C OMPOSITIO M ATHEMATICA
J EAN -P IERRE D EMAILLY
T HOMAS P ETERNELL
M ICHAEL S CHNEIDER
Kähler manifolds with numerically effective Ricci class
Compositio Mathematica, tome 89, n
o2 (1993), p. 217-240
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Kähler
manifolds with numerically effective Ricci class
JEAN-PIERRE DEMAILLY
Université de Grenoble I, Institut Fourier, BP 74 U.R.A. 188 du C.N.R.S., 38402 Saint-Martin
d’Hères, France
THOMAS PETERNELL and MICHAEL SCHNEIDER
© 1993 Kluwer Academic Publishers. Printed in the Netherlands.
Universitiit Bayreuth, Mathematisches Institut, D-95440 Bayreuth, Deutschland Received 5 March 1992; accepted in final form 29 October 1992
Introduction
Compact
Kâhler manifolds withsemipositive
Ricci curvature have been in-vestigated by
various authors. S.Kobayashi [Ko61]
firstproved
thesimple
connectedness of Fano
manifolds, namely
manifolds withpositive
Ricci cur-vature or
equivalently,
withample
anticanonical linebundle - KX.
Later on,generalizing
results of Y. Matsushima[Ma69],
A. Lichnerowicz[Li7l, 72]
proved
thefollowing interesting
fibration theorem: if X is acompact
Kâhler manifold withsemipositive
Ricciclass,
then X is a smooth fibration over its Albanese torus and there is a group ofanalytic automorphisms
of Xlying
over the group of torus translations
(see
also Section 2 for anotherproof
ofthese facts based on the solution of Calabi’s
conjecture
and on Bochner’stechnique). Finally,
there were extensive works in the last decades tostudy
the structure and classification of Ricci flat Kähler
manifolds,
see e.g.[Ca57], [Bo74a,b], [Be83]
and[Kr86];
ofspecial
interest forphysicists
is the subclassof so-called Calabi-Yau
manifolds,
i.e. Ricci flatcompact
Kähler manifoldswith finite fundamental group, which appear as a natural
generalization
ofK3 surfaces.
To make
things precise,
one says that X hassemipositive
Ricci classc1(X)
if
c1(X)
contains a smoothsemipositive
closed(l,l)-form,
orequivalently
if- Kx
carries a smooth hermitian metric withsemipositive
curvature.By
theAubin-Calabi-Yau
theorem,
this isequivalent
to Xhaving
a Kâhler metricwith
semipositive
Ricci curvature. On the otherhand,
recentdevelopments
of
algebraic geometry (especially
those related to Mori’s minimal modelprogram)
have shown theimportance
of the notion of numericaleffectivity,
which
generalizes
hermitiansemipositivity
but is much more flexible. It wouldthus be
important
to extend the above mentioned results to the case when-KX
isnumerically
effective. The purpose of this paper is to contribute to thefollowing
twoconjectures.
CONJECTURE 1. Let X be a compact Kahler
manifold
withnumerically effective
anticanonicalbundle -Kx.
Then thefundamental
group7T1(X)
haspolynomial growth.
CONJECTURE 2. Let X be a compact Kâhler
manifold with -KX
numeri-cally effective.
Then the Albanese map a : X ~Alb(X)
issurjective.
Before we state the
results,
let us recall the definition of anumerically
effective line bundle L on a
compact complex
manifold(see [DPS91]
for moredetails).
The abbreviation "nef " will be used for"numerically
effective".DEFINITION. Let X be a compact
complex manifold
witha fixed
hermitianmetric w. A
holomorphic
line bundle L over X is nefif for
every E > 0 there exists a smooth hermitian metrich,
on L such that the curvaturesatisfies
Of course this notion does not
depend
on the choice of 03C9. If X isprojective,
L is nef
precisely
if L - C ; 0 for all curves C C X. Our main contribution toConjecture
1 isTHEOREM 1. Let X be a compact Kâhler
manifold
with -Kx nef. Then03C01(X) is a
groupof subexponential growth.
The main tool to prove this result is the solution of the Calabi
conjecture by
Aubin
[Au76]
and Yau[Y77],
combined with volume bounds forgeodesic
balls due to
Bishop [Bi63]
andGage [Ga80] (see
Section 1 fordetails).
Infact,
the volume of ageodesic
ball of radius R in the universalcovering
ofX
essentially
counts the number of words of03C01(X)
oflength
R. Thedifficulty
is that we have to deal with a sequence of metrics with Ricci curvature closer and closer tobeing semipositive,
but neverthelessslightly negative
in somepoints,
and moreover the diameter of X need not remainuniformly bounded;
thisdifficulty
is solvedby observing
that alarge
fractionof the volume of X remains at bounded distance without
being
disconnected(Lemma 1.3).
Aby-product
of ourproof
is thatConjecture
1 holds in thesemipositive
case. This was in factalready
known since along
time in the context of riemannian manifolds(cf.
e.g.[HK78]);
our method is then no-thing
more than the usual riemanniangeometry proof
combined with theAubin-Calabi-Yau theorem. In this way we get:
THEOREM 2. Let X be a compact Kâhler
manifold with -KX
hermitiansemipositive.
Then03C01(X)
haspolynomial growth of degree 2 dim X,
inparticular hl(X, OX)
dim X.Note that there are
simple examples
ofcompact
Kâhler manifolds X with- Kx
nef but not hermitiansemipositive,
e.g. some ruled surfaces overelliptic
curves
(see examples
1.7 and 3.5 in[DPS91]). Also,
togive
a moreprecise
idea of what
Conjecture
1 means, let us recall Gromov’s well-known result[Gr81] :
afinitely generated
group haspolynomial growth
if andonly
if itcontains a
nilpotent subgroup
of finite index. Much moremight
beperhaps expected
in thepresent
situation:QUESTION. Let X be a compact Kahler
manifold with -KX
nef. Does thereexist a
finite
étalecovering X of
X such that Albanese map~ A1b()
induces an
isomorphism of fundamental groups?
If this would be the case,
7T1(X)
wouldalways
be an extension of a finitegroup
by
a free abelian group of even rank.Concerning Conjecture 2,
thefollowing
result will beproved
in Section 2:THEOREM 3. Let X be a n-dimensional compact Kahler
manifold
such that- Kx is
nef. Then(i),
The Albanese map a : X ~Alb(X)
issurjective
as soon as the Albanese dimension p = dim a(X)
is0,
1 or n, and alsofor
p = n - 1if
X isprojective.
(ii) If
X isprojective
andif
thegeneric fiber
Fof
ahas -KF big,
then a issurjective.
The case p = 1 in
(i)
is astraightforward
consequence of Theorem1,
aspointed
out to usby
F.Campana,
if one observes that thegrowth
of thefundamental group of a curve of genus 2 is of
exponential type.
The otherinteresting
case p = n - 1 is obtained as a consequence ofpoint (ii),
whichis itself a rather
simple
consequence of theKawamata-Viehweg vanishing
theorem. Theorem 3 settles
Conjecture
2 forprojective
3-folds. In that case,we can also obtain a direct
algebraic proof
of the Albanesesurjectivity
inmost cases
by
an examination of the structure of Mori contractions of X.When the contraction is not a
modification,
wegive
thedescription
of thefibration structure of X. This is done in Section 3.
To conclude let us mention that the first theorem was used in the classific- ation of
compact
Kâhler manifolds with nef tangent bundles[DPS91]
in acrucial way.
Acknowledgement
Our collaboration has been made
possible by
PROCOPE and the DFGSchwerpunktprogramm "Komplexe Mannigfaltigkeiten".
We would like to thank Prof. F.A.Bogomolov,
F.Campana
and P. Gauduchon for very useful discussions.1.
Subexponential growth
of the fundamental groupIf G is a
finitely generated
group withgenerators
gl , ... , gp , we denoteby N (k)
the number of elementsy E
G which can be written as wordsof
length
k in terms of thegenerators.
The group G is said to havesubexponential growth
if for every E > 0 there is a constantC(E)
such thatThis notion is
independent
of the choice of generators. In the free group with twogenerators,
we haveIt follows
immediately
that a group withsubexponential growth
cannot con-tain a non abelian free
subgroup.
The maingoal
of this section is to prove THEOREM 1.1. Let X be a compact Kahlermanifold
such thatKX1
is nef.Then
03C01(X)
hassubexponential growth.
Proof.
The firststep
consists in the construction of suitable Kâhler metricsby
means of the Aubin-Calabi-Yau theorem. Let w be a fixed Kähler metricon X. Since
Kx’
isnef,
for every ~ > 0 there exists a smooth hermitian metrich,,
onK-1X
such thatU,
= 0398h~(K-1X) -~03C9.
By [Au76]
and[Y77, 78]
there exists aunique
Kâhler metric úJe in thecohomology
class(w)
such thatIn fact u,
belongs
to the Ricci classc1(K-1X)
=e1(X),
hence so does theright
hand
side - ~03C9~
+ ew + Ue. Inparticular
there exists afunction f~
such thatIf we set úJe = oi +
i~~~ (where depends
on~), equation (+)
isequivalent
to the
Monge-Ampère equation
because iai
log
It follows from the results of
[Au76]
that(+ +)
has aunique
solution ç,thanks to the fact the
right
hand side of(+ +)
isincreasing
in ~. Since u~ ~03C9,equation (+) implies
inparticular
thatRicci(03C9~) -~03C9~.
We now recall a well-known differential
geometric technique
used toget
bounds for
N (k) (this technique
has beenexplained
to us in a very efficient wayby
S.Gallot).
Let(M, g)
be acompact
Riemannian m-fold and let E CM
be a fundamental domain for the action of7T1(M)
on the universalcovering M.
Fix a E E and set/3
= diam E. Since03C01(M)
actsisometrically
on
M
withrespect
to thepull-back metric g,
we infer thathas volume
equal
toN (k) Vol(M)
and is contained in thegeodesic
ballB(a,
ak +/3),
where a is the maximum of thelength
ofloops representing
the
generators
gj. Thereforeand it is
enough
to bound the volume ofgeodesic
balls inM.
For this weuse the
following
fundamentalinequality
due to R.Bishop [Bi63],
Heintze-Karcher
[HK78]
and M.Gage [Ga80].
LEMMA 1.2. Let
be the
(geodesic) exponential
map. Denoteby
the
expression of
the volume element inspherical
coordinates with t ER+
andlE Sa(1)
= unitsphere
inT M,a’ Suppose
thata(t, l)
does not vanishfor
te
]0,,r(e)[,
with03C4(03B6) =
+ 00 ora(7(e), l)
= 0. Thenb(t, l)
=a(t, 03B6)1/(m-1)
satisfies
on]0, 03C4(03B6)[
theinequality
where
If
Riccig -
Eg, we infer inparticular
and therefore
b(t, 03B6) 03B1-1 sinh(at)
with a =V E/(m - 1) (to
checkthis,
ob-serve that
b(t, e)
= t +o(t)
at 0 and thatsinh(at)ablat -
acosh(at)b
has anegative derivative). Now,
everypoint x
EB(a, r)
can bejoined
to aby
aminimal
geodesic
arc oflength
r. Such ageodesic
arc cannot contain any focalpoint (i.e.
any critical value of03A6), except possibly
at the endpoint
x.It follows that
B(a, r)
is theimage by 03A6
of the open setTherefore
As
a -1 sinh(03B1t) t e-t,
we getwhere vm
is the volume of the unit ball in R’. D In ourapplication,
thedifficulty
is that themetric g
= úJe varies with E aswell as the constants a = a,,,
03B2 = 03B2~
in(*),
and03B1~(m-1)~
need notconverge to 0 as Etends to 0. We overcome this
difficulty by
thefollowing lemma,
which shows that anarbitrary large
fraction of the volumeof X
remains at bounded distance without
being
disconnected.LEMMA 1.3. Let
Ul , U2
be compact subsetsof X.
Thenfor every 8> 0,
there are closed subsets
U1,e,S
CU1
andU2,e,S
CU2
withVol03C9(UjBUj,~,03B4) 8,
such that any two
points
xi EU1,e,S,
X2 EU2,e,S
can bejoined by
apath of length C8-1/2
with respect to WE, where C is a constantindependent of
Eand 5.
Proof.
The basic observation is thatdoes not
depend
on E, therefore~03C9~~L1(X)
isuniformly
bounded. First suppose thatU1
=U2
= K where K is acompact
convex set in some coordinate openset 03A9 of
X.
Wesimply join
xi EK, X2 e K by
thesegment [x1, x2]
C K andcompute
the averagew,length
of thissegment
when x1, X2 vary(the
averagebeing computed
inL2
norm withrespect
to theLebesgue
measure of0). By
Fubini and the
Cauchy-Schwarz inequality
we getwhere
Ci
isindependent
of E; the lastinequality
is obtainedby integrating
first with
respect
to y =(1 - t)xl
when t %2 ,
resp. y = tx2when t , 2 (observe
that
dxj % 22n dy
in bothcases).
It follows that the set S of
pairs (Xl, x2) E K
X K such thatlength,,,,,
([x1, x2])
exceeds(C1/03B4)1/2
has measure 03B4 in K x K.By Fubini,
the setQ
of
points
xi E K such that the sliceS(x1) = {x2
EK; (x1, X2)
ES}
has volumeVOl(S(x1)) 2Vol(K)
itself has volumeVol(Q) 23/Vol(K).
Now for xl, X2 EKBQ
we haveby
definitionVol(S(xj)) 2 ’Vol(K),
thereforeIf y is a
point
in this set, then(xl , y) (E
S and(x2 , y) OE S,
henceBy continuity,
a similar estimate still holds for any twopoints
xl , X2 EKBQ,
with some y E K. WhenU1
=U2
=K,
the lemma is thusproved
withUj,~,03B4
=KBQ:
note thatand
replace 3 by
e5 with c =Vol(K)/(2C2)
toget
the desired bound 5 for the volume ofUjBUj,~,03B4.
If
Ul , U2
areisomorphic
tocompact
convex subsets inC",
we find a chainof such sets
V1,..., VN with V1 = U1, VN = U2
andVJ
flV°j+1 ~ 0. By
thefirst case, there exists for
each j = 1,..., N
a subsetVj,E,S
CVj
withVol03C9(VjBVj,~,03B4)
5 such that anypair
ofpoints
inVj,~,03B4
can bejoined by
apath
oflength __ C35-lI2.
If we take 51 2Vol03C9(Vj
~Vj+1)
for everyj,
then(VjB Vj,E,S)
U(Vj+1BVj+1,~,03B4)
cannot containVj
~Vj+1
and thereforeVj,E,S n Vj+i,~,03B4 ~ 0.
Thisimplies
that any x eU1,~,03B4:
=Vl,,,,,5
can bejoined
to any y E
U2,~,03B4: = VN,~,03B4 by
apiecewise
linearpath
oflength NC303B4-1/2.
The case when
Ul , U2
arearbitrary
is obtainedby covering
these sets withfinitely
manycompact
convex coordinatepatches.
DWe take U to be a
compact
setcontaining
the fundamental domainE,
solarge
that U°~gj(U°) ~ Ø
for eachgenerator
gj. Weapply
Lemma 1.3 withU1
=U2
= U and 5 > 0 fixed such thatWe get
Ue,8
C U withVol03C9(UBU~,03B4)
03B4 anddiam03C9~(U~,03B4) C8-lI2.
The in-equalities
on volumesimply
thatVol03C9(U~,03B4 ~ E) 1 2 Vol03C9(E)
andUe,8 n gj(U~,03B4) ~ Ø
forevery j (note
that all gj preservevolumes).
It is thenclear that
satisfies
Since m =
dimR X = 2n, inequality (**) implies
Now X is
compact,
so there is a constantC(~)
> 0 such that 03C9nC(~)03C9n~.
We conclude that
The
proof
of Theorem 1.1 iscomplete.
DREMARK 1.4. In the non-Kâhler case, one
might try
instead to use hermi-tian metrics WE in the same conformal class as w, such that
x03C9n~
=X03C9n
and039803C9~(K-1X)
= u~ -~03C9. Then Lemma 1.3 still holds. Themajor difficulty
isthat the first Chern form
039803C9~(K-1X)
differs from the Riemannian Ricci tensor Ricci(WE)
and there is no knownanalogue
ofInequality
1.2 in that case.The fact that we control
039803C9~(K-1X) by -~03C9
insteadof -~03C9~
could be also asource of difficulties.
REMARK 1.5. It is well known and easy to check that the
equation (+ +) implies
In
fact,
this follows from the observation thati~~~
0 at a minimumpoint,
thus
(à)
+i~~~)n/03C9n
1 and(++) implies E min
çmin f,. Similarly we
have~max ~ max f~. Since fe
is apotential
of0398h~(K-1X) - Ricci(03C9)
and con-verges to an almost
plurisubharmonic
function as E tends to0,
it is reasonable toexpect
thatC( E )
haspolynomial growth
inE-1;
this wouldimply
that7T1(X)
haspolynomial growth by taking
E =k-2.
WhenKXl
has asemiposi-
tive
metric,
we can even take E = 0 and find a metric wo withRicci(03C90) =
u0 0. This
gives :
THEOREM 1.6.
If
X is Kâhler andKi’
is hermitiansemipositive (e.g. if Kxm
isgenerated by
sectionsfor
somem)
then03C01(X)
haspolynomial growth of degree
2n. Inparticular
REMARK 1.7. If X is a Fano
manifold,
i.e. ifK-1X
isample,
the abovetechniques
can be used to show that X issimply connected,
as observedlong
ago
by
S.Kobayashi [Ko6l].
In fact the Aubin-Calabi-Yau theorem pro- vides a Kâhler metric w withRicci(w)
= u >0,
say u ~03C9. Then Lemma 1.2implies a2blar +,E/(2n - 1)b(t, 03B6) 0,
thusb(t, 03B6) 03B1-1 sin(at)
witha =
yi E/(2n - 1).
Inparticular 03C4(03B6) 7TI a,
hence the universalcovering X is compact
of diameter 03C0/03B1 and03C01(X)
is finite(all
this wasalready
settledby
S.Myers [My4l]
forarbitrary
Riemannianmanifolds).
The Hirzebruch- Riemann-Roch formulaimplies
Moreover,
the Kodairavanishing
theoremapplied
to theample
line bundle L =K-1 gives
hence
2.
Surjectivity
of the Albanese mapLet X be a
compact
Kâhler manifold and letq(X)
=h1(X, OX)
be itsirregu- larity.
Recall that the Albanese map is aholomorphic
map from X to the Albanese torusdefined
by
the
path
from xo to x in theintegral
is taken modulo anarbitrary loop
at xo,i.e. modulo
H1(X, Z).
We first reprove Lichnerowicz’ fibration theorem[Li71] by
asimpler
method based on the Bochnertechnique (of
courseLichnerowicz had somehow to circumvent the Aubin-Calabi-Yau
theorem,
which was not available at thattime).
Ourstarting point
is thefollowing
basic formula.
FORMULA 2.1. Let # be the
conjugate
linearC--isomorphism TX ~ 03A91X,
v H iv J 03C9,
given by
a Kiihler metric w. Denote alsoby # : pTX ~ flp
theinduced C°°
isomorphism from
p-vectors top-forms.
Thenfor
anarbitrary
smooth section v
of pTX
we havewhere
dV ú)
is the Kiihler elementof
volume and e is the hermitian operatorassociated to the Ricci
curvature form:
pk denotes theeigenvalues of Ricci(03C9)
in an
£ù-orthonormal frame (alazk) -
Proof.
We first make apointwise
calculation of~~v and ~~(#v)
in anormal coordinate
system
for the Kâhler metric w. In such coordinates we can writewhere
(ejklm)
is the curvature tensor ofTX
withrespect
to w. The Kahlerproperty
shows that we have the symmetry relations ejklm = Clkjm = ejmlk, and the Ricci tensor R == 2Rlm dzl
AdZm
is obtained as the trace:Rlm
=Lj
Cjjlm.Since w is tangent of order 2 to a flat metric at the center xo of the
chart,
we
easily
see that the first orderoperator 3
has the same formalexpression
at xo as in the case of the flat metric on C": if w is a smooth
(0, q)-form
withvalues in a
holomorphic
vector bundle E trivializedlocally by
aholomorphic
frame
(eA)
such that(eA(xo))
is orthonormal andDe03BB(x0)
=0,
we have at xothe formula
This
applies
of course to the case of sections ofllp TX
or03A9pX expressed
interms of the frames
~/~zI
anddzi, III
= p. Fromthis,
weimmediately
findthat for any smooth sections v = 2
v¡alaz¡
and w = Lw, dz,
we haveat the
point
xo .Now,
we getComputing Ô ~(#v)
at xo we obtainFormula 2.1 then follows from this
identity by writing
We
easily
deduce from this the fibration theorem of Lichnerowicz[Li7l, 72],
as well as
analogous
results of[Li67]
in the caseRicci(03C9)
0.THEOREM 2.2. Let
(X, w)
be a compact Kiihlermanifold.
Consider the natural contractionpairing
(i) If Ricci(03C9) 0,
then ’1’ has zero kernel inHO(X, 03A9pX).
In that case, theAlbanese map
a : X - Alb(X)
is a submersion and everyholomorphic
vector
field of Alb(X)
admits alifting
to X.Therefore,
there is a groupof analytic automorphisms of
Xlying
over the groupof
translationsof
Alb(X).
(ii) If Ricci(03C9) 0,
then ’1’ has zero kernel inHO(X, 039BpTX).
In that case theidentity
componentAut(X)° of Aut(X)
is abelian and leaves invariant allglobal holomorphic p-forms
or p-vectorfields.
Proof.
Let v be a smooth section ofAPT x
and let w = #v be the associated smooth(p, 0)-form. By
definition of # we have v w =Ilv112. Now,
whenRicci(03C9) 0,
Formula 2.1 shows thatIxllawl12 dV03C9 fxllavl12 dV03C9,
thus v isholomorphic
as soon as w is. Therefore we get aninjective conjugate
linearmap
with the
property
that(#-1w)
.J w is a non zero constant for w ~ 0. This shows that the kernel of ’1’ inHO(X, 03A9pX)
is zero. On the otherhand,
whenRicci(w) % 0,
theinequality
is reversed and weget
aninjection
Hence in that case the kernel of 03A8 in
H°(X, ApTx)
is zero.(i) By
the above with p =1,
everyholomorphic
1-form h which is notidentically
zero does not vanish atall,
because there is a vector field v such that v h = 1. Let(hl , ... , hq)
be a basis ofH0(X, 03A91X).
Then for eachpoint x
E X the 1-formshl(x), ... , hq(x)
must beindependent
inTX,x.
Inthe basis of
TAIb« provided by
thehj’s,
we haveda (x) = (hl(x),
...,hq(x))
and so
d03B1(x)
issurjective. Now,
there areholomorphic
vector fieldsvl , ... , vq on X such
that vi hj = 8ij.
These vector fieldsclearly generate
asubgroup
G ofAut(X)°
which lies over the group of translations ofAlb(X).
(ii)
Let vil , ... , V q be a basis of the Liealgebra
ofAut(X)°.
Then all Lie brackets[vi, vj] vanish,
because we havefor every
holomorphic
1-form h(just
observethat vi
hand vj h
areconstant
functions).
ThusAut(X)°
is abelian.Moreover,
for anyholomorphic p-form
w, the Lie derivative5tv/w)
vanishes:because all
holomorphic
forms on acompact
Kahler manifold are d-closed.Hence w is invariant under
Aut(X)°. By duality,
weeasily
conclude that theholomorphic
p-vectors are alsokept
invariant. D We now discussConjecture
2 forcompact
Kahler manifolds Xwith -KX
being only
nef. Theproof
of thefollowing
theorem has been communicatedto us
by
F.Campana.
THEOREM 2.3. Let X be a compact Kâhler
manifold with -Kx
nef. Let03B1:X ~ A1b(X) be
the Albanese map.If
dim a(X)
=1,
then a issurjective.
Proof.
a(X)
is a smooth curve C. Assume that C has genus g . 2. Then7T1( C)
hasexponential growth;
in fact it contains a free group with2g - 1
generators. Because of the exact sequence03C01(X) ~ 03C01(C) ~ 7To(F),
theimage
of a* has finite index in03C01(C),
hence03C01(X)
is ofexponential growth,
contradicting
Theorem 1.1. DFirst suppose dim a
(X)
= dim X. If a(X) zk Alb(X),
there would be at leasttwo
independent
sections ofKx coming
fromH0(03A9nAlb(X)); since -Kx
isnef,
these sections would not vanish and so
Kx
=OX,
contradiction. The nextinteresting
case isdim 03B1(X) = dim X - 1,
which we treat next. We first prove a moregeneral
statement.THEOREM 2.4. Let X be a compact Kiihler
manifold with - Kx
nef. Then there is noholomorphic surjective
map ~ : X ~ Y to aprojective variety
Ywith
03BA(Y) > 0
suchthat -KF
isbig for
thegeneral fiber
Fof
cp.By
definition the Kodaira dimension03BA(Y)
is the Kodaira dimension of adesingularisation.
Proo f .
Assume there is a map cp as above. We may assume that Y is normalby passing
to thenormalization,
and moreover that the fibers areconnected
by taking
the Stein factorization. Choose a veryample
divisor Hon Y.
Letting m
= dimY,
wepick
a curvewith
Hi ~ |H|
ingeneral position.
Then C is smooth as well asXc = cp-’ (C)
by
Bertini’s lemma. Moreoversince C ~
Sing(Y) = 0
and since wy =7T*(Wy)
onYBSing(Y)
for every de-singularisation
7T:9 -
Y.Let f =
cplxc. We claim:is
big
and nef.In
fact,
which is nef because of
(1). Letting
p =dim XC
andtaking p-th
powers, we observe thatc1(f03C9Y|C) c1(O(F)) by (1),
Fbeing
ageneric fibre,
thuswhich is
positive by
ourassumption that -KF
isbig.
Now we canapply Kawamata-Viehweg’s vanishing
theorem[Ka82, Vi82]
to obtainBut
03C9XC ~ 03C9-1XC/C
=f*(wc),
so via theLeray spectral
sequence we concludeH1(C, wc)
=0,
which is absurd.COROLLARY 2.5. Let X be a n-dimensional
projective (or Moishezon) manifold with -KX
nef. Assume that the Albanese map a has(n - l)-dimen-
sional
image.
Then a issurjective.
Proof.
If a is notsurjective,
theimage
Y =03B1(X) automatically
has03BA(Y)
> 0 since we get at least twoindependent holomorphic
forms of maxi-mum
degree
from the Albanese torus. We may thus assume03BA(Y)
> 0. Let F be thegeneral
fiber of a, which is a curve.Since -KF = - KX|F
isnef,
Fis rational or
elliptic.
In the first case, a issurjective by
theprevious
theorem.If F is
elliptic,
then03BA(X)
=0,
soh0(X, mKX) ~
0 for some m and conse-quently mKx
=tix .
Therefore a is ontoby
Theorem 2.2(i).
DThe last
part
of theproof
shows moregenerally
thatconjecture
2 holds ifK (X)
= 0. A differentproof
ofCorollary
2.5 has beengiven by
F.Campana.
3. Threefolds whose anticanonical bundles are nef
In this section we want to
study
the structure ofprojective
3-folds X with-KX
nef in more detail. Inparticular
we proveConjecture
2 in dimension 3 withpurely algebraic methods, except
in one veryspecial
case. Infact,
we prove that the Albanese map issurjective except possibly
when all extremalcontractions of X are of
type (B),
defined inProposition 3.3(2).
For thestructure of surfaces
with -KX
nef we refer to[CP91].
Let
always X
denote a smoothprojective
3-foldwith -KX
nef and leta : X ~
Alb(X)
be the Albanese map.By
the last words of Section2,
thestructure of X is clear if
03BA(X)
=0;
so we will assume03BA(X) = -~;
note thatKx
is not nef in this case. Then there exists an extremalray on X ([Mo82],
[KMM87]);
let ~: X ~ W be the associated contraction. We want toanalyze
the structure of 9.
PROPOSITION 3.1.
If
dim W2,
a issurjective.
Moreprecisely:
(1) If W
is apoint,
X is Fano withb2
=1,
inparticular
X issimply
connected.(2) If W
is a(smooth)
curve, theng(W)
1. In caseg(W)
=1,
we have a =cp;
if g(W)
=0,
we haveq(X)
= 0. In all cases ~ has the structureof
adel Pezzo
fibration.
(3) If
W is a(smooth) surface,
then either(a)
cp is aP1-bundle
and-Kw
is nef(b)
cp is a proper conic bundle with discriminant locus à such that-(4Ku,
+A)
isnef,
andq(W)
1.Proof. (1)
If dim W =0,
thenq(X) = 0,
hence our claim is obvious.(2)
Let dim W = 1. SinceRq~(OX)
= 0 for q >0,
either cp is the Albanese map and then we must show thatq(W)
= 1 orq(W)
= 0. So assumeq(W)
2. Then the canonical bundle KW isample.
LetKX/W
be the relative canonicalbundle,
soSince the Picard number
p(X)
=p(W)
+ 1 = 2(see
e.g.[KMM87]),
andsince -KX
is nef and~-ample ([KMM87]), -Kx,u,
isample.
Henceby
Kodaira
vanishing:
so
H1(X, ~(OW(KW))
= 0 andHl(W, OW(KW))
=0,
which is absurd.(3)
Now assume dim W = 2. Then W is smooth and cp is aP1-bundle
or a conic bundle([Mo82]).
Sinceq(X)
=q(W),
we have adiagram
with
/3 being
the Albanese map of W and ybeing
finite.(3a)
Assume cp to be aP1-bundle.
We will provethat -KW,
isnef,
hence03B2
is onto and so is a. Take any irreducible curve C C W. Since~-1(C) = P(Ec)
with a rank 2-bundleEc
onC,
we have(after possibly passing
to thenormalization of
C):
by
theadjunction
formula. Sincewe have
Since -Kx
isnef,
we conclude thatNow
c1(EC ~ (det EC/2)
=0, hence - KWBc
must be nefand - KW
itself isnef.
(3b)
Next assume cp to be a proper conic bundle. Let à C W be the discriminantlocus,
i.e.From the well-known formula
(see
e.g.[Mi81])
for every curve C C
W,
we deduce from the nefnessof - KX that - (4KW
+A)
is nef.
Now we conclude
by
means of thefollowing:
LEMMA 3.2. Let W be a smooth
projective surface,
à C W be a(possibly reducible)
curve. Assumethat -(4KW
+A)
is nef. Thenq(W)
1.Proof. Obviously K(W) =
-00. We caneasily
reduce theproblem
to thecase of W
being
minimal. If W =1=P2,
then W is ruled over a curve C. Nowit is an easy exercise
using [Ha77, V.2]
to prove thatg(C)
1. DPROPOSITION 3.3. Assume dim W = 3. Let E be the
exceptional
setof
(P.(1) If
dim~(E)
=0, then -KW
isbig
andnef
andq(X)
= 0.(2) If
dim~(E)
=1,
then W issmooth,
q; is theblow-up of
the smooth curveCo
=ço(E) and - Kw
isagain
nef exceptfor
thefollowing special
cases:Co
is rational and moreover eitherProof. By [Mo82]
E isalways
an irreducible divisor and if dimcp(E)
=1,
W is smooth
and cp
is theblow-up
of a smooth curve. We mayalways
assumeK 5
=0,
otherwiseq(X)
= 0by Kawamata-Viehweg vanishing.
(1)
We have thefollowing
formula of Q-divisors:with some e E
Q+ ([Mo82],
in fact either E ~P2
or E is a normalquadric
and =
2,
1 or1/2). Hence - KW
is nef. Furthermore:and since
E3
> 0(E
hasalways negative
normalbundle, [Mo82]),
we con-clude from
K3x =
0 thatK3W 0, so -KW
isbig
and nef(observe
that Wmight
besingular).
Now a"singular"
version of theKawamata-Viehweg vanishing
theorem([KMM87, 1.2.5, 1.2.6] applied
to D =0) yields
Since
Rq~(OX)
= 0 for q >0,
we getq(X)
= 0.(2)
From the formulaKx
=cp*(Kw)
+ E, weimmediately
see thatfor every curve C ~
Co.
Let
NC0/W
= N denote the normal bundle ofCo.
Let V =N*
0 Y with L ~Pic(Co)
be itsnormalization,
i.e.H0(V) ~ 0,
butHO(V 0 %)
= 0 for allline bundles W with
deg W
0.Let 03BC
=deg 0.
Then E can be written as E =P(N*) = P(V).
The"tautological"
line bundleOP(V)(1)
has a "canonical"section
Ci satisfying ci
= - e =c1(V) (see [Ha77, V.2]).
In thisterminology
Let F be a fiber of ’PIE. Write for numerical
equivalence
Since
(KX · F) = -1,
we have a = 1. Moreoverjust by
definition of g andby
the fact thatN;IX
=CP(N*)(1).
Henceso -KW
is nef ifLetting g
be the genus ofCo,
we haveK2E
=8(1 - g);
on the other hand wecompute by adjunction:
Thus
8(1 - g)
= 4b - 4e -4g,
andconsequently
Since - KAIE
isnef,
we haveK2X · E 0,
which isequivalent
to b el2.Combining
this with(**)
shows that b + g 0 at least if g 1.Therefore, if g 1, -KW is
nef.Now assume g = 0. Then
(*)
isequivalent
toAgain by
nefnessof - KXjE
weget
so b e. This settles
already
the case e 2.Since e :
0,
we are left with e = 0 and e = 1 andadditionally
e b el2 + 1. This leads to
(A)
and(B).
DREMARK 3.4. Assume
that -KX
isbig
and nef. Then X is "almost Fano"in the
following
sense.By
the Base Point Free Theorem[KMM87]
we havea
surjective
map~:X ~ Y, given by
the basepoint
freesystem - mKx for
some suitable m, to a normal
projective variety
Y. Thisvariety
Y carries anample
line bundle L such thatcp*(L) = -mKx.
The map cpbeing
a modific-ation,
we conclude that L= -mKy.
Thus Y is Q-Gorenstein with at mostcanonical
singularities
and the Q-Cartierdivisor -KY
isample.
We say thatY is "Q-Fano". In
particular
Y hasirregularity
0(Q-Fano
varieties are evenexpected
to besimply
connected and so X would besimply
connected. This is true in dimension threeby
a recent result ofKollar, Miyaoka
andMori.).
n We are now interested in those X which are not "almost
Fano",
i.e. such that(-Kx)3
= 0.PROPOSITION 3.5.
Assume -KX
nef andK 5
= 0.If
cp is a contractionof
type
(B),
thenq(X)
= 0 and moreover X is birational to a Q-Fanovariety.
In
particular Alb(X)
= 0.Proof.
Let ~: X ~ W be thecontraction,
which is theblow-up
ofCo
C Wsuch that
C0 ~ P1
andLet E C X be the
exceptional
divisor. We have(1,
= Hirzebruch surface of index1).
Let C C E be theunique
section withC2
= - 1. Let03C0:X+ ~ X be
theblow-up
of C. SinceNCIE
=O(-1)
andwe get
NE/X|C = O(-1)
and obtain fromthat
NC/X = O(-1) ~ O(-1).
Hence theexceptional
divisor D =03C0-1(C)
isPi
XPi
andNDIX- = OP(NC/X)(-1) = C(- 1) 0 O(-1).
Therefore D can beblown down
along
the otherruling. Let 03C3: X+ ~ X-
be thisblowing
down.CLAIM 3.6. The anticanonical
divisor -Kx-
is nef.Proof.
Let A- C X - be anarbitrary
curve not in the center of 0’, A+ thestrict transform in X+ and A the
image
in X. AsKx- = o-*(Kx-)
+D,
we haveand