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Axisymmetric eddy current inspection of highly conducting thin layers via asymptotic models
Houssem Haddar, Zixian Jiang
To cite this version:
Houssem Haddar, Zixian Jiang. Axisymmetric eddy current inspection of highly conducting thin layers
via asymptotic models. Inverse Problems, IOP Publishing, 2015. �hal-01214308�
onduting thin layers via asymptoti models
Houssem Haddar
∗
, ZixianJiang
†
Abstrat
Thin opper deposits overing the steam generator tubes an blind eddy urrent probes in non-
destrutivetestingsofproblematifaultsandarethereforeimportanttobeidentied.Existingmethods
basedon shape reonstrutionusing eddy urrent signalsenounter diulties ofhigh numerialosts
duetothelayer'ssmallthiknessandhighondutivity.Inthisartile,weapproximatetheaxisymmetri
eddyurrent problemwithsomeappropriateasymptotimodelsusingeetive transmissiononditions
representingthe thindeposits. Inthese models, the geometrial information related to the deposit is
transformedintoparameteroeientsonatitiousinterfae. Standarditerativeinversionalgorithmis
thenappliedtotheasymptotimodelstoreonstrutthethiknessofthethinopperlayers. Numerial
testsbothvalidatingtheasymptotimodelandshowingbenetoftheinversionproedureareprovided.
Keywords: axisymmetrieddyurrent inspetion,asymptotimodel, thiknessreonstrution ofthin
layers.
1 Introdution
Thinlayersofopperdepositsareobservedinnon-destrutiveeddyurrenttestingofsteamgeneratortubes
forthe safetyand failure-free operatingof nulearpowerplants. Coveringthe shell sideof thetube, these
deposits lead to a signiant signal feedbak in the eddy urrent inspetion due to the high ondutivity,
despite their extremely small thikness (see Table 1for a omparison with the tube). These deposits do
notdiretlyeet theprodutivityof steamnor thesafetyof struture. Howevertheirpresene may mask
otherkindsofproblematifaultssuhasloggingmagnetitedeposits, raksintubes,et. Thisis whyitis
importantto identifythem.
tubewall opperlayer
ondutivity(in
S · m
−1)σ t = 0.97 × 10 6 σ c = 58.0 × 10 6
thikness(in
mm
)r t
2− r t
1= 1.27 0 ≤ f δ (z) ≤ 0.1
Table1: Condutivityandsaledierenesbetweentubewallandopperlayer.
Inpreviousstudies, we modeledthe axisymmetrieddy urrentproblem withan eientnite element
approximationwhih involvesartiial boundaryonditionsto ut o theomputational domainand thus
redue thenumerial ost(see [10℄). Basedon this model isdevelopedan inversionalgorithmusing shape
optimization methods to reonstrut the shape of some logging magnetite deposits [12℄. These methods
anbenaturally applied to thiknessreonstrution of thin opperdeposits. However, amajor numerial
hallenge to dealwith this aseis thehigh numerialost resulting from thefat that the omputational
domainshouldbedisretizedintoanemeshwiththesamesaletothelayerthiknessoftheopperdeposits.
Besidesadaptivemeshreningmethod(seeforexample[7℄),anotherwidelypratiedstrategytoredue
omputational ost onsists in modeling the thin deposit with eetive transmission onditions (see for
example[19℄, [21℄). [20℄ in partiular suppliesanalysis andomparison of dierent impedanetransmission
onditionsforthinsheetsintwodimensionaleddyurrentmodel. Thesetransmissiononditionsareobtained
bymathingtheasymptotiexpansionsofthesolutionwithrespetto asmallparameterharaterizingthe
∗
houssem.haddarinria.fr,DÉFIteam,INRIASalay,Palaiseau,Frane.
†
zixian.jiangpolytehnique.edu,DÉFIteam,INRIASalay,Palaiseau,Frane.
perspetive,anadditionalmajoradvantageofasymptotimodel istoavoidre-meshingat eahiteration. A
rih literature on asymptoti models has beendeveloped for dierent approahes and various appliations
(seeforexample[3℄,[2℄,[6℄,[5℄,[4℄, [18℄,[13℄,[14℄, [22℄andthereferenestherein).
In the researh note [9℄ the authors built and ompared several asymptoti models using a family of
eetive transmission onditions
{Z m,n } m,n∈{0,1,2}
for the axisymmetri eddy urrent inspetion of thin opper deposits. Roughly speaking, if the thikness of a thin deposit at vertial positionz
of the tubewrites
f δ (z) = δd(z)
, then theindexm
of thetransmission onditionZ m,n
denotes are-saling parameterof the opper ondutivity with regard to
δ
:σ c = σ m /(δ m )
, while the indexn
stands for the order ofasymptotiexpansionofthesolutionwith respetto
δ
. Numerialtests thereinonaredued1Dasewithonstant deposit thikness showthat theasymptoti modelswith
Z 1,n
(n = 0, 1
)onditionsgivesatisfyingapproximationofthefullmodelandleadto easyonstrutionofinversionmethods.
Inthis artilewerst introduetheaxisymmetri modelforeddy urrenttesting andsomeusefulteh-
niquestodeveloptheasymptotimodels(Setion2). Usingthesamemethodpresentedin[9℄,wethenbuild
thevariationalasymptoti modelswith
Z 1,n
(n = 0, 1
)transmissiononditionsfor generalaseswith vari- abledeposit thikness(Setion3). Byintroduing adjointstatesassoiatedtoderivativesoftheimpedanemeasurements,weformulate theinverseproblem forthiknessreonstrutionastheminimizationof aleast
square ost funtional of layerthikness by gradient desent (Setions 4). Finally, numerialexamples of
modelvalidation,measurementapproximationandthiknessreonstrutionaregiveninSetion(5). Forthe
useofasymptotimodelsininverseproblemswemayite[8℄,[15℄and[16℄forvariousappliations.
2 Asymptoti approximation of axisymmetri eddy urrent model
This setion is devoted to a formal derivation of asymptoti models for eddy urrent problems with the
preseneofhighlyonduting thindeposits. Theobjetiveistogettheeetivetransmissiononditionson
theinterfaebetweenthethinlayerandthetubewithwhihthevariationalasymptotimodelhasnolonger
thevolumeintegralonthethinlayerdomain.
First let us briey introdue the axisymmetri eddy urrent problem. For more details readers may
refer to [10℄. In the ylindrial oordinates, a vetor eld
a
an be deomposed into the meridian parta m = a r e r + a z e z
and the azimuthal parta θ = a θ e θ
.a
is axisymmetri if∂ θ a
vanishes. Under the assumption of axisymmetry and the low eletri permittivity / low frequeny regime (ωǫ ≪ σ
), the 3-Dtime-harmoniMaxwell'sequationsfortheeletriandmagnetields
( E , H ) ( curl H + (iωǫ − σ) E = J
inR 3 ,
curl E − iωµ H = 0
inR 3 ,
withadivergene-freeaxisymmetriappliedsoure
J
(div J = 0
)anbereduedtoaseondorderequationona2-Ddomain
R 2 + := { (r, z) : r ≥ 0, z ∈ R}
fortheazimuthalpartoftheeletrieldE θ
that wedenoteinthesequelby
u = E θ
:− div 1
µr ∇ (ru)
− iωσu = iωJ θ = iωJ
inR 2 + ,
(1)where
∇ := (∂ r , ∂ z ) t
anddiv := ∇·
are gradient and divergene operators in 2-D Cartesian oordinates.Assume that
J ∈ L 2 (R 2 + )
has ompatsupport, and thatµ
andσ
areinL
∞(R 2 + )
suh thatµ ≥ µ v > 0
,σ ≥ 0
and thatµ = µ v
,σ = 0
forr ≥ r 0
suiently large. Then problem (1) with a deay ondition atinnity(
u → 0
asr 2 + z 2 → 0
)hasauniquesolutioninH (R 2 + )
whereforanyΩ ⊂ R 2 +
wedenoteH(Ω) := n
v : r
1/
2(1 + r 2 )
−λ/
2v ∈ L 2 (Ω), r
−1/
2∇ (rv) ∈ L 2 (Ω) o
with
λ
anyreal> 1
(see[10℄). LetusindiatethatifΩ
isboundedinther
-diretionthenH (Ω)
isequivalenttothefollowingspaeforwhihweshallusethesamenotation
H(Ω) := n
v : r
1/
2v ∈ L 2 (Ω), r
−1/
2∇ (rv) ∈ L 2 (Ω) o
.
a(u, v) :=
Z
Ω
1
µr ∇ (ru) · ∇ (r¯ v) − iωσrw¯ v
dr dz = Z
Ω
iωJ ¯ vr dr dz ∀ v ∈ H (Ω).
(2)Fornumerial reasons, the omputational domain will be trunated in radialdiretion at
r = r
∗ withr
∗> 0
suientlylarge,andwesetaNeumannboundaryonditiononr = r
∗. Thesolutiontothetrunatedproblemshouldsatisfy(1)on
Ω = B r
∗:= { (r, z) ∈ R 2 : 0 ≤ r ≤ r
∗}
. Thisiswhyweshalluseinthesequelthegenerinotationforthevariationalspae
H (Ω)
withΩ
denotingR 2 +
orB r
∗. Wealsoreallthattheproblemon
Ω = B r
∗ anbeequivalentlytrunated toaboundeddomainB r
∗,z
∗= { (r, z) ∈ R 2 : 0 ≤ r ≤ r
∗, | z | < z
∗}
byintroduingappropriateDirihlet-to-Neumannoperatorsontheboundaries
Γ
±:= { (r, z) : 0 ≤ r ≤ r
∗, z =
± z
∗}
. This would be onvenient for aelerating numerial evaluation of the solution. The analysis andexamplesofdomaintrunationusingNeumannandDirihlet-to-Neumannboundaryonditionsanbefound
in[10℄. Weremarkthatthederivationoftheasymptotimodelsandtheinversionmethodsinthesequelare
independentof the domain trunation strategy. This is whyweuse the variationalformulation(2) as our
startingpointand thenweapplydomaintrunationinthenumerialexamples.
Finally letusspeifytheproblem settingsof eddy urrenttestingfor thin layerdeposit. Weonsider a
thinopperdepositoveringaxisymmetriallytheshell sideofthetube(seeFigure1foraradialutofthe
setting in theylindrial oordinate system, the
z
-axis is the tube axis, the thin deposit shown in blue isexaggeratedin thikness). The eddy urrent probeis omposed oftwooaxialoils, whose radialutsare
representedbytwosmallretanglesinFigure 1,that movein the
z
-diretionduring asan.Onthedomainofproblem
Ω
,wedenoteΩ
±:= { (r, z) ∈ Ω : r ≷ r t
2}
. TheappliedurrentJ
issupportedbytheoils,therefore
suppJ ⊂ Ω
−. ThedepositlayerisdepitedbyΩ δ c ⊂ Ω +
withavariablethiknessf δ (z)
(exaggeratedinthikness,showninblue). Wedenoteby
u δ
±theeletrieldsoutsidethedepositlayer,withu δ
− onΩ
− andu δ +
onΩ + \ Ω δ c
, andbyu δ c
thein-layereletrield, i.e. onΩ δ c
.Tube Deposit
z
r
Coils
uδ− uδc uδ+
fδ(z) rt1 rt2
Γt2 Γc Γt1
Ωδ c
Ω− Ω+
Figure1: Representationof theeddyurrenttestingofathinlayerdeposit.
2.1 Resaled in-layer eddy urrent equation
Therststep isto rewritethein-layereddyurrentequationby resalingtheoordinatein thetransverse
diretion and theondutivity with respet to thelayerthikness. Theanalytialsolution of this resaled
equation allowsto get arelation between the boundary valuesof Dirihlet andNeumann type onthe two
longitudinalboundariesofthethinlayer.
Weassume thatthe thikness
f δ (z)
writesf δ (z) = δd(z)
, withδ > 0
asmall parameterandd(z) > 0
adimensionlessquantity. Asweareonernedonlywiththe
Z 1,n
(n = 0, 1
)transmissiononditions(see[9℄), weresalethedepositondutivitybyσ c = σ 1 /δ
,wheretheresaledondutivityσ 1
isonsiderablysmaller thanσ c
. Weresalealsotheoordinateinthetransversediretionofthedepositsbythehangeofvariableρ = (r − r t
2)/δ
withρ ∈ [0, d(z)]
,and wedenote byu(ρ, z) := ˜ u δ c (r t
2+ δρ, z)
the resaledin-layersolution.Let
k 1
besuhthat(k 1 ) 2 = iωµ c σ 1
. From(1) andtheresalingsettings,weobtain∂ ρ 2 u ˜ = − δ B 1 1 u ˜ − δ 2 B 1 2 u ˜ − δ 3 B 3 1 u ˜ − δ 4 B 1 4 u, ˜
(3)B 1 1 = 2ρ r t
2∂ ρ 2 + 1 r t
2∂ ρ + k 1 2 , B 1 2 = ρ 2
r 2 t
2∂ ρ 2 + ρ
r 2 t
2∂ ρ − 1
r 2 t
2+ ∂ z 2 + 2ρ r t
2k 2 1 , B 3 1 = 2ρ
r t
2∂ z 2 + ρ 2
r t 2
2k 2 1 , B 1 4 = ρ 2 r 2 t
2∂ z 2 .
2.2 Transmission onditions between in-layer eld and elds outside the layer
Thetransmissiononditionsbetweentheeldinside thetube
u δ
− andthein-layereldu δ c
areu δ
−= u δ c
andµ
−1t ∂ r (ru δ
−) = µ
−1c ∂ r (ru δ c )
onΓ t
2.
(4)Thetransmissiononditionsbetween
u δ c
andtheeldoutsidethedeposit layeru δ +
writeu δ + = u δ c
andµ
−1v ∂ n (ru δ + ) = µ
−1c ∂ n (ru δ c )
onΓ c .
(5)Withtheunit normalandtangentialvetorson
Γ c
at thepoint(r t
2+ δd(z), z) n = (1, − δd
′(z))
p 1 + (δd
′(z)) 2
and
τ = (δd
′(z), 1) p 1 + (δd
′(z)) 2 ,
werewrite(5) usingvetordeompositiononthesediretions
( n , τ ) u δ c = u δ +
and∂ r (ru δ ) = µ c /µ v + (δd
′) 2
1 + (δd
′) 2 ∂ r (ru δ + ) + (1 − µ c /µ v ) δd
′1 + (δd
′) 2 ∂ z (ru δ + )
onΓ c .
(6)Togetherwiththepartialdierentialequationforthein-layereld(3), thesetransmissiononditionson
bothsidesofthethin layerasboundaryonditionswillservetoestablishCauhyproblems whosesolutions
linktheeldsonbothsidesofthethin layer,thatisarelationshipbetween
u δ
− onΓ t
2 andu δ +
onΓ c
. Togettheeetivetransmissiononditionson
Γ t
2, wefurtherapplyaTaylorexpansionofu δ +
.2.3 Extension of
u δ +
using Taylor's expansionsTogeteetivetransmissiononditionslinkingup
u δ
±ontheinterfaeΓ t
2 betweentubeandthindeposit,weshouldextendtheeld
u δ +
,originallydened onlyonΩ + \ Ω c
,tothewholedomainΩ +
. Anaturalapproahwould be to assumethat the extendedeld, still denoted by
u δ +
, satises the sameeddy urrentequation(1)as
u δ +
onΩ + \ Ω c
, i.e. with oeientsof thevauumµ = µ v
,σ = σ v = 0
. We remark that therighthand side of equation(1) vanishesin
Ω +
sineJ
hassupport onlyinΩ
−. Usingthe variable substitutionν = r − r t
2,onerewrites(1)inΩ +
asX 4 j=0
ν j A j (ν∂ ν , ∂ z ) u δ + = 0,
(7)where
A 0 (ν∂ ν , ∂ z ) = (ν∂ ν ) 2 − ν∂ ν , A 1 (ν∂ ν , ∂ z ) = 2 r t
2(ν∂ ν ) 2 − 1 r t
2ν∂ ν , A 2 (ν∂ ν , ∂ z ) = 1
r 2 t
2(ν∂ ν ) 2 − 1
r t 2
2+ ∂ z 2 , A 3 (ν∂ ν , ∂ z ) = 2 r t
2∂ z 2 , A 4 (ν∂ ν , ∂ z ) = 1 r 2 t
2∂ z 2 .
Theasymptotiexpansionof
u δ +
withrespettoδ
isintheformu δ + (r, z) = P
∞n=0 δ n u + n (r, z)
. Obviouslyeahterm
u + n (r, z)
veriesthesameequation(7). With Taylorseriesexpansion,onehasu + n (r t
2+ ν, z) =
X
∞k=0
ν k u + n,k (z)
whereu + n,k (z) = 1
k! ∂ ν k u + n
(r t
2, z).
Sine
ν∂ ν (ν k u + n,k (z)) = k(ν k u + n,k (z))
, we an indeed writeA i (ν∂ ν , ∂ z )
asA i (k, ∂ z )
while it is applied to(ν k u + n,k (z))
. Thus,from(7)onehasP 4
j=0
P
∞k=0 A j (k, ∂ z )(ν k+j u + n,k ) = 0.
TheequalityatorderO (ν k )
givesA 0 (k, ∂ z ) u + n,k = −
X 4 j=1
A j (k − j, ∂ z ) u + n,k−j ,
with
u + n,−1 = u + n,−2 = u + n,−3 = u + n,−4 = 0
. NowweonsiderA 0 (k, ∂ z ) = k 2 − k
. Fork ≥ 2
,A 0 (k, ∂ z ) 6 = 0
,thus invertiblewithitsinverse
A
−10 (k, ∂ z ) = k
21
−k. Sowehaveu + n,k = −A
−10 (k, ∂ z )
X 4 j=1
A j (k − j, ∂ z ) u + n,k−j
, k ≥ 2.
(8)Nowweindutivelydenetwofamiliesofoperators
{S k 0 (∂ z ) , S k 1 (∂ z ) }
:S 0 0 := Id, S 0 1 := 0, S 1 0 := 0, S 1 1 := Id,
k ≥ 2
S k 0 := −A
−10 (k, ∂ z )
X 4 j=1
A j (k − j, ∂ z ) S k−j 0 (∂ z )
,
S k 1 := −A
−10 (k, ∂ z )
X 4 j=1
A j (k − j, ∂ z ) S k−j 1 (∂ z )
.
(9)
From the indution (8) one gets
u + n,k (z) = S k 0 (∂ z ) u + n (r t
2, z) + S k 1 (∂ z ) ∂ r u + n (r t
2, z)
. Therefore we havethefollowingexpansion
u + n (r t
2+ ν, z) = X
∞k=0
ν k
S k 0 (∂ z ) u + n + S k 1 (∂ z ) ∂ r u + n
(r t
2, z),
∂ r u + n (r t
2+ ν, z) = X
∞k=0
ν k (k + 1)
S k+1 0 (∂ z ) u + n + S k+1 1 (∂ z ) ∂ r u + n
(r t
2, z).
Wealsodene theoperators
S e k 0 := S k 0 − r 1
t2
S k 1
andS e k 1 := r 1
t2
S k 1
. ThentheaboveTaylorexpansionswrite
u + n (r t
2+ ν, z) = X
∞k=0
ν k
S e k 0 (∂ z ) u + n + S e k 1 ∂ r (ru + n )
(r t
2, z),
∂ r (ru + n )(r t
2+ ν, z) = X
∞k=0
ν k (k + 1)
(r t
2S e k+1 0 + S e k 0 )u + n + (r t
2S e k+1 1 + S e k 1 )∂ r (ru + n )
(r t
2, z).
(10)
Althoughonly asymptotiproblems oforder
0
and1
aredisussed in thesequel, theaboveexpressionsfor anyordersouldfailitatefurtherexploitationsbeyondthesopeoftheurrentwork.3 Asymptoti models for deposits with variable layer thikness
Inthissetion,webuild theasymptotimodelsoforder
0
and1
forthin deposits ofvariable thikness,thatis to establishthe transmissiononditions
Z 1,n
forn = 0, 1
basedon the materialof the previoussetion.ThegeneralproedureonsistsinsolvinganalytiallyaCauhyproblemoftheresaledin-layereddyurrent
equationin itsasymptoti expansionform(3)withboundaryonditionson
Γ t
2 (4). The resultingsolutionyieldstheDirihletandNeumannboundaryvalueson
Γ c
whihshould mathwith transmissiononditions (6). FinallywiththeTaylorexpansionsofu δ +
(10) ,onegetstheeetivetransmissiononditionsonΓ t
2.Tosimplifythepresentation,espeiallytheomplexitiesintroduedbythetransmissiononditions(6)on
theurvedboundary
Γ c
,weassumethatthemagnetipermeabilityofthedepositsequalstothatofvauumµ c = µ v
. Thisassumptionmathesthepratialappliation wehaveinmindsinetherelativepermeability ofopperis1
.Weintroduethenotationforjumpandmeanvalueson
Γ t
2[v] := v + | r
t2− v
−| r
t2, [µ
−1∂ r (rv)] = µ
−1v ∂ r (rv + ) | r
t2− µ
−1t ∂ r (rv
−) | r
t2, h v i := 1
2 v + | r
t2+ v
−| r
t2h µ
−1∂ r (rv) i = 1 2
µ
−1v ∂ r (rv + ) | r
t2+ µ
−1t ∂ r (rv
−) | r
t2.
3.1 Formal derivation of
Z 1 , 0
transmission onditions We reall the asymptoti expansionu δ + = P
∞n=0 δ n u + n
and expandu(ρ, z) = ˜ P
∞n=0 δ n u n (ρ, z)
andu δ
−= P
∞n=0 δ n u
−n
. Theeddyurrentequation (3)andthetransmissiononditions(4)onΓ t
2 forthersttermu 0
yieldtheCauhyproblem
( ∂ ρ 2 u 0 = 0 ρ ∈ [0, d(z)], u 0 | ρ=0 = u
−0 | r
t2, ∂ ρ u 0 | ρ=0 = 0.
This problem hasaonstantsolution
u 0 (ρ, z) = u
−0 | r
t2for
ρ ∈ [0, d(z)]
. Consideringitsvalue atρ = d(z)
andthersttransmissiononditionof (6)for
u 0
onΓ c
,wegetu
−0 | r
t2= u + 0 | r
t2.
(11)TheCauhyproblemfor
u 1
withinitialvaluesgivenby(4)is
∂ ρ 2 u 1 = −B 1 1 u 0 = − k 2 1 u 0 | r
t2ρ ∈ [0, d(z)], u 1 | ρ=0 = u
−1 | r
t2,
∂ ρ u 1 | ρ=0 = − 1 r t
2u
−0 | r
t2+ 1 r t
2µ c
µ t ∂ r (ru
−0 ) | r
t2.
Itfollowsthat
∂ ρ u 1 = − 1 r t
2u
−0 | r
t2− µ c
µ t
∂ r (ru
−0 ) | r
t2− ρk 2 1 u
−0 | r
t2,
(12)u 1 = u
−1 | r
t2− ρ
r t
2u
−0 | r
t2− µ c
µ t
∂ r (ru
−0 ) | r
t2− ρ 2
2 k 2 1 u
−0 | r
t2.
(13)Theseond transmissiononditionof (6)for
u 1
onΓ c
implies∂ ρ u 1 | ρ=d(z) = − 1 r t
2u + 0 | r
t2− µ c
µ v ∂ r (ru + 0 ) | r
t2.
(14)Mathing(14)and(12)at
ρ = d(z)
gives1
r t
2µ c
µ t
∂ r (ru
−0 ) | r
t2− k 2 1 d(z)u
−0 | r
t2= 1 r t
2µ c
µ v
∂ r (ru + 0 ) | r
t2.
(15)Equalities(11),(15)andthefat that
k 2 1 = iωσ 1 µ c
implythat[u 0 ] = 0
and[µ
−1∂ r (ru 0 )] = − iγ 1 h u 0 i ,
(16)where
γ 1 = ωσ 1 d(z)r t
2= ωσ c f δ (z)r t
2.
3.2 Asymptoti model of order
0
If
u δ := u δ
± inΩ
± denote anapproximationoftheexatsolutionuptoO(δ)
error,thenfrom (16),possibletransmissiononditionsanset as