A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
A LBERT E. H EINS
A boundary value problem associated with the Tricomi equation
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 3
esérie, tome 19, n
o4 (1965), p. 465-479
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WITH THE TRICOMI EQUATION
by
ALBERT E. HEINSI.
Introduction.
We shall be concerned here with aboundary
valueproblem
associated with thegeneralized Tricomi equation,
thatis,
withwhere Re
lh0, although
we shallonly
discuss the case inwhich
Re~,>
0. Whenthe
parameter m
is apositive
and eveninteger,
theequation (1.1)
iselliptic
in the x, a
plane.
On the otherhand,
when m is odd andpositive,
thisequation
is eitherelliptic
orhyperbolic depending
on whether a ispositive
or
negative.
Theboundary
data wesupply,
will begiven
on the line o = 0and we shall be concerned here with the
elliptic domain,
that is 0. Inthis case, the
only
restriction on nt is that it bepositive.
Theexample
weshall consider in detail
supplies 4p (x, a)
for 6 =0,
xC
0 and2013*-
for a igo
= 0,
xh 0. Here werecognize
that we aredealing
with aboundary
valueproblem
which is ageneralization
of a classicalexample
in two dimensional diffractiontheory. Indeed,
for m =0,
the above data(save
for conditions atinfinity) provide
information forformulating
the celebratedbalf-plane problem
of diffraction
theory.
Such a
problem
as we have described above falls in a classrecently
considered
by
C. C.Chang
and T. S.Lundgren [1]
and W. E. Williams[2].
These writers observed that since
equation (1.1)
has a variable coefficient whichdepends only
on a, that Fourieranalysis might
beapplied
withrespect
to the variable x.Aspects
of thisanalysis
havealready
been discussedPervennto alla Redazione il 15 Marzo 1965.
1 della sup.. Pisa.
by
P. Germain and R. Bader[3].
For the case describedabove,
weexpect
that the method of Wiener andHopf
would beavailable, although
it would be difficult to
justify
it for the case Å. = 0. As we shall see,however,
there is no need for suchmachinery.
Infact,
if we take into accountA. Weinstein’s
[4]
basic remarka on the Tricomiequation
and its fundamen- tal solution and R. J. MTeinacht’s[5]
discussion for the case Å.# 0,
as wellas the recent function theoretic efforts of R. C.
MacCamy
and thepresent
writer[6, 7],
we shall see that theboundary-value problem
we have described issusceptible
to the methods ofanalytic
functiontheory. Indeed,
the finalresults appear in a form which is different from the results of Williams and has the added
advantage
ofbeing justifiable
as well as somewhatsimplified.
The method we
employ
here wasinspired by
one of the earliest funda- mental papers onsingular integral equations
of T. Carleman[8].
A distinc-tion which occurs between Carleman’s method and the one we
employ
isthe
following.
While he converted an Abeltype integral equation
with con-stant limits into one which
depends
on variable limits which could be solvedexplicitly,
we havearranged
matter so that there is no need to solve anintegral equation.
The solution of theboundary
valueproblem
is reduced to the determination of ananalytic
function in terms of data to be foundon the line o =
0,
- Theintegral equation
we derive servesonly
toprovide properties
of theanalytic
function.II.
Preliminary Reduction of Equation (1.1)
and onIntegral
Re-presentation.
In order to reduceequation (1.1)
to a more tractableform,
we take
advantage
of the fact[4]
that it may be cast into anaxially
sym- metric waveequation by
thesubstitution y
= Aaa where a =(2 + w)/2
andA =
1/a.
With thischange
ofvariables,
we have forequation (1.1)
where lc =
m/(m + 2)
and ~2 > 0.We now ask whether we can find a
representation
for a solution of thisequation
in thehalf-plane y
> 0 in terms of theboundary
data on theline y = 0. Let us recall that Weinstein
[4]
hasgiven
the fundamental solution ofequation (2.1)
in the case A =0,
while vVeinaclJt[5]
hasgiven
it for the case in whicli I is pure
imaginary.
The modification for the pre- sent case is direct.Indeed,
the functionwhere cos
(X ]1/2
is such a function. Hereu
The function
KJI (x)
is the MacDonaldfunction,
that is it is asingular
so-lution of the
equation
Indeed
if for v >0, equation (2.2)
has a solutionIy (x)
which vanishes at theorigin
when v~ 0,
we may defineThis fundamental solution of
equation (2.1)
has thefollowing
threeimpor-
tant
properties :
(i) The y
derivative of Z vanishes for y = 0.(ii)
Z has alogarithmic singularity
at x =x’, y = y’
and it therefore has anonvanishing
« residue » in the sense of two-dimensionalpotential theory.
This leads us toexpect
arepresentation
theorem of the Helmholtztype,
thatis,
the case iii = 0.(iii)
Forx’, y’
finite and IZ(x,
y,x’, y’)
isasymptotic
toA similar form exists upon
interchanging x, y
withx’, y’.
This functionZ
(x,
y,x’, y’)
which we havegiven,
can be constructedalong
linessuggested by
Weinacht[5] J
and avoids themachinery
of the Fourierintegral
theorem.simple
form of Z(x, y, x’, y’)
isnoteworthy
and it assumes an evenmore
simple
oneat y
= 0.In order to derive the
representation theorem,
we rewriteequation
(2.l )
as - -and observe that Z satisfies the same
equation
save at thepoint
x =x’,
y =
y’.
W’e form the surfaceintegral
over an area bounded
by
the exterior closed curve C which is aportion
of the x axis and a circular arc whose center is at the
point
P(x’, y’) (y’ > 0)
and of radius R. The interior closed curveC,
is a circle of radiuse
y’
and center at thepoint
P(x’, y’)
isdeleted,
of course, because of thesingularity
which Z possesses at thispoint
and thereforeprevents
adirect
application
of Green’s theorem to the entire area interior to C. We shall assume,henceforth, that cp
is twicecontinuously
differentiable in the entire area insideC,
and it is clear from the structure of Z that such is the case, save in theneighborhood
of thepoint
P(x’, y’).
Theintegral (2.3)
can now be written as the sum of two line
integrals
and because of the
regularity properties
of Z and lp, this lineintegral
vanishes. The
path
C is traversed in a counter-clockwise sense, whileC,
istraversed in a clockwise sense. The normal derivatives are exterior ones
and s is the
arc-length parameter along
C and°1,
We first ask what is the effect of
permitting E
- 0. Sincewhere y +- 0, y’ #
=((x
-r’)2 + (y
-y’)2]1/2 and Q (x, y)
is a functionwhich may be
neglected
whencalculating
the «residue >>,
we obtain thefollowing along Cl .
Weparameterize C1 by writing x
= x’+ 8 cos 9, y
==
y’ + 8
sin 0 with 0 ~ 0 C 2~ and note that ds = e d9. Then sinceyk
===
(y’)k
and E In e --~ 0 as E --~0,
the first lineintegral over 01
vanishes.The second line
integral
over01
has the limitOn the circular arc of radius R we shall assume that the
leading
termsin g~
(x, y) satisfy
a « radiation condition » when R 2013~ oo. Thatis,
uniformly
for all 0 = arctany/x,
y > 0. This radiation condition isadequate
to eliminate the contribution
along
the circular arc of radius .R as R- oo.It may be noted that the above
asymptotic
condition is the same for thefundamental I solution.
Since
on y = 0 (or (} = 0)
and sinceon y =
0,
theintegral along
the x axis takes the formin the --~ oo. Hence we have the
representation [9]
upon
interchanging z
andand y’ by y.
If~a ~~~, 0)
is known for- oo
x
we have a means ofcalculating p (z, y)
for all xand y
since this
representation
is evenin y. However,
for theproblem
we wishto
~~~ 0)
is known for x C U and(x, 0)
is known for x ~> 0.Hence
(2.4) provides
anintegral equation
for the unknown function If.(x, 0),
x - 0.III. The
Boundary Value Problem
and itsSolution.
On the line y =0, equation (2.4)
becomes arepresentation for 97 (x, 0)
in terms of f/’.(x, 0).
Indeed we have
where
and k =
+ 2) C
1 since m is a realpositive
number. Since w> 0)
the kernel of the
integral equation (3.1)
isintegrable
in theneighborhood
of the x’. It’ if.
(x, 0)
is known for - oo we have arepresentation
forfinding (p (x 0).
If on the other hand weassign 9’ (x, 0)
_= f (z)
andg~a (a~~ o) = o~ (x) equation (3.1)
becomes anintegral equation
for fl.jx, 0).
C0,
we haveIf we know the first
integral
in(3.2)
forx > 0,
we have a means of com-puting
99(x, 0)
for x>
0by equation (3.1). Further,
it ispossible
to find(p
(x, y), y >
0 in thelarge by
the Poissontype representation [10]
where 2v = k and which
incidentally requires
the continuationof 99 (x, 0),
- oo
C x cxJ
into thecomplex
domain. A further alternative is available in that we may solve anintegral equation
of the Abeltype
for(x, 0)
and may therefore use
equation (2.4)
tofind cp (x, y)
in thelarge.
We shall concentrate our efforts in this paper on
finding
the unknownportion of (p (x, 0),
that is for x > 0.Following Carleman,
we introduce ananalytic
function 1~(z)
which isregular
in theplane
cutalong
thenegative
real axis and is
given by
theintegral
Let us assume~ for the time
being,
that there does exist anappropriate
tpu
(x, 0),
x 0 which willproduce
such a function ~’(z)
andinquire why
such a form was chosen.
Clearly
forx > 0, y = 0,
aknowledge
ofwill
give
us 99(x, y)
x > 0. Infact,
for x > 0From this we see that there are immediate
integrability requirements
ong (x), although they
are notparticularly
severe in thelight
of the asymp- totic form of -+ oo.We now define the
following limits, assuming
for thepresent,
thatthey
exist. Let
an(I
These limits are, of course,
dependent (x, 0)
for xC 0, .
a functionwhich we do not know
yet.
For xC
0and
Upon simplifying
theexpression for F (x + i 0)
and . -’ weget
and
The
integral equation
isequivalent
towhere V (x)
is a known function whichdepends
onf(x) and g (x).
Itis
possible
to eliminate allintegrals
in these last threeequations
and ob-tain a linear relation
F (x - i 0) and 1p (x)
which will be valid for xC
0. We obtain thusA
simplification
can be effected if weput F(z) = z" 4Y (z) where fl
willbe
ultimately
chosenconveniently.
The branch which we choose is cutalong
thenegative
realaxis,
so thatand
Hence
equation (3.5)
becomesIf we now choose
2fl + k
=1, equation (3.6)
becomesand
Hence we have information
regarding 0
on theline
= 0 which will enable us to determine 0(z),
once we know the behavior of 0{z)
atinfinity.
This,
of course, can be determinedby
a carefulstudy
in the closed sector S arg zC ~z, recalling
theassumption
westipulated
for(x, 0),
x o.Indeed,
find[6,7]
that possesses anexponential
factor exp
(- lz)
in this closed sectorof j z 1-»-
ooand
we eliminate itby writing
so that we
get
and
Now since P
(z)
=F ~z)
z-fl exp vanishesfor I
we can determine it with the aid of a
Cauchy type representation
asor
where B (z)
is an entire function.We have not
yet put
down any conditions onf {t),
t 0and g (t),
t>0.
Without
these,
we cannot demonstrate thevalidity
of ourcalculations,
forexample
that theF(z)
we found possessesappropriate properties
whichwill
generate
anacceptable (x, 0), x
0. We shall devote the next sec-tion to a discussion of such
questions.
IV. Verification. Before we can demonstrate that the we have
given
in(3.12)
is anacceptable
one, it is necessary tosupply
some condi-tions
for f (t) and g (t)
which will insure the existence of certainintegrals.
We also
require
some conditions which willgive
us some information aboutF (x) for x ~ ~ 0 and
Such information will enable us to deter- mine theasymptotic
behaviorof 9) (x, 0)
for x -~ 0- and x -+ oo as wellas well as some of the
properties
of(x~
0) when x -~ 0-’ and x -~ - oo.One such set of conditions will be
given
but it will be clear that others may be found. We shallonly
treat the case for which0).
To include this term will
only
lead us to some detailedanalysis
which willnot add any
interesting
ideas.We start
then, by examining
the behavior of the functionfor 2013>-
02013~
= 0. Let us note that theintegral
is either aStieltjes
transform and is a function of thecomplex
variable z or it may be viewed as a Hilbert transform when y = 0.Suppose
thatf {- t)
isreal, quadratically integrable
for 0 ~ t ~ oo and E C’ and furtherthat f (- 0) = A
i(a constant).
Then a directapplication
of the Schwarzinequality guarantees,
in view of the restriction on
~3,
the existence of theintegral
for all
positive
t. W’e denote the limit of’ thisintegral
as t --~ 00by A2 .
Since we may define
f (- t)
=0,
for tC 0,
w-e observe that,f (- t)
t-fl exp(- Ar)
isquadratically integrable along
the entire t axis and therefore theintegral
in(4.1)
defines aquadratically integrable
function almosteverywhere
for real
z (11,
p.121].
This assures that theintegral
in(4.1)
vanishes for~x~--~oo~y=0.
We can,
however,
obtain moreprecise
information with ourhypotheses
on
f (- t). According
to an Abelian theorems for theordinary Stieltjes
trans-form
[12,
p.185] (that is,
theintegral
in(4.1) with y = 0, 0)
we havethat the
integral
in(4.1)
isasymptotic
to x - 0+ and toB2 x-1,
x -+ oo where
B,
andB2
are known constants.lience,
we have thatand
It follows that
F1 (x)
=0) obeys
the « radiation condition » whenx ~ -~- oo .
It ispossible
to carrythrough
this discussion for Acomplex
and
suitably limited,
that is Re 1 ~ 0 but we shall not pursue these details here.Further information is available from the
theory
of theordinary Stieltjes
transform. Let us suppose that arg z
[ ~.
Then theintegral
in(4.1)
converges and in fact
represents
asingle-valued analytic
function of z which has a cutalong
thenegative
realaxis, provided
thatf’ ( - t)
is subject
to the conditions we gave For ,1) real andnegative,
we have anof the
limiting
value of aCauchy type integral
from which we may derivefor x 0
and
The
integrals
are taken in the sense of theCauchy principal
value.We shall have need of the
asymptotic
behavior of(4.1)
in the limitx -
0- , (y
=0),
since as weshall
seepresently,
it will be needed to pro- vide informationregarding
the behavior of era(x, 0), x ~
0. In order to de- termine thisbehavior,
we writewhere 0
C - x
C 2. The lastintegral
isclearly
0(1)
as x - 0-. The se-cond
integral
may be examined with the aid of thetheory
of Abelian asymp- totics of suchprincipal
valueintegrals.
W’epllt t
= 1+ 1
and - x = 1+ (.
Then
We may write
f (---
1 -r)
=At 1 -~-
0(1)
where 0(- 1)
= 0. If we now im-pose the additional
requirement
on 0(1),
that itobeys
a uniformLipschitz
condition of
positive
order E> fl,
we mayapply
Tricomi’s discussion toget
Now we have information which win enable us to
examine (p, (z, 0)
for
x C 0
andE (z).
Tobegin with,
we note thatThis relation
implies
that(z),
an entire functionof z,
varnishes atinfinity
and therefore vanishes
everywhere.
HenceFor x
0,
we haveUpon using
the definition of terms ofIk’/2
êuulAbel-type integral equation
for(x, 0),
that isIn the
neighborhood
of the left side of theorigin,
that is a? 2013~0-,
B
(sin kn/2)f(x)
= B(sin kn/2) A1 +
0(x),
while the termcontaining
theprincipal
valueintegral
isequal
to - B(sin lcn/2) At +
0((- x).81.
Hencethe
right
side of theequation (4.4)
is x -~ 0-. From these remarks we may conclude that(x, 0)
isintegrable
in theneighborhood
of the
origin,
that is as x -0-.
We are now left with the task of
describing
lpa(x, 0)
when x - - oo.In order to do
this,
we note thatis
asymptotic
towhen x - oo and D is a known constant. The x
dependence
agrees with that ofF, (x)
when x --~ oo~ so that we are left with theimplication
that theintegral
exists. Thus
(t~ 0)
cannot have anexponential growth
which exceeds exp(- 1t),
t -+ - oo and indeed may be less than this. If we nowreplace x
by -
x and tby - t
inequation (4.4),
it will assume a more conventional ibrin from which we can read off some of theproperties
of(A).
Let us observe that the unilateral
Laplace
transform ofIk/2 Plot),
that isis
analytic
in theright-half plane
Re s> ~,
> 0 of thecomplex
spla,ne,
while the first and second terms on the
right
side of theeqaation
haveunilateral
Laplace
transforms which areanalytic
in theright
halfplanes
Re s
~
0 and Re s> ~, respectively.
Hence the unilateral transform of(- t, 0)
isanalytic
in theright half-plane
Re s>
A. This transform in turn can berepresented
as thequotient
of two unilateralLaplace
trans-forms and is t’l
(s~-1)
for Re s>
1and 8 1-+
00.Since fl 1,
I thisquoti-
ent vanishes at
infinity
in this halfplane.
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Équations
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This work was ill part by tlte Air Furce Office of Scientific
The uf Michigan
Ann Arbor, ltichigctrr, U. S. ~-1.