A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
C ELSO M ARTÍNEZ M IGUEL S ANZ
Spectral mapping theorem for fractional powers in locally convex spaces
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 24, n
o4 (1997), p. 685-702
<http://www.numdam.org/item?id=ASNSP_1997_4_24_4_685_0>
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in Locally Convex Spaces
CELSO
MARTINEZ -
MIGUEL SANZ *1. - Introduction
In
[9]
the authors extended thetheory
of fractional powers ofnon-negative operators,
a classicaltopic
in Banach spaces, tosequentially locally
convexspaces.
Previously,
W. Lamb(see [6], [7]
and[13])
had elaboratedanother,
more
restrictive,
extension. The reason for thisstudy
was the fact that thenatural domain of certain
operators
is not contained in a Banach space. Inparticular,
thishappens
if we consider the fractional derivatives andintegrals
of Riemann-Liouville and
Weyl (see [12]).
On the otherhand,
thegeneralized
differential
operators
which are veryimportant
in theapplications
are definedin distributional spaces which are not Banach spaces but
sequentially complete.
With this new
theory
some of theseoperators (let
usconsider,
as anexample,
the
operator -A,
where A is theLaplacian)
will benon-negative,
and there-fore we could
study
their fractional powers. Inparticular,
Besselpotentials (see [14]),
defined in the space oftempered distributions,
could be describedas the fractional powers of the
operator (I - 0 ) -1.
The basic
properties
of fractional powers were established in[9],
with theexception
of thespectral mapping
theorem. The knowntechniques (based
onthe
theory
ofGelfand)
were not suitable to prove this theorem. In this paper, this result has beenproved by obtaining
newintegral representations
for theresolvent
operator
of the fractional powers.In the
following,
X will be asequentially complete locally
convex space and we will say that X is anS-space (Frechet
spaces are aparticular case).
Given a linear
operator
T :D(T)
c X -X,
we will say that acomplex
number z
belongs
to thealgebraic
resolvent if theoperator
z - T isbijective. Otherwise,
we will saythat z belongs
to thealgebraic spectrum or(r).
In a
topological
sense, the resolvent setp (T )
will be the set of allcomplex
z
of peT)
such that(z - T) -
1 is continuous and thespectrum a (T)
will bethe
complement
ofp (T ).
If T is closed and the space X has theproperty
that* Work
partially supported dy
DGCYT, grant PB95-1103,Spain.
Pervenuto alla Redazione il 11 marzo 1996 e in forma definitiva il 26 novembre 1996.
every linear closed
operator
from X toX, everywhere defined,
is continuous(closed graph theorem)
thenp(T)
=peT) and a(T)
=8 (T).
Given a directed
family
of seminorms P that describes thetopology
ofX,
we will say that a linearoperator
A :D (A)
C X - X isnon-negative
ifp (A) D] -
oo,0[
and the set +A)-1: ~,
>01
isequicontinuous, i.e.,
if for allp E P
there exist a seminormq ( p)
and a constantMp > 0
such thatThe fractional powers with
complex exponent
awere defined in
[9]
in thefollowing
way:if A is continuous and
D(A)
=X,
where J" is the
integral operator
as definedby
Balakrishnan in[ 1 ],
whoseexpression
for 0 91a n(n
>1)
is(a
formula obtainedby
H. Komatsu in[5]). Although
in[9]
the space X wasa Frechet space, the results of this paper are true also when X is an
S-space,
since the
sequential completeness
is sufficient for thevalidity
of theelementary
results of
integration applied
there. On the otherhand,
the definition of Aacoincides,
in Banach spaces, with the one introduced in[10]
and[8].
In
[9]
it wasproved
that theoperators A’,
for a EC+,
areclosed, satisfy
the
property
ofadditivity
and that Aa is an extension ofJI;
moreover Aa isequal
to Ja if andonly
if the domainD(A)
is dense. In[11]
and[12]
the fractional powers in Frechet spaces wereapplied
to obtain certain results about fractionalintegration
and differentiation.The main
goal
of this paper is to relate8(A") to 8(A)
anda(Aa)
tocr
(A).
Inparticular,
we will prove thatIn relation to these
results,
a notable difference betweenS-spaces
andBanach spaces is that if X is of the first
class,
thealgebra
of the continuous linearoperators, everywhere defined,
from X toX,
does not admit neither the Riesz-Dunford FunctionalCalculus,
nor thetheory
of Gelfand.2. - Functional calculus for
densely
definednon-negative operators
In this section we will construct a Functional Calculus that will allow us to obtain
integral
formulas for certainoperators
and toestablish,
in some cases, the existence of continuousinverse, everywhere
defined on X.Given 3 >
0,
we will say that aholomorphic
functionbelongs
to the classgo if
0 andG (z)
exists.It is understood that the number 3 can vary with each function G. We will say that G
belongs
to the classg,
ifeZ G (z)
= 0 andG (z)
exists.
A function G
belongs
togo
ngi
if andonly
if there exist the limitsG(z)
andG(z).
From classes
go
andg,
we can definefi
={F : CB~- -+ C, holomorphic,
such that
F (z) = G(log z),
G EGj 1, j = 0, 1,
where R-=] - oo, 0]
and forlog z
we consider the branch that is real forpositive
real numbers and is discontinuousalong
thenegative
real axis.PROPOSITION 2.1.
If F
ETo,
then:(i)o limz~o F(z)
exists andlim 1, 1 ,, z-1 F(.z)
= 0.(ii)
For all A > 0 there exist the limitsand
f,
l andf2
areanalytic functions
inR* =]0, oo[,
asfunctions of
realvariable.
(iii)o
Thefunctions (k
=1, 2)
are bounded in]0, 1 ],
while thefk (k
=1, 2)
are bounded in
[ 1, oo[.
(iv)o By writing
the
following formula
holds,
where theintegral
converges as a Riemannimproper integral.
For all F E
property (ii)
ismaintained,
butproperties (i)o, (iii)o
and(iv)o
are
respectively replaced by
(i)
1 lim 1, 1 , .F (z)
exists andz F (z)
= 0.(iii)
1ThefunctionsÀ2 f£(À) (k
=1, 2) are bounded in ]0, 1 ], while the Xfk (k
=1, 2)
are bounded in
[ 1, oo[.
(iv)
1 Withf meaning
the same as in(iv)o,
andwriting F (C)O)
= limF (z)
we obtain theidentity
where the
integral
converges as a Riemannimproper integral.
PROOF. Since a function F
belongs
to if andonly
if functionF (z)
=F(I/z) belongs
to it is sufficient to proveproperties (i)o, (ii), (iii)o
and(iv)o.
The first one follows on
immediately
from the definition of Let us prove(ii).
GivenF(z) = G (log z),
where G Ego
is definedfor )i3z) I
1r +8,
we take s : 0 smin{8, ~c/2{,
andcalling , log
to the branch of thelogarithmic
function which is real for
positive
real numbers and is discontinuousalong
theray
{~,ei ~’~+~~ : ~~ > 01,
we consider the functionFE (z)
=G(Elog z). Clearly,
and, by continuity,
there exists the limit called in the statement, with a valueequal
to Similarreasoning
isapplied
forf2 (~,) .
To prove
property (iii)o, given X
>0,
we take a circumference r centeredon
2013~,
of radius ch(0
csin s).
Then r does not cut to the rayt >
01
and thus r is contained in the domain ofFg. Expressing
the functionFe( -À)
=by
means ofCauchy’s integral
formulaalong
r we haveand derivating
Taking
into account(in
a similar way asproperty (i)o)
that the functionsand are
bounded, respectively,
in theproximities
of zero andinfinity,
we obtain assertion(iii)o
for functionfl.
Ananalogue procedure
isused for
f2.
Finally, given
z EC B property (iv)o
results fromexpressing F(z)/z through Cauchy’s integral
formulaalong
of thepath composed
from the arcs:counter-clockwise
oriented,
withs, p, R positive. Taking
limits as E -0,
p -->. 0 and R ~ o~o we conclude
(2.2),
afterhaving applied properties (i)o
and
(ii).
DREMARKS 2.2. If F E
Fo, (2.2)
would allow us to consider asthe
Stieltjes
transform associated with thecomplex
measuredJ1(t)
=Likewise, (2.3)
would indicate thatF(z)
is theStieltjes
transformcorresponding
to the measure
(see [3]
and[4]).
In addition to the notations introduced in the
previous result,
we will writeWe define the classes
In
particular,
From now on, in this
section, A
will be adensely
definednon-negative
operator.
It is not very difficult to check if a
holomorphic
function defined onC ) R- belongs
to classesFk, ’Hk, k = 0,
1. Thefollowing examples
will be of usefulness in ourexposition.
EXAMPLE 2.3. If 0 9la
1,
functionz’ belongs
to~o (but
not toand, if SEe B R-,
the functionis in class
Ho
EXAMPLE 2.4 Given 0 y
1/2
and t >0,
functionbelongs
toThe same is valid for 1.
EXAMPLE 2.5 If a is such that 91a
> la 12,
the setS2«
=CB f~.’e’o’ : k > 0
and -~c
sf) S 7rl is
notempty
and if - Jvt ES2«,
the function(J1 + za) -1 belongs
to For the same values of a,
given S E C B R-,
the functionis in class
Ho,
but not in The same is true,given
r >0,
forDEFINITION 2.6. Given F E and
being f : :]0, oo[--+ C
the functiongiven by
theexpression (2.1),
theintegral operator
verifies the estimate
where
C1 -
andC2 = 1 dk.
From thisinequality
we can deducethat, given k
>0, operator T (X -~- A) -1 is continuous,
whichimplies
that T is closable. We defineF(A) = F(0)
+T.
Asimple example
is theoperator
A’ =(z~)(A).
It is evident that if A is continuous or
D(A)
=X, operator F(A)
inherits the sameproperties.
For F EHi
we define the continuousoperator
REMARK 2.7. If F E for
all q5
E X it is easy to see that theintegral
--is
absolutely convergent
withrespect
to anyseminorm p
E P and thereforedefines on X a continuous
operator. Taking
into account the identities(2.2)
and
(2.3),
we haveand we can
deduce,
thanks to thedensity
ofD(A),
that the two definitions ofF (A)
coincide.REMARK 2.8. It is immediate that if F E
then,
forall J1
>0, F(A)
commutes with
(~
+A) -
1 in the domain of A. AsF(A)
is defined as aclosure
operator,
thiscommutativity
can be extended to the domain ofF(A).
This
property
is verified in all the space X when F E In this case,F(A)
commutes with A in
D(A),
since theequality
for q5
ED(A), implies
that ED(A)
and =F(A)Aq5.
REMARK 2.9. It can be
proved, by
means of thepath
used inProposition
2.1(part (iv)o),
that if A is a boundedoperator
in Banach space X with 0 Ep (A)
and F E
U J-li ,
the definition ofF (A )
coincides with the one obtained with the Riesz-Dunford functional calculus(see [2,
p.568]).
REMARK 2. lo. When F’ E and
f (~,) >
0 for all h >0,
Remark 2.2 shows thatF(A)
coincides with theoperator
associated to the function F ac-cording
to the Hirsch functional calculus(see [3] -[4]). Likewise,
the sameproperty
is verified when F E andf(À) S
0 for all X > 0.However,
the functions considered in theexamples 2.3,
2.4 and2.5,
the moreinteresting
inthis paper, do not
belong,
ingeneral,
to the above mentioned cases, andthus,
Hirsch functional calculus cannot be used here.THEOREM 2.11
(Formula
of theproduct
inIf F
EHo,
G E andH = FG E
Ho,
then theoperator F (A) G (A)
is closable andIn the case that
D[H(A)]
CD[G(A)],
thenThis
happens
whenG (A)
iseverywhere defined
onX,
inparticular, if
G EIn order to prove the formula of the
product
we need several lemmas.LEMMA 2.12.
If
F EHo
nHI and F (oo)
=0,
we havewhere
f
andf *
aregiven by (2.1 )
and(2.4)
and theintegral
isabsolutely convergent.
Furthermore,
da isuniformly bounded for
À > 0.PROOF. It is easy to obtain the estimate
where H and K are
respective
bounds of the functionsf
andÀf’. Thus,
the finalpart
of the statement is proven. Given ), > 0 and b >0,
let w== 2013~+~&, w2 - -~, - i b
and let r be the contour used in theproof
ofProposition
2.1(part (iv)o),
with the suitable size ofpositive s,
p, R so that r contains inside w 1 and w2 .Through Cauchy’s integral formula, by taking
limits as s0,
p- 0 and R - oo,
hypothesis F (oo)
= 0 enables us to obtainConsequently:
On the other
hand, by denoting:
and
making
b =À(1 - r )q
with 0 r 1and q
>0,
it is easy to obtain the estimates:which,
if we take q >3/2, imply
thatJk )
=0, k
=1, 2. Hence,
in order to prove the formula of the statement, it
only
remains to check thatlim,,, 13
=0,
which is a consequence of theinequality:
where for the second
integral
we have used the estimatewhich comes from
log(I
+x )
x, if x > 0. D LEMMA 2.13(Formula
of theproduct
inHo nHI). If F
and Gbelong to
the
product
H = FG is inHo
fland F(A)G(A)
=H(A).
PROOF. Let
f,
g, h andf *, g*,
h* be the functions associated toF,
G andH, given, respectively, by (2.1 )
and(2.4).
The fact that Hbelong
to~Lo
nHI
Iis
obvious,
sinceand the functions
f *
andg*
are bounded. Theproof
can be reduced to thecase in which
F(oo) = G(oo) =
0. In this case,by using
Tonelli-Hobson’s theorem we can writeits second member can be rewritten in the form
Next,
we will writeIl
with the variables ~ and12
with J1 anda =
À/ J1 (after
which will be done in12, À
=/~). Then, by applying
thesecond resolvent
equation
we obtainwhere
and, given
r, s : r,The
functions hj 4)
areabsolutely integrable
onWs,r
withrespect
to any
seminorm p c= P.
The restriction toWs,r
is made because there is noguarantee
that each one of thefunctions hj
isintegrable
on W.By
means ofthe
change
ha - h we obtain:Therefore, by associating h
1 withh4
andh2
withh3
we deduce:where in order to substitute
lims-o
r,l 1 S,rby ffw
and thenapply
reiteratedintegration,
it suffices to check theintegrability
on W of the functionsand
but this is an immediate consequence of the second assertion of Lemma
2.12, together
with the fact that the functionsÀ -1 f
andÀ -1 g
areabsolutely
inte-grable.
Aftercarrying
out the reiteratedintegration
on W andapplying (2.6),
we conclude that
as we wished to prove. D
Given 0 y
1 /2,
for t > 0 we will denoteGt (z)
= the functionalready
mentioned in theexample 2.4,
thatbelongs
toHo n HI.
With the model ofexpressions (2.1 )
and(2.4)
we are able to obtain its associatedfunctions gt
and
g:.
LEMMA 2.14.
If
F eHo,
theproduct
FGt belongs to Ho n HI for
allt
Furthermore,
PROOF. It is clear that if co E C
and )i3co) I
n+ 8 (with
then:
It follows that
On the other
hand, by simple calculation,
we have:Therefore, gt
andbelong
toand g7
andÀ g7 belong
toFurthermore,
fromProposition
2.1(part (ii))
we can see that F eFo implies
that
~. -1 f *
eoo[)
andf *
e1]).
Ifh
t is the functiongiven by (2.1 ),
associated toHt, then, taking
into account theidentity
together
with the fact that~, -1 f 1])
and~. -2 f E L 1 (] 1, oo[),
oneeasily
deduces that
), - 1 h Hence, Ht belongs
toHo n Hi . For q5
ED (A)
we havewhere, by
the dominated convergencetheorem,
thepart
between brackets tends toF(A)o
as t goes to zero, due to the fact thatand fixed
It must therefore be
proved
that the secondintegral
tends to zero.By denoting
(these
suprema exist due topart (i)o
ofProposition 2.1 )
andby changing
thevariable k = we obtain
(where Mp
and the seminormq(p) verify ( 1.1 )). Equality
0, together
with the fact that F EHo
and theintegrability
of the function1 on
Rj imply
that the last term of the second member of the obtainedexpression
tends to zero as N - oo,while,
afterfixing N,
the first summand of this member tends to zero as t -~ 0.Therefore,
we conclude that the first member tends to zero as t ~0,
whichcompletes
theproof
of(2.7).
Relation
(2.8)
can be obtained as aparticular
case of(2.7) for q5
ED(A).
Taking
into account thedensity
ofD (A)
and the estimatewhich is obtained from the definition of
Gt (A),
we conclude thevalidity
of(2.8)
forall 0
E X. DPROOF. OF THEOREM 2.11. Let F E and G E
~lo
such that H =FG E
Ho.
For t >0,
the fact thatG Gt
tbelongs
to 1implies,
as notedin Remark 2.8 that
operator (GGt)(A)
commutes with A onD(A)
and thusE
D(A)
forall q5
ED(A).
Given s >0, by
virtue of Lemma 2.13we have
(FGt)(A) (HGsGt)(A)Ø,
andtaking
limits for tgoing
to zero, Lemma 2.14 assures that
and as
F(A)
isclosed,
onceagain
the same lemmaimplies
thatafter
making s
go to zero.Hence, equality F (A) G (A) - H (A)
iseasily obtained,
because of the fact thatH (A)
is closed andD(A)
is dense. D3. -
Spectral mapping
theorem for fractional powers ofnon-negative operators
with dense domainWe will continue in this section
by supposing
that A is anon-negative operator
with a dense domain.By using
the formula of theproduct,
we willestablish
algebraic
andtopological spectral mapping
theorems for the fractional power Aa . Inparticular,
we willgive
newintegral
formulas torepresent
the resolventoperator (w -
1 if theexponent a
is small and w has the formw =
raeiea
with r > 0 and-1r S () S
7r. Thefollowing
lemma studies theproduct
of A"(n
>1) by Gt (A),
and will be veryuseful,
since it will enableoperators
An to be treated as ifthey belong
toLEMMA 3.1. The range
of Gt (A)
is contained in andPROOF. Since the function
belongs
to~Co n HI
we can use(2.5)
todescribe the
operator (z"Gt)(A)
and thusand
reasoning by
induction on n, one deduces thatRan[Gt (A)]
CD(An)
andidentity (3.1 ). Moreover, Gt(A)
and An commute onD (An ) .
0THEOREM 3. 2.
If 91a > lal2, the following
assertions aresatisfied:
(i)
Thenon-empty
setS2a
=(C ~ ~ ~.a el 8a : ~ >
0 and -7r o7c }
is contained inthe resolvent set
p (Aa )
andif
-A ES2a,
then(ii)
GivenSEe B R-,
then saE p (Aa ) if and only if s E p (A),
and S’ Ep (A’) if
and
only if s
Ep (A).
For SE p (A) and 0
E X we havePROOF. Assertion
(i) (proved
in[1] ]
and[10]
when X is a Banachspace)
is obtained
applying
the formula of theproduct
to the functionsza
+ it and1
Let us now prove
(ii).
We havealready
seen in theexamples
of Section 2that the functions
respectively belong
toHo n HI
and toHo.
Since the function z - sbelongs
neither to the class
Ho
nor to?-Cl,
we will need to use the functionGt
in orderto
apply
the formula of theproduct.
As the function
(za - sa)Gt(z) belongs
tonHI
and itsproduct by
Gis the function
(z - s ) Gt (z),
also in nHi,
we canapply
Theorem 2.11 andthus
from
which, by applying
Lemmas 2.14 and 3.1 andtaking
limits for tgoing
to zero, one deduces that
Similarly
it isproved
thatAccordingly, s
E if andonly
if sa E If s Eby denoting
we have:
where the last
equality
is due to(2.1 ).
As theintegral operator
that appears in last term iseverywhere
defined on X andcontinuous,
it follows that sa Eif and
only
if s E p(A).
The
proof
of(iii)
isanalogous
to(ii), by considering
the functionsof the class
Ho,
andchecking
the identitiesLEMMA 3.3
(Moment inequality).
Let 0 91a and a seminormThen,
there exist apositive
numberC(p,
a,fi) (depending
on p, a andfi)
and aseminorm
r(p, fi)
E P(depending
on p andfi)
such thatPROOF. From the definition of
non-negative operator, by
induction on m, itfollows that
given p E p
and apositive integer
m, there exist apositive
numberK (p, m)
and a seminormq ( p, m )
E 7~(depending
on p andm )
such thatFirstly,
let us prove(3.3) for f3
- m. Givenwriting J.o .
=(1.2), applying (3.4)
andminimizing
withrespect
to 3 >0,
we obtain
where
Let us now prove the
inequality (3.3)
for 0 9lotIf q5
ED(A~)
and we take m =
[91p]
+ 1(where
is theinteger part
of we see,after
expressing
theintegrand
in the formÀa-lAm-,B [(X
+A)-’]m A°q5
andby
using (3.5),
that theintegral fooo Àa-l ~A(~, -I- A)-1~"Z ~ d~,
isabsolutely
conver-gent
withrespect
to any seminormp E P. Operating with [(I+ A)-’]m
itfollows from
(1.2)
thatBy arguing
in a similar way to the former case, we writeL oo[
--~and in the first
integral
we use the secondinequality
of(3.4)
and in thesecond,
after
writing
theintegrand
in the form(~, -+- A ) -1 ~ m A~ ~,
we firstapply inequality (3.5)
and after(3.4). Finally, by minimizing
the obtainedestimate with
respect
to 3 >0, inequality (3.3)
is concluded. DTHEOREM 3.4. Let a E
C+.
Then0
E p (A) if and only if 0
and 0 Ep (A) if and only if 0
Ep (Aa ) .
PROOF. Let 0 and n > ffia. From relation
it follows that 0
Conversely,
if 0E p (Aa ) then,
for allpositive integer
m we have that 0
E P [(A~)~ =
andtaking m
such thatm(91a)
>1,
wehave that which
yields
that 0 Ep(A).
If 0 E
(3.6) implies
that(A’)-’ = A"-’(A-’).
On the otherhand,
from
(1.2)
it follows that(A-~ )"
=A"-’(A-’)"
and thereforeIdentity (3.7) implies
that if 0 Ep (A),
then 0 EConversely,
if0 E
p(Aa),
thenoperator (A-1)a
is continuous and if 0f3 min(l, 91a),
Lemma 3.3
implies
that(A-1)~
is continuous and thanks to themultiplicativity (Proposition
3.3 of[9])
theoperator A-’ = ~(A-1)~~
1/f3 so is and thus 0 Ep (A).
DTHEOREM 3.5.
(Algebraic spectral mapping theorem)
Let a EC+. If8 (A) is
not
empty,
thenIf cr (A)
isempty,
thespectrum cr (A" )
also is.PROOF. Given a linear
operator
T :D(T)
C X -~X,
it is known thatBecause of
this,
theproof
can belimited,
without loss ofgenerality,
to the casewhere
and in this case thealgebraic spectral mapping
theorem is aconsequence of Theorems 3.2 and 3.4. D
THEOREM 3.6.
(Topological spectral mapping theorem)
Let a EC+. If a (A)
is not
empty,
then M 11 -. "’If a (A)
isempty,
thespectrum cr (A" )
also is.PROOF. Theorems 3.2 and 3.4 show that the result is true
if lal2
Hence,
thevalidity
of the theorem for all a EC+
would follow ifequality (3.8)
is true for
topological spectra.
We canonly
prove, ingeneral,
thatTo prove the other
inclusion, taking
into account theidentity
we would have to assure that if the
operator (zn -
is a continuouseverywhere
definedoperator,
theoperators Tm (zn - T") -
I(m = 1, 2, ... , n - 1)
so are. But this
result,
which is not true ingeneral,
is valid for T =A’/",
asa consequence of Lemma 3.3. D
4. -
Spectral mapping
theorem for fractional powers ofnon-negative operators
with non-dense domainThroughout
thissection,
A will be anon-negative operator
defined on anS-space
X such thatD (A) ~
X. Let us consider theS-space Xo
=D(A)
andthe
operator Ao
with domainD(Ao) = D(A) : Aq5 e
and defined asAoo
=Aq5 for 0
ED(Ao).
Theoperator Ao
isobviously
anon-negative densely
defined
operator
and it is easy to check thatAg
= J a for all a EC+.
Thefollowing proposition
allows us toadapt literally
the results of thepreceding
section to the case of
non-densely
definedoperators.
PROPOSITION 4.1. Let a E
C+ and n
> 91a. Thenthe following
assertions hold:PROOF. It is clear that the
operator T(a) = ( 1
+A)nja(1
+A)-"
is anextension of A".
Conversely, if g6
ED[T(a)],
then( 1
+A)~"q5
ED(J’)
andJ" ( 1 + A)-’o belongs
toD(A"
=An-" A" ) (Proposition
3.1 of[9])
whichgives A n ( 1
+A)~"q5
ED ( A" ) . Hence 0
ED ( A" ) (Lemma
3.2 of[9])
whichcompletes
theproof
of(i).
It is immediate to
check, through paragraph (i),
thatp(Aa)
cConversely, given z
E it is clear that z - A" is a one-to-oneoperator.
Let us see that it is
surjective. Given 0
EX,
theelement 1fr
_(,z -
+A) -"q5
ED(Ao)
and we have that(z - _ (1
+A)-n~
ED(An).
Let ustake an
integer k
> and let~8
=nka,
then cD(Ag),
and fromthe
equality Aglfr = ( 1
+A)-’q5
we have thatAg1fr
ED(Ag). Therefore,
E
D(A§~~) .
As cD(A 2~),
the formeridentity implies
that1fr
ED(A +2~) . Reiterating
thereasoning
it is concludedthat *
ETaking 17
=( 1
we havethat q
ED (A" )
andand therefore z D
THEOREM 4.2. Theorems
3.4,
3.5 and 3.6 also arevalid, though
theoperator
A wasnon-densely defined.
PROOF.
By applying
Theorem 3.4 to thedensely
definedoperator Ao
andby using
the relationsand
valid for z E
p (A)
and W Ep (Aa),
we obtain that Theorem 3.4 continuesbeing
true for the
operator
A.The
proof
of thespectral mapping
theorems for theoperator
A is the sameas that of the case
densely defined, taking
into account that Lemma 3.3 and Theorem 3.4 are true for allnon-negative operator.
DREFERENCES
[1] A. V. BALAKRISHNAN, Fractional powers
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de MatematicaAplicada.
Universitat de Valencia.
46100
Burjassot,
Valencia.Spain.
(e-mail: martinel@ uv.es, sanzma@ uv.es)