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Critical thickness of a hybrid aligned nematic liquid crystal cell

G. Barbero, R. Barberi

To cite this version:

G. Barbero, R. Barberi. Critical thickness of a hybrid aligned nematic liquid crystal cell. Journal de

Physique, 1983, 44 (5), pp.609-616. �10.1051/jphys:01983004405060900�. �jpa-00209638�

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Critical thickness of a hybrid aligned nematic liquid crystal cell

G. Barbero (*) and R. Barberi

Unical Liquid Crystal Group, Department of Physics, Calabria University, I-87036 Rende, Italy (Reçu le 5 octobre 1982, révisé le 6 décembre 1982, accepté le 13 janvier 1983)

Résumé. 2014 Nous avons analysé la déformation des cristaux liquides nématiques dans une cellule avec alignement planaire sur une paroi et homéotrope sur l’autre. Nous supposons que l’interaction superficielle est du type (w/2) sin2 (~ - 03A6) et que l’énergie d’ancrage homéotrope est plus grande que celle relative à l’ancrage planaire.

En l’absence du champ électrique, nous démontrons qu’il existe une épaisseur critique dc au-dessous de laquelle

le cristal liquide nématique n’est pas déformé. Nous discutons aussi la dépendance en dc du champ réduit E/Ec (où Ec est un champ de seuil d’instabilité pour transition de type de Freedericks). Ec dépend seulement des énergies d’ancrage Wi sur les parois et du cristal liquide.

La dernière analyse montre qu’il y a deux épaisseurs critiques dc(H) et dc(P) : pour d dc(H) la cellule est homéotrope,

et si d > dc(P) elle est planaire. Enfin nous démontrons que si les énergies d’ancrage homéotrope et planaire sont égales, la cellule hybride est réalisable seulement si E/Ec 1.

Abstract.

2014

We discuss the director deformation inside a hybrid aligned nematic (HAN) cell, assuming that the

surface interaction is of the (w/2) sin2 (~ 2014 03A6) kind, and we suppose that the anchoring energy for homeotropic alignment is greater than the planar one.

In the absence of an external electric field, we show that a critical thickness dc, below which the nematic liquid crystal (NLC) is undistorted, exists. Furthermore we investigate theoretically dc vs. the reduced electric field

(E/Ec, where Ec is a threshold field depending upon the anchoring energies and the intrinsic constants of the NLC).

The last analysis shows that there are two critical thicknesses dc(H) and dc(P): for d dc(H) the sample is homeotropic (HOM), while for d > dc(P) it is planar (PLAN). Finally we point out that if the anchoring energies are the same

on the upper and lower plates of the sample, the HAN-configuration is realizable only if E/Ec 1.

Classification

Physics Abstracts

61.30G - 42.65J

-

42.1OQ

Introduction.

-

The HAN cell has been recently

considered by various authors from a pratical [1-4]

and fundamental [5, 6] point of view. In fact this cell

seems to be particularly suitable for creating coloured displays [1, 2] or optical devices that might use self focusing to get bistability [4]. Furthermore the hybrid alignment gives a volume flexo-electric polarization : by analysing the behaviour of the HAN cell submitted

to an electric field it is possible to determine the bulk flexo-electric constant [6].

M. M. Labes et al. [4] and L. Terminassian-Saraga

et al. [7] show that the NLC film subject to antagonist homeotropic and planar anchoring on two glass plates can be distorted only if the thickness d of the

sample is greater than the critical one dc, and give

an order of magnitude for dr. In the present paper

we will calculate in a rigorous way dc, and will analyse

the influence of the elastic anisotropy K = I - K 11 /K3 3

and of the electric field on dc.

1. HAN cell without external field

-

The sample geometry is shown in figure 1. A NLC is placed between

two glass plates (at Z = - d/2 and Z = d/2) coated

to induce homeotropic and planar orientations [8]

respectively. In this condition the sample has under-

gone a mixed splay-bend distortion. We can obtain the director deformation of the NLC by the conti-

nuum theory, supposing that the anisotropic inter-

action between the liquid crystal and the substrate is not strong. In this paper the surface energy is modelled as (wi/2) sin2 (Qi

-

oi), where wi is the anchoring strength coefficient, tP¡ the easy axis and (Pi the director angle at the surface substrate [9, 10].

In the case of the HAN cell we have tP 1 = 0 and tP2 = n/2 on the lower and upper walls respectively,

and we suppose wl > w2 [11].

Article published online by EDP Sciences and available at http://dx.doi.org/10.1051/jphys:01983004405060900

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610

Fig. 1.

-

Schematic representation of a HAN cell in the

case of finite anchoring energy. T, and T2 represent the tilt angles at the interfaces (in the strong anchoring hypo-

thesis they are given by (p, = 0 and CP2 = n/2).

1.1 ONE CONSTANT APPROXIMATION.

-

In the one

constant approximation (K11 1 = K33 = K, i.e. K = 0) by minimizing the total free energy we obtain

with the boundary conditions

where Li = K/wi are the de Gennes-Kleman [12]

extrapolation distances, the Z-axis is normal to the substrate and 9 is the tilt angle formed between the director n and the Z-axis.

The subscript Z means the derivative with respect to Z.

By solving equation ( 1.1 ) we obtain :

where the constants Q2 = Q(d/2) and 91 1 = Q(2013 d/2)

are determined by equations (1.2). In the strong anchoring hypothesis wi -> oo and hence cp 1 = 0,

Q2 = n/2; then 9 = (n/2 d) (Z + d/2) [3, 6]. When

the anchoring energies are finite, but L d, it is possible to linearize the boundary conditions (1.2)

and after trivial calculations we obtain :

Consequently, from equation ( 1. 3)

In these cases (i.e. wi -> oo or Li d) for any sample-

thickness d the tilt angle Q is linearly increasing with

Z : this implies that a critical thickness dc, below which the sample is undistorted, does _not exist.

In the opposite situation, i.e. Li ~ d, the boundary

conditions give, for example,

By solving this transcendent equation for 2 Q 1 we find that

where h is an integer and

With the aim of determining the critical thickness dc,

it is necessary to find the situation where QZ -> 0,

e.g. 92 - 9i

Then we can restrict ourselves to the case in which qJ¡ E (0, n/2). Using this assumption in equation (2 .1 )

we have h = 0 and h = 1 only.

Furthermore, by taking into account that 0, 1 = 0, ø2 = n/2 and w1 > w2, we get Q2 > qJt’ and hence sin (P2 > sin Q 1. By using equation (2. .1 ) the latter condition can be rewritten as

These relations are equivalent to

Since L, L2, we deduce that h = I is not accep- table.

In consequence we have

and hence

The function Q2 = Q2(d) is monotonically increasing

with d : this implies that equation (2.3) has only

one solution.

From equations (2.2), (2. 3) it is possible to deter-

mine Qi, and then, by means of ( 1. 3), the tilt angle Q.

The transcendent equation (2.3) has a non-trivial

solution only if

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which implies d > dc(H) = L2 - [1. Then the equa- tions (2.2), (2.3) have the unique solution Qi; = 0

if d dc(H) : consequently the sample is undistorted.

For d > dc(H), Qi # 0, i.e. it is possible to obtain the

HAN cell. We point out that for d dcH) the NLC subject to conflicting boundary conditions destroys

the smaller anchoring energy, reacting to the increasing distortion ; thus the result for the total free energy is

w2/2.

_ _

The previous result, dc(H) = L2 - Li, is in agree- ment with that given by M. M. Labes [4].

It is possible to rewrite equation (2.2) as

Now it is necessary to test the stability of the solu- tion Q2 = 0 (i.e. (Q = 0 : the sample is in the HOM-

configuration) for d d, .

In this case the total free energy is given by :

where

’Ps represents the nematic-substrate interaction.

From equations (2. 2) and (1. 3) we find that :

and hence, by using Q2 as parameter, we obtain, from (5)

Consequently

From these relations we deduce that T2 = 0 is a stable

configuration only if d dc(H’), while for d > dc (H)

the total free energy corresponding to HOM-situation is a maximum (see appendix 1).

Finally we point out that if the surface interaction is of the parabolic form the critical thickness does not exist.

_ _

In fact if ’YS = (1/L1) Q2 1 + (1/£2) (7t/2 CfJ2)2 the boundary conditions (1.2) become :

Taking into account equation (1.3) we find that the constants qJi are given by (1.4) and the tilt angle by (1. 5) : hence the sample is always distorted

1. 2 GENERAL CASE.

-

In the general case (K 11 K33, i.e. K # 0) equations (1.1), (1.2) become :

where Li = K33/Wi and C2 is an integration constant,

fixed by the boundary conditions (6.2). From (6.1), (6.2) we obtain

being

By solving the simultaneous equations (7) we can

deduce the unknowns Q 1, Q2, Q and C (see Figs. 2).

Figures 2 show the behaviour of Q2 and Q 1 vs.

the sample-thickness d for some elastic anisotropies.

From figures 2 we see that if d >> d c (H) the HAN cell

assumes a configuration near the ideal one, with strong anchoring energies.

In order to determine dc(H) , from (7.1) written for Z = ± d/2 we determine, after some algebra,

(Pl (Pl((P2) and

From (8) it is easy to show that ðd( ({J2)la({J2 > 0 still,

for any Q2 E (0, nI2), and hence dIHI = lim d(qJ2).

for any T2 c

CP2 -+ 0

In the case of small Q2, routine calculations give

Therefore, from (8), we have d((P2) = L2 - L1 + 0(Q2) and then dc,(H’) = L2 - L1, as in the case of

elastic isotropy; but Li = K33Iwi if we consider the situation L2 > L1(Wl > w2). In the opposite situation

an analogous calculation (where Q1 - n/2 if d - dc(p))

shows that the sample is planar if d d,(P) = L1 L2,

where Li = K 11 /wi. In order to examine the stability

of the HOM-configuration for d dc (H) we proceed

as in the previous case.

Now the total free energy W is still given by equa-

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612

Fig. 2.

-

a) Plot of Q2 and b) of l{JI vs. the sample thickness d (J.1m), for K = 0, K = 0.3 and K = 0.6, which are reasonable

values [ 12]. We note that K > 1 only next to the transition

N - SA, and in this range the HAN cell is not used. The

case L1 = 1 J.1m and L2 = 5 J.1m is considered, giving dcH) = 4 um. We point out that lim CP2 = 7r/2 and

d-+ 00

lim Q1 1 = 0.

d-+ 00

tion (5), but f(Q, cpz) = ( 1 - K sin2 Q) cpi. Using (6. .1 ) and (7 . 2) it is possible to rewrite as

In the limit of a small deformation close to the

HOM-configuration (e.g. rp2 - 0) we have from the

previous discussion

as was the case when K11 = K33. Hence the HOM-

configuration is stable for d dv(H).

We note that the present case, in the absence of an

external field, is very important for the analysis of the

non-linear birefringence in a HAN cell [5]. Here for

E Et, E, being the threshold field for the Freedericks transition, it is possible to expand the tilt angle (p as a

power series in e = E/Et. This way the zero approxi-

mation gives equation (7), while higher orders give

linear equations integrable only if the zero order is

known [14] (see appendix 2).

2. HAN cell submitted to external field.

-

Now let

us analyse in greater depth the case of a HAN cell

submitted to an electric field parallel to the X-axis.

For a small positive dielectric anisotropy, ea = s ||

-

El [15], instead of (6 .1 ) we have

where ç -2 = (sa/4 nK33) E’, while the boundary

conditions remain as given by (6.2) [16]. The para-

meter ç is the well-known electric coherence length.

By proceeding as in the previous case we obtain

being

Equations (10) solve the present problem.

In this case the analysis of the existence of the HAN cell vs. the sample-thickness d is more complicated

than in the absence of an external field [ 17J. In fact if d

decreases the NLC tends to assume the HOM-confi-

guration, in order to reduce the total free energy related to the elastic distortion, as seen above. But this

configuration may be unstable if the electric field is strong enough. Then in this situation, the PLAN- configuration is more favorable energetically.

In consequence we must consider the limit p2 -> 0+

(HOM-configuration) and CPt -> (n/2)- (PLAN-confi- guration).

2.1 TRANSITION HAN -+ HOM CONFIGURATION.

-

with reference to the case Q2 -> 0+ we deduce from

( 10 .1 ) : wi 1 = CPt (CP2). By substituting this result into

( 10 . 2) we obtain d = d(CP2). For small CP2 we have

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Consequently, from equation ( 10 . 2), the critical thickness d,,, (H) is given by

From (12.1) we deduce that if ç is very small, e.g. the field is very large (see below), d,(H ) is given by

while if -1 L 1 we obtain dr(H) ~ L2 - L1 - (1/2) ç - 2(L3 - L 3). As in section 1 for d dcH) the sample

assumes the HOM-configuration, while for d > dc(H) it is in the HAN-configuration.

It is easy to show that if d dc (H) the HOM-configuration is stable. In this case the free energy density f(cp, cpz) appearing in (5) is :

Taking into account equation (9) we have : f (Q, qJz) = C 2 - 2 ç -2 sin2 qJ.

Furthermore if we consider a small distortion near the HOM-configuration (i.e. qJ2 -> 0+) we obtain

Now, by observing that equations (11) and (9) imply that

and by putting dc,(H’)/d = 1 + d, we obtain the following form for the total free energy :

If 16 is very small [ 18], by expanding the square roots as power series in 6 we obtain, after a simple calculation,

in our hypothesis hence

2.2 TRANSITION HAN - PLAN CONFIGURATION. - Finally we examine the situation where w 1 -> (n/2) -.

By putting (pi = (n/2) - bi we can consider the case 6, -> 0+.

From ( 10 .1 ) in this limit we have

Obviously 62 is real and furthermore 62 ð1, since lp2 = n/2 (i.e. 62 = 0) is favoured energetically. Hence, in our

case where L1 L2, from (14) we conclude that the electric coherence length 03BE must be smaller than L 1 :03BE , L 1.

This implies that the HAN-configuration can degenerate into a PLAN-configuration only if the applied field is larger than a critical one, given by

A similar analysis is not necessary for equation ( 11.1 ), because (p 1 is real and furthermore (p 1 (P 2 for any

]ç, in our hypothesis. In consequence the HAN-configuration may degenerate into the HOM-configuration for

any field, as may be expected.

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614

The critical field E. is needed to break the anchoring on the non-favoured plate. If K 10 ~ " N, ga - 0.1 [ 12]

and L2 ~ 5 J.1m, L 1 ~- 1 J.1m [ 19, 20] we deduce that E, n~ 107 V/m. Hence, by supposing L 1, we find that

From (16) and ( 10 . 2), by putting dc,( :’) = lim d((p ) we deduce that

ð1 -+ 0 +

It is easy to show that if d dcP) the sample is in the HAN-configuration. In fact, the second term 0(d 1 ) in equation (16) is of the form :

which, from the assumptions ç L1 and L1 L2, is smaller than zero. In consequence from (10.2), we find

that d dc(P) if d1 = 0. We point out that ð1 # 0 implies 62 =A 0, from equation (14), i.e. the sample is in the HAN-configuration.

From (17) we note that if ç --> Lt, dc --> oo. Further-

more if ç is very small with respect to L, (i.e. E > Ee), dcP) is still given by ( 12 . 2).

A calculation similar to that performed for the

HAN - HOM transition, shows that the PLAN-

configuration is stable if d > dc(p).

From the previous discussion it is possible to con-

clude that only if the sample-thickness d is in the range

dc, (H) _ dr (p) the HAN-configuration is realizable, while

in the cases d dc (H) or d > dc(,P) the sample can only

assume the HOM- or PLAN-configuration, respecti- vely.

Figure 3 shows the behaviour of dc (H) and dcP) vs. the

reduced applied field (ç -1 = L-’(EIE,)).

From it we see that :

1. The HAN cell may be realized only in the shaded region.

Fig. 3.

-

Variation of the critical thickness dc(H) (lower line)

and dcP) (upper curve) vs. the reduced applied field E,-1 = L1(E/Ec), in the case L2 =5 um, L1 =lJ.1m.

The HAN-configuration is stable only in the shaded region.

2. If E/Ec 1 the only limitation for the realiza-

bility of the HAN-configuration is represented by

d > dc(H).

In this region if L22> L21) the critical thickness is

approximatively given by dcH) ~ (L1I2)[2 - J2 -

3. If EIEc > > 1 the range dc,(p) - dc(H) is very small,

then it is difficult to realize the HAN cell. We point

out that in this region dc(p) and dC(H) drop to zero with

the same behaviour.

4. If Li = L2, it is found that dc (H) = 0 for any electric field, while dC(P) undergoes an abrupt change if

the strength of the external field exceeds the threshold defined by equation (13) (see Fig. 4).

Fig. 4.

-

In the case of Li = L2 the HAN-configuration

is stable for any d only if EIE, 1, while for EIE, > 1 it is

always unstable.

3. Conclusion.

-

This work constitutes the first theoretical examination of the critical thickness in a

rigorous way. We have shown that in the absence of an

external field dc depends only on the bend elastic

constant (if w, > w2). Our results concerning the

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dependence of dc on the anchoring energies wi are in qualitative agreement with those of M. M. Labes et al.

However, they did not consider the general case where

K =A 0 and E # 0. In these situations we have shown that only if the sample-thickness d is in the range

d , (H) - dC,(p) the HAN-configuration is stable, where

dC (H) and dC(P) are the critical thicknesses for the transi- tions HAN HOM and HAN PLAN respectively.

In particular we have demonstrated that the transition HAN - PLAN has a well defined threshold, EC, = (2/L,)VF7rK 33/Ea below which it is forbidden.

Obviously, in our case, the transition HAN HOM is always possible.

Acknowledgments.

-

One of the authors (G.B.) is grateful to M. M. Labes for suggesting this problem, to

G. Durand for supplying the preprint of his paper and to G.N.S.M. of Italian National Research Council that has partially supported this work. We wish to

thank C. Oldano for useful discussions.

Appendix 1.

-

The case L1 = L2 must be analysed

in separate ways.

In this situation from equations ( 1. 2) we find that equation (1.1) has the following solutions :

ponding to homeotropic, planar and hybrid configu- rations, respectively.

In the last case Q2 is determined by means of equa- tions ( 1. 2) written for _i = 2, and is given by the trans-

cendental equation (Lt = L2 = L)

From such a relation we deduce that :

a) lfJ2 is monotonically increasing with d,

consequently

A simple analysis shows that the i) and ii) solutions

are not related to stable configurations, while the hybrid configuration minimizes the total free energy tl’, and hence it is a stable configuration.

In fact, in this case, we have Ys s = (sin2 qJ 1 +

cos2 Q2)/ L, and after routine calculations we obtain

that are equal to zero for the boundary conditions ( 1. 2), and

Hessian determinant of the function Now it is easy to show that

being Q2 E (nI4, nI2). From the previous relations, it follows that neither for cp = Q2 = 0 nor cp 1 = Q2 = n/2

the function T has an extremum, while for Q 1 =

(n/2) - Q2 it has a minimum, since 02 tp 10lfJî = (21d) + (2/L) cos 2 cp I > 0, being Q1 1 E (0, n/4). We

observe that in this case dc,(H) = 0, i.e. for any sample-

thickness d we have QZ = 0 : the sample is distorted, as

may be expected. By using this method it is possible to deduce dc in another way.

In fact in the general case (L1, = L2) we obtain

that are equal to zero for equations ( 1. 2), and

By noting that

being L2 > L1, we deduce :

is a stable configuration if

is not a stable configuration.

While if d > dc the stable configuration is distorted.

The method followed in the text gives also some

information about the behaviour of Q1 1 and Q2 vs. the

sample-thickness : for this reason we have preferred it.

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616

Appendix 2. - By putting and

into (8) we obtain, for the zero order in e, equation (6) for Q(O) and Co. For the first and second order we have for Q(1) and Q(2) two linear differential equations, that are easily integrable. After simple calculations we get

where g(Z) = 1

-

K sin2Q(o)(Z) and yl, C12 are

integration constants, fixed by the boundary condi-

tions (5.2). It is easy to show that C2 = y 1 = 0 and hence Q(1) = 0. An analogous procedure gives

The integration constants are now # 0. From

equation (5.2) we determine these constants, and

hence (P(2)’ In this way it is possible to obtain the

dielectric constant 82 [5], linear in the intensity, with the

relation :

where E = (E + e1.)/2, without solving the general

problem.

References

[1] MATSUMOTO, S., KAWAMOTO, M., MIZUNAYA, K., J. Appl. Phys. 47 (1976) 3842.

[2] RIVA, R., Fis. Tecnol. 2 (1979) 114.

[3] BARBERO, G., STRIGAZZI, A., Fizika 13 (1981) 85.

[4] HOCHBAUM, A., LABES, M. M., J. Appl. Phys. 53 (1982)

2998.

[5] BARBERO, G., SIMONI, F., Appl. Phys. Lett. 41 (1982)

504.

[6] DOZOV, I., MARTINOT-LAGARD, Ph., DURAND, G., preprint (1982).

[7] PEREZ, E., PROUST, J. E., TERMINASSIAN-SARAGA, L., MAUER, E., Colloid Polym. Sci. 255 (1977) 1003.

[8] Actually these conditions can be satisfied by putting,

as shown in ref. [7], a NLC between a free sur-

face (homeotropic orientation) and water (planar orientation).

[9] NAEMURA, S., J. Physique Colloq. 40 (1979) C3-514;

WARENGHEM, M., Mol. Cryst. Liq. Cryst. 89 (1982) 15.

[10] COGNARD, J., Mol. Cryst. Liq. Cryst. Suppl. Ser. 1 (1982) 1.

[11] In this paper we suppose always that w1 > W2, i.e.

L1 L2. In the opposite case our calculation remain valid if we permute ~1 with ~2 and consider the limit ~1 ~ (03C0/2) rather than ~2 ~ 0. This situation is examined in ref. [4].

[12] See for example DE GENNES, P. G., The Physics of Liquid Crystals (Clarendon Press) 1974.

[13] SCUDIERI, F., Opt. Commun. 37 (1981) 37 ;

SCHAAT, M., MULLER, F., IEEE Trans. Electron Devices 25 (1978) 1125.

[14] BARBERO, G., STRIGAZZI, A., Mol. Cryst. Liq. Cryst.

Lett. 82 (1982) 5.

[15] DEULING, H. J., Solid State Phys., Suppl. 14 (1979),

where the general case is considered.

[16] In the case of 03B5a 0 or in the case of 03B5a > 0 and E

parallel to Z-axis, in equation (9) the second term

becomes - 03BE-2 sin2 ~. This implies that the

calculations performed for 03B5a > 0 and E//X are

formally invariant if we replace the electric cohe-

rence length 03BE with i03BE, where i2 = 2014 1.

[17] We are indebted to the referees of « Le Journal de

Physique» for useful remarks on this section.

[18] The hypothesis |03B4| ~ 1 is not necessary; it is per- formed in order to give a simplified form to equa- tion (13.2).

[19] NAEMURA, S., Mol. Cryst. Liq. Cryst. 68 (1981) 183;

NAEMURA, S., L.C. alignment mechanism and influence

on display-device characteristics, preprint June

1982.

[20] LEVY, Y., RIVIÈRE, D., GUYON, E., J. Physique Lett.

40 (1979) L-215.

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