C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
R OSS S TREET Parity complexes
Cahiers de topologie et géométrie différentielle catégoriques, tome 32, n
o4 (1991), p. 315-343
<http://www.numdam.org/item?id=CTGDC_1991__32_4_315_0>
© Andrée C. Ehresmann et les auteurs, 1991, tous droits réservés.
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PARITY COMPLEXES
by
Ross STREET CAHIERS DE TOPOLOGIEET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
VOL. XXXII-4 (1991)
Résumé
On construit un modulepratique
de lan-cat6gorie
libreengendr6e
par certainspolytopes
orient6s de manuread6quate.
Pourfaire la construction tout ce
qui
est n6cessaire dupolytope
estl’ensemble
gradu6
de faces et le classement parsigne
des (m-D-faces dechaque
m-face. Leconcept
decomplexe parité
fait abstraction de cette structure.La
description
de lan-cat6gorie
libreengendr6e
par uncomplexe parité
estsimple
mais la preuvequ’elle
est unen-catégorie
etqu’elle
est libre entraine delongues
inductions. On considère lesproduits
et lesjoints
descomplexes parités.
Commeapplications,
lesobjets
fondamentaux,de lacohomologie g6ndrale
non-abélienne et ceuxde la théorie de descente se sont
précisés
pour lapremiere
fois.Introduction
Parity complexes
are a new combinatorial structure introduced here in order toprovide
a uniform treatment of thediagrams
in all dimensions that appear in descenttheory
and in thetheory
ofhomotopy types.
The
particular
sequence of thesediagrams arising
from thesimplexes
was treated in
[Sll.
The modification of that work needed to deal with cubeswas done in
part by [AS],
and abeautifully geometric
treatment of cubes witha derived treatment of
simplexes appeared
in[A].
A different treatment ofsimplexes
wasgiven by with
a view to an abstraction togeneral pasting diagrams.
Such an abstraction wasaccomplished by [J],
but the axioms thereare rather
complicated.
The calculations of
[S1]
led me toconjecture
(inMontreal,
1985) thatthe decision to make all the odd faces
part o
the source and the even facespart
of thetarget uniquely
determined thecocycle
conditions ofhigher-order
non-abelian
cohomology.
Thisprovided
one motivation for theconcept
ofparity complex.
Apart
from thesimplexes
and cubes there were thediagrams arising
indescent.
J.W.
Duskinproposed
(about 1981) that there should be a descent w -category
associated with eachcosim licial w-category
and drew thediagrams
in low dimensions. The first
step
inealing
with a class ofdiagrams
is to finda suitable notation. For
simplexes
and cubes we had agood
notation. Onlooking
at the descentdiagrams,
I realized(early
1987) thatthey
weresimply products
ofsimplexes
with"globs";
these latter form a very easy classof
diagrams
to treat. I gave a talk in theSydney Category Seminar outlining
aprogram to
investigate
these matterg. The next week MiJohnson pointed
out that my
description
of theproduct
in that lecture was toosimplistic.
Ishould have realized this since I discussed the associated chain
complex
inthe same
lecture,
and ute iezoorproduct
of the chaincump!exes
Is associated to the correctproduct. Johnson’s
lectures onpasting
schemes (nowappearing
inhis PhD thesis
[J]) provided
the first successful abstraction from thesimplex example,
andstrongly
influenced this work. Hisgoal
tocapture
thegeneral pastable diagrams
ofhigher-order categories
is more ambitious than thegoals
outlined here.
These considerations led me to
try
to abstract the constructions of[Sl]
from
simplexes
to a structure in which"negative"
and"positive"
faces weregiven.
The abstraction arosepurely
from the desire to deal withproducts
ofexamples already
understood.However,
the resultantconcept
ofparity complex
is an accessible multi-dimensionalgeneralization
ofloop-free graph;
the free
w-category generalizes
thecategory
ofpaths
in thegraph.
The first section
gives
the definition ofparity complex
and thestraight-forward roof
thatsimplexes provide
anexample.
A differentproof
will be obtain later from the fact that
simplexes
are iterated cones;however, presentation
of thisexample
in the first section shouldgive
readersa
feeling
for the axioms and convince them that the hardpart
of the work of[Sl]
is included in ourgeneral theory
and not inverifying
the axioms.Duality
is
explained. Also,
the chaincomplex
of free abelian groups associated to eachparity complex
is described.The second section introduces the notion of movement which
captures
the idea of passage from one
part
of theparity complex
to anotherby replacement
ofnegative
facesby positive
faces.Composition
anddecomposition
of moves is examined inpreparation
for the construction of the freew-category
on aparity complex.
The details of this construction appear in the third section and its universalproperty
isgiven
in the fourth section.The fifth section describes the
product
andjoin
ofparity complexes.
These
require
some extra conditions in order to work well. The final section describes the descento-category
of acosimplicial .-category
and thespecial
case,
sought by John
E. Roberts[R1],
ofcohomology
with coefficients in an ta-category.
The connection withhomotopy types
will bepursued
elsewhere.Added
September
1991. This paper is aslight
modification of aMacquarie
Mathematics
Report IS2].
Soon after thatReport
was written,John
Powerpointed
out that theparity complexes
axiomatized there were notgeneral enough
to cover all thepasting diagrams
one would like toinclude,
even for 3-categories.
Thepasting
schemes of[J]
were better in thisrespect.
We wereespecially encouraged by
theapplications
of the work foreshadowedby Kapranov-Voevodsky [KV1], [KV2 . However,
inMay 1990, Vaughan
Pratt(through
his interest in concurrency incomputer
science[P])
and MichaelJohnson
came up with a series ofexamples
to show the real limitations of my axioms (even for the 3-cube). This meant that theReport
was m error.They
also had
examples
to show that the relation 4 was notgenerally
anti-symmetric.
I had observed that the relation (which contains ) was infact a total order for
snmplexes, cubes,
and otherexamples.
Sinceantisymmetry
of a was an
indispensable
tool in both[J]
and[S2],
Iput
aside my revision of[S2].
In mid
1990,
Ronnie Brown(Bangor)
informed me that Richard Steiner(Glasgow)
had some new results in this area. I did some work on theapproach
of
[ASn]
but was not able to use it to overcome theproblems
we wereexperiencing. Also, John
Power(Edinburgh)
was able to extend toarbitrary
dimensions his
geometric approach to pasting [Pw].
Richard Steiner visited
Macquarie University
for the month ofAugust.
This
provided
the motivation foragain concentrating
indepth
on thesubject.
Johnson,
Steiner and I came to the condusion that we should settle for the timebeing
on the case ofantisymmetry
of the relation .4 (afortiori
of the relation).
I returned to a revision and correction of
IS2]
and was amazed to find that I couldsimply
eliminate theoffending
axioms! Thepresent
paper is therefore a minor modification of theoriginal Report.
The resultant notion ofparity complex
is still not asgeneral
as one would like (since it assumesantisymmetric),
but we do obtain the cubes and the full descentta-category.
I am
grateful
to SamuelEilenberg,
MichaelJohnson, John
Power,Vaughan
Pratt, Richard Steiner for their various contributions to this work whichcertainly
go wellbeyond
thepoints
mentioned above.§1. Definitions, and the simplex example
Definition
Aparity complex
is agraded
settogether with,
for each elementxeC£
(n >0),
twodisjoint non-empty
finitesubsets x-,
x+cCn-1 subject
to Axioms 1, 2 and 3 which appear below aftersome
simple terminology
is introduced.Elements of x- are called
negative faces
of x, and those of x+ arecalled
positive faces
of x . It is alsoappropriate
to think of x as the name ofa rule which allows the
replacement
of xby
x+.Symbols £, ’1 , C
will be used to denotesigns -
or + when either is intended.Each subset S c C is
graded
viaSn
= S nCn .
The n-skeleton of S c C is definedby
Call S n-dimensional when it is
equal
to its n-skeleton. Thecomplement
of Sin C is denoted
by -iS.
Let S - denote the set of elements of C which occur asnegative
faces of somexeS,
andsimilarly
for S+. Insymbols,
Also let S+ denote the set of
negative
faces of elements of S which are notpositive
faces of any element of S. Soalso,
letWrite S1 T when
(S-nT-) u ( S +nT+)
= 0. In such notation weidentify
asingleton
S = (x) with its element.Definition
A subset S c C is called wellformed
whenSo
has at most oneelement, and,
for allx, yeSn (n > 0),
if x # y thenxly .
Write x y when
x+ny-=O.
Thisimplies
x =y since x-, x + were assumeddisjoint.
For any S cC,
let as denote thepreorder
obtained on Sas the reflexive transitive closure of the relation on S. Put = C. In
general,
as is contained in, but notequal
to, the restriction of to S.Whenever order
properties
of a subset S of C are referred to in thiswork,
itwill be
implicitly
understood that the order as is intended.Axiom 1
Axiom 2 x- and x+ are both well
formed.
Axiom
3 (a) x y ximplies
x = y .Example
A A 1-dimensionalparity complex
isprecisely
a directedgraph
with no circuits.
Example
B Thew-glob
is theparity complex
G definedby
and
Example C
Thew-simplex
is theparity complex
A described as follows.Let
An,
denote the set of (n+1 )-element subsets of the set N of natural numbers0, 1,
2, .... Eachx E An
is written as(xo,
x1’ ... ,xn)
where xoxi ... Xn. Let
xa
i denote the set obtained from xby deleting
xi . Takeac- to be the set of
xd
i with i odd and x + to be the set ofxa
i with i even.The facial identities
for
immediately imply
thefollowing
characterizationswhich make Axiom 1 clear.
Now consider Axiom 2. To see that x- is well
formed,
take y, z E x- with y= z andya1
=zdk. By symmetry
we may suppose i:g k.Then yi
= xi, zk = xk+1 ; soy = x g , z=xdk+1.
Soi , k+1
are odd. So i+k is odd. Soy 1 z .
A similar
argument applies
to x+.For Axiom 3 take x y
in An.
Observe thatxo S
yo . If xo = yo theny ao x d0 . Similarly,
if x. = y. thenxan a y a.. Using
the last sentence witha
simple
induction on n , we see that x y a ximplies
x = y . Thisgives
(a).For
(b),
suppose x =zai ,
y =z8; .
If i is oddand j
is even thenz at
x yzd0,
so(z0,
z2, z3, ... ,Zn+1) (Z1,
z2, zw ... ,Zzt+t),
whichimplies, by repeated
last-elementreznoval,
that zo zicontrary
to zo * z, . If i is evenand j
is odd thenzd n+1
x yzdn
for nodd,
andzar
x a yzOn
+1 forn even; each of these
implies, by repeated
first-elementremoval, that zn =
Zn+1, a contradiction.
Example
D Thisnon-example
isbasically given
(for other reasons)by
Power[Pw],
and shows that there are reasonable structures which do notsatisfy
ourAxiom 3. Put
We describe the faces of elements
xE C by writing
Putand
Notice that
CE f + n b-, nE b+ n c- ; vEc+nd- BE d+Qf -;
hence f b c df,
so Axiom 3 (a) does not hold. Axiom 3 (b) does not hold either.Proposition
1.1and
Proof
uer-n x++implies
there are vEx-, wE X+ such that u E v-, new+.So wv with vex- wex+ contradicts Axiom 3(b). This
gives
the firstequality;
the second is similar. So the unions in Axiom 1 aredisjoint;
the otherequalities
nowfollow.qed
To each
parity complex
C there is an associated chaincomplex
F offree abelian group,
Take Fn
to be the free abel ian group on the setCn
. ForxECn
weinterpret x-e F.
as the formal sum of its elements. Define d :F.
-
F 1B-1
to be thehomomorphism
such that d(x) = x+ - x-. Our Axioms ensurethat
Proposition
1.2 thtnProof
y E u- n x- +implies y EW+,
were So w u a v E x+, wEX-contrary
to Axiom
3(b).qed
This is an
appropriate point
to mentionduality.
For each subset K of N notcontaining 0,
t h e K -dual CICo f
C consists of the samegraded
set asC but with x- and x+
interchanged
whenxeo
for neK. We write xK forx as an element of
CK,
sothat,
forxECn,
xIC- is x-K whenne K,
andxK- is x;K when neK. As the axioms for a
parity complex
areself-dual,
the K-dual of a
parity complex
is aparity complex. Consequently,
once aproposition
isproved
for allparity complexes,
the dualpropositions automatically
hold.Proposition 1.3 If
x+ is a subsetof
awell-forrned
S c C then x+ is asegment of
S .Proof Suppose
w u 4s v with w, v E x+, so that there is y E w+ n tr.By Proposition
1.2, u- n x-+ = 0. So y K x-+. Now y E w+ c x++.By
Axiom I,y E x+-. So y E z- where z E x+. So y E u-n z-. But u, z E S well formed.
So u = z E
x+.qed
§2.
MovementThis section introduces the calculus of movement (which we
might
have called
"replacement"
or"surgery" ).
For theseresults,
none of the axiomsis
required.
Definition Suppose S, M, P
are subsets of C.Say
S moves M t o P whenand Denote this
by
s : M - P.Observe that any S moves S* to S+. Observe also that M and S determine P ; also S and P determine M.
However,
there need be no P towhich a
given
S moves agiven
M.Proposition
2.1 For subsetsS,
Mof C,
there exists a subset P such that Smoves M to
P if
andonly if
a nd
Proof
If P exists then andConversely,
if the two conditionshold,
define P as we are forced to, and calculateProposition
2.2S uppose
S moves A to B a nd X c A h a s S+QX = 0.If
Yn S- = Yn S+ = 0 then S moves (A u Y)n X to (B u Y)n,X.Proof Using
one direction ofProposition
2.1, we obtainand
and
using
the other directionyields
that S moves (A u Y) n X toProposition
2.3(Composition of moves) Suppose
S moves M to Pand T moves P to
Q. If
S-n T+ =0 then SuT moves M toQ.
Proof
and, since the
disjointness
condition is selfdual,
the other half isdual.qed Proposition
2.4(Decomposition of moves) Suppose
S = TuZ movesM t o P with Zt c P.
If
T 1 Z then there exists N such that T moves M to N and Z moves N to P.Proof
Since Z* c P and P nZ-c Pn S -=0,
the dual ofProposition
2.1yields
Z : N - P and N = (PuZ-)n-iZ+. Thedisjointness hypotheses imply
T£ = S£ n,Z£. ThenBy Proposition
2.1, T moves M to Iwhere the
penultimate step
usesZ - C S -=S +US+C MUS +
and M n Z + CMQS + =O. qed
Observe
that,
if S is well formed and is adisjoint
union of T andZ,
then we have T 1 Z as
required
in thehypothesis
of the aboveproposition.
§3. The (o-category of
aparity complex
Definitions
A cell of aparity complex
C is apair (M, P)
ofnon-empty
well-formed finite subsets M, P of C such that M and P both move M toP. The set of cells is denoted
by
O(C). The n-source andn-ta rget
of(M , P)
are defined
by
An ordered
pair
of cells(M, P), (N, Q)
is calledn-composable
whenin which case their
n-composite
is definedby
The
goal
of this section is to show that this defines anw-category
O(C). It is clear that we do obtain anw-category N(C)
of unrestrictedpairs (M ,
P) of finite subsets of Cusing
the aboveformulas
for source,target
andcomposition;
the axioms for anm-category [Sl]
are immediate. That D(C) is closed under the source andtarget operations
is clear. So all that remains is to show that O(C ) is closed under thecompositions.
Call
(M,P)E0(C)
an n-cell when MuP is n-dimensional. This is thesame as the
requirement
that the cell isequal
to its n-source (and/or its n-target).
Then we haveM.
=Pn .
Movement in an n-cell
(M ,
P)Call S c C
receptive when,
for all xEC and{E,N} = f-,+),
if xEnQXnn C S and Sn xee = O then SQXne = O.
A cell
(M, P)
is calledreceptive
when both M and P arereceptive.
Weshall
eventually
show that all cells arereceptive.
First we shall relatereceptivity
to movement.Proposition
3.1If
x+ moves M to P and M isreceptive
then x- movesM to P.
Proof
Since x+ moves M tosomething,
we have x +* c M and M n x++ =O(Proposition
2.1).By Proposition
1.1, x-* = x--QQ+- = x ++C M. Since M isreceptive,
MQX-+ = 0.Hence, by Proposition 2.1,
x- moves M toThis leads us to the
following
technical lemma.Lemma 3.2
Suppose
C is aparity complex
in which all cells arereceptive
and suppose
(M, P)
is an n-cellof
C.Suppose
X cCn+t
isfinite
and wellformed
with Xtc M.
( =P. ).
Put Y =(MnUX-)nX+.
Then:(a) Xt is a
segment of Mn ;
is a cell and is a cell.
Proof
Let m be thecardinality
of X. Theproof
involves threesteps.
Step 1.
(b)implies
(c).All movement conditions are covered
by
(b)except
for ’X moves Y toN§";
but this follows from the definition of Y and the calculation:Wellformedness is covered
by
(b)and
the wellformedness of X.Step 2.
(b)f o r
m = 1implies
(a) a n d (b) ingeneral.
The
proof
isby
induction on m.By hypothesis
andProposition 1.3,
wecan assume m > 1. Let x be a maximal element of X. Then x+c
Xt
cMn
and x+ is well formed (Axiom
2),
so (b) for m = 1gives
us a celland
x-nMn = O.
Since X is wellformed, so is Z = Xn rfx) and alsoBy induction, Zt
is asegment
ofNn,
is a cell for and
Now we prove (b).
By maximality
ofSo
So is a cell.
We still need to show
X- nMn
= 0. ButHence
Now we prove (a).
Suppose X+-
is not asegment
ofM n .
Then thereexist u , v E
X t
andnon-empty
S cMnnX +
=M1B n,X+ (using X- n Mn
= 0)such
that {u , v}US
is a maximal chain inMn
from u to v. Then S cMnQx+ CNn. By Proposition
1.3, either u or v is not in x+ .Suppose
v«x+ . Then
vE(X+ux-)Qx+=Z+
which is asegment
ofNn;
souE Z+.
SouE x+ . Let s be the first element of S. Then u s ; so Since
Mn
is wellfonned,
x+- n s- = 0. SoSo there exists we x- with w + n S-=0 . So w s
su(V) in N n and w ,
vE Z t contrary
to thesegment property
ofZ +.
Hence we must have VEX+ andu E x+. Then let s be the last element of S. Then s v ; so O=S+QV-C
s+ n x+ - . Since
Ng
is wellformed,
x++ n s+ = 0. SoSo there exists wE x- with s+ n w- * 0. So u
SU[u]
s w inN n
and u , wE Z +
contrary
to thesegment property
ofZ t.
SoX*
is asegment
ofMn.
Step 3.
(b) holdsfor
m = 1.Let x E
Cn+1
be the element of X ; so we have x + CMn
and Y =(MnUx-) n x+ = (Mn n x+) u x- .
What we need to prove is that(M(n-1)UY,
P (n-1) u Y) is a cell and x
n Mn
= O . We do thisby
induction on n. For n =0, M uP
= M 0
is asingleton.
So x+ =M0. By
Axiom 2, Y = x- is asingleton,
so that
(Y ,
Y) iscertainly
a0-cell,
and we have x- nMo
= 0by
Axiom 1.So suppose n > 0.
By Proposition
1.3, x + is asegment
ofMn,
so wecan write
Mn
as adisjoint
unionwhere S is an initial and T is a final
segment. By Proposition
2.4, we haveA, B c
Cl
such thatSince ( M, P ) is a cell,
tn-1 (M, P) = ( M (n-2) u P n-t ’ p(n-1»
is an (n-1 )-cell towhich, by
induction, we canapply Steps
1 and 2 because T satisfies the conditions of the Lemma. Thisgives
that(M(n-2)
uBuT ,P (n-t) uT)
is an n-cell, Tt is a
segment
ofPn-1,
andT-nPn-1=Ø.
Now(M(n-2)uB,P(n-2)uB)
is an (n-1 kell to
which, by induction,
we canapply Steps
1 and 2 because x+satisfies the conditions of the Lemma. This
gives
that(M(n-2) uAUX+, P(n-2) uBux+)
is ann-cell,
x-+ n x++ = x + t is asegment
of B, and x +- n B= 0. Now
(M(n-2)UA, P(n-2)UA)
is an (n-1 )-cell towhich, by
induction, wecan
apply Steps
1 and 2 because S satisfies the conditions of the Lemma. So(M(n-1) US, p(n-2) uAuS)
is an n-cell andSt
is asegment
ofMl.
In
particular, A,
B are well formed andreceptive
(since all cells arereceptive by hypothesis). By Proposition
3.1, x- moves A to B.We shall prove S- n x-+ = 0
by
induction on thecardinality
p of S.For p = 0, it is
clear,
so suppose p > 0. Assume it isfalse;
so there iswE S,
vE x- with w- n v+=O. Let u be maximal in S with w .4s u. But vwu and vE x’
imply
u+ n x+- = 0 (dual ofProposition
1.2).By Proposition
2.2,x+ moves A’= ( A Ur) nu+ to B’ = ( B ur ) n r u+. Since u is maximal in
S,
u+ CA.
So, by
induction on n,(M(n-2) uA’, P(n-2)
UA’) is a cell.By hypothesis
on
C,
we have that A’ isreceptive. By Proposition
3.1, x - moves A’ to B’.So x- +nu- c x-+Q A’)= 0. Hence w = u. So w E Snr{u} = S’ which moves
Mn-1
to A’. Since thecardinality
of S’ isp-1,
inductiongives
S’-n x-+ = 0.But this contradicts
wE S’,
vEx- with w- n v+= 0. So S- n x-+ = 0 asclaimed.
That S 1 x- follows from the calculations:
Proposition
2.3 nowgives
S u x- :Ml
- B. Now S is well formed as itis a subset of
Mn-1
and x- is well formedby
Axiom 2; so SIKimplies
S u x- is well formed.
Dually,
T+ n x- =0,
x- u T is wellformed,
and x- u T : A-
P n-1’
Since S is initial and T is final in the well formed set
Mn,
wehave S u T wpll formed and S- UT+ = O.
By Proposition
2.3 and theabove,
we have SUx U T = Y =( Mn Ux-)Qrx+
is well formed and movesMn-1
toPn-1.
So(M(n-1)UY, P(n-1) UY)
is a cell asrequired.
Alsosince
x--nS-=x-nT-=O.qex
Proposition
3.3 All cellsof
allparity complexes
arereceptive.
Proof
Sincereceptivity
is a condition whichapplies
dimensionby dimension,
it suffices to prove this for
parity complexes
of finite dimension n. We prove thisby
induction on n. Forparity complexes
of dimensions 0 and 1,receptivity
is an
empty
condition. Forcomplexes
of dimension 2, weonly
need to see thatsingletons (a)
arereceptive. Suppose x--nx+-C{a}
and(a)
n x++ = 0. Nowx-n x;- is
non-empty
since it contains thenegative
faces of minimal elementsof x-. So (a) = x--nx+-; so a E x+-. So aEx-+; so
{a} n x-+=
0.So, using duality
for the othercondition,
we haveproved (a) receptive.
Now
inductively
suppose that all cells arereceptive
inparity complexes
of dimension n. Let C be aparity complex
of dimension n+l. The the n-skeleton D of C is aparity complex
of dimension n and,,by induction,
the cells of D are
receptive.
Let(M, P)
be an (n-1)-cell of C. We must prove thatMn-1 = P n-l
isreceptive. Suppose
r-nx+-cP n-1
andP n-1nx++ =
0. Now
(M, P)
is an (n-1)-cell of D and X = x-cD.
is finite and well formed with X’ = x- n x+-cPn-1.
So the dual of Lemma 3.2applies
togive
X +
nP n-1 =
0. That is, x-+nP n-1
= 0.Using duality
for the other condition,we have
proved P-i recePtive.qed
Proposition 3.4 I f ( M, P )
is an n-cellof
C a nd zr. C..
with z- cPn-1
then
Proof. We prove it
by
induction on thecardinality
ofK.
IfMn = Pr
isempty
then the result is dear So supposeMn
isnon-empty.
AssumeMn-
n z+=O;
so there isw E Mn
with w- n z+ =O. So z w. Let u be maximal inK
with w u. Thenu+ c p n-1. By Proposition
2.4,A = MnQr{u}
movesMn-1
to B = (PUr) n r u+ .By
Lemma 3.2, we have a cell(M(n-2)UBU{u}
P(n-1)U{u}
). So (Mnr{u} , P(n-2)UBU(MnQr{u}))
is an n-cell. Now z- cp n-1
",u+ c: B (since z- n u+ = 0implies
u z whichimplies
u z w u,contrary
to Axiom 3 (a)).By induction, (MnQr (u)-
n z+ = 0.By
Lemma 3.2(dual), z-cpl implies z+nP n-1 = O;
soz+nu+ = O,
so z+c-iul. Also z- cB. So Lemma 3.2 (b) (dual)
gives
z+ n B = 0. So z +n ir = z+nu-n, u+ c z+ nB= 0. So we have the contradiction
Proposition
3.5Suppose (M, P), (N , Q)
are n-cells with a ndThen, Mn-
nNn+=
0 and the(n-1)-composite (M,
P) *n-1(N, Q)
is a cell.Proof
We prove thisby
induction on thecardinality
q ofNn
(=Qn).
It isclear for q = 0.
Suppose
q = 1, so thatNn = (z),
say. Then z-cNl = P n-1’ By Proposition 3.4, M n’
n z+ = 0.By
Lemma 3.2(b), Mn +
n z+ =Mn+ nrMn- n
z+CPn-1Qz+=O. By Proposition
2.1,Mn-Qz-CPn-1QMn-=O
SoMnu (z)
iswell formed.
Proposition
2.3gives flw (z) : Mn-1
-Ql.
So thecomposite (M, P)*n-1(N, Q)
is a cell.Now suppose q > 1. Let z be a minimal element of
Nn.
Then z-cNn-1
=Pn-1. By
Lemma 3.2(b), putting
we obtain cells
(N.t) u {z} , Q(n-2)UN’n-1U{Z}
and( N’, Q Ow-1) uN’n). By
theq = 1
case,( M u{z}, P(n-2)U(N’)n-1U{z}] )
is a cell andMn-
n z+ = 0.By
induction since the
cardinality
ofN’n
isq-1,
we obtain the celland But
z+) = O,
so we have atl that isrequired.qed
Theorem
3.6If
C is anyparity complex
then a(C) is anw-category.
Furthermore, if (M,P), (N,Q)
aren-composable
cells thenfor
allProof Suppose (M,P), (N,Q)
are both r-cells. For r n, the result is trivial. We use induction on r-n which we now assumepositive. By Propositions
3.5 and2.3,
we see thats1B+1(M,P) .1B Sn+1(N ,Q)
is an(n+1 )-cell,
and so are the other three
expressions
obtainedby replacing
either or boths ’s
by
t ’s; moreover,(M ku Pk) ’n ( NkuQk) + =O
for k = n+1. Define r-cells( M’ , P’ ), (N’,Q’)
to agree with( M, P), ( N , Q), respectively,
in dimensionsn and > n+1, while
M’ n+1= Mn+1 uN n+1’ P’ n+1 = P n+1 uNn+1= N’ n+1’ Q’ n+1= P n+1 UQn+1;
this uses
PrnpnRitinn ’2 ’2
with X = 0. Then(M’,P’) llvT’ Q’)
are (n+1)composable. By
induction,( M’, P’ ) *n+1(N’,Q’)
is a cell and(M’ku P’k) -n ( N’kU Q’k) + =O
for all k > n+1. Sincethe result is
proved.qed
4. Freeness
of the to-category
Definition
For eachxeCp’
two subsetsJ1(x), TT(X)CC(p)
areinductively
defined as follows. Put
for The
pair (u(x) ,
x(x)) is denotedby (x).
Theorem
4.1(Excision of extremals) Suppose (M , P)
is an n-cell andUE Mn
( =Pn ) is
such that(M , P) = (u).
Th en there exist n-cell s( N , Q) , ( L , R )
a n d m n such that( N , Q ), ( L , R )
are not m-cells andAlgorithm
Since(M,P) # (u),
there exists alargest
m such thatfor :
From the definition
of A
and TT, and from movementproperies
of a cell,Mm+1= u(u)m+1
+Mm+1 QPm+1’ p m+1 = x(U)m+1
+Mm+1 "p m+1 .
So
Mm+1 QPm+1
contains at least oneelement w,
say. Let x be a minimal element ofMm+1
which is less than w and let y be a maximal element ofMm+1
which isgreater
than w.By
Lemma 3.2(a),
either x or y is not inu(u)m+1 .
So either x or y is inMm+1QPm+1. By minimality
of x andmaximality
of y,and
If
xEMm+1QPm+1, by
Lemma 3.2, we have cells( N , Q ), ( L , R)
defined asfollows,
andthey clearly
have theirm-composite equal
to(M ,
P) :If
YEMm+1QP m+1’ by
Lemma 3.2, we have cells(N , Q), ( L, R)
defined as follows, and
they
tooclearly
have theirm-composite equal
to(M,P):
Definition
An elementXECP
is calledrelevant when x>
is a cell. This amounts tosaying
thatu(x)n
andx(x).
are well formed for 0 S np-1,
andfor
Call (x)
an atom when x is relevant.All elements of dimension 0 and 1 are relevant. An element of dimension 2 is relevant if and
only
if x-- n x+- and x-+ n x+ + aresingletons.
Remark
In manyexamples
we find that it is easy to characterize the setslt(x)
and TT(x) and to prove thefollowing stronger
forms of Axiom 1 and 2:(Rl)
u(x)- U
K(x)+ =u(x)+
u x(x)- andp(xh
n K(x)+ =;L(x)+
m K(xh =0;
(R2)
u(x)
and x(x) are well formed.Then it follows that every element of C is relevant. Such an
example
is A.To see
this,
define a subset u =(u0,
ul, ... ,un)
of N to bealternating
whenconsecutive elements u i , ui+1 have
opposite parity
(that is, one is even andone is odd). Call u
negative alternating
when uo isodd, positive alternating
when uo is even. Writexau
for the result ofdeleting
from xe Athose x r with rE u. Then it is easy to show
[Sl; Proposition 3.11
thatu(x) = { xdu:
u isnegative alternating}
andK(x) =
{ xdu:
u ispositive alternating ),
and that (Rl ) and (R2) hold. Hence, every element
of
A is relevant.Recall the
concept
of "freew-category"
from[Sl;
Section4].
Theorem
4.2 Thew-category
O(C) isfreely generated by
the atoms.Proof
Define the rank of a cell(M,P)
to be thecardinality
of the sub-parity complex
of Cgenerated by (M,P).
Excision of extremals (Theorem4.1)
produces
two cells of smaller rank than( M,
P).Repeated application
ofthat
algorithm
must therefore terminate. It canonly
terminate when each cell in thedecomposition
has the form(x).
Since thealgorithm produces
cells ateach
stage,
thesefinal (x)
must be atoms. Hence the atoms dogenerate.
Every decomposition
of an n-cell(M, P)
into atoms will include allthe
(u)
withUEMn
(=Pn)’
and these will be theonly
n-cells in thedecomposition
which are not (n-1)-cells.Consider the case where
Mn = {u}.
We shall examine theambiguity
ina
decomposition
This situation is
depicted by
thediagram
below, whereQn-2
= AUu+UBand
Ln-2
= A u u’t u B with the unionsdisjoint.
The second sentence of Theorem 3.6 tells us that
N n-t
must contain allXE Mn-1Qru-
for which there is a yEu- with x a y;similarly
forRn-1
wi tha reversed. These are the
o n l y compulsory
elements of these sets since,by
asequence of processes
represented by
thediagram
or the similar
diagram
with x on the Bside,
one can transfer all the other elements fromNn-1
toRn-1
and vice versa. These processesonly
involve themiddle-four-interchange
law for (n-1)-cells.Furthermore,
there is aunique
decomposition
of(M, P),
of the kind we areconsidering,
such that thecardinality
ofNn-t
is least:namely,
the one for whichNn-1
consists ofprecisely
itscompulsory
elements.Now consider a
general
n-cell(M,
P) withMr
ofcardinality greater
than 1. Then we have a
decomposition
of(M,
P) as... *
n1((N,Q) *n-,2u>*n-2(L,R))*n-1((N’,Q’)*n-2u’>*n-2(L’,R’))*n-1((N’
..in
which,
if u u’, the order of u and u’ cannot bechanged
even withalteration of the "whiskers"
(N,Q ), (L,R), (N’, Q’), ( L’, R’).
However, if u-Qu’+= 0 then we either have the situationdepicted
in thediagram
in which
and
or the similar situation with u, u’
interchanged;
so it ispossible
tointerchange
u, u’by appropriately altering
the whiskers.The
only possible
or de rchanges
in thedecomposition
are thereforeconsequences of the
n-category
axioms. Freenessfollows.qed
5.
Product and join
Definition The prod uct
C x D of twoparity complexes C, D
isgiven by
for xe CP, aEDq, eE f-, +),
whereE(p)E{-, +)
is c for p even and is not efor p odd. The usual
rebr*keGng associativity bisection respects dimension,
and
negative
andpositive
faces. Theproduct
ofparity complexes
is not aparity complex
ingeneral.
For