C OMPOSITIO M ATHEMATICA
P IOTR B LASS
Picard groups of Zariski surfaces
Compositio Mathematica, tome 54, n
o1 (1985), p. 3-36
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3
PICARD GROUPS OF ZARISKI SURFACES
Piotr Blass
To Kirsten
Acknowledgements
In addition to P. Deligne to whom the main idea of this paper is due 1 wish to thank Bill Fulton for his patient illumination of Deligne’s outline and for listening to my several early versions. With such two guides 1 could hardly go astray.
In addition I would like to acknowledge with pleasure conversations with J.S. Milne, A.
Fauntleroy, R. Donagi, R. Lazarsfeld, L. Tu, L. Ein, L. Illusie, M. Raynaud, J. Denef, John Milnor, S. Mori and Steve Yau.
1 was also greatly encouraged by frequent conversations with my former student and present collaborator Jeffrey Lang. He had solved several questions related to this paper.
1 am deeply grateful to the Institute for Advanced Study in Princeton for providing the perfect environment for this effort during the Algebraic Geometry Year 1981-82.
In particular 1 wish to thank C. Underwood, I. Gaskill, D. Phares, K. Lunetta, P.
Murray and Rene Baril for typing various parts of this manuscript.
© 1985 Martinus Nijhoff Publishers, Dordrecht. Printed in The Netherlands.
Introduction
This paper
originated
in thefollowing philosophical
framework.Inspired by
M. Noether’s theorem[4]
and facts aboutgeneric
doubleplanes
overC, [10],
as well asby
Rudakov’s andSafarevic’s computations
in char-acteristic two
[8]
we were led tosuspect
that thering k[x, y, z ]/( zP - f (x, y»
is a UFDprovided f
is asufficiently general polynomial
ofdegree
m. Herek = k,
characteristick = p > 5, m > 5,
say. The aboveconjecture
still remains open but here we offer a result that in ouropinion
renders itextremely probable,
to say theleast,
in the case when p divides m.We consider in the paper a
generic polynomial
with indeterminate coefficients.F = Y-Tij X’Yi,
where0 i + j p,
and thering
R =L[X,Y,Z]/(ZP - F), L = k(Tj)’
whereTij
arealgebraically indepen-
dent transcendentals over
k, deg F = p.
We show that R is a UFD. Thisis our main theorem
(MTH)
in itsalgebraic
form. In asubsequent papér
we
hope
to prove ouroriginal conjecture
and also togeneralize
the resultof this paper to
degrees of f 9L p.
The
proof given
here follows veryclosely
an outline shown to the authorby Deligne.
It isconceptually
akin to SGA VII exp XIX. A new featureis,
forexample,
DRL - MTH(see Chapter V).
Let us outline the
main
idea of theproof,
which issimple,
ifsomewhat lengthy
in detail. LetS = Proj L [ X, Y, Z, Zo ]/( Zp - F(X, Y, Zo». S-
hasN = p 2 - 3p
+ 3 rational doublepoints
oftype A p - l, (Sing S ).
Thegalois
group
G = Galtk ( Tj) : k (TJ) )
actson S and
itpermutes
the N ele-ments of
Sing
S. _Step
I is to show that G induces the fullsymmetric
group onSing
S.Step
II is to refine the above and toanalyze more closely
the action of G onPic 9 ( S
is the minimaldesingularization
ofS).
It turnsout
thatthere are elements of G which induce the
identity
onSing S
butnevertheless act
non-trivially
on certainexceptional
curves contained inS. See
Double Reversal Lemma(DRL)
and Gal B below.Step
III is to deduce from DRL the fact thatPic S
isgenerated by
theobvious curves,
namely
theexceptional
curvesfor É - S
and a veryample
curve on Spulled
back toS.
Step
IIIprovides
usalready
with theproof
of our main theorem in itsgeometric
form(MTHG).
Theequivalence
of thegeometric
form with thealgebraic
from( R
is aUFD)
follows from asimple
exact sequence whichwe had introduced in a
previous
paper[1],
see(0.5.1)
below.Finally,
let us remark that JeffLang
has proven a number of related results in his Ph.D. thesis[6].
His method was to use differentialequations
in characteristic p > 0.At a crucial
point
in ourproof
we use the fact thatPic( S )
has nop-torsion.
We hadconjectured it,
but the firstproof
is due to W.E.Lang
whose result we
quote
from[7].
It is not hard to extend our main theorem to the case where F is
replaced by
thepolynomial
not ofdegree p
but rather ofdegree pe, e
=1, 2,....
We leave this extension as an exercise to the reader. In a subse-quent
paper wehope,
among otherthings,
to examine the transition from"generic"
to"general"
and to prove ouroriginal conjecture
at least in thecase
when pl m.
*Chapter
I.Notation;
statement of the main theorem and of theprincipal
theorems and lemmas used in its
proof
0. Notation
(0.1)
k = k is analgebraically
closed field ofcharacteristic p >-
5.TiJ
are* See appendix to this paper, Comp. Math. 54 (1985) 37-40.
indeterminates
algebraically independent
overk,
0 i+ j p.
We have the natural
morphisms
If X ---> A is a
morphism
we denoteby Ex
the schemeEA
X X andby
7rx theprojection ’TTx: Ex
X.If U c A is open or closed ’TTu:
Eu --+
U has the abovemeaning
withrespect
to the inclusion map U -A. Weapply
the same convention tomaps D - E, D - A, X - E,
X - A.(0.2)
We willidentify
closedpoints
of A withpolynomials
ofdegree
p ink[ X, Y].
Thefollowing
subset of A will beimportant
to us, V,Acorresponding
topolynomials g E k [ X, Y ]
ofdegree
p such that the surface ZP = g has nosingularities
atinfinity.
It is not hard to prove that V is open and dense in A. This follows from thefollowing
fact:Let us write out
g( X, Y)
in terms ofhomogeneous parts:
Then, g E V
if andonly
if thesystem
ofequations gp _
1 =0, agp/ax
=0,
agplay
= 0 hasonly
the solution x =0, y
= 0.Further,
we define a subsetU c V as follows g E U if and
only
if g e V and g hasonly non-degener-
ate
singularities (i.e.,
gx =gy
= 0implies
hessian ofg # 0).
We will show below that U is open and densein V,
see(3.1.3).
(0.3)
In this paper we willconstantly
discuss analgebraic
surface overL. Let us fix once and for all some notation relative to that surface.
R =
L [ X, Y, Z ]/( Zp - F( X, Y )). ,S affine
orS aff
=Spec( L [ X, Y, Z] /( ZP -
F(X, Y»)
where F is as above.S aff
=Spec
R. S =Proj(L[X,Y, Z, Zo ]/( Zp - F( X, Y, Zo )))
whereF(X, Y, Zo )
is Fhomogenized (some-
times
we will writeF( X, Y, Xo )). n:s --> S
a minimaldesingularization
ofS over L.
PL
denotes theprojective
n-space overL.
The
following
facts can be shown aboutS’aff
and S. There is a naturalprojection,
a finite map:We will denote
by
1 the element of Pic Sgiven by:
S has a set of isolated
singularities
denotedSing ( S ).
One can show that:Thus
Also,
all thesingularities
are rational doublepoints
oftype A p _ 1,
see(3.1.14). Further,
the number ofsingularities
isp2 - 3p
+3,
see(3.1.12).
The elements of
Sing S
will be denotedby
Greek letters a,/3,
y, etc. Ifwe need to write out their coordinates in
AL we
will writea = ( al, a2, a3 ),
etc. In
particular,
we define(0.4)
Thefollowing
facts about the minimal resolution mapn: S -- S
are well
known, see [1] Section
1.Let a E
Sing S,
thenn -1 ( « )
consists of a tree of( p - 1)
rationalcurves over L with intersection matrix
(in
PicS )
The tree can be
pictured
as follows:We wish to
emphasize
thefollowing
subtlepoint
which is ofkey importance
in this paper. There are twopossible
natural choices ofordering
the curves of the tree(from
left toright
or fromright
toleft).
We choose from the outset one orientation for each
singularity
aESing S
and we number the curves
accordingly.
Thus the tree will now be labelledTa
stands for the ordered(tree)
sequenceCl C2 , ... , Cp 1. ToPP
standsfor
Cpa-l’ Cpa-2’...’ Cr.
-For each ae
Sing
S we now define aspecial
element ofPic S
and
Da
has thefollowing properties.
First ofall, Da. c;a
=O( p )
for allj,
1 j p -
1. Also(0.5)
We will denoteby
the
subgroup generated by
1 and theÇ"l
a ESing (S),
1j
p - 1.There is an intersection form on Pic
S,
we denote itby
A .B, A,
BE PicS.
It can be shown that 1.1 =
l’
= p.Also,
we have the exact sequenceAnd Cl R is a finite
elementary
p group, see[6]
or[9].
It was shownby
W.E.
Lang
thatPic( S )
has no torsion[7].
(0.6)
Let X be a scheme(noetherian), Et(X)
thecategory
of finite étalecoverings
of X.Let R be an
algebraically
closed field b:Spec 9 - X,
ageometric point
of X. Let
Y E Et( X ).
Fbx ( y)
is the set ofliftings
If W ---> X is a
morphism,
weget
the basechange
functor Et X - Et Wdenoted R W
orjust
R.If
X,
Y are schemes we denoteby X
U Y thedisjoint
union of X and Y.(0.7)
In thefollowing
definition theground
field is assumedalgebrai- cally
closed of characteristics # 2.A,
B are smoothcurves, B irreducible,
7T finite.03C0’
DEFINITION : A --- > B is called very
simple
if there exists apoint q
E A with7r(q)
= q and such thate( q)
= 2(ramification
istwo);
further if B 0 = B-
( q ) ,
A ° =7T-I( B 0),
then A ° - B ° is finite andétale;
also qr is étaleonA-
{q}.
(0.8)
DEFINITION:S,
T two finite sets. m: S - T a two-to-one and ontomapping.
We call thefollowing
commmutativediagram
a doubleflip:
where as is an
automorphism
of S such that there are two elementsA,
B E T with
preimages {A1,A2}, {B1,B2}
in S and such that:Also
a s 1 S - {AI,A2,BI,B2}
is theidentity. (Intuitively
we think of T as the set ofposition
of a certain number ofcoins;
each coin has " heads"and " tails",
hence the two-to-one map m: S - T. A "doubleflip"
corresponds
toturning
overexactly
two coins withoutaltering
the orderof the
coins.)
1. Statement
of principal
resultsOur Main Theorem
(MTH)
is this:MAIN THEOREM
( MTH ) (1.1): R is a unique factorization
domain.We will restate the theorem and in fact prove it in its
geometric
form.MAIN THEOREM
(GEOMETRIC FORM) (MTHG) (1.2): Pic(,S ) = PicOb(S).
REMARK: Since there is no torsion we
will,
infact,
prove pPic(S) =
p
Pic°b( S ).
The
equivalence
of MTH and MTHG is an immediate consequence of the exact sequence(0.5.1).
We will deduce MTHG from thefollowing
theorems to which we
give descriptive
namesG1, G2, G2’,
DRL(double reversal lemma).
Here are the statements:
THEOREM Gl
(1.3):
G =Gal(k(1;j): k ( T ij ))
acts onSing( S )
as thefull
symmetric
group.THEOREM G2
(1.4):
There exists a 0 E G such that a induces theidentity
onSing
S butfor
somepair of singularities
a,/3
ESing
SJ(fl) =
-
HaQ( Hb)= - H03B2 and for all P =;É y =t: a, -y EE Sing S a (JH HY.
THEOREM G2’
(1.5):
For everypair of singularities
a,/3
ESing
S thereexists ao E G such that a induces the
identity
onSing
S butQ( Ha ) _
-
Ha Q ( Hb ) _ - H03B2
andQ ( HY ) = HY for03B2 #
Y # a y ESing
S.DRL
(DOUBLE
REVERSALLEMMA) (1.6):
For everypair of singularities
a,/3, a *,8
inSing
S there is an element a E G such that the inducedisometry i ( Q ) of Pic( S )
preservespic,b(g )
andsatisfies: i(o)(Da)
=D;P, i ( Q )( D03B2 )
= D03B2oP, i(o)(l)=
1 andfor
all Y ESing
S with a =1= y 4=8
we havei(o)(Dy) D,,.
Thelogical
structureof
theproof
will be asfollows:
The
implication Gl,
G2 => G2’ is asimple
exercise and will not bedescribed. The
implication
MTHG MTH has been indicated above.Thus,
our paper consists inproving Gl, G2,
seeChapter
IV.Further,
inshowing
G2’ =>DRL,
this will be sketched at the end ofChapter
IVbelow,
andfinally
we will prove theimplication
DRL -MTHG,
inChapter
V.Chapter
II. Preliminaries1. Fundamental group
facts (see
SGAI, Reference [3J)
Let i : Y - X be a
morphism
oflocally
neotherian connected(regular)
schemes. Let b :
Spec 03A9 ->
y be ageometric point
of Y. Let us abusenotation and denote
by b
also thecorresponding geometric point
of X.(2.1.0)
We recall the definition of the inducedhomomorphism:
Now
By
SGAI,
p. 142 we have theisomorphism
of functors:we define 8 =
i *(a) by
thediagram:
PROPOSITION
(2.1.1) If
W EEt(X)
is irreducible then7TI(X, b)
acts transi-tively
onFbx(W) for
any basepoint
b in X.PROOF: W is
connected,
soProposition
1 follows from SGA1, [3],
p. 140.PROPOSITION
(2.1.2):
Assume W EEt(X)
irreducible and thatR ( W )
=Wy decomposes Wy
=s(Y)
U T where s: Y -Wy
is a section and T irreduci-ble. Then
for
any basepoint
b E X the actionof TI1 (X, b)
onFb ( W )
istransitive and twice transitive.
PROOF :
Transitivity
was shown above. Also the statement isindependent
of base
point (by
SGAI ).
So choose the basepoint
to be in Y.where
F Y( s ( Y ))
is the one elementset {A}.
Now
’03C0}(Y, b )
acts onFbY(Wy),
it fixes A and actstransitively
onFbY(T )
since T isirreducible,
see[3],
p. 140. Now the identificationF Y( W ) = F bY( WY )
shows that for some elementA
1 ofF Y( X ), 03C01 ( X, b )
acts on
FbY(W)
so that the stabilizer ofA
1 actstransitively
on thecomplement of A1
inFbY(W). This, together
withtransitivity,
establishestwice
transitivity. Q.E.D.
PROPOSITION
(2.1.3):
LetW E Et(X), R ( W ) = WY E Et( Y ),
let b be abase point in
Y.Suppose
that the actionof 03C01 (Y, b )
onF Y( WY )
includes atransposition,
then so does the actionof 03C01 (X, b )
onFbY(W). Also, if b is
any other base
point in X
notnecessarily in Y,
the actionof ’03C01 (X, b )
onFbx(W)
also includes atransposition.
PROOF: Follows
immediately
from the definition of the induced homo-morphism ’03C01(Y, b ) - ’03C01 (X, b )
and the fact that the functorsFb Y, Fb
areisomorphic.
PROPOSITION
(2.1.4) : Let V, W E Et( X ),
m : V - W étalecovering of degree
two,m y:
Vy - WY
the inducedcovering.
Suppose
that there is a a E 03C01( Y, b )
such that thediagram
is a double
flip.
Then also thediagram
is a double
flip.
PROOF : Follows from the definition of ô and a
diagram
chase.REMARK
(2.1.4.1):
Under the aboveassumptions
for any basepoint
b inX the the action of
7T1 (X, b)
onFbz(V) - Fb ( W )
includes a doubleflip.
PROOF:
Diagram
chaseusing
the fact thatFb
andFb
areisomorphic
functors.
2. Preliminaries on curves
THEOREM
CI(2.2.1) :
Let A - B be a verysimple covering,
then the actionof 7TI (B 0 , b )
onFb (A 0)
contains atransposition.
THEOREM C2
(2.2.2):
Let D--->A -- > B be two verysimple coverings.
Assume that
q
ED, q
EA,
q E B are such thate,,(q)
=2, e’TT( q)
=2,
° gr°
e1T( q)
=2, ,p (q)
=q, 7T( q) = q.
Let D ° -- > A 0 -- > B 0 be the induced étalecoverings
where B 0 =B - {q},
A 0 =17 - 1 (B ° ),
D 0= ~ - 1 ( B ° ).
Thenfor
any base
point
b in B 0 the actionof
’!Tl( B ° , b )
on thediagram Fb ( D ° )
-Fb ( A ° )
includes a doubleflip.
PROOF OF THEOREM Cl : We denote
f :
A -B, q
EA, f ( q )
= q,e f ( q )
= 2.the induced étale cover.
Let
(9q
be the localring of q
in B.____ sep.
Let êq
be the henselization of(9q.
We may takeiflq C k( B 0 )sep.
.Consider the cartesian
diagram
If
K
is the field of fractions ofâq
weget
the induceddiagram
Now
Spec mqXBover q Z
S USpec (O9,(-t)
where S is a union of sectionsover
Spec (9.,
thus a trivialcovering
and t is auniformizing
parameter in(9,.
This follows fromelementary theory
of henselianrings. Correspond- ingly,
we can write the seconddiagram
as:where
again S
is a union of severalcopies
ofSpec K.
Now we have
Spec k ( B ° ) - Spec K Spec k ( B ° ) - B ° ).
Thus weget
ageometric point b
ofSpec K
and thecorresponding geometric point bl
1 of BO.’1T}(SpecK,b):::=Gal(k(AO): K )
acts onFSCec Ï (5’U
Spec K(Ii»
and it is clear that it induced atransposition. Consequently,
’!Tl (B ° , bl)
induces atransposition
inFt 1 0 ( A ° ) by
our discussion of the fundamental group(2.1.3).
PROOF oF THEOREM C2: Choose a henselization
and consider the base
change.
We get the leftmost column from
elementary properties
of henselianrings.
S is a union of severalcopies
ofSpec dq,
thus a trivialcovering.
Similarly, SI and S2
are trivialcoverings
of S.We get the induced
diagram, where k
is the field of fractions ofCq.
Choose an
embedding K c K ( B ° ) .
This defines ageometric point b
ofSpec k (and bi
ofB ° ). By [3],
prop.8.1,
p.143,
we have7r,(Spec k,
b )
=Gal( k (B 0): K )
and this group acts on4 4
and we get a double
flip by simple
Galoistheory (just
sendVi to 2013 V.).
If
bl
is a thecorresponding
basepoint
of B ° we conclude that the’TrI
( B °, b 1 )
actionon Fb1 (D 0) Fb1 (A 0)
includes a doubleflip (from
ourdiscussion of the fundamental group
(2.1.4)).
3.
Irreducibility of
the hessianWe will need the
following proposition
in order to prove that D is irreducible and normal and cp: D - E is finite. A relatedquestion
isdiscussed in
Coolidge’s
book about curves[Treatise
onAlgebraic
PlaneCurves, Dover],
p. 153.PROPOSITION
(2.3.1 ) : Fxx Fy y - ( Fx y ) 2 = H( F ) is
irreducible inR 1 =
k[T, X,Y].
LEMMA
(2.3.2): Fxx is
irreducible and so isFyy.
.PROOF :
Fxx
= 2T20
+Sxx
whereSxx
does not involveT20. RI/(Fxx):’:= R 2;
R 2
=R 1 /( T2o ), a
domain.Q.E.D.
LEMMA
(2.3.3.) : Fy y
does not divideH( F ).
PROOF :
Fy y
contains the term2 To2
and( Fx y ) 2
does not containT02.
COROLLARY
(2.3.4) :
Let V:H( F )
= 0 so thatk[V] = R 1 /H( F ) then Fy y is
not a zero divisor in
k [ h ].
PROOF : Obvious.
COROLLARY
(2.3.5): k[V] injecte
into the localizationk [ h ][ 1 /Fy y ]
LEMMA 2.3.6:
k [ T ] [ 1 /Fy y ] is a
domainePROOF : Define a
homomorphism
h ofR1
intoR1 by h ( X ) = X, h ( Y ) = Y,
h(Tj) = Tj
for(i,j) =1= (2,0)
andh(T2o) = H(F) = T2o Fyy + SxXFyy -
( Fx y )2.
Note thatFyy, Sxx, FX y
do not involveT20.
Alsoh ( Fyy ) = Fyy. ,h
induces an
injective
map h :R 1 /( T2o ) - R 1 /( H( F ))
which takes the classof
Fy y
to the class ofFyy.
We thereforeget
the induced map:which is still
injective.
But now theimage
ofh includes
notonly Ti., X,
Y for
(i,j) =1= (2,0)
andsxx Fyy - (Fxy)2
hence alsoT2o Fyy
but alsoT20
since we have inverted
Fyy
in theimage.
Thushl
is anisomorphism.
Thisproves
Proposition (2.31). Q.E.D.
4.
Non-singularity of
S atinfinity
For the sake of
completeness
we also include asimple
lemma about thesingularities
of S.LEMMA
(2.4.1):
There are nosingularities of
S in S - S.PROOF: At such a
singular point
we would have:but it is clear that the
only
common solution in L is X = Y = 0 but then also Z = 0 and that does not define apoint
of theprojective
space overL.
Q.E.D.
Chapter
III.Geometry
of themappings
(3.1 )
GeneralitiesThe main results of this
chapter
are theorem(3.2.12) (existence
of aspecial pencil)
and twicetransitivity
result(3.3.1).
In order to prove theseresults,
we have to established certain basic facts about the maps 77-:E - A and cp: D 2013 E. These facts should also be of some
independent
interest in the
theory
of Zariski Surfaces. Theorem(3.2.12)
will becombined with basic facts about the fundamental group to prove the crucial Theorem G2
(1.4).
The twicetransitivity
result will be essential inproving
thetwo-transitivity
in Theorem Gl(1.3).
PROPOSITION
(3.1.1):
E issmooth, irreducible; in fact
E isisomorphic to an affine
space over kof
dimensionequal to
the dimensionof
A.PROOF : If we write out
Fx and Fy
weeasily
see that:is
isomorphic
toREMARK
(3.1.1.1.):
the above observation is due to S. Mori. We will usehis idea
again
in(3.2.10)
below.REMARK
(3.1.1.2):
qr has at least one finite fiber.PROOF: This follows from
example (3.1.6)
below.COROLLARY
(3.1.1.3):
v isdominating
andgenerically finite.
Thefield
extension k
( A )
ck ( E )
is afinite algebraic
extension.PROOF: This follows from the above remark and
[5].
PROPOSITION
(3.1.2):
7rv:Ev --+
V is afinite
map.PROOF: It is
enough
to show that ff v isquasi-finite
andprojective ([5],
exercise
11.2,
p.280).
(i)
uv isquasi-finite.
If g E v then the surface ZP = g canonly
havefinitely
manysingularities. Otherwise,
there would be asingularity
atinfinity
which contradicts the definition of V.(ii)
7rv isprojective.
We have the commutativediagram:
where
S v
is defined inp3 v by
ZP -F(X, Y, Zo )
andSing(Sv)
is definedby
the abovehomogeneous polynomial
and itspartials
with respect toX, Y, Z, Zo.
The middle vertical arrowcorresponds
toprojecting
from thepoint
atinfinity
onthe
Zaxis
in each fiber. The mapEv ---> P’
isprojective
becauseSing(Sv) c Sv
is closed andEv
is the reducedimage
ofSing(Sv),
thus closed inp2 .
ThereforeE v -
V isprojective. Q.E.D.
COROLLARY
(3.1.3):
U c V is open and dense. ’lTu:Eu -
U is étale.PROOF:
Ev
is open and dense in E. Thepolynomial H(F)
is notidentically
zero on E.Thus,
it defines a proper closed subschemeove Ev.
Since 77V isfinite, 77v(,uv)
is a proper and closed subset of V.Now U =
V - 7rv (av).
This shows that U is open and dense in V. The fact that -7u is étale follows from the Jacobian criterion.COROLLARY
(3.1.4):
For any basepoint
b in U the actionof 77,(U, b)
onFb ( Eu) is
transitive.PROOF:
Eu
is open and dense in E and thus it is irreducible and therefore connected. Thecorollary
follows now from SGA1, [3],
p. 140.PROPOSITION
(3.1.5):
D is irreducible and normal. ç: D - E isfinite of degree
two.PROOF: This follows from the
irreducibility
of thepolynomial H( F )
inthe
ring k[E] == k[Too,T20,TII,Tol’’’.. X, Y],
see(2.3.1)
and[5],
p.147,
exercise 6.4.Next we
given
anexample
of apoint
T E U.By counting
thepoints
in’TT - 1 ( ’T)
we will find thedegree
of gr to bep 2 - 3 p
+ 3. This result wasoriginally
provenby
J.Sturnfield,
see[1].
EXAMPLE
(3.1.6):
For almost every choice of A E k thepolynomial h(x,y)=xy+Axp-l+yp-]+xyp-l+yxp-]
1 defines apoint
T E U.Further we have that the
cardinality of ’TT-I( ’T) is p2 - 3 p + 3.
Theproof
will follow from the
following computational
lemmas:PROOF OF EXAMPLE
(3.1.6)
LEMMA
(3.1.7):
For all but
finitely
many choices of A E k thesystem
ofequations
has no solution.
LEMMA
(3.1.8):
For all butfinitely
many A E K the intersection numberof
gx = 0 and
gy
= 0 atinfinity
is p - 2.PROOF OF LEMMA
(3.1.7):
Consider thesystem:
x = 0
implies y
= 0 but(x, y) = (0, 0)
is not a solution. Assume x =1=0,
and rewrite the last
equation,
eliminate Ax p - 2
It is
enough
to show thatand
have no common
component. (x
= 0 is excludedagain).
Weget finitely
many values from A from the first
equation
once this is established.At common
points
atinfinity
of the two curvesIf x = 0 then
since
p =A
3. Thisgives
Thus no
point
with x = 0. If x =1= 0 thenSet
T = y/x
so thatT p - 2
= 1. The secondequation gives
so that
so that
which
gives
2 = 1. Contradiction.Therefore the two curves have no common
point
atinfinity
andthey
cannot have a common
component. Q.E.D. (for
lemma5.1.).
PROOF OF
(3.1.8):
Thisproof
is based on an idea of Jim Sturnfield. At a commonpoint
atinfinity
we must have:Thus there are p - 2 common
points.
Homogenize
Set
Set
Rewrite
as
The
tangent
line at W =0, x
= T isSimilarly
for the second curveand we consider W = 0. We obtain:
and we have :
We
compute
thetangent
line at W =0,
x = T. Fromwe obtain:
or
Finally
defines the
tangent
line. We compare the two obtainedtangent
ines:Suppose
So that 2 + 2 TA = 0. But choose A so that
A =1= - -
for every T such thatT
T p - 2
= 1. Then weget
a contradiction. Thus for all butfinitely
many A E k weget
no commontangent, Q.E.D.
LEMMA
(3.1.9):
For all butfinitely
many choicesof
A E k we have g E V.PROOF is
by computation. By (0.2)
we must consider thesystem,
Suppose
that there is a solution with x #0,
thenand
Set
T = y/x
so thatBut A TP - 1 = - 1
and we obtainContradiction for almost every choice of A.
Q.E.D.
COROLLARY
(3.1.10) :
There exists apoint
g E V such that’TT-I(g)
consistsof p 2 - 3 p
+ 3unramified points ( at
which u isétale) deg
r =p 2 - 3 p
+ 3.COROLLARY
(3.1.10.1):
’TT isgenerically
étale.COROLLARY
(3.1.10.2) :
U is open and dense in A(and
inV).
COROLLARY
(3.1.11 ) :
Thedegree of
thefield
extensionk(A)
ck(E)
isp2 - 3p + 3.
COROLLARY
(3.1.12) :
Thesurface saff
hasp 2 - 3p
+ 3singularities
atfinite
distance.PROOF :
Sing
S =Fbu(Eu)
where b: speck U -- Spec k ( U ) - Spec
U.Now the
cardinality
ofFbu(Eu)
isequal
to thedegree
of ’TT u:Eu --->
U andthat is
p 2 - 3p
+ 3.Q.E.D.
COROLLARY
(3.1.13):
The mapDu - Eu
isfinite
and étaleof degree
two.The
degree of
thefield
extensionPROOF: Follows from definition of
D,
and(3.1.11)
above.COROLLARY
(3.1.14):
All thesingularities of
S arenon-degenerate.
PROOF: The maps
Du - Eu --->
U are étalecoverings.
Let b :Speck U
U be as above
(3.1.12).
Now we have m :Fb (Du) - Fb (Eu)
and this map is two-to-one and onto. ButFb(D,) =
set ofpairs
Furthermore, Fb(Eu) = Sing S,
and mcorresponds
toprojecting a,t>
toa.
By
acounting argument
we must have all t = 0 so allHa =1=
0.Q.E.D.
(3.2)
Existenceof
aspecial pencil
In order to prove the main result of this section Theorem
(3.2.12)
belowour next
objective
is to find apoint q E V -
U such that thecardinality
of
’TT-I(q)
=(deg r) - 1.
We will do thisby by by producing
anexplicit example
of such a q.EXAMPLE
(3.2.1):
Construction of theSpecial Polynomial (point
ofV)
q.The
point q
will be constructed as follows:where B = + 1
if p #
13 and B = -1 if p = 13. A E k can be chosen sothat the
cardinality
of’TT-I(q) = (deg ’TT) -1, q E V.
Also the surface Zp = g has(deg ’TT) - 1
nondegenerate singularities
and onedegenerate singularity (in
other wordsH( F )
isequal
to zero atexactly
onepoint
of’TT-l( q ».
LEMMA
(3.2.2): q e V for
almost every choiceof
A E k.PROOF: Identical to the
proof
of 5.3.LEMMA
(3.2.3):
For almost every A E k the systemof equations ( * * )
belowonly
has the solutions(0, 0, t ),
t E kPROOF: Consists of the
following computation:
(0, 0, t )
isalways
a root. Also x =0 => y
= 0.Let us find all solutions with x =1= 0. We eliminate A from the first two
equations
as follows:or
And we obtain:
We wish to show that the curves
and
have
only finitely
manypoints
in common.Again
x = 0implies y
= 0 soenough
to prove this for x # 0.LEMMA
(3.2.4):
The curvegy
= 0 is smooth and irreducible.PROOF: Consider the
projective
curve(closure
ofgy
=0)
At
points
atinfinity, i.e.,
where W =0,
we have:or if
at
infinity implies
Thus,
there are nosingularities
atinfinity.
Wedehomogenize:
and check for
singularities
at finite distance:First of all x = 0 is
impossible if y
= 0 then x =0,
contradiction. Assumey #
0 and transformx = 0 is excluded. We obtain
Now we must have
If
P =1=
13 then B = 1by
ourassumption
and 13 = 0 a contradiction. If p = 13 then B= -1, - 9 = - 4
or5 = 0, again
a contradiction.Q.E.D. (for
lemma3.2.4).
In order to
complete
theproof
of(3.2.3)
it isenough
to find onepoint
on the curve
gy
= 0 which is not on the first one in the system( *
** ) (3.2.3.2).
Take a Doint with
and with
so that
The first curve
gives
or
since
Thus
contradiction since p > 5.
COROLLARY
(3.2.5):
For almost every A E k( * * ) (3.2.3.1)
hasonly
the(0, 0)
solution in(x, y).
LEMMA
(3.2.6):
For almost every choiceof
A E k the intersection numberof
gx = 0 and
gy
= 0 at thepoints
atinfinity
is p - 2.PROOF:
Analogous
to(3.1.8).
We omit it.LEMMA
(3.2.7): Assumptions
as in(3.2.6).
The intersection number at theorigin
is two.PROOF :
Simple computation using p =1=
2 andp =1=
3(omitted).
COROLLARY
(3.2.8):
Thecardinality of u - 1 (q)
isp 2 - 3 p
+ 2 =degff -
1.The hessian is non-zero at all but one
point of ’TT-I( q).
It is zero at onepoint
which we call
q, q
E’TT-I( q).
PROOF: The total intersection number of the curves gx =
0, gy
= 0 is( p - 1)2 by
Bezout’s theorem. The number of intersections at finite distance is( p - 1 ) 2 - ( p - 2) -1 by
the above. Thus itis p 2 - 3 p + 2.
Also the local intersection number is
equal
to one at everypoint
wherethe hessian is non-zero.
Q.E.D.
PROPOSITION
(3.2.9):
Let A be as inexample (3.2.1).
Let L be the line in A =Spec k [ Tij ] corresponding
topolynomials of
theform :
then 7rL:
EL - L, EL
is an irreducible and smooth curve. There isexactly
one
ramified point lying
over q, let us call itq
withramification
indexe(q)
= 2.LEMMA
(3.2.10): EL
is smooth and irreducible.PROOF :
Now we have shown above that the last curve is smooth and
irreducible,
see
(3.2.4). EL
L isisomorphic
to theprojection
to theSpec k[À] axis
of the space curve defined in
Spec k[x,y,À] by
the twoequations:
q
corresponds
to thepoint À
= 0. The matrix ofpartials
withrespect
to x,y, À is:
or
We have shown above that if
for every
point
of the space curveexcept À
= x = y = 0.Thus,
all of thosepoints
are smooth.Also, À
= x = y =0,
thepoint q,
is smooth and x is auniformizing parameter
atq. Finally,
we see that the hessian has asimple
zero
at q
ande ( q )
= 2. All this follows from the matrix.Similarly,
we consider the mapDL
isisomorphic
to the curve in4-space Spec k[x,y,À,W] ]
The Jacobian matrix is:
all
points
with W = 0 areclearly
smooth.... If À = 0 and W = 0 then we must be at thepoint = given by x = y = À = W = 0 by (3.2.9).
Wecompute
matrix there:it has rank
3,
thus thepoint
isnon-singular.
W is a
uniforming parameter at q
andgxxgyy - (gXy)2
=W2
has azero of order two at
q.
From this we see that theprojection
’TTL 0~L : DL --->
L( L corresponds
to theSpec ]A; [À] axis)
has ramificationequal
tofour at
q.
AlsocfL (q) = q
ande"’L (q)
=2, therefore, e,,(q)
= 2.LEMMA
(3.2.11): DL is
Irreducible.PROOF:
(PL: DL ---> EL
is finite andgenerically
two to one. ThusDL
may have at most twocomponents.
LetCL
be thecomponent
which containsq. Now q
is a smoothpoint
ofCL
ande(q)
= 2.Also, CL - EL
is a finitemap
(proper
andquasi finite),
thusCL - EL
must havedegree
two.Therefore, CL
=DL (inclusion
of a closed subscheme is proper -[5].
p.102)
48(a).
The
following
theorem summarizes what we have shown:THEOREM
(3.2.12) ( Existence of
aSpecial Pencil) :
There exists apoint
inq E h - U and a smooth rational curve L closed in V such that q E L and
Lu
=Ln U is open and dense in L and closed in
U.Further,
letL1 be
theopen subset
of
Ldefined by LI
=LuU{ q}.
We have the inducedcoverings:
are very