C OMPOSITIO M ATHEMATICA
E. P RUGOVE ˇ CKI A. T IP
Semi-groups of rank-preserving transformers on minimal norm ideals in B ( H )
Compositio Mathematica, tome 30, n
o2 (1975), p. 113-136
<http://www.numdam.org/item?id=CM_1975__30_2_113_0>
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113
SEMI-GROUPS OF RANK-PRESERVING TRANSFORMERS ON MINIMAL NORM IDEALS IN
B(H)
E.
Prugove010Dki1
and A.Tip2
Noordhoff International Publishing
Printed in the Netherlands
Abstract
Transformers on any minimal norm ideal of the
C*-algebra B(H), generated by left, right
or two-sidedmultiplication
with operatorsacting
in
H,
share many features with these operators.Thus,
their spectra are related in asimple
manner,semi-groups
of such transformers have manyproperties
in common with thecorresponding
operatorsemi-groups,
their generators are
algebraically related,
etc. Inparticular,
such trans-former
semi-groups
can beunambiguously
characterizedby
theirproperty
ofpreserving
the rank of the operators in the norm ideal on whichthey
act.Necessary
and sufficient conditions under which their generators arespectral
operators are derived.. 1. Introduction
The present paper deals with the
theory
of a class of linear transforma- tions in two-sided minimal norm ideals ofcompletely
continuousoperators
on acomplex
Hilbert space Ye. As is well known[1-3],
each such ideal J can be
equipped
with aunitarily
invariant cross-normand the linear manifold W of all
completely
continuous operators with finite rank is a dense subset of Jequipped
with theappropriate
cross-norm
topology. Throughout
this paperwill
denote the two-sided minimal norm ideal ofcompletely
continuousoperators
on H with agiven unitarily
invariant cross-norma(S) = ISla’
S~ J03B1.
SinceJais
aBanach space with respect to the norm a, it makes sense to consider linear transformations in this space. In order to
distinguish
betweenordinary
Hilbert spaceoperators
andoperators
on the Banach spaceJa,
1 Supported in part by a grant from the National Research Council of Canada.
2 Supported by the Foundation for Fundamental Research on Matter, which is sponsored by the Netherlands Organization for the Advancement of Pure Research.
we shall refer to the latter as ’transformers’.
(Other
names in use are :transformators, super-operators and,
in the morespecialized
context ofstatistical
mechanics,
Liouvilleoperators.)
We shall denote transformerson
J03B1 by A, B,···,
In case A isbounded,
wewritellAlla
=supS~J03B1|AS|03B1/|S|03B1./
Limits in the a-norm will be denoted
by
a-lim.The
organization
of the present paper is as follows :In section 2 a
general
Banachspace X
is considered on which aone-to-one semi-linear
mapping
X ~ X+(X~X),
calledconjugation,
is defined. This
mapping
entails acorresponding mapping
A ~ Ac oflinear
operators
onX,
which is definedaccording
to(AX)+
= AcX+(X c- -9.).
Variousproperties
of thismapping
c areinvestigated.
Theseresults are to be used
frequently
in theremaining part
of this paper.In section 3 left and
right multiplication
transformers(in general unbounded)
on anideal J a
are studied(defined according
toA
S =(AS)**, ArS
=(SA)**,
whereS~J03B1
and A is adensely
defined operator onH).
In
particular
it is shown that therespective point,
continuous and residual spectra of Aand Al coincide,
and a similar result holds for A andAr .
It is also shown that if A generates astrongly continuous, uniformly bounded, semi-group
on9V,
then sodo Ai and Ar
onJa.
It is also shown that
if A,
andA2
generatestrongly continuous, uniformly
bounded
semi-groups U1(t) and W2(t), respectively,
one,
thenu(t) =
W1l(t)U2r(t)
constitutes astrongly continuous, uniformly bounded, semi-group
onJa
with infinitesimal generatorA=A1l+A2r.
Thesemi-groups
of transformers onJa
considered thus far have the property ofmapping
finite-rank elements ofinto
elements of the same rank.This raises the
question
whether this property is characteristic foroperator-induced semi-groups
of transformers onJ ex.
This matter issettled in the affirmative sense in section 4 where it is shown that rank-
preserving semi-groups
of transformers oncan
beimplemented by
two
semi-groups
of operators on A. This result makes itpossible
toobtain an
unambiguous
characterization ofgeneralized
inner derivation(defined through DA(B) = (AB - BA)**,
where A is notnecessarily bounded)
on bothJ03B1 and 4(e).
In section 5 some attention isgiven
tothe
question
whether scalarspectral operators
on e induce scalar type transformers onJa.
This is indeed the case forsimple
left andright multiplication
transformers but ingeneral
such a result does not hold.This is due to the fact that two
commuting uniformly
boundedspectral
measures on
do
notlead,
ingeneral,
to aproduct spectral
measure, which isuniformly
bounded onJ a.
In addition to
throwing
somelight
on a yetunexplored
area in thetheory
of minimal norm ideals the above results are also of interest in quantum statistical mechanics[4]
and quantum fieldtheory [5].
This isdue to the fact that the behaviour in time of the statistical
operator (density operator) p,
which is apositive
normal element of the traceclassgB 1 (Je)
ofoperators
onA,
isgoverned by U(t)
=ul(t)u*r(t)
withOZ/(t)
= exp( - iHt),
where H = H is the full Hamiltonian of thesystem.
Working
with transformers enables us to derive[5]
many results ofscattering theory
for thedensity
operators which areanalogous
towell-known
corresponding
results for statevectors.2.
Conjugation
of transformers onB(H)
Let us consider in this section the
general
case of acomplex
Banachspace X
with elementsX, Y, ···
on which anoperation
ofconjugation,
denoted
by X~X+,
isdefined,
i.e. X~X+ is a one-to-one, norm-preserving,
semi-linearmapping
of X intoitself,
for which(X+)+ =
X.Let A E
fJ4(fI).
Then theconjugation
c inB(X)
is introducedaccording
to(AX)+=AcX+.
It iseasily
established thatAc~B(X)
and that themapping
A ‹ A’ possesses thefollowing properties (A, B EfJ4(fI), 1
is theidentity
onB(X) and IIAII stands
for the operator bound of A) :(1) lC=I, (2) Acc~(Ac)c=A, (3) (03BBA+B)c=03BBAc+Bc, 03BB~C, (4) (ABY
=AcBc, (5) IAcl
=lAI
and(6)
If A-1 exists as an element offJ4(fI),
then
(A-1)c
=(Ac)-1,
so that ifp(A)
denotes the resolvent set of someA E fJ4(fI),
we have À Ep(A)
H 1 c-03C1(Ac).
It follows from
property (5)
that themapping B(X)c B(X)
is con-tinuous in the uniform
topology
onfJ4(fI).
From theproperty |X| = IX’l
for X~X it follows that the same is true with respect to the strong operator
topology.
If
fI = Ja
then it is natural to choose the involution A ~ A* infJ4(fI)
as the
conjugation operation
used to defineconjugation
c inB(J03B1).
Dueto the
special
form of the bounded linear functionals onJ a
and theproperty
trST =trS*T*, S~J03B1, T~J*03B1,
it follows that themapping
A - Ac is continuous in the weak transformer
topology.
We will say that A
~B(X)
isself-conjugate
if A = Ac. Onthe
self-conjugate
transformers are those that carry Hermitean operators into Hermiteanoperators.
It is seen from the above property(6)
that thespectrum
u(A)
of aself-conjugate
transformer A is invariant under reflections with respect to the real axis(i.e. 03BB~03C3(A)~03BB~03C3(A)).
It isnaturally
desirable to extend the concept of theconjugate
transformer Ac of A to the case when A is not bounded. The obvious definition is now(AX)+
=AcX+,
Xc- -9.
so that X+ E-9Àc
if Xc- -9,,.
In this case property(5)
looses itsmeaning
and the otherproperties
have to be modified insofar as domains of definition are concerned. Thefollowing
lemma iseasily
established.LEMMA 2.1:
(a)
Ac isdensely defined
on Xif
andonly if
A isdensely defined
on X.(b)
AC is closed on fIif
andonly if
A is closed on X.THEOREM 2.1 : Let A be a linear
transformation
in X. A’ generates a uni-formly bounded, strongly
continuous one-parametersemi-group {N(t)|t ~
0on
fI if
andonly if A
generates such asemi-group {u(t)|t
~ 0. In thatca.se
f( t)
=uc(t).
PROOF :
Suppose
that A generates thesemi-group u(t)
as stated above.This is the case if and
only if (ref. [6], chapter 9)
A isclosed, densely
definedon X and in addition
n E p(A)
for n= 1, 2, 3,...
with(I-n-1A)-m ~
Kfor all n =
1, 2, 3, ···, m
=1, 2, 3 ···.
According
to lemma 2.1 Ac is closed anddensely
definedalong
with A.Furthermore property
(6)
remains true forunbounded,
closed A.For,
let03BB~03C1(A).
ThenR03BB-A
= fI and B =B03BB = (À - A)-1
exists as an elementof
B(X).
Since Y+ runsthrough
all of fI if Y =(À-A)X does,
it follows thatB03BB-Ac =
X. The relationB(03BB-A)X
=X, X~DA
leads toThus  - A c has
range X
and a bounded inverse BC =(03BB-Ac)-1
so that03BB~
p(Ac).
For real n =1, 2, 3, ...
it followsimmediately
thatm~p(A) implies nE p(AC).
From theproperties (4)
and(5) above,
we infer thatI(Bn)ml = |((Bn)m)c|
=|(Bcn)m| and hence |(I-n-1A)-m| ~ K,
n =
1, 2, 3, ...,
m =1, 2, 3, ···.
Thus Acobeys
the same conditions as A does and hence generates thesemi-group V(t)
as stated above. This proves the first part of thetheorem ;
the’only
ifpart being
clear fromLemma 2.1 and
equality (1).
The relationV(t) = ec(t)
follows the usual(ref. 8, chapter 9)
construction of thesemi-group
from its infinitesimalgenerator.
REMARK: In Theorem 2.1 we considered
uniformly
bounded semi- groups. A similar theorem can be established under somewhat different conditions. Forinstance,
one can obtain a bound for whichby redefining W(t).
It was shown in the
proof of Theorem
2.1 that for closed A the resolvent sets, and hence the spectra of A and Ac aremapped
onto each otherby
taking complex conjugates.
Infact,
more can be said about this relation-ship. Denoting
thepoints
spectrumby
up, the residual spectrumby 6r
and the continuous spectrum
by 03C3c (where
we follow the definition of the variouscomponents
of the spectrum asgiven
in ref.[6])
it iseasily
checkedthat:
LEMMA 2.2: The spectra
up(AC), ur(AC)
anduc(AC)
consistof
thecomplex
conjugates of
the elements in the spectra6p(A), 6r(A)
anduc(A), respectively.
3.
Semi-groups
related to left andright multiplication
transformers Let A~B(H).
Then forS~J03B1,
AS and SA areagain
contained inJ03B1
and we can define the transformers
Al
andAr by A 1 S
= AS andAr S
= SA.Since
J03B1 is
a two-sided idealA,
andAr
are contained inB(J03B1).
In factwe have the
following result,
whoseproof
is an immediate consequence of cross-normproperties.
LEMMA 3.1:
Let A, and A2
be contained inB(H).
ThenA, defined by AS = A1 SA2, S~J03B1 is a
bounded lineartransformer
onJ03B1
andIIAlla = IAIIIA21. ln particular, if A~B(X),
then~Al~03B1
=~Ar~03B1
=|A|.
The situation becomes more
complicated
for unbounded A. Then wedefine :
DEFINITION 3.1: For a
given densely
defined linear operator A the left andright multiplication transformers, A1
andAr respectively,
inducedby A,
aregiven by
LEMMA
3.2 : Suppose
A is closed anddensely defined
on H. 1henAi
=Ar
and
Acr
=A*l,
whereAi
andAi
aredefined b y A*lS
=(A*S)**
andA*rS
=(SA*)**,
with S in the proper domain.PROOF : If B is a linear operator in H and
S~B(H)
then(cf.
ref.7,
p.
300) (SB)*
= B*S*.If, moreover, B
is closed anddensely defined,
then B** = B and(S*B*)*
= BS.Suppose S~DAr.
ThenS~B(H)
andAcrS* = (ArS)* = (SA)*** = (A*S*)** = A*lS*
i.e.Acr ~ Ai.
ForS*~DA*l
it follows from
reading
this sequence of relations from theright
to theleft that
Ai
cAr
and henceAcr
=A.i.
Consider next the case that
S~DAl
cB(H).
ThenAlS~B(H)
andA’S* = (A1S)* = (AS)*** = (S*A*)**
=AIS*
orAi ce Ai.
In the sameway as above it follows that
A*r
cA i
and henceAcl = A * . /
REMARK: A more obvious definition of
AI
andAr
would beAlS
= ASand
Ar S
= SArespectively. Indeed,
if A is closed and S is bounded then AS is closed.Hence, if (AS)**
exists then(AS)**
= AS and both definitionsof Ai
coincide for closed A. On the other hand SA isonly
defined on thedomain of A
and,
in order to obtain a useful definition ofAr,
we haveto
require
that SA can be extended to a boundedoperator,
contained infa.
This is achieved in definition 3.1by demanding
that(SA)**,
the smallest closed extension of SA
(SA
is ingeneral
not closed orclosable,
even if A isclosed),
is an element ofJ a.
Note that the symmetry
expressed
in Lemma 3.2 may be lost if thedensely
defined operator A is not closed. In that case AS need nolonger
be
equal
to(S*A*)*
=A**S,
which property was used in the secondpart
of the
proof
of the lemma.LEMMA 3.3: Let A be closed and
densely defined
on e. ThenAl
andAr
are closed and
densely defined
onfa.
PROOF:
Suppose
that A isdensely
defined on Jf. LetSEfa, S =1=
0.For
given e
> 0 there exists an R~R.R ~ 0,
such thatIS - Ria e/2.
We write R
according
to its canonicaldecomposition
n
R -
03A3 03BCk(·, Xk)yk, l’ 1
03BC2 ··· ~ In > 0-As DA
is dense in :Yt there exists for eachyk ~ H
azk~DA
withI Yk - zkl 03B5/(203BC1 n).
Then the operatorRo
=S=
103BCk(·, xk)zk is
an elementof
fa’
contained inDAl.
Weobviously
have that|S-R0|03B1
e. Hencewe conclude
that DAl
is dense inJ03B1. Since
A is closed anddensely
definedthis is also true for
A*,
sothat DA
is dense inJa.
SinceA,
=(A*)c,
it follows from lemma 2.1
that DAr
is dense infa.
Let A be closed and
densely
defined in H.Suppose
that for certain{Sn}~n=1 ~ DAl
with03B1 - limn~~ Sn=S
the limitT= 03B1-limn~~ AlSn
exists. Let x be an
arbitrary
element of YC. Sincewe see that y --- Sx =
s-limn~~yn, where yn
=Sn x.
For z = Tx we havein addition
(AS,,
=A 1 Sn’
since A isclosed)
and hence
s -limn--. 00 AYn
= z. As A is closed it follows that y =Sx~DA
and
Ay = z.
Thus ASx = T x forarbitrary
xeàv. Hence AS = T.Since S and T are contained in
J03B1 it
follows thatS~DAl
andA 1 S
= T.Hence
Al
is closed.Starting
fromAi
andusing
Lemma 2.1 we show in the same way thatAr
isclosed.
THEOREM 3.1: Let A be closed and
densely defined
on A. Then03C1(Al)
=p(A)
andfor
À Ep(A,), (À - A,) -1
is the boundedleft multiplication transformer (03BB-A)-1l.
In additioncr p(Al) = 03C3p(A), 03C3r(Al) u,.(A)
and03C3c(Al)
=03C3c(A).
PROOF:
(a) Suppose
thatR03BB-A
is dense in e and that(03BB-A)-1
existson R03BB-A. By essentially
the same method as used in part(a)
of theproof
of Lemma 3.3 it follows that
R03BB-Al
is dense inJ03B1. Let
the transformer B onfa
be definedby
the relation BS =(À-A)-lS.
ThenSx~DA (A
=A**)
for every x~H and we have(03BB-A)-1 (À-A)Sx
= Sx for allx~H,
so that(03BB-A)-1(03BB-A)S=B(03BB-Al)S=S, S~DAl.
ThusB =
(03BB-Al)-1
exists onfa
and has dense domain.Suppose
that À Ep(A).
In that case
(03BB-A)-1
is bounded andeverywhere
defined on Je(A
isclosed). Consequently B
=(03BB-Al)-1
is bounded andeverywhere
definedon
J03B1. Hence p(A)
cp(AI).
Suppose
now that03BB~03C3c(A).
Then(03BB-A)-1
exists as adensely defined,
discontinuous operator. Since A isclosed, (03BB-A)-1
isnecessarily
unbounded. Thus there is a
sequence {yn}~n=1
cD(03BB-A)-
1 withYn =1=
0 and|(03BB-A)-1yn|
>n|yn|.
We show that(03BB-Al)-1
is unbounded. Thus letSn
be definedby Sn
=(., X)yn, x ~
0. ThenSn
ED(03BB-Al)-1
andWe now have
and we conclude that
(03BB-Al)-1
is unbounded. SinceA,
isclosed,
(Â-Al)-’
is closed and unbounded. Hence03BB~03C3c(Al)
and03C3c(A)
c03C3c(Al).
(b) Suppose
that 03BB Eup(A).
Then there exists anx c- e, x ~ 0,
withAx = 03BBx.
Defining S by S
=(., y)x, y ~
0 we see thatAlS
=(., y)Ax
= 03BBSand hence
03BB~03C3p(Al). Suppose, conversely,
that03BB~03C3p(Al).
Then thereexists an
S~J03B1, S~0
withAlS = AS = 03BBS. Since S+O
there is atleast one
x~H,
such that y =Sx ~
0. For this x and y we haveAy
= ASx = 03BBSx =03BBy and hence 03BB~03C3p(A).
We concludethatap(A) = 0" p(Al).
(c) Suppose
that03BB~03C3r(A).
Thenf1llÀ-A
is not dense in H and thereexists a non-zero vector x in Jf which is
orthogonal
toR03BB-A.
Thisimplies that R03BB-Al
is not dense infa.
Infact, if 03B1-limn~~(03BB - Al)Sn
=(.,y)x
for some
{Sn}~n= 1 ~ DAl
andy ~ 0
then we would havewhich is
impossible
sincex.1 f1ll;’-A
andconsequently (x, (03BB-A)z)
= 0for any
z~DA.
Hence
03BB~03C3p(Al)
or À Ecrr(Al).
The firstpossibility
must be excludedon account of
Qp(Al)
=6p(A),
so that03C3r(A)
c6r(Al). Using
now the wellknown facts that p, 03C3c, 6p and cr are
disjoint,
that their union is C and that thecomplement of p
in C is 0", we conclude thatp(A)
=03C1(Al),
COROLLARY 3.1 : Let A be closed and
densely defined
on e. Thenp(Ar)
=p(A)
andfor
À Ep(Ar), (À - Ar)-1
is the boundedright multiplication transformer (À - A)r ’.
In additionPROOF : As A is closed and
densely
defined on P this is also the casefor A*.
Applying
first Theorem 3.1 toA* = A’
and afterwards Lemma 2.2we get the desired result on the resolvent sets and spectra
by noting
thatp(A) = p(A*)
and03C3c(A) = 03C3c(A*).
THEOREM 3.2:
Suppose
A generates auniformly bounded, strongly
continuous one parameter
semi-group
on :Yt. ThenA,
andAr
generateuniformly
a-bounded andstrongly
continuous one parametersemi-groups on J03B1.
PROOF : Since A generates a
uniformly bounded, strongly
continuoussemi-group
onH, A
is closed anddensely
defined on X. Moreover(see the proof of Theorem 2.1) n E p(A)
for n =1, 2, ... and (1-n-1A)-m| ~
Kfor all n =
1, 2, ···, m = 1, 2, 3, ....
Since A is closed anddensely
definedwe have
p(A)
=03C1(Al) = p(Ar)
and it follows at once that n =1, 2, ...
is also contained in the resolvent sets of theclosed, densely
defined(on fa)
transformers Al
andAr .
Sinceare bounded transformers on
for À e p(A)
it is clear from Lemma 3.1 that~(1-n-1Al)-m~03B1~K, ~(1-n-1Ar)-m~03B1~K
forn = 1, 2, ···
andm =
1, 2, ...,
and the theorem isestablished.
THEOREM 3.3:
Suppose
that{u(t)|t ~ 0}
is auniformly bounded, strongly
continuous one-parameter
semi-qroiips
on H. Then:(1) {ul(t)|t ~ 01
and{ur(t)|t ~ 0}
constituteuniformly bounded,
one-parameter
semi-groups on J03B1,
continuous in the strongtransformer topology,
and their bounds coincide with the boundof U(t).
(2)
Let A be theinfinitesimal
generatorofo/1(t).
ThenAl and Ar
are theinfinitesimal
generatorsof ul(t)
andur(t), respectively.
PROOF : The
proof
of(1)
isstraightforward. According
to theorem 3.2Al
andAr
generateuniformly bounded, strongly
continuoussemi-groups
on
J03B1.
Let us show then thatB,,
the infinitesimal generator ofur(t),
is contained in
Ar (the corresponding proof
forB,
cA,
is evensimpler).
Suppose
that SEJa
is contained inDBr.
Let x,y c- A, x =1= 0, y =1=
0. Then(cf.
ref.1)
R =(·, z)y ~ J*03B1
andConsequently t-1(u*(t)-1)S*x
convergesweakly
towards(BrS)*x
in Je.However,
sinceu*(t)
is astrongly
continuoussemi-group,
this is sufficientto conclude that S*x is in the domain
of A*,
the infinitesimalgenerator
ofu*(t).
Since x was chosenarbitrarily
fromJe,
it follows from theequality (Br S)*x
= A*S*x that(Br S)*
= A*S* or, sinceS~B(H), (BrS)* = (SA)*.
NowBrS
is contained inJ03B1 and
therefore is bounded.Hence
BrS=(BrS)**=(SA)**~J03B1,
i.e.S~DAr.
Since S was chosenarbitrarily
fromDBr
we conclude thatDBr ~ DAr.
THEOREM 3.4:
Suppose {U1(t)|t
~01
and{u2(t)|t
~01
are twouniformly bounded, strongly
continuoussemi-groups
on e with boundsKi
andK2, respectively.
Then{u(t)|t
~01, defined
onJ03B1 by
constitutes a
uniformly bounded, strongly
continuoussemi-group of
trans-formers
onJ03B1
and its bound does not exceedKI K2. Denoting
theinfinitesimal
generatorsof U1(t), OZ! 2(t)
andW(t) by Al, A2
andA,
respectively, then, for
S EE11l ~ DA2r
we havePROOF : The
semi-group properties
ofu(t)
areevident,
thecontinuity being
clear form the strongcontinuity
ofu1(t)
andu*2(t).
In additionLemma 3.1 shows us that
|u(t)|03B1 = |u1(t)||u2(t)| ~ KI K2.
Suppose
thatS~DA1l~DA2r.
Then(A1S+SA2)**~J03B1
andtends to zero for t ~ + 0. We conclude that
REMARK:
W(t)
canobviously
be written as theproduct
of the twocommuting
transformersu1l(t)
and0Jl 2r(t).
For thespecial
case thatA2
=A,
we haveGll2r(t)
=uc1l(t),
i.e.Gll(t)
isself-conjugate.
COROLLARY 3.2 :
Suppose
thatu1(t)
and*2(t)
in Theorem 3.4 are twostrongly
continuous groupsof unitary
operators on :Yt(i.e., according
toStone’s
theorem,
theirinfinitesimal
generators can be written asAl
=iH 1, A2
=iH2,
whereHl
andH 2
areself-adjoint
onH).
Then{u(t)|t~ RI
is a
strong 1 y
continuous groupof
isometrictransformers
onJ03B1.
4.
Semi-groups
ofrank-preserving
transformersDEFINITION 4.1: A bounded transformer A on
J03B1 is rank-preserving
if it maps every finite-rank operator
SE fa
into an operator A S of rankequal
to the rank of S.We note that a bounded transformer on
J03B1 is rank-preserving
if itmaps the set
R1
of rank-one operators into itself and if it is invertible.If
u1(t)
andu2(t)
are bounded and invertible operators on e thenu(t)S
=u1(t)Su*2(t)
isclearly
arank-preserving
transformer.Moreover,
if0/11 (t)
andOZI 2(t)
areuniformly
boundedstrongly
continuoussemigroups
in t ~ 0 then we have seen in Section 3 that
W(t)
isstrongly
continuousin a-norm on
J03B1. This
section is devoted to theproof
of thefollowing theorem,
which represents to a certain extent a converse of the above statement.THEOREM 4.1:
Suppose
thatW(t),
t ~0,
is an a-continuoussemigroup of rank-preserving transformers
on a minimal norm idealfa
on theC*-algebra B(H) of
a Hilbert space :Ytof
dimension greater than two.Then there are
strongly
continuoussemigroups ul(t)
andOZIr(t) of
operatorson e such that
e(t)S
=ul(t)Sur(t), for
allSE J a
and t ~ 0.We
proceed
now with theproof,
in the course of which we deriveseveral
auxilliary
lemmas.First of all we note that since
W(t)
maps a rank-one operator(., y)x
into an
operator
which is also of rank one, we can writeOf course,
x(t)
andy(t)
are notuniquely
determinedby
x and y, sincefor any nonzero
y(t)
E C.LEMMA 4.1: For any two normalized vectors xo, yo ~ H there are vector-
valued
functions xo(t)
andyo(t) defined for
all t ~[0, io(xo , yo)]
=I0, LO(XO’ Yo)
>0,
such that(yo(t), yo)
is nonzero and continuous int~I0,
|y0(t)| ~ 1, tElo,
andOJl(t)(., Yo)xo
=(., y0(t))x0(t) for
alltElo,
wherexo =
x0(0),
Yo =YO(o).
PROOF : Since
0Jl(0)
= 1 andGll(t)
is a-continuous in aright neighbour-
hood of t =
0,
there is a number LO > 0 and there are vector-valued functionsx1(t)
andy1(t)
such thatu(t)(·, yo)xo
=(., y1(t))x1(t) =1= 0,
for all
t~[0, ro]
=Io .
This last relation follows from the fact that the functional~(R)
=tr f R(.,
an element off: (cf.
ref.[1])
and therefore it is a-continuous in
R~J03B1. Since, ~[u(0)(·, yo)xo] = 1,
the
continuity
of this functionalimplies
that 0 forsufficiently
small values of t ~ 0.By setting y(t)
=(x1(t), xo)
andwe get
by using (1)
Hence
(Y2(t), yo) is
continuous inIo .
Sincey(O)
=1,
we havey2(o)
= yo .Furthermore,
thea-continuity
ofuc(t)(·, yo)xo implies
thatis continuous in
t~I0. By
virtue of the fact thatY2(t) =1=
0 for allt~I0,
since
(Y2(t), Yo) =1=
0 for all such t, we conclude thaty0(t) = |y2(t)|-1y2(t), x0(t) = IY2(t)lx2(t),
are the vector-valued functionssatisfying
all theconditions of the
lemma.
LEMMA 4.2: Let W be a
rank-preserving trans, former
and let xo, yo,x’ , y’0
be nonzero vectors in A’ such thatW(., yo)xo
=(·, y’0)x’0.
Then either there is a bounded linear operator
W’
on H such thatW(., yo)x
=(·, y’0)W’lx,
or there is a bounded semi-linear operatorW’
suchthat
W(., yo)x
=(·, W’rx)x’0 for
all x~H.Similarly,
either there is abounded linear operator
W"
such thatW(., y)xo
=(·, W"r)x’0
or there isa bounded semi-linear operator
W"
such thatW(., y)xo
=(·, y’0)W’ly for
all y ~H.PROOF : We shall prove
only
the first part of the lemma. Theproof
ofthe second part is
analogous.
Let xo, x1, x2 c- e be
linearly independent,
and let us setSince W is linear and
rank-preserving
we can writefor some vectors
(x0 + 03B11 x1 + 03B12 x2)’, y’0(03B11, a2) in
H whichdepend
onoei ,
(X2 E C.
The left-hand side of the aboveequation
can beequal
to theright-hand
side if andonly
if eithery’0
= 03C91ybl) = w2yb2)
or ifx’0 = 03B61x(1)1 = 03B62x(2)2,
where col , W2,03B61, 03B62
are nonzerocomplex
numberssince W is
strictly rank-preserving.
In the first case we haveand then
obviously
for all
03B11, 03B12 ~ C.
Thusx1 ~ x’1
=W’lx1
determines a linear operator when x 1 varies over all vectorslinearly independent
of Xo.By setting W’xo
=x’0,
we havecompleted
the construction ofW’l.
Its boundedness follows from the factthat |W’lx| = |y0|-1|W(·, y0)x|03B1.
In the second case
W(·, y0)xk = (·, y’k)x’0, y’k = 03B6-1ky’0, k = 1, 2
andclearly W(., y0)(x0
+ al xl+a2x2) = (., y’0
+03B11y’1
+03B12y’2)x’0.
Hence the con-struction
of a semi-linearW’r
is obtained in the same mannerby setting y’1
=W’rx1,
and theproof
of the lemma iscomplète
In view of the
assumption
thatu(t)
isrank-preserving
in someright neighbourhood [0, 03C41] of zero,
we inferby using
thepreceding
lemmathat for each such value of t there is either a linear
u’l(t)
or an antilinearu’r(t)
as defined in that lemma.LEMMA 4.3 : For
given
normalized xo,y 0 E:Yt
there is aright neighbourhood I’0 of t
= 0 and afamily { u’l(t)|t~I’0} of
bounded linear operators which isstrongly
continuous int~I’0
and such thatfor
all x~H whereyo(t)
has been chosen as in Lemma 4.1.PROOF : We must first eliminate the
possibility
thate(t)
and xo, Yo E:Yt determine a semi-linearu’r(t)
rather than lineare(t)
for values of t inarbitrarily
smallneighbourhoods
of zero. Hence assume that there is asequence t1, t2’... ~ + 0 such that
OJl(tn)(., Yo)x
=(., u’r(tn)x)x0(tn).
Thenthe
expression
converges to
(z, yo)(x, xo)
due to thea-continuity
ofW(t). Setting
abovex = xo and z = yo we conclude that
Since
by
Lemma 4.1(yo, y0(tn))
-1,
we infer that(xo(tn), x0) ~
1 andtherefore
limn~~(z, u’r(tn)x) = (z, yo)(x, xo).
This wouldimply
thatwhen,
infact, OJl(tn)
converges in a-norm to theidentity
transformer infa’
and therefore
Thus,
we have established the existence of aright-neighbourhood I’ 0
oft = 0 in which
(2)
holds.The strong
continuity
ofu’l(t)
follows from theinequalities
which are the consequence of
elementary properties
of the a-norm andof
ly,(t)l
= 1(cf.
Lemma4.1).
SinceGll(t)
is a-continuous andthis
continuity
ofu’l(t)
is obtainedby noting
thatyo(t)
isstrongly
con-tinuous since
IYo(t)1
~ 1 andis continuous for any z E 9V.
Now, having
established the existence of astrongly
continuousu’l(t) satisfying (2),
weproceed by proving
the existence of a continuousnon-zero
complex
functioncvo(t)
defined for t in aright neighbourhood I"
of zero, for whichul(t)
=03C90(t)-1u’l(t), t~I"0
is notonly strongly
continuous but also additive:
First of
all,
we note thatOn the other hand
Applying
the secondpart
of Lemma 4.2 toU’l(t2)x, YO(t2)
~H(instead
of xo, yo
E Je),
we inferby using (4)
andsetting
that either we can choose
YO(t2)’ = YO(tl
+t2),
and thenU"l(t1,
t2,x)
defined
by
is an semi-linear
operator,
or[ul(t2)x]’ = U’l(t1
+t2)X,
in which caseu"r(t1,
t2;x)
definedby
is a linear
operator.
The first case can be eliminatedby
areasoning
similar to the one used for
U’r(t)
in theproof of Lemma
4.3. Thus(5)
musthold true.
Setting
in(5)
y =yo(t2)
andcomparing
with(3),
we concludethat for some nonzero
W(tl’ t2; x)
~ CSince
e(t)
isrank-preserving
for t EI’0,
it follows thatu’l(t)
isinvertible,
and therefore
Hence
ro(tl,
t2 ;x)
does notdepend
on x:LEMMA 4.4: The
complex-valued function 0)(tl, t2) defined by (6) for
tl , t2, tl + t2 EI’ 0
is continuous, nonzero, and such that(0, 0)
= 1 andPROOF : The
continuity of 03C9(t1, t2)
follows from the strongcontinuity of u’l(t) by noting
that in(u’l(t1)u’l(t2)x0, xo)
=xo)
both sides of the relation are nonzero.
Furthermore, u’l(0)
= 1 andtherefore we get
03C9(0, 0)
= 1by inserting
in(6)
tl = t2 = 0.Finally, (7)
follows from
The above lemma tells us that the
complex
function03C9(t1, t2)
has allthe
properties
of a local factor(cf.
ref.8,
p.8)
except one,namely
theproperty
Iw(tl, t2)1
~ 1might
belacking. However,
sinceW(tl’ t2)
does not
vanish,
there areuniquely
determined real-valued functions03C1(t1, t2)
and03C8(t1, t2)’ 0 ~ 03C8(t1, t2) 203C0,
such thatWe deduce from Lemma 4.4 that
03C1(0, 0) = 03C8(0, 0)
=0,
and that
p(ti , t2)
and03C8(t1, t2)
are continuous for t1,t2 ~I"0,
whereI"0
cI’
is anadequately
chosenright neighbourhood
of t = 0. Thus pand 03C8
are local exponents(cf.
ref.8,
p.20)
and there are continuousfunctions
po(t)
and03C80(t), t~I"0 (see
ref.8,
pp.19-21 ;
the statement of this result ispresented
in this reference for the case when pand 03C8
are definednot
only
forright
but also for leftneighbourhoods
of tl = 0and t2
=0,
but its
proof
does notrequire
thisassumption)
such thatHence we can write
W(tl’ t2)
=WO(tl)WO(t2)’ cvo(t)
= exp[po(t)
+i03C80(t)],
and therefore the relation
ul(t)
=03C90(t)-1u’l(t),
t EI"0
is established.Let us
employ again
Lemma 4.2 indefining
afamily
of bounded linear operatorsOZIr(t) by
Using
anappropriate
version of Lemma 4.3 to eliminate thepossibility
ofsemi-linear
operators occurring
inarbitrarily
smallright-neighbourhoods
of t =
0,
we infer that(8)
must hold at least in someright-neighbourhood I1
of t = 0. In order to show now thatat least for t in some
neighbourhood I’1 ~ I1
nI"0,
we defineV(x ; t) by (., V(x, t)y)ul(t)x
=u(t)(·, y)x,
whereobviously V(xo, t)
=e"(t),
andthe
possibility
ofV(x, t) being
anti-linear is eliminated as beforeby setting
above y = yo.Choose x
orthogonal
to xo , and note that thelinearity of u(t) implies:
Since
u(t)
isrank-preserving,
the operatorul(t)
is invertible and con-sequently OZI,(t)xo
islinearly independent
of x. Hence(10)
can be true ifand
only
ifV(axo
+ x,t)
=V(x, t)
=V(xo, t)
=W,(t).
This establishes that(9)
holds for allt~[0, r],
where L > 0 isadequately
chosen. HenceOJl(t)R
=ul(t)Ru*r(t),
0 ~ t ~ r for all finiteR~R,
and since W is dense inJa,
and1000(t)la’ |ul(t)|
and|ur(t)|
arefinite,
this relation holds for allR~J03B1. Furthermore, OZIl(t)
andOZIr(t)
can be extended tosemigroups
defined for all t ~ 0
by setting ul(t) = ul(t’)ul(03C4)n, OZI r( t) = ur(t’)ur(03C4)n,
t =
t’ + ni, 0 ~ t’
r, n =1, 2, ···.
Thus we aredealing
with two one-parameter
strongly
continuoussemigroups
of transformers which coincide on someright neighbourhood
of zero.Hence, they
have tocoincide
everywhere.
This establishes that Theorem 4.1 is true.REMARK: It is
interesting
to note that Theorem 4.1generalizes
somewell-known results
(cf.
ref.8)
on rayrepresentations
of one-parameter Lie groups. Infact,
it is easy to see that thefollowing
definition of a raysymmetry mapping
isequivalent
to the conventional one(cf.
ref.9).
DEFINITION 4.2 : A ray symmetry
mapping T
in Je is abijective mapping of Ri
ontoitself,
which maps hermitianprojectors
S ER 1 into
hermitianprojectors TS,
and is such thattr{(S1)*(S2)}
=tr{S*1S2}
for any twoorthogonal projectors SI’ S 2 E g/ll .
Wigner’s
well-known theorem(cf.
ref.9) implies
that every ray symmetrymapping T
is a transformer of é9 onto itself which preserves the Schmidt innerproduct (’, ·)2 : (Si, S2)2
=tr{S1 S*2}.
On the otherhand,
this theorem does not
preclude
thepossibility
that the transformerT
is semilinear rather than linear.However,
in either caseT
can be extended to,respectively,
a linear or semilinear transformer T on the Schmidt classB2(H).
In case of a continuoussemi-group
of ray symmetrymappings
T(t)
witht(O)
= I thepossibility
ofsemilinearity
can be eliminatedby using
the type of argumentemployed
in the courseof proving
Lemma 4.3.Furthermore,
in this case weeasily
deduce thatul(t) ~ OZIr(t)
from therequirement
thatT(t)
maps the set ofself-adjoint
one-dimensionalprojectors
into itself.5.
Spectral
transformers inducedby spectral operators
In this section we consider left and
right multiplication transformers,
which are derived fromspectral operators [10].
The centralquestion
iswhether such transformers and their linear combinations are
again spectral.
We recall that ahomomorphic
map E from a Booleanalgebra
A =
A(J)
of subsets of a set J into a Booleanalgebra
ofcommuting projections
in thecomplex
Banachspace X
is called aspectral
measurein