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Divergence Measure Fields and Cauchy's Stress Theorem.

M. SÏILHAVYÂ(*)

ABSTRACT - Divergence measure fields are integrable vector fields whose dis- tributional divergence is a measure. Some versions are derived of the divergence theorem for divergence measure fields on sets of finite perimeter. Using these results, it is shown that Cauchy fluxes from the theory of Cauchy's stress the- orem can be extended to a class of surfaces that includes singular surfaces of continuum mechanics (shock waves and phase boundaries). On the singular surfaces, the divergence of the stress has a surface delta type singularity, with tractions on a surface and its opposite different from each other.

1. Introduction.

Cauchy's stress theorem asserts that the forcef(S) exerted by one part of a continuous body on another part through a surface S of contact is expressed by

f(S)ˆ …

S

TndA

wherenis the normal toS,dAis the element of area ofS, andT, the main object of the stress theorem, is the stress tensor (1). Cauchy's derivation was heuristic, with unnecessary additional assumptions. Noll [19] raised the question of a rigorous derivation under minimal assumptions. Basic properties of interactions in a body were formalized in the concept of a Cauchy flux (2) in [13] and using this notion, the proof of the Cauchy stress

(*) Indirizzo dell'A.: Mathematical Institute of the AV CÏR, ZÏitna 25, 115 67 Prague 1, Czech Republic ± Department of Mathematics, University of Pisa, Via F.

Buonarroti, 2, 56127 Pisa, Italy.

2000 MSC74A99, 28A75

(1) Similarly, the flux of heatF(S) through a surfaceSis given by the heat flux vectorqviaF…S† ˆ„

SqndA.

(2) See Section 5.

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theorem was given under natural, albeit still restrictive assumptions (3).

These ideas were then adapted to the context of sets of finite perimeter [3, 29, 24, 14, 20] (4). The assumptions of [13] lead to bounded stress fields, and in [29] it was shown that the distributional divergence div T of T is a bounded (integrable) function; see also [1]. Clearly, there are many si- tuations where the boundedness ofTand of divTare violated. Unbounded stress fields occur in fracture mechanics and in the existence theorems in nonlinear elasticity; div T has a (surface) d type singularity on singular surfaces (shock waves and propagating phase boundaries). Cauchy fluxes leading to unbounded stress fields and with divTan (unbounded) integr- able function are treated in [24-25]. In [25] it was shown that at this gen- erality the Cauchy flux can be defined only for «almost all» surfacesS. This covers unbounded stresses but excludes singular surfaces. The extension to stress fields arising in the presence of singular surfaces is in [7, 15-18].

These works consider Cauchy fluxes for which the resulting stress field may be unbounded with distributional divergence a Radon measure.

Following [7], such tensor/vector fields are called divergence measure fields in the subsequent treatment (5). However, the concept of almost every surface adopted in [7, 15-18] excludes surfaces where divT is not absolutely continuous with respect to Lebesgue's measure, in particular, the Cauchy flux is generally undefined on singular surfaces.

This paper (i) derives some new properties of the divergence measure fields including versions of the divergence theorem for them and (ii) uses (i) to extend Cauchy fluxes to a class of surfaces which includes the singular surfaces. To simplify the description, we switch from vector valued Cauchy fluxes (such as force) to scalar valued ones (such as the heat flux) (6); ac- cordingly, the stress tensorTchanges to the flux vectorq. The results may be extended to vector valued fluxes by components.

The divergence measure vector fields are locally integrable fields q:Rn!Rnwhose distributional divergence divqis a Radon measure. The paper first briefly addresses the question of the nature of the measure divqin Section 3. It is shown that ifq2Lploc(Rn)then for 1p<n=(n 1)

(3) See below.

(4) A variational approach to Cauchy's theorem is developed in [11], and an approach based on Whitney's geometric integration theory [28] is outlined in [21].

See also [23].

(5) The spaces of fields with integrable distributional divergence are treated in many works, e.g., [2, 12]; papers [4±6] consider divergence measure fields.

(6) See footnote (1) above.

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any Radon measure can arise as div q, while ifn=(n 1)p 1; then the singularities of div qare not be arbitrary: div q vanishes on sets of Hausdorff dimension mn p=(p 1) if p is finite and of dimension m<n 1 ifpˆ 1;moreover, in the latter case divqalso vanishes on each set ofn 1 dimensional Hausdorff measure 0.

Next, several versions of the divergence theorem are given for diver- gence measure vector fields and sets of finite perimeter. Ifqis a smooth vector field and W a smooth scalar field with compact support then the divergence theorem reads

…

@M

WqnMdHn 1ˆ …

M

DWqdLn‡ …

M

WqdivqdLn …1:1†

for any normalized set of finite perimeterMRnwith the measure the- oretic boundary@M and the measure theoretic normalnM(see Section 2 for definitions). For divergence measure vector fields the right hand side generalizes to

…

M

DWqdLn‡ …

M

Wdivq

where the last integral is the integral of a continuous function with re- spect to the Radon measure divq, but the left hand side of (1.1) does not have an immediate meaning. It turns out that for divergence measure vector fields the expressionqnM cannot be interpreted pointwise, i.e., the left hand side of (1.1) must be interpreted as a functional on scalar fields W on @M; [4-6]; this occurs even when the distributional diver- gence div qis an integrable function [26; Theorem 1.2, Chapter I]. It is shown that such a functional exists for every set of finite perimeter (Proposition 4.1, generalizing [6] to sets of finite perimeter); this func- tional is called the normal trace (7) ofq. Ifqis «bounded» near@M(see the definition of domination in Section 4), the normal trace has addi- tional properties. Theorem 4.2 gives two conditions under which the normal trace is a measure; one of these guarantees a measure with support on the closure@Mof the measure theoretic boundary; the other guarantees a measure supported on @M but requiresq2Lploc(Rn)with pn=(n 1) and regular boundary in some measure theoretic sense.

Finally, Theorems 4.4 and 4.6 give conditions which guarantee that the

(7) [6].

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normal trace is of the form …

@M

WqMdHn 1 …1:2†

where qM is an Hn 1 integrable function. Theorem 4.4 deals with bounded vector fields (q2L1(Rn)) and shows that then the normal trace is as in (1.2) withqM 2L1(@M)for any set of finite perimeter; this has been proved in [2; Theorem 1.9] for open sets with Lipschitz boundary. Theorem 4.6 deals with a generalqand proves (1.2) for sets M whose boundaries do not intersect some exceptional set ofn 1 di- mensional Hausdorff measure 0 where divqis too singular.

Using the divergence theorem 4.6, it is shown that every Cauchy flux that is defined for almost every surface in the sense of [7, 15-18] can be automatically extended to a class of surfaces where the measure divqhas a surface type singularity, thus including the singular surfaces. Clearly, this extended Cauchy flux reflects more fully the properties of the interaction.

However, generally the flux cannot be extended to all surfaces, for, firstly, the flux q vector has to satisfy the domination condition as mentioned above, and, secondly the surface cannot intersect the exceptional set where divqis too singular. Ifqis bounded then the domination condition is au- tomatically satisfied, the exceptional set is void and the Cauchy flux can be extended to all surfaces.

After a brief recapitulation of the basic measure theoretic notions in Section 2, Section 3 states some properties of the divergence measure fields. The divergence theorems and Cauchy fluxes are discussed in Sections 4 and 5, respectively. The proofs are given in the rest of the paper.

2. Preliminaries.

For a setMRnwe denote byMc:ˆRnnMthe complement ofM. If x2Rn and r>0 thenB(x;r)is the open ball of radiusrand center x.

Lnis the (outer)Lebesgue measureinRn;ifARnthenjAj Ln(A) is the Lebesgue measure ofA. If 0m<1; we denote byHmthem dimensional Hausdorff measure [10; §§ 2.10.2-6]. Briefly, if ARn then

Hm(A):ˆlim

d!0Hmd(A)

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where for anyd>0 thesizedapproximationHmd(A)is defined by Hmd(A)ˆaminf X1

iˆ1

(diamCi=2)m:CiRn; A[

i

Ci;diamCi<d

( )

; where diamCˆsup fjx yj:x;y2Cgis the diameter ofC,

am:ˆGm(1=2)=G(m=2‡1);

and Gis the Euler gamma function. If mis an integer, then am is the volume of the unit ball inRmandHmcoincides with themdimensional area on mdimensional manifolds inRn; in particularHnˆLn.

IfMRnisLnmeasurable andx2Rnwe say thatMhas adensityat xif the following limit exists:

D(x;M):ˆlim

r!0

M\B(x;r)

j j

anrn ;

which is then called thedensity ofMat x. A pointx2Rn is said to be a point of densityofMifD(x;M)ˆ1. For a measurable setMwe denote by M the set of all points of density of M. By Lebesgue's differentiation theorem [27; Theorem (7.2)],Mis a Borel set and the symmetric differ- ence ofM andM hasLn measure 0. We define themeasure theoretic boundary@Mof a measurable setMby

@MˆRnn(M[(Mc));

cf. [10; § 4.5.12].@Mis a Borel set andj@Mj ˆ0:We say that a measurable setMRn isnormalizedifMˆM:

By a Borel measure in Rn we mean any s additive function m:A![0;1] whose domainA is a salgebra which containsall Borel sets inRn:Thus the restrictions ofLn;Hmto their respective systems of measurable sets are Borel measures. By a (signed)Radon measureinRn we mean any sadditive functionm:B !Rdefined on thesalgebraB of all Borel sets in Rn. By a measurewe mean either a Borel or a Radon measure. If m is a Radon measure we denote by j jm the total variation measure,which is a nonnegative Radon measure. Thenk k ˆm j j(Rm n)<1 denotes thetotal variationofm. We denote byM(Rn)the set of all Radon measures on Rn and by M‡(Rn)the subset of nonnegative Radon mea- sures onRn.

IfARn is a Borel set andma measure, we denote bymj Athere- striction ofmtoA, i.e., a measure given by

mj A(B)ˆm(A\B)

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for anyBfrom the domain ofm. We say that a measuremissupportedon a Borel setAifmˆmj A. We say that a measuremvanisheson a Borel set Nifm(A)ˆ0 for eachANfrom the domain ofm. Ifmis a measure and f:Rn!Ra Borel function that is integrable with respect to m; then fm denotes the measure given by

(fm)(A)ˆ …

A

f dm

for eachAfrom the domain ofm:The reader is referred to [10; Chapter 2]

for further details of the measure theory.

A measurable setMRnis said to be a set offinite perimeter(cf. [10;

Theorem 4.5.6]) if the distributional partial derivativesDi1M; 1in; of the characteristic function 1MofMare Radon measures.Mis a set of finite perimeter,Hn 1(@M)<1(cf. [10; Theorem 4.5.11]) ,there exists a Borel functionnM:@M!Sn 1, whereSn 1 is the unit sphere inRn such

that …

M

DWdLnˆ …

@M

WnMdHn 1 …2:1†

for each W2C10 (Rn): Here C10 (Rn) is the set of all infinitely differ- entiable functions with compact support and DW is the gradient of W.

The functionnM is determined by (2.1) uniquely to within a change on anHn 1 negligible subset of@M; and is called themeasure theoretic normal ofM.

3. Divergence measure fields.

Aq2L1loc(Rn)(8) is said to be adivergence measure fieldif there exists am2M(Rn)such that

…

Rn

DWqdLnˆ …

Rn

Wdm …3:1†

for everyW2C10 (Rn):One then writes divq:ˆm:The space of all diver-

(8) Here Lploc(Rn), 1p 1, stands for the set of all measurable maps q:Rn!Rnthat are locally integrable with poverp.

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gence measure fields is denoted by L1locMdiv(Rn) and we write LplocMdiv(Rn):ˆL1locMdiv(Rn)\Lploc(Rn)whenever 1p 1.

Fornˆ1 the spaceL1locMdiv(Rn)reduces to the space of functions of bounded variation onR1;throughout the rest of the paper we assume that n>1: The following are archetypical examples of divergence measure fields:

EXAMPLES3.1 ± (i)(Transversal fields). Letf 2L1loc(Rn 1)and define q2L1loc(Rn) byq(x1;. . .; xn)ˆ(0;. . .;0; f(x1;. . .; xn 1)); x2Rn:Then q2L1locMdiv(Rn) anddivqˆ0.

(ii)(Singular surface). Lete1 be the coordinate vector in the x1 di- rection and q(x)ˆe1 if x1>0 and q(x)ˆ0 if x10; x2Rn. Then q2L1locMdiv(Rn) anddivqˆHn 1j fx2Rn:x1ˆ0g.

Ifmis a Radon measure and 0m<1; we say thatmisHm abso- lutely continuous if j j(B)m ˆ0 for every Borel set BRn with Hm(B)ˆ0:We say that a Borel setBhassfiniteHmmeasureifBis a union of countably many Borel sets of finiteHmmeasure.

THEOREM3.2. Let n=(n 1)p 1; q2LplocMdiv(Rn); and set d:ˆ n p=(p 1) if p<1,

n 1 if p= 1.

(

(i)If p<1; thenjdivqj(B)ˆ0for everyBorel set B ofsfiniteHd measure;

(ii)if pˆ 1thendivqisHn 1 absolutelycontinuous.

For the given range ofp, the value ofdchanges monotonically from 0 to n 1: The theorem imposes a restriction on the dimensionality of the measure divq: ifq2Lploc(Rn); then divqcannot be concentrated on sets of dimension d:Thus, e.g., the Dirac dcannot occur as the divergence of someq2Lploc(Rn)withpn=(n 1);the improved integrability ofqim- plies improved regularity of divq. In particular, for bounded vector fields divq is absolutely continuous with respect to the n 1 dimensional Hausdorff measure. The bound d is optimal: if 1p<n=(n 1); then essentially every measure can occur as a divergence of someq2Lploc(Rn) while if n=(n 1)p 1then there are vector fields q2Lploc(Rn)with divergences concentrated on sets of dimension s higher than but arbi- trarily close tod:

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EXAMPLE 3.3. ± (i) If 1p<n=(n 1) then for anysigned Radon measuremwith compact support there exists aq2LplocMdiv(Rn)such that divqˆm:

(ii) If n=(n 1)p 1 then for anys>d there exists a q2LplocMdiv(Rn)such thatdivqis notHs absolutelycontinuous.

The vector fieldqis constructed as the Newton force (the gradient of the Newton potential) for the uniform mass distribution on a compact setK with 0<Hm(K)<1; see Proposition 6.1.

4. The divergence theorem.

Proposition 4.1 and Theorems 4.2, 4.4 and 4.6 discuss the divergence theorem for normalized sets of finite perimeterMandq2L1locMdiv(Rn) in decreasing generality but with improving properties of the boundary term (see the discussion in Introduction). It is first noted in Proposition 4.1 that the boundary term is always a linear functional on the space Lip0(@M) of Lipschitz continuous functions with compact support on

@M. For any set WRn we denote Lip0(W)the set of all real valued

Lipschitz continuous functions W on W such that fx2W:W(x)6ˆ0g is bounded, with norm

W

k kLip0(W)ˆLip(W)‡k kW C(W) where Lip(W)is the Lipschitz constant ofWand

W

k kC(W):ˆsupfjW(x)j:x2Wg:

PROPOSITION4.1 (Normal trace as a functional). If M is a normalized set with finite perimeter andq2L1locMdiv(Rn)then there exists a linear functionalNM(q;):Lip0(@M)!Rsuch that

NM(q;Wj@M)ˆ …

M

DWqdLn‡ …

M

Wdivq …4:1†

for everyW2Lip0(Rn):If N:ˆ(Mc)then

NM(q;)‡NN(q;)ˆ divqj @M:

…4:2†

If M or Mc is bounded then NM(q;) is continuous with respect to k kLip0(@M):

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HereWj@Mis the restriction ofWto@Mand the assertion is that the right hand side of (4.1) depends only on the boundary values of W: NM(q;)is called the normal trace of q on@M: Although the frameworks are not strictly comparable, (4.1) may be considered to be a generalization of the relevant results of [4-6]. Equation (4.2) says that the normal traces from the two sides of@Mare different if divqis concentrated on@M;see (4.11), below, for a more concrete form, cf. also Example 3.1(ii).

Next we are concerned with specific forms of the normal trace. IfMis a normalized set of finite perimeter andq2L1locMdiv(Rn)we say that the normal traceNM(q;)is

(i) ameasureif there exists anMˆnM(q)2M(@M)such that NM(q;W)ˆ

…

Rn

WdnM

for everyW2Lip0(@M);

(ii) an integrable function if there exists qMˆqM(q)2 2L1(@M;Hn 1)such that

NM(q;W)ˆ …

@M

WqMdHn 1

for everyW2Lip0(@M).

The following theorem discusses conditions under which the normal trace is a measure. IfMis a normalized set of finite perimeter, we say that aq2L1loc(Rn)is

(i) weakly dominated on @M if there exists a sequence rj>0;

rj !0; and a constantC<1such that 1

anrnj …

@M

…

B(x;rj)

q(y)nM(x)

dLn(y)dHn 1(x)C …4:3†

for everyj2N;

(ii) dominatedon @M if there exists a functiong2L1(@M;Hn 1) and a sequencerj>0; rj!0; such that

1 anrnj

…

B(x;rj)

q(y)nM(x)

dLn(y)g(x) …4:4†

forHn 1a.e.x2@Mand everyj2N:

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Clearly, ifqis dominated on@Mthen it is weakly dominated on@M:If q2L1(Rn) then q is dominated on any @M; if q2L1loc(Rn) then q is dominated on@MifMis bounded.

THEOREM4.2. (Normal trace as a measure).Letq2L1locMdiv(Rn)and let M be a normalized set of finite perimeter. Then

(i) ifqis weaklydominated on@M; the normal trace is a measure supported on@M;

(ii) if q2LplocMdiv(Rn), where n=(n 1)p<1; d is as in Theorem3.2,qis dominated on@M, and

@sM has as finiteHdmeasure …4:5†

where@sMˆ fx2@M:D(x;M)does not existg; then the normal trace is a measure supported on@M:

Assertion (i) guarantees a measure supported on @M, which may be large, while (ii) guarantees a measure supported on@M; which is a set with Hn 1(@M)<1:Condition (4.5) requires that the «singular part»@sM of the boundary be small. We note thatD(x;M)exists and is equal to 1/2 for Hn 1 a.e. x2@M; however, since d<n 1; Condition (4.5) requires more. Theorem 4.2 holds also ifpˆ 1; in which case (4.5) can be omitted, but in this special case the normal trace is an integrable function, cf.

Theorem 4.4, below.

Finally we consider situations when the normal trace is an integrable function. Let firstq2L1locMdiv(Rn)\L1(Rn); it will turn out that then the normal trace is an integrable function for every normalized set of finite perimeter; moreover, it is given by a functionq0(x;n)which we shall now introduce. If x2Rn; n2Sn 1; and r>0; let B(x; n;r):ˆB(x;r)\

\ fy2Rn:(y x)n<0g:Ifq2L1loc(Rn); we define a functionq0:Rn Sn 1!Rby

q0(x;n)ˆ limr!0

n an 1rn

…

B(x;n;r)

q(y) x y x y

j jdLn(y) if the limit exists and is finite;

0 if the limit either does not exist or is infinite;

8>

>>

>>

<

>>

>>

>:

x2Rn;n2Sn 1:The functionq0(x;n)is a generalization of the expression q(x)n:

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REMARK4.3. Ifq2L1loc(Rn)andx2Rnis a Lebesgue point ofqthen q0(x;n)ˆq(x)n

for everyn2Sn 1:

Hereqis any representation of the classq. In Example 3.1(ii), q0(x;n)ˆ e1n if e1n>0;

0 else;

(

for anyxwithx1ˆ0. Thusq0is bound to be nonlinear in the presence of discontinuities in the normal component ofq.

THEOREM4.4. (Normal trace as a function, special case).

(i) If q2L1locMdiv(Rn)\L1(Rn) then for everynormalized set of finite perimeter M the normal trace is a bounded function, i.e., there exists a qM2L1(@M;Hn 1)such that

…

@M

WqMdHn 1ˆ …

M

DWqdLn‡ …

M

Wdivq …4:6†

for everyW2Lip0(Rn);moreover, qMis given by qM(x)ˆq0(x;nM(x)) …4:7†

forHn 1a.e.x2@M; andkqMkL1(@M;Hn 1) kqkL1(Rn):

(ii)If, more generally,q2L1locMdiv(Rn)andqis dominated on@M;

then the normal trace is an integrable function qMwhich satisfies(4.7)for Hn 1a.e.x2@M.

The existence of the normal trace as in (i) has been proved in [2;

Theorem 1.9] for open sets with Lipschitz boundary. In addition, (4.7) shows that the normal trace depends on the shape of@Monly through the normal nM. In the context of Cauchy fluxes, assertions of this type are called Cauchy's postulate.

To proceed to the generalp, we need to isolate the part of the measure divqwhich is singular with respect toHn 1:The following proposition, a direct generalization of Lebesgue's decomposition, is a basis for that. If 0m<1; we say that anh2M‡(Rn)isHmsingularif it is supported on a Borel setBwithHm(B)ˆ0:

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PROPOSITION4.5. If h2M‡(Rn)and0mn then there exists a unique decomposition ofhas

hˆh<m‡hm‡h>m

…4:8†

whereh<m;hm;h>m2M‡(Rn)have the properties

(i) h<misHmsingular;

(ii) hmisHmabsolutelycontinuous and supported on a set ofsfinite Hmmeasure;

(iii) h>m(B)ˆ0for everyBorel set B ofsfiniteHmmeasure.

We may say that the dimensions ofh<m;hm;h>mare less than, equal to, and bigger thanm, respectively. The Lebesgue decomposition is the case mˆn by noting h>n ˆ0 by (iii). By the Radon Nikodym theorem [27;

Theorem (10.39)] we have

hm(A)ˆfHmj S0

…4:9†

for some Borel setS0Rnof s finiteHmmeasure and some nonnegative Borel functionf:Rn!Rwithf 2L1(S0;Hm); f(x)>0 for everyx2S0 and f(x)ˆ0 for every x2=S0(9). Then S0; f are determined to within a change on aHmnull set. For aq2L1locMdiv(Rn)we apply Proposition 4.5 withmˆn 1 to obtain

jdivqj ˆ jdivqj<n 1‡ jdivqjn 1‡ jdivqj>n 1: Thenjdivqjn 1ˆfHn 1j S0wheref; S0are as above; moreover,

divqj S0ˆJHn 1j S0

for some Borel function J:Rn!R such that J2L1(S0;Hn 1) and J(x)ˆ0 for x2=S0: The set S0 is the (analog of the) singular set of con- tinuum mechanics and J is related to the jump of the normal trace of q across@M; see (4.11), below.

THEOREM 4.6 (Normal trace as a function, general case). Let 1p 1; q2LplocMdiv(Rn)and let M be a normalized set M of finite perimeter for whichqis dominated on@M and

jdivqj<n 1(@M)ˆ0:

…4:10†

(9) On the contrary, the measure h>m, despite of being Hm absolutely continuous, cannot be expressed as in (4.9), because it is supported on a set of nonfiniteHmmeasure.

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Then the normal trace of q on @M is an integrable function qM2L1(@M;Hn 1). If N:ˆ(Mc)then also the normal trace ofqon@N is an integrable function and

qM(x)‡qN(x)ˆ J(x) …4:11†

forHn 1a.e. x2@Mˆ@N:

Equation (4.10) ensures that @M does not intersect the region where div q is too singular. In contrast to the situation q2L1locMdiv(Rn)\

\L1loc(Rn); in the present context the normal traceqMdoes not seem to be given by (4.7) generally. However, we have the following weak form of the local dependence ofqMon the shape of@M:

REMARK 4.7. If Mi; iˆ1;2; are two normalized sets of finite peri- meter which satisfythe hypothesis of Theorem4.6and if S:ˆ fx2@M1\

\@M2:nM1(x)ˆnM2(x)gthen the normal traces qMisatisfy qM1(x)ˆqM2(x) forHn 1 a:e: x2S:

5. Cauchy fluxes.

LetP be the set of all bounded normalized sets of finite perimeter. An oriented surfaceis a pairSˆ(S;^ nS)such that is a Borelsubset of@Mofsome M2P andnS(x)ˆnM(x)forHn 1a.e.x2S:^ LetS betheset of alloriented surfaces. We say that the oriented surfacesSˆ(^S;nS)andTˆ(T;^ nT)are compatibleif there exists an oriented surfaceUˆ(U;^ nU)2S such that

S^[T^ ˆU^ and nU(x)ˆ nS(x) if x2S;^ nT(x) if x2T^ (

forHn 1a.e.x2U:^ We then writeUˆS[T:IfM2P we interpret@Mas the oriented surface@Mˆ(@M;nM):

We denote by G the set of all Borel functions (not classes of equiva- lence)h:Rn![0;1] such thath2L1loc(Rn). Ifh2G andh2M‡(Rn)we denote [7]

Phh:ˆ fMRn:M2P; …

@M

h dHn 1<1;h(@M)ˆ0g;

S hh:ˆ fS2S :S@M;M2Phhg:

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We say that NS is a null set if N S nS hh for some h2G; h2M‡(Rn). We say that a setD S contains almost all ofS ifS nD is a null subset ofS :Ifpis a property associated with all surfacesS2S ; we say thatpholds for a.e.S2S if there areh2G andh2M‡(Rn)such that p(S)is true for allS2S hh:

ACauchy fluxis any mappingF:D !R; where D S ; such that for someD0 D that contains almost all ofS we have

(i) if S, T2D0 are disjoint compatible material surfaces then S[T2D0and

F(S[T)ˆF(S)‡F(T);

(ii) there existsh2G such that jF(S)j

…

S

h dHn 1 …5:1†

for everyS2D0;

(iii) there existsh2M‡(Rn)such that jF(@P)j h(P) for anyM2P with@M2D0:

We say thatFis aCauchy flux of classLploc; 1p 1;if the function has in (5.1) can be chosen inLploc:

The above definition is equivalent to the one given in [7, 15-18]; the papers [13, 29] deal withh2L1loc(Rn),hˆcLn; c2R; and [24-25] with h2Lploc(Rn),hˆfLn; f 2Lploc(Rn); 1p 1:

THEOREM5.1. F is a Cauchyflux if and onlyif there exists a vector fieldq2L1locMdiv(Rn)such that, for anyrepresentationqof the classq,

F(S)ˆ …

S

qnSdHn 1 …5:2†

for a.e. S2D:The correspondence F$q is one to one if one identifies Cauchyfluxes that differ onlyon null subsets ofS and interpretsqas Lebesgue classes of equivalence. Moreover, F is of class Lplocif and onlyif q2LplocMdiv(Rn), 1p 1:

The fieldqis called the flux vectorcorresponding toF. Theorem 5.1 follows from the results of [7]; previous special cases are [13, 29, 24-25].

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For a given Cauchy fluxFwith the flux vectorqdefine

P:ˆ fM2P: qis dominated on@M andjdivqj<n 1(@M)ˆ0g;

S :ˆ fS2S :S@M for someM2Pg;

andF:S !Rby

F(S)ˆ …

S

qMdHn 1 …5:3†

for anyS2S whereM2P; S@MandqMis the normal trace ofqon

@M; which exists by Theorem 4.6. The function F is well defined by Remark 4.7.

THEOREM 5.2. If F is a Cauchyflux then F is a Cauchyflux and F(S)ˆF(S)for a.e. S2S ;if F is a Cauchyflux of class L1locthen F is defined onS ˆS :

The fluxFis definednaturallyas the densities from (5.3) satisfy the divergence theorem. Its domainScontains singular surfacesS(surfaces with divqj S6ˆ0) providedqis dominated onS.By (4.11),

F(S)‡F( S)ˆ divq(S) where Sis the surfaceSwith the opposite orientation.

6. Proof of Theorem 3.2 and Example 3.3.

PROOF OFTHEOREM3.2. (i): It suffices to prove thatjdivqj(B)ˆ0 for each Borel setBwithHd(B)<1:LetBbe a Borel set withHd(B)<1:

From the Hahn decomposition [27; Theorem 10.36] we deduce that there exist Borel sets BB with B‡\B ˆ ;; B‡ˆB‡ˆB such that divqj B0: Our goal is to prove that divq(B)ˆ0: It suffices to prove only divq(B‡)ˆ0 for which in turn by [10; § 2.2.5] it suffices to prove that divq(K)ˆ0 for any compact subsetK of B‡: Thus letKB‡ be compact. LetW:Rn ![0;1] be given by

W(x)ˆ

1 if j jx <1;

2 j jx if 1j j x 2;

0 if j jx >2 8>

<

>:

and note thatWis a Lipschitz continuous function withjDWj 1 forLna.e.

x2Rn:Lete>0. Sinced<nandHd(K)<1, we haveLn(K)ˆ0:Using q2Lploc(Rn);p<1; we deduce that there exists a bounded open setUwith

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KUandkqkLp(U)<e:Furthermore, by [10; Theorem 2.2.2(2)] this setU may be chosen so as to satisfy divq(UnK)<e:SinceKis compact, there exists and>0 such that for any ballB(x;r)withr<dandK\B(x;r)6ˆ ;, we haveB(x;2r)U:From the definition ofHd;there exists a covering of K by a finite system of balls B(xi;ri); i2I; with ri<d and adP

i ridHd(B)‡1 (10). Thus S

i2IB(xi;2ri)U:LetWi(x):ˆW(ri1(x xi));

i2I; x2Rn, and let

v(x)ˆmax fWi(x):i2Ig

for everyx2Rn:Then 0v1; vis Lipschitz continuous, andvˆ1 on K. Since the support ofvis inU, we obtain

divq(K)ˆ …

K

vdivqˆ …

U

DvqdLn …

UnK

vdivq …6:1†

directly from the definition of divq(see (3.1)). We now estimate the right hand side. Since 0v1 and divq(UnK)e; we have

…

UnK

vdivq2e:

…6:2†

Further,

…

U

DvqdLnL1=qkqkLp(U) L1=qe …6:3†

where q:ˆp=(p 1) is the conjugate HoÈlder exponent and Lˆ

ˆ„

UjDvjqdLn:One easily finds that forLna.e.x2Rnthere exists at least onei2Isuch thatDv(x)ˆDWi(x)and hence

Lˆ …

U

jDvjqdLnX

i2I

…

Rn

jDWijqdLn

ˆX

i2I

…

B(xi;2ri)

jDWijqdLn 2nanX

i2I

rn qi 2nan=ad(Hd(B)‡1)

(10) In this proof we switch without change in notation from the Hausdorff measureHdto the spherical measureS d, [10; §§ 2.10.2±6], which is possible by the inequalities HdS d[(2n=(n‡1†]d=2Hd, see [10; § 2.10.6], which show that HdandSdhave the same system of null sets and sets of finite measure.

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where we note thatn qˆdandjDWij ri1onB(xi;2ri):Thus 0divq(K)(2nan=ad(Hd(B)‡1))1=qe‡2e

by (6.1), (6.2) and (6.3). The arbitrariness ofe>0 gives divq(K)ˆ0. Thus divq

j j(B)ˆ0.

(ii): We have to prove that ifBRn is a Borel set withHn 1(B)ˆ0 then divj qj(B)ˆ0. Thus letHn 1(B)ˆ0; letBhave the same meaning as in the proof of part (i), letKbe a compact subset ofB‡, and prove that divq(K)ˆ0: Let e>0; let U be an open set with KU such that divq(UnK)<e;corresponding to thisUwe find and>0 as in the proof of part (i). Since Hn 1(K)ˆ0; there exists a covering of K by a finite system of ballsB(xi;ri); i2I; withri<dandP

i rin 1<e:Ifvis as above, then (6.2) holds while (6.3) is replaced by

…

U

DvqdLnLk kq L1(U)

…6:4†

whereLˆ„

UjDvjdLn:As above, LX

i2I

…

Rn

DWi

j jdLnˆX

i2I

…

B(xi;2ri)

DWi

j jdLn 2nan

X

i2I

rin 12nane:

Thus we have

0divq(K)2nanek kq L1(U)‡2e

by (6.1), (6.2) and (6.4). Hence divq(K)ˆ0 and consequently

divq(B‡)ˆ0: p

PROPOSITION6.1. Letmis a signed Radon measure onRn with com- pact support and

q(x):ˆ 1 nan

…

Rn

(x y)dm(y) x y j jn …6:5†

for everyx2Rnfor which „

Rn

x y

j j1 ndj j(y)m <1:Then (i) q2L1locMdiv(Rn)and

divqˆm;

…6:6†

(ii) if1p<n=(n 1)thenq2Lploc(Rn);

(iii) if n=(n 1)p 1 then q2Lploc(Rn) provided j j(B(x;m r)) crm for all x2Rn and all 0<r<a, where m>d; a>0, c>0 are constants and d is as in Theorem3.2.

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PROOF. Writeh:ˆj j;m let f(x) :ˆ

…

Rn

x y

j j1 ndh(y)

for every x2Rn so that f:Rn![0;1] and prove that f2Lploc(Rn) for everyp satisfying 1p<n=(n 1):By HoÈlder's inequality, with q the conjugate exponent,

fp(x)k kh p=q …

Rn

jx yj p(n 1)dh(y):

Therefore, ifz2Rnandr>0, …

B(z;r)

fp(x)dLn(x)k kh p=q …

Rn

…

B(z;r)

x y

j j p(n 1)dLn(x)dh(y):

For anyy2Rnwe haveB(z;r)B(y;jz yj ‡r)and therefore …

B(z;r)

jx yj p(n 1)dLn(x) …

B(y;jz yj‡r)

x y

j j p(n 1)dLn(x)

ˆC(jz yj)‡r)n p(n 1) whereC:ˆnan=(n p(n 1)):Therefore

…

B(z;r)

fp(x)dLn(x)Ck kh p=q …

Rn

(jz yj ‡r)n p(n 1)dh(y):

The last integrand is a bounded function ofyon the compact support ofh and thus the integral is finite. Hencef2Lploc(Rn); thus in particular,fis finite for Ln a.e. x2Rn and henceq is defined Ln a.e. onRn. (i): By

q(x)

j j n 1an1(x) we see that q is locally integrable. Equation (6.6) is standard by noting thatqis the derivative of the Newton potential corre- sponding to the mass distributionm:(ii): Has been proved above. (iii): Letm satisfy the hypothesis of (iii) and letsbe any number such thatd<s<m:

Assume first thatp<1and denote byqthe conjugate exponent. Writing x y

j j1 nˆjx yj s=qjx yjs=q‡1 n; we obtain by HoÈlder's inequality fp(x)…

x y

j j sdh(y)p=q… x y

j jp(s=q n‡1)dh(y):

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Prove that there exists aC<1such that …

x y

j j sdh(y)<C …6:7†

for everyx2Rn:Letx2Rnand writeM(r)ˆh(B(x;r))forr>0 so that M(r)crm. Then, standardly,

… x y

j j sdh(y)ˆ …

B(x;a)

x y

j j sdh(y)‡ …

B(x;a)c

x y j j sdh(y)

…a

0

r sdM(r)‡ …

B(x;a)c

a sdh(y)

r sM(r)ja0‡s …a

0

r s 1M(r)dr‡a skhk

cmam s

m s ‡a skhk ˆ:C which proves (6.7). Hence,

fp(x)Cp=q …

x y

j jp(s=q n‡1)dh(y):

Thus ifz2Rnandr>0; we have, usingB(z;r)B(y;jz yj ‡r);

…

B(z;r)

fp(x)dLn(x)Cp=q …

Rn

…

B(y;jz yj‡r)

x y

j jp(s=q n‡1)dLn(x)dh(y):

…6:8†

Bys>dwe haven‡p(s=q n‡1)>0;thus the inner integral is finite and equal to nan(n‡p(s=q n‡1)) 1(jz yj ‡r)n‡p(s=q n‡1); which is a bounded function of y on the compact support ofh:Thus the right hand side of (6.8) is finite. The casepˆ 1is similar. p PROOF OFEXAMPLE3.3. (i): This follows from Proposition 6.1 (i), (ii). Proof of (ii): If 0mn then there exists a compact set K such that 0<Hm(K)<1and for some constantc,

Hm(K\B(x;r))crm

for all x2Rn and r>0 [9; Corollary 4.12]. Choose any m such that d<m<s:Let m:ˆHmj K and let q be given by (6.5). By Item (i) of Proposition 6.1, q2L1locMdiv(Rn)and divqˆm: The measuremsatisfies

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the hypothesis of Item (iii) of Proposition 6.1 and thusq2Lploc(Rn):On the other hand, sincem<sandHm(K)<1; we haveHs(K)ˆ0: p

7. Proof of Proposition 4.1 and Theorem 4.2.

Let j be a radially symmetric mollifier on Rn; for any r>0 let jr(z)ˆr nj(z=r); z2Rn:For anyf 2L1loc(Rn)denote byfr2C1(Rn)the rmollification off,

fr(x)ˆ …

Rn

jr(x y)f(y)dLn(y);

x2Rn:Ifq2L1locMdiv(Rn)then divqr(x)ˆ

…

Rn

jr(x y)divq(y)

for every x2Rn: For anyMRn let 1M be the characteristic function of M.

LEMMA 7.1. Let M be a normalized set of finite perimeter and W2Lip0(Rn) such that Wˆ0 on @M. Then the function u:ˆ1MW is in Lip0(Rn)and Duˆ1MDWforLna.e. point inRn:

PROOF. Letv2C01(Rn); by the Gauss-Green theorem for the setM and the functionvW;

…

Rn

uDvdLn …

M

WDvdLnˆ …

M

vDWdLn …

Rn

v1MDWdLn

since vWˆ0 on @M: Thus the weak derivative of u is Duˆ1MDW and satisfies j jDu Lip(W) forLn a.e. point of Rn:The mollifications ur of u satisfy

Dur(x)ˆ …

Rn

jr(x y)Du(y)dLn;

henceDur(x)Lip(W)and consequentlyur(x) ur(y)Lip(W)jx yj for everyx,y2Rn:Furthermore,ur(x)!u(x)for everyx2Rn:Indeed, if x2M it suffices to use that u is continuous on M, vanishes onMc; and D(x;M)ˆ1; ifx2(Mc) thenu vanishes onMc; is bounded onM, and

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D(x;Mc)ˆ1: If x2@M then j j u Lip(W)r on B(x;r): The limit in ur(x) ur(y)

Lip(W)jx yjgivesju(x) u(y)j Lip(W)jx yjfor each

x,y2Rn: p

PROOF OFPROPOSITION4.1. Let Mbe a normalized set of finite peri- meter. Firstly, note that (3.1) holds for every W2Lip0(Rn). Indeed, it suffices to apply (3.1) to the sequence of mollificationsWrofWand letr!0:

Secondly, note that ifW2Lip0(Rn)andWˆ0 on@Mthen …

M

DWqdLn‡ …

M

Wdivqˆ0:

…7:1†

Indeed, the function uˆ1MW is Lipschitz continuous by Lemma 7.1; the application of (3.1) tougives (7.1). For anyW2Lip0(@M); defineNM(q;W) by

NM(q;W)ˆ …

M

D~WqdLn‡ …

M

~ Wdivq …7:2†

where~Wis any Lipschitz extension ofWtoRn with compact support. The existenceW~is easily deduced from the existence of an extension with the same Lipschitz constant ([10; Theorem 2.10.43]) and the fact that fx2@M;W(x)6ˆ0g is bounded. We note that the value of the right hand side of (7.2) is independent of the extensionW~by (7.1). Moreover,NM(q;)is linear since ifl2R;one can choose the extension corresponding tolWto be l~Wand similarly for the sum. This completes the proof of the existence of NM(q;):To prove (4.2), it suffices to write (4.1) forMand forN, to add the results, and subtract (3.1). Next, letMbe bounded and prove that

jNM(q;W)j Ck kW Lip0(@M) …7:3†

for some Cand allW2Lip0(@M):Using a suitable cutoff function that is equal to 1 on the (bounded) closure ofM, one can show that the extension~W ofWcan be chosen as to satisfy

~ W

k kLip0(Rn)Dk kW Lip0(@M) …7:4†

whereDis a constant independent ofW:But then from (7.2) and (7.4) we obtain (7.3) whereCˆD(„

Mj jdLq n‡kdivqk):Finally, ifMc is bounded, thenNN(q;)is continuous and (4.2) establishes the continuity ofNM(q;):

p LEMMA 7.2. Letq2L1locMdiv(Rn) and let M be a normalized set of finite perimeter.

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(i) If q is weaklydominated on @M then the normal trace is re- presented bya measurenMˆpM sMwhere

pMˆw lim

r!0 qr@MnMHn 1 j @M inM(Rn);

…7:5†

sMˆw lim

r!0 mr in M(Rn);

…7:6†

whereqris the mollification ofq,mr2M(Rn)is given by hmr;Wi ˆ

…

@M

…

M

W(y)jr(y x)dLn(y)ddivq(x)

for everyW2C0(Rn); and w* denotes the weak* convergence, understood along an appropriate sequence ofrtending to0;the support ofnMis in@M.

(ii) Ifqis dominated on@M thenpM ˆq0Hn 1j @M where q0ˆw lim

r!0 qr@MnM in L1(@M;Hn 1) where w denotes the weak convergence.

PROOF(i): Sinceqis dominated on@M; there exists a sequencerj!0 and aC<1such that (4.3) holds. Since for eachx2@Mandr>0;

qr(x)nM(x)

D

…

B(x;r)

q(y)nM(x)

dLn(y)

whereDis the maximum ofj; we deduce from (4.3) that …

@M

qr(x)nM(x)

dHn 1(x)E

for some E<1 and all rˆrj; j2N: Thus the total variation of qrj@MnMHn 1j @Mis bounded and hence, for some subsequence ofrj; still denoted byr; the limit in (7.5) exists. Further, one easily finds that jhmr;Wij divqj(@M)k kW L1(Rn) for each W2C0(Rn) and each r; i.e., kmrk divqj(@M):Thus for some subsequence ofrj; still denoted byr; the limit in (7.5) exists. LetW2Lip0(Rn):The divergence theorem for smooth vector fields and sets of finite perimeter reads

…

@M

WqrnMdHn 1ˆ …

M

DWqrdLn‡ …

M

WdivqrdLn; …7:7†

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and …

M

DWqrdLn! …

M

DWqdLn; …

@M

WqrnMdHn 1! …

Rn

WdpM

sinceqr!qinL1loc(Rn)and by (7.5). Next note that …

M

WdivqrdLnˆ …

Rn

Wrdivq

where

Wr(x)ˆ …

M

W(y)jr(x y)dLn(y);

…7:8†

and write …

Rn

Wrdivqˆ …

M

Wrdivq‡ …

(Mc)

Wrdivq‡ …

@M

Wrdivq:

…7:9†

The three terms on the right hand side of (7.9) converge, respectively, to …

M

Wdivq; 0;

…

Rn

WdsM:

The first two limits follow from (11)

Wr(x)! W(x) for everyx2M;

0 for everyx2(Mc)

by the dominated convergence theorem, while the last limit is (7.6) by observing that „

@MWrdivqˆ hmr;Wi:To summarize, the limit in (7.7) gives …

Rn

WdpMˆ …

M

DWqdLn‡ …

Rn

WdsM‡ …

M

Wdivq:

Thus the normal trace NM(q;) is represented by a measure nM: The support ofnM is in@M. Indeed, the support ofqrj@MnMHn 1j @Mis in @M and to show that the support of sM is in @M, we note that for each r<r; the support ofmr is infx2Rn:dist(x; @M)rg:

(11) Here we use thatMis anormalizedset of finite perimeter.

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(ii): If q is dominated on @M; there exists a sequence rj!0 and a g2L1(@M;Hn 1)such that (4.4) holds forHn 1 a.e.x2@M:IfDis the maximum ofj; then

jqr(x)nM(x)j Dg(x)

forHn 1a.e.x2@Mand everyrˆrj; j2N:The sequence of functions qrnM is thus Hn 1 equiintegrable on @M and hence [8; Corollary 11,

§ IV.8] there exists a subsequence of rj; still denoted r; and a q02 2L1(@M;Hn 1)such that

qrnM*q0 in L1(@M;Hn 1)

The limit in (7.5) ispMˆq0Hn 1j @M: p

PROOF OFTHEOREM4.2. (i): Follows from Lemma 7.2(i).

(ii): We only have to prove that the measurenM of (i) is supported on

@M: By Lemma 7.2(ii) we have pMˆq0Hn 1j @M: The measure sM satisfies

hsM;Wi ˆlim

r!0

…

@M

Wrdivq

whereWris given by (7.8). At everyx2@MwhereD(x;M)exists we have Wr(x)!D(x;M)W(x):By (4.5) and Theorem 3.2,jdivqj(@sM)ˆ0:Thus we have thatWr!D(;M)Wforjdivqjj @Ma.e.x2Rn:Hence

limr!0

…

@M

Wrdivq! …

@M

W(x)D(x;M)divq(x):

ThussMˆD(;M)divqj @Mand consequently

nMˆq0Hn 1j @M D(;M)divqj @M;

which is a measure supported on@M: p

8. Proof of Theorems 4.4 and 4.6.

Ifh2M‡(Rn)and 0m<1; themdimensional upper density ofhby um(x;h)ˆlim

r!0sup h(B)

amrm:Ban open ball of radiusrr; x2B

; x2Rn:

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