R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
A LBERTO F ACCHINI
Mittag-Leffler modules, reduced products, and direct products
Rendiconti del Seminario Matematico della Università di Padova, tome 85 (1991), p. 119-132
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and Direct Products.
ALBERTO
FACCHINI (*)
SUMMARY - In this paper we prove that every
Mittag-Leffler
module is a pure submodule of a reducedproduct
ofpure-projective
modules. This leads usto look for characterizations of the
rings
over which all reducedproducts
ofMittag-Leffler
modules areMittag-Leffler
modules. Here we focus our at- tention on therings
over which every directproduct
ofMittag-Leffler
mod-ules is a
Mittag-Leffler
module.1. Introduction.
All
rings
have anidentity
and all modules areunitary.
Recall that aleft module M over a
ring R
is said to be aMittag-Leffler
module if the canonicalhomomorphism
is monic for every
family (Ax)
ofright
R-modules[9].
Forinstance,
every
finitely presented
module is aMittag-Leffler
module. The class ofMittag-Leffler
modules is closed for(arbitrary)
direct sums, pure sub- modules and pure extensions. Inparticular pure-projective modules,
which are
exactly
the direct summands of direct sums offinitely
pre- sentedmodules,
areMittag-Leffler
modules.Raynaud
andGruson,
who studied and defined
Mittag-Leffler
modulesfirst, proved
that(*) Indirizzo dell’A.: Universita di
Udine, Dipartimento
di Matematica e In-formatica,
Via Zanon 6, 33100Udine, Italy.
The author is a member of GNSAGA of CNR. This research was
partially
supported by
Ministero della Pubblica Istruzione(Italy).
every countable subset of a
Mittag-Leffler
module M is contained in acountably generated pure-projective
pure submodule of M([9,
Th6o-r6me
11.2.2.1]).
In this paper we prove that every
Mittag-Leffler
module is isomor-phic
to a pure submodule of a reducedproduct fl
where F is aiEI
countably complete
filter on a set I and(Nj )I
EI }
is afamily
of pure-projective
modules(Proposition 2.1).
In order totry
to invert this re-sult,
thatis,
in order totry
to characterize therings
for whichMittag-
Leffler modules are
exactly
the pure submodules of reducedproducts
of
pure-projective modules,
we arenaturally
led to thestudy
of therings
with theproperty
that every directproduct
ofpure-projective
modules is a
Mittag-Leffler
module(or, equivalently,
with the prop-erty
that every directproduct
ofMittag-Leffler
modules is aMittag-
Leffler
module).
We show that thisproperty
is«two-sided»,
in thesense that it holds for the
right
modules over aring
if andonly
if itholds for the left modules over the same
ring (Theorem 3.2).
Then weprove that a left coherent
ring
such that every directproduct
ofMittag-
Leffler modules is a
Mittag-Leffler
module has theproperty
that any intersection offinitely generated
left ideals is afinitely generated
leftideal and all its left annihilator ideals are
finitely generated (Theorem 3.3).
Theorem 3.2 has a very
interesting
consequenceconcerning
the con-jecture according
to which aring
withright
pureglobal
dimension zerohas left pure
global
dimension zero also.Namely
suppose that R is aring
withright
pureglobal
dimension zero. Then everyright
R-moduleis a
Mittag-Leffler module,
so that all directproducts
ofpure-projec-
tive left R-modules are
Mittag-Leffler
modulesby
Theorem3.2, i. e. ,
every countable subset of any direct
product
ofpure-projective
x
left R-modules
M,,
is contained in apure-projective
pure submodule of This isslightly
less thansaying
that any directproduct
of pure-projective
left R-modules ispure-projective,
which would beequiva-
lent to
saying
that R has left pureglobal
dimension zero.In the last section of the paper we show that the
property
that ev-ery direct
product
ofMittag-Leffler
modules is aMittag-Leffler
moduledoesn’t hold for the
ring
Z ofintegers,
that it holds for a valuation do- main if andonly
if the valuation domain is afield,
and that it holds for acommutative von Neumann
regular ring
if andonly
if thering
isself-injective.
There is a close connection between this paper and the papers
[6]
and
[15],
where similar closureproperties
of various classes of modules withrespect
to directproduct
are studied.I wish to take this
opportunity
to thank M.Dugas
for someexplana-
tions about the
techniques employed
in his paper[3].
2.
Mittag-Leffler
modules and reducedproducts.
Let R be an associative
ring
withidentity
and let M be a left R-mod- ule. The module M is said to be aMittag-Leffler
module if the canonicalhomomorphism
is monic for every
family {A,, }
ofright R-modules [9].
Forinstance,
every
pure-projective
module is aMittag-Leffler
module.Raynaud
andGruson
proved
that a module M is aMittag-Leffler
module if andonly
ifevery countable subset of M is contained in a
countably generated pure-projective
pure submodule of M([9,
Th6or6meI I. 2. 2.1 ]
or[1,
Theorem6]).
Let I be any index set and 1F a
countably complete
filter onI,
thatis,
a filter such that intersections of
Ko
elements ofbelong
to ~. IfI)
is afamily
of leftR-modules,
the reducedproducts fl
isiEI
fl
whereTj Ni
is the directproduct
of the modulesNi
andiEI iEI
is the
subgroup
The
proof
of our first result is a modification of theproof
of[3,
Lem-ma
1.1].
PROPOSITION 2.l. Let M be a
Mittag-Leffler left
R-module. Then M isisomorphic
to a pure submoduleof
a reducedproduct IT
iEI
of pure-projective left
modulesNi
modulo acountably complete filter
5.PROOF. Let I =
{i i
cM, Iii
be the set of all countable subsets of M. For every i E I letNi
denote a fixedcountably generated
pure-projective
pure submodule of Mcontaining
i. Let F be the set of allS c I with the
following property:
Then F is a
countably complete
filter onI,
because if,Sn
E tf for everyxi = x ff X E
Ni
and xi = 0 if x fNi . Let p: M -
M be definedby 1J(x) =
= x + for every X E M. We shall prove
that p
is a pure monomor-phism.
Let X, Y E M. In order to show that
p(z
+Y) = 1J(x) + p(y)
we mustshow that
(x +
EU(50 ,
thatis, {i
E +y)i
= xi + E ~.This holds because
{x,
y, x +y}
EI,
and forevery j
E I if{x, y, x + y} c j
then so that =x + y
= Simil-arly
= for every r E R and x EM,
is a homomor-phism.
Now let be such that
~(x) = 0.
Then x Ei. e. , { j
E =0)
={ j
E Therefore there exists i E I with theproperty
that forevery j
E I such that ic j
one In par- ticularif j
= i uthen
= x ENj
This contradiction showsthat q
is monic.Finally,
in order to prove that themonomorphism 1J
is pure suppose thatis a
system
ofequations
with rklE R and bk E M, and
suppose that(S)
has a solution +
U(~,
...,(ani)ieI
+U(~
in M. To showthat 9
is apure
monomorphism
it is sufficient to prove that(S)
has a solution in[13, Proposition 3].
Set1J(bk) = (bki)iEI
+ =1,
..., n. Sincethe + 1 =
1,
... , m, are a solution of thesystem,
it followsthat the sets
are elements of !
But ~,
which is afilter,
is closed for finite intersec-tion,
so thatbelongs
Therefore there exists i E I such that forevery j
E I withone
has ]
l
for every 1~ =
1, ... ,
n. Inparticular for j
=~ we
get
1J(alj),
..., e isa solution
of thesystem (S). Hence q
is pureby [13, Proposition 3].
0Proposition
2.1 cannot be inverted: it is not true that every puresubmodule of a reduced
product
ofpure-projective
left modules moduloa
countably complete
filter T is aMittag-Leffler
module. Forinstance,
every direct
product fl Nj
is a reducedproduct
of thistype (take
F =iEI
= {7}),
and we shall see in Section 4 that there exist directproducts
ofpure-projective
left modules over suitablerings
which are notMittag-
Leffler modules. Thus we are
naturally
led tostudy
when a directproduct
ofpure-projective
modules is aMittag-Leffler
module and in the rest of the paper we shalltry
to describe therings
for which thishappens.
’3.
Mittag-Leffler
modules and directproducts.
We
begin
this section with an easy butinteresting
lemma.LEMMA 3.1. Let M be a
left
R-module. Then M is aMittag-Leffler modute if
andonly if
the canonicalhomomor~phism
is monic
for
everyfamily {Fa} of fini- tely presented right
PROOF. We need the
following
CLAIM.
If AR , RM
areR-modules,
aI, ..., an EA,
XI’ ..., Xn E M andn
Y-
ai 0 xi is the zero elementof
AOR M,
then there exist afinitely
pre-i=1
sented module
FR ,
ahomomor~phism
1J: F -~A,
andb1,
...,bn
E F suchthat is the zero eterrr,ent
of
FOR M
and = aifor
every ... , n.In order to prove the claim fix a direct
system
offinitely presented right
R-modulesAex,
a EL1,
withlimA~.
Then thereexists /3
E L1such that all the elements in the
image
ofAg.
Sincethere
exist y > /3
in 4and
bl , ..., bn
inAY
suchthat )
inAy OR
M and ai is theimage
of bi
in the canonicalhomomorphism Ay -") A.
ThereforeA.,
is therequired finitely presented module,
and the canonical homomor-phism Ay -") A
is therequired homomorphism
p. This proves the Claim. FIn order to prove the Lemma it is sufficient to prove that if
RM
is aleft module that is not a
Mittag-Leffler module,
then there exists afamily
offinitely presented right
modules~F~ ~,~
for which the canonicalhomomorphism Y
is not monic.But if
RM
is not aMittag-Leffler module,
there exists afamily
oflight
modules for which the canonicalhomomorphism
) is not monic. Let be a non- zero element in the kernel of this
homomorphism.
Then the elementsL a,,, i 0 xi
are the zero elements inAx ©
M for every A.By
the Claimi
’
just proved,
for each A there exist afinitely presented
moduleF,~ ,
ahomomorphism px : Fx - Ax
and such that 1JÀ = i and5i
= 0 inF,~
O M. Now construct the commutativediagram
I ’
where the vertical arrows 0 and #’ are induced
by
theThe element is non-zero because its
image
via W is SinceE (8) the
mapping
IF cannot be monic. Thisconcludes
theproof
A
of the Lemma. D
THEOREM 3.2. Let R be a
ring.
Thefollowing
statements areequivalent:
(a) Every
directproduct of Mittag-Leffler left
R-modules is aMittag-Leffer module;
(a’) Every
directproduct of Mittag-Leffler right
R-modules is aMittag-Leffler module;
(b) Every
directproduct of pure-projective left
R-modules is aMittag-Leffler module;
(b’) Every
directproduct of pure-projective right
R-modules isa
Mittag-Leffler module;
(c) Every
directproduct of finitely presented left
R-modules isa
Mittag-Leffler module;
(c’) Every
directproduct of finitely presented right
R-modulesis a
Mittag-Leffler rrtoduLe;
(d) Every
direct powerMX of
aMittag-Leffler left
R-module Mis a
Mittag-Leffler module;
(d’) Every
direct powerMX of
aMittag-Leffler right
R-moduleM is a
Mittag-Leffler module;
(e) Every
direct powerMX of
apure-projective left
R-moduleM is a
Mittag-Leffler module;
(e’) Every
direct powerMX of
apure-projective right
R-rrcoduLeM is a
Mittag-Leffler
module.PROOF. The
implications (a’ )
~(b’ )
~(c’ )
are trivial.(c’)
~(a).
If(c’)
holds and is afamily
ofMittag-Leffler
leftR-modules,
we must provethat IIMa
is aMittag-Leffler module, i.e.,
a
that if is a
family
offinitely presented right
R-modules the homo-morphism
is monic(Lemma 3.1).
Consider the commutative
diagram
The arrow on the left is monic because
fl fx
is aMittag-Leffler
moduleby (c’),
and the lower horizontal arrow is monic because theM«’s
areMittag-Leffler
modules. Therefore the upper horizontal arrow is monic. This proves(a).
Thus we have shown that
(a’)
~(b’)
=>(c’)
=>(a). By symmetry,
thatis, by passing
to theopposite ring,
we obtain that(a)
~(b)
~(c)
~(a’ ).
This proves that the first six conditions(a)-(c’)
are
equivalent.
(e) ~ (b).
If is afamily
ofpure-projective
leftR-modules,
its direct sum M
= @ Mcx
istrivially
apure-projective
left R-module.a EX
If
(e) holds,
thenMX
is aMittag-Leffler
module with a direct summandisomorphic
tofl M~.
This proves(b).
« EX
Since
(a)
==>(d)
~(e)
are trivialimplications,
weget
that(d)
and(e)
also are
equivalent
to the first six conditions. The conclusion followsimmediately.
DA
ring
R is said to be coherent if everyfinitely generated
left idealis
finitely presented,
or,equivalently,
if every directproduct
of flatright
R-modules is flat
[12, § I.13].
It ispossible
to prove that R is left coherent if andonly
if the left annihilator1(x) = {r
E Rrx
=0}
of every elementX E R is a
finitely generated
left ideal and the intersection of twofinitely generated
left ideals isfinitely generated.
Also recall that a left annihila- tor ideal of R is a left ideal I in R for which there exists a subset S c R such that I =L(S) _ {r
e = 0 forTHEOREM 3.3. Let R be a
Left
coherentring
such that every directproduct of Mittag-Leffler left
R-modules is aMittag-Leffler
module.Then all
left
annihilator idealsof
R arefinitely generated,
and so arearbitrary
intersectionsof finitely generated left
ideals.PROOF: Let be a
family
offinitely generated
left ideals of R.Then the left modules are
finitely presented,
sothat IIR/Ik
is aMittag-Leffler
module. LetA
be the canonical
monomorphism. By [7,
TheoremI] p
factorsthrough
amonomorphism
rl
IÀ
-N,
where N isfinitely presented.
Since R is leftcoherent,
the module Rl rl
Ix
also isfinitely presented, i.e.,
the left ideal nIÀ
isfinitely generated [12, Proposition I.3.2].
Thereforearbitrary
intersec-tions of
finitely generated
left ideals arefinitely generated.
Now let
l(S)
be a left annihilator ideal of R. Thenl(S)
= rl1(x)
is anxES
intersection of left ideals that are
finitely generated
because R is left coherent. Thereforel(S)
isfinitely generated.
DREMARK 3.4. The class e of all the
rings
R such that every directproduct
ofMittag-Leffler
R-modules is aMittag-Leffler
module could have a close connection with the class e’ of allrings
R such that every di- rectproduct
oflocally projective
left R-modules islocally projective [15].
We shall see in
Example
4.1 that thering
Z ofintegers
is not in e. Sinceevery
right
noetherianring
is in e’[15, Corollary 4.3]
it follows that e’ is not contained in e. We do not know if e is a proper subclass of ~’ . If thiswere true every
ring
in e would beright
and left coherent and our Theo-rem 3.3 would
immediately
follow from[15, Corollary 4.3].
4.
Examples.
EXAMPLE 4.1. THE RING Z. The
ring
Z ofintegers
does not have theequivalent properties
stated in Theorem 3.2. To see this letZ(p)
be thecyclic
groupwith p
elements for eachprime
p. Let us show that condi-tion
(c)
of Theorem 3.2 does not holdby proving
that the directproduct where p
ranges in the set of allprimes,
is not aMittag-Leffler
p
Z-module.
By making
use of[1, Proposition 7]
it is sufficient to prove that ~ is not an group, where t denotes the tor- sionsubgroup,
andKl-free
means that all its countablesubgroups
arefree
[4, § 19].
It is very easy to show that D =0~(p)
p and thatis a divisible abelian group. Therefore
]
r - r r
is a nonzero torsion-free divisible abelian group; in
particular
it cannotbe
N1-free.
Note that every direct power
M~
of afinitely presented
Z-moduleM is a
Mittag-Leffler
Z-module. Infact,
if M is anyfinitely presented Z-module,
the exact sequence 0-") t(M)
- M -~M/t(M) --~
0 induces ashort exact sequence 0 -
MX -")
- 0. NowM/t(M)
is a finite direct
product
ofcopies
ofZ,
so that is a directproduct
ofcopies
ofZ,
and therefore it isSi-free [4,
Theorem19.2].
Moreover, t(M)
is torsion of boundedorder,
so that is torsion of bounded order. ThereforeMX ,
extension of anN1-free
abelian groupby
a torsion group of bounded
order,
is aMittag-Leffler
Z-module[1, Proposition 7].
This proves that the conditionEvery
direct powerMx of
a
finitely presented
R-module M is aMittag-Leffler
module isstrictly
weaker than the ten
equivalent
conditions of the statement of Theo-rem 3.2.
EXAMPLE 4.2. VALUATION RINGS. If R is a valuation domain that is not a
field,
R does not have theequivalent
conditons stated inTheorem 3.2.
To prove
this,
suppose R is a valuation domain that is not a field and with theproperty
that every directproduct
ofMittag-Leffler
R-mod-ules is a
Mittag-Leffler
R-module. Under thesehypotheses
there existsa non-zero element r E R that is not invertible. Then P = rl Rrn is a n:l
prime
ideal[5, Proposition I.1.6(d)]. By
Theorem 3.3 P is afinitely
gen- erated ideal because it is an intersection offinitely generated
ideals andany valuation domain is coherent. Since R is a valuation
domain,
P is a
principal prime ideal,
so that either P = 0 or P is maximal[5, Proposition I.1.6(b)].
Since r is notinvertible,
one has Rr JD
Rr2 ;¿ P,
and therefore P cannot be the maximal ideal. This proves that P = 0. Now consider the module M =I1 R/Rr2n .
Since M is a di-n>1
rect
product
offinitely presented modules,
M is aMittag-Leffler
mod-ule. For each t .1 let xt =
(xn,
be the element of M definedby
Let N be the submod-
ule of M
generated by
the set{xt ~ t ~ 1 ~.
Since M is aMittag-Leffler module,
there exists apure-projective
submoduleQ
of M with N ;Q [9,
Th6or6me11.2.2.1]. Then Q
iscyclically presented [5,
TheoremII.3.4 and
Proposition II.4.3],
sothat Q
= F OT,
where F is free and T is torsion. ThenN~Q~M implies
that N + ++
t(M)/t(M) ~
wheret(M)
is the torsion submodule of M andQ
+Consider the torsion-free module
+
t(M)/t(M).
It isgenerated by
the sett
~11,
where the bar denotes reduction modulot(N),
and it is easy toverify
that?-Yt+l = Yt
for every t ~ 1. It follows that rN = N. But if x is a nonzero element of R then x 0 Rrn for some n(because
Q Rr"‘ =0).
ThereforeRx ¿
so thatxN ¿ rn N = N, i.e.,
N is a divisible R-module. Hence N = N ++
t(M)/t(M)
is a torsion-free divisible R-module contained in the free R- moduleQ
+t(M)/t(M).
Thisimplies
that N =0, i.e.,
N ct(M)
is torsion.This contradiction proves that a valuation domain that is not a field does not have the
equivalent
conditions stated in Theorem 3.2.Most of what we
proved
above for valuation domains can be extend- ed to coherent valuationrings
that are notintegral
domains.Namely,
ifR is a coherent valuation
ring (i.e.,
a coherent commutativering
whoseideals are
linearly
orderedby
setinclusion),
which has theproperty
that every directproduct
ofMittag-Leffler
modules is aMittag-Leffler module,
then any intersection ofprincipal
ideals isprincipal by
Theo-rem 3.3. It follows
(as
in the case of valuationdomains),
that R has ex-actly
oneprime
ideal[5, Proposition I.1.6].
Moreover its value semi- groupG,
which is a0-segmental semigroup, i.e.,
it is the extended po- sitive cone of atotally
ordered abelian group modulo an ideal[10],
iscomplete
as a lattice(compare [6, Example 5.3]).
EXAMPLE 4.3. VON NEUMANN REGULAR RINGS.
PROPOSITION 4.4. Let R be cc von Neumann
regular ring.
(1) Every
directproduct of left Mittag-Leffler
R-modules is aMittag-Leffler
R-moduleif
andonly if
the direct powerRR
is aMittag- Leffler right
(2) If
R is aleft self-injective ring,
then every directproduct of left Mittag-Leffler
R-modules is aMittag-Leffler
R-module.(3) If R
iscommutative,
then every directproduct of Mittag-Lef fler
R-modules is aMittag-Leffler
R-moduleif
andonly if
R isself-injective.
PROOF.
(1)
The«only
if»part
followsimmediately
from Theorem 3.2(a)
-(e’ ).
For the converse suppose that{Mk}
is afamily of Mittag-
Leffler left R-modules and that
R R
is aMittag-Leffler right
R-module.By [7, Corollary],
in order to prove thatJIM,
is aMittag-Leffler
left R-module it is sufficient to prove that the natural map is
inj ective.
For this it isenough
to observe that the natural mapR R O (~ M~ ) ~ M,
can be written as thecomposi-
tion of the three canonical maps
where the first map is
injective
becauseRR
is aMittag-Leffler right module,
the second map isinjective
because theMx’s
areMittag-Leffler modules,
and the third map is the obviousisomorphism.
(2)
If R is a leftself-injective regular ring,
thenR R
is aregular left
modules in the sense ofZelmanowitz [14],
thatis, given
any m ER R
there existsf
EHomR (RR, R)
such thatf(m).
m = m[14,
Theorem2.10]. By [14, (1.4)]
allfinitely generated
submodules ofRR
are regu-lar,
henceprojective [14, Corollary 1.7].
ThereforeRR
is aMittag-Lef-
fler left R-module
[7, Corollary]. By
Part(1)
every directproduct
ofright Mittag-Leffler
R-modules is aMittag-Leffler
R-module. The con- clusion followsimmediately by
Theorem 3.2.(3)
The «if»part
hasjust
beenproved.
The converse follows from[7,
Theorem2, (b)
=>(c)].
05. Remarks.
(1)
We saw inProposition
4.4 that over a von Neumannregular ring
R the class ofMittag-Leffler
modules is closed forproducts
if andonly
ifR R
is aMittag-Leffler right
module(by
Theorem 3.2 thishap-
pens if and
only
if the left moduleR R
is aMittag-Leffler module).
Thebehaviour of noetherian
rings
iscompletely
differentbecause,
as weshow in the next
paragraph,
over aright
noetherianring
R every di- rect powerR x
is aMittag-Leffler
left R-module(this
is alsoproved
in[15, Corollary 4.3]
and in[9, Example II.2.4.1],
but here wegive
a very easyproof
of thisfact).
Note that over thering
Z there areproducts
offinitely presented
modules that are notMittag-Leffler
modules(Exam- ple 4.1).
Let us prove that if R is a
right
noetherianring
every direct powerR X
is aMittag-Leffler
left R-module. If R is aright
noetherianring
andAR
is aright R-module,
then the natural map A OR X
-A~
is monic[7,
Theorem
1].
Therefore for everyfamily
ofright
R-modules(Ax)
thevertical arrows in the
diagram
are
monomorphisms,
and the lower horizontal map is anisomorphism.
Therefore the upper horizontal arrow is a
monomorphism, i.e., R X
is aMittag-Leffler
left R-module.(2)
The class e of therings
over which every directproduct
ofMittag-Leffler
modules is aMittag-Leffler
module contains(a)
therings
with left pureglobal
dimension zero or withright
pureglobal
dimension zero, because all left(right)
modules over these
rings
areMittag-Leffler
modules([11,
Theorem
6.3]
or[1,
Theorem8]);
(b)
theself-injective
von Neumannregular rings (Proposition 4.4);
(c)
theendomorphism ring R
= of a vector space Vover a field K. This
ring
R is a von Neumannregular ring,
which is not
self-injective
if V is of infinite dimension. B.Zimmermann-Huisgen proved
in[15, Example 4.7]
thatthe left R-modules
R X
areregular,
so thatR R
is aMittag-
Leffler R-module
(repeat
theproof
ofProposition 4.4(2)).
From
Proposition 4.4(1)
we conclude that every directproduct
ofMittag-Leffler
modules over thering R
==
End (10
is aMittag-Leffler
module.(3)
The class e of therings
we have studied in this paper, thatis,
the
rings
over which every directproduct
ofMittag-Leffler
modules isa
Mittag-Leffler module,
isexactly
the class of therings
over which ev-ery direct
product
ofpure-projective
modules is aMittag-Leffler
mod-ule
(Theorem 3.2). Suppose
we want tostudy
the subclass P of e con-sisting
of therings
over which every directproduct
ofpure-projective
left R-modules is
pure-projective.
Then therings
in this subclass 0 areexactly
therings
with left pureglobal
dimension zero. I would like tothank
professor
Daniel Simson for thisinteresting
remark.(4)
In Section 2 weproved
that everyMittag-Leffler
module is apure submodule of a reduced
product
ofpure-projective
modules. In or-der to reverse this result we should have studied when all pure sub-
modules of reduced
products
ofpure-projective
modules areMittag-
Leffler
modules,
or,equivalently,
when all reducedproducts
of pure-projective
modules areMittag-Leffler
modules. Since thisproblem
turned out to be almost
intractable,
we decided tostudy
when directproducts.
ofpure-projective
modules areMittag-Leffler
modules andconstruct some
examples
andcounterexamples.
This is what we did in Sections 3 and 4. We conclude this paper with a remark about aparticu-
lar case of reduced
products
ofpure-projective
modules.Suppose
that R is an artinalgebra (that is,
aring
which isfinitely generated
as a module over a commutative artinianring)
with the prop-erty
that every directproduct
ofMittag-Leffler
modules is aMittag-
Leffler module. If M is a
finitely generated R-module,
thengiven
any index set I and any filter d onI,
the reducedproduct MI/f! of copies
ofM modulo F is a
Mittag-Leffler
R-module.To prove
this,
note that under thesehypotheses
the submoduleof
MI (notations
as in Section2)
is a direct summand ofMI (proof
of Theorem F in
[8]).
ThereforeMI/dis isomorphic
to a direct summand ofMI ,
which is aMittag-Leffler
module. The conclusion followsimmediately.
REFERENCES
[1] G. AZUMAYA - A.
FACCHINI, Rings of
pureglobal
dimension zero and Mit-tag-Leffler modules,
J. PureAppl. Algebra,
62(1989),
pp. 109-122.[2] S. U.
CHASE,
Directproduct of modules,
Trans. Amer. Math.Soc.,
97(1960),
pp. 457-473.[3] M.
DUGAS,
On reducedproducts of abelian
groups, Rend. Sem. Mat. Univ.Padova,
73(1985),
pp. 41-47.[4] L.
FUCHS, Infinite
AbelianGroups,
VolumeI,
AcademicPress,
New Yorkand
London,
1970.[5] L. FUCHS - L.
SALCE,
Modules over ValuationDomains,
MarcelDekker,
New York and
Basel,
1985.[6] G. S.
GARFINKEL, Universally
torsionless and tracemodules,
Trans.Amer. Math.
Soc.,
215(1976),
pp. 119-144.[7] K. R.
GOODEARL, Distributing
tensorproduct
over directproduct,
Pacific J.Math.,
43(1972),
pp. 107-110.[8] C. U. JENSEN - B.
ZIMMERMANN-HUISGEN, Algebraic
compactnessof uLtra-
powers and
representation
type, Pacific J.Math.,
139( 1989),
251-265.[9] M. RAYNAUD - L.
GRUSON,
Critères deplatitude
et deprojectivité,
Inven-tiones
Math.,
13(1971),
pp. 1-89.[10] T. S.
SHORES,
Ongeneralized
valuationrings, Michigan
Math.J.,
21(1975),
pp. 405-409.
[11] D.
SIMSON,
On pureglobal
dimensionof locally finitely presented
Grothendieck
categories,
FundamentaMath.,
96(1977),
pp. 91-116.[12] Bo
STENSTRÖM, Rings of Quotients, Springer-Verlag, Berlin-Heidelberg-
New
York,
1975.[13] R. B.
WARFIELD, Purity
andalgebraic compactness for modules,
Pacific J.Math.,
28(1969),
pp. 699-719.[14] J. M.
ZELMANOWITZ, Regular moduLes,
Trans. Amer. Math.Soc.,
163(1972),
pp. 341-355.[15] B.
ZIMMERMANN-HUISGEN,
Pure submodulesof direct products offree
mod-ules,
Math.Ann.,
224(1976),
pp. 233-245.Manoscritto pervenuto in redazione il 14