C OMPOSITIO M ATHEMATICA
D AVID E. R OHRLICH
Galois theory, elliptic curves, and root numbers
Compositio Mathematica, tome 100, n
o3 (1996), p. 311-349
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Galois theory, elliptic curves, and root numbers
DAVID E. ROHRLICH *
Department of Mathematics, Boston University, Boston, MA 02215 Received 2 August 1994; accepted in final form 3 January 1995
© 1996 Kluwer Academic Publishers. Printed in the Netherlands.
The inverse
problem
of Galoistheory
asks whether anarbitrary
finite group G can be realized asGal(K/Q)
for some Galois extension Il ofQ.
When sucha realization has been
given
for aparticular
G then a naturalsequel
is to findarithmetical realizations of the irreducible
representations
of G. Onepossibility
isto ask for realizations in the Mordell-Weil groups of
elliptic
curves overQ:
Givenan irreducible
complex representation
T ofGal(K/0),
does there exist anelliptic
curve E
over Q
such that T occurs in the naturalrepresentation
ofGal(K/Q)
onC0 ÍZ E(K)?
Thepresent
paper does notattempt to investigate
thisquestion directly.
Instead we
adopt Greenberg’s point
of view in his remarks on nonabelian Iwasawatheory [5]
and consider a relatedquestion
about root numbers. Let pE denote therepresentation
ofGal(K/Q) on C0s E(K)
and(r, 03C1E~
themultiplicity of
T in PE, and writeL(E,
T,s)
for the tensorproduct
L-function associated to E and T. Theconjectures
ofBirch-Swinnerton-Dyer
andDeligne-Gross imply
that(cf. [10],
p.127),
whence forrepresentations
T with real-valued character the root numberW ( E, T )
shouldsatisfy
The
reasoning
here is based on theconjectural
functionalequation
ofL(E, , s ),
which for
representations
with real-valued character relatesL ( E, T, s )
to itself andtherefore
gives
us(0.2)
as a consequence of(0.1).
Nowif W(E, )
= - 1 then(0.2) implies
that themultiplicity
of T in C 0sE(K)
is odd and hencepositive.
Thuswe are led to our basic
question:
Given T, an irreduciblecomplex representation
of
Gal(K/Q)
with real-valuedcharacter,
does there exist anelliptic
curve E overQ such that W(E,) = -1 ?
The best-known and most
easily
statedsufficient condition,
and the one whichfigures
inGreenberg’s
paper[5],
is thefollowing:
PROPOSITION A.
If
dim T is odd or det T is nontrivial then there exists anelliptic
curve E
over Q
such thatW(E, ) = - 1.
* Research partially supported by NSF grant DMS-9396090
Our primary
concem is therefore withrepresentations
of even dimension and trivial determinant.By
way ofillustration,
consider the case of a Galois extensionof Q
with Galois group
A5,
thealtemating
group on 5 letters.Up
toisomorphism, A5
hasexactly
four nontrivial irreduciblerepresentations,
all with real-valued character:two of dimension
3,
one of dimension4,
and one of dimension 5. SinceA5
issimple
all of theserepresentations
have trivial determinant. In view ofProposition A, only
therepresentation
of dimension 4presents
an issue.PROPOSITION B. Let K be a Galois
extension of Q
withGal(K/Q) ~ A5,
andlet be the 4-dimensional irreducible
representation of Gal(K/Q), unique
up toisomorphism.
There exists anelliptic
curve Eover Q
such thatW(E,) = -1 if
and
only if some decomposition subgroup of Gal(K/Q)
isisomorphic
toA4, S3,
or
(Z/2Z)2.
Buhler ([1], pp.47 and 136-141) has tabulated 174 fields K with Gal(K/Q) ~ A5,
and about half of the fields in his table
satisfy
our criterion. Forexample,
if Il isthe
splitting
fieldof x5
+1 Ox 3 - 10x2
+ 35x - 18(the
field of conductor 800 in thetable)
then thedecomposition
groups ofGal(K/Q)
at 2 areisomorphic
toA4,
and hence there exists an E for which
W ( E, T )
= -1. In fact one can take for E anyelliptic
curveover Q
withsplit multiplicative
reduction at 2. On the otherhand,
if Il is thesplitting
field ofx5 + 6x4
+19x3
+25x2 + 11x +2 (the
field ofconductor 1501 in the
table)
then none of the groups inProposition
B occurs as adecomposition
group, andconsequently W (E, 7)
= 1 forevery E over Q.
Proposition
B illustrates thetype
of statement which can be deduced fromour main
result,
Theorem 3.However,
we would like toemphasize
that Theorem 3 is far frombeing
a definitive result of itskind,
because theunderlying
localcalculations do not cover all
possibilities
when the residue characteristic is 2 or3. While this defect tums out not to matter in the case of
A5
and in many other cases, the effect ingeneral
is that the necessary conditions affordedby
Theorem3 are weaker than the sufficient conditions. A second
point
about the theorem is thatusually
there is no way topredict
what it says about agiven
group G and agiven
irreduciblerepresentation
7 of Gexcept by calculating
the restriction of 7 to various smallsubgroups
of G. Consider forexample
the nextsimple
group afterA5, namely PSL(2, F7). Up
toequivalence PSL(2, F7)
has five nontrivial irreduciblerepresentations:
two of dimension3,
which do not have real-valuedcharacter,
andone each of dimensions
6, 7,
and 8. Of concem here are therepresentations
ofdimensions 6 and 8. The
disparate
behavior of these tworepresentations
underrestriction to
subgroups
is reflected in thefollowing proposition.
LetDn
denotethe dihedral group of order 2n.
PROPOSITION C.
Let K be a Galois extension of Q with Gal(K/Q) ~ PSL(2,F7),
and let
(6)
and7(8)
be the irreduciblerepresentations of Gal(K/Q) of dimensions
6 and 8
respectively, unique
up toisomorphism.
(1)
There exists anelliptic
curve Eover Q
such thatW(E, (6))
= -1if
andonly if
somedecomposition subgroup of Gal(Il /Q)
isisomorphic
toS4, A4, D4,
or(7-/2Z)2.
(2)
There exists anelliptic
curve Eover U
such thatW(E, (8))
= -1if
andonly if
somedecomposition subgroup of Gal(K/Q)
isisomorphic
toS4, D4,
or
S3.
A beautiful
example
of a Galois extensionof Q
with Galois groupPSL(2, F7)
hasbeen
given by
Trinks(see
LaMacchia[7],
p.990,
or Matzat[9],
p.212):
Il isthe
splitting
field of thepolynomial x7 -
7x + 3. In thisexample
the decom-position
groups at 3 areisomorphic
toS3,
but none of the other groups listed inProposition
C occurs as adecomposition
group. Hence there is anelliptic
curve E over Q for which W(E, (8)) = - 1 but none for which W(E,(6)) = -1.
We shall see that
W(E,(8)) = -1
whenever E hassplit multiplicative
reductionat 3.
To
complete
our survey of illustrativespecial
cases, let us note that there aresituations in which
W(E, T)
isalways
1:PROPOSITION D. Let Il be a Galois extension
of Q
such thatGal(K/Q) ~ Dq
xDr
xDS
xDt
with distinctprimes
q, r, s,t 5,
and let T be an irreducible 16-dimensionalrepresentation of Gal(K/Q).
ThenW(E, )
= 1for
everyelliptic
curve E over
Q.
As with other deductions from Theorem
3, Proposition
D does not appear to bepredictable
on apriori grounds. However,
there is one case in which a result likeProposition
D would beentirely expected, namely
the case where the Schur index of r is even(by
contrast, every irreduciblerepresentation
ofDq
xDr
xD,,
xDt
has Schur index
1).
Thepoint
here is that therepresentation
pE ofGal(K/Q)
on C oz
E(K)
is thecomplexification
of arepresentation
overQ.
Hence if T is any irreduciblerepresentation
ofGal(K/Q)
then(T, pE)
is divisibleby
theSchur index
m(T)
of T. Inparticular,
if tr is real-valued andm(r)
is eventhen
(0.2)
wouldimply
thatW(E, T)
= 1. The nextproposition
verifies thisconclusion under some condition at the
primes
2 and 3. Since the Schur index of an irreduciblerepresentation
with real-valued character is either 1 or 2(the Brauer-Speiser theorem),
to say thatm()
is even is to say thatm( T)
= 2.PROPOSITION E. Let Il be a
finite
Galois extensionof Q
and r an irreduciblecomplex representation of Gal(K/Q)
with real-valued character. Assume that thedecomposition subgroups of Gal(K/Q)
at 2 and 3 areabelian. If m() =
2 thenW(E, )
= 1for
everyelliptic
curve E overQ.
Given the
incompleteness
of our local calculations at theprimes
2 and3,
someextraneous condition at these
primes
seemsinevitable,
but theparticular
conditionchosen here could be
replaced by
a number of alternativehypotheses.
Forexample,
instead of
imposing
a condition on thedecomposition
groups at 2 and 3 we couldrequire
that E have semistable reduction at 2 and3,
or moregenerally
that E attainsemistable reduction over abelian extensions of
Q2
andQ3.
In any case, the mainpoint
is that ifm(T)
= 2 then root numbers are of no use indetecting
thepossible
occurrence of T in the Mordell-Weil group of an
elliptic
curve overQ.
This is aninherent limitation of our
point
of view.In conclusion let us
point
out that Theorem 2 of thepresent
paper is a gener- alization of the local results in[11],
the latterbeing
thespecial
case where T isthe trivial
representation.
We also take thisopportunity
to mention the paper of Kramer and Tunnell[6],
which should be added to the list of references in[11].
The
ingredients
in theproof of
Theorem 2.7 of[6]
and ofProposition
2 of[11]
arethe same; the latter result
merely
carries theargument
onestep
further.It is a
pleasure
to thank John Millson forclarifying
aproperty
ofStiefel-Whitney
classes and Brian
Conrey
forproviding
the reference[5].
1. A local calculation
By
arepresentation
of a group G we shallalways
mean a finite-dimensionalrepresentation
over thecomplex numbers,
understood to be continuous if G has anatural
topology.
Thecontragredient
of arepresentation
7r will be denoted 7r*. We say that 7r isself-contragredient
if 03C0 c-’-7r*, symplectic
if the space of 7r admits anondegenerate symplectic
form invariant under 7r, and realizable over a subfield E of C if there is an E-form of the space of 7r which ispreserved by 7r.
We mentionin
passing
that if theimage
of 7r is finite then 7r is realizable over R if andonly
if 7ris
orthogonal,
i.e. if andonly
if the space of 03C0 admits anondegenerate symmetric
bilinear form invariant under 7r.
By
a character of G we shall mean either a one-dimensionalrepresentation (i.e.
a
’quasicharacter’ X :
G -C )
or the trace of arepresentation
of dimension1, depending
on the context. In the case of ’one-dimensional characters’ the twomeanings coincide,
of course. Ofparticular importance
to us are one-dimensional characters ofGal(F/F),
orequivalently,
ofGal(Fab/F),
where F is a local field of characteristic 0 andFab
its abelian closure. We shallroutinely identify
suchcharacters with finite-order characters of F x
by agreeing
that~(x) = ~((x-1, Fab/F)) (x ~ F ), (1.1)
where
(*, Fab/F)
is thereciprocity
lawhomomorphism
asnormalized by
Artin.For
example, 1 F
can denote either the trivial character ofGal( F/ F)
or the trivial character ofF X ,
and if Il is aquadratic
extension of F thenXK/F
can denoteeither the
quadratic
characterof Gal(F/F)
with kemelGal(F/K)
or thequadratic
character of F with kemel
NK/F(K ).
We remark that the choice ofx -1 rather
than x on the
right-hand
side of(1.1)
is made for the sake ofconsistency
with[2]
and
[18].
If Il is any finite extension of F then we denote
by indK/F
andresK/F
theinduction and restriction functors associated to
Gal(F/F)
and itssubgroup
of finiteindex
Gal(F/K).
In the case where F is nonarchimedean we shall makefrequent
use of the fact that the Artin
conductor-exponent a(*)
satisfies the formulaa(indK/F03C0)
=d(K/F) dim 03C0
+f(KIF)a(7r), (1.2)
where 7r is an
arbitrary representation
ofGal(F/K)
andd(K/F)
andf(K/F)
denote
respectively
theexponent
of the relative discriminant of Il over F and the residue classdegree
of li over F. Ageneral
reference for theproperties
ofa(*)
that will be needed here is
[15].
Given a
representation
7r ofGal(F/F),
an additivecharacter 0
ofF,
and aHaar measure dx on
F,
letf( 7r , 03C8, dx)
denote the associatedepsilon
factor. If the determinant of 7r is trivial then we define the root numberW(03C0)
of 7rby
theformula
the
point being
that when det 03C0 is trivial theright-hand
side of(1.3) -
which is in any caseindependent
of the choice of dx - isindependent
of the choiceof 0
as well.If 7r is
self-contragredient
as well as of trivial determinant thenH(03C0) = ±1.
Thisis in
particular
the case for therepresentations
ofprimary
interesthere, namely
those of the form 7r = 03C3 ~ T with 03C3 a
symplectic representation
ofGal(F/F)
and T an
arbitrary representation of Gal(F/F)
with real-valued character. Indeed theself-contragredience of a 0
T and thetriviality
ofdet a 0
r follow from the formulasand
respectively,
because asymplectic representation
isself-contragredient,
even-dimensional,
and of trivialdeterminant,
while arepresentation
with finiteimage
isself-contragredient
if andonly
if its character is real-valued.Although
ourgoal
is to calculateW(03C0)
in a case where thisquantity
isindepen-
dent of any
choices,
the method of calculation forces us to considerrepresentations
for which the root number
depends
on the choice of0.
Such a root number is still definedby
theright-hand
sideof ( 1.3)
but should inprinciple
be denotedW(03C0,03C8).
However,
to avoidcarrying 1b
in thenotation,
let us agree that for each local field F of characteristic 0 we choose the additive characterwhere
Qp
is thetopological
closureof Q
inF,
and
f xlp
denotes theimage
of x under thecomposition
of natural mapsWith this convention we have
1b R-
=1b F
otrK/ F
for a finite extension li ofF,
andconsequently
if 7r is arepresentation
ofGal(F/K)
thenFormula
(1.4)
is theanalogue
for root numbers of(1.2)
and anexpression
of thefact that
’epsilon
factors are inductive in dimension 0’. For furtherbackground
onroot numbers the reader is referred to
[2], [18],
or[12].
Later in the paper we shall encounter
representations
of the Weil groupW ( F / F)
and of the
Weil-Deligne
groupW’(F/F)
as well asrepresentations
ofGal(F/F).
Thus it is
appropriate
to note that all of the definitions and conventionsjust
men-tioned are
meaningful
in thelarger
context. Inparticular,
if 03C3 is asymplectic representation
ofW(F/F)
orW’(F/F)
and T is arepresentation
ofGal(F/F)
with real-valued
character,
then it is still true thatW(03C3 ~ T)
is a well-defined num-ber
equal
to f 1. We alsopoint
out that formula(1.1 )
allows us toidentify arbitrary
characters of F’
(not necessarily
of finiteorder)
with characters ofW (F/F)
andhence with characters
of W’(F/F).
Some two-dimensional
representations
By
a dihedralrepresentation
we shall mean an irreducible two-dimensional repre- sentation which has finiteimage
and is realizable over R.Equivalently,
a dihedralrepresentation
is a two-dimensionalrepresentation
withimage
a dihedral group oforder
6. Theequivalence
of the two definitions follows from the fact that a finitesubgroup
ofGL(2, R)
isconjugate
to asubgroup
ofO(2, R)
and is therefore eithercyclic
or dihedral.To avoid a
possible ambiguity
we make one further remark. Inpart (i)
of the fol-lowing proposition
we consider arepresentation
of the formindH/F~,
whereH/F
is a
quadratic
extension of nonarchimedean local fields of characteristic 0 and cp isa character of H". Since we do not assume
that ~
has finite order therepresentation
indH/F~
must beinterpreted
apriori
as arepresentation
ofW(F/F)
rather than ofGal(F/F). However,
we prove that ifindH/F~
is irreducible andsymplectic
then
~|F
coincides with~H/F,
thequadratic character of
Fxcorresponding to
H. Since F is
nonarchimedean,
theequality ~|F
=XH/F implies that p
hasfinite
order,
whenceindH/F~
is arepresentation
ofGal( F 1 F).
PROPOSITION 1. Let F be a nonarchimedean
local field of characteristic
0.(i)
Let H be aquadratic
extensionof
F and ~ a characterof
H x . The repre- sentationindH/F~
is irreducible andsymplectic if and only if ~|F
=XH/F
and ~2 ~ 1H.
(ii)
Arepresentation ofGal( F / F)
is dihedralif and only if it
hasthe form indH/F~
for
somequadratic
extension Hof
F and some character rpof
H xsatisfying rplFx
=1 p
andrp2 =1= 1H.
Proof.
Both assertions arequite standard,
but for the sake ofcompleteness
weprovide
a detailedargument.
(i)
A two-dimensionalrepresentation
issymplectic
if andonly
if it has trivialdeterminant,
becauseSp(2, e)
=SL(2, C).
Nowaccording
to the formula for the determinant of an inducedrepresentation (cf. [2],
p.508),
Therefore
indH/F~
issymplectic
if andonly
if~|F
=~H/F.
We claim that under theseequivalent conditions, indH/F~
is irreducible if andonly if ~2 fl 1 H.
Indeedthe condition
~|F
=XH/F implies
that yJ oNH/F
=1F
andconsequently
that~ o 03B3 =
~-1, where 1
denotes the nontrivialautomorphism
of H over F. Hencethe standard
criterion ~ ~
(p o y for theirreducibility
ofindH/F~
isequivalent
tothe condition ~
~ cp-1,
i.e.~2 ~ 1H.
(ii)
Let 03C0 be a dihedralrepresentation of Gal(F/F),
viewed as a mapSince 7r is
(absolutely)
irreducible theimage
of 7r is not contained inSO(2,R).
It follows that the fixed field of
03C0-1(SO(2,R))
is aquadratic
extension H of F and that 7r ~indH / FCP
for some character (p of H . Then det 7r =xH/F,
whence~|F
=1F by (1.5).
AlsoreSH/F03C0 ~
~ EB~-1,
because the nontrivial coset ofSO(2,R)
inO(2, R)
acts onSO(2,R) by
inversion. Since theimage
of 7r isnonabelian
resH/F03C0
is notscalar,
andconsequently ~2 ~ 1H.
For the converse we use the fact that an irreducible
representation
with finiteimage
and real-valued character is eithersymplectic
or realizable over R.Suppose
that H is a
quadratic
extension of F and yJ a character of H such that~|F
= 1 Fand
~2 ~ 1H.
The condition~|F
=1F implies
firstthat ~
has finite order and secondthat ~
o -ycp-l, where i
is the nontrivialautomorphism
of H over F.Since ~ ~ cp-1
it followsthat ~ o q fl
(p. ThereforeindH / FyJ
is irreducible. Alsodet(indH/FCP)
=xH/F by (1.5)
andby
the formula for an induced character. ThusindH/F~
is a two-dimensional irreduciblerepresentation
with finiteimage,
real-valuedcharacter,
and nontrivial determinant. Since asymplectic representation
has trivial determinant we conclude thatindH/F~
is realizable over R.REMARK. It can
happen
thatindH/FCP
is dihedral eventhough cp2
=1H. Propo-
sition 1
merely
asserts thatindH/FCP
can also be written asindH’/F~’
withH’/F
quadratic, ~’|F
=1F,
and(~’)2 ~ 1HI.
Statement
of
Theorem 1To state the
theorem,
fix a nonarchimedean local field F of characteristic 0 and let H be the unramifiedquadratic
extension of F. Put q =xH/F.
We also fix atwo-dimensional
symplectic representation u
ofGal( F/ F)
which isirreducibly
induced from a tame character of H X . Thus a is
irreducible, symplectic,
and of theform
where ~ is a character of H x with
a(~)
= 1.According
toProposition 1, ~|F
= 71 and~2 ~ 1 H.
Let 03B8 denote the unramifiedquadratic
character ofH X ,
so that03B8|F = ~,
andput
and
Then
|F
=1F
and2 ~ 1H. Consequently, Proposition
1implies
that & is dihedral.Let
OH
denote thering
ofintegers
of H. Since H is unramified over F there isa unit
UH/F
CO H such that H = F( UH/F)
andu2H/F
E F. The value of~(uH/F)
is
independent
of the choice ofuH/F,
because~|F
= ~ and therefore~|O F
istrivial. For the same reason,
~(uH/F) = ±1.
Given
representations
p and rof Gal(F/F),
we define theirinner product (p, T)
by
where on the
right-hand
side p and Tare viewed asrepresentations
ofGal(K/F)
for some finite Galois extension Il of F and
(trp, tr r)
is the usual innerproduct
oncharacters of
Gal(K/F).
Thus if p is irreducible then(p, T)
isjust
themultiplicity of p
in T.We denote
1F simply by
1.THEOREM 1. Let T be a
representation ofGal(F / F)
with real-valued character.Then
To prove the theorem it will suffice to treat two
special
cases:(i)
T issymplectic.
(ii)
T is realizable over R.Indeed every
representation
ofGal(F/F)
with real-valued character is a directsum of
representations
oftypes (i)
and(ii),
and as functionsof T,
both sides of the formula to beproved
aremultiplicative
across direct sums. Webegin by proving
the theorem for
representations of type (i).
The case where T is
symplectic
Suppose
that T issymplectic.
Then det T istrivial,
dim T is even, and also~03B6, ~
iseven for any irreducible
representation 03B6
ofGal(F/F)
which is realizable over R.Hence the
right-hand
side of the formula to beproved
is1,
and Theorem 1 followsin this case from a
general
fact:PROPOSITION 2.
If a
and T aresymplectic representations of Gal( F / F),
thenW(03C3~) = 1.
Proof.
Let V and W be the spaces of a and T. Thus V and W areequipped
with
nondegenerate
invariantsymplectic forms,
and we may view Q and T as mapsGal(F/F) ~ Sp(V)
andGal(F/F) ~ Sp(W).
Put U =V 0 W
and 7r == a 0 T.The tensor
product
of thesymplectic
forms on V and W is anondegenerate symmetric
bilinear form on U which is invariant under 7r.Furthermore,
7r hastrivial
determinant,
so that we may view 7r as a mapGal(F/F) ~ SO(U).
Henceby Deligne’s
theorem on root numbers oforthogonal representations ([3],
p.301),
W(03C0)
is 1 or -1according
as 7r does or does not lift to thespin
coverSpin(U) ~ SO(U).
Now the naturalembedding
afforded
by
the tensorproduct
does lift toSpin( U ),
because the fundamental group ofSp(V)
and ofSp(W) -
hence also ofSp(V)
xSp(W) -
is trival. Since(1.6)
lifts to
Spin(U),
so does 7r, and thereforeW(Jr )
= 1.REMARK. For later reference we note that
Deligne’s
theorem(hence
alsoPropo-
sition
2)
holds withGal(F/F) replaced by W(F/F),
cf.[3],
p. 314.The theorem
of Frôhlich-Queyrut
To prove Theorem 1 in the case where r is realizable over R we will need the
following
result:PROPOSITION 3. Let Il be a nonarchimedean local
field of
characteristic0,
L theunramified quadratic
extensionof 1(,
and À a characterof
Lx such that03BB|K = XL/K.
Thenwhere
uL/K
EO£
is any element such that L =K(uL/K)
andu 2
E I(.Proof.
Let ~ be the unramifiedquadratic
character of LX. Then~|K
=XL/K.
Hence
putting  =
~03BB wehave  |K
= 1 K, so thatby
the theorem ofFrôhlich-Queyrut ([4],
Thm.3).
On the otherhand,
let 03C9 be auniformizer of Il and let
n(03C8K)
be thelargest integer
n such that1b R-
is trivial on03C9-nOK.
Since 0 isunramified,
Comparison
with ourprevious
formula forW() yields
This is the stated
result,
becauseThe case where T is realizable over R
In the case where r is realizable over R we first prove a
preliminary
versionof Theorem 1 in which the
exponent ~1,)
+~~,)
+(il, T)
isreplaced by a(03C3 ~ T)/2 - a(T).
To see that the latterexpression
is aninteger,
write a =indH/F~. Then o, 0
T =indH/F(~ ~ resH/F)
andconsequently
by (1.2).
PROPOSITION 4.
If
T is realizable over R, thenProof.
As functions of T, both sides of the formula to beproved
define homo-morphisms
from the Grothendieck group of virtualrepresentations
ofGal(F/F)
realizable over the reals into the group
{±1}.
Hence it suffices toverify
the for-mula on a set of
generators
of the Grothendieck group. In factapplying
Serre’sinduction theorem
([13], Prop. 2,
p.177)
we see that we may restrict our attentionto
representations
of the form T =indK/F7r,
where Il is a finite extension of F and 03C0 arepresentation
ofGaI(F/A")
of one of thefollowing types:
(b)
7r is aquadratic
character ofGal(F/K).
(c)
7r= x e y, where X
is a character ofGal(F/K)
oforder
3.(d)
7r is dihedral.Before
tuming
to a consideration of cases we observe that if T =indK/F03C0
then
_
whence
by (1.4). Also
because the
product
of the root number of arepresentation
and the root number ofits
contragredient
is the determinant at -1(cf. [12],
p. 144 or[18], (3.4.7)).
Nowaccording
to the formula for the determinant of an inducedrepresentation,
the finalexpression
in(1.9) is det (-1)/det 03C0(-1). Hence (1.8)
and(1.9) give
On the other
hand, by (1.2)
we haveand also
via
(1.7).
HenceCombining (1.10)
and(1.11),
we conclude that for T =indK/F03C0
the assertion ofProposition
4 isequivalent
to the formulaNext we observe that
(1.12)
is satisfied whenever K contains H. Indeed if K contains H thenso that
(recall
that~|O F
istrivial).
This result does coincide with(1.12),
because[Il : F]
=2[K : H] and f (K/F)
=2f(K/H).
It remains to prove
(1.12)
for 03C0 as in(a), (b), (c),
or(d),
and li a finite extension of F notcontaining
H. The latterassumption implies
thatf (KIF)
isodd,
whence(1.12)
becomesPut L = HL and 03BB = ~ o
NL/H,
so that L is the unramifiedquadratic
extensionOf ll and
resK/FO"
=indL/K03BB.
ThenConsequently
and
by (1.2)
and(1.4) respectively.
After substitution of(1.14)
and(1.15)
into(1.13)
the statement to be
proved
isNote that
since
xL/h
=xH/F
oNKIF
= q oNKIF.
We nowproceed
to a consideration ofcases.
(a)
If 03C0 =1 h
then(1.16)
follows from(1.17)
andProposition 3,
becauseL =
K(uH/F)
and(b)
If 03C0 is aquadratic
characterof Gal(F/K)
with kernelGal(F/K’)
thenas virtual
representations.
In view of thetransitivity
of induction theproof
of theproposition
for T =indh/F7r
reduces to the case treated in(a).
(c)
If 7r= x ED X
then it is more convenient toverify (1.13)
than(1.16).
Sinceais
self-contragredient
we have(X (D resK/F03C3)*
=~ ~ resK/F03C3,
whenceThe
right-hand
side of(1.13)
is also1,
becausedet 7r( -1)
=1,
dim7r =2, a(03C0)
=2a(x),
anda(7r 0 resKI Fa)
=4a((x
oNL/K)03BB).
This lastpoint
followsfrom
(1.2)
onnoting
thatand
that x (D reSK/FOr
=indL/K((~
oNL/K)03BB).
(d)
If 7r is dihedral thenby Proposition
1 we can write 7r =indM/K03BC
with aquadratic
extension M of K and acharacter y
of M 1 such thatp |K
= 1 K. Thereare now two cases,
according
as L = M orL -1
M.Case 1: L = M.
Let 1
be the nontrivialautomorphism
of L over Il . The condition03BC|K
=1 j; implies that y
o 03B3 =03BC-1.
Since 7r =indL/K03BC
it followsthat
resL/K03C0 = 03BC ~ 03BC-1.
Alsoa(7r)
=2a(p)
anddet 03C0(-1)
=~L/K(-1) = 1
because L is unramified over Il . Thus the assertion of
(1.16)
is thatSince
03BC|K
=1K
this follows from(1.17)
andProposition
3.Case 2:
L :1
M. In this case LM is abiquadratic
extension of IF. Let P be the thirdquadratic
extension of K contained in LM. Since LM = LP and L is unramified over IF the extensionL M/ P
is unramified and L M =P(uH/F).
Furthermore,
the character v of(LM)
definedby
satisfies
by (1.17).
Thereforeby Proposition
3. In factbecause v(uH/F) = ~(u2H/F)[K:F]03BC(-u2H/F) = 1.
On the other
hand,
Therefore
and
by (1.2)
and(1.4).
Formula(1.4)
also tells us thatReplacing
Lby
Peverywhere
in thepreceding calculation,
and thenusing
the factthat LM =
PM,
we deduce thatBut
because
indP/K1P
=1K ~
~P/K and(~L/K
isunramified). Together, (1.21)
and(1.22) give
Combining
this with(1.18), (1.19),
and(1.20),
we conclude thatNow
a(7r)
=d(M/K) (mod 2):
this can be seen eitherby using
the factthat
a(7r)
=d(M/IF)
+a(03BC)
andMIK’
=lh
orby noting
thatD(MIK) = a(~M/K)
=a(det 03C0)
andquoting
a theorem of Serre([13],
thm.1,
p.173).
Thusthe
exponent d(M/K)
in(1.23)
can bereplaced by a(7r),
and(1.16)
follows.Completion of
theproof
The final
step
of theproof depends
on ageneral
fact about conductors.LEMMA . Let 7r be an irreducible
representation of Gal( F / F)
and cp atamely ramified
characterof Gal( F / F). If a(~
Q903C0) ~ a(03C0)
then 7r is one-dimensional and either 7r or cp 0 7r isunramified.
Proof.
Let V be the space of 7r and I the inertiasubgroup
ofGal(F/F),
andlet
V1r(I)
be thesubspace
of Vconsisting
of vectors fixedby
I. Thena(03C0)
= dim V - dimV1r(I)
+higher-order terms,
where the
’higher-order
terms’depend only
on the action of thehigher
ramification groups on V.Since ~
is tame, theassumption
thata(~ ~ 7r) ~ a(7r)
means thatdim V(~~03C0)(I) ~ dim V03C0(I)
and hence in
particular
thatAs I is normal in
Gal(F/F)
these spaces are invariantsubspaces
for the irre- duciblerepresentations
~ ~ 7r and 7rrespectively. Consequently,
one of the twospaces coincides with
{0}
and the other with V. Hence one of rp 0 7r and 7r is ramified and the other unramified. If 7r is unramified then 7r can be viewed as anirreducible
representation
of theprocyclic
groupGal(F/F)/I,
so that 7r is one-dimensional. On the other
hand,
if yJ 0 7r isunramified,
then7r 1 l
actsby
scalarmultiplication by
the characterrp-III,
whence7r (I)
is central in7r(Gal(F / F)).
Since
7r(Gal(F / F))/7r(I)
iscyclic
it follows that7r(Gal(F/F»
is abelian andagain
we conclude that 7r is one-dimensional.The
following proposition completes
theproof
of Theorem 1.PROPOSITION 5.
If T is a representation of Gal( F / F)
which is realizable overR then
a(o, 0 T)/2 - a(T) - (7,1)
+~,~~
+(T, à) (mod 2).
Proof.
Since the statement to beproved
is additive in T, we may assume that T is either irreducible or of the form 7r 0 7r* with 03C0 irreducible. In the latter case T issymplectic
and therequired
congruence follows from Theorem 1(already proved
for
symplectic representations)
andProposition
4. Henceforth we assume that r is irreducible. In this case the statement to beproved
isa(03C3 ~ )/2 - a() ~ { (mod 2) if ~ 1, ~, or
(1.24)
0 (mod 2)
otherwise.Let 7r =
res H/ FT.
Thenso that
Since
a(*)
is invariant under restriction to the Galois group of an unramifiedextension,
we also haveHence
(1.24)
isequivalent
to1 (mod2) if ~ 1, ~, or
(1.25)
a(~ ~ 03C0) - a(03C0) ~ {0 (mod 2) otherwise. (1.25)
Now
if = 1 or = ~
then 7r =IF
anda(~
003C0) - a(7r)
==a(~)
=1,
so that inparticular a(~
07r)
-a(03C0)
== 1(mod 2)
as stated in(1.25).
On the otherhand,
if~ then
and since 0 is unramified we obtain
At this
point
we recall that~2 ~ 1 H .
Since(~|F )2 = 7î2
=1 F
and H X = FO H,
it follows that~2|O H
isnontrivial,
or in other words that~2
is ramified.Thus
a(~2)
= 1 and theright-hand
side of(1.26)
is -1. Hence(1.25)
holds alsofor 7 -- il.
Next suppose that T is not
isomorphic
to1, ~,
or à. We claim thata(~ ~ 7r)
and
a(03C0)
areequal,
whencecongruent
modulo 2. To seethis,
first consider thecase where 7r is irreducible. If
a(~ ~ 7r) i a(03C0),
then 7r is one-dimensionalby
the
lemma,
andconsequently
T is also one-dimensional. Since T is realizable over R but different from 1 and q, we deduce that r is a ramifiedquadratic
character.As H is unramified over F it follows that 7r is also a ramified
quadratic
character.Since
~2|O H
isnontrivial,
as we saw a moment ago, it follows that 7r and ~03C0 are bothramified, contradicting
the lemma. Next suppose that 7r is reducible. Since is irreducible we can write 7r = K e03BA’
with irreduciblerepresentations K
and K’such that T =
indH/F03BA
=indH/FK’.
Ifa(~
07r) ~ a(7r)
thena«p 0 r,) 0 a(K)
or
a«p 0 03BA’) ~ a(03BA’);
saya(~ ~ 03BA) ~ a( K).
Then rc is one-dimensionalby
thelemma. If K is unramified we can write K =
resH/Fl
with an unramified charactert
of Gal(F/F).
Then T =indH / FK == ¿ EB
~,contradicting
theirreducibility
of r.Hence is ramified. The lemma now
implies
that pK is unramified.Consequently, ôK
is alsounramified,
so that03BA
=resH/Fl
for some unramified character t ofGal(F/F).
ThenTaking determinants,
we obtain det T =¿ 2 det â,
and since T and ô, are bothrealizable over R, we deduce
that t 4
= 1. We now consider twopossibilities:
t2 -
1 ort2 0
1. Ifc2
= 1 then t is the unramifiedquadratic
character 7î ofF x ,
whence
reSII/Ft
is trivial and the conclusionof (1.27)
becomes T =, contrary
tohypothesis.
On the otherhand,
if2 ~ 1,
then t is one of the two unramifiedquartic
characters of
F ,
whenceresH/F¿
is the unramifiedquadratic
character 03B8 of HX.Therefore
(1.27)
becomesSince T is realizable over R whereas 03C3 is irreducible
symplectic,
we have a contra-diction here too, and we conclude that our
original hypothesis a( t.p 0 7r) ~ a(03C0)
was in error.
2.
Complementary
calculationsAs
before,
F denotes a nonarchimedean local field of characteristic 0. If n is apositive integer
thensp(n)
denotes therepresentation
ofW’(F/F) commonly
referred to as the
’special’
or’Steinberg’ representation
of dimension n.PROPOSITION 6. Let r be a
representation of Gal( F / F)
with real-valued char-acter. Then