A NNALES DE L ’I. H. P., SECTION B
S.R.S. V ARADHAN
Self Diffusion of a tagged particle in equilibrium for asymmetric mean zero random walk
with simple exclusion
Annales de l’I. H. P., section B, tome 31, n
o1 (1995), p. 273-285
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273
Self Diffusion of
atagged particle in equilibrium
for asymmetric
mean zerorandom
walk with simple exclusion
S. R. S. VARADHAN
(*)
Courant Institute of Mathematical Sciences, New York University, New York, U.S.A.
Vol. 31, n° 1, 1995, p. -285. Probabilités et Statistiques
Dedicated to the memory of Claude Kipnis.
ABSTRACT. - We consider a
tagged particle
in asimple
exclusion modelwhere the
probability
distribution of thejump
sizes has zero mean, but isnot
necessarily symmetric.
We establish for thetagged particle,
a centrallimit theorem under the usual
scaling.
Nous considérons une
particule marquee
dans un modèled’ exclusion
simple
où la loi deprobabilité
des sauts est de moyenne nulle mais pas nécessairementsymétrique.
Nous démontrons pour ledéplacement
de la
particule marquee
un théorème central limite avec lechangement
d’échelle usuel.
1. INTRODUCTION
We consider a random walk with
simple
exclusion. This means that wehave a collection of
particles
inZd, d
> 1 with at most oneparticle
per site. Eachparticle
waits for anexponential
time with mean 1 and at theend of this time
picks
a random site tojump
to. Theprobability
that a(*) Supported by NSF grant DMS-9201222 and ARO grant DAAL03-92-G-0317.
Classification A.M.S. : 60 K 35, 60 F 17.
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques - 0246-0203
Vol. 31/95/01/$ 4.00/@ Gauthier-Villars
274 S. R. S. VARADHAN
particle,
located at x,picks
the site y tojump
to isgiven by p(y - x).
However the
jump
can be executedonly
if thesite y
is free. Otherwise theparticle
remains in theoriginal
site and waits for a newexponential
time. All the
particles
aredoing
thissimultaneously
andindependently
ofeach other. Since we are
dealing
with processes in continuous time ties willnever occur and this describes the evolution
completely.
For a more mathematical definition of the model we start with the state space Q
consisting
of functions yy onZd taking
values either 0 or 1. If=
1,
then there is aparticle
at x and if =0,
the site x is free.We next define certain transformations on the space O.
The transformation ax,y for two sites x, y in
Zd
could be either aparticle jumping
from xto y
or onejumping from y
to x. Of course= then ax,y does
nothing
and isidentity. Given p ( x )
> 0 withp(0)
= 0 and~p(x)
=1,
i.e. the distribution ofjumps,
we can define aformal infinitesimal
generator acting
on suitable functions F on HIt is known
[3]
that thisgenerator
defines agood
Markov Process on S2. For
each p
in 0p 1,
we have on S2 the Bernoulliproduct
measureP~
with =1]
= p for all x inZd.
EachP~
is an invariant measurefor our evolution.
Corresponding
toeach p
we have asystem
ofinteracting particles
with initial distributionPp
which is inequilibrium.
Ofp(x)
weassume that it is zero outside a finite set. The case when
p(x)
=p( -x)
isthe
symmetric
case and then the process is reversible withrespect
to anyone of the invariant measures. But in this article we will assume
only
thator that the
jumps
have mean zero. Now the process is notnecessarily
reversible. We will also assume an
irreducibility
conditionnamely
that{x : p ( x )
>0} generates
the whole groupZd .
If we start our evolution under the
assumption
that there is aparticle
at0 and that at other sites we have a random Bernoulli
configuration
withdensity
p , we cantag
theparticle
at 0 as it moves around and denote its location at time tby zt .
We are interested inproving
a Brownianscaling
limitfor zt ,
i.e. to establish that converges as A - oo to aBrownian motion in distribution. In
[2],
with ClaudeKipnis
weproved
thatthis was indeed so in the
symmetric
case. The casep(l)
=p(-1) = 1 2
inone dimension is
special
and leads to Brownian motion with zero variance.In all other cases it is
nondegenerate.
In this article we will extend these results to theasymmetric
mean zero case.2. EVOLUTION OF THE TAGGED PARTICLE
In order to follow the motion of a
tagged particle
the state space has to bechanged.
The state space H cannotdistinguish
betweenparticles.
Weshall find it convenient to describe the current state of the
system by giving
the location of the
tagged particle
and the environment around thetagged particle.
In other words the state space isfi
=Zd
xHo.
HereHo
is thespace of
configurations
onZd - ~0~.
In order to describe the evolution in the spacefi
we need to describe a transformation Tx that acts onHo
for
each x ~
0.is
meaningful only
if = 0 and describes the effect of thetagged particle,
whichby
definition isalways
at zero,jumping
to x. We relocate theorigin
at x the new location of thetagged particle.
The transformations for 0 are well defined onno.
The evolution of thetagged particle
onfi
isgoverned by
thefollowing generator
If F were a function
of q only,
thenIn other words if
(zt, qt)
is thetagged system , ~t by
itselfis a
MarkovProcess with
generator Lo .
The Bernoulli measuresPp
onHo
definedby
Vol. 31, n° 1-1995.
276 S. R. S. VARADHAN
are invariant measures for
Lo. L
on the other hand does not have aninvariant measure because
the zt part
will wander away inZd.
Our initial distribution on
S2
is80
xPg,
i.e. we start from z = 0 and 7yis in
equilibrium .
Then under theL
evolution yy isalways
inequilibrium.
zt is the location of the
tagged particle
at time t and thescaling
limit isto be established for it.
3. OUTLINE OF PROOF
A direct calculation
yields
.or
equivalently
for each 0 inR~
Therefore,
Here
M(t)
is aMartingale
withstationary
increments. The basic idea in[2]
was toreplace
the first term on theright
in the aboveequation by
aMartingale
term and an error term.Our
ability
to do sodepended
on thefollowing procedure.
Step
1.Solve the
equation
For
simplicity
let us takejust
onecomponent of ~ .
Based on an estimatewhere
D~(~) = - Lo u, u >~
is the Dirichlet form of u, weget
for the solution uxThis
gives
us boundsholding uniformly
as A - 0.Step
2.Using
eitherspectral theory
or a more directargument
one establishes in fact thatand
This was
enough
to reduce the Brownianscaling property for zt
to thesame
thing
for aMartingale
withstationary
increments which iselementary
and standard.
Step
3.We prove
compactness by establishing
thetightness
of the distributions ofunder Brownian
scaling.
Step
4.Establish the
nondegeneracy
of the Brownian motion obtained as thescaling
limit.4. DETAILS OF PROOF
Due to the
asymmetry
one has to makechanges
in theproof along
theway.
Vol. 31, n° 1-1995.
278 S. R. S. VARADHAN
Step
1.where are
weights
with = 0 . We can therefore rewritefor some
weights y).
Because ofirreducibility
we can assume thaty) ~
0only
ifp(y - x)
> O. Since~(x) - ~(y) = (03C3x,y~)(x))
we canwrite,
where
Here and in what follows E is
expectation
relative toPg
for some fixed0 p 1. If we denote
by
then the full Dirichlet form for
Lo
isStep
2.If now one solves the
equation
one can
get
the estimatesWe can as before take a
subsequence
of uxconverging
to a limit uin
Hi.
HereHi
is thecompletion
of nice functions withrespect
to theDirichlet norm
Do (u) .
It contains a lot ofgeneralized
functions and consiststechnically
of limits ofequivalence
classes of functions modulo constants.Let us suppose that the
following
estimate holds. For all functions F andG,
then
Lo
will be a boundedoperator
fromHi
into andAux -
0weakly
inH-i.
ThereforeFrom this we
obtain,
where , > is the
pairing
betweenHi
andH -1,
the latterbeing
the formaldual of the former.
Taking
limits as A - 0 in(4.1)
ifd1
= lim 03BBEu203BB andd2
= limalong
suitablesubsequences
thenBy
lowersemicontinuity Do ( u) d2.
Thereforedi
= 0 andd2
=Do ( u).
This proves the
strong
convergence of ux inHi
and also establishesIt is now routine to prove the
uniqueness
of the limitpoint.
So theinequality (4.2)
which is obvious with C = 1 in thesymmetric
case is the crucialstep
in thenonsymmetric
case. We shall prove it in the last section. The rest of the details are identical to thesymmetric
case.Step
3.Whereas in
[2],
for thesymmetric
case,compactness
was a consequence of the estimate instep 1,
in our moregeneral
context we need to use somespecial properties
of We start with the estimateAs in
step
1Vol. 31, n° 1-1995.
280 S. R. S. VARADHAN
and
We have used the facts that
~r~(~c)-~(y)~
1 and =EG2(~7) _
1. Therefore
In other words
Compactness
is now a consequence ofGarsia-Rodemick-Rumsey
estimatewhich can be found in
[4].
Step
4We now establish the
nondegeneracy
of thelimiting
Brownian motion.From the outline of the
proof
it is clear that what we need to establish isthat the
martingale produced by / 1b(qs) , 0
> dsnamely N(t), B
>cannot cancel the
martingale M(t),
() >. There are two classes ofmartingales generated by
theunderlying
Poisson events:jumps
that involvethe
tagged particle,
identifiedthrough
Tx and thoseinvolving
otherparticles
identified
through
with 0. These areorthogonal martingales
because
they
relate to non simultaneous Poissonjumps.
IfN(t)
wereto
totally
cancelM(t),
which involvesonly
the firsttype
ofjumps,
itsorthogonal projection
on to the secondtype
ofmartingales
should go to zero.This can
happen only
if for thecorresponding
ux, - 0 as A - 0.But if
Di (ux)
- 0 then it follows from our estimates that 0as well and this forces
N(t)
to beidentically
zero. With a small bit ofextra calculation one can turn this into a lower bound for the variance of the
limiting
Brownian motion.With
only
the basic estimate(4.2) remaining
to beproved
in the nextsection we have now established our main result.
THEOREM 4.1. -
If
zt is the locationof
thetagged particle
inZd
then as1~ ~ 00 the distribution
of
the stochastic process converges in Skorohod space to a Brownian motion onRd
with anondegenerate
covariance matrix.5. THE BASIC ESTIMATE
For ’ the
operator Lo acting
on functions defined onno
we wish to establish the
following
estimate.THEOREM 5.1. - For
functions
andfor
some constantCP depending only
on p.Here ,
>P represents
the innerproduct
inL2 (PP )
andDo (F)
is theDirichlet
form
Before we prove Theorem 5.1 let us make some observations.
1. If
Lo
weresymmetric
inL2(Pg)
then theinequality
is valid with 2.Suppose
A is a Markovgenerator
on a finite state space with an invariant measure ~c and A is notsymmetric.
Let A be thesymmetrization
A -~- 2 A*
in~2(~6).
Since Aand
A have the same range, if we haveAg
= hwe also have for
some g, Ag
= h and the is well defined and the two Dirichlet forms are relatedby
Let us first prove a similar estimate for the
untagged system
L on H.Vol. 31, n° 1-1995.
282 S. R. S. VARADHAN
LEMMA 5.2. - For any two
functions F, G
on SZ andfor
any pProo, f: -
Theproof depends
on thefollowing
considerations.Suppose
~1,~2,’’’~ are k
points
inZd
such that ai + a2 + ... + ak =0,
then theprobability
distribution onZd
definedby == i
forj
=1, 2 ... k
andx(x)
= 0 for all other x hasclearly
mean 0. Thesequence Yo =
0,~i
= Y2 = ai + a2 , ... , yk = ai + a2 + ... ~.. a~ - 0 defines acycle
C = ~1, ~ ~ ~ , and a x can be associated to each suchcycle by taking ~ = ~ 2014
Moreover one can assume that thecycle
has no doublepoints.
Otherwise thecycle decomposes
into two ormore
cycles
and xc is a convex combination of 03C0Cicorresponding
to thecomponent cycles.
We can therefore limit ourselves to irreduciblecycles.
IfCi, C2 , ... , Cz
are l irreduciblecycles
and ~2?’ " wi arenonnegative weights adding
up to1,
the convex combinationp(x) = (x)
is amean zero
probability
distribution onZd.
We have the converseLEMMA 5.3. -
Any p(x)
withfinite
support and mean 0 has arepresentation
for
someweights
w1, w2, - - - , wi and irreduciblecycles Cl, C2, - - - , Ci.
Proof -
Aproof
of this lemma can be found in[5].
We continue with the
proof
of lemma 5.2. Eachcycle
C introduces anoperator Ac
on Hby
One can
verify
thatAc
hasPP
for an invariant measure and is ingeneral
nonreversible unless k = 2. For any
cycle
C we can consider thecycle
C + x described
by x, x
+ ~1, ~ ~ ~ , x+ ~ = ~ starting
andending
at xrather than at 0 and define
We can make a translation invariant
generator
on Hby defining
Lc
is atypical generator
forasymmetric
mean zero random walk withsimple
exclusion. A consequence of lemma 5.3. is therepresentation
LEMMA 5.4. - Our generator
L for asymmetric
mean zerosimple
exclusionhas a
representation
for
someCl, C2, ~ ~ ~ , CL
which are irreduciblecycles.
Now we can
complete
theproof
of lemma 5.2. The Dirichlet form for L iseasily
seen to beweighted
sum of the forms for eachCi.
Therefore there isno loss of
generality
inassuming
l = 1 or L =Ac
for some irreducible C.The Dirichlet form for
Lc
is the sum of Dirichlet forms for eachAc+x. By
Schwartz’s
inequality
it isenough
to prove the estimate for eachAc+x
andthis is
essentially
observation 2. The idea is that instead of detailed balance thatproduces reversibility
we now have local balance thatyields
bounds.Now we have to extend these considerations to the
tagged system.
We need another basic idea.Suppose (Q, 0, P)
is aprobability
space andTl, T2, ~ ~ ~ , T~
are k measurepreserving
transformations. Let us assumeTk ... Ti
=I,
and defineOur claim is that our basic estimate is valid in this context.
LEMMA 5.5. - We have
for
all F andG,
Proo.f.
because
Vol. 31, n° 1-1995.
284 S. R. S. VARADHAN
Rest is Schwartz.
Finally
we return to theproof
of Theorem 5.1. Theoperator
decomposes
intocycles
and we can assume without loss ofgenerality
thatp(x,) _
for some irreducible C. Theproblem
is that 0plays
aspecial
role and translates C + x of the
cycle
C that touch 0 create trouble. Wecan write
where
L2F
involvesonly jumps
of theuntagged particles
and in additionto full
cycles
that are estimated without any trouble there areincomplete cycles
becausethey
gothrough
theorigin. Li on
the other hand involvesonly jumps
of thetagged particle.
Let us remark that
so that the terms of
Li
andL2
look similar. Let ourcycle
be0 =~0~1, " ’, yk = 0
with ai
= ~2 - for i =1,.’., ,1~ .
Thenignoring
constants I/k and
disregarding
the fullcycles,
The rest of the
proof
can be best described in words.Suppose
there is anempty
site in theloop
in front of thetagged particle,
i.e. = 0. Thenthe
tagged particle
can move, that is we canapply
Now theempty
site created at theorigin
isreally
at - ai =(a2 + ... + ak )
because theorigin
hasshifted
with thetagged particle. -ai
is the last site of theloop
that startsfrom the new
origin
i.e. the old ai . One can effect o~~2 +... +~~ _ 1,~2 +~ ~ ~+ak andget
a free site at a2 + ... + We canproceed
in this fashiontill we
get
a free site at a2. Now thetagged particle
canjump
to a2 andthe whole process starts
again.
After severalsteps
thetagged particle
willreturn to its
original starting point
with anempty
site in front and all otherparticles
inexactly
the sameposition
that we started from. This takesexactly n
=~(A; 2014 1) steps
and we use up every term ofLi
andL2 exactly
once. In other words
where =
S1E1
andSi
= I onEi.
We can uselemma 5.5 at this
point
and we are done.6. REMARKS
The basic estimate
(4.2)
for theuntagged system
was derived and usedby
Lin Xu in his New YorkUniversity
PhD dissertation to establisha
hydrodynamic scaling
limit for mean zero random walks withsimple
exclusion. A central limit theorem for the
position
of atagged particle
inthe case of
asymmetric
one dimensionalsimple
exclusion(non
zeromean)
was considered in
[1] ] by
C.Kipnis.
ACKNOWLEDGEMENTS
The author wishes to thank F. Rezakhanlou for valuable discussions.
REFERENCES
[1] C. KIPNIS, Central limit theorems for infinite series of queues and applications to simple exclusion, Ann. Prob. Vol. 14, 1986, pp. 397-408.
[2] C. KIPNIS and S. R. S. VARADHAN, Central limit theorem for additive functionals of reversible Markov processes and application to simple exclusions, Comm. Math. Phys.
Vol. 104, 1986, pp. 1-19.
[3] T. LIGGETT, Interacting Particle Systems, Springer-Verlag, 1985.
[4] D. W. STROOCK and S. R. S. VARADHAN, Multidimensional Diffusion Processes, Springer- Verlag, Berlin-Heidelberg-New York, 1979.
[5] L. XU, Ph. D Dissertation, New York University, 1993.
(Manuscript received April 9, 1994;
revised August 14, 1994. )
Vol. 31, n° 1-1995.