∇uk|p2uk,

Tm(uk)Tm(u) dx

C1(p) |∇(Tm(uk)Tm(u))|2

(|∇Tm(uk)|+|∇Tm(u)|)2−p+o(1) if 1< p <2, C1(p)|∇(Tm(uk)Tm(u))|p+o(1) ifp2,

(40) withC1(p)a positive constant depending onp. By (37) and (40) (using (11) again) we get

Tm(uk)Tm(u)

W01,p(Ω)→0 ask→ +∞. (41)

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