C OMPOSITIO M ATHEMATICA
J AN B RINKHUIS
On a comparison of Gauss sums with products of Lagrange resolvents
Compositio Mathematica, tome 93, n
o2 (1994), p. 155-170
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On
acomparison of Gauss
sumswith products of Lagrange
resolvents
JAN BRINKHUIS
Erasmus Universiteit, Econometrisch Instituut, Postbus 1738, 3000 DR Rotterdam, Netherlands Received 13 February 1991; accepted in final form 3 August 1993
Introduction
Kronecker’s classical determination of the
quadratic
Gauss sumproceeds by comparison
with theexpression ns(e21tis/p - e-21tiS/p)
where sruns over all odd natural numbers p. The relation is
simple:
the twonumbers are
equal.
Moregenerally,
for a Gauss sum of a character modulo p oforder n,
there is a naturalgeneralization
for theexpression above;
it isthe
product
of certaincyclotomic integers
which arise asLagrange
resol-vents. This
product
is called a norm resolvent. Here the relation is not sosimple.
A. Frôhlich has found aninterpretation
for this lack ofsimplicity:
he discovered a connection between the
quotients
of norm resolvents and Gauss sums, and the relative Galois module structure of thering
ofalgebraic integers
in thecyclotomic
fieldQ(e21ti/p)
over the subfield K overwhich
Q(e21ti/p)
hasdegree
n.In this paper we
bring
a newobject
onto the scene and relate it to thesequotients
and to this Galois module. It is an element of theintegral
groupring
R of acyclic
group oforder n,
the coefficients of which count certain transversals of thesubgroup
of order n in thecyclic
groupFp*
or,equivalently,
the number ofpoints
on certain varieties over the finite fieldFp.
We fix n and let p vary over allprime
numbers n 1 mod n. If we takethis
point
of view the newobject gives
an element in the groupring
R foreach
prime
p ofQ(e21ti/n)
of absolutedegree
one. This suggests to search fora
global object
which’glues
themtogether’.
We have made a first step in this directionby defining
groupring
elements forarbitrary prime
ideals inQ(e21ti/n)
which arerelatively prime
to 2n. Moreover we relate these elements toappropriately
definedquotients of ‘generalized
norm resolvents’and Gauss sums.
A further
problem
which we consider is whether thequotients
of normresolvents and Gauss sums can sometimes be
algebraic
units. Thisproblem
is
suggested by
the connection with Galois module structure.Finally
wemention that
by
now there is an extensive literature on thequotients
underconsideration
(for example [F], [G], [H]
and[L])
and that for someknown results we
provide
directproofs.
A. Frôhlich introduced me to these
intriguing quotients
many years ago.My
work on them did not appear inprint,
butthey
have been a source ofinspiration
to me ever since and this has led(sometimes indirectly)
to anumber of other results which have been
published
in various papers. It isa great
pleasure
to thank Ali Frôhlich for all hishelp,
for manystimulating
’Covent Garden discussions’ and
specially
for hisnon-abating
insistencethroughout
the years that awrite-up
should beproduced.
Also 1 would liketo
acknowledge
many conversations on Galois modules with Adrian Nelson and thehelpful
comments of Colin Bushnell who read anearly
draftof this paper.
l. Three
objects
ofstudy
In this section the three
objects
ofstudy
of this paper are introduced. Let n G Fl begiven.
Let QC be analgebraic
closure ofQ,
the field of rationals.For each
integer d
let ,ud be the group of d-th roots ofunity
in QC. Let p be aprime
ofQ(/ln)
withp ~ n.
l.l The relation between norm resolvends and Gauss sum elements
Let Y =
Z[/ln]/P
be the residue field of p. The naturalsurjection
fromZ[Pn]
to Y maps Mninjectively
to Y We view Un as asubgroup
ofY*,
themultiplicative
group of Y Thesymbols
S and T will be used to denote transversals of Mn inY*,
thatis, S
resp. T is acomplete
set of cosetrepresentatives
in Y* of thequotient
groupY*l03BCn. Let p
E- N be the rationalprime with p ) p.
Let m= #(y* //ln)’
thatis,
moreexplicitly,
m =
(pf(plp)
-1)ln
wheref(p ) p)
is the absolute residue classdegree
of p.Let §
be a canonical additive characteron Y,
thatis,
is thecomposition
of the trace map Tr from Y to
Z/p
and someisomorphism j
fromZ/p
to pp.Z =
Z[/lnp]/pZ[/lnp]. Again
we may view /lnp as asubgroup
ofZ*,
themultiplicative
group of Z. For each finite abelian group A and eachcommutative
ring W
we let é9A denote the groupring
of A over R. Allgroup
ring
elements to be considered in this paper will be inside thering
QCG where G = T*. To
begin with,
we define thefollowing
groupring
elements.
As elements of /lnp
belong
both to 0’ and toZ*,
we have tostipulate
how these formulas are meant to be read:
y-’4f(y)
andx-’Vi(sx)
are meantto be elements of Z*.
We call
Ns
ageneralized
norm resolvend and r a Gauss sum element forreasons to be
explained
in Section 2. The relation betweenNs
and i is the firstobject
ofstudy.
1.4 Transversal
oj»
pn in Y*.For each transversal S we let
s(S)
E Y be the sum of the elements of S. Letp(S)
E Y be theproduct
of the elements of S. We define thefollowing
element in ZG.
For
simplicity
we do not indicate thedependence
of B on theprime p
in thenotation.
(1.6)
Let R be thesubring Z/ln
of QC G. So R is the groupring
of ,u" overZ,
not to be confused withZ[03BCln]’
thering
ofalgebraic integers
in thecyclotomic
fieldQ(/ln)’ Clearly,
for T a transversal theproduct p(T).
B liesin R and it does
only depend
on the choice of T up to a factor from /ln.This element
p(T).
B is the secondobject
ofstudy.
(1.7)
REMARKS. Let T ={tt,...,tm}
be a transversalof M.,
in Y*. Thecoefficients of B
essentially
count the number ofpoints
on varieties overfinite fields.
Namely,
if we writewith
b4 c- Z
foraIl ç E /ln’
then foreach j
onehas, by
definition ofB,
thatbç
is the number of transversals
of M,,
in Y* with sum 1 andproduct ç;
thatis,
itequals
n - m times the number ofpoints
over the finite field Y of theaffine
variety
which is definedby
thefollowing pair
ofequations.
1.8. Galois modules associated to certain relative
cyclotomic field
extensionsIn the rest of this section we assume moreover that the absolute residue class
degreef(p 1 p) of p equals
1.Then m = p -
1/n.
We define the relative extension of number fieldsN/K by
N =Q(0 with (
as defined in(1.2)
and[N: K]
= n. Let u be theisomorphism
from(7L/p)*
toGal(N/Q)
which is definedby C"(’)
=(x
for allXE(7Ljp)*.
Weidentify
/ln with the Galois group ofN/K by
thefollowing composition
ofhomomorphisms
For each number field Flet
(9F
be itsring
ofintegers. Now (9N
and itssubgroup (9KM.(
areby
Galois actionZJ1n-modules
and so is thequotient (!)N/(!)KJ1n. C.
Its structure is the thirdobject
ofstudy.
Theisomorphism
classof this module can be viewed as an element of the Grothendieck group
Ko T(ZJ1n)
of the category oflocally freely presented Z/ln-modules.
This isthe category of those modules M for which there exists an exact sequence of
Zp,,-modules 0 - P - Q - M - 0
with P andQ finitely generated, locally
freeZ/ln-modules
of the same rank(then
M isfinite).
Details aboutthe functor
KoT
can be found in[T].
2. The relation of
(()N/(() KJ.1n. ç
withNs
and TIn this section we recall some
general
fundamental Galois module results from[F]
for thespecial
extensions of number fieldsN/K
which we areconsidering
in this paper. We refer inparticular
to§1(b)
ofChapter
VI of[F].
In this section we assume, as in(1.8),
that the absolute residue classdegree of p equals
1.Let VQ
be thering
of adeles of Q. LetAc
be thering
of
integral
adeles of Q. The inclusion mapfrom pp
into Oc induces amorphism
ofrings
i fromQ/unp
toQC /ln.
For each number W E N we definethe element
Xso
EQC /ln by
thefollowing expression.
We observe that
JVJ
=i(Ns)
withJVs
as defined in(1.3).
LetÎln
be thegroup of all characters of ,u"; we extend each
XEun by 0-linearity
to amorphism
ofrings
from the groupring Oun
to thecyclotomic
fieldQ(,un);
we denote this
morphism
alsoby
X.(2.1)
THEOREM.(i)
There is a canonicalisomorphism n from KOT(ZPN)
to
the factor
group(VO,un)* I(A o/ln)*.
(ii)
The elementi( 1:)
is invertible in thering QC /ln and for
each w in(9N
theelement
JVsWi(1:)-t
is contained in the maximal Z-order in the0-algebra Uyn - (iii)
For each (J) c-(9N
one has that the(9K Pn-submodule of (9N generated by
w is a
free
module withfinite
index in(9N iff
N =K/ln.
co. Then this indexequals
theproduct of
thealgebraic integers X(Xs’ i(1:)-1)
where X runs overPn.
That is,(iv)
For eachwe (!)N
one has that(9N
=(!)K/ln. W if[ ..IV"scoi(-r)-t is a
unit inthe maximal order
of
the0-algebra GIÀ,,.
(v)
For eachWE (!)N
withN = K(/ln)’ w the
classof
theZJln-module (!)Nj(!)K/ln. W in Ko T(Z/ln) corresponds
under theisomorphism n of (i)
to theinverse
of
the classof
the elementJVscoi(-r)-t
in(Vo/ln)* j(A o/ln)*.
(2.2)
REMARKS.(i)
Later we willgive
a directproof
for(2.1)(ii):
seeRemark
(4.3).
(ii)
If n =2,
then(9N
=(9KM,,. ,.
See[F]
Ch.VI, §1(b)
for this and for the relation between this fact and the classicalsign
determination of thequadratic
Gauss sumby
Kronecker. For the latter we refer to[B-S]
Ch.5,
Sec. 4.3.
(iii)
It has been shown that(9N e (!)KJ1n
as(9KM,,-modules
if n is an oddprime (see [B]
and[Co]). Using
the theorem abovegives
that the element.Ksco i( -r) -
1 is not invertible in the maximal Z -order ofQJ1n.
(iv)
The case n = 4 will be studied in Section 8.(v)
Ourterminology
norm resolvend and Gauss sum element for.Ns
andi is
inspired by
the onegenerally
used in the literature on Galois moduletheory (see [F1]).
One can firstapply
the map i to these elements and thena character
XE Îln.
Theresulting algebraic
numberX(i(..IV"s))
=X(..IV"J)
resp.X(i(,r»
isprecisely
the norm resolvent of w, resp. the Galois Gauss sum, associated to the Galois character onGal(N/K)
which is defined as thecomposition
of theisomorphism Gal(N/K) ^_r p"
from(1.7)
and the charac-ter x. The verification of this fact is
straightforward
but would take toomuch space to
justify
inclusion of it in this paper.3. On the
question
whetherperiods
can bealgebraic
unitsIn this section we assume
again
that the residue classdegree f(p p) equals
1. The trivial
character BE Î1n
extendsby linearity
to theaugmentation morphism E
fromZ/ln
to Z. Frôhlich has raised thequestion
whether therational
integer B(i(JVs)i(-r)-l)
can beinvertible,
thatis,
whether it can beequal
to± 1.
We observe that in(2.2)(ii)
we have mentioned that the elementi(Ns)i(’r)-t
itself is not invertible in thering Zpn
if n is an oddprime
number. The sumY-,, C’
where x runs overM,,(Fp),
the set of n-th rootsof
unity
in the fieldFp,
isusually
called aperiod.
Thequestion
aboveamounts to the
question
whetherperiods
can bealgebraic
units. IndeedEx x = TraceN/K(
andas is
readily
verified from the definitions. Now we state our result.(3.2)
THEOREM. Assume that n is odd.(i)
For eachprime
divisor qof B(i(JVs)i(’r)-t),
one hasq :0
p and the leastcommon
multiple of
n andf (q),
the orderof
q mod p inFp*,
is a proper divisorof p - 1.
(ii)
There is at least oneprime
divisor qof t( i( JV s )i(’r) - 1) for
which theclass
of q
mod p has oddorder in F*
1 n
particular B( i( JV s )i( -r) - t)
neverequals
1: 1.Proof. (i) Let q
be aprime
numberdividing B(i(JVs)i(-r)-t).
It suffices toprove the
following
claim: there is more than oneprime
q of Klying
aboveq. Then
(i)
follows from theequivalence
of thefollowing
two conditions ona
prime
number q.(1)
There is more than oneprime
of Klying
above q.(2) q #
p and lcm(n, f)
:0 p - 1.The laws of factorization of
prime
numbers incyclotomic
fields arewell-known;
see forexample [Wa] (2.13).
It isreadily
verified thatthey imply
theequivalence
of(1)
and(2). Finally
we argueby
contradiction to prove the claim above. Assume that there isonly
oneprime
q of Klying
above q.
Then, by (3.1),
q divides allalgebraic conjugates
ofTraceN/K(.
Write
a = TraceN/K’.
As(9N == ZGal(N jQ) .,
it follows that(9K
=ZGal(K/0).
a. We have now shown that thealgebraic conjugates
of a forma Z-basis of
(9K
and thatthey
are ail divisibleby
q. This is absurd and so we arrive at therequired
contradiction. This finishes theproof
of(i).
(ii)
It suffices to prove thefollowing
claim:v,(a)
=vq(a)
for at least onefinite
prime
q ofK, where vl,
resp. V., denotes the valuationcorresponding
to q
resp. q
andwhere q
denotes thecomplex conjugate prime
of q.Indeed,
then it follows that there exists a finite
prime
q of K with q #q
andvq(a) #
0. Then(ii)
follows from theequivalence
of thefollowing
twoconditions on a
prime number q #
p.(1) Complex conjugation
c actsnon-trivially
on the set ofprimes
of Kabove q.
(2)
The orderf
of the classof q
mod p inFp
is odd.Again,
thisequivalence
can be derived from[Wa] (2.13).
Finally
we argueby
contradiction to prove the claim above. Assume thatvq(a) = vq (a)
for each finiteprime
q of K. Thenv,(aà-’)
= 0 for each finiteprime
q of K. It follows that aa-t is analgebraic
unit of absolute value 1 in the abelian extension K of Q. It is well-known that thisimplies
thataâ-1
is a root of
unity,
so, as PK= {± 1}, a
= ± â. On the otherhand,
we haveseen in the
proof
of(i)
thatimplies (!)K
=ZGal(KjQ) . a,
so thealgebraic conjugates
of a form a basis of theimaginary
abelian fieldK,
seen as avector space over Q. This contradicts a = + â. This finishes the
proof
ofthe theorem. Q
The
assumption
that n is odd in Theorem(3.2)
cannot beomitted,
as thecase x = B of the
following proposition
shows.(3.3)
PROPOSITION.Ifn = 4, then X(i(%s)i(-r)-t) =
+ 1for
eachof
thetwo X E /ln
for
whichX2
= 8.This result follows
immediately
from thefollowing
easy lemmatogether
with the fact that if X has order
2,
the numberX(i(-r»
is thequadratic
Gausssum and so has absolute value
/P.
Let h mod p be a root of X 2 + 1 = 0in
Fp.
(3.4)
LEMMA.(iv) If
T is a transversalof
then4. On the relation of B with
Ns
and iThe aim of this section is to establish the
following
formula in the groupring
ZZ* and some consequences of it. This section is without theassumption f(p p)
= 1.(4.1)
FORMULA.Proof.
(on multiplying
out and onusing
that S is a transversalof M,,
inY*)
(as
for eachy E Y* multiplication by y
induces abijection from
the set oftransversals T with
s( T)
= 1 to the set of transversals T withs( T)
=y)
Let ce ZC* be the formal sum of the elements of /ln’
(4.2)
COROLLARY.The following
relation holds between the elementsi{Ns), i(,r), p(S) .
B and cof
the groupring QC /ln’
(4.3)
REMARK. Thiscorollary gives
anexplicit proof
of statement(ii)
ofTheorem
(2.1)
in the case w =Ç.
In fact itgives
aslightly
stronger result: the elementi(Xs)i(-r)-’
1 lies in theintegral
groupring
R =7lJ.ln. Namely
c lies in7L/ln by
definition and we havealready pointed
out, in(1.6),
thatp(S) .
B lies inZ/ln.
Proof of Corollary (4.2). Applying
to formula(4.1)
thehomomorphism
fromZup
x Y* to ZY* which is inducedby
theprojection
map from ,up x Y* toY*,
one gets the
following
formulaCombining (4.1)
and(4.4)
to eliminate theexpression ET s(T)=O p (T)-’,
one getsthe
following
formula(taking
into account that c"’ = nm -1Ic).
Applying
themorphism
i to formula(4.5)
andusing
thefollowing identity
one gets the formula in the statement of the
corollary.
It remains toverify (4.6).
We do this
’componentwise’.
Let for each character X of /ln’ theprojection
ofQC /ln
to the component 0’ ofQC J.ln
whichcorresponds
to X, also be denotedby
X. We have to
verify
that for each X eitherX(c)
= 0 or 1 +x(i(i))
= 0. If X isnon-trivial,
thenclearly X(c)
= 0.If X
is the trivial character e, thenNow, by
thesurjectivity
of the trace map from Y toFp,
thehomomorphism it/1
from Y to /lp is
surjective; combining
this with the fact that the sum in Qc of /lp is zero, its follows thatEyEY 1§(y)
is zero. This finishes theproof of Corollary
(4.2).
nFinally
we record for later use thefollowing
formulas which follow from formula(4.1) by applying
suitable characters of /lnp to it.(4.7)
COROLLARY.where Tr denotes the trace map
from
Y toFP’
5. The relation of Jacobi sums with
-4§
and rFor each
character q5
of Y* its Gauss sum is definedby
For each k E N and for each
choice ’0 1 - - .,’Ok
of k characters of Y* onedefines the
following
numberThis number is called a Jacobi sum; the
study
of Jacobi sums has along history (see
A. Weil’s paper[We]).
An easy property is thatJ(O 1 - - - Ok)
is an
algebraic integer
in thecyclotomic
fieldgenerated by
the values of the charactersOj(l j k).
(5.3)
For eachcharacter X ofu,,,
let Xl,..., Xm be the characters of Y* which extend X, ordered in some way.(5.4)
THEOREM. For each character Xof
/lnthe following formula
holdswhere the summation is
only
carried out over thosem-tuples (jt,... ,jm) for
To prove this result we need the
following
formula(5.6)
LEMMA.for
each SE Y* and allcharacters X. of
/ln.Proof.
(using
that the inner sumequals mX(x) -
1 if x E /ln and that itequals
zerootherwise)
Moreover we need the
following
fact.(5.7)
LEM MA.If
theproduct
Xjt,.",Xjm is not the character then the numberis zero, where p runs over all
permutations of
theset {l,..., ml.
Proof.
For theproof
we may assumethat X
is the trivial character on /ln(for example by replacing
Xjtby XjtXï 1, Xj2 by Xj2xlt, etc.).
Then uclearly
does not
depend
on the choice of S. Moreover theassumption
of the lemmaamounts then to the
following
one: there is an element xe Y* withMultiplying
u with(Xj,...Xj_)(x)
one getswhere
again
p runs over allpermutations
of theset {l,..., m}. Clearly {xs t, ... , xSm}
isagain
a transversal of /ln inY*,
so theexpression (5.8)
isequal
to u,by
theindependence
of u on the choice of transversals. It followsthat u =
0,
asrequired.
D(5.9)
REMARK. If theproduct
of Xj1,,..., Xjm is the character z --X(zm),
then
r(Xj,,.... Xj_)
=X(i(-r» by
thedefinitions,
where r is the Gauss sumelement defined in Section 1.
(5.10) Proof of
Theorem(5.4).
where
(j 1, ... , jm)
runs over allm-tuples
of elements of the set{ 1, ... , m}.
Finaly
one uses Lemma(5.7),
Remark(5.9)
and Definition(5.2)
to finishthe
proof.
n(5.11)
REMARK. One cansimplify
theexpression
in Theorem(5.4) by taking
all termstogether
for which thesequence jl, ..., jm
is the same up topermutation:
these sequencesgive
rise to the same Jacobi sums. Thecoefficients of the Jacobi sums in the
resulting expression
are then rationalintegers.
6. On the
counting
of transversalsWe recall our convention that the variable T runs over transversals of /ln in Y*. In this section we compare the
numbers bo = # {Tls(T)
=01
andb = # {Tls(T)
=1}.
We observe that theright
hand side of theequality
in
Corollary (4.7) (ii)
can be written asbo - b 1.
We write(6.1)
PROPOSITION.(6.2)
REMARK. Inparticular
we get thefollowing
easy to state result: for each odd ordersubgroup
of themultiplicative
group of a finite field thereare more transversals with sum zero than with sum one.
(6.3)
REMARK.Knowing bo - b
amounts toknowing e(B)
=b 1.
Name-ly, by Corollary (4.7) (i)
one has nm =bo + #(y*). b i.
Proof of Proposition (6.1). (i) Combining Corollary (4.7) (ii)
with formula(5.5)
for the case / = c andusing
theestimate JJI qm/2,
which results from the fact that1-r(x)1
=qt/2,
one getsimmediately
the estimationIbo - bl
(ii) By Corollary (4.7) (i)
andby
thecongruence #(Y*) =- - 1
mod p onegets
bo - b 1 =-
nm mod p.(iii)
Assume that n is odd. First we prove that for any s the sumLXEJln (Tr(xs) is
not zero. Theonly
Q-linear relation of thep-th
rootsof unity is,
up to scalars fromQ,
the relation£§Il (j;
there are p terms in it andour sum consists of n terms and p does not divide n. Therefore
xEun ,Tr(xs)
# O.Now as n is
odd, - 1 e p,,,
so for each coset Rof ,un
in Y* =Fg
the cosetsRand - Rare different. Therefore one can
pair
the factors in theproduct
‘=SEs xeJln Tr(xs)
intopairs
ofcomplex conjugate numbers;
so this expres- sion is anon-negative
realnumber,
and so it is even apositive
realnumber,
as all its factors
are #0,
as we have seen above.By Corollary (4.7) (ii)
thisfinishes the
proof
of statement(iii).
D7. The determination of the
quotient
ofi(,Ns-)
and1(1) modulo p
In this section we assume
again
that theprime
p is ofdegree
one over p.Let x
be theidentity
map on J1n’ viewed as aprimitive
character of /ln. Foreach jE (Z/n) *
letO’jEGal(Q(/lnp)jQ(/lp))
be definedby O’j(ç) = çj
for allÇEJ1n.
Let for each tER the number{t}
be definedby
0{r}
1 andt -
{t} E Z.
Let E3 be theunique prime
ideal of0(p,,P)
above the chosenprime
p.(7.1)
PROPOSITION.The following
congruences holdfor all j e (Z/n)*
and allk e Z/n,
where h isdefined to
ben(kj/n) .
Inparticular
Xk(i(JVs)i(-r)-t) is always a p-unit.
Proof.
We embedO(/lnp)
inQcp,
analgebraic
closure ofOp,
the field ofp-adic rationals, by
theembedding
whichcorresponds
to theprime
B. LetÇ
be thep-th
root ofunity
for whichit/J(x) = (X
for an x E Y =F p.
Now weare
going
to determine theleading
parts of the localexpansions
ofXki(JVs)
and
Xki(t’)
at theprimes
above p. Tobegin
with(writing (
= 1 +(Ç - 1)
andexpanding by
Newton’sbinomium)
Using
that(Sr )
is apolynomial
in x ofdegree
r and thatY-.,c 14. X t = n
ift = 0 mod n and = 0
otherwise,
one concludes that in theexpression
abovethe smallest r e R for which
the coefficient of
(C - 1)",
is non-zero, isIt follows that
Therefore
This
implies
thatExpanding
the Gauss sumX’(i(T»
in a similar way one getsCombining (7.2)
and(7.3)
one gets the congruence in the statement ofProposition (7.1).
D(7.4)
REMARK.Alternatively
one can derive that the numbersxk (i(XS)i(T) -1)
arep-units
from the factthat C
generates a local normalintegral
basis ofN/K
at theprime
p.(See
the last statement onp. 221
of[F 1]).
(7.5)
REMARK.Proposition (7.1)
determines the elementi(Xs)i(r)-l
inthe group
ring Z/ln
modulo p.A
special
case of the congruence of theproposition
is thefollowing
onewhich is the core of Kronecker’s
sign
determination of thequadratic
Gausssum.
(7.6)
COROLLARY.Proof.
One has toapply Proposition (7.1)
with n = 2 and with S the set;:.f the classes
modulo p
of the odd numbers1, 3, 5,...,
p - 2. Then the left- hand side of the congruence ofProposition (7.1) specializes
to the left-hand side of the congruence(7.7).
Theright-hand
side of the congruence ofProposition (7.1) specializes
toThis finishes the
proof.
D8. The case n = 4
In this section we prove the
following
result.(8.1)
PROPOSITION. Let n = 4 and assumethat p
isof degree
one overp. For each úJ E
(9N
and eachprimitive character X of
/ln thefollowing inequality holds for
thealgebraic integer X(JVS’ i(-r)-t)
in theGaussian field
where N+ is the real
subfield of
N and where thesuperscript -
denotescomplex conjugation.
Moreoverif
w # iiJ, thenThe motivation to search for this
inequality
is that it has thefollowing
Galois module theoretic consequence which follows
using Proposition (2.1 ).
(8.2)
COROLLARY.If p is a prime
number = 1 mod 4. Then N =Q(/lp)
has no normal
integral
basis over thesubfield
K with[N : K]
= 4.Proof of (8.1).
Leth mod p
be a generator of,u4(F p)
and writei =
X(h mod p).
Then i2 z1. Wesimplify
notationby denoting
for eachW E ON
and eachs e Fg
the result ofhitting
coby
the fieldautomorphism
ofN =
Q(/lp)
which raisesp-th
roots ofunity
to the power sby ws.
For eachSES
Therefore,
as z - z istotally imaginary
Using
moreover the fact that Gauss sums have absolute value.JP,
sox(i(r»1 =.JP,
one gets the firstinequality
in the statement of theproposi-
tion. The
proof
of theproposition
is finishedby
the remark thatand
that,
as a consequence(8.3)
REMARK. Therequirement
inProposition (8.1)
that X isprimitive
is essential. See
Proposition (3.3).
References
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