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HAL Id: hal-00581771

https://hal.archives-ouvertes.fr/hal-00581771

Preprint submitted on 31 Mar 2011

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and singular problem

Jacques Giacomoni, Habib Mâagli, Paul Sauvy

To cite this version:

Jacques Giacomoni, Habib Mâagli, Paul Sauvy. Existence of compact support solutions for a quasi-

linear and singular problem. 2011. �hal-00581771�

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FOR A QUASILINEAR AND SINGULAR PROBLEM

Jacques Giacomoni - Habib Mˆaagli - Paul Sauvy Abstract. Let Ω be aC2 bounded domain ofRN,N≥2. We consider the following quasilinear elliptic problem:

(Pλ)

−∆pu=K(x)(λuq−ur), in Ω, u= 0 on∂Ω, u≥0 in Ω, where p > 1 and ∆pu def= div`

|∇u|p−2∇u´

denotes the p-Laplacian operator. In this paper, λ > 0 is a real parameter, the exponents q and r satisfy −1 < r < q < p−1 and K : Ω −→ R is a positive function having a singular behaviour near the boundary∂Ω. Precisely, K(x) =δ(x)−kL(δ(x)) in Ω, with 0< k < p,La positive perturbation function andδ(x) the distance ofx∈Ω to∂Ω.

By using a sub- and super-solution technique, we discuss the ex- istence of positive solutions or compact support solutions of (Pλ) in respect to the blow-up ratek. Precisely, we prove that if k < 1 +r, (Pλ) has at least one positive solution forλ >0 large enough, whereas it has only compact support solutions ifk≥1 +r.

1. Introduction

Let Ω be a C

2

bounded domain of R

N

, N 2. We discuss the existence of weak solutions in W

1,p0

(Ω) L

(Ω) to

(P

λ

)

½ −∆

p

u = K(x)(λu

q

u

r

) in Ω, u = 0 on ∂Ω, u 0 in Ω.

u W

1,p0

(Ω) L

(Ω) is a weak solution to (P

λ

) if for all test functions ϕ ∈ D(Ω),

Z

|∇u|p−2∇u.∇ϕ dx= Z

K(x) (λuq−ur)ϕ dx. (1.1)

In the equation in (P

λ

), λ > 0 is a positive parameter, −1 < r < q < p 1 and K ∈ C(Ω) is a positive function having a singular behaviour near the boundary ∂Ω. Precisely, K(x) = δ(x)

−k

L(δ(x)) in Ω, with 0 < k < p and L ∈ C

2

((0, 2d]) a positive function, with d

def

= diam(Ω), defined as follows:

L(t) = exp ÃZ 2d

t

z(s) s ds

!

, (1.2)

1

(3)

with z ∈ C([0, 2d]) ∩ C

1

((0, 2d]) and z(0) = 0. Let us note that (1.2) implies that

t→0lim+ tL0(t)

L(t) = 0 (1.3)

and for allε >0,

t→0lim+tεL(t) = 0 (1.4)

and

t→0lim+t−εL(t) = +∞. (1.5)

The above asymptotics of L force

∀ξ >0, lim

t→0+

L(ξt) L(t) = 1.

Then L belongs to the Karamata class [9]. Setting K the class of functions satisfying (1.2), we get the following properties: if L

1

, L

2

∈ K and if p R, then L

1

.L

2

∈ K and L

1p

∈ K.

Example 1.1. Let m N

and A > 0 large enough. Let us define

L(t) =

Ym

n=1

µ logn

µA t

¶¶µn

, t∈(0,2d]

with log

ndef

= log ◦ · · · ◦ log (n times) and µ

n

> 0. Then L ∈ K.

In the present paper, we investigate first the following issues for the prob- lem (P

λ

):

existence of non-trivial weak solutions according to λ > 0, H¨older regular- ity of weak solutions. Next, we study further the properties of non-trivial solutions. Since the non-linearity in the right-hand side is a singular ab- sorption term near the boundary, a non-trivial weak solution may not be positive everywhere in Ω and compact support (non-trivial) weak solutions or compactons (solutions with zero normal derivative at the boundary) may exist for stronger singularities, that is for large k > 0 whereas for small k > 0 any non-trivial weak solution is positive. Then, the natural question is to determine the borderline condition on the parameter k, which gives the strength of the singular potential K, between existence of positive weak solutions and existence of free boundary weak solutions. The existence of compact support solutions is important in the applications, in particular in biology models (population dynamics and epidemiology models for in- stance) and was investigated quite intensely for nonlinear reaction diffusion equations with absorption in the last decades. In particular, concerning the case where the equation involves a quasilinear and degenerate operator, we can refer to the result in V´ azquez [14] where under a suitable condition about the behaviour of the non-linearity near the origin, a strong maximum principle is proved and consequently the positivity of solutions. The given condition is sharp in the sense that for different situations where this con- dition is not satisfied, the existence of free boundary solutions is shown.

In Alvarez-D´ıaz [2] (see also D´ıaz [4] for related results on the subject),

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the authors consider a class of nonhomogeneous reaction-diffusion equations with strong absorption and study the behaviour of the solution near the free boundary. In particular, a non degeneracy property (the solution grows faster than some function of the distance to the free boundary) is obtained when the growth of the reaction term near the boundary satisfies some esti- mate by below. In Il’yasov-Egorov [8], the authors consider a semilinear equation with a similar (and non singular) conflicting nonlinearity as in the equation in (P

λ

) and the existence of compactons is proved using the fiber- ing method. An interesting feature of this result is that the Hopf lemma is violated for such kind of equations. In the present work, we consider the extension case where the equation involves a p-Laplace operator and a singular potential in the right-hand side and show that a more complex situation occurs in respect to the non singular case.

In the next section, we give the main results proved in this paper. These results extend a previous work due to Haitao [7] in the semilinear case (p = 2) and which involves a smaller class of nonlinearities.

2. Main results

The main results of our paper concerning the problem (P

λ

) are stated below:

Theorem 2.1. When k < 1 + r, there exists a constant Λ

1

> 0 such that:

(1) For λ > Λ

1

, (P

λ

) admits a positive weak solution.

(2) Any weak solution of (P

λ

) is C

1,β

¡ Ω ¢

for some β (0, 1).

(3) For λ < Λ

1

, (P

λ

) has no positive solution.

Theorem 2.2. Let r > 0 and one of the two following conditions be satisfied:

1 +r > q and k∈

»

1 +r,1 +(p1)(r+ 1) p−q+r

«

, (2.1)

1 +r≥q and k∈[1 +r,2 +r). (2.2)

Then, there exists Λ

2

> 0 such that:

(1) For λ > Λ

2

, (P

λ

) has a compact support weak solution u

λ

. (2) Any weak solution of (P

λ

) is C

1,β

¡

Ω ¢

for some β (0, 1).

(3) For λ < Λ

2

, (P

λ

) has no non-trivial solution.

The outline of the paper is as follows. Before giving the proofs of those theorems, we establish some useful preliminary results in the next section.

The proof of Theorem 2.1 is given in section 4 and the proof of Theorem 2.2 is given in section 5. The technical results stated in section 3 are finally proved in appendix A and B. The related regularity results are a conse- quense of the general regularity results stated in appendix C.

Throughout this paper, we will use the following notations:

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(1) To p (1, +∞) we associate p

0def

=

p−1p

. (2) For x Ω, δ(x)

def

= dist(x, Ω) = inf

y∈Ω

d(x, y).

(3) d

def

= diam(Ω) = sup

x,y∈Ω

d(x, y).

(4) Let ω be a non-empty set of Ω and f, g : ω −→ [0, +∞]. We write f (x) g(x) in ω

if there exist two positive constants C

1

and C

2

such that

∀x ω, C

1

f (x) g(x) C

2

f (x).

(5) Let ω R

N

, L

N

(ω) denotes the

N−

dimentionnal Lebegue’s mesure of ω.

(6) Let ε > 0, we define Ω

εdef

= {x Ω, δ(x) < ε}.

(7) ν : ∂Ω −→ R

N

denotes the outward normal associated to Ω.

(8) For v W

1,p0

(Ω), we write kvk

def

= k∇vk

Lp(Ω)

=

µZ

|∇v|pdx

1

p

.

(9) The function ϕ

1

W

1,p0

(Ω) denotes the positive and renormalized

(i.e.

1

k

Lp(Ω)

= 1) eigenfunction corresponding to the first eigen- value of −∆

p

,

λ1def

= inf

½Z

|∇v|pdx, v∈W1,p0 (Ω), Z

|v|pdx= 1

¾ .

It is a weak solution of the following eigenvalue problem:

½ −∆

p

u = λ

1

u

p−1

in Ω,

u = 0 on ∂Ω, u 0 in Ω.

Using Moser iterations and the regularity result in Lieberman [10], ϕ

1

∈ C

1,α

¡

Ω ¢

for some α (0, 1). Moreover the strong maximum and boundary principles from V´ asquez [14], guarantee that ϕ

1

sat- isfies those two properties:

(a) There exist two positive constants K

1

and K

2

only depending on p and Ω such that:

∀x Ω, K

1

δ(x) ϕ

1

(x) K

2

δ(x). (2.3) (b) There exist ε

> 0 and δ

> 0 only depending on p and Ω such

that:

∀x

δ

, |∇ϕ

1

(x)| > ε

. (2.4) 3. Preliminary results

3.1. A non-existence lemma.

Lemma 3.1. When k < 1 + r, there exists λ

> 0 such that (P

λ

) has no

non-trivial solution for λ λ

.

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Proof: Let us define

λ1,Kdef

= inf

v∈W1,p0 (Ω) v6=0

Z

|∇v|pdx Z

K(x)|v|pdx .

From the Hardy’s inequality, there exists a constant C > 0 only depending on Ω and p such that for all v W

1,p0

(Ω),

Z

|v|p

δ(x)pdx≤C Z

|∇v|pdx.

Since k < p, λ

1,K

> 0. Let u W

1,p0

(Ω) L

(Ω) be a non-trivial solution of (P

λ

), then from (1.1) taking u W

1,p0

(Ω) as a test function we get,

0< λ1,K

Z

K(x)updx≤ Z

|∇u|pdx= Z

K(x)¡

λuq+1−ur+1¢

dx. (3.1)

This inequality is impossible for λ λ

def

= min{1, λ

1,K

}. Indeed, - if u(x) 1, λu

q+1

u

r+1

0 as soon as λ 1,

- if u(x) > 1, K(x) ¡

λu

q+1

u

r+1

¢

< λ

1,K

K(x)u

q+1

as soon as λ λ

1,K

. Then, either L

N

({x Ω, u(x) > 1}) = 0 and we get

0< λ1,K

Z

K(x)updx≤0,

or

λ1,K

Z

1{u>1}K(x)updx≤λ1,K

Z

1{u>1}K(x)uq+1dx,

which contradicts q < p 1 .

¥

3.2. Construction of a sub-solution for (P

λ

).

Lemma 3.2. When k < 1 + r, there exist M > 0, λ

> 0 and τ > 1 such that u

λ def

= M ϕ

1τ

is a sub-solution of (P

λ

) in Ω, provided that λ λ

.

Proof: Let M > 0 and τ > 1, then we define u

λ

= M ϕ

1τ

in Ω. A straightforward computation yields

−∆

p

u

λ

= (M τ )

p−1

h

(p 1)(τ 1)|∇ϕ

1

|

p

ϕ

1(τ−1)(p−1)−1

λ

1

ϕ

1τ(p−1)

i

and

K(x) (λu

λq

u

λr

) = −K(x) (M

r

ϕ

1τ r

λM

q

ϕ

1τ q

) . By properties (2.3) and (2.4) of the function ϕ

1

, if we let

δ0def

= min (

δ, ε K2

„(τ1)(p1) 2λ1

«1 p, 1

K2

„ 1

2λMq−r

« 1 τ(q−r)

) ,

both of the above expressions are negative on Ω

δ0

. Moreover,

p

u

λ

(x) (M τ )

p−1

1)δ(x)

(τ−1)(p−1)−1

in Ω

δ0

(7)

and

K(x) (u

λr

λu

λq

) M

r

L(δ(x))δ(x)

τ r−k

in Ω

δ0

. Since k < 1 + r, we can choose a constant τ > 1 satisfying

1)(p 1) 1 < τ r k.

Hence, for M > 0 large enough we get −∆

p

u

λ

K(x) ¡

λu

qλ

u

rλ

¢

in Ω

δ0

. In Ω \

δ0

, K, ϕ

1

and |∇ϕ

1

| are bounded, therefore there exists λ

> 0 such that for λ λ

, −∆

p

u

λ

K(x) ¡

λu

qλ

u

rλ

¢

in Ω \

δ0

. Thus, u

λ

is a sub-solution of (P

λ

) in Ω for M large enough and λ λ

.

¥

3.3. Construction of a super-solution for (P

λ

).

We consider the following problem:

(Q)

½ −∆

p

v = K(x)v

q

in Ω,

v = 0 on ∂Ω, v > 0 in Ω, with q, p and K satisfying the above assumptions.

Lemma 3.3.

(1) If k (0, 1 + q), (Q) has a unique solution v W

1,p0

(Ω) ∩ C ¡ Ω ¢ satisfying

v(x)∼δ(x) inΩ.

(2) If k = 1+ q, (Q) has a unique solution v W

1,p0

(Ω)∩C ¡ Ω ¢

satisfying

v(x)∼δ(x) Z 2d

δ(x)

L(t) t dt

! 1

p−k

inΩ.

(3) If

k∈

³

1 +q,1 +q+p−(1+q)p

´

, (Q) has a unique solution

v∈W1,p0 (Ω)∩

C¡ Ω¢

satisfying

v(x)∼δ(x)p−(1+q)p−k

³

L(δ(x))

´ 1

p−(1+q)

inΩ.

(4) If

k∈ h

1 +q+p−(1+q)p , p

´

, (Q) has a unique solution v W

loc1,p

(Ω) C

0

¡

Ω ¢

satisfying

v(x)∼δ(x)p−(1+q)p−k

³

L(δ(x))

´ 1

p−(1+q)

inΩ.

(5) If k = p and if L satisfies the following condition:

Z 2d

0

t−1L(t)p−11 dt <+∞, (3.2)

(Q) has a unique solution v W

1,ploc

(Ω) ∩ C

0

¡

Ω ¢

satisfying

v(x)∼ Z δ(x)

0

t−1L(t)p−11 dt

! p−1

p−(1+q)

inΩ.

(8)

Proof: See section A in appendix.

¥

From a solution of (Q), we can easily construct a super-solution of (P

λ

).

Indeed, let us consider v W

loc1,p

(Ω) ∩ C

0

¡ Ω ¢

the solution of (Q) given by lemma 3.3. Then, u

λ def

= M v is a super-solution of (P

λ

) in Ω as soon as M λ

p−(1+q)1

. Particularly when k < 1 + r and λ λ

, chosing M sufficiently large u

λ

W

1,p0

(Ω) ∩ C ¡

Ω ¢

and is a super-solution of (P

λ

) in Ω satisfying

u

λ

u

λ

and u

λ

(x) δ(x) in Ω.

Now let us state a non-existence result for the problem (Q).

Proposition 3.1. Let v W

1,p0

(Ω) ∩ C ¡ Ω ¢

be a positive sub-solution of (Q) inand let us suppose there exists ε > 0 such that

Z

K(x)ϕ1p−1+εdx= +∞. (3.3)

Therefore, for any η > 0, (Q) has no weak solution v W

1,ploc

(Ω) ∩ C

0

¡ Ω ¢ such that v ηv in Ω.

Proof: See section B in appendix.

¥

Corollary 3.1. If k > p, there is no non-trivial weak solution of (Q).

4. Proof of Theorem 2.1

4.1. Existence of a C

1,β

positive solution when λ λ

.

Proposition 4.1. When k < 1 + r, provided λ λ

, (P

λ

) has a weak solution u

λ

W

1,p0

(Ω) L

(Ω). Furthermore, there exists β (0, 1) such that u

λ

∈ C

1,β

¡

Ω ¢ .

Proof: In the equation of (P

λ

), the expression h

λ

(x, v)

def

= K(x)(λv

q

−v

r

) involves a singular term K(x) which blows up as δ(x) 0, so we can not directly apply the sub- and super-solution method on Ω. To overcome this difficulty, we apply a sub- and super-solution method in a sequense of subdomains of Ω. Let us introduce (Ω

k

)

k∈N

Ω an increasing sequence of smooth subdomains of Ω such that Ω

k

−→

k→∞

Ω in the Hausdorff topology with

∀k∈N, 1

k+ 1 <dist(∂Ω, ∂Ωk)< 1 k.

Then, for all k N

we consider the following problem:

(Pk)

½ −∆puk=K(x)(λukq−ukr) in Ωk, uk =uλ on∂Ωk, uk0 in Ωk.

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By definition of Ω

k

, there exists C

k

> 0 such that

∀v∈Ikdef

=

· min

k

uλ,max

k

uλ

¸ , sup

x∈Ωk

¯¯

¯¯∂hλ

∂v (x, v)

¯¯

¯¯≤Ck.

As a consequense, there exists µ

k

> 0 such that for all x

k

, the func- tion v 7−→ h

λ

(x, v) + µ

k

v

p−1

is increasing on I

k

. Therefore by sub- and super-solution method, (P

k

) has a solution u

k

W

1,p

(Ω

k

). Indeed, we can construct the following iterative monotone scheme: for all n N

, let u

k,n

W

1,p

(Ω

k

) be the weak solution of

(Pk,n)

½ −∆puk,n+µk(uk,n)p−1=hλ(x, uk,n−1) +µk(uk,n−1)p−1 in Ωk, uk,n=uλ on∂Ωk, uk,n0 in Ωk

with u

k,0

= u

λ

in Ω

k

. By induction on n N, (P

k,n

) has a unique solution u

k,n

W

1,p

(Ω

k

). By using the weak comparison principle (u

k,n

)

n∈N

satisfies

u

λ

u

k,n

u

k,n+1

u

λ

in Ω

k

. Consequently, for all n N

,

¯¯

¯hλ(x, uk,n−1) +µk

³

(uk,n−1)p−1(uk,n)p−1

´¯¯

¯L(Ωk)

and since u

λ

is smooth in Ω, we can state by a regularity result due to Lieberman [10] (see Theorem 1) that (u

k,n

)

n∈N

⊂ C

1,γ

¡

k

¢

for some γ (0, 1). Moreover there exists a constant C > 0 only depending on γ, Ω

k

, ku

λ

k

L(Ωk)

and ku

λ

k

L(Ωk)

such that ku

k,n

k

C1,γ

(

k

) C. From Ascoli- Arzel`a theorem, there exist u

k

∈ C

1

(Ω

k

) and a subsequence (u

k,m

)

m∈N

such that u

k,m

−→

m→∞

u

k

in C

1

¡ Ω

k

¢

. Passing to the limit when n +∞ in (P

k,n

), u

k

is a weak solution of (P

k

).

For all k N, we define ˜ u

k def

= 1

k

.u

k

in order to extend u

k

on Ω by zero. We prove that (˜ u

k

)

k∈N

is an increasing sequence in Ω. Indeed, since Ω

k

k+1

, if we compare u

k+1

with every term of (u

k,n

)

n∈N

in Ω

k

, using the weak comparison principle we get

∀n∈N, uk,n≤u˜k+1in Ωk.

Passing to the limit in the above inequality,

³

˜ u

k

(x)

´

k∈N

is non-decreasing for all x Ω. Therefore there exists u

λ

L

(Ω) such that ˜ u

k

−→

k→∞

u

λ

a.e.

in Ω and

u

λ

u

λ

u

λ

in Ω. (4.1)

It follows that ˜ u

k

−→

k→∞

u

λ

in D

0

(Ω) and u

λ

satisfies (1.1). Using inequality (4.1) and Hardy’s inequality, K(x) [λ(u

λ

)

q

(u

λ

)

r

] W

−1,p0

(Ω), which im- plies that u

λ

W

1,p0

(Ω). Finally applying proposition C.1 of the appendix, we get the C

1,β

¡

Ω ¢

regularity of u

λ

.

¥

(10)

4.2. Existence of Λ

1

. Let us define

Λ

1 def

= inf {λ > 0, (P

λ

) has a positive solution} .

By Lemma 3.1 and the first step of this proof, λ

Λ

1

λ

< +∞. By definition of Λ

1

, for any λ > Λ

1

there exists µ

1

, λ) such that (P

µ

) has a positive solution u

µ

W

1,p0

(Ω) L

(Ω). Moreover using proposition C.1, u

µ

∈ C

1,β

¡

Ω ¢

. Since u

µ

is a sub-solution to (P

λ

), we prove that u

µ

u

λ

in Ω. Indeed, K(x) > 0 in Ω, so there exists δ

0

> 0 such that

−∆

p

u

µ

0 ≤ −∆

p

(C

0

ϕ

1

) in Ω

δ0

, with C

0

> 0 large enough to satisfy

u

µ

C

0

ϕ

1

on ∂Ω

δ0

.

By the weak comparison principle, u

µ

C

0

ϕ

1

in Ω

δ0

. Morever u

µ

and ϕ

1

are bounded in Ω \

δ0

, thus u

µ

1

in Ω for some C > 0. Therefore chosing M sufficiently large in the definition of u

λ

, we get u

µ

u

λ

in Ω.

Finally, applying again sub- and super-solution technique as in step 1, we get a solution u

λ

∈ C

1,β

¡

Ω ¢

of (P

λ

) .

¥

Proof of Theorem 2.1: The proof follows from proposition 4.1 and subsection 4.2.

¥

5. Proof of Theorem 2.2

5.1. Existence of a solution under condition (2.1) or (2.2).

Proposition 5.1. Let

k∈ h

1 +r,1 +q+p−(1+q)p

´

. Then, under condition Z

K(x) (u

λ

)

r+1

dx < +∞, (5.1) there exists λ

∗∗

> 0 such that the problem (P

λ

) has a non-trivial weak solu- tion u

λ

W

1,p0

(Ω) L

(Ω) as soon as λ > λ

∗∗

.

Remark 5.1. Since u

λ

W

1,p0

(Ω), by Hardy’s inequality

δ(x)uλ Lp(Ω)

. So using H¨older’s inequality, assumption (5.1) in Theorem 5.1 is satisfied if

L(δ(x))δ(x)

r+1−k

L

α0

(Ω), where α =

r+1p

> 1. And this last condition is satisfied if

k <1 +r+p−(1 +r)

p . (5.2)

So (5.2) implies (5.1); but this condition is not sharp and can be weakened

by using the precise behaviour of u

λ

given in lemma 3.3. Indeed,

(11)

(1) if k [1 + r, 1 + q), u

λ

(x) δ(x) in Ω. Therefore condition (5.1) is satisfied if

k < 2 + r. (5.3)

(2) if k = 1 + q, condition (5.1) is also satisfied if k < 2 + r.

(3) if

k

1 +q,1 +q+p−(1+q)p

,

uλ δ(x)p−(1+q)p−k

L(δ(x))

1

p−(1+q)

in Ω.

Therefore, condition (5.1) is satisfied if

k <1 +(p1)(r+ 1)

p−q+r . (5.4)

Remark that if 1 + r > q, (5.3) is always true for k [1 + r, 1 + q] and since

1 +q <1 +(p1)(r+ 1)

p−q+r ⇐⇒r+ 1> q, (5.5)

condition (2.1) implies (5.1). Similarly if 1 + r q, by equivalence (5.5), (5.4) is never satisfied for

k∈

1 +q,1 +q+p−(1+q)p

and condition (2.2) im- plies (5.1). We can easily check that both conditions (2.1) and (2.2) are weaker than (5.2). Moreover, let us suppose one of the following conditions be satisfied:

1 +r > q and k∈

1 +(p1)(r+ 1)

p−q+r ,1 +q+p−(1 +q) p

« ,

1 +r≥q and k∈

2 +r,1 +q+p−(1 +q) p

« .

Then, using lemma 3.3 again, condition (5.1) is not satisfied, which guar- antees the ”sharpness“ of conditions (2.1) and (2.2).

In the proof of Proposition 5.1, we will need the following well known lemma.

Lemma 5.1. Let x, y R

N

and , ·i the standard scalar product in R

N

. Then there exists a constant C

p

> 0 such that

h|x|p−2x− |y|p−2y, x−yi ≥



Cp|x−y|p if p≥2, Cp |x−y|2

(|x|+|y|)2−p if 1< p <2.

Proof: See Lemma 4.2 in Lindqvist [11] or Lemma A.0.5 in Peral [12].

¥

Proof of proposition 5.1: Let us introduce the functionnal

Iλ(v) =1

p Z

|∇v|pdx+ 1 r+ 1

Z

K(x)|v|r+1dx− λ q+ 1

Z

K(x)|v|q+1dx,

with v W

1,p0

(Ω). Let ϕ

0

6= 0 ∈ D(Ω) be a non-negative function. There-

fore there exists λ

∗∗

> 0 such that I

λ

0

) < 0 for λ > λ

∗∗

. Let us fix a

(12)

constant M > 1 such that M u

λ

ϕ

0

in Ω and introduce the cut-off func- tion f

λ

defined in Ω × R by:

fλ(x, v) =



K(x) [λ(M uλ)q(M uλ)r] if v > M uλ(x), K(x) [λ|v|q− |v|r] if v∈[0, M uλ(x)],

0 if v <0.

The function v 7−→ f

λ

(x, v) is a Carath´eodory function. For (x, v) × R, let us set F

λ

(x, v) =

Z v

0

fλ(x, t)dt

and consider the functional E

λ

defined as follows:

∀v∈W1,p0 (Ω), Eλ(v) =1 p

Z

|∇v|pdx− Z

Fλ(x, v(x))dx.

A straightforward computation gives us

Eλ(v) = 1

p Z

|∇v|pdx− λ

q+ 1A(v, q) + 1

r+ 1A(v, r)

−λB(v, q) +B(v, r) r

r+ 1C(r) +λ q q+ 1C(q),

(5.6)

with

A(v, s)def=

Z

1{0≤v≤M uλ}K(x)|v|s+1dx, B(v, s)def= Z

1{v≥M uλ}K(x) (M uλ)svdx

and

C(s)def= Z

1{v≥M uλ}K(x)(M uλ)s+1dx.

Let ε > 0 and v W

1,p0

(Ω), then we split the integral A(v, q) in Ω \

ε

and Ω

ε

:

A(v, q) = Z

Ω\Ωε

1{0≤v≤M uλ}K(x)|v|q+1dx+ Z

ε

1{0≤v≤M uλ}K(x)|v|q+1dx

def= AΩ\Ωε(v, q) +Aε(v, q).

Since in Ω \

ε

, K is bounded, from the embedding W

1,p0

(Ω) , L

q+1

(Ω), there exists a constant C

1

such that

A

Ω\Ωε

(v, q) C

1

kvk

q+1

. (5.7) In Ω

ε

, by H¨older’s inequality we have,

Aε(v, q)≤Aε(v, r)τ µZ

ε

1{0≤v≤M uλ}K(x)|v|pdx

1−τ ,

with τ =

p−(1+q)p−(1+r)

< 1. Using inequality (1.4) and Hardy’s Inequality, we finally obtain, for ε small enough

Aε(v, q) C2ε12(p−k)(1−τ)Aε(v, r)τ µZ

ε

|v|p δ(x)p dx

1−τ

C2ε12(p−k)(1−τ)(τ A(v, r) +C3(1−τ)kvkp). (5.8)

(13)

From the above arguments and since

B(v, q) = Z

Ω\Ωε

1{v≥M uλ}K(x) (M uλ)qvdx+ Z

ε

1{v≥M uλ}K(x) (M uλ)qvdx

def= BΩ\Ωε(v, q) +Bε(v, q),

we also get

BΩ\Ωε(v, q)≤C4kvk (5.9)

and

Bε(v, q)≤C5ε12(p−k)(1−τ)(τ B(v, r) +C6(1−τ)kvkp). (5.10)

Using inequalities (5.7) to (5.10),

Eλ(v) 1

2pkvkp−λ C1

q+ 1kvkq+1−λC4kvk+1 2B(v, r)

+ 1

2(r+ 1)A(v, r)− r

r+ 1C(r) +λ q

q+ 1C(q), (5.11)

for ε > 0 sufficiently small. With condition (5.1), this inequality proves that E

λ

is coercive and bounded from below on W

1,p0

(Ω). So let us define

c

λdef

= inf

v∈W1,p0 (Ω)

E

λ

(v)

and let (v

n

)

n∈N

W

1,p0

(Ω) be a minimizing sequence of E

λ

, that is to say E

λ

(v

n

) −→

n→+∞

c

λ

.

³ E

λ

(v

n

)

´

n∈N

is bounded, therefore by inequality (5.11) (v

n

)

n∈N

is bounded in W

1,p0

(Ω). Thus, there exist u

λ

W

1,p0

(Ω) and a subsequence (v

m

)

m∈N

such that v

m

−→

m→+∞

u

λ

weakly in W

1,p0

(Ω), strongly in L

q+1

(Ω) and in L

1

(Ω) and a.e. in Ω. Then we get

ku

λ

k ≤ lim inf

m→+∞

kv

m

k. (5.12)

Using Fatou’s Lemma and inequality (5.1), it follows that

1

rA(uλ, r) +B(uλ, r)≤lim inf

m→+∞

µ1

rA(vm, r) +B(vm, r)

<+∞. (5.13)

Again from Fatou’s lemma and inequalities (5.8),(5.10) and (5.12),

λ

q+ 1Aε(uλ, q) +λBε(uλ, q) lim inf

m→+∞

λ

q+ 1Aε(vm, q) +λBε(vm, q)

«

C7ε12(p−k)(1−τ). (5.14)

Since v

m

−→

m→+∞

u

λ

in L

q+1

(Ω) and in L

1

(Ω),

AΩ\Ωε(vm, q) −→

m→+∞AΩ\Ωε(uλ, q) and BΩ\Ωε(vm, q) −→

m→+∞BΩ\Ωε(uλ, q). (5.15)

(14)

Gathering the estimates (5.12) to (5.15) and using (5.6), we obtain:

cλ= lim inf

m→+∞E(vm)≥Eλ(uλ)−C7ε12(p−k)(1−τ)≥cλ−C7ε12(p−k)(1−τ).

Passing to the limit as ε 0, we finally get E

λ

(u

λ

) = c

λ

. By definition of c

λ

, u

λ

satisfies

Eλ(uλ) = min

v∈W1,p0 (Ω)

Eλ(v)

and since E

λ

is Gˆateaux differentiable, u

λ

satisfies the Euler-Lagrange equa- tion associated to E

λ

:

∀v∈W1,p0 (Ω), Z

|∇uλ|p−2∇uλ.∇v dx= Z

fλ(x, uλ)v dx.

In particular, setting v = (u

λ

)

W

1,p0

(Ω), by weak maximum principle it follows that u

λ

0 a.e. in Ω. Moreover, since M u

λ

is a super-solution of (P

λ

), for all non-negative v W

1,p0

(Ω),

Z

|∇(M uλ)|p−2∇(M uλ).∇v dx Z

K(x) [λ(M uλ)q(M uλ)r]v dx.

Setting v = (u

λ

M u

λ

)

+

W

1,p0

(Ω), we obtain

0 =

Z

³

fλ(x, uλ)−K(x) [λ(M uλ)q(M uλ)r]

´

(uλ−M uλ)+ dx

Z

³

|∇uλ|p−2∇uλ− |∇(M uλ)|p−2∇(M uλ)

´ .∇

³

(uλ−M uλ)+

´ dx.

Using lemma 5.1,

³

(u

λ

M u

λ

)

+

´

= 0 a.e. in Ω and by Poincar´e’s inequality u

λ

M u

λ

a.e. in Ω. Finally

Iλ(uλ) =Eλ(uλ) = min

v∈W1,p0 (Ω)Eλ(v)≤Eλ0) =Iλ0)<0,

therefore u

λ

is a non-trivial weak solution of (P

λ

) .

¥

5.2. Compacted support of the solution.

In this section we define

g

λ

(t)

def

= t

r

λt

q

, t [0, +∞) and a

def

= µ r

λq

1

q−r

(5.16) in such a way that g

λ

is positive and increasing on the interval (0, a

). Let us start by stating a result which guarantees the existence of an appropriate super-solution of (P

λ

) near the boundary.

Lemma 5.2. Let u

λ

W

1,p0

(Ω) L

(Ω) be a weak solution of (P

λ

). Then u

λ

∈ C ¡

Ω ¢

and there exist δ

> 0, M > 0 and α (1, p

0

) such that

uλ(x)≤M ϕ1(x)α inδ.

Références

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