DE L ’U NIVERSITÉ DE C LERMONT -F ERRAND 2 Série Probabilités et applications
M
ARIUSZL
EMANCZYKThe centralizer of Morse shifts
Annales scientifiques de l’Université de Clermont-Ferrand 2, tome 87, sérieProbabilités et applications, no4 (1985), p. 43-56
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THE CENTRALIZER OF MORSE SHIFTS
Mariusz LEMANCZYK
Abstraot We examine the centralizer of Morse shifts.
1/
Let0 1 xab°x b x :::
be aregular
Morse sequenoe andI b(,1
r.Then
a/ C(T) = {Tioj :
where T is the shift and 0 is the mirror map.b/
There are no roots of T:2/
There are Morse shifts with uncountable centralizer:Let
’Jttr2t! be
the class of allergodic automorphisms T with
in the
point speotrum
of r : We introduce somenumber
d t
( "1:) for ieand
prove that if . cothen t is ooalescent.
Introduction
Let(X, B, 03BC)
be aLebesgue
space and T aninvertible transformation of
(X.~,~) . By C(T)
we mean theoentralizer of T i.e. the group of all
automorphisms
S ofwith TS-ST; The centralizer is an
important
invariant inergodio theory.
It can statesome ergodio properties
of T. Inparticular knowing C (T~
we canusually
answer whether T has roots or Tis embeddable in measurable flows.
Moreover,
if;~~P is a finitegene rat or
of T thenSP, S e- C (T) -
are theonly generators
wi ththe same finite distributions as P.
In the
present
paper weinvestigate
centralizers of Morse shifts: These shiftsplay
animportant
role inergodic theory
in
providing
concreteexamples,of dynamical systems
withrequired properties / [7],
II r 151 /.
There are some direct reasons to
compute
the oentralizers of Morse shifts: As weshall
see inSection
5 theproperty
to have an uncountable oentralizer is a
typical
one in the class of allautomorphisms acting’in
a fixedLebesgue
apace. On the other handexamples
ofautomorphisms
with the trivial centralizer i:e:i e. Zare well-known / mixing
rankone)
minimal self-joining automorphisms [8][20]/.
Our main theorem/
Theorem1 /’ provides
alarge
olass ofautomorphisms
withoountsble but not trivial oentralizer
Consider Morse
dynamioal systems
asexamples
intopologioal dynamic / 1461 ~’:
We see that theirtopological properties
areusually common
for all Morsesequences / f3~ ~ /:
Inparticular
the group of all
homeomorphisms
ofOx oommuting
with the shiftto .’ .
is
equal
to{Tioj : iez, j-001
It isinteresting
toknow whether or noti
Surpriaingly
i.t turns out thatin our class
the
answer can benegative.
aswell
aspositive.
2. Notations
Now,
rre introduae a bit ofterminology-
~ohelement will be called
a blook, k
iscalled the
length
of B and we denote itby )B(.
DenoteB [i j, j] (b.0 k.4 b.)
, blockIL 1
1
.
~
1 of
,
defined by setting bL.0
ifb¿-1
and ifb;-0:
Let’C.
(o*
o6 .)be
I another block; Then theproduot
Bx C ia definedN
p
by BO.B.
If
We will say B appears in C at i
within d
if If=0 we say
simply Bappears
in C at i4Now,
let be finite blocks oflengths
at leasttwo
beginning
with zeroand put
The sequenoe x defined in
/11
is said to be a Morsesequenoe.
if/i/ infinitely
of theb~~s
are different from0...0,
/13/ infinitely
many of theare
different from01...010
andObviousii-/lI
follows fr/ii1l.
If
x is
a Moresequence then
one oanfind
an almostperiodio
point
suah thatPut
ie Z ~
where T is the shift on I.It is known
o7 T)
isstrictly ergodic
Theunique
T-invariant measure
/ ergodic /
we shall denot eby /x
and thesystem ~~a) ~~~~ ,T,~x).
’ will said to be a Morsedynamioal system /
Morse shift,f i
t
Denote by
6 the mirror mapA--
i I ~ oThen and
by. strictly ergodioity of Q
cspreserves
Kwiatkowski
inM
hasfound
out the struoture of~ /
the setX(x) described
there is containedin I
and theset,
X (x) -is oountable
I, Namely,
let~0,:::,a~-l~~.t> 0, put
Then
Dnt=(Dnt,...,Dnt)
is apartition of C1
into open and.... t
closed subsets.
Moreover, for
every andevery
teNthere
is only
one suohwill be
called t-s18bols.
.- ,
In what follows wo
will
say aboutproperties
of x instead of Ton
~
and forexample
if no confusion beoomes we shallwrite
C (x)
instead of0(T) :
3. Coalesoenoe
Let
be aLebesgue spaoe.
We say .an
automorphisms :X9is
ooalesoentif
everyendoaiorphism
ofoommuting
with t isnecessarily invertible.
Consider the olass of allergodio automorphisms t
of(X,J3
for whichwhere is the group of all
eigenvalues
ofunitary operator
iv
definedin)the following way
Here 0and denotes the group
generated. by {exp
Let us notioe that
Sp(r)
iff there is an,-staok
for r iiei a
partition (1, Tk,
iii, Moreover it is notdifficult
toverify
thatergodicity of T implies
thatthere is
only
one/ reordering
if neoessary elements of anothern.-staok / n.-staok for ~ ,
so we denote itby
In addit ion if then
trt
D -
Do.... ,D,,(1..
t In addition ifni nt+1
then Dt D ’.1-
If
v
then weget
a sequenoe of T-invariantpartitions
D~‘’~~ ::: :
Let thelimit partition:
We assertoard
Dt.
ia a constant number for allieI / t.e.
either oardiEI
or oardDl-m
for some natural.m/ a.e. 03BC.
Indeed D is,z-i ariant and measurable
partition,
so ourclaim easily
follows
from[1] .
Put -oard Let us observe that is an invariant of
isomorphyi
Proposition 1
If isfinite
then 1; isooaiesoent.
..
. Proof
tet
bd any t-invariantand measurable
partition
of X and let be canonical map: It is sufficient t o show/C93/
that if and~‘~~’~ , X/~ ,~/~
areisomorphic then z
isequal
to thepartition
intopoints.
So,
let us suppose it.Thus
there is the sequenceof and Let
D,
be any"typical"
atom from D. Therefore
-
"’t 7,0 "’- v
because the
preimage
carriesnt-stacks
intont-stacks.
Hence fcannot stick
together points
as soon asthey belong
to the sameatom
D J /because
of oardD,
-cardDd / :
Finally,
containss-algebra gene rat e y nt-t-stacks
t -,~/ 0,
D.Therefore T
must beequal
to thepartition
,,into
points.
Remark
1
For every Morse sequence x,d~.(x) .2 i
Remark 2 If
d!’t1tBî:) = 00
then t need not be coalesoent. For instance if ~ is a Morse, shift and ~’ any Bernoulliautomorphism cannot
beooalescent / [9], [18] I.
4. Centralizer and
simple spectrum
In this section weformulate and prove some characterization of
automorphism having simple spectra
that we need in thefollowing.
Proposition
2 Let anautomorphism
of aLebesgue
space:
ThenU~
has asimple ppectrum
iff theunitary
centralizerof -c I Q, /x) 9 ,
~t isunitary,
isabelian.
Proof If U has a
simple spectrum
then everyunitary operator V,
is a function of 1:’ I:e: there exists a bounded fun.otim f such thatV=f (t) = f fd3,
where B is thespectral
measure ofUt.
uz
Let
v’ e Cunit(t)
then Hence Ut0 U’t
Utf’dE = ff’dE=VV
Ut/r5J/:
Now,
suppose T does not havesimple spectrum:
Then there are such thatL~- (X, )
whereBL
is thecyclic
spacegenerated by f; , I : e : i-1.,2,
C is
U,~-invariant
and there existsU1:B1--~ Bz
which isunitary
and
/[5J/. We define
twounitary
operators V, V’ on L2(X,03BC) setting
to see that but
Indeed,
ifIt ---easy
to seethat V. Vte 0 (t)
butVVX*I Indeed, if
identity
and acontradiotion
toergodioity of t.
B2, ’- ’
It
1s
known that every Morse sequenoe x has asimple spectrum. Combining
this withProposition
2 we have obtainedCorollaryl
For every Morse sequence x,CfxJis
abelian.5; A olass of Morse sequences with unoountable oentralizer In this section we
give
a olass of Morse, sequences withunoountable centralizer: We also
provide
somearguments
that theproperty
to have an uncountable oentralizer is atypical
one.Let
(X,3y)
be aLebesgue space
and T be anergodic
automorphism
of us consider thegroup S
of allautomorphisms
S: withthe
weaktopology 11’ /[61/
defined in the
following
wayNow,
we reoall some knownresults
on the weaktopology.
/2,/~,~,’lr.~,°~
is atopologioal group /E61 /,
/3/(~,’i~~
iscompletely
.metrizableI[C] /0
/5/. C (,,)
is aclose
set. , ,
it-it-1
./6/
Ift -> S, ,1: -> id
and is aperfect set,
so from the Bairsproperty C(t)
is uncountableWe let
51..
1 denote the class of all with forsome sequence Then
51
contains a denseGs
set ofautomorphisms
ofIndeed,
ifS admits
acyclic approxima-
tion with
speed o(1/n)
thenUzt i d’"for
some sequenceand moreover the class of all
automorphisms admitting
acyclic approximation
with a fixedspeed
contains a denseG~
setSo,
we haveproved
theproperty
to have an uncountableoentralizer is a
typical
one in~.
Let us observe that theclass 3
is olosed undertaking factors,
so if then Sdoes not have
mixing factors,
inparticular h(S)=0:
But astronger
fact’ is true. If then S isdisjoint
from allmixing
transformations/[z1~ /:
Now,
we are able to show there are Morse shifts with unoountable oentralizer:Given a Morse sequenoe ::: we denote
Proposition
3 Letx=b°x bl v
ii - 9 be a Morse sequence.If lim then
C (z)
is unoountable.t -> oo
Proof We will prove that x admits a
cyclic approximation
with
speed o ( 1/n):
We
have5t i-O, .;...; ,.n-t: -1, /
seeSection2 /
From it follows that
3t
/ &We define a
cyclic approximation St putting
Now,
we wishto
estimateWe then
get
Therefore x admits desired
cyclic approximation.
6 The measure-theoretic centralizer of
regular
Morse sequences This section is devoted to prove the main result of the paper
Theorem1
Let be aregular
Morse sequencesatisfying /11/
and letS t C(x) 4
ThenS=T’6¿
for someiezo j=O,1.
We start with
presenting
our mainteohniques / Proposition 4,5/
needed in
proving
ofTheorem1.
Let x-b k b x i be a Morse sequenoe
A measurable function
CP:X-{O,1~Ç?
is said to be a oode oflength
k if/i/
depends only
onthen
G
/iii/
k is the smallest natural numbersatisfying /ii/
andwe denote it
by
The
following Proposition
establishes a list ofproperties
of finite codes that we will need.
Proposition
4/a/ Let f
be finite codai Then for aiei~~Y~E ~ ~
if then/b/
LetS e C (x) and W
0; There is a finite oodeCP
such thatProof The
proof
isstraightforward
and we useonly
ergodic
theorem.Following
we say x is aregular
Morse sequence if . there isg ~
0 such thatand In addition we assume
Then
following
oharaoterization ofregular
Morse sequences satisfying /11/
can be found in[14].
Proposition 5
Let be aregular
Morse sequenoe and let/’11/
holds. Thenappears
-
L L v
in x at i within
Ö
thenand n appears
in x ati]
In the
sequel
we will need some faóts of combinatorial nature.Let be a
regular
Morsesequence satisfying /11/
and let Let
c~> 0,
bedetermined by Proposition
5.;Let us and assume is a oode of
lenght
k so that/12/
’ for a.e.Fix for whioh
/~2/
holds.Next ,
we f ind t e N solarge
that,Assume in addition
Now we shall define some map
H:{Ot11~
in the.following
waywhere otherwise and
Let us observe that
Indeed,
otherwise we would haved( s=0,1
Obese a sector of y,
say Y [-m,m1, m > n£
such thaty [-m,m]
consists of pt-symbols
and this seotor contains/18/
at least(1-£)p
ofa( , r=0,1
oalculatedonly
in theplaces
of theform’-u+vnt’ v=0 , ± 1, ±2 , : : :
To see
/18/ it
is sufficient to useergodio
theorem and the fact that for everyr =0,1 , t-0,1,~., ~
Hencea contradiction.
Now,
we show is one--to-one: Indeed let us suppose H(0).Hfl)i
ThenBut from
/14/
a contradictioni
At
present,
we estimate We haveHenoo
Let us consider
again
the sectory [-m,m~ satisfying /18/
and we match
by
arrowe~
with o~(y) / Picture 2/.
-L c ~ ... I I
Pict ure 2 We wish to estimate the number R of
eJ ’ r=0,1 without
arrow:~e have therefore
Proof
ofTheoreml
From-the invertibility
of H we have/21/
t t forr-O,1.
Take now where
always
t-symbol. Then
Find
thegreatest to
such that y contains LUsing
the condition of boundnesa of{’ÀtY
weget
wheneverSo
ohoosing E
as small as we need andapplying
Proposition
5 we obtain-1]
for
some
v E Z:Letting get
at onceLet us set
h=0,l .
So eitheror
~t,c.X(~1~>d:
But is T-invariant andergodioity
of T forceswi th po s it ive measure /
to have fullmeasure: Finally
Corollary 2
For everyregular
Morse sequence w’ th/11/
there are ’no roots of the shift induced
by
x.gorollary
3 For every regular Morse sequence with/j1/
iE
Z~ ~
roof In the case of the
equality 0 (TJ
isuncountble.
Final remarks Let us now consider the class of all
nonperiodic
substitutionson’two symbols
of constantlenght
./
for definition andproperties
seefill /
Iii
disorete substitutions: ife
defined in/22/
has theproperty
for somei, ~ ~-1 li i/o ont inuous
substitutions: otherwise.Their
topologioal
centraliter was oalculated in13]i
It isequal
tolTk:
k EZ ~
forIii
andfor Iii!
/here
õ isagain
the mirrormap/;
Now,
we are able to show measure-theoretio centralizerfor
suoh a 0 : Let 0
be discrete substitution:Then 6) may
beconsidered from the measure-theoretic
point
of view as adiscrete, ergodio dynamical system
withFrom M it follows that It is easy to see that the last group is
equal
to the 2-adiointegers.
Let
j9
be a oontinuous substitution. Then thedynamical system arising from 0
isequal
to whereis a Morse sequence
/’
if B does not start with zero wereplace
B
by
So fromTheorem1
=0(6) ={T¿~ ,i
e-Z, j=O,1
Consider the class of Morse sequences over a fixed finite Abelian group
G /
see/;
Let be such a one:Let us call it
regular
ifsup
-te7/ where{|B| : B=0 6g(0) ... 6(|g|-1)(0) 06g(0) ... 0 6g(0) ... 6-, (0)
and B appears in5i
igi
denotes the orderof g
and9(i) -i+g ,
If(hEi
is bounded then
Proposition
5 holds for theseregular
Morsesequences over G. The
concept
of finite oodeProposition
4 go as in Section 6. Let us assume SE C x and in addition for everyg s G: Repeating
cons*lderations of Section 6 we see that theonly
formula which is notquite
clear is the
following
To prove it we takep as
in /18/1
There must exist aniofZ
such thatwith an, arrow for every
geG I
it is asimple
consequenceof/18/,/20/
and/.
Thisproves that if S E
G (x )
,g E G
thenS=TL68
for someI e z, geG.
Toget
it is sufficient to know thathas a
simple spectrum.
Ingeneral
it isstill
unknownwhether
they
havesimple speotra
or not.Recently
Kwiatkowski have communicated me that he knowsexamples
of Morse sequences/over
anycyclic group/of
the form xzzBxBx : : :having simple spectrum
References
[1]
L.M.Abramov,
V.A.Rohlin,
Theentropy
of a skewproduct
of measure
preserving transformations, Vesta,
Len. Univ. 7/1962/,
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in Russian/
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J.R.Blum,
N.Friedman, Commuting
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E.Coven, Endomorphisms
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The structure of substitution minimalsets,
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Introduction to Hilbert space, Chelsea1951 [6]
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A. delJunco, A
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verw. Geb.10
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Therank
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The sequenceentropy
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[16] J.C. Martin,
Generalized Morse sequences onn-symbols, Proc.
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The structure ofgeneralized
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Centralizer of anergodio
Measurepreserving transformation,
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Anexample
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97-122[21] P. Walters,
Some invariant6-algebras
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~
M. LEMANCZYK
Nicholas Copernicus University
Institute of Mathematics TORUN
Poland
Requ en F6vrier 1985