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1 The direct problem

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Inverse Scattering and Optic Fiber design

Nabil Belouardy

Pierre Rouchon

PICOF’02, Carthage , April 2002

Abstract

Suitable radial profiles of refractive index are designed in order to reduce signal dispersion and increase fiber capacity. It is shown that for any radial index profile independent of the frequency, the phase velocity cannot be constant, even locally around any frequency. On the contrary, it is proved, that the phase velocity can be maintained constant when the refractive index is a function of space and frequency. Some simple and explicit computations show how to design such an index profile (as a function of space and frequency) in order to ensure a constant phase velocity.

1 The direct problem

The modal analysis (propagation modes, see [1]) of an optic fiber with cylindric symmetry (cylindric coordinates (r, θ, z)) leads to the following problem: for each frequency ω, finding a propagation constant β > 0 and non zero electric and magnetic fields of the form

(

E = exp(i(ωt−βz))E0(r, θ) H= exp(i(ωt−βz))H0(r, θ) satisfying the Maxwell equations









∇ × E=∂B∂t

∇ × H= ∂D∂t

∇ · D= 0

∇ · B= 0

whereDandBobey (

D=²0²rE B=µ0H.

Ecole Polyetchnique, Promotion X98, 91128, Palaiseau cedex, France.

Ecole des Mines de Paris, Centre Automatique et Syst`emes, 60 Bd Saint-Michel, 75272 Paris cedex 06 FRANCE. rouchon@cas.ensmp.fr.

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The relative permittivity ²r is equal to square of the refractive index n. It is real (no absorption, conservative case) and depends onr and ω (radial and material dispersion). EandBmust tend to zero whenrtends to +∞(boundary conditions). Since ∇ × E = −iωH, we can eliminate H and concentrates on findingβ such that (cis the light velocity in vaccum)

∆E+∇[(2/n)∇n· E] =−(ω2n2)/c2E, ∇ ·(n2E) = 0.

admits non zero solution of form E = E0(r, θ).ei(ωt−βz) vanishing at infinity.

Throughout the paper, we say that a spatial field tends to 0 at infinity when the module of any derivatives of order less or equal to 2 decreases enough rapidly.

E0 admits 3 components (Er, Eθ, Ez) in the cylindric frame (er, eθ, ez). Let us denote byA=Erer+Eθeθ,C=Ez/(iβ) andν=cβ/ω. Then we have the following system

ω2

c22−n2)A= ∆A+∇(∇log(n2)·A) ω2

c22−n2)C= ∆C+log(n2)·A ω2ν2

c2 C=∇ ·A+log(n2)·A

where the two components of correspond to derivation with respect to x= rcosθ and y = rsinθ. Simple computations show that ifA is solution of the first equation, andCis given by the last equation, thenCautomatically satisfies the second equation. Thus we can just consider the first equation:

ω2

c22−n2)A= ∆A+∇(∇log(n2)·A) (1) Classically, the termlog(n2)·A is neglected when ∂n∂r is much smaller than the inverse characteristic wave lengthc/ω. So we will consider the following ap- proximate direct problem: for a given profile (r, ω)7→n(r, ω), for any frequency ωsuch that |ω|/c¿1/|∂n∂r|, findν such that

ω2

c22−n2)A= ∆A (2)

admits a non zeros solutionA = (Ax, Ay) that tends to O at ∞. For a given ω, we can have several ν. This corresponds to different propagation modes associated to the same pulsationω.

Let us prove (at least formally) that for a given branch, says ν =φ(ω), we have always φ0(ω)> 0 when n is independent ofω. This means that for any profilen(r) independent of ω, the phase velocity cannot remain constant. This fact comes from the following analysis that can be made rigorous if necessary.

The first variation of (2), yields ω2

c22−n2)δA+2ω

c22−n2)Aδω+ +2ω2ν

c2 Aδν= ∆δA

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whereδAandAare fields tending to 0 at infinity. We then take the dot-product withA, integrate over the plane (x, y), use the fact that ωc222−n2)A = ∆A and integrate by part, to obtain

µZ Z 2ω

c22−n2)A2

δω+

µZ Z 2ω2ν c2 A2

δν= 0.

Similarly,R R ω2

c22−n2)A2=R R

(∇Ax)2+ (∇Ay)2. Thus we have

= δν δω = c2

ω3ν

R R(∇Ax)2+ (∇Ay)2 R RA2 .

We do not know if such obstruction to constant phase velocity (ν = cte independent ofω), is still valid if we do not neglect the term∇log(n2)·A in the original equation (1).

2 The inverse problem

Take (2) and set ω 7→ ν(ω). Find r 7→ n(r, ω) such that for anyω, exists a non zero solution of (2) that tends to 0 at infinity. Notice thatn depends on ω. We will see that this problem always admits a solution. In fact they are many solutions. We will propose here below a simple and explicit one by taking A = W(r)er independent of ω. Then (2) reduces to the following classical equation (0 stands ford/dr):

W00+W0/r−W/r2+ω2

c2(n2−ν2)W = 0.

This second order differential equation is regular singular atr= 0 (see, e.g.,[2, page 197]) andα= 1 is a root of the indicial equation. Thus we set W(r) = rexp(h(r)) whereh(r) will be chosen later. Thenhsatisfies

rh00+r(h0)2+ 3h0+ω2

c2(n2−ν2) = 0.

Set, e.g.,h(r) =−r/σwhereσis a positive length. We have the explicit formula n2=ν2 c2

ω2(rh00+r(h0)2+ 3h0) =ν2+ c2

σω2(3−r/σ)

that can be used to design physical profilen. In particular we recover the fact that forr= 0, n > ν and for rlargen < ν. Moreover we know explicitly the propagation mode:

E0= exph(rer−i c

ων(rh0+ 2)ez)

For a typical wavelength of λ = ωc = 1µm, figure 1 illustrates the obtained profile for σ = 10λwith a constant phase velocity associated to ν = 1.5. We have checked that the approximation|dn/dr| ¿1/λis valid.

Notice that similar computations can be made for the complete system (1) where ∂n∂r is not neglected.

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0 10

20 30

40 0.550

1

1.5 1.3

1.35 1.4 1.45 1.5 1.55 1.6 1.65 1.7 1.75

wavelength (µm) radius (µm)

refractive index n

Figure 1: the refractive index n(r, ω) that ensures a constant phase velocity ν = 1.5: with such profile, the fiber is dispersion free and the corresponding propagation mode is almost independent ofω.

References

[1] Agrawal G.P. Fiber-Optic Communication Systems. John Wiley and Sons, 1997.

[2] E.T. Whittaker and G.N. Watson.A course of modern analysis (4th edition).

Cambridge University Press, Cambridge, 1927.

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