Weighted
U
-frequent hypercyclicity
Céline ESSER [email protected]
University of Liège – Institute of Mathematics
Lens – October 24, 2018
Joint work with
Introduction and statement of the problem
LetT : X → X be a linear operator (X separable Banach space,dim X = ∞).
• TisU-frequently hypercyclic (ufhc)if∃x ∈ X such that∀U 6= ∅open
d {n ≥ 0 : Tnx ∈ U } > 0 .
The set of such points is denotedUFHC(T )(Shkarin 2009).
• Tisreiteratively hypercyclic (rhc)if∃x ∈ Xsuch that∀U 6= ∅open
Bd {n ≥ 0 : Tnx ∈ U } > 0 .
ForE ⊆ N, the densities used are
• the upper densityd(E) = lim sup n→+∞
# E ∩ [0, n]
n + 1 • the upper Banach densityBd(E) = lim
k→+∞lim supn→+∞
# E ∩ [n, n + k]
k + 1
One hasd(E) ≤ Bd(E)hence
T ufhc =⇒ T rhc
but one can prove thatTrhc ; Tufhc (Bès, Menet, Peris, Puig 2016)
Weighted upper densities
Leta = (an)n∈Nbe a sequence of positive real numbers such thatP
n∈Nan= +∞.
Thea-upper densityof a setE ⊆ Nis defined by
da(E) = lim sup
n→+∞ n X k=0 ak1E(k) n X k=0 ak
An operatorTisa-upper frequently hypercyclic (ufhca)if∃x ∈ X such that∀U 6= ∅
open,
da {n ≥ 0 : Tnx ∈ U } > 0 .
The set of such points is denotedUFHCa(T )and is a residual set
Remarks
• If an
bn & 0, thenda≤ db. Hence ufhca⇒ufhcb (Ernst, Mouze 2017)
• Ifan= 1for alln ∈ N, thenda= d. Hence ufhca⇔ufhc
• Letνn= an
Pn−1
k=0ak
. If there isC > 0such thatνn ≥ Cfor alln ∈ N, then
da(E) > 0as soon as#E = +∞
Consequences
• (H1) We consider sequencesa = (an)n∈Nsuch thatan % +∞ • (H2) We impose thatνn& 0
Example 1
For anyα > 0, the sequence(nα)n∈Nbelongs toA:
• nα% +∞ • νn= Pn−1nα k=1kα ∼ nα nα+1 & 0
Example 2
For anyα > 1, the sequence(αn)n∈Ndoes not belong toA:
νn= αn Pn−1 k=1αk = α n α−αn 1−α = (1 − α) 1 α1−n− 1 → α − 1
Comparison of the densities
Result
• For everya ∈ A, one hasd ≤ da.
• For everyα > 0, the sequencea = (nα)
n∈N∈ Asatisfies 1
1 + αda≤ d ≤ da.
Consequence
For every operatorT, there isa ∈ Asuch thatUFHC(T ) = UFHCa(T ). In particular,
UFHC(T ) = \
a∈A
UFHCa(T )
and
Result
• For everya ∈ A, one hasda≤ Bd.
• Let(Ek)k∈Nbe a sequence of subsets ofN. There existsa ∈ Asuch that
Bd(Ek) ≤ e da(Ek) ∀k ∈ N .
Consequence
For every operatorT,
RHC(T ) = [
a∈A
UFHCa(T )
and
IfT is rhc, thenRHC(T ) = HC(T )(Bès, Menet, Peris, Puig 2016)
Result
For everya ∈ A, one hasUFHCa(2B) 6= HC(2B).
However, ifT is rhc, then
HC(T ) = [
a∈A
UFHCa(T )
Chaos and ufhc
aOne has(Menet 2017) • chaos⇒rhc
• chaos;ufhc
Result
For everya ∈ A, there is a chaotic operator on`1which is not ufhc a.
Product of operators
Question: Given an operatorTwhich is ufhc / ufhca/ rhc, what can we say about the
operatorT × · · · × T?
Result
IfT is ufhca, thenT × · · · × T is ufhca.
Keys:(using ideas from Bayart, Rusza 2015&Bès, Menet, Peris, Puig 2016) • ufhca⇒weakly-mixing
• Ifda(E) > 0, then there isδ > 0such that the set
k ≥ 0 : da E ∩ (E − k)) > δ
is syndetic
Consequence
Main references
F. Bayart and I. Z. Ruzsa
Difference sets and frequently hypercyclic weighted shifts
Ergod. Theory Dyn. Syst.,35, 691–709, 2015.
J. Bès, Q. Menet, A. Peris and Y. Puig
Recurrence properties of hypercyclic operators
Math. Ann.366, 545–572, 2016.
A. Bonilla and K-G. Grosse-Erdmann
Upper frequent hypercyclicity and related notions
Rev. Mat. Complut.,31, 673–711, 2018.
R. Ernst and A. Mouze
A quantitative interpretation of the frequent hypercyclicity criterion
Ergod. Theory Dyn. Syst., https://doi.org/10.1017/etds.2017.55, 2017.
Q. Menet
Linear chaos and frequent hypercyclicity
Trans. Amer. Math. Soc.369, 4977–4994, 2017.
S. Shkarin
On the spectrum of frequently hypercyclic operators