C OMPOSITIO M ATHEMATICA
A. J OSEPH
Towards the Jantzen conjecture
Compositio Mathematica, tome 40, n
o1 (1980), p. 35-67
<http://www.numdam.org/item?id=CM_1980__40_1_35_0>
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35
TOWARDS THE JANTZEN CONJECTURE*
A.
Joseph**
© 1980 Sijthoff & Noordhoff International Publishers - Alphen aan den Rijn
Printed in the Netherlands
Abstract
Let g
be acomplex semisimple
Liealgebra, U(g)
itsenveloping algebra,
PrimU(g)
the set ofprimitive
ideals ofU(g)
and b a Cartansubalgebra
for g.For g simple
of type An-l(Cartan notation),
Jantzen[3],
5.9conjectured
that thecardinality
of each PrimU(g)
fibreprojecting
onto a fixedregular integral
central character and onto afixed
nilpotent
orbit ing*
isjust
the dimension of theappropriate
irreducible
representation
of thesymmetric
group Sn. Here it issuggested
that theappropriate
formulation of thisconjecture
forgeneral g
involves the dimensions of certainsubspaces
ofpolynomials
on
fj*
which determine the dimensions of the irreducible finite dimensionalrepresentations
ofparabolic subalgebras
of g. Its reduc- tion to the Jantzenconjecture
for type An-i isessentially
a com-binatorial result of Garnir
[14].
Thenthrough
a carefulstudy
ofad A
finite
homomorphisms
of induced modules(which gives
some resultsof
independent interest)
the Jantzenconjecture
is reduced to twoopen
questions.
The first involves theprincipal
series and wouldgive
a lower bound
(involving
the dimensions of the above-mentionedsubspaces)
on thecardinality
of eachregular integral
fibre. In caseAn-i this is
just
the number of involutions inSn
and coincides with Duflo’s upper bound[13],
II.2. The second is aproblem
of Borho[1],
3.3 which whenever the last part of
[21],
4.3 holds(for example
in type An-1[25], 4.1)
fixes the associatednilpotent
orbit.* Work supported by the C.N.R.S.
** Present address: Department of Mathematics, Tel-Aviv University, Ramat Aviv, Israel.
0010-437X/80/01/0035-34 $00.20/0
1. Introduction
Unless otherwise
specified
all vector spaces are assumed over thecomplex
field C.1.1 For each vector space V, let
S( V)
denote thesymmetric algebra
over V and V* the dual of V. For each Liealgebra
a, letU(a)
denote its
enveloping algebra
andZ(a)
the centre ofU(a).
For each associativealgebra
A letjl(A) (resp. Spec
A, PrimA)
denote the set of two-sided(resp. prime, primitive)
ideals of A and A A the set ofclasses of irreducible
representations
of A, with a similar convention for a group. ForU (a) A
wesimply
write a". Aring
is said to beNoetherian if it is left and
right
Noetherian.1.2
Let g
be acomplex semisimple
Liealgebra.
Theprincipal
aimof this paper is the classification of Prim
U(g).
Take I E PrimU(g).
Then the map 11’: I-I n
Z(g)
is asurjection
of PrimU(g)
ontoMax Z(g)
with fibres of finitecardinality
[10], 8.5.7(b), [13],
II, Thm.1. Give
U(g)
the canonical filtration[10],
2.3.1 andidentify gr(U(g))
withS(g). Identify g* with g through
theKilling
form and call X Eg*
nilpotent
if ad X isnilpotent.
As noted in[6],
Sect. 7, the zerovariety
’(gr I)
of gr I is contained in the cone .N’ ofnilpotent
elements ofg*
which under the
adjoint
group G is a finite union of orbits.Suppose
further that the radical
’B/gr
I of gr I isalways
aprime
ideal. Thensince G is
algebraic,
there is aunique nilpotent
orbit 0 cg*
whoseZariski closure
6
coincides with’V(gr I)
and hence a map K of PrimU(g)
into.N’/G (c.f. [3], 2.9).
Thisgives
rise to thefollowing problem.
For eachÂ
E MaxZ(g),
(J E.N’/G
determinecard{1T-I(Â)
rlJ{-I«(J)}. For g simple
of type An-i: n =2, 3,..., (Cartan notation)
andfor
regular integral A,
J.C. Jantzenconjectured [3],
5.9 that these numbers arejust
theappropriate
dimensions of the irreduciblerepresentations
of thesymmetric
groupSn. (Recall
thatSn
is innatural
bijection
with.N’/G.
Thenon-regular
case is handledby [5],
2.12 and it is
generally supposed (c.f. [21],
Sect.4)
that the non-integral
case mirrors theintegral case.)
1.3 In
attempting
to prove Jantzen’selegant
yetmysterious
con-jecture,
it isclearly important
to find areinterpretation
whichapplies
to any
semisimple
Liealgebra.
Nowalthough
mostprimitive
ideals in type An-, are not induced ones,they
all take the form(c.f.
9.3 and[5],
4.5
d))
of a minimalprime
idealcontaining
an induced one. This leadsus to suggest
(see 8.2)
that for Cpolarizable [10],
1. 12.8,
orequivalently
for anyRichardson
orbit 6(see 8.2),
thecardinality
of7r’*(À)
nJ{-I«(J)
is the dimension of the spacegenerated by
thepolynomials
on$*
which determine allpossible
dimensions of finitedimensional irreducible
representations
of anappropriate
subset ofparabolic subalgebras.
Thenthrough
a carefulstudy
oflocally ad g
finite
homomorphisms
of induced modules(Sects. 4-7)
and[21-25],
we are able to reduce the Jantzen
conjecture
to thefollowing
twoopen
questions,
9.1 and 10.2. First to show that for each induced ideal J one hasVgrJ
ESpec S(g) -
aproblem suggested by
Borho[1],
3.3.Second to show that the
simple subquotients
of thespherical principal
series of different
multiplicity (or just
of non-commensurable multi-plicity, 10.5)
in the sense of the Hilbert-Samuelpolynomial,
neces-sarily
admit different annihilators. Our moregeneral conjecture
for anarbitrary semisimple
Liealgebra
furtherrequires
the solution ofcertain combinatorial
questions involving
theWeyl
group and the root system. In type An-h these are resolvedthrough
results ofSpecht [33],
Garnir[14],
Schensted[31]
and Knuth[27].
1 should like to thank M.
Duflo,
G.Cauchon,
A. Lascoux and N.Spaltenstein
for useful conversationsconcerning
this work.2. The Hilbert-Samuel
polynomial
To set notation we recall some standard results
concerning
theHilbert-Samuel
polynomial.
2.1 Let A be an associative
algebra
which we shallalways
assumefinitely generated
and with anidentity.
Given T, T’subspaces
of A weset TT’ = lin
span{tt’: t
ET, t’ E T’l
and foreach k E N,
we defineTk inductively through To
= C,Tk
=T k- ’T
and set T-I = 0. Now suppose that T is a finite dimensionalgenerating subspace
of Acontaining
theidentity.
Then thesubspaces T-1 C TO C TI C ...,
define a filtrationfor A. For
each k E N,
set Tk =Tk/Tk-I
and letdenote the associated
graded algebra
which we shallalways
assume commutative. If M is afinitely generated
left Amodule,
fix a finite dimensionalgenerating subspace M°
and foreach k E N,
setMk-1 = T k-lMO@
Mk =MkIMk-1 .
Thenis a
graded
module for gr Asatisfying
thehypotheses
of[32], Chap.
II, Thm. 3.
Through
its conclusion there exists apolynomial qT(M) (the
Hilbert-Samuelpolynomial)
such thatqT(M)(k) =yk =0
dim M, = dimMk,
for all ksufficiently large.
We setd(M)
=deg qT(M)
and leteT(M)/d(M) !
denote the coefhcient ofkd(M)
inqT(M).
We recall thatd(M) + 1, eT(M)
arepositive integers
which do notdepend
on thechoice of
generating subspace Mo
andd(M) (denoted by
dim M in[25])
does notdepend
on the choice ofgenerating subspace
T(whereas eT(M) does).
We defined(A) (which
coincides with Dim A defined in[6])
andeT(A) through
A considered as a left A module.When A =
U(a),
for some finite dimensional Liealgebra
a, we shallalways
take T to be theimage
of the canonicalembedding
of aQ
C inU(a) (which
defines the canonical filtration{U(a)k: k = 0, 1, ...},
ofU(a))
and wesimply
writee(M)
foreT(M).
Weidentify gr( U(a))
withS(a).
2.2 Recall the well-known
[32], Chap.
II,Prop
10LEMMA: Let
0 --> MI ---> M --- >M2--*0,
be an exact sequenceof finitely generated
A modules. Then oneof
thefollowing
hold(i) d (Mi) d (M )
andd (M2)
=d(M), eT (M2)
=eT (M ) . (ii) d(MI) = d (M) = d (M2)
andeT (M) = eT(MI)
+eT (M2).
(iii) d (M2) d (M)
andd (Ml)
=d(M), eT(MI)
=eT(M).
2.3 Let a be a finite dimensional Lie
algebra, A
=U(a)
and V a left andright U(a)
module(which
we can consider as a leftU(a) Q U(a) module).
Set LAnn V =f a
E A: a V =01,
RAnn V =la
E A : Va =01.
We shall say that V is ad a finite if for each X E a, the
endomorphism
ad X : v - Xv - vX of V is
locally
finite.Suppose
V is ad a finite andfinitely generated
as aU(a) Q U(a)
module. Then we can choose afinite dimensional
subspace V°
of V which generates V as aU(a) 0 U(a)
module and satisfies(ad X) V° C V°,
for all X E a. LetT denote the
image
ofa@C
inU(a).
Then for all k EN, one hasTkVO
=Tk-I VOT
=Tk-2VOT2
=... =VOTk,
and inparticular
thatIt follows that V is
finitely generated
as a left and as aright U(a)
module and the Hilbert-Samuelpolynomials
for these three actions coincide. We used(V), e(V)
to denote the common invariants.1
An
elementary computation gives
LEMMA:
Suppose
V isfinitely generated
as aleft
and aright U(a)
module and Ann V = LAnn
Vo U(a) + U(a) @ RAnn
V. Then(i) d(U(a)@ U(a)/Ann V)
=d( U(a)/LAnn V) + d( U(a)/RAnn V), (ii) e(U(a) U(a)/Ann V)
=e( U(a)/LAnn V)e( U(a)/RAnn V).
2.4 The
f ollowing generalizes [25],
3.1.PROPOSITION:
Let g be
asemisimple
Liealgebra
and V an ad gfinite U(g) 0 U(g)
moduleof finite length.
Then(i) d( U(#)lLAnn V)
=d( U(#)lRAnn V)
=d(V).
(ii) If -v/gr(LAnn V)
andVgr(RAnn V)
are bothprime ideals,
thenthey
coincide.(Recall
thatU(g)
isgiven
the canonicalfiltration).
By
2.3,[13], Prop.
7 and[23], 3.2,
3.6, we haveThis
gives (i).
For(ii)
observe thatgr(LAnn V)
C Ann gr V(with
gr Vprescribed by
2.1 and2.3)
and soby (i), d(V) = d ( U(g)/LAnn V) = d(S(g)/gr(LAnn V)) > d (S(g)/Ann
grV) > d(gr V) = d(V).
GivenVgr(LAnn V) prime,
one obtainsVgr(LAnn V) = VAnn
grV
andhence
(ii).
3. Induced modules
3.1
Let g
be asemisimple
Liealgebra, $
a Cartansubalgebra
for g, R C$*
the set of non-zero roots, R+ C R a system ofpositive
roots,B C R+ a Z basis for
R, sa
the reflectioncorresponding
to the root a,W the group
generated by
the sa : a ER, P(R)
the lattice ofintegral weights.
Fix aChevalley
basisfor g
and letXa
denote the element in this basis ofweight a
E R. Let n(resp. n-)
denote thesubalgebra of A spanned by
theXa :
a E R+(resp. a
ER-)
and set b : = nQ fj.
For eachsubset B’ C B, set R’= ZB’
f1 R,
R’+ = R, flR’,
WB, thesubgroup
ofW
generated by
the sa : aE R’, wB,
theunique
element of WB,taking
B’ to -B’,
P(R’)++ = {A
E$*: 2(À, a )/(a, a)
EN+,
for all a EB’), B" = IA e *: (,k, a) = 0,
for alla E: B’l.
Let pB, D b(or simply, p)
denote the
subalgebra of g
with reductivepart b (D (@ CXa :
aER’},
mB,
(or simply, m)
the nilradical of pp and a-B,(resp.
p if B’ =B )
the half sum of the roots in R’+. Given À EP(R’)",
letVB,(À)
denote thesimple
finite dimensional pa module withhighest weight À -
p and in the notation of[10],
5.1 setMB,(A)
=ind(VB’(À),
pB,t #), IB,(A) =
Ann
MB{A).
We remark that dimVB{A)
= dim VB{A +v),
for all v E B". When B’ is the empty set,MB{A)
coincides with the Verma moduleM(A)
forg, b, B, p
as defined in[10],
7.1.14. We letL(A)
denote theunique simple quotient
ofM(,k)
and setI(,k)
= AnnL(A).
If
MB,(A)
is defined it is aquotient
ofM(A)
and soI(A)
DIB{A).
Let u H ‘u
(resp. M’->M)
denote theinvolutory antiautomorphism
ofU(g)
definedthrough ‘Xa
= X-a: a E R, tH = H, for all HE t (resp.
X = -X,
for all X Eg).
Set mB’ =tmB’ (or simply, m-).
LEMMA: For each B’ C B, A E
P (R’)++, (i) d(MB{Á» =
dim mB’.(ii) e(MB,(,k»
= dimVB{A).
Take
M = MB{Á), M°= VB,(A)
in 2.1. Then M identifies withU(g)@u(p)Mo= U(m-)@Mo
and for allkEN,
we haveMk
=U(m-)k@Mo,
whichgives
therequired
assertions.3.2
Identify
U : =U(g) 0 U(g) canonically
withU (g (f) g),
setj(X) =
(X,-X),
for all X E g and k : =j(g).
Given A, IL Efj*,
M(resp.
N)
asubquotient
of M(A)(resp. M(li»,
defineHomc(M,
N) as a U modulethrough «aob),x)m=’âx6m,
for alla, b E U(g),
x EHomc(M,N), meM.
LetL(M, N)
denote thesubspace
ofHomc(M, N)
of all t finite elements(which
is a U submodule andad A
finite in the sense of
2.3).
Given A, IL EP(R’)++,
thenL(MB,( ), MB,(I£»
is non-trivial iff k - 1£ EP(R), [9],
5.8.3.3 Call A
e $*
dominant if2(A, a)/(a, a) e
N-, for all a E R+ andregular
if(A, a) 0
0, for all a E R. For each À E$*,
setW(A) = {w
E W : wk= A ),
R, =f a
E R :2(A, a)/(a, a )
EZ), R1
= R+ flRA, WA
the
subgroup
of Wgenerated by the sa :
a e RAand WA
theunique
element of WA
taking R1
to-R1.
GivenA, IL
Efj*
such that À - 1£ EP(R),
thenWA
=WJL
and we say that Aand 1£ belong
to the samefacette
of$*
ifW(A) = W(IL)
and there existsw E WA
such that wA and WIL are both dominant. GivenA, IL E P(R’)++
consider(MB{-A)@MB{-IL»*
as a U modulethrough transposition
and letLB{A, IL)
dénote thesubspace
of ail r-finite éléments(which
is anad g
finite U module and non-trivial iff
A - IL
EP(R)).
If B’ is the emptyset we
simply
writeL(A, li). If li
isdominant,
then[12],
Thm.4.2, L(A, IL)
admits aunique simple quotient V(,k,.u)
and we setV(A, WIL)
=V(w -’,k, IL),
for all wE WJL (c.f. [12],
Thm.4.1).
LEMMA: For all.
are
simple U(g)
modules, then(i)
is clear (seeproof
of[13],
Prop.9). (ii)
follows from(i)
and[9],
5.5.
REMARK: We shall
eventually
see(c.f.
6.2(iii))
that(ii) holds
without restriction on
simplicity.
3.4 Given À E
fj*, let À
denote its orbit under W, which may be identified with the elementI(A)f1Z(#)
ofMax Z(g).
SetBei = (I(> ):
..t EÂ).
Thenaei
C7T-l(À) (notation
1.2) and indeed[13],
Thm. 1equality
holds. Given k EP(R)
we may furtheridentify À
with anelement of t"
(by taking
theunique simple
t module with extremeweight A)
andthen t" = P(R)IW.
LetP (R )+
denote the dominantelements of
P(R).
Wegive P(R)+ (which
we sometimesidentify
withN": r = rank
g)
thetopology
inducedby
the Zariskitopology
on$*.
4. The
primeness
of thering L(MB,(A), MB,(A»
Retain the notation of Section 3. We start with some standard
reasoning.
4.1 A t-finite U module M is said to admit a f ormal character
(with
respect tot)
if eachisotypical
componentMv: v
E t" has finite multi-plicity,
which we denoteby [M : û].
LEMMA:
Suppose
M # 0 admits af ormal
character. Then M admits at least onesimple subquotient.
Choose û E t" such that
Me 0
0. Let N’ be a submodule of M for which Ni has minimal non-zeromultiplicity
and set N =UN . By
construction every proper submodule of N has noisotypical
component oftype v.
Hence the sumN
of all proper submodules of N is a proper submodule of N and soN/N
is therequired simple subquotient.
4.2 A U module L is said to admit a central character if there exists ll E
Max(Z(g) @ Z(g»
such that z -A (z) -
1 isnilpotent
forevery z E
Z(g) @ Z(g).
LEMMA: Let L be a t
finite
U module.If
L admits both af ormal
and acentral
character,
then L hasfinite length.
Let
(À, iî):
k, IL Eb*
define the central character of L(c.f. 3.4). By [12],
Thm.4.5,
thesimple subquotients
of L form a subset of( V(A ’, > ’): A ’ e Â, > ’ e il ).
Recall[12],
3.4 thatV(À’,li’)
has a non-zero
isotypical
component of type(A’- li)^
and this can have at most(card W)2
values. Now if L has infinitelength,
thenby
4.1 it admitsinfinitely
manysimple subquotients
which therefore cannot allbelong
to the above set. This contradiction proves the lemma.
REMARK:
Obviously
L haslength --5(card W)2 _ maxf[M: (,k’- JI’) A]: A’ E Â, ’ E 1}.
4.3 PROPOSITION: For
allk, ii
Eb*
and everysubquotient
M(resp.
N) of M(,k) (resp. M(>))
one has(i) L(M, N)
hasfinite length
as a U module. Inparticular
it isfinitely generated
as aleft
or aright U(g)
module(cf. 2.2).
(ii) L(M, M) is
a Noetherianring.
It is clear that
(- Â, - ¡1)
defines the central character ofL(M, N).
Identify t
with g. Given F a finitedimensional g
module considerM@F
as a g modulethrough X(m@f)=Xm@f+m@Xf:XEg,
m E
M, f
E F. We haveHomg(F, L(M, N))
=Homg(M@
F,N)
up toisomorphism (c.f. [8], 6.2).
NowM@ F
has a formal character with respectto b
and sotaking
account of thepossible simple subquotients
of N(c.f. [10],
7.1.7,7.4.7, 7.6.1)
it follows thatL(M, N)
admits a formal character. Hence(i)
obtains from 4.2 and(ii)
fromthe fact that
U(g)
is Noetherian.REMARK:
B y [5],
3.6 there isinteger n(g) depending only
on g which is an upper bound to thelength
of any Verma module for g.By [20],
2.2 we then have dim
Homg(MD F, N) S n (g)
dim F.4.4 In the remainder of Sect.
4,
we fix B’ C B and A EP(R’)++.
Forall
v e B ",
theidentity
map onU(rtt-) (notation 3.1)
induces aj(m)
invariant linear
isomorphism OÂ-’ (or simply, 0,)
ofMB,(A)
ontoMB{A - v). Suppose
further that v EP(R)+.
Thenby [9],
8.4 we haveOA-’EE L(MB,(A), MB,(A - v))
and we let0’-’ (or simply, 0,)
denote theunique simple t
module it generates. It is clear that for all,k, li
EP(R’)++,
0 # a EL(MB,(Ii), MB,(A ))
one has 0»a # 0.4.5 The action of
U(g)
inMB{A)
defines anembedding
ofU(g)/IB{A)
inL(MB,(A), MB,(,k»
which may be strict[9],
6.5(see
also10.5)
even ifMB,(A)
is asimple
module.Conversely equality
can hold[8],
6.10 even ifMB,(,A)
is notsimple.
In fact sinceL(MB,(A), MB,(A»
isgenerated by
its ad rn- invariantelements,
it follows thatequality
holds whenever tn- is commutative and dim
VB,(A)
= 1. SetP(R’)" -
(A E P(R’)++: -wB,A
isdominant} = (A
EP (R’)++: 2(A, a )/(a, a ) §É N+,
for all a E
R+"R’+}.
For all À EP(R’)++,
thereclearly
exists v E B’.ln P(R)+
such that k - v EP (R’)’.
Theimportance
of this setderives from the
following
result of Conze-Berline and Duflo[9],
2.12,4.7, 6.3.
THEOREM: For all B’ C
B,
and all À EP(R’)V, (i) MB,(Á) is
asimple U(g)
module.(ii) U(g)/IB’(Á) = L(MB’(À ), MB,(Á».
REMARK:
(i)
is aspecial
case of a result of Jantzen[18].
4.6 A result of
Lepowsky [29],
Thm. 1.1, states thatMa (À)
admits aunique simple
submodule if dimVB,(A)
= 1. Thispresumably
fails ingeneral.
Yet it does have thefollowing important
variation:PROPOSITION: Consider
MB,(À)
as aL(MB,(Á), MB,(A))
module.Then
MB,(À)
admits aunique simple
submodule.Choose v E B’.l fl
P(R)+
such that À - v EP(R’) v
and setL : =
L(MB{Á - v), MB,(Á»6J1
which(c.f. 3.2, 4.4)
is a non-zero left ideal ofL(MB,(Á), MB,(A»).
Now for all O;;é mE MB{Á),
we have0 0 6J1m
E: MB,(,k - v )
and soU(g)O,m
=Ma (À - v), by
4.5(i).
It fol-lows that N : = Lm =
L(Mp(À - v), MB,(À»MB,(À - v),
is a non-zeroL(MB,(Á), MB«À))
submodule ofMa (À)
which isindependent
of thechoice of m.
Consequently
for any non-zerosimple L(MB(À), MB,(Á»
submodule No of
MB{Á),
we must have No::> LNo = N and so N satisfies the conclusion of theproposition.
4.7 We denote the submodule in the conclusion of 4.6
by NB,(A).
Consider
NB«À)
as aU(g)
module(the
lattergiven
the canonicalfiltration).
LEMMA:
(i) d(NB’(Á»
= dim mB’,(ii) e(NB«À ))
= dimVB«À ), (iii) d(MB,(Á)/NB{Á»
dim ma.Choose
v (=- B,l n P (R)’
suchthat Á - v E P(R’) V.
Set A =U(g)/IB’(Á - v),
B =L(MB’(À), MB,(À - V)),
C =L(MB’(À - v), MB,(Á»,
V =
Va (À - v),
M= MB’(À - v),
D = End M.By 4.4,
wehave 0»
E B.By
4.5(ii),
A =L(M, M)
and so0»C
is aright
ideal of A. Further-more
by [26], 4.2,
A m- is aprime
Goldiering
whichby [24],
5.8 is aquotient
ofU(8)’-
and is hence[42] finitely generated.
Recall[9],
8.4 that 0, is aj(n)
invariantweight
vector ofj(b) weight
v.Consider
A m- / 0,C’-
as afinitely generated right
A’" module.By [39],
2.3(which trivially generalizes
to Goldierings)
it isenough
toshow that
d(A m- / lJvCm-) d(A m-).
This followseasily
from thedimensionality
estimates(i)
and(ii) given
below. First for each IL EP(R)-,
letA-- (resp. B:-, C:-)
denote thesubspace
of A’-(resp.
Bm-, C’-) of j(b) weight
vectors ofweight 1£
andidentify
M withU(rn-) Q
V. Then A"’ is aj($)
submodule of D’- which is in turnisomorphic
toU(m-) @ End
V(c.f.
5.8). Thisgives dim A:- 00.
Since AO, C B and aO, = 0 : a E A
implies a
=0,
we obtainSet
JI* = -WBII. Recalling
that M is asimple
module it follows from [9],5.5,
5.8 that dimC:-
dimB*.
Yet Olle = 0: c E Cimplies
c = 0and so
By [26],
4.2 eachregular
element s E Am isregular
in Dm . Thelatter identifies with
U(m-)@End
V in which the elements ofU(m-)
act
by right multiplication
in M =U(m-) @
V. Thus for each m E Mwe can choose a E D"’- such that a V = Cm. If sm = 0, then sa V = 0 and so saM = 0.
Consequently
sa = 0, whichby
theregularity
of simplies
a = 0 and hence m = 0.By (*)
we can choose c E Cm such that s : = Bvc isregular
in A m-.We have shown that cm ¥- 0 for all 0 0 m E M and so
dim(U(m-)kc(1 0 V»
=dim(U(m-)k@ V),
@ for all k E N . Since cM C CM CNB{À)
it followsby
3.1 thatd(NB (À)) > d(Mp (À - v))
= dim MB’and
equality implies e (NB«A )) *
dimVB,(A - v)
= dimVB«A ).
Yet theopposite inequalities
obtain from 3.1 and the fact thatNB,(,k)
is a submodule ofMB{À).
Thisgives (i)
and(ii),
which combined with 2.2(i) imply (iii).
4.8 THEOREM: For all
B’CB, À
EP (R’)++, (i) NB{À) is a faithful L(MB«A), MB,(A))
module.(ii) L(MB,(À), MB,(,k» is a prime,
Noetherianring.
by
4.3(i),
A has finitelength
as a U module and soby
2.4(i)
we musthave
d(U(g)/R) = d(U(g)/L).
This contradictiongives (i).
Combinedwith 4.3
(ii)
and 4.6 thisgives (ii).
5. Localization
5.1 Let A be a
prime,
Noetherianring
and S the set ofregular
elements of A
(so
then Fract A =S-’A).
Given M a left Amodule,
set
S-’M :
=S-IA@AM (or simply, Fract M).
We shall say that M is divisable(by S)
if the map m -10
m of M intoS-’M
isinjective (equivalently,
if foreach s E S,
0#m E M one has sm 00).
Obviously
any submodule of a divisable module is divisable. Inparticular
any left ideal of A is divisable as a left A module.Suppose
in addition that A and M are
finitely generated.
Thend(M):5 d(A), by [25],
2.1.Suppose
further that M is divisable. Then we have theLEMMA:
d (M)
=d (A).
Suppose d(M) d(A).
Choose 0 # m G M and setN = Am,
L =Ann m. Then for every left ideal K of A we have
d (K/(K
nL) d (A/L)
=d (N) d (M) d (A).
Henceby [39],
2.3 if K 00,
then K flL 0 0 and so
([15],
Lemma7.2.5) L n S 0 0.
This contradicts thedivisability
of M.5.2 Retain the notation and
hypotheses
of 5.1 and suppose in addition thatd(A) 00.
Let rk M denote the maximum number of direct summands of non-zero left A submodules of M. Recall that M is assumedfinitely generated
and soS-1M
isfinitely generated
as aleft
S-’A
module.By ([15],
Lemma4.3.2,
Thms.2.1.6, 7.2.1)
we can writeS-1M
as a direct sum of k:=rkMsimple S-’A
modulesQ1, Q2, ..., Qk
eachisomorphic
to a fixed minimal left ideal L ofS-’A.
Let N be any A submodule of M.(ii) e(M)
=e(L
fl A) - rk M. Inparticular
rk M dividese(M).
(i)
LetMo
be a finite dimensionalgenerating subspace
for M.By
the
hypothesis
of(i)
there exists s E S such thatsM° C
N. Thend (MIN ) S d(AIAs) d (A)
=d(M).
(ii)
Set Pi = A rlQ; :
i =1, 2,...,
k. We haveS -’Pi
=Qi
andd (Pi)
=d(M) by
5.1. Let N be the direct sum of the Pi(which
may be considered as a submodule ofM).
We haveS-’N
= M and soby (i)
and 2.2
(iii)
thate(M)
=e(N).
Hence it isenough
to show thate(P;)
=e(L
flA),
for all i. Set P = Pi. LetpO
be a finite dimensionalgenerating subspace
for P and cp theS-’A
moduleisomorphism
ofS-Ip
onto L. Choose s E S such thatscp(pf)
C A. Then P’ : =ASP°
isan A submodule of P and
S-Ip’ = S-’P by
the left Ore condition onA. Hence
d(P/P’)d(P) by (i). Again ço(P’) = As ço(PO) C L n A;
S-I(cp(p’» = çP(S-’P’)
= L and sod«L
nA)/cp(P’» d(L
flA) by (i).
Hence
e(P)
=e(P ’)
=e(L
f1A),
asrequired.
5.3
(Notation,
Sects. 3,4).
Fix ÀiE P (R’)++
such thatÀi - Àj
EP(R): i, j = 1,2,3.
Choose
v EE Bl n P(R)’
such thatA2 - V e P(R’)’
and a finite dimensional t submodule F ofL(MB,(À2 - v), MB,(Ai))
such thatL(MB,(À 1), MB’(lk2»F 0
0. Theni9,L(MB, (À 1), MB,(À2»
F is a non-zero two-sided ideal of theprime
Noetherianring U(A)IIB’(À2 - v). By
2.2,[1], 2.4, [25],
2.1 and[6],
3.6, we have 2 dim ma =d ( U(g)/IB-(A2 - V» = d(O,,L(MB,(,ki), MB,(À2» F) - d(L(MB.(Àt), MB,(,k2»)
where the last step obtains from the fact that8."
F are finite dimensional and t stable.By
4.3
(i),
and[25], 2.1,
2.8 we obtain theopposite inequality.
(i) By 5.3,
there exists b EL(MB,(À2), MB,(Ai))
such that 0 # ba EL(MB,(,k 1), MB,(À 1»
and so(i)
follows from 4.8(i). (ii)
follows from(i)
and4.6.
5.6- COROLLARY: For all 0 0 a E
L(MB,(À2), MB,(À3»
one hasaL(MB’(ÀI), MB{À2» ¥-
0.By 5.5, aL(MB,(À,), MB’(À2))MB’(Ài) D aNB{À2) ¥-
0.5.7 In the remainder of Sect. 5 we fix
k, j£
EP (R’)++:
À - p EP (R).
LEMMA:
Choose vEB,.1np(R)+
such thatMB’(À-v) is a simple U(g)
module. Then L : =L(MB«À - v), MB’(À»8v
contains aregular
element
of L(MB«À ), MB«À )).
Taking
4.8(ii)
into account this followsexactly
as in theproof
of[9],
8.5.5.8 For all
a E U(m-),
xe Hom(VB«p), VB,(À»,
definera @ x
E(Hom(MB,(.L), MB,(À»y(m) through (ra @ x)(b @ e) = ba @ xe,
for allb E
U(m-),
e EVB«p ).
It is clear that the mapa @ x - ra @ x
extendslinearly
to anisomorphism
ofU (m-) (D Hom(VB,(it), VB,(À»
onto(Hom(MB,(p,), MB,(À»)i(m),
and weidentify Hom(VB,(p,), VB,(À»
withthe
image
of1 @ Hom(VB«p), VB«À))
under this map.5.9 THEOREM: For all À, p E
P (R’)++:
À - .L EP (R ), L(MB«p ), MB«À))
andL(MB«À), MB«À))Hom(VB«>), VB«À))
arefinitely generated
divisableleft L(MB«À), MB,(À»
modules and considered assubmodules
of Hom(MB,(p,), MB,(À» satisfy
Take 0 # a E L.
By 5.6,
there exists b E L’ such that 0 # ab E A andso if s E A is
regular,
we have sa 0 0. Hence L is divisable.By
an argument whichexactly parallels [9], 5.10,
it follows that for each finite dimensionalsubspace T C K,
there exists v e B’l. nP(R)+
suchthat
T0»
CL(MB,(À
+v), MB«À)).
This and 5.6 establishes the divis-ability
of AK. Choose a E K.By
4.5 and[9], 5.10,
there existsv E B’l. n P(R)+
such that evaeL(MB,(À), MB,(À -v))
and thatMa (À - v)
is asimple U(g)
module.By 5.7,
we can choose b eL(MB«À - v), MB,(A))
such that s : = b0v isregular
and we havesa E L. Thus Fract AK C Fract L. In
particular, taking g
= A, we have(Hom(MB{A), MB{A»)j(m) C Fract A.
Thusby
5.8 we obtainFract AK =
Fract(A Hom( VB«> ), VB«À ))).
It is clear that each X E tn- is
locally ad-nilpotent
in A and for each 0 0 a EU(m-),
we have am = 0: m EMa (À), implies m
= 0. SetZ : =
U(m-)n-" {O} C Z(m-). Through
the argument of[7], 2.4,
eachz E Z is
locally ad-nilpotent
inA ;
has trivialright
annihilator and so isregular (either by
4.8(ii)
and[15], 7.2.3,
orby ad-nilpotence).
Thus Zis an Ore subset for both
U(g)/IB{A)
and A. Definec(m-) (or simply, c)
as in[24],
2.6. We recall[24],
2.6 thatU(C)R = U(m-)n
which inparticular gives
thatIB{A) n U(c) = O.
Thus theembedding U(#)/IB,(A) ÙA
restricts to anembedding
ofU(c)
andthrough
thead-nilpotence
of rtt-,by
an argument whichexactly parallels [24],
3.3,we find that
Z-’L
=Z-I(U(c)Lm-).
Combined with our earlier in-clusions this proves the theorem.
5.10 Set m = dim m and let dm denote the
Weyl algebra
of index mover C. We note the
following
result which obtains from 5.9 and the methods of[26].
THEOREM: For all B’ C B, A E
P (R’)++,
(i) L(MB,(A), MB{A»m- is a prime,
Noetherianring.
(ii)
FractL(Ma (A), Mp (A))’"’
=Fract(Hom(MB«À ), MB{A»ym).
(iii)
FractL(MB{A), MB«À))
=Fract(Um@End VB«À)),
up to anisomorphism.
6.
Multiplicities
In 6.1-6.4 we fix B’ C B and take
k, 1£
EP (R’)++:
A - > EP (R )
andJI E B’l. n P(R).
6.1
(Notation 4.4).
Ingeneral 0»§É L(MB«A), MB,(A - v)).
Yet 0» EHom(VB{A), VB«A - v))
and soby
5.9 there exists sregular
inL(MB«A - v), Mp (A - v)))
such that sO, EL(MB«A), MB«A - v)).
Let0,
denote the finite dimensional t modulegenerated by
s0».(For
v E
P(R)+
one can choose s =1, though
for our purposes theprecise
choice of s is
irrelevant.)
LEMMA: For all 0 # a E
L(MB,(Ii), MB{A»,
one has O,a 0 0.By
thedivisibility
ofL(MB,(.u), MB,(A - v)),
the relation seva = 0implies
0»a = 0 and so a = 0.6.2 LEMMA:
Set M =
L(MB,(Ii), MB,(Á - v»l 0,,L(MB,(Ii), MB,(Á»,
J =0,L(MB,(À v), Ma (À)). By
construction JM = 0 andby
4.8 and 6.1, J is a non-zero two-sided ideal of theprime,
Noetherianring
A : =L(MB«A - v), Me (À - v)). By
4.3(i),
M is afinitely generated
leftA module and so
by 5.4, [25],
2.1 and[6],
3.6 we obtaind(M) S D(AIJ) d (A)
= 2 dim m.By 5.4,
2.2 and 6.1 thisgives e(L(MB,(p), MB,(A - v))
=e(e»L(MB,(p ), MB,(A ))) * e(L(MB,(..t), MB’(À». Replac- ing v by
-vgives (i).
Ananalogous
argument(with
Ov on theright) gives (ii).
Combined with 3.3(ii)
and 4.5(i) they give (iii).
6.3 PROPOSITION: Both dim
VB«p)
and dimVB,(Á)
dividee(L(MB,(p), MB«A))).
By
6.2 it suffices to prove the first assertion with À EP (R’) v . By
4.5(ii), 5.2,
5.4 and5.9,
it isenough
to show that dimVB-( p, )
dividese(U(g) Hom(VB«p), VB’(À»).
Yet the latter isclearly
a direct sum ofdim
VB,(p) isomorphic U(g)
submodules and so therequired
assertionis obtained.
6.4 LEMMA: For all À, J.L E P
(R’)++:
À - IL E P(R),
there exists apositive integer c(g) depending only
on g such thate (L(MB,(I£), MB,(,k»):5 c
dimVB{IL)
dimVp (A).
Let T denote the
image
ofm- C
inU(m-).
Set L =L(MB{IL), MB,(Á»,
M =MB,(p ),
N =MB,(À ), Mk
=T k 0 VB«p ), Nk
=Tk @ VB,(À), Lk
=f a
EE L:(ad’ T)a
=0},
for all k E N. If aE Lk,
thenaMk
= 0implies
aM = 0(c.f. [8],
9.9,Eq. (14)).
Let E be a finite dimensionalgenerating subspace
for L considered as a leftU(g)
module and let F denote the
image
ofg Cf) C
inU(g)/IB’(À). By
thead-nilpotence
of rtt-, we can assume E to be ad T stable without loss ofgenerality
and that there exist r, s E N+ such thatF k E
CL kr+s,
for allk E N. Choose t E N such that
EM° C
N’. Since E is ad tn-stable,
it followsby
induction on tE N thatEMf C Nf+1
and soF kEM"
CNk+f+l,
for allk, tE
N. Inparticular, pkEMkr+s
CNk+kr+s+1
and soby
our first observation dim
F’E -
dimM(k+l)r dim N k(,+1)+,+,. Setting
dim rtt- = m, thisgives
Taking
5.4 into account, the assertion of the lemma holds withc(g) = (r
+1)2m(2:),
whichdepends only
on g(if
m, r refer to the casem- =
n-).
6.5 Fix
r E N+,
P a finite dimensionalsubspace #0
of Q[xl, x2, ...,xr]
and f2 a Zariski dense subset of N’.Assign
to thepair
P, f2 theinteger P’
defined as follows. Pick a basispk-1
for P withPi E
Z[Xl,
x2, ...,Xr].
Fix s E N, and let P,s be the smallestpositive integer
for which we can write for all i =1, 2,..., k,
Set
This is
independent
of the basis chosen.Obviously P " -- dim P.
LEMMA: For each s E
N+,
there exists a Zariski dense subset f2’C f2 such that pA,s = dim P,for
all À E ,fl’. Inparticular pn
= dim P.Fix s. We can write lIl as a union of
(2s
+1)(dim P)2
subsets in eachof which the Zij are constant. At least one such subset must be Zariski dense and this
clearly
satisfies the conclusion of the lemma.6.6 Given m, n E
N+,
let[m : n]
denote the greatest common divisor of m, n. Set e =rank g
and letal, a2,..., a2t
denote the fundamentalweights for g
x g. These form a dual basis to B x B and in 6.5 weidentify Z2t
withP (R ) x P (R )
andN 2,e
withP(R)+ x P(R)+.
GivenB’ C B,
setDB,={wE
W:w-1B’CR+}.
For all kE P(R)++
one hasDBÀ
CP(R’)++.
For all w EDB,,
define apolynomial
pw-iB on$*
through
For all À E
P(R)++,
one hasP,,,-’B(1k)
= dimVB,(wÁ), [17],
p.257, Eq.
(40).
Setd(#)
=IIaER+ (P, a) (which depends only
ong).
LEMMA: There exists a dense subset n