A NNALES DE L ’I. H. P., SECTION C
P IOTR H AJŁASZ
A note on weak approximation of minors
Annales de l’I. H. P., section C, tome 12, n
o4 (1995), p. 415-424
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A note
onweak approximation of minors
Piotr HAJ0141ASZ*
Instytut Matematyki, Uniwersytet Warszawski
ul. Banacha 2, 02-097 Warszawa, Polska email: hajlasz@mimuw.edu.pl
Ann. Inst. Henri Poincaré,
Vol. 12, n° 4, 1995, p. 415-424. Analyse non linéaire
ABSTRACT. - Let where Q ç Rn is a bounded open
domain,
be a set of allmappings u
EW 1 ~P ( SZ, Rn )
such thatadj
Du E LqAmong
other results we prove that
if n - 1 p n, 1 q n/ (n - 1),
thenthe subclass of
mappings,
which consists ofmappings
with bounded(n - 1)-dimensional image,
is dense in thesequential
weaktopology
ofWe also extend this result to other
Ap,q type
spaces.1991 MSC Primary: 28A75, 73C50. Secondary: 28A05
Key words: Nonlinear elasticity, approximation of minors, Sobolev mappings, Suslin sets.
1. INTRODUCTION AND STATEMENT Let Q be a bounded domain. We define
where the matrix
adj
Du satisfies theidentity (det Du)Id
= Duadj
Du.Spaces
of this type arise in a natural way as classes on which variational functionals related to nonlinearelasticity
are defined(see
e.g.[1], [5], [6],
* This work was partially supported by KBN grant no. 2 1057 91 01. This research was
carried on while I was visiting C.M.L.A. E.N.S. de Cachan in 1993. I want to thank for support and hospitality.
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire - 0294-1449 Vol. 12/95/04/$ 4.00/@ Gauthier-Villars
[7] [8], [10], [16], [19], [21], [22], [24], [29]).
It is veryimportant
to notethat if q >
p/(n - 1),
then the space is not linear. The space is endowed both with strong and weaktopology.
We say that ustrongly
in if u
strongly
in andadj Duk - adj
Dustrongly
inLq;
u
weakly
in if uweakly
in andadj Duk - adj
Duweakly
in Lq. All kinds of weak convergence, asusual,
will be denotedby "harpoon" ~
inplace
of "arrow". Our main results are Theorem 1 and itsgeneralisation,
Theorem 3.THEOREM 1. -
Ifu
EAp, q ( SZ ),
SZ CRn,
n -1 p n, 1 qn / ( n -1 ),
then there exists a sequence E such that values
of belong
to a certain bounded
(n - 1)-dimensional simplicial
set(which depends
on
v)
and - uweakly
in In the other words the subsetof
which consists
of mappings
with bounded(n - 1)-dimensional
rangeis dense in in the
sequential
weaktopology.
Remark. - Note that it is not
possible
to substitute in the above theorem weak convergence inby
strong convergence. Othervise we would have(after passing
to asubsequence),
Du a.e. and hence0 - det det Du a.e.
COROLLARY 1. -
If u
is as above, then there exists E such that -~ uweakly
in and det 0.COROLLARY 2. -
If u
En ~.1 ( SZ ),
thenfor
each qn / ( n - 1 )
thereexists a sequence
u~v>,
such that E ~ uweakly
inand det 0.
The above corollaries are in contrast with the
following
theorem ofMiiller-Qi-Yan [24].
~~ ~ n
THEOREM 2
[24,
Lemma4.1 ] ). -
Letp >
n-1, q >
n - 1 and - u
weakly
in1.
If
q >n ,
, then det det Du inn-1 2.
If
q =n
and det 0, then det det Du in
L1(K)
for
all compact sets K C SZ.The
following
theoremgeneralizes
Theorem l.THEOREM 3 . -
If
u E p n, then there exists asequence E
Rn)
such that valuesof belong
to acertain bounded
[p]-dimensional simplicial
set(this
setdepends
onv)
andu(v)
~ uweakly
inW 1 ~P.
Moreoverif adjs
Du Efor
some s, qslinéaire
417
A NOTE ON WEAK APPROXIMATION OF MINORS
such that 1 qs
( [p]
+1 ) / s,
then we canadditionally
obtain thatadjs
Duweakly
inRemarks. -
1) Up
to thesign
andorder, adj s
Du is a multidimensional matrixconsisting
of all s x s minors of Du(cf [5]). By [p]
we denote thegreatest
integer,
less then orequal
to p.2) By
the same reason as in the case of Theorem1,
we cannot substitute weak convergenceby strong
convergence.Theorems 1 and 3 are in some sense related to the results about the
approximation
of Sobolevmappings
between manifoldsN) ([28],
[3] [2], [15], [4], [13], [12]).
At firstsight
theproblem
seems to bedifferent because of a different nature of Sobolev
mappings N)
and
mappings
However the carefulstudy
shows somedeep
connections between these
problems.
Inparticular
the crucial(for us)
method of retractions
(Lemma 1)
is a modification of theanalogous
methodpreviously
used in the context ofapproximation
of Sobolevmappings
between manifolds
[4], [13].
To see further connections between the
theory
of andmappings
we refer to[14].
By Q"
we will denote a"general"
n-dimensional cube.By
C we willdenote a
general
constant. It canchange
its value even in the sameproof.
Writting
forexample C(n, p),
we will show that this constantdepends
onn and p
only.
2. PROOFS OF THEOREMS 1 AND 3
Before we
proceed
to theproofs
of thesetheorems,
we shall state and prove main technical lemma(Lemma
1below).
Thefollowing mapping
isdefined in
Rn ~ ~ x ~ :
In other words is a
mapping
which is anidentity
on thecomplement
ofthe ball B’~
(x, ~),
and which is aprojection along
radii onto theboundary
~)
inside the ball.Evidently
is discontinuous at z - x.Moreover
Vol. 12, n ° 4-1995.
for z E
Bn (x, ~).
In thesequel
we will use thefollowing
notation. If x =(x 1, ... ,
is a sequence ofpoints
ofRn,
then we setIn the
proof
of Theorems 1 and 3 thefollowing
lemma willplay a
fundamental role.
LEMMA 1. - Let u E
Rn ),
SZ E p n. LetA1, ... , Ak
E .Rnbe a
family of
measurable sets such that(~/2)n |Ai|
oo anddist
(Ai , A~) >
2~for
all i~ j.
Thenfor
almost all x =(xl, ... ,
EAl
x ~ ~ ~ xAk,
o u E Moreover there exists x EAl
x ~ ~ ~ xAk
such that
where the constant
C(n, p) depends
on n and ponly.
Remark. -
Assumption
dist(Ai, A~ ) >
2~ guarantees that the sets=
{x
ERn dist (x, Ai ) ~~
arepairwise disjoint.
Before we
proceed
to theproof
of Lemma 1 we shall be concerned withsome other lemmas.
We say that
f
E ACL if the functionf
is Borel measurable andabsolutely
continuous on almost all linesparallel
to coordinate axes.Since
absolutely
continuous functions are almosteverywhere differentiable, f
E ACL haspartial
derivatives a.e. and hence thegradient ~f
isdefined a.e. Now we say that
f
EACLP (n)
iff
ELP(O)
nACL (n)
LP. The
following
characterization of Sobolev space is due toNikodym ([25], [20,
Section1.1.3]).
THEOREM 4
(Nikodym). -
= A C Lp( SZ ) .
Since
maybe
it is not evident how to understand this theorem, we shall comment it now. This theorem states that each ACLp(H)
functionbelongs
to and thegradient V f,
which is defined a.e. forf
E ACLP(S2)
isjust
the distributionalgradient.
On the other hand, each elementf
E(which
is anequivalence
class of functionsequal
exept the set of measurezero)
admit a Borelrepresentative,
whichbelongs
to the space ACLp
( SZ ) .
LEMMA 2. - Let
f :
X -~ Y be amapping
betweenseparable
metric spaces X and Y.
If f
is a Borelmapping,
then thegraph
Gj = ~ (x, f(x)) I x
EX}
C X x Y is a Borelset.
419
A NOTE ON WEAK APPROXIMATION OF MINORS
Proof -
Let{~4~}~i
be afamily
ofpairwise disjoint
Borel subsets of00
Y such that
U
= Y anddiam A(n)i 1/M.
Then the set00
is Borel and hence
Gy
=n Bn is
also a Borel set.n=1
We also need the
following
famous theorem of Lusin andSierpinski [17], [18], [9,
Thm.2.2.13].
THEOREM 5
(Lusin-Sierpinski). -
Let P : Rn be anorthogonal projection. If B
C is a Borel set, thenP(B)
C Rn is Hn-measurable.Remark. - Note that this theorem is no
longer
valid if we assume that Bis
Hn+k measurable,
instead ofbeing
Borel. Note also that it is not true ingeneral
thatP(B)
is Borel even if B is Borel.We will use the above
Lusin-Sierpinski’s
theorem in theproof
of thefollowing
"Sard’stype"
lemma.LEMMA 3. - Assume that
f : l~~
is a Borelmapping.
Then thefollowing
two conditions areequivalent:
1. For almost all segments I C
parallel
to oneof
the coordinateaxes, = 0.
2. For almost all x E
R~,
the setf -1 (x)
isdisjoint from
almost allsegments
parallel
to oneof
the coordinate axes.Remark. - For
generalizations
and further results see[ 11 ], [13].
Proof. -
Let P :Qn P(xl, ... , xn) _ (x2, ... , ,xn)
be theorthogonal projection
in the directionparallel
to the first coordinate axis. It induces theprojection
P :Q"
x xR~, P(x, ~) _ (P(x), y).
By
Lemma2,
thegraph G f
CQn
x is a Borel set and henceby
Theorem
5,
the set ç x is ®Hk-measurable.
Now it follows
directly
from Fubini’s theorem that thefollowing
threeconditions are
equivalent.
2. For almost all segments
I, parallel
to the axis = 0.3. For almost all X E
R~, f -1 (x)
isdisjoint
from almost all segmentsparallel
to x 1.Vol. 12, nO 4-1995.
Of course one can repeat the above construction with x 1
replaced by
x2, x3, ..., Then the lemma follows
easily.
The above lemma can be
applied
toR~) mappings
as it followsfrom the
following elementary
observation.LEMMA 4. -
If f : [0, 1]
--~ 2 isabsolutely
continuous then= 0.
Proof - Othervise, applying
Fubini’stheorem,
we would find the one dimensional slice of the setf ( [0,1] )
withpositive
one dimensional measure, and such that this slice is theimage
of a certain subset of[0,1]
withthe measure zero. This contradicts the
following
well known fact: Ifg :
[0,1]
~ R isabsolutely
continuous and E C[0,1],
= 0then
H1 (g(E)) =
0(see [27,
Theorem7.18]).
Lemmas 3 and 4 lead to the fact that if
f
EACL(Q", R~),
where l~ > 2,then for almost all X E
Rk,
isdisjoint
from almost all linesparallel
to an
arbitrary
coordinate axis. Hence of
EACL(Q’~, R~)
for almostall X E
R~.
Now we are inposition
to prove Lemma 1.Proof of
Lemma l. - As we havealready
seen, for almost all x EAi
x ~ ~ ~ xAk ,
o u EACL(n);
hence thegradient
ou)
isdefined almost
everywhere
and now in order to prove o u E it suffices to provethat
ou)|]
ELp (SZ) (see
Theorem4).
Evidently
ou(z) = u(z)
for zE 0 B U ~))
and henceis clear that the lemma will follow if we prove the
inequality
Note that id
for j
and hence for almost allz e
421
A NOTE ON WEAK APPROXIMATION OF MINORS
Denoting
the left hand side of(2) by
I we haveIn the last but one
step
we used the estimateThis ends the
proof
of(2)
and hence that of the lemma.Proof of
Theorem 1. - First we will prove the theorem under the additionalassumption
that theimage
of u is bounded i.e.u(x)
EQn
for almost allx E
S2,
whereQn
is a certain cube.Then,
as we will see, thegeneral
casewill follow from the
density
of bounded maps in the strongtopology.
Divide the cube
Qn
in a standard way, into vnidentical,
small cubes.Denote these cubes
by
i =1, 2,..., yn.
be a cube withthe same centre as and half the
edgelength.
Let x Wedefine the retraction
as follows
where
8(x, z)
> 0 is such that E In the otherwords,
inside
C~7i ’v,
is a retractionalong
radii onto with "source" atx.
Evidently
isbilipschitz equivalent
with 1rx,e typemapping (with
6’ =
Cv-l),
so we can repeate theproof
of Lemma1, replacing Ai by
n’v.
This leads to thefollowing corollary:
There exists xi ~ 1 2Qn,03BDi for i =1, 2, ... , vn,
such thatand
Vol. 12, n ° 4-1995.
Evidently
theimage
ofu~"~
is(n - 1)-dimensional.
Since for cp ECB
then it is easy to see
repeating
arguments from theproof
of Lemma 1 that we can choosefor i =
1, 2, ... , vn
in a way, such that in addition to(4)
Now it suffices to prove
that,
afterextracting
asubsequence,
- u inand
adj adj
Du in Lq. We haveu~v~ (z) ~ ] Cv-1
a.e., so
u(v)
-~ u a.e. and hence in LP(since
u andu(v)
arebounded).
The estimations
(4), (5)
show that sequencesDu(v)
andadj Du(v)
arebounded in LP and Lq
respectively.
Henceu~v> ~ u
in and moreoverafter
taking
asubsequence adj
in Lq to a certain H E Lq.By
the theorem of Ball and
Reshetnyak [ 1 ], [26], [5, Chapter 4,
Thm.2.6], [16], adj adj
Du in measures, and henceadj
Du = H. Thiscompletes
the
proof
in the case of bounded maps.Since the constants in the
inequalities (4)
and(5)
do notdepend
onthe size of the cube
Qn,
then the theorem will follow if we prove thedensity
of bounded maps in the strongtopology
of To thisend,
letPR :
Rn[-R, R]n
be a retraction with aLipschitz
constant 1; now it is easy to see thatPR
o uR-~ u
in andadj D (PR
ou) R~ adj
Du inLq
(in
theproof
of the second convergence we use anelementary inequality
This
completes
theproof.
Proof of
Theorem 3. -By
the same reason as in theproof
of Theorem 1,we can assume that u is
bounded,
i.e.u(x)
EQn
for a.e. x, whereQn
is a fixed cube.
At the
beginning
we prove the first part of thetheorem,
i. e. we willbe concerned with the weak convergence of
u~v>,
withouttaking
care ofminors
adj s
In the first step, as in the
proof
of Theorem 1, we compose themapping u
with the discontinuous retraction onto
(n - 1)-dimensional
set which is the union of the boundaries of all cubesQ7’v,
i =1 , 2, ... ,
vn.This way we obtain
(cf.
theproof
of Theorem1)
amapping
E!~
U (~~i ’v)
withi=1
423
A NOTE ON WEAK APPROXIMATION OF MINORS
(uiv)
is thecomposition
of u with a discontinuous retraction describedabove.)
Sinceulv) v u
a.e., then it follows from(6)
thatulv)
inIf
p > n -
1, then theproof
iscompleted.
Hence we can assumethat p n - 1. The set consists of 2n,
(n - 1 )-dimensional
cubes.Now we divide each such
(n - I )-dimensional
cube into afamily
of vn-1very small cubes
(with edgelength Cv-2).
This leads to thedecomposition
vn
=
U
and hence to thedecomposition
ofU ~Q~".
j=i
’
i=l
Now almost the same arguments as in the
proof
of(6)
show that we canvn
compose the
mapping uiv)
with the discontinuous retraction fromU
i=1 onto
(n - 2)-dimensional
setU
This way we obtain themapping
E with
As above then the
proof
iscompleted.
Ifp n - 2, then we can of course continue this construction and compose with retraction onto
(n - 3)-dimensional
set.By induction,
we can continue this construction up to the moment, we compose with retraction onto[p]-dimensional
set. This way we get E with values in[p]-dimensional
set. MoreoverSince
u(03BD)n-[p [ u
a.e., thenby (7), u
inW1,p.
This ends theproof
of the first part of Theorem 3.If we know
additionally
thatadjs Du
e Lqs for some 1(M
+~)/~~
then as in theproof
of Theorem1,
we can assume thatadditionally
to(7),
thefollowing inequality
holdsHence up to a
subsequence, adjs
2014 ~ in L~ to a certain H ~ Theinequality
1 qs([p]+l)/~ implies that? ~
s, henceby
the theorem ofBall-Reshetnyak (cf
theproof
of Theorem1), adjs adjs
Duin measures and hence H =
adjs
Du. This ends theproof
Vol. 12, n° 4-1995.
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