A Note on the Bifurcation of Solutions for an Elliptic Sublinear Problem.
ALESSIO PORRETTA(*)
1. Introduction.
We consider the following semilinear problem in a bounded domain V%RN:
. /
´
Lu1uu4lu uF0 , ug0 , u40
in V, in V, on ¯V, (1.1)
where 0EuE1 andLuis a linear differential operator defined asLu4 42div (A(x)˜u),A(x) being a symmetric, bounded and coercive matrix, that is such that
(1.2) aNjN2GA(x)jQjGbNjN2
for every jRN, a.e. xV, with a,bD0 . A necessary condition to find nonnegative nontrivial solutions of (1.1) is that lDl1, the first eigenvalue of the operator L on V with Dirichlet (*) Indirizzo dell’A.: Dipartimento di Matematica, Università di Roma «Tor Vergata», Via della Ricerca Scientifica, 00133, Roma, Italia.
boundary conditions. Notice that (1.1) is the Euler equation of the functional
(1.3) Jl(u)41 2
V
A(x)˜uQ˜u dx2l 2
V
(u1)2dx1 1 u11
V
NuNu11dx
uH01(V) , which, since 0EuE1 , is not bounded from below if lDl1.
As it was remarked in [8] (see also [6]), the existence of a solution of (1.1) for everylDl1 can be obtained applying the abstract fixed point results by Krasnoselskii ([9]). This approach relies on the definition of the inverse operator ofuOLu1 NuNu u
NuN
and makes use of its compact- ness properties and the computation of its derivative at zero and at infin- ity. Similarly, using the results of Rabinowitz in [11], in [6] it is proved the existence of a connected branch of solutions (l,ul) bifurcating from infinity atl4l1. The same kind of arguments is used in a more general context in [3] to deal also with sublinear eigenvalue problems, following the method developed in [1] (see also [10]).
As a consequence of the previous results, the bifurcation diagram for solutions of (1.1) reads as follows: there is bifurcation from infinity if and only ifl4l1while no finite value oflcan be a bifurcation point from the zero solution. The aim of this note is to prove that the bifurcation from the trivial solution actually occurs at l4 1Q.
More precisely, we prove that there exists a sequence ul, lDl1, of Mountain Pass type solutions of (1.1) such thatVulVH1
0(V)tends to zero as lgoes to infinity. In fact, we do not know whether any sequence of sol- utions of (1.1) will converge to zero as l tends to infinity, nevertheless the sublinear behavior of the absorption term both near the origin and at infinity yields a classical Mountain Pass type structure to the functional Jl which allows to construct such a sequence, obtaining the bifurcation from u40 at l4 1Q. This is the result that we prove.
THEOREM 1.1. Let 0EuE1 , and let (1.2) be satisfied. Then for everylDl1problem(1.1)admits a solution ulH01(V)which is a criti- cal point of Mountain Pass type of the functional Jl defined in (1.3).
Moreover this family of solutions ul satisfies
lim
lK 1Q
VulVH1 0(V)40 . (1.4)
The bifurcation from the trivial solution at infinity has already been proved for the semilinear problem
. /
´
Lu4lup uF0 , uc0 , u40
in V, in V, on ¯V, (1.5)
withpD1 . For a certain range of values ofpthis was obtained in [5] via a priori estimates while a general result (for every subcriticalpD1) was proved in [4] using the variational structure of the equation and esti- mates on the Mountain Pass level of the related functional. Our problem (1.1) is much different with respect to (1.5) since the nonlinearitylu2uu is asymptotically linear at infinity and the Mountain Pass character is due to a sublinear positive perturbation. This implies that the approach- es of these previous papers do not work, in particular the standard regu- larity (bootstrap) argument is not such helpful and the method used in [4] would only give here an estimate on theLu11(V) norm ofu. For this reason we use here a refined construction of the Mountain Pass solutions ul, which are obtained through a recurrence argument, allowing, at fixed l, to estimateJlon the paths [ 0 ,ul], wherelElandulis the Mountain Pass solution previously found.
Let us stress that, in dimension N41 , a full study of the equation (1.1) is carried out in the recent work [7]. In that paper the case of thep- laplace operator is also considered and the set of solutions of the prob- lem is fully characterized, giving multiplicity results as well. While our results can be proved without relevant changes for thep-laplace opera- tor as well, we cannot give here a full picture of the behavior of the sol- utions in dependence of l.
2. Proof of Theorem 1.1.
We denote byl1the first eigenvalue of the operator Lwith Dirichlet boundary conditions on ¯V, and by W1 the positive eigenfunction such that LW14l1W1, VW1VL2(V)41 .
PROOF OFTHEOREM 1.1. The proof of Theorem 1.1 is a consequence of the following two Propositions.
PROPOSITION 2.1. LetlDl1. Then problem(1.1) admits a solution ulwhich is a critical point of Mountain Pass type of the functional Jl
defined in (1.3). Moreover ul satisfies:
(2.1) Jl(ul)G
g
u11 1 2 12
h g
Vs
NwNu11dxh
12u2g
ls
V
w22
s
V
A(x)˜wQ˜w dx
h
1112uu,
for every w:l
s
V
w2dx2
s
V
A(x)˜wQ˜w dxD0 .
PROOF. We are going to use the classical theorem of Ambrosetti and Rabinowitz ([2]) with a little change in the choice of the paths.
We start by proving thatu40 is a local minimum for the functional Jl. Precisely, we claim that
)rD0 : Jl(u)D0 (uBr0]0( 4 ]VuVH1
0(V)Gr,uc0(, (2.2)
which will easily imply that
)s : Jl(u)Fs (u:VuVH1
0(V)4r. (2.3)
In order to prove (2.2) we argue by contradiction. If (2.2) were not true, it would exist a sequence un in H01(V) such that:
VunVH1
0(V)K0 , unc0 , Jl(un)G0 (nN,
that is 1 2
V
A(x)˜unQ˜undx1 1 u11
V
NunNu11dxG l 2
V
NunN2dx. (2.4)
Setting wn4Vuun
nVH1 0 (V)
, we have:
V
NwnNu11dxG l(u11 ) 2
VunV
H01(V)
12u
V
NwnN2. (2.5)
SinceVwnVH1
0(V)41 , we have that, up to subsequences,wnconverges to a function wH01(V) almost everywhere in V, hence we deduce by Fa- tou’s lemma and (2.5) thatw40 , so thatwnstrongly converges to zero in L2(V) as well by Rellich theorem. Dividing the equality in (2.4) by VunVH1
0(V)
2 , using the ellipticity of A(x) we conclude thatwntends to zero inH01(V), contradicting the fact that VwnVH1
0(V)41 . Thus (2.2) is proved.
Now, assume that (2.3) is violated. Then we deduce again the existence of
a sequence un such that VunVH1
0(V)4r and lim sup
nK Q
Jl(un)40 . Up to a subsequence we have that there exists a functionu in Br4]VuVH1
0(V)Gr( such thatun weakly converges to u in H01(V). By lower semicontinuity we get thatJl(u)G0 , so that (2.2) implies thatu40 . As a consequence, un tends to zero strongly in L2(V), hence from
a 2
V
N˜unN2dxG1 2
V
A(x)˜unQ˜undxGJl(un)1l 2
V
NunN2, we conclude, since lim sup
nK Q
Jl(un)40 , thatunstrongly converges to zero inH01(V), which is not possible sinceVunVH1
0(V)4rfor everyninN. Thus (2.3) is proved.
The proof that the functionalJlsatisfies the Palais-Smale condition is standard and the details are left to the reader. Let us just recall that the main tool is, as usual, the proof that a Palais-Smale sequenceunis bound- ed, in order to apply the compactness properties of the equation. To ob- tain the boundedness of the sequenceun, it is enough to argue by contra- diction, assuming that VunVH1
0(V) goes to infinity and reasoning on the normalized sequence un
VunVH1 0 (V)
, which can be proved to strongly converge to zero (actually, it will converge to a nonnegative eigenfunction corre- sponding to the eigenvector l, since lDl1 it must converge to zero).
We define now the class of paths to which apply the usual deforma- tion lemma. First, let
Cl»4
{
wH01(V) :lV
w22
V
A(x)˜wQ˜w dxD0
}
,which is clearly a nonempty subset of H01(V) since W1Cl for every lDl1. Note that for anywClwe have that there exists only one value twD0 such that Jl(tww)40 .
Then we define the set of paths:
Xl»4 ]gC( [ 0 , 1 ],H01(V) ) :)wCl: g( 0 )40 , g( 1 )4tww(. We can then prove that
c»4 inf
gXl sup
[ 0 , 1 ]
Jl(g(t) )
is a critical value forJl. Indeed, let r and s be given from (2.3). Since Jl(tww)40 it follows from (2.2) thatVtwwVH1
0(V)Dr, hence there exists a value t such that Vg(t)VH1
0(V)4r and thus cFs. Now, if the set Kc4 4 ]vH01(V) :Jl(v)4c,Jl8(v)40(were empty, it would exist a contin- uous deformation h: [ 0 , 1 ]3H01(V)KH01(V) and a value eD0 such that h(t,v)4v for any vH01(V) such that NJl(v)2cN Ds
2 and Jl(h( 1 , v) )Gc2efor everyvsuch thatJl(v)Gc1e. Ifgeis a path such that sup
[ 0 , 1 ]
Jl(ge(t) )Gc1e, we have that the pathh( 1 , ge(t) ) belongs to Xl and sup
[ 0 , 1 ]
Jl(h( 1 ,ge(t) ) )Gc2e, contradicting the definition of c. Therefore c is a critical value and there exists a critical point ul in Kc. Clearly, ul is a weak solution of (1.1). Moreover, note that the path g(t)4ttww belongs to Xl for any wCl, hence we get:
Jl(ul)4cGsup
[ 0 , 1 ]
Jl(ttww) . A straightforward calculation implies (2.1). r
PROPOSITION 2.2. Let ul be the solution of (1.1) found in Proposi- tion 2.1. Then we have:
lim
lK 1Q
VulVH1 0(V)40 . (2.6)
PROOF. We denote, in what follows, by C all possibly different con- stants which do not depend on l. First of all, since Jl8(ul)40 , we have
g
u11 1 21 2h
V
ulu11dx4Jl(ul)2 1
2aJl8(ul),ulb4Jl(ul) , so that using (2.1) we obtain the estimate:
(2.7)
V
ulu11dxG
g s
V NwNu11dx
h
122ug
ls
V
w22
s
V
A(x)˜wQ˜w dx
h
11u12u , fore every wCl. In particular, choosing w4W1 in (2.7) we getV
ulu11dxG C l
u11 12u
, (lDl1. (2.8)
Moreover, for every l8 El we have that
V
A(x)˜ul8Q˜ul8dx2l8
V
ul82dx4 2
V
ul8u11dx,
hence
V
A(x)˜ul8Q˜ul8dx2l
V
ul28dx4(l8 2l)
V
ul28dx2
V
ulu811dxE0 .
Thus ul8Cl for every l8 El, so that (2.7) implies:
V
ulu11dxG
g s
VNul8Nu11dx
h
12u2g
ls
V
ul8
22
s
V
A(x)˜ul8Q˜ul8dx
h
11u12u,
which yields, using the equation solved by ul8,
V
ulu11dxG
g s
V Nul8Nu11dx
h
12u2g
(l2l8)s
V
ul821
s
V Nul8Nu11dx
h
1112uu (l8 El.(2.9)
Our main task now is proving that the sequence ]ul( is bounded in H01(V). To this purpose, we argue by contradiction. Assume then that VulVH1
0(V)is not bounded. Then we can construct a subsequencelh, such that:
(2.10) lh2lh21F1 , VulhVH1
0(V)FVulh21VH1
0(V), lim
hKQ
VulhVH1
0(V)41Q.
From (2.9) written forulh andulh21 we obtain (note that lh2lh21F1):
V
uluh11dxG
g s
VNulh21Nu11dx
h
12u2g s
V
ul2h211
s
VNulh21Nu11dx
h
1112uu.
In order to simplify our notations, we denote henceforth ulh by ul and
ulh21 by ul21, so that we rewrite the previous inequality as
V
ulu11dxG
g s
VNul21Nu11dx
h
12u2g s
V
ul22 1
1
s
VNul21Nu11dx
h
1112uu. (2.11)
Let us set vl4Vu ul
lVH1 0 (V)
. Then we have:
VvlVH1
0(V)41 , Lvl1 vlu
VulVH1 0(V) 12u 4lvl. (2.12)
Moreover, using (2.11) and since VulVH1
0(V)FVul21VH1
0(V) we obtain:
V
vlu11dxG 1 VulV
H01(V) u11
g s
VNul21Nu11dx
h
12u2g s
V
ul212 1
s
V Nul21Nu11dx
h
111u2uG 1 Vul21VH1
0(V) u11
g s
V Nul21Nu11dx
h
12u2g s
V
ul2211
s
V Nul21Nu11dx
h
11u12uG
s
VNvl21Nu11dx
u
11s
Vs
ul212 dxVNul21Nu11dx
v
11u12u ,which yields:
V
vlu11dxG
s
VNvl21Nu11dx 11
u s Vs
ul221dx
V Nul21Nu11dx
v
11u12u .(2.13)
We claim now that there exists a constant eD0 such that:
lim inf
lK Q
s
V
ul2dx
s
VNulNu11dxFeD0 . (2.14)
Indeed, assume that (2.14) is not true: then we get that, for a subse- quence (not relabeled)
lK Qlim
s
V
ul2dx
s
V NulNu11dx 40 , so that, using (2.8),
V
vl2dx4 1 VulVH1
0(V)
2
V
ul2dxG C VulVH1
0(V)
2 lu1
1 12u
. But, using (2.10) (recall that here ul4ulh), this implies that
llimK Q
l
V
vl2dx40 , which yields, from the equation solved by vl (2.12):
llimK Q
V
N˜vlN2dx40 .
This can not hold because of (2.12), hence we deduce that (2.14) must be true. Now, (2.13) and (2.14) together imply that there existslDl1and a constant dD0 such that:
V
vlu11dxG 1 11d
V
vl2u111dx (lDl. Therefore, we also have that there exists a constant CD0:
V
vlu11dxGC
g
111 dh
l.(2.15)
Now, (2.12) implies, on account of standard regularity results (see [12]), that, for a value pDN2 :
VvlVLQ(V)GCVlvlVLp(V), which yields, thanks to (2.15) (take also pDu11):
1GCl
V
vlVvlVLQ(V)
V
Lp(V)GClV
vlVvlVLQ(V)
V
Lu11(V) u11p
GCl
g
111dh
lp VvlV1LQ(V) (u11)/p .
Then we have
VvlVLQ(V)GCl
p
u11
g
111dh
u1l1,so that VvlVLQ(V) converges to zero as l tends to infinity. Then l
V
vl2dxGCl
V
vlu11dxGCl
g
111 dh
l.Since (2.12) implies (recall (1.2)) a
V
N˜vlN2dxG
V
A(x)˜vlQ˜vldxGl
V
vl2dx,
we conclude thatvl strongly converges to zero inH01(V), which contra- dicts the fact thatVvlVH1
0(V)41 . The contradiction proves that no subse- quence ulh satisfying (2.10) can exist, and then that VulVH1
0(V) is bounded.
It is now easy to repeat the same arguments to prove that ul con- verges to zero in H01(V). Indeed, if this were not true it would exist a value eD0 and a subsequence ulh such that:
lh2lh21F1 , VulhVH1
0(V)Fe (hD0 . (2.16)
In this case (2.9) still implies that
V
ulu1h 1dxG
g s
VNulh21Nu11dx
h
122ug s
V
ulh
21
2 1
s
V Nulh
21Nu11dx
h
111u2u,
and then
V
uluh11dxG
s
V Nulh21Nu11dx 11
u s Vs
ul2h21dx
VNulh
21Nu11dx
v
11u12u .(2.17)
This is the same inequality as (2.13) previously obtained onvl. Thus, the same arguments can now be applied; indeed, we have the alternative
that either there exists a constant e such that
lim inf
hK Q
s
V
ul2hdx
s
V NulhNu11dx FeD0 (hD0 ,
or there exists a further subsequence (not relabeled) such that
lim
hK Q
s
V
ul2h
s
V NulhNu11dx40 .
In both cases, the same arguments used before for vlallow to conclude that a subsequence of ulh strongly converges to zero in H01(V), which contradicts (2.16). This concludes the proof thatulstrongly converges to zero in H01(V) r
REMARK 2.3. Note that, at least if N22
N12EuE1 , we can also argue from the proof of Theorem 1.1 that
llimK Q
VulVLQ(V)40 . In fact, recall that we have the estimate:
V
ulu11dxG C l
u11 12u
(lDl1.
If N22
N12Eu, then u11
12uDN
2, hence we get from the equation solved byul, VulVLQ(V)GClVulV
L u11 12u(V). Hence, using that u11
12uDu11 ,
1GCl
V
ulVulVLQ(V)
V
L u11
12u(V)GCl
V
ulVulVLQ(V)
V
Lu11(V) 12u
GC 1 VulVL12uQ(V) . We first deduce from this inequality thatVulVLQ(V) is bounded, then we obtain, for a value p such that max
m
u11 , N2n
EpEu121u1:lim
lK Qlp
V
ulpdxGClp
V
ulu11dxGC 1 l
u11 12u2p
,
so thatlul strongly converges to zero in Lp(V) with pDN2 . Classical regularity results (see [12]) then imply that ul converges to zero in LQ(V). In particular, this proves the convergence of ul in LQ(V) for any value of u at least in dimension NG2 .
Aknowledgments. This work originated from a discussion I had with Lucio Boccardo in Trieste at the International School held at the ICTP in April 1996, so I am grateful to the organizer A. Ambrosetti for the pos- sibility to attend that meeting. I also thank J. Hernandez who addressed to me references [8] and [7], and B. Pellacci and E. Montefusco for stim- ulating my interest about this problem with friendly discussions.
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