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Dynamical systems
Invariant measures for piecewise continuous maps
Mesures invariantes pour les applications continues par morceaux
Benito Pires
1DepartamentodeComputaçãoeMatemática,FaculdadedeFilosofia,CiênciaseLetras,UniversidadedeSãoPaulo, 14040-901, Ribeirão Preto – SP,Brazil
a r t i c l e i n f o a b s t r a c t
Articlehistory:
Received15March2016 Acceptedafterrevision3May2016 Availableonline24May2016 PresentedbyClaireVoisin
We say that f : [0,1]→ [0,1] is a piecewisecontinuous intervalmap if there exists a partition 0=x0<x1<· · ·<xd<xd+1=1 of [0,1] such that f|(xi−1,xi) is continuous and thelaterallimits w+0 =limx→0+f(x),wd−+1=limx→1−f(x),w−i =limx→x−i f(x) and w+i =limx→x+i f(x) exist for eachi.We provethat every piecewisecontinuous interval map withoutconnectionsadmitsan invariant Borelprobability measure. Wealso prove thateveryinjectivepiecewisecontinuousintervalmapwithnoconnectionsandnoperi- odicorbitsistopologicallysemiconjugatetoanintervalexchangetransformation.
©2016Académiedessciences.PublishedbyElsevierMassonSAS.Allrightsreserved.
r é s um é
Onditque f: [0,1]→ [0,1]estuneapplicationd’intervallecontinueparmorceauxs’ilexiste une partition0=x0<x1<· · ·<xd<xd+1=1 de [0,1] telleque f|(xi−1,xi) est conti- nue et telle que les limites latérales w+0 =limx→0+f(x), wd−+1=limx→1−f(x), w−i = limx→x−
i f(x)etw+i =limx→x+i f(x)existentpourchaquei.Onprouvequetouteapplica- tiond’intervallecontinueparmorceauxsansconnexionadmetunemesuredeprobabilité invariante. Onprouveégalementque touteapplicationinjectived’intervallecontinuepar morceauxsansconnexionetsansorbitepériodiqueesttopologiquementsemiconjuguéeà unéchanged’intervalles.
©2016Académiedessciences.PublishedbyElsevierMassonSAS.Allrightsreserved.
1. Introduction
Muchinformationaboutthelong-termbehaviouroftheiteratesofamapisrevealedbyitsinvariantmeasures.Regard- ing piecewisecontinuous intervalmaps,thepresence ofa non-atomicinvariantBorelprobability measurecan beusedto constructtopologicalconjugaciesorsemiconjugacieswithintervalexchangetransformations(IETs).
E-mailaddress:[email protected].
1 PartiallysupportedbySãoPauloResearchFoundation(FAPESP)grant#2015/20731-5.
http://dx.doi.org/10.1016/j.crma.2016.05.002
1631-073X/©2016Académiedessciences.PublishedbyElsevierMassonSAS.Allrightsreserved.
Transfer operatorshaveproved tobe animportanttool toobtain absolutelycontinuous invariant probabilitymeasures forpiecewisesmoothpiecewisemonotoneintervalmaps(see[1,3–5,9]).Ingeneral,thesetypesofresultsassumethateach branchofthepiecewisecontinuousmapisCr-smooth(r
≥
1),monotoneandhasderivativegreaterthan1.TheaimofthisarticleistoprovetheexistenceofinvariantBorelprobabilitymeasuresforpiecewisecontinuousinterval maps not embraced bythe transferoperator approach.In thisway,our resultincludesgap maps,piecewise contractions and generalisedinterval exchange transformations(GIETs). No monotonicityandno smoothnessassumptions,beyond the uniform continuityofeach branchofthemap, areassumed. Ourresultisthe naturalversion oftheKryloff–Bogoliouboff Theorem(see[8])forpiecewisecontinuousintervalmaps.
We arealsointerested inconstructingtopologicalsemiconjugacybetweeninjectivepiecewisecontinuous intervalmaps and interval exchange transformations, possibly with flips. In thisregard, it is worth mentioning the result by J. Milnor and W. Thurston(see[12]), whichstatesthat anycontinuous piecewise monotone interval map ofpositive entropyhtop is topologicallysemiconjugate toamap withconstantslope equalto
±
ehtop.Thisresultwasgeneralisedby L. Alsedàand M. Misiurewicz in[2]to piecewise continuous piecewise monotone interval mapsofpositive entropy. Concerningcount- ably piecewise continuous piecewise monotone interval maps,a necessaryandsufficient condition fortheexistence of a non-decreasingsemiconjugacytoamapofconstantslopewasprovidedbyM. MisiurewiczandS. Rothin[13].Theauthor andA. Nogueiraprovedin[14]thateveryinjectivepiecewisecontractionistopologicallyconjugatetoamapwithconstant slopeequalto±
12.The proof ofthe Kryloff–Bogoliouboff Theorem failsfor discontinuous maps.In thisarticle, we presenta variation of thisproofthatovercomessuchlimitation.Thehypothesisofnoconnectionscannotberemovedsincethereareexamplesof piecewisecontinuousmapsthathaveconnectionsandadmitnoBorelinvariantmeasure.Theproofpresentedheredoesnot holdforcountablypiecewisecontinuousmapssinceforsuchmapsthelaterallimitsmightnotexistatallpointsof
[
0,
1]
.2. Statementoftheresults
Throughoutthisarticle,assumethat f
: [
0,
1] → [
0,
1]
isapiecewisecontinuousintervalmap.Hence,thereexistsapar- tition0=
x0<
x1< · · · <
xd<
xd+1=
1 of[
0,
1]
suchthat f|
(xi−1,xi)iscontinuousandthelaterallimitsw+0=
limx→0+ f(
x)
, w−d+1=
limx→1− f(
x)
,w−i=
limx→x−i f
(
x)
andw+i=
limx→x+i f
(
x)
existforeach i.Let D= {
x0, . . . ,
xd+1},
W= {
w+0,
w−1,
w+1, . . . ,
w−d,
wd+,
w−d+1}.
Wesaythat f hasnoconnectionsif
w∈W
∞ k=0{
fk(
w)} ∩
D= ∅.
(1)Wesaythatx
∈ [
0,
1]
isaperiodicpointof f ifthereexistsanintegerk≥
1 suchthat fk(
x) =
x.OurfirstresultturnsouttobeaversionoftheKryloff–BogoliouboffTheorem[8]forpiecewisecontinuousintervalmaps.
Theorem2.1.Letf
: [
0,
1] → [
0,
1]
beapiecewisecontinuousmapwithnoconnections,thenf admitsaninvariantBorelprobability measureμ
.Moreover,if f hasnoperiodicpoints,thenthemeasureμ
isnon-atomic.The hypothesis ofnoconnections inthestatement ofTheorem 2.1,althoughmore readilycheckable,maysounda bit restrictivebecause,forinstance,itprohibitsthataleft-continuousmap f takesonediscontinuityintoanother.Indeed,what needs tobeavoidedfortheexistenceoftheinvariantmeasureisthepresenceofclosedconnections,amoretechnicalnotion giveninSection3.
Intheworldofgeneralisedintervalexchangetransformations,thehypothesisofnoconnectionscorrespondstothenotion ofhavingan
∞
-completepath.Asremarkedin[11,p. 1586],everyGIETwithsuchpropertyistopologicallysemiconjugate toanIET.Thenextresultextendsthisclaimtopiecewisecontinuousmaps.Itcanalsobeconsideredageneralisationofthe item (a)oftheStructureTheorembyGutierrez[6,p. 18].Corollary2.2.Let f
: [
0,
1] → [
0,
1]
beaninjectivepiecewisecontinuousmapwithnoconnectionsandnoperiodicpoints,thenf is topologicallysemiconjugatetoanintervalexchangetransformation,possiblywithflips.Now we presenta class of piecewise continuous interval mapsfor whichhaving no connections is a generic (in the measure-theoreticalsense)property.Werecallthatanirrationalitycriterion fortheabsenceofconnectionsinIETswithout flipswasprovidedbyM. Keanein[7].
Theorem2.3.Let
φ
1, . . . , φ
d+1: [
0,
1] → (
0,
1)
becontinuousmapsandlet⊂
Rdbetheopenset= { (
x1, . . . ,
xd) ∈
Rd|
0<
x1
< · · · <
xd<
1}
,thenforLebesguealmostevery(
x1, . . . ,
xd) ∈
,thepiecewisecontinuousmap f: [
0,
1] → (
0,
1)
definedby f(
x) = φ
i(
x)
ifx∈
Ii,whereI1= [
0,
x1),
I2= [
x1,
x2), . . . ,
Id= [
xd−1,
xd)
,Id+1= [
xd,
1]
,hasnoconnectionsandhenceadmitsan invariantBorelprobabilitymeasure.3. ProofofTheorem2.1
Henceforth,assumethatthemap f hasnoconnectionsandnoperiodicorbits.
Lemma3.1.Givenx
∈ [
0,
1]
andanintegerr≥
1,thereexistsanopensubinterval Jxof[
0,
1]
containingx suchthat{
f(
y), . . . ,
fr(
y) } ∩
Jx= ∅
for every y∈
Jx.
(2)Proof. Firstletusprovetheresultforx
=
xi,where1≤
i≤
d.Letγ =
r k=1{
fk−1(
w−i),
fk(
xi),
fk−1(
w+i)}.
Bythe uniformcontinuity of f
|
(xj−1,xj), 1≤
j≤
d+
1,together with thehypothesis of noconnections, we have that for every>
0,thereexist0< δ <
andaninterval Jxi= (
xi− δ,
xi+ δ) ⊂ [
0,
1]
suchthatd
fk
(
y), γ <
for every y∈
Jxi and 1≤
k≤
r,
(3)whered
fk
(
y), γ
=
minz∈γ|
fk(
y) −
z|
.Let
=
12d(
xi, γ )
,then>
0,otherwise f wouldhaveaconnection ora periodicorbit. Thistogetherwith(3)implies that|
fk(
y) −
xi| > > δ
forall y∈
Jxi and1≤
k≤
r.Hence,(2)holdsforeveryx=
xi∈
D.The casesin which x
=
x0=
0 or x=
xd+1=
1 followslikewise,by considering intervals ofthe form Jx0= [
0, δ)
and Jxd+1= (
1− δ,
1]
,respectively.Itremainstoconsiderthecaseinwhichx
∈ { /
x0, . . . ,
xd+1}
.Duetothehypothesisofnoconnections,thereareonlytwo possibilities:either{
fk(
x) :
k≥
0} ∩ {
x0, . . . ,
xd+1} = ∅
orthereexistk≥
1 (taketheleastvalue)and0≤
i≤
d+
1 suchthat fk(
x) =
xi.As forthefirst possibility,takeγ = {
f(
x), . . . ,
fr(
x) }
,then f iscontinuous on{
x} ∪ γ
.Moreover, since f has noperiodicpoints,wehavethat x∈ / γ
.Therefore,forevery>
0,thereexist0< δ <
andaninterval Jx= (
x− δ,
x+ δ)
suchthat (3)holdsfor Jx intheplaceof Jxi.Toconcludetheproof, proceedasbefore.Concerningthesecondpossibility, let Jxi= (
xi− δ,
xi+ δ)
beasinthebeginningoftheproof,then,asalreadyproved,{
f(
y), . . . ,
fr(
y)} ∩
Jxi= ∅
for every y∈
Jxi.
(4)Moreover, since k is the least value, f is locally continuous around
{
x,
f(
x), . . . ,
fk−1(
x)}
, thus there exists an interval Jx= (
x− η ,
x+ η )
suchthat Jx,
f(
Jx), . . . ,
fk(
Jx)
arepairwisedisjointintervalsand fk(
Jx) ⊂
Jxi.Now(4)impliesthat(2) holdsforevery y∈
Jx,whichconcludestheproof. 2Letq
∈ [
0,
1]
begiven.Since f hasnoperiodicorbits,thereexists≥
0 suchthatfk
(
q) :
k≥
∩
D= ∅
.Hereafter,set p=
f(
q)
,then{
p,
f(
p),
f2(
p), . . .} ∩
D= ∅.
(5)Denoteby
( μ
n)
n∞=1thesequenceofBorelprobabilitymeasureson[
0,
1]
definedbyμ
n=
1 nn−1 k=0
δ
fk(p),
where
δ
fk(p)istheDiracprobabilitymeasureon[
0,
1]
concentratedat fk(
p)
.Bythe Banach–AlaogluTheorem, thespaceof Borelprobability measureson a compactmetric spaceiscompact with respect tothe weak∗ topology. Hence,there exist aBorelprobability measure on
[
0,
1]
,denoted henceforthbyμ
,anda subsequenceof{ μ
n}
,denotedhenceforthby{ μ
nj}
∞j=1,thatconvergestoμ
intheweak∗ topology.Thenextresultisgoingtobeusedtwice,inLemma 3.3aswellasinLemma 3.5.
Lemma3.2.Letx
∈ [
0,
1]
.Given>
0,thereexistanopensubinterval Jxof[
0,
1]
containingx,andanintegerj0≥
1suchthatμ
nj(
Jx) <
for every j≥
j0.
(6)Proof. Letr
≥
1 beanintegersogreatthat 2r
<
.Since{
nj}
∞j=1 isasubsequenceof{
1,
2, . . .}
,thereexists j0≥
1 suchthat nj>
rforevery j≥
j0.Let JxbeasinthestatementofLemma 3.1.Let j≥
j0 and=
#{
0≤
k≤
nj−
1|
fk(
p) ∈
Jx}
,where# denotescardinality.By(2),wehavethat
( −
1)
r≤
nj,thusμ
nj(
Jx) =
1 njnj−1 k=0
δ
fk(p)(
Jx) =
#{
0≤
k≤
nj−
1|
fk(
p) ∈
Jx}
nj
≤
2r
<
for every j≥
j0. 2
Lemma3.3.Themeasure
μ
isnon-atomic.Proof. Let x
∈ (
0,
1)
. Given>
0,let Jx be an opensubintervalof[
0,
1]
containing x asinthestatement ofLemma 3.2.Since the set S
= {
z∈ [
0,
1] : μ ({
z}) >
0}
is atmost countable, thereexists a subinterval Jx⊂
Jx containing xsuch thatμ
∂
Jx=
0,where∂
Jxdenotestheendpointsoftheinterval Jx.By[15,Theorem6.1,p.40]andby(6),μ ( {
x} ) ≤ μ (
Jx) =
limj→∞
μ
nj(
Jx) ≤
lim supj→∞
μ
nj(
Jx) ≤ .
Thefactthat isarbitraryyields
μ ( {
x} ) =
0.Now let A1
⊂
A2⊂ · · ·
be asequence ofsubsetsof[
0,
1]
suchthatk≥1Ak
= (
0,
1)
and∂
Ak∩
S= ∅
foreveryk≥
1.By(5),wehavethat
μ
nj(
Ak) =
1 forevery j,
k≥
1.By[15,Theorem6.1,p.40]oncemore,wehavethatμ (
Ak) =
limj→∞
μ
nj(
Ak) =
1 for every k≥
1.
Inthisway,
μ ((
0,
1)) =
limk→∞
μ (
Ak) =
1,
thusμ ({
0}) = μ ({
1}) =
0. 2
The convergenceof
{ μ
nj}
∞j=1 toμ
intheweak∗ topology impliesthat limj→∞φ
dμ
nj=
φ
dμ
foreverycontinuous functionφ : [
0,
1] →
R.Thenextlemmaextendsthisclaimforthepiecewisecontinuousmapφ = ϕ ◦
f.Remark3.4.AspointedoutbyC.Liveraniin[10,p. 4],thepointwheretheproofoftheKryloff–BogoliouboffTheoremfails isLemma 3.5,whichisautomaticforcontinuousfunctions.
Lemma3.5.Foreverycontinuousfunction
ϕ : [
0,
1] →
R,jlim→∞
ϕ ◦
fdμ
nj=
ϕ ◦
fdμ .
Proof. Let
>
0 be arbitrarilysmall.ByLemma 3.3,we havethatμ ({
xi}) =
0 forevery 1≤
i≤
d.Hence,there existsan open interval Jxi containing xi such thatμ (
Jxi) <
forevery 1≤
i≤
d.By Lemma 3.2,there existan open interval Jxicontaining xi,andaninteger j0
≥
1 suchthatμ
nj Jxi
<
for every j≥
j0 and 1≤
i≤
d.
Set Jxi
=
Jxi∩
Jxi.Thefunctionϕ ◦
f isboundedbysome constantM andcontinuousoneachinterval(
xi−1,
xi)
forevery 1≤
i≤
d+
1. In this way, there exists a continuous function h: [
0,
1] → [−
M,
M]
such that h(
x) = ϕ ◦
f(
x)
forevery x∈ [
0,
1] \
di=1 Jxi.Puttingitalltogetheryields
ϕ ◦
fdμ
nj−
hd
μ
nj≤
| ϕ ◦
f−
h|
dμ
nj≤
2Mdfor every j
≥
j0,
(7)and
ϕ ◦
fdμ −
hd
μ ≤
2Md.
(8)Finally,sincehiscontinuouson
[
0,
1]
andμ
nj convergestoμ
intheweak*topology,thereexists j1≥
j0suchthathd
μ
nj−
hd
μ ≤
for every j≥
j1.
(9)Itfollowsfromtheequations(7),(8)and(9)that
ϕ ◦
fdμ
nj−
ϕ ◦
fdμ ≤ (
4Md+
1)
for every j≥
j1,
whichconcludestheproof. 2
Lemma3.6([16,Theorem6.2,p.147]).Letm1andm2betwoBorelprobabilitymeasureson
[
0,
1]
.Ifϕ
dm1=
ϕ
dm2forevery continuousfunctionϕ : [
0,
1] →
R,thenm1=
m2.Givena Borelprobabilitymeasure m on
[
0,
1]
andaninteger k≥
1,letm◦
f−k denotethe Borelmeasuredefinedby(
m◦
f−k)(
B) =
mf−k
(
B)
foranyBorelsetB.Inparticular,form
= δ
p wehavethatδ
p◦
f−k= δ
fk(p).Lemma3.7([16,Lemma6.6,p.150]).Let
ψ : [
0,
1] →
RbeaBorel-measurablefunction,k≥
1aninteger,andm aBorelprobability measureon[
0,
1]
,thenψ ◦
fkdm=
ψ
d(
m◦
f−k).
Lemma3.8.Themeasure
μ
isinvariantbyf .Proof. ByLemma 3.6andLemma 3.7(taking
ψ = ϕ
,k=
1 andm= μ
),itsufficestoshowthatϕ ◦
fdμ =
ϕ
dμ
(10)foreverycontinuousfunction
ϕ : [
0,
1] →
R.ByLemma 3.5,foreverycontinuous functionϕ : [
0,
1] →
R,ϕ ◦
fdμ −
ϕ
dμ =
limj→∞
ϕ ◦
fdμ
nj−
ϕ
dμ
nj.
(11)ByLemma 3.7oncemore(nowtaking
ψ = ϕ ◦
f andm= δ
p),wereachϕ ◦
fdμ
nj=
1 njnj−1 k=0
ϕ ◦
fd(δ
p◦
f−k) =
1 njnj−1 k=0
ϕ ◦
fk+1dδ
p.
(12)Likewise,
ϕ
dμ
nj=
1 njnj−1 k=0
ϕ
d(δ
p◦
f−k) =
1 njnj−1 k=0
ϕ ◦
fkdδ
p.
(13)Itfollowsfrom(11),(12)and(13)that
ϕ ◦
fdμ −
ϕ
dμ =
limj→∞
n1j nj−1
k=0
ϕ ◦
fk+1− ϕ ◦
fk dδ
p=
limj→∞
n1j
ϕ ◦
fnj− ϕ
dδ
p≤
limj→∞
2
f nj=
0.
Hence,(10)holds,whichconcludestheproof. 2
Remark3.9.TheproofofTheorem 2.1followsfromLemmas 3.3 and3.8.
4. Proofoftheotherresults
Corollary2.2.Letf
: [
0,
1] → [
0,
1]
beaninjectivepiecewisecontinuousmapwithnoconnectionsandnoperiodicorbits,then f is topologicallysemiconjugatetoanintervalexchangetransformation,possiblywithflips.Proof. ByTheorem 2.1, f admitsanon-atomicBorelprobabilitymeasure
μ
invariantby f.Leth: [
0,
1] → [
0,
1]
bedefined byh(
x) = μ ( [
0,
x] )
,thenhisacontinuousnon-decreasingsurjectivemap.Let1≤
i≤
d+
1 andx,
y∈ (
xi−1,
xi)
besuchthat h(
x) =
h(
y)
.Weclaimthath(
f(
x)) =
h(
f(
y))
.Assumethat x≤
y and f(
x) ≤
f(
y)
,then,theinjectivity of f togetherwith thecontinuityof f|
(xi−1,xi)yields[
x,
y] =
f−1([
f(
x),
f(
y)])
.Hence,sinceμ
isnon-atomic,|
h(
f(
y)) −
h(
f(
x)) | = μ ([
f(
x),
f(
y) ]) = μ
f−1([
f(
x),
f(
y) ])
= μ ([
x,
y]) = |
h(
y) −
h(
x) | .
(14) Asfortheothercases,toproceed likewisetoshowthat(14)stillholds.Hence,theclaimistrue.LetT
: [
0,
1] → [
0,
1]
bedefinedby T(
h(
x)) =
h(
f(
x))
.Bytheclaim, T iswell defined. Lett0,
t1, . . . ,
td+1 bedefinedby t0=
0,td+1=
1 andti=
h(
xi)
forevery1≤
i≤
d.By(14),wehavethatforeveryt,
s∈ (
ti−1,
ti)
,thereexistx,
y∈ (
xi−1,
xi)
suchthatt=
h(
x)
,s=
h(
y)
and|
T(
t) −
T(
s) | = |
h(
f(
x)) −
h(
f(
y)) | = |
h(
x) −
h(
y) | = |
t−
s|
for every t,
s∈ (
ti−1,
ti).
Thisprovesthat T
|
(ti−1,ti)isanisometry;therefore,T isanintervalexchangetransformation,possiblywithflips.Bydefini- tion, T◦
h=
h◦
f,thus f istopologicallysemiconjugatetoT. 2Theorem2.3.Let
φ
1, . . . , φ
d+1: [
0,
1] → (
0,
1)
becontinuousmapsandlet⊂
Rdbetheopenset= { (
x1, . . . ,
xd) ∈
Rd|
0<
x1
< · · · <
xd<
1}
,thenforLebesguealmostevery(
x1, . . . ,
xd) ∈
,thepiecewisecontinuousmap f: [
0,
1] → (
0,
1)
definedby f(
x) = φ
i(
x)
ifx∈
Ii,whereI1= [
0,
x1),
I2= [
x1,
x2), . . . ,
Id= [
xd−1,
xd)
,Id+1= [
xd,
1]
,hasnoconnectionsandhenceadmitsan invariantBorelprobabilitymeasure.Proof. Denoteby Idtheidentitymapon
[
0,
1]
.SetC0= {
Id}
.Let Ck= {φ
i◦
h|
1≤
i≤
d+
1,
h∈
Ck−1},
k≥
1.
Foreach 0
≤
i≤
d+
1,1≤
j≤
d,wi∈ {
w−i,
w+i}
andh∈
k≥0Ck,theset
{ (
x1, . . . ,
xd) ∈ |
xj=
h(
wi) }
isthegraphofa continuous function definedon[
0,
1]
,thusit isaLebesguenullset.Thistogether withthefactthat x0=
0 andxd+1=
1 donotbelongtotherangeofanyh∈
k≥1Ckimplies thatthesetofparameters
(
x1, . . . ,
xd) ∈
forwhichthemap f has connections isaLebesguenullset,denotedby N.Let(
x1, . . . ,
xd) ∈ \
N,theneither f hasaperiodicpointor f hasno periodicpointsandnoconnections.Inthefirstcase, f hasan invariantBorelprobabilitymeasuresupportedonitsperiodic orbits, whileinthesecondcase,byTheorem 2.1, f admitsaninvariantnon-atomicBorelprobabilitymeasure. 23. Finalremarks
The claimofTheorem 2.1 keepstrueifin itsstatement theterm“noconnections” isreplaced bythe term“no closed connections” definedbelow. Let f
: [
0,
1] → [
0,
1]
be asin(1) andlet¯
f:
P( [
0,
1] ) →
P( [
0,
1] )
bethe map definedon eachset A⊂ [
0,
1]
by¯
f(
A) =
x∈A
lim→0+f
(
x− ),
lim→0+f
(
x+ )
,
wherelim→0+ f
( − ) :=
f(
0)
andlim→0+ f(
1+ ) :=
f(
1)
.Wesaythat themap f hasaclosedconnectionifthereexist 0≤
i≤
d+
1 andk≥
1 suchthat xi∈
k≥1
¯
fk({
xi})
.Theexistenceofconnectionsneitherimpliesnorisimpliedbytheexistenceofperiodicpoints.Infact,let f1
,
f2: [
0,
1] → [
0,
1]
bethepiecewisecontinuousmapsdefinedbyf1
(
x) =
⎧ ⎪
⎪ ⎨
⎪ ⎪
⎩
x 2+
18 if 0
≤
x<
1 2 x2
+
3 8 if 12
≤
x≤
1,
f2(
x) =
⎧ ⎪
⎪ ⎨
⎪ ⎪
⎩
x 2+
14 if 0
≤
x<
1 2 x2 if 1
2
≤
x≤
1.
The map f1 hastwo periodicpoints andnoconnections. Themap f2 hasaclosedconnection butnoperiodicpoints.
Moreover,itdoesnotadmitanyinvariantBorelprobabilitymeasure.
Acknowledgements
IamverygratefultoKleyberCunhaandCarlangeloLiveraniforthepromptreplytomyquestions.Iamequallythankful fortheprecisecommentsprovidedbytheanonymousreferee.
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