Astérisque
B AS E DIXHOVEN
Rational torsion points on elliptic curves over number fields
Astérisque, tome 227 (1995), Séminaire Bourbaki, exp. no782, p. 209-227
<http://www.numdam.org/item?id=SB_1993-1994__36__209_0>
© Société mathématique de France, 1995, tous droits réservés.
L’accès aux archives de la collection « Astérisque » (http://smf4.emath.fr/
Publications/Asterisque/) implique l’accord avec les conditions générales d’uti- lisation (http://www.numdam.org/conditions). Toute utilisation commerciale ou impression systématique est constitutive d’une infraction pénale. Toute copie ou impression de ce fichier doit contenir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
RATIONAL TORSION POINTS ON ELLIPTIC CURVES OVER NUMBER FIELDS
[after Kamienny
andMazur]
by
Bas EDIXHOVEN209
Séminaire BOURBAKI 46eme
année, 1993-94,
n° 782Mars 1994
1. INTRODUCTION
Let E be an
elliptic
curve over a number field K. In otherwords, K
is a finitefield extension of
Q
and E is anon-singular algebraic
curve in theprojective plane PK
over Kgiven by
anequation
of the formy2z
= X3 + axz2 +bz3,
with a, b in K such that 4a3 +27b2 i=
0. For each field extension L ofK,
we denoteby E(L)
the set of L-rational
points
ofE;
thepoint (0,1,0)
inE(K)
will be denotedby
OE. It is well known that the setsE(L)
have aunique
stucture of abelian group with 0E asorigin,
such thatPl + P2 + P3 = OE
wheneverPl, P2
andP3
are thethree intersection
points (counted
withmultiplicity)
of E with astraight
line. Forexample, E(C)
isisomorphic
to a group of the formC/A
with A a lattice in C.This
already
shows that the torsionsubgroup E(C)tors
ofE(C)
isisomorphic
to,
Q/Z
xQ/Z.
The theorem of Mordell-Weil states that
E(K)
isfinitely generated,
henceisomorphic
toZ/nlZ
xZ/n2Z
x Z~ withnlln2,
ni >0,
n2 > 0 and r > 0. Thepair n2)
is theisomorphism
type ofE(K)tors;
theinteger
r is called the rank ofE(K).
1.1.
Conjecture.
For everyinteger d >
1 there exists aninteger Bd
such thatfor every number field K of
degree
d(over (~~
and everyelliptic
curve E over Kone has:
Bd.
This
conjecture
is known as thestrong
uniform boundednessconjecture,
the word"strong" meaning
that the bound is uniform in all number fields ofdegree
d.S. M. F.
Astérisque 227** ( 1995)
Let us introduce some notation. For d > 1 we define
1>( d)
to be the set ofisomorphism types
of the groupsE(K)tors
with E anelliptic
curve over a number field K with[K : Q]
= d. We defineS(d)
to be the set ofprimes
p for which there exists anelliptic
curve E over a number field K with[K : Q]
= d and[
divisible
by
p. With thisterminology, Conjecture
1.1 isclearly equivalent
to thestatement that for all
d, ~(d)
is a finite set. The results obtainedby Kamienny
and Mazur can now be stated as follows.
1.2. Theorem. 1
1. For d 8 the set is finite
(Kamienny
see also(9]).
2. The sets
S(d)
havedensity
zero for all d(~9~~.
3. is finite if and
only if S(d) is
finite(~9~).
Furthermore,
the sets9(1), S(2), $(1)
and$(2)
are known:The set
~(1)
was determinedby
Mazur[17]
in1976,
see also[18], using
results ofKubert
[13].
This result was at that time known as aconjecture
ofOgg ([22]),
butin fact it had
already
beenconjectured by
B. Levi([15])
in 1908(see
aforthcoming
article
by Schappacher
andSchoof).
The determination of~(2)
uses work ofKamienny,
Kenku and Momose(see [11]).
Part 3 of Theorem 1.2 is an easy consequence of a result ofFrey (1992),
which in turn is an easy consequence ofa theorem of
Faltings (see §6).
A "local" version of the uniform boundednessconjecture
wasproved by
Manin in 1969: he showed that for any number field K and anyprime
p there exists aninteger
e > 0 such that noelliptic
curve over Khas a rational
point
of orderpe (see [16]
and[23]).
1See §7 for more recent results. In particular, Conjecture 1.1 is now a theorem of Merel.
2. RELATION WITH OTHER CONJECTURES
It is
easily
seen that theABC-conjecture
for a number field Kimplies
a uniformbound for
IE(K)torsl (see [4]).
The same is true for theheight conjecture
forelliptic
curves over K(see [4]).
Instead ofconsidering elliptic
curves over number fields ofdegree d,
onemight
consider abelian varieties overQ
of dimension d.Restriction of scalars a la Weil shows that
Conjecture
1.1 is a consequence of:2.1.
Conjecture.
For every d > 0 there exists aninteger Bd
with the property thatIA(Q)torsl Bd
for all d-dimensional abelian varieties overQ.
It seems almost
nothing
is known about thisconjecture,
see[24]
and references therein.3. MAZUR’S METHOD FOR THE NUMBER FIELD
Q
Let E be an
elliptic
curve over a number field K and P EE(K)
apoint
ofprime
order N. Let
C~~
be thering
ofintegers
of K and letFq (q
someprime power)
bea residue field of
OK.
Let E be the fibre overFq
of the Neron model ofE,
andlet P in
E(Fq)
be the reduction of P.Suppose
that N does not divide q. Thenelementary theory
of group schemes shows thatP
has order N. NowE
is of oneof the
following
threetypes:
good
reduction: E is anelliptic
curve overFq,
hence] (ql/2 + 1)2,
soN
(ql/2
+1)2;
additive reduction: there is an exact sequence
-; E -~ ~ --~ 0
with( 4;
sinceFq,
one has N3;
multiplicative
reduction: there is an exact sequence0 -~ T -~ E -~ ~ -~ 0
with T = or T =
(the unique
non-trivialtwist)
and$(Fg) = Z/nZ
for some n, so in this case one has or +1)
orWe conclude that in order to prove that
S(1)
C{2, 3, 5, 7,13~,
it suffices to prove that anelliptic
curve overQ
with apoint
ofprime
orderN ft {2, 3, 5, 7,13}
doesnot have
multiplicative
reduction at 3.So let us suppose that we have P E
E(Q)
ofprime
order N with N notin
{2, 3, 5, 7,13}.
Ourgoal
is now to show that E does not havemultiplicative
reduction at 3
(actually,
with a bit more work one can show that E haspotentially good
reduction at allp > 3).
The idea of theproof
is tointerpret (E, P)
as aQ-rational point
of some moduli space, and tostudy
the reduction of thatpoint
modulo 3.
Let
Xo(N)
be the coarse moduli space ofgeneralized elliptic
curvesequipped
with a
subgroup
scheme of rank N which meets all irreducible components in allgeometric
fibres([2], [10]).
It is known thatXo (N)
is aprojective
curve overSpec(Z),
smooth over Its fibreXo(N)FN
overFN
has two irreducible components which are bothsmooth,
of genus zero and which intersect transver-sally
in the so-calledsupersingular points.
The genus ofXo(N)
isroughly N/12
and the condition
~2, 3, 5, 7,13}
meansprecisely
thatXo(N)
haspositive
genus.
By construction,
apair (E/S, G)
with E anelliptic
curve over a scheme Sand G a
subgroup
scheme of rank N of Egives
an S-valuedpoint
ofXo(N).
Pointsof
Xo(N)
with values in analgebraically
closed field kcorrespond
toisomorphism
classes of
objects (E/k, G).
The Riemann surfaceXo(N)(C)
can be obtainedby adding
twopoints (called
the cusps 0 andoo)
to(the quotient
ofthe upper half
plane by
the congruencesubgroup ho(N)
of The cuspoo
corresponds
to aprojective
line with itspoints
0 and ooidentified, equipped
with its
subgroup
The cusp 0corresponds
to anN-gon
ofprojective lines, equipped
with asubgroup Z /NZ meeting
all Nprojective
lines. In fact 0 and oogive
Z-valuedpoints
ofXo (N);
thecomplement
of 0 and oo is the moduli space forelliptic
curves with asubgroup
scheme of rank N.Let
Jo(N)
be the Neron model over Zof the jacobian
ofXo (N)Q .
Its restriction to is an abelian scheme whose fibres have dimensionequal
to the genus ofXo(N).
Thepoints
ofJo(N)
with values in a field k of characteristic different from Ncorrespond
to divisor classes ofdegree
zero onXo(N)k,
moduloprincipal
divisors. The fibre over
FN
ofJo (N)
sits in an exact sequencewith the group
Z/nZ generated by
the reduction mod N of thepoint
c inJo(N)(Q)
of order n
given by
the divisor class c =(0) - (oo).
Let T be the
endomorphism ring
ofJo(N);
it isgenerated by
the Hecke opera- torsTp (p ~
Nprime)
and the Atkin-Lehner involution wN. It will be convenient to work with the Heckeoperators Tm
for all m >1;
these are defined as follows:TN
= -wN and oneformally
has the Eulerproduct:
If one
interprets S~1 )
=S~ 1 )
as the space ofcuspidal
mod-ular forms of
weight
two onr ° (N)
and usesq-expansions,
these operators aregiven by
the usual formulas. Thisimplies
that the coefficient ofqm
of aneigenform
witheigenvalue
am forTm, equals
am times the coefficient of q. Thering
T is commu-tative, reduced,
free of rankdim(Jo (N)Q)
as Z-module. TheQ-algebra Q 0
T isa
product
oftotally
real fields andSpec(T)
is connected. For eachprime
numberp ~
N one has the Eichler-Shimuraidentity
inWeil’s theorem on the
eigenvalues
of Frobeniusendomorphisms
of abelian varieties thenimplies
that for anyhomomorphism ~:
T -~ C and for anyprime p ~= N,
one has
( 2pl/2.
The action of T on c is as follows:
Tp(c) = (p+l)c
for allprimes N,
andwN(c) =
-c. Let I ~ T be the annihilator of c. It follows thatT/I
=Z/nZ
and that I is
generated by
theTp-p-1 (p 7~
Nprime),
and n(actually
one doesn’t need
n).
The ideal I ~ T is called the Eisenstein ideal because itcorresponds
to congruences betweencuspidal
forms andnon-cuspidal
forms onro(N)
ofweight
two([17],
page37).
Let TI :=
lim T I 1m
be the I-adiccompletion
of T. The ideal 11 of T is then defined to be the kernel of the map T -~TI.
In otherwords,
~yI is the intersection of the minimalprime
ideals p of T with T. Phraseddifferently:
is the union of the irreducible components of
Spec(T)
that have non-empty intersection with
Let be the abelian
subvariety
ofJo (N)Q generated by
thetJo (N)Q,
t E 77. The Eisenstein
quotient JQ
is then definedby: Jq
:=Let J be its Neron model over Z.
By construction, T/7/
actsfaithfully
on J. Thefollowing
theorem is one of the main results of[17] (see
also[19]).
3.1. Theorem
(Mazur).
The groupJ(Q)
istorsion,
and infact, J(Q)
is gen-erated
by
c, hencecyclic
of order n.Let
Xo(N)Sm
CXo(N)
be thebiggest
open part which is smooth over Z(i.e., Xo(N)Sm
is thecomplement
of the set of doublepoints
in characteristicN).
Thepoints
0 and oo inXo(N)(Z)
are in fact inXo(N)Sm(Z).
LetJo(N)
be the usual
embedding
of a curve in itsjacobian,
normalizedby
the condition that oo is sent to 0.By composition
with the canonical mapJo (N) -~ J we
geta
morphism
J.3.2. Theorem
(Mazur). (See [18J.)
Themorphism f
is a formal immersion at oo, away from characteristic 2. In otherwords,
thecotangent
spaceof
Jz[l/2]
at 0 mapssurjectively
to orequivalently,
for eachprime p ~
2 the map fromCotO(JFp) to
is non-zero.Proof. The
hypothesis
that p is notequal
to 2implies
thatCoto(JFp)
mapsinjectively to
BecauseJo (N)
is a(commutative)
groupscheme,
wehave a canonical
isomorphism 7r*Coto(Jo(N)) (7r: Jo(N) - Spec(Z)), inducing HO(Jo(N), Composing
with thepullback of
differential forms
along f gives
anisomorphism:
S(N, 2)
where
S(N, 2)
is the Z-module of cusp forms over Z ofweight
two onro(N).
Withthis
identification,
the mapCoto ( Jo (N) ) --> Cotoo(Xo(N)) corresponds
to evaluat-ing
at oo. The Tate curve overZ ( (q) )
shows thatdq
is a Z-basis ofCotoo(Xo(N));
the q here can be
interpreted
as the function z t2014~exp(27riz)
on the upper halfplane
H. Sofinally
we see that the map oncotangent
spacescorresponds
to themap:
Let p > 2 and
let 03C9 ~
0 be aneigenvector
for T in Since p >2, 03C9
has non-zero
image
inS(N, 2)Fp;
thisimage
is aneigenvector
forT,
hence it hasD
With all
this,
we can finish Mazur’sproof
that theelliptic
curve E does not havemultiplicative
reduction at 3. So suppose that E hasmultiplicative
reduction at3. Since N > 11 >
3+1,
P inE(F3)
has non-zeroimage
in~(F3).
This meansthat the
Q-rational point (E/Q, (P))
ofXo(N) specializes
to the cusp 0 modulo 3. Let x be theQ-rational point corresponding
to(E j(P), E[N~/(P));
then xspecializes
to oo modulo 3. We consider EJ(C~). By
Thm.3.1, f(z)
istorsion.
By
Thm.3.2,
is not zero(this
can be seen in thecompletion
ofXo(N) along oo).
But this is in contradiction with thefollowing lemma,
whoseproof
is anelementary
calculation with formal groups.3.3. Lemma. Let R be a discrete valuation
ring
of characteristic 0 and with residue field k of characteristic p. Let G be a smooth group scheme over R. Letx E
G(R)
be torsion.Suppose
that the valuationof p
isstrictly
less thanp-1.
Then the
specialization
xk has the same order as x.4. KAMIENNY’S GENERALIZATION OF MAZUR’S METHOD
Let d >
1,
K a number field ofdegree d,
E anelliptic
curve over K and P EE(K)
a
point
ofprime
order N. Let y EXo(N)(K)
be thepoint corresponding
to(E/(P), E[N]/(P~).
The idea is now to look at theQ-rational point
x :=~~ u(y),
with u: K -
C,
of the dthsymmetric
power ofXo(N). By definition,
Xo(N)(d)
is thequotient by
thesymmetric
groupSd acting
on the dth powerXo(N)d.
Hence is proper overZ,
smooth of relative dimension d overZ[I/N].
Togive
a k-valuedpoint
of where k is aperfect field,
is thesame as
giving
an effective divisor ofdegree
d onLet
JZ[1/N]
be the usual map from thesymmetric product
of a curve to its
jacobian,
normalizedby
the condition that d.oo is sent to 0. Weapply
Mazur’s method to x andf d.
Suppose
p > 2 is aprime
such that N >(pd/2
+1)2.
Then at each residue field ofOK
of characteristic p, E hasmultiplicative reduction,
andP
has non-zeroimage
in~;
in otherwords,
allspecializations
to characteristic p of the K-valuedpoint
y ofXo(N)
are oo. This means that xspecializes
to d.oo modulo p. Ifmoreover
f d
is a formal immersion at thepoint
d.oo modulo p, then we obtain acontradiction as before: is
torsion,
is not zero andspecializes
to0 modulo p. These arguments prove the
following proposition.
4.1.
Proposition.
Let d >1,
N ES(d)
and suppose thatf d
is a formal immer- sion at d.oo modulo aprime
p > 2. Then N(pd/2
+1)2.
DRecall that
Xo (N)
has a formal local coordinate q at oo. Hence has formal local coordinates ql, ... , qd at(oo, ... , oo).
Theelementary symmetric
functionsa1 = ql+ ~ ~ ~ +qd,..., ad = ql ~ ~ ~ qd are then formal local coordinates of at
d.oo,
sod~l, ... , dad
is a Z-basis for4.2. Lemma. Let w be in
Coto(J),
or,equivalently,
inHO( J, S~ J/Z).
Thenis a differential form on say with
q-expansion
We have:
Proof. Let g: be the canonical map. For m > 1 define
sm =
qi
+ ... +9d ,
ThenFrom Newton’s identities
This finishes the
proof.
D4.3. Theorem
(Kamienny’s criterion). Let d 2:
2 and N ES(d). Suppose
that the
images Ti, ... , Td
inT / II
ofTl, ... , Td
E T arelinearly independent.
Then N
Proof.
By
theq-expansion principle, Tano(Jo(N))
is alocally
free T-module of rank 1. SinceQ
0 T is aproduct
offields, Q
0S(N, 2)
is a freeQ
® T-module of rank 1. It follows thatQ
0S(N, 2)~~yj~ (forms
annihilatedby
is a free module of rank 1 overQ
®(T/~yI).
Let W1,... , wr be a basis ofQ0 S(N, 2) [77] consisting
of normalized
eigenforms
forT,
and write Wi =(normalized
means that a;,i = 1 for all
i).
Let R CQ
be thering generated by
the a;,m.Then,
as a
Z-module, R
is free of somerank t,
say. Thehypothesis
thatTi, ... , Td
are
linearly independent
means that the(as,l, ... , ai,d),
1 i r,generate
theQ-vector
spacecr.
Note that Lemma 4.2implies
thatformal immersion at d.oo.
Exactness
properties
of Neron models show that the torsion of thequotient Coto(Jo(N))/Coto(J)
is killedby
2(compare [18], Cor. 1.1).
Hence c~l, ... , c~r can be viewed as elements ofR~1 ~2~
®Coto ( J) .
After
renumbering,
we may suppose that A := is non-zero.Recall that for all
embeddings R ~
C and allprime numbers l ~
N one has211/2,
and that = d:l. Forarbitrary
m one haswhere is the number of
positive
divisors of m. Hence for the norm of 0one has:
Suppose
now that p > 2 is aprime
such thatf d
is not a formal immersion at oomodulo p. Then p divides the index of
fdCoto(J)
in It followsthat there is an a E R such that A = pa, hence also =
pt.
Weconclude that p
( d ~ ) 5I2 .
Let p be a
prime
between(d!)5/2
and2(d!)5/2;
thenf d
is a formal immersion at oo modulo p.Prop.
4.1implies
that N(pd/2
+1)2 2d+1(dl)5d/2,
DWe end this section with some remarks. First of
all,
thedifficulty
withKamienny’s
criterion is that one needs to know whether
Ti, ... , Td
arelinearly independent
ornot. The
question
of lineardependence
ofTi,..., Td
in T itself iseasily
settled: let g :=dim(Jo(N)Q),
thenT1,... , Tg
arelinearly independent
in T. To prove this(optimal) result,
one remarks that it isequivalent
to oo notbeing
a Weierstrasspoint
onXo (N)Q .
Reduction modulo N shows that oo is not aWeierstrass point
(one
finds a Vandermondedeterminant,
see also[14]).
Secondly,
let us consider the case d = 2. We want to know theprimes
N forwhich
T{
andT2
arelinearly independent.
SinceT{
is theidentity,
thequestion
is whether
T2
acts as a scalar on J or not, so suppose thatT2
acts as a scalar.Weil’s bound
implies
thatT2
E{-2, -1, o,1, 2}.
But on the other hand we haveT2
= 2+1 modulo n(consider
theimage
ofTZ
inT/I
=Z/nZ).
It follows that(TV - 1)/12 num((N -1)~12)
= n5,
hence that N 61. SoConjecture
1.1is now
proved
for d = 2. The boundsgiven
in Theorem 4.3 can beimproved
inthis case: the
proof
shows that for N > 61 the map/2: Xo(N)(2)
- J is a formal immersion at oo modulo7,
so that N ES(2) implies
N((72)1/2
+1)2
= 64.To go
further,
one has to doexplicit
calculations for the N 61. Forexample, by calculating
the characteristicpolynomial
ofT2 acting
on the space ofweight
two cusp forms on
ro(N)
one sees thatT2
does not acts as a scalar modulo 5 for N =43,
53 and61,
which means that these three N are not inS(2).
5. WINDING HOMOMORPHISMS AND FUGITIVE SETS
In order to prove that the sets
S(d)
are finite for d 8and,
for alld,
havedensity
zero, it
suffices,
in view of Theorem4.3,
to prove that the set ofprimes
N suchthat
Ti, ... , Td
arelinearly dependent
is finite for d 8 and hasdensity
zero forall d. The
following
lemma shows that to check whetherTi, ... , Td
arelinearly independent
or not(for
agiven N),
it suffices to check a finite set ofrelations;
this set of relations is
independent
of N.5.1. Lemma. Let d >
1,
let N be aprime
and suppose thatT{, ... , Td
arelinearly dependent.
Consider a non-trivial relationwhich is minimal in the
following
sense: there is no non-trivial relation amongTi, ... , Td
with more coefficientsequal
to zero, and al, ... , ad have greatest com-mon divisor
equal
to 1. Then((d-1~~~5~2
for all i.Proof. Let ..., be the a; which are non-zero. We rewrite the
equation
as:
Recall that is a
product
oftotally
real fields. Hence iscanonically isomorphic (as R-algebra)
toRe,
where e =dim(JQ).
Thisgives
anembedding
Re; let Vi
=(v=,1,
..., denote theimage
ofThen, by Weil’s,bound,
we have
]
Ci3/2
for all i andj.
Since ..., arelinearly independent,
there exist
jl, ... , jr
in~1, ... , e~
such that A := is not zero. Let R be thesubring
of Rgenerated by
all v;,;.Then,
as aZ-module,
R is free ofsome rank t, say. Let R denote R. Then in
7f
we have the relation:and + ... +
air R
= R since ail , ... , havegreatest
common divisorequal
to 1. It follows that vsi I1 ~ ~ ~ A vir has
image
0 in hence 0 hasimage
zeroin R
(it
is one of the "coordinates" of v=1 I1 ~ ~ ~ A Hence we have A = for some A’ in R. It follows that>
As in theproof
of Theorem 4.3one shows that
~N(~)~ ~ ((d-1)~)5t~2,
hence the result. D Remark.Applying Siegel’s
lemma(which gives
an upper bound for the smallest non-trivial solution of a system of linearequations
with coefficients inZ)
one getsmore or less the same estimate.
Recall
that, by definition,
is theimage
of T in itscompletion TI. Hence,
for ai,..., ad in
Z,
one hasa1T’1
+ ... +adTd
= 0 if andonly
ifaiTi
+ ... +adTd
is in Im for all m. The finiteness of
S(2)
was obtainedby studying
theimage
of arelation among
Ti
andT2
inT/I.
We will nowgeneralize
this method andstudy
an
arbitrary
relationusing
the filtration T D 7 DIZ ~ ~ ~ ~.
To dothis,
it will beconvenient not to work with the
Ts,
but with the ~s in T defined as follows:The
Tm
can be written as linear combinations of the r~k:with cm,k in Z. It is
important
to note that the cm,k with m N do notdepend
on N. For all m, let be the
image
of 17m in For m >1,
letv(m)
denotethe number of factors in a
prime
factorization of m: if m= rl ~ ~ ~ tr
withthe 1i prime,
thenv(m)
= r. Note thatby definition,
we have r~t E I for allprimes 1,
hence for all m > 1 we have qm E
Suppose
now that we have d > 1 and aprime
N > d such thatTl ... , Ta
arelinearly dependent.
Then Lemma 5.1gives
a non-trivial relation =0,
withC(d)
forall i,
whereC(d)
is aninteger depending only
on d. Wewant to show
that,
for d8,
N isbounded,
and that ingeneral
N lies in a set ofprimes
which hasdensity
zero.Before
treating
thegeneral
case, let us deal with d8,
or, what amounts to the same, with d = 8. Then we havebl, ... , b8
inZ, C(8)
for alli,
suchthat the element
of T is in 1m for all m > 0. Note that in this
expression
for x the second term is inI,
the third is in I2 and the fourth is in I3.Suppose
first thatb1 ~
0. Sincebi
=b1TJl
E I n Z =nZ,
one then has(N-1)~12
nC(8),
henceN
12C(8)+1.
So we may suppose thatb1
= 0. Then x EI,
so it will be useful to consider theimage
of x inI ~I2;
this is where Mazur’swinding homomorphism
comes in.
5.2. Theorem
([17], §18).
Write N-1 = en, hence e =gcd(N-1,12).
Letbe the kernel of the eth power
endomorphism
ofF Jj.
There is aunique isomorphism
of groups(the winding homomorphism)
which sends qi to
d(~-1»2
for allprimes
t~
N.Let
~: 7/7~
--~FN
be thehomomorphism
definedby ~(?/)
=w(y)12.
Then for allprimes t ~ N, ~(r~l)
=ds(1-1~.
Now suppose that
b2, b3, b5
andb7
are not all zero. Then we have:It follows that N divides the numerator of
(2~2 32~3 54~5 7667~6 _ ~
hence N is atmost
exp(127.C(8)).
So we may now suppose thatb2, b3, b5
andb7
are zero. Thenwe have +
b6~’3
+b8~’4)
= 0.Since ~’2
is anisogeny
from J to itself(this
follows from Weil’s
bound),
we must also have:If
b4
andb6
are not both zero, we findexp(18.C(8)).
Ifb4
andb6
are bothzero, then we
find ~
=0,
whichimplies
that J = 0 and hence N 13. This finishes theproof
that the setsS(d)
with d 8 are finite.Note, by
the way, thatthe reason the
proof works,
is that we obtained linear relations among theimages
of
the ~l
inI/I2.
This method breaks down for d =9,
since then one has to deal with +b61J21J3
+~9~3.
In the
general
case(i.e.,
darbitrary)
let m be minimal such that not allbi
with
v(i)
= m are zero. We define x := then x E Im+1. We choosean
isomorphism
of groupslog: FN --; Z/(N -l)Z.
The fact(see [17], Thm.18.10)
that I C T is
locally principal, implies
that we have ahomomorphism
of groups:(The
tensorproducts
are overZ.)
We have = 0. To see what this means,let us first consider where i with
the lj prime.
One computes thatwhere we view
Bi
as aninteger.
Note thatBi
does notdepend
onN,
thatBi
doesnot
depend
on the choice oflog: FN -> Z/(N -l)Z
and that not allB=
are zero.Let F be the
homogenous polynomial
ofdegree
m, with coefficients inZ,
in thevariables
X~,
I dprime,
whose monomials are the withv(i)
= mand 1 i d. Then the relation 0 =
~m(x) _
can be rewrittenas
F(log 2, log 3, ...)
= 0 inZ/(N-1)Z.
The set ofprimes
N with theproperty
that
F(log 2, log 3, ...)
= 0 inZ/(N-1)Z
is called thefugitive
set associated to F(note
that this does notdepend
on the choice of thelogarithms
on theFN).
We conclude that the set of
primes
N such thatTi, ... , Td
arelinearly dependent,
is contained in a finite union of such
fugitive
sets. H.W. Lenstra hasgiven
anelementary
argument,using
Cebotarev’stheorem,
thatfugitive
sets havedensity
zero. In an
appendix
to[9],
A. Granvilleimproves
this result as follows: for x E Rsufficiently large,
the number ofprimes
~V ~ in a fixedfugitive
set is boundedby
a constant times K.
Murty
has shown thatunder the
generalized
Riemannhypothesis,
Granville’s bound can beimproved
to0((x~ log(x)) log log(x)).
One expects that the actual size of afugitive
setis
0(log log(x)).
6. AN APPLICATION OF A THEOREM OF FALTINGS
In this section we prove that
S(d)
is finite if andonly
if is finite. Webegin by recalling
a result ofFrey [6].
6.1.
Proposition (Frey).
Let K be a numberfield,
d > 0 aninteger
and C asmooth
projective geometrically
irreducible curve over K withC(K)
non-empty.Suppose
that every non-constantmorphism
from C toPK
hasdegree >
2d. Thenis finite.
Proof. Consider the
morphism C(d)
-->Pic~
which sends an effective divisor D ofdegree
d to the line bundleOc(D)
ofdegree
d. This map induces aninjection
on K-rational
points,
since ifD1 ~ D2
are effective divisors ofdegree
d on C suchthat
Dl - D2
is aprincipal
divisor( f ),
thenf
is a finitemorphism
ofdegree
dto Let X be the
image
ofC(d)
inPic~.
It suffices to show thatX (K)
is finite.Suppose
thatX(K)
is not finite.Then, by Faltings’s
theorem[3,
Thm.4.2],
thereexists a non-zero abelian
subvariety
B ofPic0C
withB(K)
Zariski-dense inB,
and apoint Po
inX(K)
such thatPo+B
C X. For b inB(K),
letPb
:=b+Po
EX(K) ;
let
Db
denote the effective divisor on Ccorresponding
toPb (here
we use thatC~d~(K) --~ X(K)
is abijection).
Then for all b EB(K)
the divisorsDb
+D-b
and
2Do
arelinearly equivalent.
Note that theequality
Db + D-b = 2Do canhappen only
forfinitely
manyb,
so there exists a b and a non-constant rational functionf
on C such that Db + D-b -2Do
=( f ).
But such af
is amorphism
from C to
PK
ofdegree
at most 2d. D6.2.
Corollary (Frey, [6]).
Let d > 0 and e > 0 beintegers,
let N beprime
and suppose that 120d. Then there are, up to
isomorphism, only finitely
many
elliptic
curves E overQ
which have acyclic isogeny
ofdegree
Ne that canbe defined over a number field K of
degree
at most d.Proof. Let
I: Xo(Ne) -+ Pq
be a finitemorphism.
Take I E{2,3},
I~
N. SinceXo(Ne)
hasgood
reductionat I,
the line bundle has aunique
extensionto and induces a finite
morphism PF~
ofdegree
at mostdeg( f ).
An easycomputation
shows that wheree2 = 12 and e3 = 6
(consider
thesupersingular points).
Hence6.3.
Corollary ([9]).
Let d > 1. IfS(d)
is finite then is finite.Proof. Instead of
giving
aproof using
Cor.6.2,
wegive
aproof using
a variantof that
corollary
for the curvesX1(Ne).
Anadvantage
of this is that the curvesX1(Ne)Q
are fine moduli spaces for Ne > 4.Let d > 1 and suppose that
S(d)
is finite. SinceS(d)
isfinite,
it suffices togive,
for each N inS(d),
aninteger
r > 0 such that noelliptic
curve over a field ofdegree
d has a rationalpoint
of order Nr. So let N be inS(d)
and e > 0. Anelliptic
curve E over a field K ofdegree d, together
with a rationalpoint P
oforder
Ne, gives
a K-valuedpoint
of the modular curve hence aQ-valued point
of thesymmetric product
The curve isprojective
andsmooth over
Z[I/N],
and hasgeometrically
irreducible fibres. For any field knot of characteristicN, X1(Ne)k
has at least rationalpoints (coming
from the
cusps).
It follows that any finitemorphism
fromX1(Ne)Q
toPo
hasdegree
at leastSuppose
that e > 1 +logN(16d/(N-l)). Then, by ’Prop. 6.1, XI(Ne)(d)(Q)
is finite. Let Xl,... , Xm be thenon-cuspidal
closedpoints
of the scheme that have non-zeromultiplicity
in at least one ofthe
finitely
many effective divisors onX1(Ne)Q corresponding
to the elements ofLet
K=
be the residue field of at x=; thenKs
is a field ofdegree
d. Note that Ne >4,
soX1(Ne)Q
is a fine moduli space. Hence overeach
K;
we have anelliptic
curveE= together
with apoint P;
inE~(K~)
of orderNe.
By construction,
these have the property that all(E/K, P)
withE an
elliptic
curve overK,
K ofdegree
d and P EE(K)
of orderNe,
can beobtained
by
extension of scalars from one of the For eachi,
choosea residue field
ki
of thering
ofintegers O;
ofKi
such thatk;
has characteristic different from N andE=
hasgood
reduction atk;.
Now if(E/K, P)
is obtainedby
extension of scalars fromP=),
thenOK
has a residue field k which isan extension of
degree
at most d ofki
such that E hasgood
reduction at k. LetE/k
be the reduction. Then~E(k)~ + 1)2.
Now take r > e such that forall i one has Nr > +
1)2.
D7. BEYOND KAMIENNY AND MAZUR
D. Abramovich
[1]
has remarked that thehypothesis
inProp.
4.1 thatf d
is aformal immersion at d.oo modulo a
prime
p > 2 can be weakened. Infact,
all oneneeds is that 0 for all x in
Xo(N)(d)(Q)
thatspecialize
to d.oo modulo p.Using
this remark Abramovich hasproved
finiteness ofS(d)
for all d 14. For dequal
to 13 and 14 hisproof
uses computercomputations.
Very recently (February 11),
L. Merel has announced aproof
of the finite-ness of
S(d)
for all d. His method is toreplace
the Eisensteinquotient
J ofJo(N) by
abigger quotient Jw.
Thisquotient,
which he calls thewinding
quo-tient,
is defined as follows.Integration
over{it I t
ER>o}
C H defines a C-linear form on
H°(X°(N)(C), 03A9).
It is known that this formcorresponds
toan element e in
H1(Xo(N)(C), Q).
Let a C T be the annihilator of e, thenJw,Q =
A result ofKolyvagin
andLogachev [12], supple-
mented
by
work ofBump, Friedberg
and Hoffstein[7],
orby
work ofMurty
andMurty [21],
shows thatJw(Q)
is finite. The condition forJw,Q
tobe a formal immersion at d.oo is that
Tle, ... Tde
arelinearly independent
in thefree Z-module T.e C
H1(X°(N)(C), Q).
For Nsufficiently large
with respect to d(to
beprecise, N/(log N)4
should begreater
than 400d4 and greater thand8),
Merel shows this linear
independence using
thetheory
of modularsymbols.
The text that follows has been added at the time the final version of this
text was written
(August 1994). Shortly
after thisexpose,
Oesterlé hasimproved
Merel’s result: he shows that N E
S(d) implies N (3d/2 + 1)2.
Hisproof,
whichfollows Merel’s