A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
S EÁN D INEEN
The Cartan-Thullen theorem for Banach spaces
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 3
esérie, tome 24, n
o4 (1970), p. 667-676
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THE CARTAN-THULLEN THEOREM FOR BANACH SPACES
by SEÁN
DINEENThe
object
of this paper is togive
a characterization of domains ofholomorphy
which is similar to thatgiven by
Cartan-Thullen for finite dimensional spaces in[4]. In §
1 we recall some results from thetheory
ofholomorphic
functions on a Banach space, define domains ofholomorphy
and prove a number of fundamental lemmas.
In § 2
we prove our main results. Our main reference for thetheory
ofholomorphic
functions on aBanach space is
[16]
and for domains ofholomorphy
in finite dimensionswe refer to
[2], [3], [4], [10], [13]
and[15].
In[1), [2], [3], [11]
and[12]
there are a number of
interesting
resultsconcerning
domains ofholomorphy
in infinite dimensions.
SECTION 1. E will
represent
acomplex
Banach space with unit ballB~.
For each
positive integer
m let denote the set of all continous m-linearmappings
from Em = jE7 x .E X ... m E(m times)
into,C (the complex numbers).
Let11m
denote themapping
from E into Em which takes x into...,
x) (m times).
A continuousm homogeneous polynomial
is amapping
from E into C which is the
composition
ofAm
and an element of.6(~E7).
We denote the set of all continuouspolynomials
on Eand we note that it forms a Banach space under the norm
A
complex
valued functionf
defined on an open subset U of .E is said to beholomorphic at ~
E U if there exists a sequence(Pn (~))~=o (where Pn ($) E
Pervenuto alla Redazione il 20 Aprile 1970.
E
~
for eachn)
such thatfor all x in some
neighbourhood
of~. f
is said to beholomorphic
on Uif it is
holomorphic
at allpoints
of U. Since theexpansion
in(2)
isunique /’0..
dmf(E)
(see [16])
wewrite m!
>1.= Pm ($)
and call(2) )
theTaylor
seriesexpansion
of
f
atE.
For the remainder of this paper U will denote a connected open subset of E with anonempty boundary ~ U (the questions
we consider aretrivial for
U = E). CA
will denote thecomplement
withrespect
to jE7 ofthe subset A of E. If
A,
andA2
are subsets of E we denoteby
d(Ai, A2)
the distance between
d.1
andA2 , i.
e.DEFINITION 1. B c B is U-bounded if B is a bounded subset of E and o. We note if E is finite dimensional that the closed
U-bounded sets are
exactly
thecompact
subsets of U.DEFINITION 2.
(a)
is the set of allcomplex-valued holomorphic
functions on U.
(b) ~b (U)
is the set of allholomorphic
functions on U which arebounded on all U-bounded sets.
-
DEFINITION 3. Let Bc U then
But (resp.
is the set ofsuch that
for
(resp.
and is called theU (resp. Ub)-holomorphic
hull of B.
DEFINITION 4. A connected open subset U of B is a domain of holo-
morphy (resp.
b domain ofholomorphy)
if there existsf E W ( U) (resp. Wb ( IT))
which cannot be extended to an element of
qe ( U1) (resp. Wb (Ut))
where~T1
is a connected open subset of .E which
properly
contains U.For a subset 7 of
(the
dual we=
sup I ø (P) I
for all P E6P
Q E V
669
1-1 -""’.
LEMMA 1. Let B c U and Yc then for
all ~
EB u (resp. B U, b)
we have
for each
integer m
and allf E I (U) (resp. C7Yb ( U)).
PROOF. Let 0 E T~ and
f
EI (U) (resp. ~’b ( ~T))
thenby
the definitionof
holomorphic
hullHence
i. e.
LEMMA 2. Let B c U and 0 be such that B
+ a B1 e
U. Iff E ge (U) (resp. geb ( U))
is bounded on B+
thenf
isholomorphic (by analytic
continuation if
necessary)
onB u + (resp. Bu,
b+ o&Bi)
and~ n
where
BUt b)
a.PROOF.
By Cauchy’s inequalities (see [16],
p.22)
weget
where M =
sup
.By
lemma 1 thisimplies (taking
V =Bl)
x
By
theCauchy-Hadamard
formula([16],
P.10) f is holomorphic (by analytic
...0,.. -
continuation if
necessary)
on(resp. Bu,
b+ aB,)
and for x EBo
1-1
(resp. Bu b)
and( y 11 I ,
we haveIf a is a
positive
real number and Ac E wesay A --~- (XB1
is an aneigh-
bourhood of A.
LEMMA 3. Let U be a domain of
holomorphy (reap.
b-domain of holo-morphy)
and let B be abounded. If eachf E (resp. 9(b ( D’))
is boundedon some
a ( f ) neighbourhood
of B thenBu (resp. BU, b)
is U-bounded..11
PROOF. It is easy to check that
Bu (resp. Bu,
’b)
isalways
a bounded1-1
subset of .E so there remains
only
to show thatd (Ba, >0 (resp.
-
d (BU, b , CU))> 0).
If not there exists asequence, (En)n"=0,
of elements be-longing
toBa (resp.
such thatd ($n , C~ ~T ) -~ 0
as n -+ oo. Lemma 2implies
that everyf E qe (U) (resp. ~b ( D~))
has an extension to aholomorphic
function in some a
( f ) neighbourhood
of each~.
Since U is a domain ofholomorphy (resp.
b-domain ofholomorphy)
and~(~,6~7)2013~0
as n --1- 00this is a contradiction.
LEMMA 4. Let U be a connected open subset of E such that it is im-
possible
to find two open connected subsetsU1
andU2
of E with the fol-lowing properties.
(1) and Uf ct.
U(2)
For every there exists an11
E such that1=/1 on U2
=
then
Ba, b
is U-bounded for each U-bounded set B and= d(BU,b CU)
=
PROOF. Since -’ we
get immediately
thatCU).
-
’
Suppose d (B, > d
b,C U ), Choose $1
and a>
0 such that B+ ~2
-~i ’)*
and is U-bounded where~2 - ~1
denotes theconvex balanced hull
of E2 2013 E1(choose E1,E2
suchthat [[ $z
- -(1|| d
’and take 0 a
1/2 [d (B, Cu) -||2 2013 E1 II ]). For ZEBu, b
weget by
Cauchy’s inequalities
and lemma 1 that671
(this
ismeaningful
when weidentify
.E with a subset of( ~ (’~.E ))’ by
meansof the
mapping
for all Lemma 2implies that f is holomorphic
on the set+E2 2013 E1 + aBi
and for a1 a we have-
But and this contradicts the
hypothesis
for Uand hence proves the lemma.
The
analogous
lemma forge (~)
can beproved
in a similar fashion and weget
LEMMA 5. Let U be an open connected subset of jE7 such that for each there exists which cannot be extended to a
holomorphic
function in a
neighbourhood of $.
Then theholomorphic
hull of each com-
pact
subset .g’of U, Ku,
is acompact
subset of U andd (K, CU) =
.11
=d(KU,CU)
In the next two lemmas we concern ourselves with
topologies
on(see [5], [7]
and[16]).
LetTo
denote thecompact
opentopology
and let T denote the
bornological topology
associated withTo (see [7]).
Since
To
iscomplete (see [16]),
T is alsocomplete
and barrelled.LEMMA 6.
Let xn
E IT for n= 1, 2,...
and suppose supIf (Xn) !
oo forn
I
defines a continuous semi-norm onn
(Cfl (U), T).
PROOF. Let
Bp
=( f ) S 1}.
ThenBp
isabsorbing (by hypothesis)
and since
Bp = f 1 { f ;|f(xm) 1}
it is closed and convex. SinceT)
p
is barrelled this
completes
theproof.
LEMMA 7. Let p be a continuous semi-norm on the space
(U), T)
and suppose is an
increasing
sequence of open subsets of U such00
that U
Vn
= IT then there exists apositive integer
no andC >
0 such thatn=l
PROOF.
Suppose
the result is not true. Then for eachpositive integer
n we can choose such that and
sup If, (x) I .,- 1/n.
x E V n
The sequence 1 is a bounded subset of
(ge (U), To)
andconsequently
of
(9l (U), T) but p ( fn)
as rc - oo which is a contradiction.SEOTION 2.
THEOREM
(Cartan-Thullen I).
Let U be a connected open subsetof
theBanach space E. For the
properties
listed below we have(1)
=>(2)
=>(3)
->(4)
->(5)
=>(6). (2)
=>(1) if
.E isseparable
but this does not holdfor arbitrary
E.(1)
U is a b-domainof holomorphy
(2)
Foreach ~
E 8 U there existsf E geb ( ~ )
which cannot be extendedanalytically
to aneighbourhood of ~.
(3)
It isimpossible
tofind
two open connected subsetsU1
andU2 of
E such that :
(a)
U flU, :) U2 ~
Q~ andU.-~ Ui
(b)
For everyf
E9(b ( IT)
there exists anf,
E such thaton
U2
(4) If
.8 is U-bounded thenBu
b is U-bounded and d(B, eU)
== d(BU,b , CU)
(5) If
B is U-bounded thenBUb
is U-bounded.(6)
For each sequenceof
elementsof
U such that~n E
8 ~Tas n --~ oo there exists
f
E( U)
such thatsup I f (~n) I
00.n
PROOF.
(l)-->(2)->(3), (4) _> (5)
and(6) => (2)
are obvious.Suppose (5)
holds and(6)
does not. Then there exists a sequence,n= 0 ,
of elements of U such thatE 6
U as n --~ oo andsup f (~n)
n
for all
f E Qtb ( ~ ).
Now endowed with the
topology
of uniform convergence on U-bounded sets is a Frechet space and themapping f -~ f (~~,) ( f E geb (U))
is continuous with
respect
to thistopology
for each n. Hence p( f )
== sup f (~n) ~ 1
defines a continuous semi-norm on and thus theren
exists B c
U,
U-bounded and0 >
0 such thatfor all
f E Hb ( U), By using
the fact thatHb ( U)
is analgebra
weeasily
show that C can be taken
equal
to 1.=
Therefore for each n which contradicts the fact that
Bu, b
isU-bounded,
Hence(5)
>(6). (3)
->(4) by
lemma 4.673
In
[12]
there is anexample
of a Banach space whose unit ball is nota b~domain of
holomorpby.
Thisgives
anexample
in which(2)=~=>(1).
We
complete
theproof by showing (4)
==>(1)
if ~ isseparable.
SincejE7 is
separable, U
contains a countable dense subset M. Let(~~)~ 2
be asequence of elements in M
containing
eachpoint
in Minfinitely
often. Foreach $n
letAn
be the open ball withcentre ~n
and radiusd (8n , eU).
If(4)
holds we can constructby
induction a sequence of U-bounded sets and a sequence(Zn)::2
ofpoints
of II with thefollowing properties :
1) ~==~=~
2)
,n+l E3) Bn
is anincreasing
sequence and each abounded set is contained-
in some
Bu . (This
ispossible
since deU)
= 0 and d(Bn,
a, b,> 0).
By
construction we can choose such thatsup [ fn (x) I ~ 1/2n
XE Bn and
for all n and for each m, we have
Hence
f (zn)
as n - oo. Thisimplies
thatif ~ E
6 U and 8>
0 is ar-bitrary
Thus
f
has no extension as aholomorphic
function to alarger
subset of .E than U. Thiscompletes
theproof.
As
regards qe ( U)
we do not know if the converse to lemma 5 is true even if E isseparable.
We now prove some resultsabout ck ( U)
similar totheorem 1.
THEOREM
(Cartan-Thullen II).
Let U be an open connected subset
of
theseparable
Banach space E then thefollowing
areequivalent
(1)
U is a domainof holomorphy
(2)
There exists anincreasing
sequenceof
U-boundedsets, (B~,)~ Z ,
suchthat
Bn
= and eachcompact
set is contained in the interiorof
someBn.
PROOF.
Suppose (1)
istrue;
then there existsf E c?t ( U)
which has Uas its natural domain of existence. For each
compact
subset K of U chooseoc
(K) >
0 such thatf
is bounded on .g-~-
2a(K) B1 .
The sets K+
a(K) Bi
cover U as K ranges over all
compact
subsets of ~7. Since E isseparable
we can choose a sequence of
compact
subsets of U such thatU =
(Kn +
oe(Kn) B,).
Now let~
= inf. (z and define =t~~
=
(Kn +
cx(Kn) Bl).
ThenBn
is anincreasing
sequence of U-bounded sets andf
is bounded onBn + P,, Bl.
Lemma 2implies
thatf
is holomor.-
phic (by analytic
continuation ifnecessary)
onBn, u + BnB1
I Sincef
has U=
as its natural domain of existence this
implies d (Bn,
U,eU) >
0. SinceBn
is U-bounded for each n this means thatBn, u
is U-bounded for each n.Each
compact
subset of U iseasily
seen to be contained in the interior of-
some
Bn.
Tocomplete
theproof
we note that the sequenceBn,
u has allthe
required properties.
(2)
==>(1)
This isquite
similar to theproof
that(4)
=>(1)
in theprevious
theorem. Let be the sequence of U-boundedgiven by hypo-
thesis. Let M be a countable dense subset of U and take
($n)n’-2
as a sequence of elements in Mcontaining
eachpoint
in Minfinitely
often. Foreach n
letAn
be the open ball withcentre n
and radius Let0 2 = B 2
and choose
(this
ispossible
since~(A~6~7)===0
andB2
isU-bounded).
Suppose C2 Cn and Z2
... , zn have been chosen. Choosekn+i
suchthat
On,
Zn E LetOn+,
= and choose z,,+, E n For each n there existsIn E (M (U)
such thatThe function
f
= Eg{ ( U)
and has U as its natural domain of exi- stence. Hence(2)
>(1).
The
example quoted
in theorem 1 also shows that theseparability
condition was essential in theorem II.
THEORFM
(Cartarc-Thullen III).
Let U be a connected open subset
of
a Banach space E then thefollo- wing
areequivalent :
(1)
Foreach $
there existsf E 9l (U)
which cannot be extended toa
holomorphic function
in aneighbourhood of ~.
(2)
For each sequence,(En)oon= 1, of
elementsof
U which converges to somepoint
in 6 U there existsf
EcY ( U)
such thatsup I f I =
00.n
675
PROOF.
(2) ==> (1)
is obvious. We now show if(2)
is not true then(1)
is not true.
If
(2)
is not true there exists a sequence, of elements of U which converges and such thatsup I
oo for allf E
n
By
lemma6 p ( f )
=sup is
a continuous semi-norm on(9t (U), T).
n
Let
f E
bearbitrarily
chosen. For eachpositive integer n
letis an
increasing
sequence of subsets of U and U.By
lemma 7 there exists no and C such that
’
-
Since 9( (U)
is analgebra
we can take C = 1 andhence
E for eachn.
By
our choice of theVn’s, f
is bounded on aneighbourhood
ofLemma 2
implies f
can be continued as aholomorphic
function in a1/no neighbourhood of $n
for each n and hence in someneighbourhood
of~.
This
completes
thisproof.
If the closed bounded subsets of .E’
(the
dual ofE )
areweek*-sequen- tially compact
condition(2)
of the last theorem can bereplaced by
thefollowing equivalent
condition(see [8]).
(2’)
For each sequence,(~~,)~ 1,
of elements of U which has no limitpoint
in IT there existsf E qe (U)
such thatIn
particular (2’)
>(2)
if .E isseparable
or reflexive.I would like to thank Professor
Leopoldo
Nachbin forsuggesting
theproblem
to meoriginally
and Professor John Horváth for a number of in-teresting
conversations on thissubject.
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The Johns Hopkin8 University